The first-order decomposition of cyclopropane has a rate constant of 6. 7 x 10-4 s-1. if the initial concentration of cyclopropane is 4. 33 m, what is the concentration of cyclopropane after 234 s?
The concentration of cyclopropane after 234 s is 3.70M, using formula of half life.
As indicated by units of k, this is a first order reaction.
We can use the integrated rate law \([A] = [A]_{0} e^{-kt}\)or we can use half life.
First order half life = 0.693/k = 0.693/6.7x10-4 s-1
1034s = \(t\frac{1}{2}\)
number of half lives elapsed =234sec x 1 half life/1034 sec = 0.226 half lives elapsed
Fraction remaining = \(0.5^{n}\)
where n is half lives elapsed
Fraction remaining = \(0.5^{0.226}\)
Fraction remaining = 0.855
Concentration remaining = 4.33 M x 0.855 = 3.70 M
Therefore, concentration of cyclopropane after 234 s is 3.70M, using formula of half life.
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Change 60. miles/hour to km/min?
A buffer solution is prepared by adding NH4CIto a solution of NH3 (ammonia).NH3(aq) + H2O(0) = NH4+ (aq) + OH-(aq)What happens if HCl is added?
ANSWER
The addition of HCl will shift to reactants
EXPLANATION
When some strong acid is added to a buffer, the equilibrium is shifted to the left, and the hydrogen ion concentration increases by less than expected for the amount of strong acid added. Buffer solution helps in adjusting the pH of a substance.
Since the HCl is a strong acid, it will shift to the left (reactant sides)
Copper has the highest conductivity of any metal used in electronics. True False Question 54 (1 point) Express the number .000000as9? using the powers of ten. A) \( 3597 \times 10^{-9} \) B) \( 35.97
Copper has the highest conductivity of any metal used in electronics. The statement is false.
Silver is the element that conducts electricity the best, followed by copper and gold.
The earth's most conductive metal is by far silver. Silver only has one valence electron, which explains this. This one electron can also go about freely and encounter little opposition. As a result, some of the metals with this particular property are silver and copper.
Silver is the metal with the highest thermal and electrical conductivity because of its distinctive crystal structure and lone valence electron.
Since copper is the non-precious metal with the highest conductivity, it has a higher electrical current carrying capacity than other non-precious metals. The strength of the metal rises when tin, magnesium, chromium, iron, or zirconium are added to copper to create alloys, but its conductivity decreases.
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. 11 gallons of gasoline for $26.29
or 6 gallons of gasoline for $14.45?
Answer:
6 gallons of gasoline for $14.45 is the best price
Explanation:
26.29/11=2.39 $ per gallon
14.45/11=1.31 $ per gallon
suppose a beaker of isobutyl alcohol is put inside a sealed tank containing isobutyl alcohol gas at 103. degree c and 619. torr. after ten minutes, will there be more liquid in the beaker, less liquid, or the same amount?
Based on the Laws of Thermodynamics, when a beaker of isobutyl alcohol is put inside a sealed tank containing isobutyl alcohol gas at 103.
Degree c and 619. torr, the pressure inside the tank will be higher than the pressure in the beaker, causing some of the liquid to evaporate and increase the liquid volume in the beaker. Therefore, after ten minutes, there will be more liquid in the beaker than before.
When a beaker of isobutyl alcohol is put inside a sealed tank containing isobutyl alcohol gas at 103°C and 619 torr, the molecules of isobutyl alcohol gas in the tank will be more energetic due to the increased temperature. As a result, they will move faster and collide with each other more frequently, raising the pressure inside the tank. The higher pressure in the tank will push molecules of isobutyl alcohol gas into the beaker, where they will condense into liquid due to the decrease in pressure.
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what is always formed when a strong acid solution reacts with a strong base solution?
Answer:
water and salt
Explanation:
A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water. The neutralization of a strong acid and strong base has a pH equal to 7.
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PLS MARK BRAINLIEST
what is the formula for disphosphorous trioxide
Answer:
P4O6 is the formula
Explanation:
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this is just to make sure but plz help
Which of these is a disadvantage of using natural gas A It is not considered safe to use in homes. B Scientists have developed new ways of extracting it C It burns less cleanly than other fossil fuels D Extraction through fracking can contaminate groundwater
Answer:
A
Explanation:
Natural gas is flammable. A natural gas leak in a house can cause potential fires, and inhaling the gas can cause natural gas poisoning.
* Answer B: The fact that scientists have developed new ways of extracting natural gas - is an advantage, not a disadvantage.
* Answer C is wrong, because compared with some other fossil fuels, natural gas emits the least amount of carbon dioxide into the air when combusted -- making natural gas the cleanest burning fossil fuel of all.
* Answer D: the content of the statement is about the production process, not about using of natural gas.
....
Hope this answer can help you. Have a nice day!
Answer:
Explanation:D Extraction through fracking can contaminate groundwater
The isotope uranium-238 decays at a constant rate (half-life of 8.2 x 1015 years). It also occasionally divides in half, and in this process of fission the two parts are violently repelled from one another, creating track-like scars in crystalline materials and obsidian. By counting the frequency of fission tracks and comparing this to the known rate for fission, the archaeologist can calculate the age of the sample. This dating technique is called
The dating technique described in your question, which involves counting the frequency of fission tracks in a sample and comparing it to the known rate of fission, is called fission track dating.
This method relies on the decay of uranium-238, which has a half-life of 8.2 x 10¹⁵ years.
When uranium-238 undergoes fission, the resulting fragments are violently repelled from each other, leaving behind track-like scars in materials such as crystalline substances and obsidian.
By measuring the number of fission tracks in a sample and knowing the rate of fission, archaeologists can estimate the age of the sample.
Fission track dating has been used to determine the ages of various geological and archaeological materials.
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The carbon dioxide concentration in the atmosphere was 282 parts per million (ppm) in the year 1750. In the year 2010, this increased to 387 ppm. Calculate the percentage increase in carbon dioxide concentration over this period of time.
The percentage increase in carbon dioxide concentration over this period of time is 37.23%.
How to calculate percentage increase?Percent increase refers to how much a percentage has gone up over time.
In order to calculate this number, one would need to find the difference between the original value and the final value, subtracting to find the exact total of the decrease.
According to this question, carbon dioxide concentration in the atmosphere was 282 parts per million (ppm) in the year 1750. In the year 2010, this increased to 387 ppm. The percentage increase can be calculated as follows:
% increase = (387 - 282)/282 × 100
% increase = 37.23%
Therefore, 37.23% is the percentage increase in the concentration of carbondioxide.
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Answer: 105 ppm
Explanation: The increase is: 387 – 282 = 105 ppm
Which one(s) of the following statements about the buddy system for allocating memory is/are TRUE? A. The buddy system is ideal for quickly allocating pages on demand for user-space applications B. The buddy system ensures allocation that is free of internal fragmentation C. With the buddy system, memory segments can be either divided or coalesced, to satisfy an allocation request D. The buddy system allocates memory that is physically contiguous None of the mentioned
The correct statement about the buddy system for allocating memory is:
C. With the buddy system, memory segments can be either divided or coalesced to satisfy an allocation request.
The buddy system is a memory allocation technique used in operating systems. It divides memory into fixed-size blocks or segments, typically in powers of two. When a memory allocation request is made, the system looks for a free block of suitable size. If the block is larger than required, it can be divided or split into smaller blocks to satisfy the request. Conversely, if adjacent blocks are free, they can be coalesced or merged to form a larger block for allocation.
A. The buddy system is not specifically designed for quickly allocating pages on demand for user-space applications. It is a general memory allocation strategy used in various contexts.
B. The buddy system may still result in internal fragmentation. Internal fragmentation occurs when allocated memory blocks are slightly larger than the requested size, leaving unused space within the block.
D. The buddy system does not guarantee physically contiguous memory allocation. It can allocate memory from different available blocks, which may or may not be physically contiguous.
Therefore, the only true statement is C. With the buddy system, memory segments can be either divided or coalesced to satisfy an allocation request.
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pure potassium hydrogen phthalate (khp) is used for the standardization of the naoh solution. suppose the khp is only 90% pure. will the reported molarity of the naoh be too high, too low, unaffected? explain why.
the reported molar concentration of the sodium hydroxide solution will be too high when is used for the standardization of the naoh solution.
The term "standardization" in scientific or analytical chemistry means the process of determining standards or concentrations of a particular substance.
One of the benefits of standardization, and the most important one, is that you get results with minimal error.
.A standard solution has an accurately known concentration and for this experiment sodium hydroxide was standardized with a primary standard acid, potassium hydrogen phthalate. A primary standard could be any pure chemical that can be used as the initiation of a quantitative analysis.
If the khp is only 90% pure, the real mass of the acid will be less than weighed doing less the real moles of potassium hydrogen phthalate. Thus, in titration, volume of NaOH will be less than real volume and reported molar concentration will be too high.
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The yield of a chemical process is being studied. From previous experience, yield is known to be normally distributed and σ=3 . The past five days of plant operation have resulted in the following percent yields: 91.6, 88.75, 90.8, 89.95, and 91.3.
a. Find a 95% two-sided confidence interval on the true mean yield. b. Find a 95% upper level confidence interval on the true mean yield. c. How many samples of yield is needed to obtain a 95% two-sided confidence interval with width 1? d. If we don't know the value of σ , how would the 95% two-sided confidence interval be?
The two-sided confidence interval is (87.85 ≤ μ ≤ 93.11) , with 87.85 being the lower level and 93.11 being the upper level.
What is a yield in an experiment?The amount of product you actually get after doing an experiment is known as the experimental yield. Calculating the % yield will show you how much of the theoretical yield you actually achieved in a particular experiment. The quantity of pure and dry product produced in a chemical reaction is known as the reaction yield (absolute yield). The relative or percentage yield (%) is typically determined in order to assess the effectiveness of a chemical process in organic synthesis.
How is the yield of a chemical reaction determined?The percent yield can be calculated by applying the following formula:%yield = (actual yield/theoretical yield) x 100.
Brifieng:Step-by-step explanation:
Given the data:
91.6, 88.75, 90.8, 89.95, 91.3
Mean, m = Σx / n
n = sample size = 5
Mean = 452.4 / 5 = 90.48
Standard deviation, σ = 3
Zcritical at 95% = 1.96
Confidence interval :
Mean ± Error margin
Error margin = Zcritical*σ/sqrt
Error margin = 1.96 * 3/sqrt(5)
Error margin = 2.630
Lower boundary : 90.48 - 2.630 = 87.85
Upper boundary : 90.48 + 2.630 = 93.11
(87.85 ; 93.11)
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which gas is not an example of a naturally occurring greenhouse gas?responsesnitrous oxidenitrous oxidemethanemethanechlorofluorocarbonchlorofluorocarbonwater vapor
Chlorofluorocarbons (CFCs) are not naturally occurring greenhouse gases.
Chlorofluorocarbons (CFCs) are not naturally occurring greenhouse gases. They are synthetic compounds that were widely used in refrigerants, solvents, and aerosol propellants.
CFCs were found to deplete the ozone layer in the upper atmosphere, leading to the adoption of the Montreal Protocol to phase out their use.
While they are not naturally occurring, they contribute significantly to global warming due to their strong greenhouse effect.
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Some materials are classified as poor conductors of electricity. They allow electricity to pass under certain conditions. Explain with the help of an example.
Answer:
Explanation:
Some substances are poor conductors because they do not possess freely moving ions but they conduct electricity in their aqeous solution beacuse their ions become free to move when dissolved in water. Common example of such substances is NaCl which is commnly called table salt
a sample of (NH4)2SO4 contains 0.750 mole. what is the mass of the sample
Explain why leaf-cutter ants gather pieces of leaves and store them in their nests when they do not eat leaves.
Answer:
Sample response: Leaf-cutter ants gather pieces of leaves and store them in their nests to provide raw materials and food for the fungus that grows on the leaf pieces. The ants feed on the fungus, so by collecting leaves the ants are effectively able to grow their own food supply.
Explanation:
Answer:
Leaf-cutter ants gather pieces of leaves and store them in their nests to provide raw materials and food for the fungus that grows on the leaf pieces. The ants feed on the fungus, so by collecting leaves the ants are effectively able to grow their own food supply.
Explanation:
edg 2020
Assume that NO is continuously synthesized. The addition of a saturating concentration of L-NMMA to a relaxing aortic ring with intact endothelium would probably:
The addition of a saturating concentration of L-NMMA to a relaxing aortic ring with intact endothelium would probably affect the synthesis of NO. L-NMMA is a competitive inhibitor of nitric oxide synthase (NOS), which is the enzyme responsible for the synthesis of NO. By inhibiting NOS, L-NMMA would prevent the production of NO, leading to a decrease in its concentration in the aortic ring.
Nitric oxide (NO) is continuously synthesized in the body, and it plays a crucial role in regulating blood Nitric oxide (NO) is continuously synthesized in the body, and it plays a crucial role in regulating blood vessel tone and promoting vasodilation. In the presence of intact endothelium, the endothelial cells release NO, which diffuses to the underlying smooth muscle cells of the blood vessels and causes relaxation.
L-NMMA (N-monomethyl-L-arginine) is a competitive inhibitor of the enzyme nitric oxide synthase (NOS), which is responsible for the synthesis of NO. When a saturating concentration of L-NMMA is added to a relaxing aortic ring with intact endothelium, it would likely inhibit the activity of NOS. As a result, the production of NO would be decreased, leading to vasoconstriction and a decrease in the relaxation of the aortic ring.
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1-If the reaction between hydrogen and iodide absorbs
7. 93x10 J of heat , how many moles of iodine were consumed ? H₂ ( g
) + 1₂ ( s ) → 2 HI ( g ) AH = 53. 0 kJ
2- How many grams of oxygen gas a
Approximately 0.15 moles of iodine were consumed in the reaction. Use the stoichiometry of the balanced equation to find the moles of iodine.
To find the moles of iodine consumed in the reaction, we can use the given heat absorbed and the heat of the reaction (AH). The heat absorbed is given as 7.93x10 J, which we need to convert to kilojoules (kJ) by dividing it by 1000.
7.93x10 J ÷ 1000 = 7.93x10 kJ
Now, we can use the stoichiometry of the balanced equation to relate the heat of the reaction (53.0 kJ) to the moles of iodine consumed. According to the balanced equation:
H₂ (g) + I₂ (s) → 2 HI (g)
The stoichiometric coefficient in front of I₂ is 1, which means that 1 mole of iodine is consumed in the reaction.
Using the ratio of heat of reaction to moles of iodine, we can set up a proportion:
53.0 kJ ÷ 1 mole of iodine = 7.93x10 kJ ÷ x moles of iodine
Cross-multiplying and solving for x, we get:
x = (7.93x10 kJ)(1 mole of iodine) ÷ 53.0 kJ
x ≈ 0.15 moles of iodine
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The hh genotype gives rise to:
Please select the single best answer
H substance
H secretors
Bombay phenotype
h antibodies
The hh genotype gives rise to the Bombay phenotype.
The Bombay phenotype, also known as the hh phenotype, is a genetic condition that results from a specific combination of alleles at the H blood group locus. People with the Bombay phenotype have a genotype of hh, meaning they do not produce the H antigen on their red blood cells. This can have significant implications for blood transfusions, as the lack of H antigen on the surface of red blood cells can cause a potentially life-threatening reaction when transfused with blood from someone who is an H antigen secreter (i.e., has an HH or Hh genotype).
Therefore, the hh genotype gives rise to the Bombay phenotype, characterized by the absence of the H antigen on red blood cells.
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A student measures the time it takes for two reactions to be completed.
Reaction A is completed in 12 seconds, and reaction B is completed in 21
seconds. What can you conclude about the rates of these reactions?
A. The rates of reactions A and B are equal.
B. The rate of reaction A is lower.
C. The rate of reaction B is lower.
Answer:
c
Explanation:
because the left side of reactant is take more time to make a product than the first
The rate of these reactions should be considered as the option b. The rate of reaction A is lower.
Conclusion of the rate of reactions:Since Reaction A is completed in 12 seconds, and reaction B is completed in 21 seconds.
So based on this, we can say that the rate of reaction A should be lower as it contain 12 seconds as compared to reaction b.
hence, the option b is correct.
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During a lab exam a student looked through the microscope and identified the following cell parts: circular DNA, ribosomes, cell wall, and cytoplasm. What type of cell did she identify?
Eukaryotic
Endoplasmic
Prokaryotic
None of the above
Answer:
The correct answer to this question is a prokaryotic cell.
Explanation:
Prokaryotes have circular DNA and a cell wall, whereas eukaryotes have their DNA packaged into chromosomes and may not have a cell wall (as is the case in animal cells).
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Convert 167.9mL to daL.
Answer:
0.01679
Explanation:
1 ml = 0.0001 dal
167.9×0.0001 = 0.01679
The units like milliliter [mL] and dekaliter [daL] are used to measure the volume of the substance. 167.9mL is converted into daL and is equivalent to 0.01679 daL.
What are units?Units of measurement are used to denote the physical quantities of the substances and are converted into various units of the metric system to express the same quantity but in various expressions. They are the magnitudes that express the various parameters.
The units milliliter [mL] and dekaliter [daL] are used to express the smaller physical quantities of the volume. They are the derived units that arrive from the fundamental units. The units from milliliter [mL] to dekaliter [daL] are converted as:
1 mL = 0.0001 daL
Given,
Volume = 167.9mL
The units are converted as:
1 mL = 0.0001 daL
167.9mL = 167.9mL × 0.0001 daL
= 0.01679
Therefore, 0.01679 daL is the volume.
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calculate the mass of 3.5 moles of copper sulphate
Answer: 558.5545 g
Explanation:
The formula for a sulphate ion is \(\text{SO}_{4}^{\text{ }2-}\), so the formula for copper sulphate is \(\text{CuSO}_{4}\).
The atomic mass of copper is 63.546 g/mol.The atomic mass of sulfur is 32.065 g/mol.The atomic mass of oxygen is 15.994 g/mol.This means the formula mass of copper sulphate is:
63.546+32.065+4(15.994)=159.587 g/mol.So, in 3.5 moles, the mass is (159.587)(3.5)=558.5545 g
In locations with very low dissolved O2 concentrations in drinking water, the observed Ksp of ferrous (II) hydroxide will be:
Since the equilibrium constant can only be affected by temperature, even in low O2 concentration, the Ksp of Fe(OH)2 remains the same.
Dissolved oxygen in water
Aquatic organisms perform gaseous exchange using the gills as such, the oxygen that is present in water is dissolved oxygen. The dissolved oxygen content is also one of the indicators of water quality.
Let us note that Ksp is an equilibrium constant. It is important to note that equilibrium constant can only be affected by the temperature if the system hence, in locations with very low dissolved O2 concentrations in drinking water, the observed Ksp of ferrous (II) hydroxide will be the same.
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The observed Ksp of ferrous ( II ) hydroxide will be : The same
Factor affecting KspIn areas with low dissolved O₂ concentrations in water will still have its Ksp to be the same because the concentration of oxygen does not have a direct impact the Ksp value.
The factor which has a direct impact on the Ksp value of ferrous ( II ) Hydroxide is the change in temperature.
Hence we can conclude that the observed Ksp of ferrous ( II ) hydroxide will be The same.
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What charge does nitrogen form when it satisfies the octet rule?
A: 3
B: -3
C: 5
D: -5
If 24 grams of sodium chloride reacts with an excess amount of magnesium how many grams of sodium oxide will be produced
What results when two waves that are completely out of phase meet?
Answer:
Explanation:Destructive interference occurs when the maxima of two waves are 180 degrees out of phase: a positive displacement of one wave is cancelled exactly by a negative displacement of the other wave. The amplitude of the resulting wave is zero.
If two waves that are completely out phase if meet they results in destructive interference. Hence, their intensities decreases for the resultant wave.
What is interference ?A wave of greater, lower, or the same amplitude is created when two waves merge through interference by combining their displacements at all points in space and time.
The interaction of waves that are coherent or correlated with one another, either because they originate from the same source or because their frequencies are similar or almost identical, leads to both constructive and destructive interference.
All sorts of waves, including light, radio, acoustic, surface water waves, gravity waves, and matter waves, can exhibit interference effects. In constructive interference, the waves are in single phase forms a resultant wave with higher amplitude.
When waves from out of phase meets, the resultant wave will have an amplitude less than the individual amplitudes.
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