A certain thin one-dimensional rod has a length of L and a non-uniform density, which is given by the following function (assume x=0 corresponds to the left end of the rod): Show work Answers are given below: Q1) Find the rod’s center of mass as a function of . 3L/4 Q2) Find the moment of inertia for the rod if it is rotated about its midpoint (). L5/210

The normal force exerted by the lawn on the mower is 137.2 N.

To find the normal force exerted by the lawn on the mower, first we need to understand that there are two forces that are acting upon the mower.

The force applied by the gardener, F = 62 N

Weight of the lawn mower, W = mg = 18 kg × 9.81 m/s² = 176.58 N

The force applied by the gardener is not exactly perpendicular to the ground, so we need to find the component of the force perpendicular to the ground.

This can be done using the formula: F⊥ = F sinθ whereF is the force applied by the gardener andθ is the angle between the handle of the mower and the surface of the lawn.

Substituting the values:F⊥ = 62 sin 41.0°F⊥ = 39.4 N

Now that we have the force perpendicular to the ground, we can find the normal force exerted by the lawn on the mower using the formula: F⊥ + N = WwhereN is the normal force exerted by the lawn on the mower.

Substituting the values:N = W - F⊥N = 176.58 - 39.4N = 137.2 N

Therefore, the normal force exerted by the lawn on the mower is 137.2 N.

Answer: The normal force exerted by the lawn on the mower is 137.2 N.

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“There is no centre of the universe! According to the standard theories of cosmology, the universe started with a "Big Bang" about 14 thousand million years ago and has been expanding ever since. Yet there is no centre to the expansion; it is the same everywhere”.

Answer:

There is no center of the universe.

Explanation:

According to scientists, the universe started with a "Big Bang" millions of years ago and has been expanding ever since.

The chi-square test assumes that the variables being analyzed are measured at a nominal or ordinal level of measurement.

In statistics, the level of measurement refers to the nature and properties of the data being collected. There are four levels of measurement: nominal, ordinal, interval, and ratio. Nominal and ordinal levels are considered categorical, while interval and ratio levels are considered numerical. The chi-square test is specifically designed for analyzing categorical data, where the observations can be classified into distinct categories or groups. It is used to determine whether there is a significant association or relationship between two categorical variables.

The test calculates the difference between the observed frequencies and the expected frequencies under the assumption of independence between the variables. It compares the observed and expected frequencies using a chi-square statistic and determines the p-value to assess the statistical significance of the association. Therefore, the chi-square test assumes that the variables being analyzed are measured at a nominal or ordinal level because it deals with categorical data and evaluates the relationship between different categories or groups.

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Answer: The x-component of the total force 97N

Explanation:

Given the following :

Mass (M) of skier = 73.9 kg

Pull force on the skier = 105N

Angle of pull = 22.5°

The direct backward force directly pulling the skier = 74.8N

the x-component of the total force on the skier

The horizontal component of the force = Magnitude of the pulling force × cosine of the angle of pull (FCosΘ)

FCosΘ = 105cos22.5°

105cos22.5 = 105 × 0.9238795

= 97.007350

= 97N

The backward force acting directly backward = 74.8N

Therefore, net x - component of the total force equals ;

97N - 74.8N = 22.2N

Answer: Ham radio

Explanation:

The helicopter of mass `m` requires a force to move in an upward direction with an acceleration of `a = 0.10g`, where `g` is the acceleration due to gravity.

The force required can be calculated as follows:

\(`F = m x 0.10g`\)

For an upward direction, the force required is greater than the weight of the helicopter, which acts downwards. The weight of the helicopter is given by `W = mg`, where `g = 9.81 m/s²` (acceleration due to gravity).

Substituting the value of `g` into the equation, we have:

\(`W = mg = m × 9.81 m/s²`\)

Therefore, the magnitude of the force required to give the helicopter of mass `m` an acceleration of `0.10g` upward is:

\(`F = m x 0.10g = m x 0.10 × 9.81 m/s² = 0.981m N`\)

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Communications satellites would fly off in a straight line never to be see again if it were not for a force from the earth, The moon "falls" from a straight line because there IS some attraction toward the Earth.

The satellite will tend to move tangential to the initial orbit without the assistance of centripetal force at the same speed as it did just before the gravitational field vanishes. As a result, the spacecraft will veer off course and leave its orbit.

The combined gravitational force of acts on the mass in your body. What gives you weight is that. Additionally, you would weigh less than you do now if you were on a planet with a lower mass than Earth. You make the same gravitational force on Earth that it does on you.

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The current through the 2Ω resistor is 9.5A

The terminal voltage is 10.8 V

a) The voltage V across 8 Ω resistor is V = I*R = 8*0.5 = 4V

the current through 16Ω resistor is then I = V/R = 4/16 = 0.25 A

the current through 20Ω resistor is then I = current through 8Ω resistor + current through 16Ω resistor = 0.75 A

voltage across 20Ω is V = I*R = 0.75*20 = 15 V

the source voltage is Vs = V8 + V20 = 4+15 = 19 V

therefore the current through 2Ω resistor is

I = V/R = 19/2 = 9.5 A

b) The terminal voltage is

Vterminal = VR = I*R = 0.450*24 = 10.8 V

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To react completely with 0.500 L of volume of 0.500 M Na2CO3, you would need 0.250 L of 2.00 M HCl.

Write down the balanced chemical equation for the reaction between HCl and Na2CO3:

2 HCl + Na2CO3 → 2 NaCl + H2O + CO2

Determine the stoichiometry of the reaction:

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Na2CO3.

Calculate the number of moles of Na2CO3:

Given that the volume of Na2CO3 solution is 0.500 L and the concentration is 0.500 M, we can use the formula:

Moles = Concentration × Volume

Moles of Na2CO3 = 0.500 M × 0.500 L = 0.250 moles

Use the stoichiometry to determine the number of moles of HCl needed:

According to the stoichiometry of the balanced equation, 1 mole of Na2CO3 reacts with 2 moles of HCl.

Therefore, to react with 0.250 moles of Na2CO3, we would need 2 × 0.250 = 0.500 moles of HCl.

Convert moles of HCl to volume:

Given that the concentration of HCl is 2.00 M, we can use the formula:

Volume = Moles / Concentration

Volume of HCl = 0.500 moles / 2.00 M = 0.250 L

Convert the volume to liters:

The final answer is 0.250 liters of 2.00 M HCl are needed to react completely with 0.500 L of 0.500 M Na2CO3.

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The can be obtained by using the balanced chemical equation: Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2  Write the balanced chemical equation for the reaction.

Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2

Calculate the number of moles of Na2CO3. Using the formula n = c × V, where n is the number of moles, c is the concentration, and V is the volume, we get:

n = c × V

= 0.500 M × 0.500 L

= 0.250 mol

Calculate the number of moles of HCl required.The balanced chemical equation shows that 2 moles of HCl react with 1 mole of Na2CO3. Hence, the number of moles of HCl required can be calculated as follows

:n(HCl) = 2 × n(Na2CO3)

= 2 × 0.250 mol

= 0.500 mol

Calculate the volume of 2.00 M HCl required.The number of moles of HCl required is 0.500 mol. Using the formula V = n/c, where V is the volume, n is the number of moles, and c is the concentration, we get:

V = n/c

= 0.500 mol ÷ 2.00 M

= 0.250 L

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If a wave having a wavelength of 4.0 meters and an amplitude of 2.5 meters travels a distance of 24 meters in 8.0 seconds, the frequency of the wave would be 0.75 Hz.

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

As given in the problem a wave having a wavelength of 4.0 meters and an amplitude of 2.5 meters travels a distance of 24 meters in 8.0 seconds.

The number of waves in 24 meters = 24 / 4

                                                          = 6 waves

The number of waves that travels in 8 seconds = 6

The number of waves that travel in 1 second = 6 / 8

                                                                      = 0.75

Thus, the frequency of the wave would be 0.75 Hz.

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Answer:

\(\displaystyle KE = 32 \ J\)

General Formulas and Concepts:

Energy

Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2}mv^2\)

Explanation:

Step 1: Define

Identify variables

m = 2 kg

v = 4 m/s

Step 2: Find KE

Topic: AP Physics 1 - Algebra Based

Unit: Energy

Answer:

Beryllium chloride

Explanation:

I hope this helps!

Can I get branliest?!

a. The capacitance of a portion of a circuit is to be reduced from 4000 pF to 1600 pF can be added to the circuit to produce the effect without removing existing circuit elements is 2666.67 pF.

b. Any existing connections must not need to be broken to accomplish this.

To reduce the capacitance of a portion of a circuit from 4000 pF to 1600 pF, we can add another capacitor in series with the existing capacitor. This is because the total capacitance of capacitors in series is given by the formula:

1/Ctotal = 1/C1 + 1/C2

Where Ctotal is the total capacitance, C1 is the capacitance of the first capacitor, and C2 is the capacitance of the second capacitor.

We can rearrange this formula to solve for C2:

1/C2 = 1/Ctotal - 1/C1

Substituting the given values:

1/C2 = 1/1600 pF - 1/4000 pF

1/C2 = 0.000625 - 0.00025

1/C2 = 0.000375

C2 = 1/0.000375

C2 = 2666.67 pF

Therefore, a capacitor with a capacitance of 2666.67 pF can be added in series with the existing 4000 pF capacitor to reduce the total capacitance to 1600 pF. And no existing connections need to be broken to accomplish this.

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The new (resultant) vector could be written as 0 m, since the vectors cancel each other out. The vector going 5 m West is cancelled out by the vector going 5 m East, and the vector going 11 m West is cancelled out by the vector going 11 m East. This means that the final result is a vector with a magnitude of 0 and no direction.

The exhaust brake prevent the tow vehicle from going too fast and it reduces the likelihood of an accident. Automatic Exhaust Brake is  maintains vehicle speed.

Exhaust brakes prevent vehicles from going downhill too fast. Automatic Smart Exhaust Brake delivers smoother, less aggressive exhaust braking characteristics during the downhill descents.

It does not apply obvious braking if the vehicle speed is not increasing. Automatic Exhaust Brake is  maintains vehicle speed, whereas Full Exhaust Brake is intended to reduce vehicle speed.

Exhaust brake is a means of slowing diesel engine by closing off the exhaust path from engine and causing exhaust gases to be compressed in the exhaust manifold and in cylinder.

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Answer:

dyow

Explanation:

sorrrey

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Current of the Device is 3.0 Ampere . The Resistance is given as 6.0 Ohm's . And, we have been asked to calculate the Potential Difference .

As we know ,

Where ,

Therefore , by Substituting the given values in the above Formula :-

\( \sf {\dag \: \: \: Potential \: Difference \: = \: Current \: \times \: Resistance} \)

\( \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3.0 \: \times \: 6.0} \)

\( \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3 \: \times \: 6} \)

\( \bf {\Longrightarrow \: \: \: \bf {Potential \: Difference \: = \: 18 \: }} \)

Hence :-

\( \underline {\rule {210pt}{4pt}} \)

Additional Information :-

\( \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} \)

\(\Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } \)

\(\Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } \)

\( \underline {\rule {210pt}{4pt}} \)

Note :-

Answer:

3. There would be no sound.

Explanation:

Sound is produced by vibrations that travel through a medium, most commonly through air.

If there is no matter to vibrate (such as in the vacuum of space) then there's no way for a sound wave to be produced.

Thus the answer is option 3. There would be no sound.

      The sum of the forces exerted on an object must be zero since, in accordance with Newton's first law of motion, an object moving at a constant speed experiences no net external force. F net = 0 F net = 0 or F = 0 are two ways to express mathematically that an object is not being affected by any net external forces.

First Law of Newton: Inertia

According to Newton's first law, unless pushed to alter its condition by the operation of an external force, every object will continue to be at rest or in uniform motion in a straight line. Inertia is the propensity to resist changes in a condition of motion.

He second equation swaps out p for mv since p=mv. V stands for the object's speed, t stands for time, and F stands for force.

Newton's second law of motion uses the inertia formula "Force = Mass * Acceleration" to describe this phenomena and property. According to the formula, heavier objects need greater force to modify their acceleration.

Newton's first law is demonstrated by the motion of a ball falling through the atmosphere or by the firing of a miniature rocket into the atmosphere. The first law can also be used to explain how a kite moves as the wind changes.

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The value of x, y, and z in the equation for F is x = 1, y = 1/2, and z = 2.

To use the method of dimensions, we need to first identify the fundamental dimensions involved in the problem. The fundamental dimensions in this problem are:

Length (L)

Mass (M)

Time (T)

Now let's consider each term in the equation for F:

K is non-dimensional, so it doesn't have any fundamental dimensions.

a has dimensions of length (L).

p has dimensions of mass per unit volume, or density, which is mass (M) divided by length cubed (L³).

v has dimensions of length per unit time, or velocity, which is length (L) divided by time (T).

Using these fundamental dimensions, we can write the dimensional formula for each term in the equation for F:

[F] = M L T⁻² (force)

[K] = 1 (dimensionless)

[a] = L

[p] = M L⁻³

[v] = L T⁻¹

Substituting these dimensional formulas into the equation for F, we get:

M L T⁻² = \((KL)^x (ML^{-3})^{y} (LT^{-1}})^{z}\)

Simplifying, we can rewrite this as:

M L T⁻² = K \(M^y L^{x-3y+z} T^{-z}\)

Equating the dimensions of both sides, we get the following system of equations:

\(M = K M^{y}\)

Solving for x, y, and z, we get:

x = 1

y = 1/2

z = 2

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Operators must have unobstructed access to a ladder for escape from a trench within a distance of 25 feet.
According to OSHA regulations, operators must have unobstructed access to a ladder for escape from a trench within 25 feet. So, the correct answer is c 25 feet.

According to OSHA Occupational Safety and Health Administration, employers must provide ladders, steps, ramps, or other safe means of egress for workers working in trench excavations 4 feet 1.22 meters or deeper1. The means of egress must be located so as not to require workers to travel more than 25 feet 7.62 meters laterally within the trench1. Therefore, the answer is c 25 feet. Operators must have unobstructed access to a ladder for escape from a trench within 25 feet. So, the correct answer is c 25 feet

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Answer:

E = V / d       125 V / .018 m = 6940 V/m     electric field

F = E Q       force on Q due to E

F = E n e     where n is the number of electrons in Q

m g = E n e

n = m g / E e     where n is the number of electrons e needed to support drop

n = 1.6 * 10E-16 * 9.8 / (6940 * 1.6 * 10E-19)

n = 1.41

Since n needs to be an integral number of charges, the drop would

not be suspended (motionless under these conditions).

The statements best describes how a star chart should be held while facing north is, The edge of the map labeled south should be held towards the observer.

What is star chart ?

A map or diagram of the stars and other celestial bodies in the sky is called a star chart. The locations of the stars, constellations, planets, and other celestial bodies are often displayed at a certain time and location on Earth. Star maps can be used to locate celestial bodies in the night sky, to organise astronomical observations, or to track their movements through time.

Given that,

The statements,

In between following options, best describes how a star chart should be held while facing north is,

The edge of the map labeled south should be held towards the observer

This is because when facing north, the direction labeled "south" on the map should correspond to the direction of the actual south, and thus be facing the observer.

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The magnitude of the acceleration due to gravity on planet p is 5 meters per seconds squared.

From the Second Equation of Motion;

s = ut + (1/2)gt²

Where v is final velocity, u is initial velocity, g is acceleration due to gravity and t is time elapsed.

Given the data in the question;

Plug the given data in the above formula and solve for g.

s = ut + (1/2)gt²

40m = (0 × 4s) + ( (1/2) × g × (4s)²

40m =  (1/2) × g × 16s²

Multiply both sides by 2

2 × 40m = 2 × (1/2) × g × 16s²

80m = g × 16s²

g × 16s² = 80m

g = 80m / 16s²

g = 5m/s²

Therefore, the acceleration due to gravity is 5m/s².

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Answer:

The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

Note:

Please mark as Brainliest, or i'll go to your house and kidnapp your family, lol

(it's a joke btw)

Answer:The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

Explanation:Formula of Net Force

FN is the force acting on a body. When the body is at rest, the net force formula is given by, FNet = Fa + Fg.

I think that's correct

Explanation:

a) E= fs

b) 2E = mv²

c) E= Mc ²

The charges may be positive or negative. However, the behavior of the charges depend on the position of like charges and unlike charges.

An electrical charge may be positive or negative. We must recall that a charge may attract or repel another charge. According to the first law of electrostatics, like charges repel while unlike charges attract.

The image is not shown here however, the behavior of the charges depend on the position of like charges and unlike charges.

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Answer:

Angle of diffraction for second order maxima is θ = 18.941°

Explanation:

From the question it is given that

wavelength of incident light = λ = 541 nm = 541 x \(10^-^9 m\)

order of maxima = n =2

diffraction grating has 600 lines per mm

⇒ distance between two slit is \(\frac{1mm}{600}\) = 1.66 x \(10^-^6\) m

using the relation of Braggs diffraction formula i.e.,

2dsinθ = nλ ..................................(1)

where, d = distance between two lines of grating

θ is the angle of diffraction

n= order of maxima

λ is the intensity of incident photon

on substituting the respected values in relation (1) we get,

2 x 1.66 x \(10^-^6\)m sinθ = 2 x 541 x \(10^-^9 m\)

⇒ sinθ = 0.3246

⇒ θ = \(sin^-^1(0.3246)\) = 18.941 °

Using 1st equation of kinematics

\(\\ \bull\sf\longmapsto v=u+at\)

\(\\ \bull\sf\longmapsto v=0+0.25(180)\)

\(\\ \bull\sf\longmapsto v=45m/s\)

⇛Initial velocity (u) = 0 m/s

⇛Acceleration (a) = 0.25 m/s²

⇛Time (t) = 3 minutes

⇛Final velocity (v) = v

Converting 3 minutes into seconds

\( \Large\begin{gathered} {\underline{\boxed{ \rm {\red{v \: = \: u \: + \: at}}}}}\end{gathered}\)

\( \bf \large \longrightarrow \: \: v \: = \: 0 \: + \: 0.25 \: \: (180)\)

\(\bf \large \longrightarrow \: \: v \: = \:45 \: m/s\)