a brass wire which is 4.00 m long and 4.00 mm in diameter hangs from the ceiling. if a mass of 5.00 kg stretches the wire by 0.160 mm, the stress in the wire is

Answer: Fossil fuels power the machine that shakes the tree so the apples fall to the ground

Explanation: most machines are powered by fossil fuels

The kinetic energy of another body having three times the mass of the given object will be 108 J

Kinetic energy-In physics, the kinetic energy of an object is the energy  it has due to  motion. It is defined as the work required to accelerate a body from a given mass from rest to a specified speed.

The kinetic energy of a body is given by \(K.E= \frac{1}{2}Mv^{2}\) (first equation)

Given K.E= 36J

Now the mass of second body is m=3M

also the second body is moving with the same speed v

So kinetic energy of second body K.E₂= \(\frac{1}{2}mv^{2} =\frac{1}{2}(3M)v^{2}\)=36×3

=108J (from first equation)

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The sound wave passed through a glass of water as well as a helium balloon because helium is less thick than air.

Frequency is the number of full wavelengths in a certain amount of time (f). When a wavelength lengthens, its frequency and energy (E) decrease. You may conclude from these equations that the wavelength gets shorter as the frequency rises.

As described in Waves, the strength drops as it gets farther away from the speaker. Moreover, because to the viscosity of the air, the energy is absorbed by things and transformed into heat energy.

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The biconditional statement is true. An angle is a right angle if and only if it is not obtuse.

In geometry, a right angle is defined as an angle that measures exactly 90 degrees. On the other hand, an obtuse angle is an angle that measures greater than 90 degrees but less than 180 degrees. The biconditional statement states that an angle is a right angle if and only if it is not obtuse. This means that if an angle measures exactly 90 degrees, it is a right angle, and if it does not measure 90 degrees, it is not a right angle. Since the definitions of right angle and obtuse angle are mutually exclusive and cover all possibilities, the biconditional statement holds true.

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a. [True]

b.  [False]

c. [True]

d. [True] The final temperature of the iron and water is halfway between the initial temperatures of each.

what occurs when a piece of heated metal is plunged into water that is at normal temperature. The metal will eventually cool as the water warms up. The temperatures of the two things will eventually be equal. When this occurs, it is stated that they are in thermal equilibrium with one another.

Since the materials are pliable, higher temperatures considerably increase the actual contact areas between surfaces. As a result, as the heating temperature is raised, the thermal contact resistance considerably reduces and the rate of heat transfer rises.

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Answer:

Before starting the simulation and having the waves encounter the barrier, the wavelength is manipulated. This is the independent variable. The pattern of diffraction will vary as a result of the change in wavelength. The diffraction angle is therefore the dependent variable. A “constant” is a parameter that stays the same regardless of the variables. The parameter of the barrier that is held constant is the size.

(i) The hydraulic gradient is 0.45.

(ii) The flow rate is approximately 0.00000167 cubic meters per second.

(iii) The hydraulic conductivity is approximately 0.000037 meters per second.

(i) Hydraulic gradient:

The hydraulic gradient (i) can be calculated by dividing the head difference (h) by the distance (L) between the manometer tappings:

i = h / L

Given:

Head difference (h) = 45 mm

Distance between manometer tappings (L) = 100 mm

Converting the units to meters:

h = 45 mm / 1000 = 0.045 m

L = 100 mm / 1000 = 0.1 m

Substituting the values into the formula:

i = 0.045 m / 0.1 m = 0.45

(ii) Flow rate:

The flow rate (Q) can be calculated using the equation:

Q = (V / t) / A

Where V is the quantity of water collected, t is the duration of the test, and A is the cross-sectional area of the test sample.

Given:

Quantity of water collected (V) = 500 ml = 0.5 L

Duration of test (t) = 300 seconds

Diameter of test sample (d) = 100 mm

Converting the units to meters:

V = 0.5 L = 0.5 / 1000 = 0.0005 m³

t = 300 seconds

d = 100 mm / 1000 = 0.1 m

Calculating the cross-sectional area (A) using the formula for the area of a circle:

A = π * (d/2)^2

Substituting the values:

A = π * (0.1/2)^2 = π * 0.005^2 = 0.00007854 m²

Substituting the values into the formula for flow rate:

Q = (0.0005 m³ / 300 s) / 0.00007854 m²

Calculating the flow rate:

Q = 0.00000167 m³/s

(iii) Hydraulic conductivity:

The hydraulic conductivity (K) can be calculated using Darcy's Law:

K = Q / (A * i)

Given the values we calculated:

Q = 0.00000167 m³/s

A = 0.00007854 m²

i = 0.45

Substituting the values into the formula:

K = 0.00000167 m³/s / (0.00007854 m² * 0.45)

Calculating the hydraulic conductivity:

K ≈ 0.000037 m/s

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Answer:

Cell is the unit which has two terminals one positive and one negative. A battery is a group of cells in which one negative terminal is attached to one positive terminal.

Cell:- Cell is the smallest unit of a battery.

Battery:-A battery is combination of cells.

The machine's efficiency is 81.61%, indicating that it converts 81.61% of the input energy into useful output energy, while the remaining percentage is lost as waste or dissipated in the process.

To calculate the efficiency, we can use the formula:

Efficiency = (Actual Output / Design Capacity) × 100

Given:

Actual Output = 7,407

Design Capacity = 9,050

Substituting the values into the formula:

Efficiency = (7,407 / 9,050) × 100

          = 0.817 × 100

          = 81.61%

Therefore, the efficiency of the machine is 81.61%.

Efficiency is a measure of how effectively a machine or system is utilizing its available capacity. In this case, the machine has a design capacity of 9,050 units, but it only produced an actual output of 7,407 units.

By dividing the actual output by the design capacity and multiplying by 100, we find that the machine's efficiency is 81.61%. This indicates that the machine is operating at approximately 81.61% of its full capacity.

A higher efficiency percentage would indicate a more optimal utilization of the machine's capacity, while a lower percentage suggests room for improvement in maximizing output.

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The gravitational acceleration at the surface of the planet, times a function of r is g = mG/r².

Gravitational acceleration is described as an object receiving acceleration due to the gravitational force acting on it.

From Newton's second law of motion we can write

F=ma

Here, F is the force acting on the object.

m is its mass and

"a" is the acceleration.

Also according to Newton's law of gravity we can write,

Fg = GmM / (r+h)²

Also a = Fg/M

a = g = {GmM / (r+h)²} / M

g = Gm/r²

The gravitational acceleration at the surface of the planet, times a function of r is g = mG/r².

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The radial acceleration as 9.16×1011 m/s2 or 9.35×1010 times the acceleration due to gravity (g).

The angular acceleration can be calculated using the formula: angular acceleration = (final angular velocity - initial angular velocity) / time. Here, the final angular velocity is 9.81×105 rpm and the initial angular velocity is 0 rpm, and the time is 1.75 min (or 105 seconds). Converting rpm to rad/s, we get the final angular velocity as 1.03×107 rad/s. Substituting these values in the formula, we get the angular acceleration as 9.81×104 rad/s2.

The tangential acceleration can be calculated using the formula: tangential acceleration = radius × angular acceleration. Here, the radius is given as 8.90 cm (or 0.089 m) and the angular acceleration is calculated as 9.81×104 rad/s2. Substituting these values in the formula, we get the tangential acceleration as 874.9 m/s2.

The radial acceleration at full revolutions per minute can be calculated using the formula: radial acceleration = (angular velocity in rad/s)2 × radius. At full revolutions per minute, the angular velocity is 9.81×105 rpm, which is equal to 1.03×107 rad/s. Substituting this value and the radius of 0.089 m in the formula, we get the radial acceleration as 9.16×1011 m/s2 or 9.35×1010 times the acceleration due to gravity (g).

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The bending of light as it passes from one medium to another is governed by Snell's law, which depends on the indices of refraction of the two media and the angle of incidence

The bending of light as it travels from one medium to another is described by Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction of the two media:

n1 sin(theta1) = n2 sin(theta2)

where n1 and n2 are the indices of refraction of the two media, theta1 is the angle of incidence (the angle between the incident ray and the normal to the interface between the two media), and theta2 is the angle of refraction (the angle between the refracted ray and the normal).

The index of refraction of a medium is a measure of how much the speed of light is reduced when it travels through that medium compared to its speed in a vacuum.

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Answer:

40200

Explanation:

200 even numbers from 1 to 400

so n=200

sum of all even numbers is n(n+1)

so sum = 200(201)

which equals 40200

Answer:

An image of the cosmic microwave background radiation, taken by the European Space Agency (ESA)'s Planck satellite in 2013, shows the small variations across the sky (Image credit: ESA/Planck Collaboration) The cosmic microwave background (CMB) is thought to be leftover radiation from the Big Bang, or the time when the universe began

Explanation:

The primary aspect in determining distance is ball speed. KE = 0.55mv2, Fav = m(v)/(t).

The rate at which your ball departs the club head after impact is known as ball speed. Generally speaking, the swing speed should be 1.5 times faster than the speed of the golf ball.KE = 0.55mv2, Fav = m(v)/(t).The huge ball's kinetic energy is (1/2)MVi2 = Mgh since it travels a distance of h to the ground; hence, its speed is Vi = Sqrt(2gh). Since it rises elastically from the ground, this is how quickly it will go up. The small ball's speed just before the collision is also vi = Sqrt2gh because it falls a distance h as well.

KE=.5(.625)(3.30)2 yielded KE0=3.4 and KEf=1.7,

so I put up 1.7=.5(.625)v2 to find the velocity and discovered the final velocity to be 2.33m/s.

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Answer:

Friction of the mountain on the skier in the opposite direction

Explanation:

answered it on khan academy

Friction of the mountain on the skier in the opposite direction.

A force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions.

Forces result from contact interactions (normal, frictional, tensional, and applied forces are examples of contact forces) and other forces are the result of action-at-a-distance interactions (gravitational, electrical, and magnetic forces).

There are two forces resulting from this interaction - a force on the chair and a force on your body. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.

Therefore, Friction of the mountain on the skier in the opposite direction.

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Answer:

Subsistence farming is growing food for your own and your family's direct consumption. Like a backyard vegetable garden, but with fruit, starch crops, and animals as well. Intensive agriculture is anything that really works the land hard. The inputs cost money, so it is generally only done for profit

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Answer:

Explanation:

To determine the velocity of cart B after the elastic collision with cart A, we can use the principle of conservation of momentum. In an elastic collision, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is calculated by multiplying its mass by its velocity.

Given:

Mass of cart A (m_A) = 40 kg

Initial velocity of cart A (v_Ai) = 12 m/s

Final velocity of cart A (v_Af) = -1.9 m/s (since it moves to the left)

Mass of cart B (m_B) = 55 kg

Initial velocity of cart B (v_Bi) = 0 m/s (since it is initially stationary)

Final velocity of cart B (v_Bf) = ?

Using the principle of conservation of momentum, we can write:

Total momentum before collision = Total momentum after collision

(m_A * v_Ai) + (m_B * v_Bi) = (m_A * v_Af) + (m_B * v_Bf)

(40 kg * 12 m/s) + (55 kg * 0 m/s) = (40 kg * -1.9 m/s) + (55 kg * v_Bf)

480 kgm/s = -76 kgm/s + (55 kg * v_Bf)

To isolate v_Bf, we can rearrange the equation:

(55 kg * v_Bf) = 480 kgm/s - (-76 kgm/s)

(55 kg * v_Bf) = 480 kgm/s + 76 kgm/s

(55 kg * v_Bf) = 556 kg*m/s

Now, we can solve for v_Bf by dividing both sides of the equation by 55 kg:

v_Bf = (556 kg*m/s) / 55 kg

v_Bf ≈ 10.11 m/s

Therefore, the velocity of cart B after the elastic collision is approximately 10.11 m/s.

9) A vector describe as a quantity that has both magnitude and direction. 10) We use vectors to describe in physics in physical quantities, including displacement, velocity, acceleration, force, momentum, and torque.

The vector is typically represented by an arrow, with the length of the arrow representing the magnitude of the vector and the direction of the arrow representing the direction of the vector. In addition to the magnitude and direction, vectors also have a starting point and an end point. Vectors can be added together to obtain a resultant vector that represents the sum of the individual vectors. Vectors can also be subtracted, multiplied by a scalar, or divided by a scalar.

For example, displacement is a vector that describes the distance and direction between two points. Velocity is a vector that describes the speed and direction of motion and acceleration is a vector that describes the rate at which velocity changes. Force is a vector that describes the push or pull on an object and momentum is a vector that describes the motion of an object and its resistance to change. Torque is a vector that describes the rotational motion of an object. So therefore vectors are an important tool for physicists because they allow them to describe physical quantities in a way that is both concise and precise.

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The required tension of the string is calculated to be 87.721 N for the wave speed of 177 m/s.

The string with the tension 67 N has the speed 153 m/s.

So, let us find the tension for the string of speed 177 m/s.

On a stretched string with linear density μ, the wave speed is expressed as,

V string = √Ts/μ = 153 m/s

√67/μ = 153 m/s

√μ = √67/153 = 0.053

μ = 2.8 × 10⁻³ kg/m

Solve the tension for a wave speed of 177 m/s. We have,

Ts = μ (V string)² = 2.8 × 10⁻³ kg/m (177 m/s)² = 87.721 N

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Answer:

what diagram

Explanation:

The electromagnetic byproducts of the explosion that gave birth to the cosmos are the cosmic background radiation.

The first light to ever be able to move freely throughout the universe is the Cosmic Microwave Background (CMB), which has since been cooled. The 'Big Bang' was followed by the release of this 'fossil' radiation, which is the farthest that any telescope can observe. It is seen by scientists as a "shockwave" or echo of the Big Bang.

The flimsy great bang light is preserved in the cosmic microwave background radiation. About 2.5 percent of the sky is covered by this false-color image, which depicts variations in the ionized gas that eventually condensed to form superclusters of galaxies.

A form of radiation called cosmic background radiation is one in which photons can move around freely since the universe has been transparent to radiation since the Big Bang.

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Answer:

C, it will move.

Explanation:

Answer:

The object will move forward

Explanation:

When more than one force acts upon an object, the vector sum of these forces is the resultant force. When the resultant force on an object is zero, it will remain at rest if it is at rest, or continue to move in a straight line at a constant velocity if it is in motion.

Since the force is perpendicular to the displacement of the ball, the total work done by the force is 50 Nm.

Given the following data:

To find the total work done by the force:

The work done by an object is the product of the perpendicular force acting on the object and the distance it covers.

Mathematically, work done is given by the formula:

\(Work\;done = Force\) × \(distance\)

Substituting the given parameters into the formula, we have;

\(Work\;done = 10\) × \(5\)

Work done = 50 Nm.

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When the mass is increased by a factor of four, keeping a and k constant mechanical energy increases by a factor of 4.

The mass that is linked to the spring has no bearing on its force constant. As a result, it remains unchanged by the attached mass.

The acceleration of an object rises proportionally to the force applied to it. We can state that force and acceleration are identical because the mass does not change when the acceleration rises. So, doubling the force also doubles the acceleration.

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Answer:

(D) Vf² = Vi² + 2ad

a = 2.269 m/s²

Explanation:

Given;

final velocity of the aircraft, Vf = 33 m/s

initial velocity of the aircraft, Vi = 0

distance traveled by the plane, d = 240 m

The acceleration of the plane is given by the following kinematic equation;

Vf² = Vi² + 2ad

where;

a is the acceleration;

Based on the given options, the correct option is "D".

Calculating the acceleration with the chosen equation;

Vf² = Vi² + 2ad

Vf² = 0+ 2ad

Vf² =  2ad

a = Vf² / 2d

a = (33)² / (2 x 240)

a = 2.269 m/s²

The gravitational pull of the second moon would be stronger than that of our moon, but it wouldn't be three times stronger because the gravitational pull is also influenced by the separation between the two bodies.

It would pull in more gravitationally than our moon if Earth had a second moon that was three times as large as our own and positioned similarly to the earth. An object's mass and distance from another object both affect gravity.

The gravitational attraction of the second moon would be stronger since it would be heavier than the first. The second moon would have a larger gravitational pull since it would be heavier than the first. The strength of the gravitational force is also affected by distance.

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As the planet orbits the sun, the angle at which the sunlight hits the planet's surface may change slightly, but this does not result in significant changes in the amount of sunlight that the planet receives.

On a planet whose rotation axis is not tilted with respect to its orbital plane, the seasons are not pronounced. This is because the amount of sunlight that the planet receives does not change significantly throughout the year.

In contrast, on a planet with a tilted rotation axis, the seasons are much more pronounced. As the planet orbits the sun, the angle at which the sunlight hits the planet's surface changes significantly, resulting in longer periods of sunlight in certain parts of the planet and shorter periods of sunlight in other parts. This leads to significant differences in temperature and weather patterns, resulting in the four distinct seasons that we experience on Earth.

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Answer:

option (b) charge

Explanation: