The boat's weight might be reduced overall by discarding some of its metal blocks, which might raise the boat's height and enable it to pass beneath the bridge without colliding with it.
How can water be removed from a vertical pipe?Simply squeeze to draw the water out of the pipe, past the spray nozzle, and into the wastewater container. Place a small basin or container nearby to catch the water.
What is the vertical pipe's flow rate?A pipe, for instance, has a 2 inch radius. There are 4 square inches in the cross section. Suppose that the pipe receives 12 inches of water each minute. The flow rate is 4 squared.
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A horizontal rod (oriented in the east-west direction) is moved northward at constant velocity through a magnetic field that points straight down. Make a statement concerning the potential induced across the rod.
a. The east end of the rod is at higher potential than the west end.
b. The bottom surface of the rod is at higher potential than the top surface.
c. The top surface of the rod is at higher potential than the bottom surface.
d. The west end of the rod is at higher potential than the east end.
e. The potential is uniform.
Answer:
a. The east end of the rod is at higher potential than the west end.
Explanation:
The horizontal rod is oriented in the east-west direction. This means that applying right hand rule, the current will flow from the east to the west. Now, if we assume tat it is a closed loop, we know from polarity of voltage that current usually flows positive to negative terminal within a circuit.
This means the east is at a largely positive terminal while the west is at a largely negative terminal.
Thus, we can say that the east end of the rod is at higher potential than the west end of the rod.
give me 7 risk factors for heart attack
The seven risk factors for heart attack are Age, Tobacco usage, high blood pressure, high cholesterol level, obesity, diabetes and metabolic syndrome.
Some other risk factors for heart attack are:
Family history of heart attacksNot enough exerciseUnhealthy dietStressIllegal drug useHistory of preeclampsia An autoimmune conditionTo prevent heart attack, one must,
Follow a healthy lifestyleManage other health conditionsTake medications as directedTherefore, the seven risk factors for heart attack are Age, Tobacco usage, high blood pressure, high cholesterol level, obesity, diabetes and metabolic syndrome.
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There are two space ships traveling next to each other. The first one is 500
Kg and the second one is 498 Kg. Since they are 35 meters apart, what is
the force of gravity between the two space ships?
This question involves the concept of Newton's law of gravitation.
The force of gravity between the two spaceships is "1355.78 N".
Newton's Law Of GravitationAccording to Newton's Law of Gravitation:
\(F=\frac{Gm_1m_2}{r^2}\)
where,
F = force of gravity between ships = ?G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²m₁ = mass of first ship = 500 kgm₂ = mass of second ship = 498 kgr = distance between ships = 35 mTherefore,
\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)
F = 1355.78 N = 1.356 KN
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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.
It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,
The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.
The distance between spaceships (r) is 35 meters.
It is required to find the Force of gravity between these spaceships.
What is Gravitational force?It is defined as the force which attracts any two masses in the universe.
By Newton's law of Gravitation:
\(\rm F= \frac{Gm_1m_2}{r^2}\) , Where
\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)
Putting values in the above formula:
\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)
F = 1355.78 N = 1.356 KN
Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.
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A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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Name:.
Date:
Homework: Writing an Argument About
Australia's Skin Cancer Rate
G
4
You now have enough evidence to explain why Australia's skin cancer rate is so high. Review your
argument from Chapter 2 and think about how you will convince the AHA that both Claim 2 and
Claim 3 are accurate. You will use your completed Reasoning Tool from Activity 3 to revise and add to
your argument.
Question: Why is the skin cancer rate in Australia so high?
A 50W light bulb is in a socket supplied with 140V. What is the current in the bulb?
A torque of T= 4Nm is required to rotate the intermediate cylinder at W= 30 rad/min .
Calculate the viscosity of the
oil. All cylinders are 450 mm long. Neglect the end effects.
R=0.15m, t=0.003 m.
Result: 1.258 N.s/m
The viscosity of the oil with a torque 4Nm and a rotational speed is 30 rpm is 0.2003 N.s/m.
From the given,
torque = 4Nm
rotational speed = 30 rpm = (30 × 3.14)/60 = 3.14 rad/sec
radius = 0.15 m
thickness (h) = 0.003 m
To find linear velocity,
V = R×ω
= 0.15×3.14
V =0.471 m/s
The dragging force,
F = 2μA(V/h) (V is linear velocity and h is the thickness )
Area = area of cylinder = 2πRH, R is radius and H is the height of the cylinder.
F = 2μ(2πRH) (V/h)
= 2μ(2×3.14×0.15×0.45) (0.471/0.003)
= 133.10 μ (μ is the viscosity of the oil)
F = 133.1μ
Torque (τ) = Force × radius
4 Nm = 133.1μ × 0.15
μ = 4 / (133.1×0.15)
= 0.2003 N.s/m
The viscosity of the oil is 0.2003 N.s/m.
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For each of the following statements: Justify the correct statements and rewrite the false statements correctly.
1- U is a DC voltage.
This statement is incomplete. It is not clear what "U" refers to. "U" could represent a variety of electrical quantities such as voltage, current, or resistance, and "DC" could refer to direct current or even some other meaning depending on the context. To justify the correctness of the statement, we need more information on what "U" represents and the context in which it is being used.
If the statement is false and it was intended to say "V is a DC voltage", then a correct statement could be: "V is a voltage that does not change direction over time, known as direct current (DC)."
If the statement is false and it was intended to say "U is an AC voltage", then a correct statement could be: "U is a voltage that alternates in direction over time, known as alternating current (AC)."
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• A plastic bag filled with air has a volume of
0.008 m3. When air in the bag A plastic bag filled with air has a volume of 0.008 m^3. When air in the bag is squeezed into a
rigid container, the mass of the container (with air)
increases from 0.02 kg to 0.03 kg. Use the formula
density
volume
to calculate the density of the air in the bag.
Answer:
The change in the mass of box = 0.01 kg
Volume of air in the polythene bag = Volume of air in the rigid box
Therefore, Volume of air in the box = 0.008 m^3
Now, Density = Mass/ Volume
=> Density = 0.01 / 0.008 = 1.25 Kg / m^3
Explanation:
I looked it up
For 2 non-perpendicular vectors, R is calculated by component method.
5. A baseball player leaves the bench and runs A= 25 m [E] and then B=40 m [SW].
Draw these two vectors, determine their x- and y-components, then draw their
resultant vector R by triangle method .Use scale 5 m= 1 cm. Calculate R by
component method and compare with the graphical value.
Answer:
30.3 meters, 172 degrees.
Explanation:
A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?
The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.
Electrostatic attractionSince the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.
The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.
According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.
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Why is the pressure so high deep inside the outer planets?
Answer:
Due to its larger size
Explanation:
This is due to those planets being much larger than Earth. The larger a planet is, the more gravity that planet has, since gravity is mainly calculated based on the mass and radius of the planet. Also since the pressure deep inside of the planet depends mainly on the gravity of that planet on the surface, this is calculated as the square of the planet's surface gravity. Ultimately, the bigger the planet is the higher the pressure deep inside the planet will be.
PLEASE HELP AND SHOW WORK,THANK YOU!!
4) Suppose that two identical
mass planets are sitting
million miles apart. At that
distance the planets have a
gravitational force of 1,000,000 N.
If the planets are moved
to two million miles apart, what
is the new gravitational force
between them?
The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N
The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Given:
Initial distance between the planets = 1 million miles
Initial gravitational force = 1,000,000 N
Final distance between the planets = 2 million miles
To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.
Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.
According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:
(F2/F1) = (d1/d2)²
Substituting the given values:
(F2/1,000,000 N) = (1 million miles / 2 million miles)²
Simplifying:
(F2/1,000,000 N) = (1/2)²
(F2/1,000,000 N) = 1/4
F2 = (1/4) * 1,000,000 N
F2 = 250,000 N
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What type of atomic radiation will most deeply penetrate matter?
Multiple Choice
Beta radiation
Gamma radiation
Alpha radiation
a roller coaster weighs 2000 kg This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.
The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.
Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.
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100picometer is equal to
Answer:
100picometer is equal to:
0.1 NanometreExplanation:
Hope this works !!Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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A gas expands from I to F in the figure. The energy added to the gas by heat is 465 J when the gas goes from I to F along the diagonal path. What is the change in internal energy of the gas?
The gas's internal energy that expands from I to F changes by 1015 J.
How to determine internal energy?Since the gas is expanding and energy is added to it by heat, the change in internal energy of the gas can be calculated using the first law of thermodynamics, which states that:
ΔU = Q - W
where ΔU = change in internal energy,
Q = heat added to the system, 465 J and
W = work done by the system.
Assuming that the process is quasi-static use approximation known as the "staircase approximation."
By adding up the work done in each step, find that the total work done by the gas is approximately -550 J. The negative sign indicates that work is done on the gas.
Therefore, using the first law of thermodynamics, we can calculate the change in internal energy of the gas as:
ΔU = Q - W
ΔU = 465 J - (-550 J)
ΔU = 1015 J
Therefore, the change in internal energy of the gas is 1015 J.
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To better understand crash dynamics we have to look at "__________."
A. the law of gravity
B. Bernoulli's principle
C. the laws of motion
D. Archimedes' principle
To better understand crash dynamics we have to look at "the laws of motion."
The laws of motion
The laws of motion were introduced by Sir Isaac Newton in 1687 in his book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), which defined the laws of motion, or three fundamental laws that govern the movement of bodies. The laws of motion, according to Newton, govern the motion of an object or a system of objects that interact.
It defines the concepts of force and mass, and the fundamental dynamics of motion.The following are the laws of motion:Every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. The velocity of an object changes proportional to the force applied to it, and the acceleration of an object is proportional to both its force and its mass. For every action, there is an equal and opposite reaction.
Therefore, these laws are necessary to fully grasp crash dynamics because they explain how objects respond to outside forces that cause them to accelerate or decelerate.
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laws of vector addition
Answer:
laws ig .
Explanation:
The light waves transfer their oscillations and energy to other object in what way?
The frequency of the light waves physically causes the object to move
The energy of the light wave transfers to the electrons of the material which causes them to gain that energy
The wavelength of the light changes the velocity of the atoms in the material
The amplitude of the light will affect how much of it shines on the object
Answer: b the energy of light...
Explanation:
Explain why a solid has a definite shape
and volume.
6. How does the arrangement of atoms in most
solids differ from the arrangement of atoms in
a liquid?
According to the given statement Atoms in solids vibrate motionless, whereas atoms in fluid move.
Where are atoms found?Everything, that's correct. Matter includes all liquids, solids, sand, plants, animals, and clouds. The building components of matter are called atoms. All stuff is made up of numerous atoms, like how this house is built of many bricks. Because they are not living entities, atoms don't require food, water, or oxygen, and they can't procreate.
Can you kill an atom?The law of energy conservation states that matter cannot be generated or destroyed. As a result, an atom could be destroyed or divided into smaller particles. The electron, proton, the neutron are the three fundamental particles that make up an atom.
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An electric field has a magnitude of 400 N/C and makes an angle
60
o
with the perpendicular to the surface of a flat surface of dimensions 30 cm by 20 cm. Calculate the electric flux through the surface.
The electric flux through the surface is 20.78Nm^2/C
E=400 N/C
A=30×10^−2×20×10^−2
=6x10^-2
Now, we know that ∫ϕ=∫Eda
=E.A
=Eacosθ
As the surface make 60°
But we have to calculate according to area vector which is perpendicular to the surface, ∴→θ=90°-60°=30°
∴ϕ=Eacosθ=400×6×10^−2×cos30° =20.78Nm^2/C
The amount of electric lines of force (or electric field lines), which cross a specific area, is referred to as electric flux, a feature of an electric field. According to this theory, electric field lines begin with positive electric charges and end with negative charges. Field lines pointing toward a closed surface are deemed negative, whereas those pointing away from it are deemed positive. Every field line directed into a closed surface continues through the interior if there is no net charge there and is directed outward somewhere else on the surface.
The net, or total, electric flux is zero because the negative flux barely equals the positive flux in magnitude. If a closed surface is holding a net charge, the total flux through the surface will be positive if the charge is positive and negative if it is negative.
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The state of the atmosphere at a particular time and place is called the ————-.
Answer:
= weather
Explanation:
Which of the following best describes Earth's crust, according to the theory of plate tectonics?
Answer:
the Earth's crust is broken into about 12 plates that float on hotter, softer rocks in the underlying mantle
Explanation:
Pls help!!
Which situation describes a system with increasing gravitational potential energy?
a boy jumping down from a tree limb
a girl stretching a horizontal spring
a bicyclist riding up a steep hill
a train speeding up on a flat track
C) a bicyclist riding up a steep hill
The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:
A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.
Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.
How is Newton's Third Law of Motion used in the sport Jokgu?
Newton's third law of motion states that every force has an equal and opposite reaction force. That is when two bodies interact with each other, they apply a force on each other which are equal in magnitude and opposite in direction.
In Jokgu, when you hit the ball it applies an equal force on the leg. And when a player presses his leg against the ground, the ground exerts an equal force on the player which helps him to move around.
During a home run, the batter only needs to run around all 4 bases if he wants to, since the ball cleared the outfield fence.
True
False
Answer: False
Explanation:
The gravitational force between two objects is 50N. If the mass of one object is quadrupled and the distance is doubles, what is the new force?
If the mass of one object is quadrupled and the distance is doubled, the new gravitational force will be the same or equal to 50 N.
What is gravitational force?The gravitational force can be thought of as an attracting force that pulls all mass-containing physical objects toward it. It is by far the least powerful known natural force.
The gravitational force, F, of attraction between two objects, is given mathematically as follows:
F = GM₁M₂/r²
where;
G is the gravitational force constant
M₁ is the first mass
M₂is the second mass
r is the distance of separation
Given that the gravitational force between two objects is 50N.
If the mass of one object is quadrupled and the distance is doubled, the new force will be:
F = 4 * GM₁M₂/(2r)²
F = GM₁M₂/r²
Hence, the force remains the same.
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If a car travels 400m
in 25s
Calculate the
average Speed