A blimp moving west with a force of 30 n encounters a 20 n headwind blowing east.the buoyant force experienced by the blimp is 500 n,and the force of gravity acting on it is 450 n.what are the net horizontal and vertical forces acting on the blimp?

The best choice for screening a person's genetics for 1,000 or more genes would be: C. Sequencing.

Sequencing techniques, such as next-generation sequencing (NGS), are well-suited for screening a large number of genes efficiently and comprehensively. NGS allows for high-throughput sequencing of DNA, enabling the simultaneous analysis of multiple genes or even the entire genome. It provides detailed information about the sequence of nucleotides in the DNA, allowing for the identification of genetic variations, mutations, or other genomic features.

Microarray analysis (A) is a technique that can analyze gene expression patterns or detect specific genetic variations, but it is limited in the number of genes it can assess simultaneously compared to sequencing.

RELP analysis (B) is a technique used for detecting genetic variations based on restriction enzyme digestion patterns, but it is more suitable for specific target regions rather than screening a large number of genes.

Karyotyping (D) involves the visualization and analysis of chromosomes to detect large-scale chromosomal abnormalities but is not suitable for screening a large number of individual genes.

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The order which reflect clomiphene's mechanism of action include the following:

This is the process in which a mature egg is released from the ovary and clomiphene is a medication which induces it.

This is done by the steps mentioned above so as to ensure mature egg is released for fertilization.

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The value of r is 0.0868 and the error percentage is 5.78%.

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Tension force is the force applied on the ball in a horizontal direction or along the that makes the ball in motion

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2 C 4 H 10 ( g ) +  13 O 2 ( g )  =  8 C O 2 ( g ) +  10 H 2 O ( g )

Answer:

c

Explanation:

QUESTION :WHAT TYPE OF BOND IS CA + AR

ANSWER :

C .

COVALENT.

HOPE IT HELP

THANK ME LATER.

The approximate molecular mass of the oligopeptide with the given amino acid sequence is 1821 Da.

To find the approximate molecular mass of the oligopeptide with the amino acid sequence Ala-Gly-Asp-Leu-Lys-Arg-Gln-Lys-Leu-Lys-Ala-Glu-Arg-Leu-Pro, you need to follow these steps:

1. Identify the molecular mass of each amino acid in the sequence.
2. Add up the molecular masses of all amino acids.
3. Subtract the mass of one water molecule (18 Da) for each peptide bond.

Here are the molecular masses for each amino acid in the sequence:
Ala (A) - 89 Da
Gly (G) - 75 Da
Asp (D) - 133 Da
Leu (L) - 131 Da
Lys (K) - 146 Da
Arg (R) - 174 Da
Gln (Q) - 146 Da
Lys (K) - 146 Da
Leu (L) - 131 Da
Lys (K) - 146 Da
Ala (A) - 89 Da
Glu (E) - 147 Da
Arg (R) - 174 Da
Leu (L) - 131 Da
Pro (P) - 115 Da

Now, add up the molecular masses of all amino acids:
89 + 75 + 133 + 131 + 146 + 174 + 146 + 146 + 131 + 146 + 89 + 147 + 174 + 131 + 115 = 2073 Da

There are 14 peptide bonds in the oligopeptide, so subtract the mass of 14 water molecules:
2073 - (14 * 18) = 2073 - 252 = 1821 Da

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The chlorine atom only requires one more electron to fulfill its octet because the potassium atom only has one valence electron and has seven total electrons.

Protons, positive charged particles, and neutrons, neutral charged particles, make up the nucleus of each atom. Around the nucleus are electrons, which are negative particles. Atoms of the same element share the same chemical characteristics and mass, but atoms of other elements have unique chemical characteristics and masses. Compounds are created when atoms join in ratios of few whole numbers.

A compound is a substance made up of two or more types of elements together in a specific proportion of their atoms. As the components are combined, they interact with one another.

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A circumpolar animal dwells at the poles.

Animals are found in different areas. The areas that are inhabited by an animal is called the habitat of the animal. Different animals have different habitats.

However, the animals that are found around the poles are said to be circumpolar. In nutshell, a circumpolar animal dwells at the poles.

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The estimated age of the rock is approximately 1.58 x 10^10 years.

To estimate the age of the rock based on the mass ratio of 208Pb to 232Th, we can use the concept of radioactive decay and the half-life of 232Th.

The ratio of 208Pb to 232Th in the rock represents the amount of 208Pb that has been formed through the radioactive decay of 232Th over time. Since one 208Pb atom is the final decay product of one 232Th atom, the mass ratio can be used to determine the fraction of 232Th that has decayed.

Given that the mass ratio of 208Pb to 232Th is 0.28/1.00, we can calculate the fraction of 232Th that has decayed as follows:

Fraction of 232Th decayed = (1 - mass ratio of 208Pb/232Th) = (1 - 0.28/1.00) = 0.72

The fraction of 232Th that has decayed corresponds to the fraction of the original amount of 232Th present in the rock. Using the concept of half-life, we can relate this fraction to the age of the rock.

Since the half-life of 232Th is 1.39 x 10^10 years, we can calculate the number of half-lives that have passed using the fraction of 232Th decayed:

Number of half-lives = log(base 0.5) (fraction of 232Th decayed)

Number of half-lives = log(base 0.5) (0.72) ≈ 1.14

The number of half-lives represents the time elapsed, and each half-life is equal to 1.39 x 10^10 years.

Therefore, the age of the rock can be estimated as:

Age of the rock = Number of half-lives x Half-life of 232Th

= 1.14 x 1.39 x 10^10 years

≈ 1.58 x 10^10 years

The estimated age of the rock is approximately 1.58 x 10^10 years.

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Answer:

2.5 g mass of Ra-226 will remain after 4800 years.

Explanation:

Given data:

Mass of Ra-226 = 20 g

Sample remain after 4800 years = ?

Solution:

Half life of Ra-226 = 1600 years

Number of half lives passed = T elapsed / half life

Number of half lives passed = 4800 year / 1600 year

Number of half lives passed = 3

At time zero = 20 g

At first half life = 20 g/2 = 10 g

At 2nd half life = 10 g/2 = 5 g

At 3rd half life = 5 g/2 = 2.5 g

Thus, 2.5 g mass of Ra-226 will remain after 4800 years.

Answer:

evaporation means the state of the water went from liquid to gas which is a physical change. the sugar is still in the beaker which means its chemical properties did not change.

Explanation:

Answer:

The Answer would be D. N2O3

Explanation:

the Chemical bond is a Covalent bond to which the prefixes are Di and tri

From the given data of chemical compounds, 5.32 grams of W and 2.66 grams of X are needed.

The following calculation must be done to determine how much W and X is needed to make the necessary amount of Z because it takes 8 grammes of a chemical compound called Z to make it, and Z is made from compounds W, X, and Y in the ratios of 2: 1: 3 and Y is itself made from W and X, and to make 6 grams of Y requires 4 grams of W and 2 grammes of X.

8/6 = 1.33

The resulting ratio is 2.66 : 2.33  :3:99.

3.99 = w

3.99 x 4/6 = 2.66

1.33 grams of X are equal to 2.66 grams of W.

2.66 x 2 = 5.32

1.33 x 2 = 2.66

5.32 grams of W and 2.66 grams of X are therefore needed.

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A certain sample of liquid has a mass of 42 grams and a volume of 35 centimeters. The density of the liquid is 1.2 g.cm⁻³

You follow the same procedures you would for a solid to determine the density of a liquid. Divide the mass of the fluid by its volume after computing its volume and weight. Weigh the substance inside the container, then pour it out and weigh the resulting empty vessel. The weight of the empty container is subtracted from the weight of the filled container to determine the fluid's mass.

Mass  =  42gms

Volume  =  35 cm³

Formula Used:

Density  =  Mass ÷ Volume

Putting values,

Density  =  42 g ÷ 35 cm³

Density  =  1.2 g.cm⁻³

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Answer: disagree

Explanation:

The gene traits of offsprings depends on the inheritance from parent. There will be some dominants traits as well as recessive traits from parents. Hence the statement is incorrect.

Inheritance is the biological process of transferring genes from parents to offsprings. Identical daughter cells are produced through cell division. Cell division carries through methods such as mitosis, meiosis, binary division etc.

The genetic traits from parents inherited to the offsprings sometimes be equal from both parents and called the homozygous. Whereas the if the traits transferred is unequal it is referred to as heterozygous.

The trends in inheritance is studied well by Griger Mental, who proposed the punnett square to predict the pattern of genetic traits inherited from parents. Hence, the genetic traits both quantitative and qualitative traits are dependant upon both parents and the environmental factors.

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The best reagents to convert 1-hexyne into (e)-1,2-dibromo-1-hexene are 1 equiv. Br2 in CCl4, followed by NaOH to convert the mixture of (Z)- and (E)-isomers to the desired (E)-isomer.

This reaction is called the Vicinal Dibromination reaction. Option A: xs Br2 in CCl4 is a good choice of reagents, but it will give a mixture of (Z)- and (E)-isomers. Option B: 1 equiv. HBr will result in the formation of (Z)-1-bromo-1-hexene. Option C: ROOR is a radical initiator and will not result in the desired product.

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Answer:

In biological systems, matter is continuously changing states through chemical processes. For example, carbon in the form of the gas carbon dioxide is changed into glucose, a solid. This change, of course, occurs during photosynthesis.

Answer:

B. NH4CI

Explanation:

Answer: solid chemicals in waterharden and form rocks

Explanation:

Answer:

Fragments of rock are squeezed and cemented together.

Explanation:

I took the test and got the answer below:

Answer:

heat energy is released into the surrounding

Answer:

D. Pimmada's candle burning.

Explanation:

The new volume is calculated in each condition as follows using ideal gas equation .

The ideal gas law is the equation of condition of an ideal gas. It states that pressure into volume is equal to nRT where n is moles and T is temperature.

1. P1V1=P2V2

50*100= V2 * 10

V2= 500 Liter

2. V1/T1 = V2/T2

20/200 = V2/400

V2= 40 Liter

3. P1V1=P2V2

100*20= V2 * 60

V2= 33.33 Liter

4.  V1/T1 = V2/T2

800/400 = V2/100

V2= 200 Liter

5. P1V1/T1 = P2V2/T2

20*100/100 = 10*v2/200

v2= 400 Liter

6. P1V1/T1 = P2V2/T2

5*200/100 = 10*v2/50

v2= 50 Liter

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Answer:

A solution in which the maximum amount of solvent has been dissolved

Explanation:

For example, 36g of salt in 100g of water.

The partial pressure of oxygen in his lungs will be 108 kPa.

The correct option is C.

The partial pressure of oxygen is 21.39 kPa. The correct option is B.

The number of moles of oxygen that you take in is 4.845 moles.

The pressure of oxygen in the lungs of the diver is calculated below:

The Pressure of oxygen = 21 % * 512 kPa

The Pressure of oxygen = 108 kPa.

The partial pressure of oxygen = Total pressure -  partial pressure of water vapor

The partial pressure of oxygen = 22 kPa - 0.61 kPa

The partial pressure of oxygen = 21.39 kPa

The number of moles of oxygen taken in, n = PV/RT

n = 1000 * 12 / 8.31 * 298

n = 4.845 moles

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Answer:

108 kPa.

Explanation:

Answer:

C

Explanation:

No change.

The total number moles of products = The Total number of reactants

Answer:

Peter

Explanation:

Peter has more power, as he is able to lift the same amount of weight as Paul in a much shorter time.

If Paul can lift 100kg 10 times in 1 minute, and Peter can lift 100kg 10 times in 10 seconds, Peter is 6 times stronger than Paul, because 1 minute, or 60 seconds, is 6 times longer than 10 seconds.

Approximately 15.14 grams of iron(II) chloride are needed to produce 32.3 grams of iron(II) phosphate in the presence of excess sodium phosphate.

To determine the amount of iron(II) chloride needed to produce 32.3 g of iron(II) phosphate in the presence of excess sodium phosphate, we need to consider the balanced chemical equation for the reaction. The balanced equation is as follows:

3 FeCl2 + 2 Na3PO4 → Fe3(PO4)2 + 6 NaCl

From the balanced equation, we can see that the molar ratio between iron(II) chloride and iron(II) phosphate is 3:1. This means that for every 3 moles of iron(II) chloride, we get 1 mole of iron(II) phosphate.

To find the number of moles of iron(II) phosphate, we divide the given mass of iron(II) phosphate by its molar mass. The molar mass of iron(II) phosphate (Fe3(PO4)2) can be calculated by adding up the atomic masses of each element:

Fe: 55.85 g/mol
P: 30.97 g/mol
O: 16.00 g/mol (x 8 atoms)

Fe3(PO4)2 = (3 x 55.85 g/mol) + (2 x 30.97 g/mol) + (8 x 16.00 g/mol) = 357.66 g/mol

Now, we can calculate the number of moles of iron(II) phosphate:

Number of moles = Mass / Molar mass
Number of moles = 32.3 g / 357.66 g/mol = 0.0904 mol

Since the molar ratio between iron(II) chloride and iron(II) phosphate is 3:1, we need 3 times the number of moles of iron(II) phosphate to get the corresponding moles of iron(II) chloride:

Number of moles of FeCl2 = 3 x 0.0904 mol = 0.2712 mol

Finally, we can calculate the mass of iron(II) chloride needed using the molar mass of FeCl2 (55.85 g/mol):

Mass = Number of moles x Molar mass
Mass = 0.2712 mol x 55.85 g/mol = 15.14 g

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The correct term to complete the sentence is:
The more positive the value of E°red, the greater the driving force for reduction. The correct option is A.

In electrochemistry, E°red refers to the standard reduction potential of a half-cell reaction. This value measures the tendency of a species to gain electrons, undergoing reduction. The more positive the E°red, the more likely the species will be reduced, making it a stronger oxidizing agent.

A positive E°red indicates a spontaneous reduction process, which favors the forward reaction in an electrochemical cell. On the other hand, a negative E°red implies that the reduction is non-spontaneous, and the species is more likely to undergo oxidation. Therefore, a positive E°red value provides a greater driving force for reduction.

In summary, the standard reduction potential (E°red) helps us understand the relative tendencies of species to undergo reduction. When comparing various species, those with more positive E°red values have a greater driving force for reduction, making them stronger oxidizing agents in electrochemical reactions.

Thus, the correct option is A.

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In an experiment, we can define 3 types of variables.

Independent variables: Are these ones that the scientist can control and modify, in this case, would be the kind of rubber for the tires.

Dependent variables: Are the variables that react to the changes in the independent variables. In this case, would be "how much lasts each type of rubber".

Controlled variables: Are all of these variables that also have an impact on the dependent variable, so we need to control them (fix them) so they do not affect the study of the independent variable.

So, for this particular experiment, to find controlled variables we need to think on what things do affect the durability of tires.

Some examples can be:

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