a car with a mass of 1000kg is going at 20m/s and then stops in 25m. what was its change in kinetic energy?

Answer:

d. The region was already known to have very small rocks called "blueberries" that likely formed in liquid water.

Explanation:

The above is th reason why the landing site happens to be called the Meridiani Planum. This is because, the small rocks called blueberries gives the region a unique view which makes attractive in the Mars landing site.

When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.

The correct answer to the given question is option C.

Potential energy is the energy stored within an object because of its position or configuration.

In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.

As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.

Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.

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Radially outward is both the direction and magnitude of the inertial force. as it is moving uniformly in a circle, from the bob's frame. Radially emanating from the source of the charge is an electric field that is positively charged.

Radially outward means  This is so because an electric field is produced when a positive charge is forced by the field. The electric field pulls the positive charge with a force that is directed away from the charge's origin. It is called  Radially outward.

In physics, magnitude is referred to as an object's maximal size and direction. Both vector and scalar values use magnitude as a common factor. We know that scalar quantities are those that have magnitude and nothing else by definition.

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Answer:

24000

Explanation:

The level of the sound can be decreased by gradually draining the air from a plastic bottle. The sound about an alarm clock cannot be heard at all since sound cannot travel through a vacuum.

A ringing alarm clock will gradually grow quieter when air is gently drawn out of the area around it and placed beneath a glass jar. Because sound is indeed a mechanical wave that moves across a medium, this is the case.

We can hear the sound because the air molecules in the jar shake as sound waves pass through them. The amount of air particles available to vibrate and convey sound waves declines when air is eliminated, which lessens the sound's strength.  There will be so little remaining air to vibrate due to the almost full removal of the air that the sound will be almost undetectable.

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One filter box will be required for the plant expansion, but an alternative design needs to be proposed if the design loading rate is exceeded with one filter box out of service.

To determine the number of filter boxes required, we need to calculate the total surface area required and divide it by the maximum surface area per filter box.

Calculate the total surface area required:

Total surface area = Design flow rate / Design loading rate

Total surface area = 1.2 m³/s × 24 × 3600 s / (575 m³/d × 1 d/24h)

Total surface area = 18.67 m²

Determine the number of filter boxes required:

Number of filter boxes = Total surface area / Maximum surface area per filter box

Number of filter boxes = 18.67 m² / 50 m²

Number of filter boxes = 0.37 (round up to the nearest whole number)

Number of filter boxes = 1 (since we cannot have a fraction of a filter box)

Therefore, one filter box will be required to meet the design loading rate.

To check the design loading with one filter box out of service, we need to recalculate the loading rate:

Calculate the new design loading rate:

New design loading rate = Design flow rate / (Number of filter boxes - 1)

New design loading rate = 1.2 m³/s / (1 - 1)

New design loading rate = Undefined

Since the new design loading rate is undefined when one filter box is out of service, an alternative design should be proposed to ensure that the design loading rate is not exceeded. This could involve increasing the number of filter boxes or redesigning the filtration system to accommodate the required flow rate.

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The formula for torque is T = F x r, where T is torque, F is force, and r is radius.  Therefore, the answer is C. 6,000 N-m.

The torque around the center of the wheel can be calculated using the formula:

Torque = Force x Radius

where Force is the force applied to the wheel, and Radius is the distance from the center of the wheel to the point where the force is applied.

In this case, the force applied to the wheel is 300 N, and the radius of the wheel is 20 m. Therefore, the torque around the center of the wheel can be calculated as:
Torque = 300 N × 20 m = 6,000 N-m

So, the correct answer is C. 6,000 N-m.

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(a) The efficiency of the generator at rated load can be calculated using the following formula:

Efficiency = Output power / Input power

At rated load, the output power of the generator is 15 MW (given in Problem 4-2) and the input power can be calculated using the formula:

Input power = Field current x Armature current x Generator voltage x Power factor

Assuming the power factor to be 0.9 lagging, we can calculate the input power as follows:

Input power = 1000 x 15000 x 13.8 x 0.9 = 182.7 MW

Therefore, the efficiency of the generator at rated load is:

Efficiency = 15 / 182.7 = 0.082 or 8.2%

(b) Voltage regulation can be calculated using the following formula:

Voltage regulation = (No-load voltage - Full-load voltage) / Full-load voltage x 100%

Assuming the generator is loaded to rated kilovoltamperes with 0.9-PF-lagging loads, the armature current can be calculated as follows:

Armature current = Kilovoltamperes / (sqrt(3) x Generator voltage x Power factor)

Armature current = 1000 / (sqrt(3) x 13.8 x 0.9) = 50.9 kA

From the open circuit characteristics, we can find the no-load voltage to be 14.3 kV (given in Problem 4-2). Therefore, the voltage regulation is:

Voltage regulation = (14.3 - 13.8) / 13.8 x 100% = 3.62%

(c) Assuming the generator is loaded to rated kilovoltamperes with 0.9-PF-leading loads, the armature current can be calculated using the same formula as in part (b):

Armature current = Kilovoltamperes / (sqrt(3) x Generator voltage x Power factor)

Armature current = 1000 / (sqrt(3) x 13.8 x 0.9) = 50.9 kA

Since the power factor is leading, the generator will have to supply reactive power. This can be done by reducing the field current. Assuming the field current is adjusted to maintain rated voltage, we can find the full-load voltage from the short circuit characteristics. From the short circuit characteristics, we can see that the full-load voltage is 13.4 kV (given in Problem 4-2). Therefore, the voltage regulation is:

Voltage regulation = (14.3 - 13.4) / 13.4 x 100% = 6.72%

(d) Assuming the generator is loaded to rated kilovoltamperes with unity power factor loads, the armature current can be calculated as follows:

Armature current = Kilovoltamperes / (sqrt(3) x Generator voltage)

Armature current = 1000 / (sqrt(3) x 13.8) = 54.2 kA

Since the power factor is unity, the generator will not have to supply or absorb any reactive power. Assuming the field current is adjusted to maintain rated voltage, we can find the full-load voltage from the short circuit characteristics. From the short circuit characteristics, we can see that the full-load voltage is 13.2 kV (given in Problem 4-2). Therefore, the voltage regulation is:

Voltage regulation = (14.3 - 13.2) / 13.2 x 100% = 8.33%

(e) To plot the terminal voltage of the generator as a function of load for all three power factors, we can use MATLAB. Assuming the generator parameters are the same as in Problem 4-2, we can write the following code:

```matlab
% Generator parameters
V = 13.8e3; % Generator voltage
P = 15e6; % Output power
f = 60; % Frequency
Xs = 1.2; % Synchronous reactance
Rs = 0.015; % Synchronous resistance
Xd = 1.6; % Direct-axis reactance
Xq = 1.2; % Quadrature-axis reactance
Rd = 0.02; % Direct-axis resistance
Rq = 0.02; % Quadrature-axis resistance
Tdo = 0.2; % Open circuit time constant
Tqo = 0.2; % Short circuit time constant

% Load parameters
PF_lag = 0.9; % Lagging power factor
PF_lead = 0.9; % Leading power factor
PF_unity = 1; % Unity power factor
KVA = linspace(0, 15000, 1000); % Load range in kVA

% Calculate terminal voltage for lagging power factor
for i = 1:length(KVA)
   Ia = KVA(i) / (sqrt(3) * V * PF_lag);
   E = V + (Rs + 1j*Xs)*Ia + (Xd - Xs)*Ia^2;
   Vt_lag(i) = abs(E);
end

% Calculate terminal voltage for leading power factor
for i = 1:length(KVA)
   Ia = KVA(i) / (sqrt(3) * V * PF_lead);
   E = V + (Rs + 1j*Xs)*Ia - (Xq - Xs)*Ia^2;
   Vt_lead(i) = abs(E);
end

% Calculate terminal voltage for unity power factor
for i = 1:length(KVA)
   Ia = KVA(i) / (sqrt(3) * V);
   E = V + (Rs + 1j*Xs)*Ia + 1j*(Xd - Xq)*Ia;
   Vt_unity(i) = abs(E);
end

% Plot results
plot(KVA, Vt_lag/1000, 'r', 'LineWidth', 2)
hold on
plot(KVA, Vt_lead/1000, 'b', 'LineWidth', 2)
plot(KVA, Vt_unity/1000, 'g', 'LineWidth', 2)
xlabel('Load (kVA)')
ylabel('Terminal Voltage (kV)')
legend('0.9 PF Lagging', '0.9 PF Leading', 'Unity PF')
grid on
```

This code will plot the terminal voltage of the generator as a function of load for lagging, leading, and unity power factors. The plot will show that the voltage regulation increases as the power factor goes from unity to leading to lagging.

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Weight is a measure of how gravity pulls on an object.

Explanation:

Mass is the amount of matter in an object. So mass is constant even if an object is placed on say: Moon. But the Weight is different in different places because gravity changes.

I hope you understood. pls give brainliest if possible. thank you

The net gravitational force on b due to a and c is 5.338 x 10^-8 N.

The net gravitational force on b due to a and c can be calculated using the formula:

F = G (m1m2) / r^2

where;

First, let's calculate the gravitational force between a and b:

F1 = G (m1m2) / r^2

= 6.67 x 10^-11 * (10.0 x 10.0) / (0.50/2)^2

= 1.067 x 10^-7 N

Next, let's calculate the gravitational force between b and c:

F2 = G(m2m3) / r^2

= 6.67 x 10^-11 (10.0 x  15.0) / (0.50/2)^2

= 1.67 x 10^-7 N

The net gravitational force on b due to a and c is the vector sum of these two forces:

Fnet = F2 - F1

= 1.67 x 10^-7 N - 1.067 x 10^-7 N

= 5.338 x 10^-8 N

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Answer:

it will option B,hope it helps

C. The wavelength is longer.

A sound wave is called a longitudinal wave because compressions and rarefactions in the air produce it.

The air particles vibrate parallel to the direction of propagation.

A longitudinal wave consists of a repeating pattern of compressions and rarefactions.

Thus, the wavelength is commonly measured as the distance from one compression to the next adjacent compression or the distance from one rarefaction to the next adjacent rarefaction.

Longitudinal waves move through a medium from the point of the disturbance in the form of compressions (where particles of the medium are bunched together) followed by rarefactions (where particles of the medium are farther apart).

In longitudinal waves, the distance from one compression to the next is the wavelength.

Therefore,

In longitudinal wave the wavelength is longer.

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Answer:

spread and go up

Explanation:

like water when hot gas when cold ice when warm liquid

The change in free energy for the hydrolysis of ATP can be calculated using the equation ΔG = ΔH - TΔS, where ΔG is the change in free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.

To calculate ΔG for the hydrolysis of ATP in tissues at 37°C, the values of ΔH and ΔS must be known. At 37°C, the temperature must be converted to Kelvin (T = 37 + 273 = 310 K).

The specific values of ΔH and ΔS are required to determine the ΔG for the hydrolysis of ATP in tissues and can be obtained from thermodynamic databases or literature. Without these values, the ΔG cannot be calculated.

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(A)Gravitational potential energy GPE does the rock have initially 2674.92 Joules,(B) As the rock is halfway down, it has lost its entire GPE and converted it into KE. So, the KE will be equal to the GPE at this point i.e.1337.96J (C).The rock will be traveling at a speed of approximately 20.15 m/s when it is halfway down.

(A) The gravitational potential energy (GPE) of the rock initially can be calculated using the formula:

GPE = mgh

where:

m = mass of the rock = 6.6 kg

g = acceleration due to gravity = 9.8 m/s²

h = height of the cliff = 44.5 m

Plugging in the values:

GPE = 6.6 kg × 9.8 m/s² × 44.5 m = 2,674.92 J (Joules)

So, the rock initially has 2,674.92 Joules of gravitational potential energy.

(B) When the rock is halfway down, its height would be half of the original height, i.e., h/2 = 44.5 m / 2 = 22.25 m.

The gravitational potential energy (GPE) of the rock when it is halfway down can be calculated using the formula mentioned above:

GPE = mgh

where:

m = mass of the rock = 6.6 kg

g = acceleration due to gravity = 9.8 m/s²

h = height when halfway down = 22.25 m

Plugging in the values:

GPE = 6.6 kg × 9.8 m/s² × 22.25 m = 1,337.96 J (Joules)

The kinetic energy (KE) of the rock when it is halfway down can be calculated using the formula:

KE = (1/2)mv²

where:

m = mass of the rock = 6.6 kg

v = velocity of the rock

As the rock is halfway down, it is lost, its entire GPE and converted it into KE. So, the KE is equal to the GPE at this point.

KE = 1,337.96 J (Joules)

(C) To calculate the velocity (v) of the rock when it is halfway down, we can equate the KE to the formula for kinetic energy:

KE = (1/2)mv²

Plugging in the values:

1,337.96 J = (1/2) ×6.6 kg × v²

v² = (2 × 1,337.96 J) / 6.6 kg

v² = 406.32 m/s

v = √(406.32 m/s) = 20.15 m/s

So, the rock is traveling at a speed of approximately 20.15 m/s when it is halfway down.

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When the whole mass accelerates together as a single entity, the acceleration of the system is 0.62 m/s²

To determine the acceleration of the system, the mass on one end of the rope must be subtracted from the mass on the other end of the rope.

The mass of each child is 30 kg. The number of children is 13.

Therefore, 30 x 13 = 390 kg is the total mass of the children.

The mass of each parent is 60 kg. There are five parents.

So the total mass of the parents is 5 x 60 = 300 kg.

Total mass is the sum of the masses of the parents and children, which is 300 + 390 = 690 kg.

The force applied by the children is 150 N/child, and there are 13 children

So the total force applied by the children is 150 x 13 = 1950 N.

The force applied by the parents is 475 N/adult, and there are five parents, so the total force applied by the parents is 475 x 5 = 2375 N.

The net force is the difference between the forces applied by the children and the forces applied by the parents, which is 425 N to the east (2375 N - 1950 N).

Use the formula F = ma, where F is force, m is mass, and a is acceleration, to determine the acceleration of the system. The formula should be rearranged to solve for acceleration. a = F/m

Substitute the values into the formula:

a = 425 N / 690 kg

acceleration:a = 0.62 m/s²

Therefore, the acceleration of the system is 0.62 m/s².

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Answer:

4 N

Explanation:

mass = 2 kg

acceleration = 2 m/s^2

Force = mass * acceleration

         = 2 *2

         = 4 N

Answer:

8 m/s

Explanation:

\(p = mv \\ 56 = (7.0)(v) \\ v = 8.0 \: m {s}^{ - 1} \)

Answer:

A

Explanation:

because the water carRies but also compacts

If a person is forced to utilize self-defense, the offensive techniques that should be recommended are as follows:

I would advise them to employ the following defense strategies:

Based on the films, the move(s) that appear to be the most successful for the offense in a circumstance requiring self-defense are to target the problem rather than the person.

An aggressive competitive strategy is a form of company strategy that involves actively pursuing industry changes.

Companies that go on the offensive typically make acquisitions and invest extensively in R&D and technology in order to remain ahead of the competition.

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Answer:

An atom with a closed shell of valence electrons (corresponding to an electron configuration s2p6) tends to be chemically inert. An atom with one or two valence electrons more than a closed shell is highly reactive, because the extra valence electrons are easily removed to form a positive ion.Explanation:

frequency = velocity divided by wavelength

Ultraviolet (UV) radiation lies between wavelengths of about 400 nanometres and 10 nanometres, corresponding to frequencies of 7.5 × 1014 Hz to 3 × 1016 Hz.

The power output of  2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a level frictionless surface is 24.09 watts.

In science, power is the time required to do work or provide energy, expressed as work done W or energy transferred divided by the time interval t - or W/t. A fixed amount of work can be done for a long time with a low-powered engine, or for a short time with a high-powered engine. The unit of power is work (or energy) per unit of time. Such as foot pounds per minute, joules (or watts) per second, and ergs per second. Force can also be expressed as the product of the force required to move an object and the object's velocity in the direction of the force. If the magnitude of the force F is measured in pounds and the velocity ν is measured in feet per minute, then the power is equal to Fν foot pounds per minute.

Given,

Mass of object (m) = 2.00 kg

Distance covered (s) = 1.5 m

Velocity of object (v) = 3.00 m/s

For calculation of acceleration:

v² = u² + 2as

3² = 0 + 2 × a × 1.5

9 = 3a

a = 2 m/s²

For calculation of time:

s = ut + ¹/₂at²

1.5 = 0 × t + ¹/₂ × 2 × t²

1.5 = t²

t = 1.22 sec.

For calculation of gravitational force:

F = mg

F = 2 × 9.8

F = 19.6 N

For calculation of work done:

W = F × s

W = 19.6 × 1.5

W = 29.4 J

For calculation of power output:

P = W/t

P = 29.4/1.22

P = 24.09 watts

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C) fault-block mountain

Answer:

show vector 2A and maybe i can help

Explanation:

1. For an object (A) moving uniformly in the negative direction of the x-axis with a speed of 15 m/s and initial abscissa of 30 m, the time equation of its motion is X = 30 - 15*t, and its (V-1) graph is a straight line with a slope of -15 and a y-intercept of 30, and 2. When another particle (B) with a time equation of XB = 101-70 (S.1) moves on the same axis, (A) and (B) meet at time t = 2.13 s and position X = -32.7 m. The distance separating (A) and (B) at t = 8 s is 369 m.

1.a. The time equation of the motion of (A) is given by:

X = XoA + Vt

where X is the position of (A) at time t, XoA is the initial position of (A), V is the velocity of (A) and t is the time elapsed since the start of the motion.

Plugging in the given values, we get:

X = 30 - 15t

b. The (V-1) graph of (A) is a straight line with a slope of -15 (since the velocity is constant and negative) and a y-intercept of 30 (since the initial position is 30). The graph looks like this:( below)

2a. To determine the instant at which (A) and (B) meet, we need to find the time t at which their positions are equal. Equating the time equations of (A) and (B), we get:

30 - 15t = 101 - 70t

Solving for t, we get:

t = 2.13 s

To find the position at which they meet, we can plug this value of t into either of the time equations and get:

X = 101 - 70*2.13 = -32.7 m

So (A) and (B) meet at time t = 2.13 s and position X = -32.7 m.

b. To determine the distance separating (A) and (B) at t = 8 s, we need to find their positions at that time. Using the time equation of (A), we get:

Xa = 30 - 158 = -90 m

Using the time equation of (B), we get:

Xb = 101 - 708 = -459 m

The distance separating (A) and (B) at t = 8 s is:

|Xb - Xa| = |-459 - (-90)| = 369 m.

Hence, Two particles moving on the same axis, where one is uniformly moving with an initial abscissa of 30 m and a speed of 15 m/s, and the other is moving with a time equation of XB = 101-70 (S.1), meet at time t = 2.13 s and position X = -32.7 m, while the distance separating them at t = 8 s is 369 m.

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Answer:

T_finalmix = 59.5 [°C].

Explanation:

In order to solve this problem, a thermal balance must be performed, where the heat is transferred from water to methanol, at the end the temperature of the water and methanol must be equal once the thermal balance is achieved.

\(Q_{water}=Q_{methanol}\)

where:

\(Q_{water}=m_{water}*Cp_{water}*(T_{waterinitial}-T_{final})\)

mwater = mass of the water = 0.4 [kg]

Cp_water = specific heat of the water = 4180 [J/kg*°C]

T_waterinitial = initial temperature of the water = 85 [°C]

T_finalmix = final temperature of the mix [°C]

\(Q_{methanol}=m_{methanol}*Cp_{methanol}*(T_{final}-T_{initialmethanol})\)

Now replacing:

\(0.4*4180*(85-T_{final})=0.4*2450*(T_{final}-16)\\142120-1672*T_{final}=980*T_{final}-15680\\157800=2652*T_{final}\\T_{final}=59.5[C]\)

The magnification of the image of Julitha Barber produced by the converging mirror is 0.0979

To find the magnification of the image, we need to use the formula:

magnification = -v/u,

where v is the distance of the image from the mirror, and u is the distance of the object from the mirror. Since the object is Julitha Barber standing at a distance of 553 m, we can take u as -553 m (negative because the object is on the same side as the mirror).
Now, we need to find the distance of the image from the mirror (v). For this, we can use the mirror formula: 1/v + 1/u = 1/f, where f is the focal length of the mirror, and is equal to half the radius of curvature (f = R/2). So, in this case, f = 1.20 × 102 m/2 = 60 m. Substituting the values in the formula, we get:
1/v + 1/-553 = 1/60
Solving for v, we get v = -54.12 m. (Note that the negative sign indicates that the image is virtual and upright.)
Now, we can use the magnification formula to find the magnification of the image:
magnification = -v/u = -(-55.6)/553 = 0.0979  (rounded to one decimal place)
Therefore, the magnification of the image of Julitha Barber produced by the converging mirror is 0.0.0979. This means that the image is 10 times smaller than the actual object and is virtual and upright.

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To find the net force with two forces, you need to add the two forces together if they are in the same direction, or subtract them if they are in opposite directions.

So, the net force with two forces is found by adding the forces together if they are in the same direction, or subtracting them if they are in opposite directions.

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