A circle has a diameter of 20 what formulas are true

Answer:

x=10

Step-by-step explanation:

Pythagorean Thereom: a^2+b^2 = c^2 when the triangle is right which it is since the 90 degree angle is marked.

a=8 and b=6

8^2+6^2= 64+36 = 100

Take the square root of 100 and get 10.

The probability that 3 out of the 4 captured elk have been tagged is approximately 0.0053.

We can use the concept of combinations.

The total number of ways to choose 4 elk out of 24 is given by the combination formula:

C(24, 4) = 24! / (4!(24-4)!) = 10,626

Now, we need to consider the number of ways to choose 3 tagged elk out of the 8 tagged elk and 1 untagged elk. The number of ways to do this is given by:

C(8, 3) * C(1, 1) = 8! / (3!(8-3)!) * 1! / (1!(1-1)!) = 56

Therefore, the probability that 3 out of the 4 captured elk have been tagged is:

P = (Number of ways to choose 3 tagged elk out of 8 tagged elk and 1 untagged elk) / (Total number of ways to choose 4 elk out of 24)

P = 56 / 10,626

Calculating this division gives us the probability:

P ≈ 0.0053

So, the probability that 3 out of the 4 captured elk have been tagged is approximately 0.0053 .

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Each chart consists of a center line representing the average, an upper line indicating the maximum acceptable deviation upwards, and a lower line indicating the maximum acceptable deviation downwards. These components help analyze data and monitor process performance.Option B,E,F.

Each chart has the following three components:

1. B. A center line representing the average: This line is drawn to show the average value or mean of the data being analyzed. It provides a reference point to compare the data points above and below it.

2. E. An upper line representing the maximum acceptable variation upwards: This line is drawn to indicate the upper limit of acceptable variation or deviation from the average. It helps identify if the data points exceed the acceptable range.

3. F. A lower line representing the maximum acceptable variation downwards: This line is drawn to indicate the lower limit of acceptable variation or deviation from the average. It helps identify if the data points fall below the acceptable range.

These three components together create a control chart, which is a graphical representation used in statistical process control. Control charts help monitor and analyze data over time, allowing organizations to identify trends, detect abnormalities, and make data-driven decisions to improve processes and quality.

In summary, each chart consists of a center line representing the average, an upper line indicating the maximum acceptable deviation upwards, and a lower line indicating the maximum acceptable deviation downwards. These components help analyze data and monitor process performance.

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The answer to the given question is the angular acceleration of the wheel is 0.7742 rad/s².

We can use the formula for rotational dynamics:

τ = Iα

where τ is the torque applied, I is the moment of inertia, and α is the angular acceleration.

Rearranging this equation, we get:

α = τ / I

Plugging in the given values, we have:

α = 48 Nm / 62 kg⋅m²

Simplifying, we get:

α = 0.7742 rad/s²

Rotational dynamics deals with the motion of objects that are rotating around an axis. The key concept in rotational dynamics is torque, which is a measure of how much a force can cause an object to rotate. The moment of inertia is another important quantity in rotational dynamics, and it describes an object's resistance to rotational motion. The moment of inertia depends on the distribution of mass around the axis of rotation. The angular acceleration of a rotating object is directly proportional to the torque applied and inversely proportional to the moment of inertia. Therefore, a greater torque or a smaller moment of inertia will result in a greater angular acceleration. These concepts are used in a variety of applications, from the motion of planets to the operation of engines and turbines.

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Given:x = 5cos 3ty = 4sin 3tWe need to find the first two derivatives dy/dx and d²y/dx² for the given function using the chain rule.

Now, we know thatcosec²θ = cot²θ + 1Therefore, we can write the above expression asd(dy/dx)/dt = 12(cot²(π/27) + 1) cot (π/27)= 12(1+cot²(π/27)) cot (π/27)Now, substituting the value of cot (π/27) from the given function, we getcot (π/27) = cot (3×1/3) = 1Therefore,d(dy/dx)/dt = 12(1+1²)×1= 24To find d²y/dx²,Therefore,d²y/dx² = [(-36sin 3t)/(225sin² 3t)] - [12cos 3t×24] / (-15sin 3t)³= (-4/25) csc² 3t - 64cot 3t csc³ 3t= -4cosec² 3t/25 - 64cot 3t/125The value of t at which we need to evaluate the second derivative is t = 1/9.Therefore,d²y/dx² = -4cosec²(π/27)/25 - 64cot(π/27)/125= -4/(5+5√3) - 64/(25√3 + 125) = (-20-20√3)/425. Hence, the value of d²y/dx² is (-20-20√3)/425 when t = 1/9.

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Answer:

a^2 + b^2 = c^2

Step-by-step explanation:

12^2 + 15^2 = c^2

144 + 225 = c^2

144 + 225 = 369^2

√369 = 19.21

Answer this question by starting at the original point and moving opposite to what the question asks.

Instead of moving down 9 units, starting at (2, -5) move up 9 units.

By doing this, you are now at (2, 4)

Starting at (2,3) move to the left by 4 units.

You end up at ( -2,4)

You can also solve this problem by using addition.

To find the original add/subtract the units from the coordinates (2, -5)

To find the x coordinate: subtract 4 from 2: -2

To find the y coordinate: add 9 to -5: 4

(-2, 4)

Answer:

x + y = - 3

Step-by-step explanation:

The equation for standard form is Ax + By = C. Since there is an invisible 1 in front of both x and y, you can easily solve the problem by subtracting -1x from both sides to get 1x + 1y = -3 or x + y = -3

Answer:97 °

Step-by-step explanation:

83° & b° are a supplementary angle, meaning that they equal 180°. So:

83 + b = 180

b = 97°

The chemical tracer commonly used to trace the paths of afferent axons is called "biocytin."

Afferent nerve fibers are axons (nerve fibers) of sensory neurons that carry sensory information from sensory receptors to the central nervous system. Many afferent projections arrive at a particular brain region. Afferent nerve fiber.

The chemical tracer commonly used to trace the paths of afferent axons is called "biocytin." Biocytin is a modified form of biotin that can be taken up by neurons and transported along their axons. It is often injected into a specific region of interest and allowed to diffuse throughout the neural tissue. Afferent axons originating from the injected area can then take up and transport the biocytin, allowing researchers to visualize and study their pathways using various histological techniques, such as immunohistochemistry or avidin-biotin complex staining.

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Answer:

98

Step-by-step explanation:

96+100=196

196÷2=98

Answer:

97.

Step-by-step explanation:

86 96 100 98

Place them in order:

86 96 98 100

The median is the middle value of an ascending sequence of numbers.

As there is an even number of values the median is the mean of the 2 middle ones:

So here it is (96 + 98) / 2

= 97.

Answer:

a = 0.3 and b = - 1.1

Step-by-step explanation:

(x - 2)² = x² -4x + 4

Hence, x² - 4x + 4 = 3x - 6

x² - 7x + 10 = 0

(x - 5)(x - 2) = 0

∴ x = 5 or 2

f(5) = 25a + 5b = 2  ----- (i)

f(2) = 4a +  2b = -1  ------ (ii)

(i) X 2: 50a + 10b = 4 ----- (iii)

(ii) X 5: 20a + 10a = -5  ---- (iv)

Subtract (iv) from (iii): 30a = 9

a = 0.3

Substitute a into (ii) to obtain b

4(0.3) + 2b = -1

2b = -1 - 1.2 = -2.2

∴ b = -1.1

Hey!!

Here's your answer

7+(-7)

=7-7

=0

so the answer is 0

hope it helps...

Answer:

7+(-7) would be 0 because with one negative and one positive, they cross each other out.

Step-by-step explanation:

hope this helps. :))

Answer:

3.802e+6 miles

Step-by-step explanation:

mark me brainlist

Answer:

A:1/18 B:1/6 for 4 and 1/3 for red

Step-by-step explanation:

(a) This is an observational study.

The reason is that the researchers did not manipulate any variables or conditions; they simply observed and collected data on the two groups of babies (VLBW and normal birth weight) as they grew up.
(b) The p-value (0.0013) is less than the significance level (typically 0.05), we reject the null hypothesis.  

There is sufficient evidence to suggest that the graduation rate among the VLBW group is significantly lower than the normal-birth-weight controls.

To determine if the graduation rate among the VLBW group is significantly lower than the normal-birth-weight controls, we can perform a hypothesis test using the proportion of high school graduates in each group.
State the null and alternative hypotheses.
Null hypothesis (H0):

There is no significant difference in graduation rates between the VLBW group and the control group (\(p_VLBW = p_control).\)
Alternative hypothesis (Ha):

The graduation rate among the VLBW group is significantly lower than the control group \((p_VLBW < p_control).\).

Calculate the sample proportions and the pooled proportion.
\(p_VLBW\) = 179/242 = 0.7397
\(p_control = 193/233 = 0.8283.\)
\(p_pooled = (179 + 193) / (242 + 233) = 0.7842\)
Calculate the test statistic.
\(z = (p_VLBW - p_control) / sqrt(p_pooled * (1 - p_pooled) * (1/242 + 1/233)) = -3.0074\)
Determine the p-value.
Using a z-table or calculator, the p-value for z = -3.0074 is approximately 0.0013.

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Answer: -24x^2+28x

Step-by-step explanation: -4x*6x-(-4x)*7 to -24x^2+28x

The arc length of the polar curve r = e^5θ from 0 to 2π is √26 [(e^10π - 1) / 5].

To find the arc length of a polar curve, we use the formula:

L = ∫[a,b] √(r(θ)² + [dr(θ)/dθ]²) dθ

where r(θ) is the polar equation of the curve, and dr(θ)/dθ is its derivative with respect to θ.

In this case, we have r(θ) = e^5θ, so:

dr(θ)/dθ = 5e^5θ

Plugging these into the arc length formula, we get:

L = ∫[0,2π] √(e^10θ + (5e^5θ)²) dθ

Simplifying the integrand, we have:

L = ∫[0,2π] √(e^10θ + 25e^10θ) dθ

L = ∫[0,2π] √(26e^10θ) dθ

L = √26 ∫[0,2π] e^5θ dθ

Using the formula for the integral of e^x, we get:

L = √26 [e^5θ / 5] |_0^(2π)

L = √26 [(e^10π - 1) / 5]

So the arc length of the polar curve r = e^5θ from 0 to 2π is √26 [(e^10π - 1) / 5].

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The subset S_f of relation f is the graph of the function f(x) = sin(2x). This graph is a sine wave that oscillates between -1 and 1, and has period 2π. The congruence modulo 5 relation ≡_5 between integers in Z is a relation that states that two integers are congruent modulo 5 if their difference is divisible by 5. For example, 1 ≡_5 6 because 1 - 6 = -5, which is divisible by 5.

The graph of the function f(x) = sin(2x) is a sine wave that oscillates between -1 and 1. The congruence modulo 5 relation ≡_5 is an equivalence relation because it satisfies the three properties of an equivalence relation:

Reflexivity: For every integer a, a ≡_5 a.

Symmetry: For all integers a and b, if a ≡_5 b, then b ≡_5 a.

Transitivity: For all integers a, b, and c, if a ≡_5 b and b ≡_5 c, then a ≡_5 c.

To see that reflexivity holds, note that for any integer a, a - a = 0, which is divisible by 5. Therefore, a ≡_5 a for all integers a.

To see that symmetry holds, note that if a ≡_5 b, then a - b is divisible by 5. This means that b - a is also divisible by 5, so b ≡_5 a.

To see that transitivity holds, note that if a ≡_5 b and b ≡_5 c, then a - b and b - c are both divisible by 5. This means that a - c is also divisible by 5, so a ≡_5 c.

Therefore, the congruence modulo 5 relation ≡_5 is an equivalence relation.

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To show that {u1, u2, u3} is an orthogonal basis for R, we need to show that each pair of vectors is orthogonal and that the set is linearly independent. x as a linear combination of the u is \(x = (-1/2)u1 + (1/2)u2 + u3.\)

To calculate the inner product of each pair of vectors to show that they are orthogonal. This is done by taking the dot product of each pair of vectors and checking if it equals 0:
\(u1 • u2 = (5)(2) + (2)(-1) + (1)(4) = 0u1 • u3 = (5)(1) + (2)(5) + (1)(1) = 0u2 • u3 = (2)(1) + (-1)(5) + (4)(1) = 0\)

Since each inner product is 0, the vectors are orthogonal. Next, we need to show that the set is linearly independent. This can be done by showing that the only solution to the equation \(c1*u1 + c2*u2 + c3*u3 = 0\) is \(c1 = c2 = c3 = 0\). This can be done by solving the system of equations:

\(5c1 + 2c2 + c3 = 02c1 - c2 + 5c3 = 0c1 + 4c2 + c3 = 0\). Solving this system of equations gives us c1 = c2 = c3 = 0, which means that the set is linearly independent. Therefore, {u1, u2, u3} is an orthogonal basis for R.

To express x as a linear combination of the u's, we need to find the coefficients c1, c2, and c3 such that x = c1*u1 + c2*u2 + c3*u3. This can be done by solving the system of equations:
\(5c1 + 2c2 + c3 = -12c1 - c2 + 5c3 = 4c1 + 4c2 + c3 = 1\)

Solving this system of equations gives us c1 = -1/2, c2 = 1/2, and c3 = 1. Therefore, x = (-1/2)u1 + (1/2)u2 + u3.

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Answer: $13.65 per ticket

Step-by-step explanation:

54.6/4

Answer:

Step-by-step explanation:

Square Root of 85

The optimal point values for x1, x2, λ, and μ (Lagrange multipliers) in the given problem are:

x1 = 1

x2 = 1

λ = -4

μ = 2

To solve the optimization problem using the Lagrange multipliers technique, we first construct the Lagrangian function L(x1, x2, λ) by incorporating the equality constraint:

L(x1, x2, λ) = f(x1, x2) - λ(g(x1, x2))

Where f(x1, x2) is the objective function, g(x1, x2) is the equality constraint, and λ is the Lagrange multiplier.

In this case, the objective function is f(x1, x2) = 2x1^2 - 2x1x2 + 2x2 - 6x1 + 6, and the equality constraint is g(x1, x2) = x1 + x2 - 2.

The Lagrangian function becomes:

L(x1, x2, λ) = 2x1^2 - 2x1x2 + 2x2 - 6x1 + 6 - λ(x1 + x2 - 2)

To find the optimal values, we need to find the critical points by taking partial derivatives of L with respect to x1, x2, and λ and setting them equal to zero. Solving these equations simultaneously, we get:

∂L/∂x1 = 4x1 - 2x2 - 6 - λ = 0

∂L/∂x2 = -2x1 + 2 + λ = 0

∂L/∂λ = -(x1 + x2 - 2) = 0

Solving these equations, we find x1 = 1, x2 = 1, and λ = -4. Substituting these values into the equality constraint, we can solve for μ:

x1 + x2 - 2 = 1 + 1 - 2 = 0

Therefore, μ = 2.

The optimal point values for the variables in the optimization problem are x1 = 1, x2 = 1, λ = -4, and μ = 2. The Lagrange multipliers λ and μ represent the rates of change of the objective function and the equality constraint, respectively, with respect to the variables. They provide insights into the sensitivity of the objective function to changes in the constraints and can indicate the impact of relaxing or tightening the constraints on the optimal solution. In this case, the Lagrange multiplier λ of -4 indicates that a small increase in the equality constraint (x1 + x2 - 2) would result in a decrease in the objective function value. The Lagrange multiplier μ of 2 indicates the shadow price or the marginal cost of satisfying the equality constraint.

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Answer:

next row in the x column = 8

next row in the y column  = 15

Step-by-step explanation:

The fundamental difference between a sample survey with nonresponse and a volunteer sample is the way participants are selected and the biases that may result from each approach. While nonresponse in a sample survey can lead to nonresponse bias, volunteer samples are more susceptible to selection bias.

The fundamental difference between a sample survey of human beings that may suffer from nonresponse and data using a volunteer sample is the way participants are selected and the potential biases that may arise.
In a sample survey, a random selection of individuals is chosen from the target population. However, nonresponse can occur when some of these selected individuals fail to participate or provide incomplete information. This can lead to nonresponse bias, which affects the representativeness of the sample and the accuracy of the results. To minimize nonresponse bias, researchers should ensure that their survey design and data collection methods encourage participation and provide clear instructions for respondents.
On the other hand, a volunteer sample consists of participants who willingly choose to participate in the study, usually in response to an open invitation. This approach is more prone to selection bias, as the individuals who volunteer may not be representative of the target population. They may have certain characteristics or attitudes that motivated them to participate, leading to biased results that may not generalize to the broader population. To address selection bias, researchers should carefully consider the recruitment method and the potential impact of volunteerism on their findings.
In summary, the fundamental difference between a sample survey with nonresponse and a volunteer sample is the way participants are selected and the biases that may result from each approach. While nonresponse in a sample survey can lead to nonresponse bias, volunteer samples are more susceptible to selection bias. Researchers must be mindful of these biases when designing and conducting their studies.

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Answer:

18,1,18

Step-by-step explanation:

The slope of a line from the given graph is 4 units.

From the given graph, vertical line (rise) = 16 and horizontal line (run) = 4.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

Now, slope = Rise/Run

⇒ slope = 16/4

= 4 units

Therefore, the slope of a line from the given graph is 4 units.

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The required quotient of 1.888 x 10 and \(5.9 x 10^6\) expressed in scientific notation is \($3.1966 \times 10^{-6}$\).

To express the quotient of 1.888 x 10 and \(5.9 x 10^6\) in scientific notation, we can write:

\($\frac{1.888 \times 10}{5.9 \times 10^6}$\)

We can simplify the numerator by moving the decimal point one place to the left:

\($\frac{0.1888 \times 10^1}{5.9 \times 10^6}$\)

Now, we can divide the coefficients and subtract the exponents:

\($\frac{0.1888}{5.9} \times 10^{2-6}$\)

\($= 0.031966 \times 10^{-4}$\)

Finally, we can express the result in proper scientific notation by moving the decimal point one place to the right:

\($= 3.1966 \times 10^{-6}$\)

Therefore, the quotient of 1.888 x 10 and \(5.9 x 10^6\) expressed in scientific notation is \($3.1966 \times 10^{-6}$\).

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Answer:

x = 3.25 m

Step-by-step explanation:

First, find the height of the triangle using sin31:

sin 31 = h/9 ---> h = 9sin31 = 4.64 m

Next, we can now solve for x using tan55:

tan 55 = h/x --> x = (4.64 m)/(tan 55) = 3.25 m