A child traveling 5 m/s on a sled passes her younger brother. If her average acceleration on the sledding hill is 2 m/s^2. how fast is she passes her older brother 4 s later?

Answer: Please see the attached image.

Explanation:

A diagram of the Lewis dot structure depicts the valence electrons of the atoms of a molecule. It makes use of dots to represent lone electron pairs and lines to represent atomic bonds.

Valence Electrons are the s and p subshells on the periodic table. You count the total s and p subshells of the corresponding atom to find how much valence electrons it has.

The bus resultant displacement is approximately 4.14 km at an angle of 59.5 degrees north of east.

The first movement is 2 km due east, which means it has an x-component of 2 km and a y-component of 0 km.

The second movement is 5 km at 45 degrees north of east. This can be broken down into x and y components using trigonometry: x = 5 km * cos(45) = 3.54 km y = 5 km * sin(45) = 3.54 km

The third movement is 4 km at 30 degrees north of west. This can also be broken down into x and y components using trigonometry: x = -4 km * cos(30) = -3.46 km (negative because it’s towards the west) y = 4 km * sin(30) = 2 km

The fourth movement is 2 km due south, which means it has an x-component of 0 km and a y-component of -2 km.

Adding up all the x and y components, we get: x_total = 2 + 3.54 + (-3.46) + 0 = 2.08 km y_total = 0 + 3.54 + 2 + (-2) = 3.54 km

The magnitude of the resultant displacement can be calculated using the Pythagorean theorem: resultant_displacement = sqrt(x_total^2 + y_total^2) = sqrt(2.08^2 + 3.54^2) ≈ 4.14 km

The direction of the resultant displacement can be calculated using the arctan function: direction = arctan(y_total / x_total) ≈ 59.5 degrees north of east

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The minimum coefficient of static friction with the floor is 0.3846.

To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).

Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.

Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.

The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.

Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.

Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.

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ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

Answer:

I think it's just 100+70+140

Answer:

  72.5 A

Explanation:

There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.

  V = πr²h  . . . . .  volume of a cylinder

  V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s

Then the charge flow rate is ...

  (13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s

The magnitude of the current is about 72.5 amperes.

______

Additional comment

The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.

Horizontal component , F cos θ.

Vertical component , F sin θ.

Now, as θ increases towards 90° cos θ decreases and

As θ increases towards 90° sin θ increases.

Therefore, horizontal component of F will decrease and vertical component will increase.

Hence, this is the required solution.

The impulse exerted by Earth on the apple during the first 0.50 m of its fall is 0.74 Ns, and during the next 0.50 m, it is 0.37 Ns.

Using the equation for impulse, which is impulse = force x time, we can calculate the impulse that Earth exerts on the apple during the first 0.50 m and the next 0.50 m of its fall.

First, we need to calculate the force of gravity acting on the apple, which is given by the equation F = mg, where m is the mass of the apple and g is the acceleration due to gravity (approximately 9.81 m/s^2).

The mass of the apple is 150 g, which is 0.15 kg. Therefore, the force of gravity acting on the apple is:

F = mg = (0.15 kg)(9.81 m/s^2) = 1.47 N

Now, we can calculate the impulse exerted by Earth on the apple during the first 0.50 m of its fall. Since the force of gravity is constant, we can use the equation impulse = force x distance, where distance is the distance over which the force is applied.

Impulse during first 0.50 m = force x distance = (1.47 N)(0.50 m) = 0.74 Ns

For the next 0.50 m of the apple's fall, we need to consider that the velocity of the apple is increasing, so the force of gravity is no longer constant. However, we can approximate the average force over this distance as half the force at the start of the fall, or 0.5(1.47 N) = 0.74 N.

Using the same equation impulse = force x distance, we can calculate the impulse exerted by Earth on the apple during the next 0.50 m of its fall:

Impulse during next 0.50 m = force x distance = (0.74 N)(0.50 m) = 0.37 Ns.

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if the mass of both of the objects is doubled, then the force of gravity between them is quadrupled. Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

Check attached photo

Check attached photo

Answer:

I have a questions for u.

The electric field at the midpoint between the two charges is  determined as + 4.4 x 10⁸ N/C.

The electric field at the midpoint between the two charges is calculated as follows;

E = F/Q

E = kQ/r²

where;

The distance at midpoint between the charges is calculated as follows;

d = r/2 = 3 cm / 2 = 1.5 cm = 0.015 m

E = E₁  +  E₂

E = ( 28 x 10⁻⁶ x 9 x 10⁹ )/(0.015²) + (-17 x 10⁻⁶ x 9 x 10⁹ ) / ( 0.015² )

E = 1.12 x 10⁹  - 6.8 x 10⁸

E = 4.4 x 10⁸ N/C

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\(\left(95\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{231}{1.00}\dfrac{\mathrm{in}^3}{\rm gal}\right)\left(\dfrac{1.0}{12}\dfrac{\rm ft}{\rm in}\right)^3\left(\dfrac{1.0}{60}\dfrac{\rm min}{\rm s}\right)\approx0.211661\dfrac{\mathrm{ft}^3}{\rm s}\)

Multiplying 95 gal by 231 converts it to in^3. Dividing by 12^3 converts in^3 to ft^3. Dividing by 60 converts min to s.

Answer:

nique ta mama  

Explanation:

Answer:

Transform Boundary

Explanation:

The just slide past each other

Answer:

Transform Boundaries

Explanation:

Answer:

The speed and direction of the third fragment are 2 meters per second and 54.316º, respectively.

Explanation:

The object is not under the influence of any external force, meaning that Principle of Momentum Conservation to calculation of the velocity of the third fragment:

\((m_{1}+m_{2}+m_{3})\cdot \vec {v}_{o} = m_{1}\cdot \vec v_{1} + m_{2}\cdot \vec v_{2} + m_{3}\cdot \vec v_{3}\) (1)

Where:

\(m_{1}\), \(m_{2}\), \(m_{3}\) - Masses of the first, second and third fragments, in kilograms.

\(\vec v_{o}\) - Initial velocity of the object, in meters per second.

\(\vec v_{1}\), \(\vec v_{2}\), \(\vec v_{3}\) - Velocities of the first, second and third fragments, in meters per second.

If we know that \(m_{1} = 0.5\,kg\), \(m_{2} = 1.3\,kg\), \(m_{3} = 1.2\,kg\), \(\vec v_{o} = (0,0)\,\left[\frac{m}{s} \right]\), \(\vec v_{1} = \left(-2.8, 0\right)\,\left[\frac{m}{s} \right]\) and \(\vec v_{2} = \left(0,-1.5\right)\,\left[\frac{m}{s} \right]\), the velocity of the third fragment is:

\((-1.4,0) + (0,-1.95) + 1.2\cdot \vec v_{3} = (0,0)\)

\(1.2\cdot \vec v_{3} = (1.4,1.95)\)

\(\vec v_{3} = (1.167, 1.625)\,\left[\frac{m}{s} \right]\)

The speed of the third fragment is the magnitude of the result found above:

\(v_{3} = 2\,\frac{m}{s}\)

And the direction of the third fragment is:

\(\theta_{3} = \tan^{-1} \left(\frac{1.625}{1.167}\right)\)

\(\theta_{3} \approx 54.316^{\circ}\)

The speed and direction of the third fragment are 2 meters per second and 54.316º, respectively.

Answer:

1.Active

2.Active

3.inactive

4.active

5.active

Explanation:

hope it's help

The distance above the ground the rock should be raised in order to hits the ground double of initial time is 4h.

The given parameters;

The time of motion of the rock from the given height is calculated as;

\(h = ut + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt_0^2\\\\h = \frac{1}{2} gt_0^2\\\\t_0^2 = \frac{2h}{g} \\\\t_0 = \sqrt{\frac{2h}{g} }\)

When the time of motion is doubled to 2t₀, the height above the ground should be;

\(2(t_0) = 2(\sqrt{\frac{2h}{g} } )\\\\2(t_0) = \sqrt{\frac{4\times 2h}{g} }\)

Thus, the distance above the ground the rock should be raised in order to hits the ground double of initial time is 4h.

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a) The angle θ1 which the righthand cable makes with respect to the ceiling is  sin^(-1)(692 N / 530 N).

b) The angle θ2 which the left-hand cable makes with respect to the ceiling is  sin^(-1)(692 N / 570 N).

We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).

We may apply the ideas of trigonometry and vector addition to address this issue.

a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.

T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).

T1sin(θ1) = 692 N

We may rearrange the equation to find 1:

θ1 = sin^(-1)(692 N / T1)

We can find 1 by substituting the given tension value, T1 = 530 N:

θ1 = sin^(-1)(692 N / 530 N)

b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.

The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).

T2sin(θ2) = 692 N

To find θ2, we can rearrange the equation:

θ2 = sin^(-1)(692 N / T2)

Substituting the given tension value T2 = 570 N, we can solve for θ2:

θ2 = sin^(-1)(692 N / 570 N)

Calculating these angles using the given tension values will provide the answers in degrees.

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Answer:

When light traveling through air enters water at an angle, it moves in a curve in air and changes direction when it enters water. This bending of light is known as refraction. The angle at which the light bends depends on the difference in the refractive indices of the two media, which is why the light bends when it enters the denser medium of water.

Answer:

Fahrenheit scale

Explanation:

just guess equivalent to 10 degree

The energy transferred in Joules by the radio when it has been switched on for 2 minutes would be 6000 Joules.

Power is defined as the rate of energy transfer or the rate at which work is done, and is given by the equation:

Power = Energy transferred / Time

Rearranging the equation to solve for energy transferred, we get:

Energy transferred = Power x Time

We are given:

Power = 50 W

Time = 2 minutes = 120 seconds

Therefore, the energy transferred by the radio when it has been switched on for 2 minutes is:

Energy transferred = Power x Time = 50 W x 120 s = 6000 J

In other words, the energy transferred by the radio is 6000 Joules.

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Answer: \(3000\ W,\ 78,000\ J\)

Explanation:

Given

The voltage of the battery is \(V=12\ V\)

Current through the battery is \(I=250\ A\)

(a) Power is the product of voltage and current

Power dissipates is given by

\(P=VI\\P=12\times 250\\P=3000\ W\)

(b) Energy delivered

\(E=P\times t\)

\(E=3000\times 26\\E=78,000\ J\)

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The initial velocity of the cannon ball when it reached a height of 4.75 m is 9.65 m/s.

Velocity- The rate of change of displacement is the definition of velocity.

The formula below is used to determine the cannon ball's initial velocity.

Formula:

v² = u²+2gH......... Equation 1

Where:

v = Final velocity

u = Initial velocity

H = Height

g = Acceleration due to gravity.

From the question,

Given:

v = 0 m/s (At the maximum height)

H = 4.75 m

g = 9.8 m/s

Substitute these values into equation 1

0² = u²+2×9.8×4.75

u² = 93.1

u = √(93.1)

u = 9.65 m/s

Hence, the initial velocity of the cannonball is 9.65 m/s.

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If the mass of the cart was halved, the magnitude of the centripetal acceleration would decrease.

Centripetal force is a force that causes a change in velocity that undergoes motion in a circular path.

Centripetal force can be expressed by using the formula:

\(F = \frac{mv^2}{r}\)

Where;

m = mass of the cart

r = radius of the circular path

v = speed of the cart

Now, since F ∝ m, if the mass (m) is halved, then the magnitude of the centripetal force acting on the cart will also be halfved.

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