3.08 moles of carbon are in the sample.
What are moles?
A Mole is defined as a chemical unit, defined to be 6.022 x 10 23 ( Avogadro's Constant) entities. In science, this is often usually molecules or atoms. The mass of a mole is the gram formula mass of a substance.
Their averages are equal
moles of carbons / 5 = moles of o
19/5 = moles of c
3.08 = moles of c
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g sio2 is a(n) covalent network solid. ki is a(n) -- solid. ti is a(n) -- solid. c6h12o6 is a(n) -- solid.
The kinds of the solids are;
SiO2 - Covalent network solid
C6H12O6 - Covalent solid
KI - Ionic solid
What is a covalent network solid?
A covalent network solid, often referred to as a network covalent solid or just a network solid, is a category of solid material in which the atoms that make up the material are strongly covalently linked to one another, forming an extended three-dimensional network structure.
Covalent network solids are kept together by a dense network of covalent bonds, as opposed to molecular or ionic solids, which are held together by weaker intermolecular forces or ionic interactions, respectively.
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carbon monoxide reacts with iron (ii, iii) oxide (fe3o4) making iron and carbon dioxide. when a student performed the experiment she reacted 70.0 g of fe3o4 with 70.0 g of co and the actual yield of iron was 41.9. calculate the percentage yield.
Please help me!
The percent yiled shows the extent of conversion of reactants to products. The percent yiled here is 83.1%.
Percent yieldThe percent yiled in a reaction is calculated as te ratio of the actual yield to the theoretical yiled multiplied by 100.
Hence the balanced reaction equation is; Fe3O4 + 4CO → 3Fe + 4CO2.
Number of moles of Fe3O4 = 70.0 g/232 g/mol = 0.3 moles
Number of moles of CO = 70.0 g/28 g/mol = 2.5 moles
If 1 mole of Fe3O4 reacts with 4 moles of CO
x moles of Fe3O4 reacts with 2.5 moles of CO
x = 0.6 moles
Hence, Fe3O4 is the limiting reactant.
Now;
1 mole of Fe3O4 yileds 3 moles of Fe
0.3 moles of Fe3O4 yileds 0.3 moles * 3 moles/1 mole = 0.9 moles
Mass of Fe produced = 0.9 moles * 56 g/mol = 50.4 g
Percent yield = 41.9 g/ 50.4 g * 100/1 = 83.1%
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Covalent Compounds: Tutorial
QuestOn
The central atom can form the additional double bond with either of the outer atoms. This time, draw the ozone molecule with the double bond on the outer atom on the opposite side of the molecule that you drew in part C.
The Lewis structure of the ozone molecule have been shown in the image attached.
What is the ozone molecule?Three oxygen atoms are fused together to produce the ozone molecule, also referred to as trioxygen. Ozone is its chemical composition. Ozone is a colorless gas with a pungent smell. It is created in the Earth's atmosphere via a number of processes, such as the reaction of oxygen molecules with ultraviolet (UV) light from the sun.
Ozone has three atoms of oxygen and the molecule is bent. We can see this from the attached Lewis structure.
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Which equation is derived from the combined gas law?
StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction.
StartFraction V subscript 1 over T subscript 2 EndFraction equals StartFraction V subscript 2 over T subscript 1 EndFraction.
V subscript 1 T subscript 1 equals P subscript 2 T subscript 2.
P subscript 1 V subscript 1 T subscript 1 equals P subscript 2 V subscript 2 T subscript 2.
The equation derived from the combined gas law is option D: P₁V₁T₁ = P₂V₂T₂. Option D
The combined gas law combines Boyle's law, Charles's law, and Gay-Lussac's law into a single equation that relates the pressure, volume, and temperature of a gas sample. It allows us to analyze changes in these variables while keeping the amount of gas constant.
Boyle's law states that at a constant temperature, the pressure and volume of a gas are inversely proportional. In other words, if the volume of a gas decreases, its pressure increases, and vice versa. This is expressed as P₁V₁ = P₂V₂.
Charles's law states that at a constant pressure, the volume and temperature of a gas are directly proportional. If the temperature of a gas increases, its volume increases, and vice versa. This is expressed as V₁/T₁ = V₂/T₂.
Gay-Lussac's law states that at a constant volume, the pressure and temperature of a gas are directly proportional. If the temperature of a gas increases, its pressure increases, and vice versa. This is expressed as P₁/T₁ = P₂/T₂.
By combining these three laws, we obtain the combined gas law equation: (P₁V₁)/T₁ = (P₂V₂)/T₂. To eliminate the division, we can cross-multiply to get P₁V₁T₂ = P₂V₂T₁, which can be rearranged as P₁V₁T₁ = P₂V₂T₂.
This equation allows us to calculate the final values of pressure, volume, or temperature when any two of these variables change while the amount of gas remains constant. It is particularly useful in analyzing the behavior of gases under different conditions or when studying gas systems.
Option D
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Answer:
it was A for me.. don't know if this will help
Explanation:
Heliox is a mixture of helium and oxygen gas used to help patients with breathing difficulties. It is also used for scuba diving. The total pressure in a tank of heliox is 208 atm. If the mole fraction of o2 is 0. 220, what is the partial pressure of he in the tank?.
It should be noticed that the mole fraction of all the system's components is 1.
Describe a mole fraction.the proportion between the moles of one component in a solution or other combination and the total moles of all the components.
What is a mole fraction and an illustration of one?In a mixture, a mole fraction is the ratio of molecules of one component. By way of illustration, if the mole fraction of methane in a gas is 0.90, then this implies that 90% of the molecules are methane. Since the amount fractions resemble mole fractions, methane makes up an additional 90% of the mixture.
The mole fraction is calculated in what way?By dividing the solute's moles by all the other molecules in solution, you may determine the solute's mole fraction.
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At a certain temperature, 2.50 g Ca reacts completely in 30.0 seconds. The rate of consumption of Ca is
The rate of consumption of Ca is 0.0833 g/s.
The rate of consumption of Ca can be determined by dividing the mass of Ca consumed (2.50 g) by the time taken for the reaction to occur (30.0 seconds). This gives us a rate of 0.0833 g/s, indicating that 0.0833 grams of Ca are consumed every second during the reaction at the given temperature.
In chemical reactions, the rate of consumption or production of a substance is typically expressed in terms of the change in concentration over time. In this case, since the mass of Ca consumed is given, we can directly calculate the rate of consumption.
It's important to note that the rate of consumption of Ca may vary with temperature and other reaction conditions. The given rate applies specifically to the given temperature and the specific reaction conditions mentioned in the problem.
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SOMEONE HELP WITH THAT THING PLSSS( I also didn’t know what to put as the topic)
Answer:
hope this helps
Explanation:
Water was on earth with the dinosaurs and almost at the very start.
Water starts anywhere from clouds to ponds
I choose ponds, water evaporates from the sun and moves its way through the air being collected into clouds in the atmosphere, clouds are evaporated water molecules, then the water combines to form rain wich then end up on a hill and travel back to a water source or goes into the ground and makes groundwater and if there is enough rain overtime will form a pond.
if δs° = 80.3 j/k for the reaction above, what is s° for bcl3(g)?
The standard molar entropy (ΔS°) for the reaction is given as 80.3 J/K. From this information, the standard molar entropy (S°) for BCl3(g) will be calculated.
The standard molar entropy (ΔS°) of a reaction is a measure of the disorder or randomness of the particles involved in the reaction. It is typically given in units of J/K mol.
To determine the standard molar entropy (S°) for BCl3(g), we need to use the given ΔS° value and apply the appropriate stoichiometric coefficients from the balanced equation.
First, we need to identify the balanced chemical equation that includes BCl3(g). Once we have the equation, we can use the ΔS° value to calculate the S° for BCl3(g) using the equation S° = ΔS°/n, where n represents the stoichiometric coefficient of BCl3(g) in the balanced equation.
By dividing the given ΔS° value of 80.3 J/K by the appropriate stoichiometric coefficient of BCl3(g), we can obtain the standard molar entropy (S°) for BCl3(g). It is important to note that the units of S° will be J/K mol, indicating the amount of disorder or randomness per mole of BCl3(g).
Using this approach, the standard molar entropy (S°) for BCl3(g) can be determined based on the given ΔS° value and the stoichiometric coefficient of BCl3(g) in the balanced equation.
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a student heats a sample of hydrate once, and the mass of the sample and the evaporating dish is 17.296 g. after a second heating cycle, the mass of the sample and the dish is 14.025 g. the student stops the heat/cool/weigh cycle after the second time. if the original mass of the evaporating dish and the hydrate was 29.936 g, and the mass of the evaporating dish alone was 1.61 g, what is the mass of water removed from the sample by heating? provide your response to three digits after the decimal.
Water weighs is 12.371 g.
What is the amount of water that was heated out of the sample?Mevoporation dish weighs 1.135 g.
Mevoporating dish plus a sample of MHydrate equals 25.637g
Mfirst heated sample plus Mevoporating dish = 16.428g
Mevoporation dish plus a second hot sample equals 13.266g
Salt hydrate mass:Serving of mevoporating = 1.135g
Mhydrated sample + Mevoporating dish = 25.637g
Mevoporating dish g = 25.637-1.135g=24.502g where Mhydrate sample is equal to 25.637g.
Anhydrous salt mass:Serving of mevoporating = 1.135g
Second heated sample from a mevoporating dish weighs 13,266g
Msalt anhydrous = Msecond heated sample = 13.266-Mevoporating dish g = 13.266-1.135g = 12.131g
Volume of water:Msalt anhydrous = 24.502-12.131g=12.371g where Mwater = Mhydrate sample
12.371 g for Mwater
The sample and the dish have a combined mass of 13.266 g following a second heating session. After the second time, the pupil ends the heat/cool/weigh cycle.
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which element has the electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f7
Answer:
Lawrencium (Lr)
Explanation:
The element with the given electron configuration is Lawrencium (Lr), which has an atomic number of 103.
Match up the characteristics below with the type of molecular bond they describe. Bonds found in Halite (between Na+ and Cl-) Bonds found between Si and O in the Si-O tetrahedron Bonds inside the water molecule (between the H and O ) Bonds that exist between two water molecules Strongest bond type Weakest bond type Bonds that are used by water to dissolve sal
The characteristics and the type of molecular bond they describe:
1. Bonds found in Halite (between Na⁺ and Cl⁻): Ionic bond
2. Bonds found between Si and O in the Si-O tetrahedron: Covalent bond
3. Bonds inside the water molecule (between the H and O): Covalent bond
4. Bonds that exist between two water molecules: Hydrogen bond
5. Strongest bond type: Covalent bond
6. Weakest bond type: Van der Waals bond
7. Bonds that are used by water to dissolve salt: Ionic bond
The ionic bond is a type of molecular bond found in halite (between Na⁺ and Cl⁻). The Si-O tetrahedron is held together by a covalent bond. The bond inside the water molecule (between the H and O) is also a covalent bond. The hydrogen bond is the type of bond that exists between two water molecules. The covalent bond is the strongest bond type, while the van der Waals bond is the weakest bond type. Water uses the ionic bond to dissolve the salt.
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If 1.2mol of methane (CH4) combusts, how much carbon dioxide will be produced? (round to tenth)
CH4 + 2O2 -> CO2 + 2H2O
1.2 moles of methane will produce 1.2 mol of carbon dioxide.
To determine the amount of carbon dioxide (CO2) produced when 1.2 mol of methane (CH4) combusts, we need to use the stoichiometry of the balanced chemical equation.
From the balanced equation:
CH4 + 2O2 → CO2 + 2H2O
We can see that one mole of methane reacts with one mole of oxygen to produce one mole of carbon dioxide and two moles of water. To find the amount of carbon dioxide produced, we will set up a proportion based on the stoichiometric ratio:
1 mol CH4 / 1 mol CO2 = 1.2 mol CH4 / x mol CO2
Cross-multiplying and solving for x, we get:
x = (1 mol CO2 / 1 mol CH4) * 1.2 mol CH4
x = 1.2 mol CO2
Therefore, 1.2 moles of methane will produce 1.2 mol of carbon dioxide.
It is important to note that stoichiometry calculations involve the use of balanced chemical equations to determine the molar ratios between reactants and products. These ratios allow us to calculate the amounts of substances involved in a chemical reaction.
In this case, by applying the stoichiometry concept, we determined that 1.2 mol of methane will produce 1.2 mol of carbon dioxide. This means that for every mole of methane that combusts, an equal amount of carbon dioxide is produced according to the balanced equation.
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AM radio waves travel a shorter distance than FM radio waves.
True
False
The blood pools in the ___ vessels in those areas if they are not exposed to some kind of pressure.
A. small
B. faster
Answer:
A
Explanation:
It's smaller hole
Answer:
I would say A.
Explanation:
This carbocation rearranges. Draw the carbocation that is the result of the rearrangement. Include any nonzero formal charges in your drawing.
Carbocation rearrangements can be defined “as the movement of the carbocation from an unstable state to a more stable state by making use of different structural reorganizational shifts within the molecule”. Alkyl carbocation is a carbocation comprising an alkyl group.
Carbocation Rearrangement occurs whenever the alcohols are converted into several carbocations and this phenomenon is termed as carbocation rearrangement. In simple carbocation comprises +ve charge in a molecule that is connected to 3 more groups and holds a sextet. Carbocation rearrangement can be carried out to a reaction that does not involve alcohol. There are 2 types of carbocation rearrangements namely Alkyl and Hybrid Shift.
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a sample of methane gas is placed in a 3.7 l container at 47oc, the pressure is 0.497 atm. how many moles of ch4 gas is present?
The container contains about 0.697 molecules of CH4 gas.
We must apply the Gas Laws, whose says that PV = nRT, wherein P is just the pressures, Divided by the volume, n represents the size of molecules, R is the classical physics characteristic, and T is the absolute temperature in kelvin, to determine how many moles of CH4 gas are contained in the container.
The temperature must first be converted to Celsius to Kelvin using the formula: 47°C Plus 273.15 Equals 320.15 K.
The molar mass can then be determined using the Ideal Gas Law:
n = (PV)/(RT) = (0.497 as of now * 3.7 L)/(0.0821/molK * 320.15 K) ≈ 0.697 pinches
Therefore, the amount of CH4 methane in the container is roughly 0.697 moles.
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a car tire has a pressure of 2.38 atm at 25.3 degrees c. if the pressure inside reaches 4.08 atm, the tire will explode. how hot would the tire have to get for this to happen? report your answer in celsius.
The tire would have to reach approximately 16.83 degrees Celsius for it to explode when the pressure inside reaches 4.08 atm.
To find out how hot the tire would have to get for it to explode when the pressure inside reaches 4.08 atm, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
First, let's convert the given pressure values to absolute pressure in atmospheres. We know that atmospheric pressure is 1 atm, so the pressure inside the tire at 25.3 degrees C is 2.38 atm + 1 atm = 3.38 atm, and the pressure for explosion is 4.08 atm + 1 atm = 5.08 atm.
Next, we can rearrange the ideal gas law equation to solve for temperature: T = PV / nR.
Assuming the volume, number of moles, and gas constant remain constant, we can set up the following proportion:
(P1 * T1) / (P2 * T2) = (V1 * n1 * R1) / (V2 * n2 * R2)
Plugging in the values, we get:
(3.38 atm * 25.3 C) / (5.08 atm * T2) = 1
Now, we can solve for T2, which is the temperature in Celsius at which the tire would explode:
(3.38 * 25.3) / 5.08 = T2
T2 ≈ 16.83 C
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True or Flase: dissolving salt in distilled water creates a homogeneous mixture.
Answer:
true
Explanation:
Answer:
true
Explanation:
because the dissolved salt is evenly distributed throughout
A 0.035 M solution of ammonia has a pH of 11.33. Calculate Kb for ammonia.
With the formula NH3, ammonia is a nitrogen and hydrogen inorganic chemical.
Thus, Ammonia, the simplest pnictogen hydride and a stable binary hydride, is a colourless gas with a strong, pungent odour. It contributes considerably to the nutritional demands of terrestrial creatures by serving as a precursor to 45% of the world's food and fertilizers.
Biologically, it is a common nitrogenous waste, especially among aquatic animals.
The production of fertilizers in a variety of shapes and compositions, including urea and diammonium phosphate, uses about 70% of ammonia.
Thus, With the formula NH3, ammonia is a nitrogen and hydrogen inorganic chemical.
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what is the wavelength (in nm) of light with a frequency of- ^^ see picture
Frequency =6.75×10^14s^{-1}
\(\\ \sf\longmapsto \lambda=\dfrac{c}{v}\)
\(\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8m/s}{6.75\times 10^{14}s^{-1}}\)
\(\\ \sf\longmapsto \lambda=0.444\times 10^{-6}m\)
\(\\ \sf\longmapsto \lambda=0.4\mu m\)
What type of chemical reaction is the following? BaCl2(aq) + Na2SO4(aq)
→ BaSO4(s) + 2 NaCl(aq) *
Answer:
it's a precipitation reaction.
Explanation:
since a solid is produced, one of the elements are insoluble with one another–making a precipitate.
The science of classifying and naming organisms based on their different characteristics is called _________.
Answer:
taxonomy
Explanation:
Answer:
Taxonomy
Explanation:
The taxonometric way of classifying organisms is based on similarities between different organisms. A biologist named Carolus Linnaeus started this naming system. He also chose to use Latin words.
What is the mass number of sodium
Answer:
Explanation:
Sodium mass number 23, 11 electrons
Magnesium: neutrons = 12
aluminum : atomic number = 13
phosporus : protons = 15
Answer:
23
Explanation:
You need to add protons and neutrons to get mass
Is a salt obtained as a reaction between a base and an acid?
To answer if a salt is formed between the reaction of a base and an acid, we need to remember that, if we react a strong acid and a strong base, such as HCl and NaOH, two products will be formed: the appropriate salt and water.
In the example above, we can write the reaction as:
HCl + NaOH -> NaCl + H2O
where a strong acid and a strong base react to form a salt (NaCl) and water (H2O).
Thus, we can say that, yes, a salt is formed when an acid and a base react between each other.
In order for the process to be endothermic, the energy required to break the lattice has to be _______ than the energy released as the ions go into solution.
a. Greater
b. Less
Explanation:
I honestly believe the answer is greater
If the energy required to break the lattice is less than the energy released as the ions go into solution, then the dissolution of solute is endothermic.
An endothermic reaction is one in which energy is absorbed. This implies that the energy change of the reaction is positive.
Now, if the energy required to break the lattice is less than the energy released as the ions go into solution, then the process is endothermic and energy is absorbed.
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during petroleum refining, catalysts play an extremely important role during the
Catalytic Cracking: Catalytic cracking is a process used to break down heavier hydrocarbon molecules into lighter fractions such as gasoline.
Hydrocracking: Hydrocracking is a process that combines catalytic cracking with hydrogenation. It is used to convert heavy hydrocarbons into lighter, more valuable products. Catalysts, such as metal sulfides or noble metals supported on a porous material, are employed to promote the cracking reactions and enable the addition of hydrogen to saturate unsaturated hydrocarbons.
Catalytic Reforming: Catalytic reforming is a process used to convert low-octane naphtha into high-octane gasoline blending components. Catalysts based on platinum or platinum-rhenium are utilized to promote the isomerization, dehydrogenation, and cyclization reactions that enhance the octane rating of the naphtha.
Hydrotreating: Hydrotreating is a process that removes impurities, such as sulfur, nitrogen, and metals, from petroleum feedstocks. Catalysts containing metals like nickel or molybdenum supported on alumina or other materials are used to promote the hydrogenation of these impurities, resulting in cleaner and more environmentally friendly fuels.
Desulfurization: Desulfurization is a specific type of hydrotreating that focuses on the removal of sulfur compounds from petroleum products, particularly diesel fuel. Catalysts based on metals such as cobalt and molybdenum are employed to facilitate the hydrodesulfurization reaction, which converts sulfur compounds into hydrogen sulfide.
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Calculate the simplest or empirical formula of a substance with
0.5540 grams of potassium (K) and 0.1701 grams of oxygen (O).
Answer:
Explanation:
mass of potassium: 0.5540g
mass of oxygen: 0.1701g
molecular mass of potassium: 39.10g/mol
molecular mass of oxygen: 16.00g/mol
First divide mass of potassium and oxygen by their respective molecular masses.Divide answer by least value obtained from first stepk o
\(\frac{0.5540}{39.10}\) \(\frac{0.1701}{16.00}\)
0.0142 0.0106
\(\frac{0.0142}{0.0106}\) \(\frac{0.0106}{0.0106}\)
1.34=1.00 1
Empirical formula, EF = KO
his image shows the rock cycle.Which event most likely occurs at point V?
Why is it important for us to show demonstrations and give evidence for our scientific claims?
Please help me this is due today!!!!
Answer:
Well first, a scientific claim is claims or statements after experimenting. Similar to other claims but they have evidence and data to support the claim.
So we would show demonstrations because we need support our scientific claim.
A singly ionized Nickel atom has an overall charge of +1e (where e ~ 1.602 x 10-19 C) and a mass, m = 9.80 x 10-26 kg. It travels to the right with speed v. It then enters a region containing a uniform magnetic field of magnitude 0.3 T directed into the page. (a) Draw a diagram of the system including the path of the Nickel atom (be certain of the direction of deflection. (b) If the radius of the particle
The radius of the circular path of the Ni+ ion is r = 3.27 x 10⁻⁶ v meters proportional to its velocity v. The diagram has been attached below.
What is Lorentz force?Lorentz force refers to the force experienced by a charged particle in an electromagnetic field. It is named after the Dutch physicist Hendrik Lorentz who first described this force in 1892. The force arises from the interaction between the magnetic and electric fields that may be present in the vicinity of a charged particle.
The Lorentz force on a charged particle is given by the vector product of its velocity and the magnetic field, as well as by the scalar product of its charge and the electric field. The Lorentz force equation is:
F = q(E + v x B)
a) The diagram shows the direction of travel (v) and the charge (+1e) of the singly ionized Nickel atom (Ni+), as well as the uniform magnetic field (B) directed into the page. The path of the Ni+ ion is perpendicular to both v and B, and is deflected in a circular path due to the Lorentz force.
(b) The radius of the particle can be calculated using the equation for the Lorentz force:
F = qvB
where F is the force on the particle, q is the charge, v is the velocity, and B is the magnetic field. Since the force is perpendicular to both v and B, the path of the particle is circular.
The centripetal force on the particle is provided by the magnetic force, so we can equate the two:
F = ma = mv²/r
where m is the mass of the particle, a is the centripetal acceleration, and r is the radius of the circular path.
Combining these two equations, we get:
qvB = mv²/r
Solving for r, we get:
r = mv/qB
Substituting the values given, we get:
r = (9.80 x 10⁻²⁶ kg)(v)/(1e)(0.3 T)
r = 3.27 x 10⁻⁶ v meters
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