a body dropped from a height reaches a velocity of 13m/s just before touching the ground. What is the initial height of the ball and the time of height​

We can find the current I(3torque) at a time after t=0 equal to three times the time constant using the formula for the current in a charging RC circuit:

I(t) = I0 * e⁻ᵗ/RC)

where I0 is the initial current, t is the time, R is the resistance, and C is the capacitance.

Since we are given that I(3torque) = 3 * RC, we can set up the equation:

3 * RC = I0 * e⁻³ᵗ/ RC)

We can solve for I0 by dividing both sides by ee⁻³ᵗ/RC):

I0 = 3 * RC / e⁻³ᵗ/RC)

We can simplify this expression by multiplying the numerator and denominator by e³ᵗ/RC):

I0 = 3 * RC *e⁻³ᵗ/RC) / e

I0 = 3 * RC * e ³ᵗ/RC)

Therefore, the current I(3torque) at a time after t=0 equal to three times the time constant is:

I(3torque) = I0 * e⁻³/RC)

I(3torque) = 3 * RC * e3/RC) * e³/RC

I(3torque) = 3 * RC * e⁰

I(3torque) = 3 * RC

Therefore, the current I(3torque) at a time after t=0 equal to three times the time constant is simply 3 times the time constant, without any dependence on the value of t.

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This is an exercise in Rectilinear Uniformly Varied Motion (MRUV) is a type of motion in which an object moves in a straight line and experiences changes in its velocity at a constant rate. In this type of motion, the acceleration of the object remains constant over time.

The distinctive feature of the MRUV is that the velocity of the object changes uniformly, that is, its velocity increases or decreases by a constant amount in each unit of time. If the object experiences a positive acceleration, its velocity increases with time. On the other hand, if the object experiences a negative acceleration, its speed decreases.

In an MRUV, constant acceleration has a direct impact on displacement and the time it takes for the object to reach a certain speed. Also, the direction of the acceleration determines whether the object is accelerating or decelerating relative to its initial motion.

This type of movement is found in various situations of daily life, such as the launch of an object upwards and its subsequent fall, the movement of cars on a road with acceleration or braking, or even the study of bodies in free fall.

Vf = V₀ + a × t

Where:

In this case, the initial velocity (vi) is 1 m/s, the acceleration (a) is -1 m/s^2 (negative because it indicates deceleration), and the time (t) is 4 seconds.

Substituting these values into the formula, we get:

Vf = V₀ + a × t

Vf = 1 m/s + (-1 m/s²) × 4 s

Vf = 1 m/s - 4 m/s

Vf = -3 m/s

The electric potential due to the given charges at point P is -0.514 mV.

Find the electric potential at point P due to the given charges, we need to calculate the contributions from each charge and then sum them up.

The electric potential due to a point charge is given by the formula:

V = k * (Q / r)

where V is the electric potential, k is Coulomb's constant (approximately 8.99 x \(10^{9} N m^2/C^2\)), Q is the charge, and r is the distance from the charge to the point of interest.

For the positive charge at (0, 0):

Q1 = +2.30 mC = +2.30 x \(10^{(-3)}\)C

r1 = distance from (0, 0) to (4, 0) = 4.00 m

V1 = k * (Q1 / r1)

For the negative charge at (0, 3.00 m):

Q2 = -5.80 mC = -5.80 x \(10^{(-3)}\) C

r2 = distance from (0, 3.00 m) to (4, 0) = √\([(4.00 m)^{2} + (3.00 m)^{2}\)] ≈ 5.00 m

V2 = k * (Q2 / r2)

We can calculate the electric potential at point P by summing up the contributions:

V = V1 + V2

Substituting the values:

V = k * (Q1 / r1) + k * (Q2 / r2)

V ≈ (8.99 x \(10^9 N m^2/C^2\)) * [(+2.30 x \(10^{(-3)}\) C / 4.00 m) + (-5.80 x \(10^{(-3)\)C / 5.00 m)]

Calculating the expression within the brackets:

V ≈ (8.99 x \(10^9 N m^2/C^2\)) * [(+2.30 x \(10^{(-3)}\) C / 4.00 m) + (-5.80 x \(10^{(-3)}\) C / 5.00 m)]

V ≈ (8.99 x\(10^9 N m^2/C^2\)) * [0.575 x\(10^{(-3)}\) C/m - 1.16 x \(10^{(-3)}\) C/m]

Simplifying further:

V ≈ (\(8.99 * 10^{9} N m^2/C^2) * (-0.585 * 10^{(-3)} C/m\))

V ≈ -\(5.14 * 10^{(-4)}\) N m/C

Converting the unit to millivolts (mV):

V ≈ -0.514 mV

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Explanation:

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The largest individual galaxies in the universe are known as giant elliptical galaxies.

These galaxies are characterized by their massive size, typically much larger than spiral or irregular galaxies. Giant elliptical galaxies are predominantly made up of old stars and lack the prominent disk structure seen in spiral galaxies. Instead, they exhibit a spherical or ellipsoidal shape with a smooth distribution of stars.

Giant elliptical galaxies can contain trillions of stars and span a significant portion of the observable universe. They often reside in dense regions of galaxy clusters, where they have grown through mergers with other galaxies over billions of years. These mergers contribute to their immense size and the accumulation of stellar mass.

Due to their massive nature, giant elliptical galaxies also tend to have a supermassive black hole at their centers, with a mass billions of times that of our Sun. These black holes can significantly influence the dynamics and evolution of their host galaxies.

Examples of giant elliptical galaxies include Messier 87 (M87) in the Virgo Cluster and NGC 4889 in the Coma Cluster. These galaxies exhibit enormous sizes and play a crucial role in our understanding of galaxy formation, evolution, and the study of the most massive structures in the universe.

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The largest individual galaxies in the universe are known as superclusters, which are large-scale structures formed by clusters of galaxies. Superclusters can extend over distances of several hundred million light-years and contain thousands or tens of thousands of galaxies.

The largest individual galaxies in the universe are known as superclusters. Superclusters are large-scale structures formed by clusters of galaxies that can extend over distances of several hundred million light-years. These superclusters contain thousands or tens of thousands of galaxies, making them the largest known structures in the universe.

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When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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Answer:

A cloud chamber, also known as a Wilson cloud chamber, is a particle detector used for visualizing the passage of ionizing radiation.

Explanation:

Answer: A cloud chamber, also known as a Wilson cloud chamber, is a particle detector used for visualizing the passage of ionizing radiation.

Explanation: i got it right on my quiz .

Answer:

B) Decreases

Explanation:

Gravitational force is inversely proportional to distance. As distance between 2 objects increase, gravitational force between the 2 objects decreases.

Hope this helps!

Answer:

The answer would be B

Explanation:

A galaxy in the local group  is most likely to be the oldest.

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The total energy emitted by the black body in a thickness of 1.00 mm is approximately 0.00006 joules.

The Stefan-Boltzmann Law states that the radiant energy per unit time per unit area emitted by a black body can be determined using the equation: R = σT⁴, where σ is the Stefan-Boltzmann constant (5.67 x 10⁻⁸ W/m²K⁴), T is the temperature of the black body, and R represents the radiant energy per unit time per unit area.

Using this equation, we can calculate the radiant energy emitted by the black body. For example, if the temperature of the black body is 5000K, the calculation would be as follows:

R = σT⁴ = 5.67 × 10⁻⁸ x (5000)⁴ = 15,023.4375 watts per square meter.

Assuming the area of the black body is 20 cm² (0.002 m²), we can calculate the total radiant energy emitted by the black body:

E = R x A = 15,023.4375 x 0.002 = 30.047 watts.

To calculate the total energy emitted by the black body in a specific thickness (1.00 mm), we use the formula: energy per unit area x area x thickness.

E = E x A x t = 30.047 x 0.002 x 0.001 = 0.00006 joules.

Therefore, the total energy emitted by the black body in a thickness of 1.00 mm is approximately 0.00006 joules.

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The power input of 3hP might be sufficient and the coefficient of performance will be "3.93".

According to the question,

In order to maintain the dwelling at 70°F with,

The COP,

→ \(\beta \leq \ \beta_{max}\)

or,

→ \(\beta \leq \frac{T_c}{T_H-T_c}= \frac{530^{\circ} R}{(550-530)^{\circ}R}\)

                     \(= 26.5\)

or,

→ \(\frac{Q_{in}}{W_c} \leq 26.5\)

→  \(W_c \geq \frac{3000 \ Btu/h}{26.5}\times \frac{1 \ hP}{2545 \ Btu/h}\)

→  \(W_c \geq 0.445 \ hP\) (minimum required power)

hence,

The corresponding COP will be:

→ \(\beta = \frac{Q_c}{W}\)

      \(= \frac{30000}{3\times 2545}\)

      \(= 3.93\)

Thus the response above is correct.

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Explanation:

Force is applied to lift a body against the force of gravity. Example: If an object is lifted to a certain height (h)

Answer:

a)   y = y₀ - 4.9, v = -9.8 m / s, b)  y =y₀ - 19.6,  v = - 19 m / s

c)  y =y₀ - 44.1, v = - 29.4 m / s

Explanation:

To solve this exercise let us use the kinematic relations

          y =y₀ + v₀ t - ½ g t²

          v = v₀ - g t

They indicate that the body is released therefore the initial velocity is zero v₀ = 0

          y = y₀ - ½ g t²

          v = - gt

a) the position and velocity for t = 1s

         y = y₀ - ½ 9.8 12

         y = y₀ - 4.9

         v = - 9.8 1

         v = -9.8 m / s

the negative sign indicates that the velocity is directed downwards

b) t = 2 s

         y =y₀ - ½ 9.8 2 2

         y =y₀ - 19.6

         v = - 9.8 2

         v = - 19 m / s

c) t = 3 s

        y = y₀ - ½ 9.8 3 2

        y =y₀ - 44.1

        v = - 9.8 3

        v = - 29.4 m / s

Saturn is the following planet or moon, and its atmosphere is primarily made of hydrogen with a small amount of methane.

The correct answer is B

The planet Saturn is incredibly large and its rings make it incredibly gorgeous. Amazing moons as Titan reside there as well. The Solar System's Saturn is arguably the most popular and stunning planet. Compared to the rings of other planets, Saturn's are much larger and easier to see.

Then, only a year ago, researchers found a second Earth-like planet around Proxima Centauri, one of our nearest nearby stars. The best option we now have for maintaining human life is this planet.

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The observed peak wavelength of the star's light when it is traveling away from the Earth at 150,000 m/s is approximately 553.96 nm

When a star is traveling away from the Earth at a high speed, the light it emits is shifted towards the red end of the spectrum. This is known as the redshift effect and is caused by the Doppler effect. The Doppler effect causes a change in the observed wavelength of light when the source of the light is moving relative to the observer. In this case, the peak wavelength of the star's light will be shifted towards the longer wavelengths.
To calculate the new peak wavelength, we can use the formula: λ' =\frac{ λ}{(1+v/c)}, where λ is the peak wavelength at rest, v is the velocity of the star, c is the speed of light, and λ' is the observed peak wavelength.
Plugging in the values given, we get:
λ' =\frac{ 550}{(1+1\frac{50,000}{299,792,458})} = 553.96 nm
Therefore, the observed peak wavelength of the star's light when it is traveling away from the Earth at 150,000 m/s is approximately 553.96 nm.

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Answer: Weight = 88N

HOPE THIS HELPS

Answer:

88 N

Explanation:

If you weigh 539 N of Earth, your mass = 539/9.8 = 55kg

The acceleration due to gravity on the moon is about 1.6 m/s and your weight will be 55*1.6 = 88 N on the moon.

The reduction of 9 fluorenone can be represented by the following balanced equation:

C13H8O + 14H → C13H16O

This equation illustrates that 9 fluorenone (C13H8O) can be reduced by 14 hydrogen atoms (14H) to yield C13H16O. The molecular formula for 9 fluorenone is C13H8O, and it can be transformed through reduction to form C13H16O using 14 hydrogen atoms. Hence, the balanced equation representing the reduction of 9 fluorenone is:

C13H8O + 14H → C13H16O.

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 The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)

When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".

According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.

Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.

Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.

Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.

Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.

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Answer:

Principle Archimedes is applied in building a ship and submarine using the manipulating that buoyancy, is controlled the ballast tank system.

Explanation:

Submarine is rather had they focused on main parts of the submarine,he is complex and long process implementation,the most submarine design like submarine stability.

Submarine stability is complete and the fundamental Archimedes principle to arrive the weight of submarine is equal to buoyancy force.

Submarine into the parts and components of ballast tank the sequence in diving and surfacing,there two vital parts:-  flood parts and air vents

flood parts:- at the bottom position and allow water to enter or leave that tank.

air vents:- air vents at the top of the pressure hall,and that they submarine dive.

this time submarine is most modern system is depth is 300 to 450 meters,high pressure  air is 15 bar is tank air valve.

submarine is basic of the effective volume of all the submarine surfaced condition,submarine minus to the free water flood is equal to the fully pressure hull,submarine is the surfaced condition.

Answer:

\(F_{grav}\) is a field force, as gravity does not physically apply force and does not require proximity.

Explanation:

Answer:

Mass = 0.04 Kg

Explanation:

Given the following data;

Density = 800 kg/m³

Volume = 5 * 10^{-5} m³

To find the mass of the object;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

\( Density = \frac {mass}{volume} \)

Making mass the subject of formula, we have;

\( Mass = density * volume \)

Substituting the values into the formula, we have;

\( Mass = 800 * 5 * 10^{-5} \)

Mass = 0.04 Kg

The wavelength of a 650.00 Hz sound in air at room temperature and pressure, where the velocity of sound is 344 m/s, is approximately 0.529 m.

Sound waves travel through a medium by creating compressions and rarefactions. The wavelength of a sound wave is the distance between two consecutive points that are in phase, such as two compressions or two rarefactions. To calculate the wavelength, we can use the formula: wavelength = velocity of sound / frequency.

In this case, the frequency of the sound is 650.00 Hz, and the velocity of sound in air at room temperature and pressure is 344 m/s. Plugging these values into the formula, we get: wavelength = 344 m/s / 650.00 Hz = 0.529 m.

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Answer: 300 J

Explanation:

Force = 150 KJ

Distance = 2.0 m

The minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically would be 2940 Joules, as the work done is the product of the force applied to the displacement of the object, therefore the correct answer is option B.

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force × Displacement

As given in the problem we have to find out the minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically.

The minimum work done = 150 × 9.8 × 2

                                          = 2940 Joules

Thus, The minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically would be 2940 Joules.

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Copper is used in wiring and cookware because it can conduct electricity and heat well. The property which allow this  is call high conductance .

Conductivity is defined as a material's ability to conduct electricity or heat.

High Conductance  is the property of copper that allows it to do this . Copper is a metal and have free electrons which help in good conduction of heat and electricity .

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A child pulls a toy car at constant velocity on a rough, horizontal floor using a horizontal rope. In order to maintain constant velocity, the tension in the rope needs to be equal to the opposing force acting on the toy car.

When the toy car is moving at a constant velocity on a rough horizontal floor, the force of friction opposes the motion and acts in the opposite direction of the applied force. According to Newton's second law, when the car is moving at a constant velocity, the net force acting on it is zero.

Therefore, the tension in the rope needs to be equal in magnitude but opposite in direction to the force of friction. This ensures that the net force on the toy car is zero, resulting in a constant velocity.

If we denote the tension in the rope as T and the force of friction as F_friction, then:

T = F_friction

The tension in the rope must exactly balance the force of friction to maintain constant velocity. If the tension is greater than the force of friction, the car would accelerate. If the tension is less than the force of friction, the car would decelerate.

Hence, to keep the toy car moving at a constant velocity, the tension in the rope needs to be equal in magnitude but opposite in direction to the force of friction.

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Some of the coal's energy was turned into other forms of energy.

According to the first law of thermodynamics, energy can neither be created nor destroyed but is converted from one form to another. We know that from the first law of thermodynamics, the energy that originally in the coal does not  vanish into thin air but undergoes a conversion.

Thus, want to find out what accounts for the energy of the coal. Thus, we could say that some of the coal's energy was turned into other forms as this is in consonance with the first la of thermodynamics.

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Answer:

Distance-0

Displacement-0

Explanation:

She spun in place and fell in her exact placement she didnt move and distance or displace any area

Mali loves to make herself dizzy, so she spins in place 7 times at a particular place, then the distance and displacement will be equal to zero.

The complete movement of an object, regardless of direction, is referred to as a distance. The amount of ground a thing travels from its starting point to its destination is also referred to as distance. A distance can alternatively be thought of as a scalar quantity, meaning that it is independent of an object's motion's direction.

The term "displacement" simply describes how an object's location has changed. For instance, when an object travels from point A to point B, displacement has taken place. A vector quantity with both magnitude and direction is displacement.

Hence, distance and displacement covered by Mali will be zero.

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