Answer:
1125m
Explanation:
The car moves with a uniformly accelerated motion for 20s:
s = 1/2·a·t² + v0·t + s0 (note that vo = 0 and s0 = 0, with v0 being the initial velocity and s0 the initial displacement).
So: s = 1/2·a·t²
The acceleration will be: Δv/Δt = 15m/s / 20s = 0.75 m/s²
s1 = 1/2·0.75 m/s² · (20 s)^2 = 150m
Then it continues with the velocity he acquired (v = a·t = 0.75 m/s²·20s = 15 m/s):
s2 = vt = 15m/s·50s = 750m
The final acceleration, when stopping, will be:
a = Δv/Δt = -15m/s / 30s = -1/2 m/s²
s3 = 1/2·(1/2m/s²)·(30s)² = 225m.
Now we sum s1 with s2 and s3:
s1 + s2 + s3 = 150m + 225m + 750m = 1125m
green light has a wavelength of 500 nm calculate the frequency.
Answer:
Solution: Given, the wavelength of the photon particle = 500 nm. In order to calculate the frequency of the photon particle, we use the formula given above. The frequency of the wave is equal to 6×10-4 Hz.
Originally Answered: The frequency of a green light is 6×10^14. What is its wavelength? In your case, the wavelength is 500 nm. What is the wavelength of 675 kHz? Should you leave more than $1,000 in a checking account? What is the frequency of a light that has a wavelength of 550 nm? Why would you even want to know this?
You have been given the wavelength λ (pronounced lambda) in nanometers, but not the frequency. Fortunately, a relationship between wavelength, frequency, and the speed of light, c exists, such that c = λ ⋅ ν. To determine the frequency from the wavelength, divide c by λ:
Calculate the energy, in joules, of a photon of green light having a wavelength of 562nm? The answer is 3.54 ×10−19 J. The equation for determining the energy of a photon of electromagnetic radiation is E = hν, where E is energy in Joules, h is Planck's constant, 6.626 × 10−34J ⋅ s, and ν (pronounced "noo") is the frequency.
Explanation:
A 10 kg object encounters 2 forces: 10 N to the left and 14 N to the right. What is the acceleration of the object?
A. 0.8 m/s^2
B. 0.4 m/s^2
C. 4 m/s^2
D. 8 m/s^2
Answer: .4 m/s^2
Explanation: Since there are two forces going the opposite way, you will substract them so 14 - 10 = 4, and now to find the acceleration, we will use the sum of all forces equation, f=ma.
4 = 10a
a = .4
The acceleration of the object is 0.4 m/s^2. The correct answer is B. 0.4 m/s².
What is force?Force is defined as an object which is in a state of motion then its rate of change of moment is called force.
Here,
To find the acceleration of the object, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object times its acceleration. In this case, the net force is the vector sum of the two forces acting on the object,
Net force = 14 N to the right - 10 N to the left = 4 N to the right
So, the net force acting on the object is 4 N to the right. Using Newton's second law, we can calculate the acceleration,
Net force = mass x acceleration
4 N = 10 kg x acceleration
acceleration = 4 N / 10 kg = 0.4 m/s²
Therefore, the acceleration of the object is 0.4 m/s². The correct answer is B. 0.4 m/s².
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Calculus |||/Physics
(a) The velocity and position function of the pellet at a time , t ≥0, is (30, 30, 80) + 5t and (30, 30, 80)t + 5t² respectively.
(b) The time of flight of the pellet is 0.78 s and the range is 23.4 m.
(c) The maximum height reached by the pellet is 45.92 m.
Time of motion of the pelletThe time of motion of the pellet is calculated as follows;
t = √(2h/g)
t = √(2 x 3 / 9.8)
t = 0.78 second
Velocity of the pellet after 0.78 secondv = u + at
v = (30, 30, 80) + 5t
v = (30, 30, 80) + 5(0.78)
v = (30, 30, 80) + 3.9
v = (33.9, 33.9, 83.9) m/s
Position of the pelletx = vt
x = [(30, 30, 80) + 5t]t
x = (30, 30, 80)t + 5t²
x = (33.9 x 0.78, 33.9 x 0.78, 83.9 x 0.78)
x = (26.44, 26.44, 65.44) m
Range of the projectileR = Vₓt
where;
Vₓ is horizontal velocityt is time of motionR = 30 m/s x 0.78 s
R = 23.4 m
Maximum height of pelletv² = u² - 2gh
where;
v is the final velocity at maximum height = 0u is the initial vertical velocity = 30 m/sh is the maximum heightg is acceleration due to gravity0 = u² - 2gh
2gh = u²
h = u²/2g
h = (30²) / (2 x 9.8)
h = 45.92 m
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In Figure 10.13, the author illustrates a book being raised at constant speed. Which of the following statements are true? Select all that apply.
There is no change in the kinetic energy of the book.
The potential energy of the book-Earth system decreases.
The potential energy of the book-Earth system increases.
The potential energy of the book increases.
Answer:
There is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.
Explanation:
This is because velocity is constantly increasing. This supports the idea that the kinetic energy of the book doesn't change and that the potential energy of the book-Earth system increases.
The true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.
We have to note that from the law of conservation of mechanical energy, the sum of the kinetic and potential energy of the book at any point remains constant.
If the book is being raised at constant speed, the the true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.
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The Law of Conservation of Momentum states.... (a)The momentum of each object in a system before must be momentum of each object in a system (b) The total momentum of a system before must be the total momentum of a system after (c) The momentum of a system before will be less than the total momentum of a system after (d) The momentum of a system before wil be more than the total momentum of a system after
The law of conservation of momentum states that the momentum before the collision is equal to the momentum after the collision. It also states that the total momentum of a system or a body remains constant.
Hence, from the given options, the correct answer is option (b)
Answer:
Remains Constant
Explanation:
Hope this helps and its different for everyone what was it for you for me it was C
I'LL MARK BRAINLIST
• A steel wire 4.7 m long stretches 0.11 cm when it is subjected to a tension of 360 N. What is the spring constant of the wire?
Answer:
Explanation:
length = 4.7 m
extension x = (0.11 /100) m + 4.7 m
= 4.7011 m
force = 360 N
spring constant k = ?
formula : F = kx
k = F/ x
k = 360 ÷ 4.7011
k= 76.578 Nm^-1
The spring constant of the wire of a steel wire 4.7 m long stretches 0.11 cm when it is subjected to a tension of 360 N is 76.57 N/m.
What is the spring constant?Simple, symmetrical motion i.e., SHM is a genuinely fascinating kind of agitation. It is continuously used in the objects' oscillatory motion. Most springs have SHM. The "spring constants" that are intrinsic to springs determine how stiff they are. A well-known law, Hooke's law, describes the SHM and provides a formula for the applied force using the spring constant.
Simple harmonic motions and Hooke's law are related to the definition of the spring constant. Therefore, we must first examine Hooke's rule before attempting to define the spring constant and comprehend how it operates.
Given:
The tension force, T = 360 N,
The length of the wire, L = 4.7 meters,
The elongation, l = 0.11 cm,
Calculate the spring constant by the following formula,
k = T / l
( l = x(0.11 /100) m + 4.7 m= 4.7011 m)
Here, k is the spring constant.
Substitute the values,
k = 360 / 4.7011
k = 76.57 N / m
Therefore, the spring constant of the wire of a steel wire 4.7 m long stretches 0.11 cm when it is subjected to a tension of 360 N is 76.57 N/m.
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heteroatoms make a difference in the physical and chemical properties of an organic molecule because___.
Heteroatoms make a difference in the physical and chemical properties of an organic molecule because they substitute extra mass in an organic molecule
• Each heteroatom has its own characteristic chemistry. They substitute extra mass for the hydrocarbon structure. They increase the polarity of the organic molecule.
• Heteroatoms have an intense effect on the reactivity of organic molecules. Hydrocarbons have only a limited range of reactions, and so organic chemistry is often defined as the chemistry of carbon, it is the other elements that make it interesting.
• They are also classified as diatomic, triatomic, or polyatomic molecules depending on the number of atoms present. H2O, NH3, CH4, etc. are examples of heteroatomic molecules.
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A centrifuge in a medical laboratory rotates at an angular speed of 3,750 rev/min. When switched off, it rotates through 48.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s²) of the centrifuge.
______rad/s²
The constant angular acceleration (in rad/s²) of the centrifuge is 255.66 rad/s².
Constant angular acceleration of the centrifuge
The constant angular acceleration of the centrifuge is calculated as follows;
ωf² = ωi² - 2αθ
where;
ωf is the final angular velocity ωi is initial angular velocityθ is angular displacementα is angular accelerationWhen the centrifuge is switched off, the final angular velocity = 0
Initial angular velocity: ωi = 3,750 rev/min x 2π rad/rev x 1 min/60 s = 392.7 rad/s
angular displacement: θ = 48 rev = 48 rev x 2π rad/rev = 301.6 rad
0 = ωi² - 2αθ
2αθ = ωi²
α = ωi²/2θ
α = (392.7²) / (2 x 301.6)
α = 255.66 rad/s²
Thus, the constant angular acceleration (in rad/s²) of the centrifuge is 255.66 rad/s².
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What is the X and Y components?
A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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Your car is initially at rest when your hit that gas and the car begins to accelerate at a rate of 2.857 m/s/s. The acceleration lasts for 15.5 s. What is the final speed of the car and how much ground does it cover during this acceleration?
Answer:
Vf = 44.56 [m/s]
Explanation:
In order to solve this problem we must use the following expression of kinematics.
\(v_{f} = v_{i}+(a*t)\)
where:
Vf = final velocity [m/s]
Vi = initial velocity = 0
a = acceleration = 2.857 [m/s^2]
t = time = 15.5 [s]
Note: the initial velocity is equal to zero as the car begins its movement from rest, or with an initial velocity equal to zero.
Vf = 0 + (2.875*15.5)
Vf = 44.56 [m/s]
give a strong idea to protect , purify and the beautify of the Dal lake
Answer:
Water in dal lake is test for any heavy metals and pollutant, sewage and drainage system are also monitored for the same.
Explanation:
Dal lake is located in Srinagar that is the state capital of Kashmir and is known for recreation and tourism purposes. The area covers about 18 km sq. and forms a part of natural wetlands. The lake is prone to pollution and has recently undergone restoration measures. To address the problems of eutrophication algae and large-scale microplankton have been removed from the water. The government of India has taken various measures to check the pollution by setting up a committee to monitor the proper use of allotted funds.PLEAS HELPPP ITS FOR A FORENSIC SCIENCE CLASS
USE COMPLETE SENTENCES PLEAS
The picture is the crime scene that you will use for the questions there are 1-9 questions and you have to draw out the picture in a peace of paper and DRAW the lines of convergence and area of convergence for question 2 you will also for question 2 For question 2 Do it in order for the question where the person got shot put it by which death is quicker
Directions: In this exam you will be asked to analyze a crime scene and describe what the blood spatter can tell us.
USE COMPLETE SENTENCES AND PROPER SPELLINGS. (You have autocorrect, please use it) blood
The scene:
You enter the scene and find 2 bodies. One has been shot in the head. The other has been shot in the chest and has blood coming from their mouth and nose.
Questions
1) Which man was shot in the head, and which was shot in the chest. Use evidence from the scene to back up your claim. (1pt)
2) Find the area of convergence for both gunshot sites. (2pts)
3) How would you find the angle that the blood impacted the ground? (1pt)
4) How would you explain the bright red smaller spatter? (1pt)
5) How would you explain the small circular drops in-between position 2 and man #2? What does this tell us? (1pt)
6) Why are there large pools of blood below both men’s bodies? (1pt)
7) How do you explain the 1 large droplet going in the opposite direction of the other 4 large droplets in position 2? (1pt)
8) What are the smaller secondary droplets around primary droplets called? (1pt)
9) Who shot first? (1pt)
1) The man who was shot in the head was shot at a closer range than the man who was shot in the chest, as evidenced by the large pool of blood around his body. The man shot in the chest was shot at a slightly further range, as evidenced by the smaller pools of blood around him.
2) The area of convergence for both gunshot sites can be found by drawing a line from the center of each pool of blood and extending it into the room. The point where the two lines meet is the area of convergence.
3) The angle that the blood impacted the ground can be determined by measuring the angle between the direction of the droplets and the ground.
4) The bright red smaller spatter is caused by the presence of high velocity blood droplets, which are propelled at a high velocity when the bullet impacts the body.
5) The small circular drops in-between position 2 and man #2 are likely caused by a back spatter, which is a phenomenon where blood is propelled in the opposite direction of the force that caused it. This could mean that the man in position 2 was shot first.
6) There are large pools of blood below both men’s bodies because they were both shot at a close range, which caused a large amount of blood to be expelled from their bodies.
7) The large droplet going in the opposite direction of the other 4 large droplets in position 2 is likely caused by a back spatter, which is a phenomenon where blood is propelled in the opposite direction of the force that caused it. This could mean that the man in position 2 was shot first.
8) The smaller secondary droplets around primary droplets are called satellite droplets.
9) It is not possible to tell who shot first based on the evidence provided.
What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m
The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.
In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.
When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.
For example, if the answer is 12.345, we would round it to 12.3.
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Did you DNA strand have a mutation, if so, what type? Substitution, insertion, or deletion.
It is possible for human DNA to have mutations and the type of mutation can vary.
Types of mutations in Human DNASubstitutions, insertions and deletions are all types of mutations that can occur in DNA.
These mutations can result in changes to the genetic code which can impact how genes are expressed and how proteins are produced.
Some mutations may have no noticeable effect on an individual while others can cause genetic disorders or increase the risk of certain diseases.
It's important to note that mutations can have varying effects, from no discernible impact to significant changes in gene function.
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A worker wants to load some bricks in to his van. there are 1000 bricks and when stacked neatly they measure 2m by 1m by 1m. If the vans maximum load is 1000kg, how many bricks can he load?
The worker can load {500/ρ} number of bricks into the van.
What is mass?Mass is the total amount of matter present inside a body.
Given is that a worker wants to load some bricks in to his van. There are 1000 bricks and when stacked neatly they measure 2m by 1m by 1m.
Assume the density of the brick to be {ρ}. Let's assume that he can load {n} bricks inside the van. So, we can write -
n x mass of 1 brick = maximum load
n x ρ x V = L{max}
nρV = L{max}
n = L{max}/ρV
n = 1000/(2 x 1 x 1 x ρ)
n = 500/ρ
Therefore, the worker can load {500/ρ} number of bricks into the van.
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Consider a system of two charges of magnitude 2 × 10-7 C and 4.5 × 10-7 C which is acted upon by a force of 0.1 N. What is the distance between the two charges?
To find the distance between two charges, we can use Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
The formula for Coulomb's law is:
F = (k * |q1| * |q2|) / r^2
where:
F is the force between the charges,
k is the electrostatic constant (k = 8.99 × 10^9 N m^2/C^2),
|q1| and |q2| are the magnitudes of the charges, and
r is the distance between the charges.
Given:
|q1| = 2 × 10^-7 C
|q2| = 4.5 × 10^-7 C
F = 0.1 N
k = 8.99 × 10^9 N m^2/C^2
We can rearrange the equation to solve for r:
r^2 = (k * |q1| * |q2|) / F
Plugging in the values:
r^2 = (8.99 × 10^9 N m^2/C^2 * 2 × 10^-7 C * 4.5 × 10^-7 C) / 0.1 N
r^2 = (8.99 × 2 × 4.5) * (10^9 * 10^-7 * 10^-7) / 0.1
r^2 = 80.91 * (10^9 * 10^-7 * 10^-7) / 0.1
r^2 = 80.91 * 10^(-7 + 9 - 1)
r^2 = 80.91 * 10^1
r^2 = 809.1
Taking the square root of both sides:
r = √809.1
r ≈ 28.46
Therefore, the distance between the two charges is approximately 28.46 units.
Calculate the average speed
1) between 0 min and 3 min.
2) between 3 min and 5 min.
3) between 5 min and 10 min
4) between 0 min and 10 min
Answer:
000000000000000000000000000
A 4.0-kilogram object is accelerated at 3.0 meters per second2 north by an unbalanced force. The same unbalanced force acting on a 2.0-kilogram object will accelerate this object toward the north at
answer choices
a. 12 m/s2
b. 6 m/s2
c. 3 m/s2
d. 1.5 m/s2
The same unbalanced force acting on a 2.0-kilogram object will accelerate this object toward the north at 6.0 m/s².
What is Newton's Second Law?
According to Newton's second law, an object's acceleration is determined by its mass and the net force that is acting on it. The body's acceleration is inversely related to its mass and directly proportional to the net force applied on it
According to Newton's second Law of motion the resultant force is directly proportional to the rate of change in momentum.
Therefore; F = ma , where F is the force, m is the mass and a is the acceleration
F = 4 × 3
= 12 Newtons
The same force acts on a 2.0 kg object
F = ma
a = F/ m
= 12 /2
= 6.0 m/s²
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How long will it take an object that falls from rest to attain a velocity of 147 m/s?
Answer:
15 seconds
Explanation:
We can use this formula to solve this problem:
Velocity = Initial Velocity + Acceleration * Time
We know that initial velocity is 0, the velocity is 147, and acceleration is 9.8(because of earth's gravitational pull), so we can plug those numbers in and solve for time:
147 = 0 + 9.8*t
t = 15
Therefore, it will take 15 seconds for an object that falls from rest to reach 147 m/s.
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogram-meter^3 and the density of silicon in other units: 2.33 gram-centimeter^3. You decide to convert the density of silicon into units of kilogram-meter^3 to perform the comparison.
By which combination of conversion factors will you multiply 2.33 gram-centimeter^3 to perform the unit conversion?
Answer:
Explanation:
To convert gram / centimeter³ to kg / m³
gram / centimeter³
= 10⁻³ kg / centimeter³
= 10⁻³ / (10⁻²)³ kg / m³
= 10⁻³ / 10⁻⁶ kg / m³
= 10⁻³⁺⁶ kg / m³
= 10³ kg / m³
So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³
2.33 gram / cm³
= 2.33 x 10³ kg / m³ .
Two charged point-like objects are located on the x-axis. The point-like object with charge q1 = 4.60 µC is located at x1 = 1.25 cm and the point-like object with charge q2 = −2.14 µC is located at x2 = −1.80 cm.
A) Determine the total electric potential (in V) at the origin.
B) Determine the total electric potential (in V) at the point with coordinates (0, 1.50 cm).
Answer:
a) the total electric potential is 2282000 V
b) the total electric potential (in V) at the point with coordinates (0, 1.50 cm) is 1330769.23 V
Explanation:
Given the data in the question and as illustrated in the image below;
a) Determine the total electric potential (in V) at the origin.
We know that; electric potential due to multiple charges is equal to sum of electric potentials due to individual charges
so
Electric potential at p in the diagram 1 below is;
Vp = V1 + V2
Vp = kq1/r1 + kq2/r2
we know that; Coulomb constant, k = 9 × 10⁹ C
q1 = 4.60 uC = 4.60 × 10⁻⁶ C
r1 = 1.25 cm = 0.0125 m
q2 = -2.06 uC = -2.06 × 10⁻⁶ C
location x2 = −1.80 cm; so r2 = 1.80 cm = 0.018 m
so we substitute
Vp = ( 9 × 10⁹ × 4.60 × 10⁻⁶/ 0.0125 ) + ( 9 × 10⁹ × -2.06 × 10⁻⁶ / 0.018 )
Vp = (3312000) + ( -1030000 )
Vp = 3312000 -1030000
Vp = 2282000 V
Therefore, the total electric potential is 2282000 V
b)
the total electric potential (in V) at the point with coordinates (0, 1.50 cm).
As illustrated in the second image;
r1² = 0.015² + 0.0125²
r1 = √[ 0.015² + 0.0125² ]
r1 = √0.00038125
r1 = 0.0195
Also
r2² = 0.015² + 0.018²
r2 = √[ 0.015² + 0.018² ]
r2 = √0.000549
r2 = 0.0234
Now, Electric Potential at P in the second image below will be;
Vp = V1 + V2
Vp = kq1/r1 + kq2/r2
we substitute
Vp = ( 9 × 10⁹ × 4.60 × 10⁻⁶/ 0.0195 ) + ( 9 × 10⁹ × -2.06 × 10⁻⁶ / 0.0234 )
Vp = 2123076.923 + ( -762962.962 )
Vp = 2123076.923 -792307.692
Vp = 1330769.23 V
Therefore, the total electric potential (in V) at the point with coordinates (0, 1.50 cm) is 1330769.23 V
a) The total electric potential is 2282000 V
b) The total electric potential (in V) at the point with coordinates (0, 1.50 cm) is 1330769.23 V
What is electric potential?The electric potential is defined as the amount of work energy needed to move a unit of electric charge from a reference point to a specific point in an electric field.
Given the data in the question and as illustrated in the image below;
a) Determine the total electric potential (in V) at the origin.
We know that; electric potential due to multiple charges is equal to sum of electric potentials due to individual charges
Electric potential at p in diagram 1 below is;
\(V_P=V_1+V_2\)
\(Vp = \dfrac{kq_1}{r_1} + \dfrac{kq_2}{r_2}\)
we know that; the Coulomb constant, k = 9 × 10⁹ C
q1 = 4.60 uC = 4.60 × 10⁻⁶ C
r1 = 1.25 cm = 0.0125 m
q2 = -2.06 uC = -2.06 × 10⁻⁶ C
location x2 = −1.80 cm; so r2 = 1.80 cm = 0.018 m
so we substitute
Vp = ( 9 × 10⁹ × 4.60 × 10⁻⁶/ 0.0125 ) + ( 9 × 10⁹ × -2.06 × 10⁻⁶ / 0.018 )
Vp = (3312000) + ( -1030000 )
Vp = 3312000 -1030000
Vp = 2282000 V
Therefore, the total electric potential is 2282000 V
b)The total electric potential (in V) at the point with coordinates (0, 1.50 cm).
As illustrated in the second image;
\(r_1^2=0.015^2+0.0125^2\)
\(r_1 = \sqrt{[ 0.015^2 + 0.0125^2 ]\)
\(r_1 = \sqrt{0.00038125}\)
\(r_1 = 0.0195\)
Also
\(r_2^2 = 0.015^2 + 0.018^2\)
\(r_2 = \sqrt{0.015^2 + 0.018^2}\)
\(r_2 = \sqrt{0.000549\)
\(r_2 = 0.0234\)
Now, Electric Potential at P in the second image below will be;
Vp = V1 + V2
\(Vp = \dfrac{kq_1}{r_1} + \dfrac{kq_2}{r_2}\)
we substitute
Vp = ( 9 × 10⁹ × 4.60 × 10⁻⁶/ 0.0195 ) + ( 9 × 10⁹ × -2.06 × 10⁻⁶ / 0.0234 )
Vp = 2123076.923 + ( -762962.962 )
Vp = 2123076.923 -792307.692
Vp = 1330769.23 V
Therefore, the total electric potential (in V) at the point with coordinates (0, 1.50 cm) is 1330769.23 V
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A liquid is poured into a vessel to a depth of 16cm when viewed from the top, the bottom appears to be raised 4cm. What is the refractive index of the liquid?
Answer:
Solution
Verified by Toppr
Correct option is
C
3 cm
RI=apparent depthreal depth
Substituting, 34=apparentdepth12
Therefore, apparent depth=412×3=9
The height by which it appears to be raised is 12−9=3cm
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SIMILAR QUESTIONS
A coin is placed at the bottom of a glass tumbler and then water is added. It appeared that the depth of the coin has been reduced because
Medium
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A tank is filled with water to a height of 12.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 9.4 cm. What is the refractive index of water? If water is replaced by a liquid of refractive index 1.63 up to the same height, by what distance would the microscope have to be moved to focus on the needle again?
at what height would a volleyball reach if thrown straight up with initial velocity of 23 m/s
Answer:
26.45 m
Explanation:
Initial velocity = 23m/s
At maximum height final velocity of the voleyball will be 0 . So ,
Final velocity= 0m/s
Acceleration due to gravity = -10m/s² (taking upward direction as +ve ) .
On using third equation of motion ,
=> 2as = v² - u²
=> 2*10*s = 0² -(23)²
=> s = 23*23/20
=> s = 26.45 m
Hence the maximum height attained by the ball is 26.45m
Please help...
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Answer:
1) C. The precise location of weather-related phenomena
2) C. It shows that the galaxies are moving farther away.
Explanation:
1) The global positioning system can be used in many ways, like in navigation, mapping and surveying the land. It is also used to observe the small changes taking place in the movement of objects on earth. They are usually used to study earthquakes.
2) When light from the galaxies is shifted towards the longer wavelengths, it is called red shift. When light shifts towards the shorter wavelengths, it is called blue shift. Big bang theory states how the primordial universe started expanding from a hot and dense singularity, in the process of evolution of the universe.
The universe is expanding always. Galaxies that are a part of the universe keep expanding and move farther away from each other. The galaxies that are very far off appear to move much faster than the nearby galaxies.
6.When light bends it is called
a - broken
b- benzene
C - reflection
d - refraction
Answer:
D refraction
Explanation:
I had a question like this so and I got it right so I believe this is the correct answer
Part 3: Energy Conversions 7. Record your data in the chart and include at least 5 potential-kinetic energy conversions shown in your device's construction. Example Item Description of potential-kinetic energy conversion Example Book The book had gravitational potential energy when it was on the table. Then as the book fell off the table, it was in motion and had kinetic energy. 1 2 3 4 5
Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.
Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.
As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.
Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.
As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.
Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.
Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.
Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.
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Which statement about electromagnets is correct? A. As the number of turns in the wire increases, the strength of the electromagnet increases.B. As the intensity of the current increases, the number of turns in the wire increases.C. As the number of turns in the wire increases, the intensity of the current increases.D. As the strength of the electromagnet increases, the intensity of the current increases.
Explanation:
Increasing the current intensity through the wire cannot increase the number of turns.
Thus, option B is the incorrect option.
Also, the current in the wire will depend on the power supply and not on the number of turns the wire has. The current in the wire will not change by increasing/decreasing the number of turns.
Thus, option C is the incorrect option.
The strength of the electromagnet depends on the intensity of the current. Thus, the current intensity will determine the electromagnetic strength and electromagnetic strength will not determine the current.
Thus, option D is the incorrect option.
The strength of the electromagnet depends upon the turns of wire around the metal core and the current or voltage passing through the wire. Thus, if we increase the number of turns around the metal core and the current or voltage is also increased, the strength of an electromagnet will also increase.
Thus the correct option is A.
Final Answer:
The correct option is A.
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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