a bystander hears a siren vary in frequency from 564 hz to 376 hz as a fire truck approaches, passes by, and moves away on a straight street. what is the speed of the truck>

Answer: Wave a the first answer is right

Brainliest.

Explanation:

Answer:

A

Explanation:

inertia Equation for All Object is k m R²

inertia Equation of Hollow Cylinder I = m R²

inertia Equation of Solid Cylinder I = ½ m R²

inertia Equation of Hollow Sphere I = ⅔ m R²

inertia Equation of Solid Sphere I = 2/5 m R²

to find the speed needed we can use Mechanical Energy (ME). or Total Energy.

ME = Translation Kinetic Energy + Rotation Kinetic Energi

ME = ½ m v² + ½ I w²

ME = ½ m v² (1 + k)

v² = 2ME / m(1+k)

sinnce all objects have the same mass, we can figure that v² is proportionally with 1/(1+k)

v²(hc) = 1/(1+1) = ½ = 0.5

v = 0.707

v²(sc) = 1/(1+½) = 2/3 = 0.67

v = 0.818

v²(hs) = 1/(1+⅔) = 3/5 = 0.6

v = 0.744

v²(ss) = 1/(1+²/5) = 5/7 = 0.71

v = 0.842

these is the ratio of speed they produce in the end of the arc with initial speed = 0 m/s

so, if we must give speed to the object so that it can reach the end of the arc, the fastest speed is given to hollow cylinder and the slowest speed is given to Solid Sphere

Then the answer is

HC, HS, SC, SS

Solid sphere, solid cylinder, hollow sphere, hollow cylinder  correctly lists the objects in order from fastest to slowest speed needed to make it through the arc.

A body's inertia is a characteristic that makes it resist attempts to move it or, if it is already moving, to change the speed or direction of it.

Mathematically:

inertia All Object is = k m R²

inertia of Hollow Cylinder I₁ = m R²

inertia of Solid Cylinder I₂ = ½ m R²

inertia of Hollow Sphere I₃ = ⅔ m R²

inertia of Solid Sphere I₄ = 2/5 m R²

Total kinetic energy of a body while it roll without slipping  = Translation Kinetic Energy + Rotation Kinetic Energi

= ½ m v² + ½ I w²

= ½ m v² (1 + k)

= 2 KE / m(1+k)

Since all objects have the same mass and, v² can be expressed as proportionally with 1/(1+k).

For hollow cylinder: v₁² = 1/(1+1) = ½ = 0.5

v₁ = 0.707

For solid cylinder: v₂²= 1/(1+½) = 2/3 = 0.67

v₂ = 0.818

For hollow sphere: v₃² = 1/(1+⅔) = 3/5 = 0.6

v₃ = 0.744

For solid sphere: v₄² = 1/(1+²/5) = 5/7 = 0.71

v ₄= 0.842

The objects in order from fastest to slowest speed needed to make it through the arc are correctly listed as:

solid sphere > solid cylinder > hollow sphere >  hollow cylinder.

Option (C) is correct.

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Jim Crow laws was the legal measure which allowed whites in southern states to keep blacks from voting after reconstruction ended.

These were the state and local laws which enforced racial segregation in the Southern part of the United States.

Due to this laws, whites in southern states kept blacks from voting after reconstruction ended.

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Answer:

A

Explanation:

Hooke's law! F(spring)=-kx

There's no tricky square law here. The spring constant doesn't change, only x (distance stretched) changes. Therefore, if distance is halved, Force will be halved.

With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in identical twitches twitches per stimulus.

Alpha motor neurons are the motor neurons that innervate the fibers of the skeletal muscle. A number of branches, each innervating a different muscle fiber, are formed as the alpha motor neuron enters the muscle. A motor unit is made up of one alpha motor neuron and all of the muscle fibers it innervates. Small motor units with 3-5 muscle fibers per motor neuron are found in muscles that are involved in delicate, coordinated control. Our hand and eye muscles, as well as those that control eye movement, have very small motor units.

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Answer:

D

Explanation:

LA FUERZA NETA ES LA FUERZA TOTAL DE EMPUJE MENOS EL PESO DEL

COHETE.

\(F_{y}\) = 700000 N(sen 90° - 20°) - 560000 N = 97785 N

The approximate vertical component of the net force that is propelling the rocket away from Earth is 112,000 N. Option B is correct.

The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. The thrust force is pointing upwards at an angle of 20 degrees, and the weight of the rocket is pointing downwards. The thrust force is the force that is generated by the rocket engine. It is the force that propels the rocket upwards.

The weight of the rocket is the force of gravity acting on the rocket. It is the force that pulls the rocket downwards. The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. If the net force is positive, the rocket will accelerate upwards. If the net force is negative, the rocket will accelerate downwards. If the net force is zero, the rocket will remain at rest.

net force = thrust force + weight

vertical component of net force = thrust force * cos(angle)

vertical component of net force = 700,000 N * cos(20 degrees) = 112,000 N. Option B is correct.

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Answer:

KE =1/2mv^2

Explanation:

KE depends upon movement of the body

Answer:

Force = 7N

Explanation:

Force = Mass x Acceleration = 2 x 3.5 = 7N

Newton's second law allows to find the result for the friction coefficient of the street is:

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body.

           ∑ F = m a

Where bold indicates vectors, m is to mass and acceleration.

In the attached we see a free body diagram, it is a diagram of the forces without the details of the body, the x-axis is parallel to plane also shown with the positive in the direction of movement, going down the plane and the y-axis perpendicular to the plane.

Let's use trigonometry to break down the weight.

        Sin θ = \(\frac{W_x}{W}\)  

        cos θ = \(\frac{W_y}{W}\) / W

        Wₓ = W sin θ

         \(W_y\)  = W cos θ

We write Newton's second law for each axis.

y-axis

         N- \(W_y\)  = 0

         N = mg cos θ

x-axis

        Wₓ - fr = ma

Since they indicate that the body goes down at a constant speed, the acceleration is zero.

         W sin θ = fr

The friction force is the macroscopic representation of the interactions between the two surfaces and the formula.

         fr = μ N

we substitute.

          fr = μ mg cos θ

         mg sin θ = μ cos θ  

        μ = tan θ

Let's calculate.

         μ = tan 38.0

         μ = 0.78

In conclusion using Newton's second law we can find the results for the friction coefficient of the street is:

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Answer:

it should be 21,3 kilometer

The overall charge of an object that has 82 protons, 82 neutrons, and 109 electrons is -27. Details about charge can be found below.

The overall charge of an atom can be calculated by subtracting the number of electrons from the number of protons.

The proton number represents the number of positively charged atom while the electron number represents the number of negatively charged atom.

According to this question, a charged object has 82 protons, 82 neutrons, and 109 electrons. The overall charge of the atom is calculated as follows:

Overall charge = 82 - 109

Charge = -27

Therefore, the overall charge of an object that has 82 protons, 82 neutrons, and 109 electrons is -27.

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Answer:

Sir Isaac Newton

Explanation:

Answer:

Sir Isaac Newton.

Explanation:

Newton's laws of motion, relations between the forces acting on a body and the motion of the body, first formulated by English physicist and mathematician Sir Isaac Newton.

Answer:

4.5 W

Explanation:

Applying,

P = V²/(R₁+R₂).................. Equation 1

Where P = Power, V = Voltage, R₁ and R₂ = values of the two resistor.

From the question,

Given: V = 9.00 V, R₁ = 7.00 Ω, R₂ = 11.00  Ω

Substitute these values into equation 1

P = 9²/(7+11)

P = 81/(18)

P = 4.5 Watt.

Hence the power dessipated by the two resistors is 4.5 watt

For a 6.00 kg bowling ball:

(a) change in momentum of the bowling ball is −12.0 kg m/s

(b) impulse imparted on the pin is −12.0 kg m/s.

(c) resulting speed of the pin after the collision is 8.00 m/s

(d) force exerted on the pin during the collision −400 N

(a) The change in momentum of the bowling ball is given by

Δp = m(vf − vi) = (6.00 kg)(7.00 m/s−9.00 m/s) =−12.0 kg m/s

(b) The impulse imparted on the pin is equal to the change in momentum of the bowling ball, so the impulse is −12.0 kg m/s.

(c) The resulting speed of the pin after the collision can be found using conservation of momentum. The total momentum after the collision is the sum of the momentum of the bowling ball and the momentum of the pin. So,

mbvi = mbvf+ mpvp

​where vp = speed of the pin after the collision.

Solving for vp,

vp = mb(vi− vf)/mp = (6.00 kg)(9.00 m/s−7.00 m/s) / 0.750 kg = 8.00 m/s

(d) The force exerted on the pin during the collision is given by

F = Δp/Δt = − 12.0 kg m/s/0.030 s = −400 N

The negative sign indicates that the force is in the opposite direction of the initial velocity of the bowling ball.

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Answer:

Solids have a definite shape and volume. Liquids have a definite volume, but take the shape of the container. Gases have no definite shape or volume.

Answer:

potential energy because if your on a rolloer coaster wacth the vid

Answer:

gravitational energy

Answer:

Explanation:

First I converted the km/h to m/s, which is the more common unit for velocity. In m/s, 105 km/h is 29.2. Thus, to find the x component of the vector:

29.2cos25 = 26 m/s

If you want it in km/h:

105cos25 = 95 km/h

The pressure exerted on the outer conductor due to the current in the inner conductor is P = [(2 × 10^(-7) * I) / 0.02]^2 / (2 * 4π × 10^(-7)).

To determine the magnetic field and pressure exerted in the given system, we can use Ampere's law and the Biot-Savart law.

(a) Magnetic Field:

The magnetic field inside a superconducting wire carrying current can be calculated using Ampere's law. Ampere's law states that the line integral of the magnetic field around a closed loop is proportional to the current passing through the loop.

For the inner wire carrying the current I, we can consider a circular loop of radius r within the wire. The magnetic field inside the wire at radius r can be calculated using Ampere's law:

∮ B · dl = μ₀ I

Where:

B is the magnetic field,

dl is an infinitesimal length element along the loop,

μ₀ is the permeability of free space (4π × 10^(-7) T·m/A),

I is the current in the wire.

Since the current flows uniformly throughout the cross-section of the wire, we can consider the loop within the wire to calculate the magnetic field. The magnetic field lines will be concentric circles around the wire.

The magnetic field at a distance r from the wire is given by:

B = (μ₀ I) / (2π r)

Substituting the given values, we have:

B = (4π × 10^(-7) T·m/A) * I / (2π r)

B = (2 × 10^(-7) * I) / r

Substituting the radius of the inner wire a = 2.00 cm = 0.02 m, we have:

B = (2 × 10^(-7) * I) / 0.02

(b) Pressure Exerted on the Outer Conductor:

The pressure exerted on the outer conductor can be calculated using the Biot-Savart law. The Biot-Savart law relates the magnetic field generated by a current element to the current and distance.

The pressure exerted on the outer conductor due to the current in the inner conductor can be calculated using the formula:

P = (B^2) / (2μ₀)

P = [(2 × 10^(-7) * I) / 0.02]^2 / (2 * 4π × 10^(-7))

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Answer:

50.37 m/s and 40ms object

Puck mass (m) and J (impulse), initial and ultimate velocities are the known and unknown quantities, respectively.

The integral of a force, F, over the time period over which it acts, t, is known as an impulse in classical mechanics and is denoted by the letters J or Imp. Since force is a vector quantity, impulse also belongs to this category. An object experiences an impulse, which results in an equivalent vector change in its linear momentum along with the subsequent direction. The kilogram meter per second (kg m/s) and newton second (N s), are dimensionally equal units of momentum and impulse, respectively. In the British Gravitational System, the unit is the slug-foot per second (slugft/s), but the equivalent English engineering measure is the pound-second (lbfs). As long as it is acting, a resulting force accelerates the body and alters its velocity.

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Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

\(H_m = \frac{u^2sin^2 \theta}{2g}\)

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

\(H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta = sin^{-1}(0.2123)\\\\\theta = 12.26^0\)

Therefore, the angle of projection is 12.26⁰.

Answer:

C. photons

hope this helps

have a good day :)

Explanation:

Answer:

The answer would be c

Explanation:

Answer:

The difference in the amount of energy transferred by the two bulbs is 1200 J.

Explanation:

The energy transferred by the two lightbulbs can be calculated with the given equation:

\( E = P*t \)

Where P is the power and t is the time

For the 60 W lightbulb:

\( E_{60} = P*t = 60 W*30 s = 1800 J \)

For the 100 W lightbulb:

\( E_{100} = P*t = 100 W*30 s = 3000 J \)

Hence, the difference in the amount of energy transferred is:

\( E_{t} = E_{100} - E_{60} = 3000 J - 1800 J = 1200 J \)

Therefore, the difference in the amount of energy transferred by the two bulbs is 1200 J.

I hope it helps you!

The difference in the amount of energy transferred by the two bulbs during this time is 1200 J.

We know that

E = P*t

Here

P means the power and T means the time

So for 60W lightbulb, the energy should be

= 60*30

= 1800J

For 100 W, the energy should be

= 100*30

= 3000 J

So, the difference is

= 3000 -1800

= 1200 J

hence, The difference in the amount of energy transferred by the two bulbs during this time is 1200 J.

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Answer:

so, the answer is 56 whole number if round it, or 55.6(round it to 10th decimal)

Explanation:

(formula, idk it is wrong or right)   °C =°F - 32 then / 1.8000

44°F =  6.6666666667°C

-56°F = -48.888888889°C

So, if u want whole number as the answer

it is something like 6.6666666667°C +  48.888888889°C = 55.5555555557 °C

so, so, the answer is 56 whole number if round it, or 55.6(round it to 10th decimal)

Answer:

A, B, and D.

Explanation:

I've answered this exact question on a quiz. Hope it's not too late!

Answer:

A

C

D

Is the right answers not A.B,D.

trust

The electron current driven through the iron wire is approximately 18.14 Amperes.

The electron current driven through a 2.5-mm-diameter iron wire by a 0.067 V/m electric field can be calculated using the formula: I = n ⨯ e ⨯ A ⨯ vd where:

I = current,

n = number of conduction electrons per unit volume,

e = charge of an electron (1.6 x 10⁻¹⁹ C),

A = cross-sectional area of the wire,

vd = drift velocity of electrons.

First, we need to find the cross-sectional area A of the wire:

A = π ⨯ (d / 2)²

A = π ⨯ (2.5 x 10⁻³ m / 2)²

A ≈ 4.91 x 10⁻⁶ m²

The drift velocity (v_d) can be calculated using the formula:

vd = E ⨯ τ / m

where:

E = electric field strength (0.067 V/m),

τ = mean time between collisions (3.6 x 10⁻¹⁵ s),

m = effective mass of an electron in iron (9.11 x 10⁻³¹ kg).

vd = 0.067 V/m ⨯ 3.6 x 10⁻¹⁵ s / 9.11 x 10⁻³¹ kg vd ≈ 2.65 x 10⁵ m/s

The number of conduction electrons per unit volume (n) in iron is approximately 8.5 x 10²⁸ m⁻³.

Now, we can calculate the current (I):

I = (8.5 x 10²⁸ m⁻³) ⨯ (1.6 x 10⁻¹⁹ C) ⨯ (4.91 x 10⁻⁶ m²) ⨯ (2.65 x 10⁵ m/s)

I ≈ 18.14 A

So, the electron current driven through the iron wire is approximately 18.14 Amperes.

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Approximately 30 m/s (67 mph) wind speed is needed to tip over the 55-gallon drum.

The critical wind speed needed to tip over the drum can be estimated using the formula:

\(V = (5/2*(h/d)*(W/m))^(1/2)\)

where V is the critical wind speed, h is the height of the drum, d is the diameter of the drum, W is the weight of the drum, and m is the mass of the drum.

Converting the given values to SI units, we get:

\(h = 0.8763 md = 0.5715 mW = 214.5 Nm = 21.77 kg\)

Substituting these values in the formula, we get:

\(V = (5/2*(0.8763/0.5715)*(214.5/21.77))^(1/2) ≈ 30 m/s\)

Therefore, approximately 30 m/s (67 mph) wind speed is needed to tip over the 55-gallon drum.

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The base of table is "1.08856 m" far away from the ball land.

Given:

Distance travelled by ball,

Initial velocity,

Acceleration,

Constant speed,

As we know the formula,

→ \(S = ut+\frac{1}{2}at^2\)

By substituting the values, we get

→ \(1.2=\frac{1}{2}\times 9.8t^2\)

→ \(1.2 = 4.9 t^2\)

→    \(t = \sqrt{\frac{1.2}{4.9} }\)

→      \(= 0.4948 \ seconds\)

Let,

→ \(x = 2.2\times t\)

     \(= 2.2\times 0.4948\)

     \(= 1.08856 \ m\)

Thus the solution above is right.

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Answer:

\(m = 44~Kg\)

Explanation:

Net Force

Newton's second law explains the dynamics principles when a number of forces are applied to an object.

The net force vector is the sum of the individual vector forces applied. The magnitude of the net force is related to the magnitude of the acceleration of the body as follows:

\(Fn=m.a\)

Furthermore, the acceleration can be calculated if we know the kinematic behavior of the body:

\(\displaystyle a=\frac{v_f-v_o}{t}\)

Where vf, vo, and t are the final speed, initial speed, and time, respectively.

The box is pushed across the floor with a force of 25 N against a frictional force of 14 N.

The net force applied to the box is:

\(Fn = 25 N - 14 N = 11 N\)

We also know the box is accelerated from rest (vo=0) to vf=4 m/s in t=16 seconds, thus:

\(\displaystyle a=\frac{4-0}{16}\)

\(a = 0.25~m/s^2\)

From the equation:

\(Fn=m.a\)

We solve for m:

\(\displaystyle m=\frac{Fn}{a}=\frac{11~N}{0.25~m/s^2}\)

\(\mathbf{m = 44~Kg}\)

Answer:

1.3 Pa

Explanation:

from general gas equation

p1v1/TO =P2V2/T2