A beam of white light is incident on a thick glass plate with parallel sides, at an angle between 0°and 90° with the normal. Which color emerges from the other side first?A) redB) violetC) greenD) None of the given; all colors emerge at the same time.

Answer:

B. gravity

Explanation:

The ball if moving down so gravity is acting on it because it is pulling it down to earths toward the center of earth aka the ground.

The goal of the lab is to investigate the relationship between density and buoyancy. The lab aims to determine how different objects or substances behave in fluids and understand the principles of density and buoyancy through experimental observations and calculations.

The goal of the lab or the question being addressed in the lab report is to investigate and understand the concepts of density and buoyancy. Density refers to the measure of how much mass is contained within a given volume, while buoyancy refers to the upward force exerted on an object submerged in a fluid, such as water or air.

The lab report aims to explore the relationship between density, mass, and volume by conducting experiments and analyzing data. It may involve measurements of different objects or substances, determining their masses and volumes, and calculating their densities. The report may also involve experiments related to buoyancy, such as determining the buoyant force on an object and investigating factors affecting buoyancy.

By conducting the lab and analyzing the obtained results, the lab report aims to provide a deeper understanding of these fundamental concepts in physics and to demonstrate the principles of density and buoyancy through practical experimentation. The report may also include discussions of the significance and applications of density and buoyancy in various fields, such as engineering, architecture, and fluid dynamics.

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Answer: B

Explanation: The wavelength determines color. The wavelength is measured from crest to crest.

When the piston of a pump reaches its lowest point, the volume remaining in the pump is referred to as the residual volume.

Residual volume is the volume of fluid that remains in the pump after the maximum amount of fluid has been displaced. This residual volume can be significant in certain applications, as it can lead to incomplete delivery of fluid or inaccurate measurements.

To minimize residual volume, pump manufacturers may design pumps with low dead space volumes or use specialized mechanisms to ensure complete displacement of fluid.

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The vectors are said to be equal if they have same magnitude as well as same direction.

In case of C and G,

The direction of both the vectors are same but the magnitude of G is more than C.

Thus, C and G are not equal vectors.

In case of E and D,

Both the vectors have opposite direction to each other and the magnitude of D is more than E.

Thus, E and D are not equal vectors.

In case of B and C,

Both the vectors have same direction but the magnitude of C is more than the magnitude of B.

Thus, B and C are not equal vectors.

In case of A and H,

Both the vectors have same direction and both the vectors cover three boxes, thus, the magnitude of the vectors is same.

Hence, A and H are equal vectors.

Answer:

Force pull the child up. With the springs and the weight when you jump.

Assuming that no energy is lost to the surroundings, the final temperature of the water is 26.4 °C.

To solve the problem, we need to use the principle of conservation of heat energy, which states that the total heat gained by a system is equal to the total heat lost.

Let us consider the two systems, copper and water.

Copper Temperature: 100.0 °C

Mass: 20.0 g

Water Temperature: 22.0 °C

Mass: 50.7 g

Let the final temperature of water be x.

Assuming that no energy is lost to the surroundings, the total heat gained by the copper and water is equal to the total heat lost by them. Q gained by copper = Q lost by water

Heat gained by copper = mass of copper x specific heat capacity of copper x change in temperature= 20 x 0.385 x (x - 100)

Heat lost by water = mass of water x specific heat capacity of water x change in temperature= 50.7 x 4.18 x (x - 22)

Therefore,20 x 0.385 x (x - 100) = 50.7 x 4.18 x (x - 22)

Solving for x, we get the final temperature of water as x = 26.4°C.

Hence, the final temperature of the water is 26.4 °C.

Note: In order to solve the question, it is important to use the correct specific heat capacity values for copper and water, which are 0.385 J/g°C and 4.18 J/g°C, respectively.

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Answer:

blue

Explanation:

blue is the only color being reflected, meaning it's the only one that will be visible

Approximately 5808 Newtons is the normal force exerted by the road on the truck.

To find the normal force exerted by the road on the truck, we can use the following equation:

friction force = coefficient of friction × normal force

We can also use the following kinematic equation to relate the stopping distance, initial velocity, and acceleration:

stopping distance = (initial velocity\()^2\)/ (2 × acceleration)

where the acceleration is in the opposite direction of the initial velocity (i.e., to the west).

We can solve this equation for the acceleration:

acceleration = (initial velocity\()^2\) / (2 × stopping distance)

Plugging in the given values, we get:

acceleration =\((18 m/s)^2\)/ (2 × 123 m) ≈ \(2.05 m/s^2\)

Now, we can use Newton's second law to relate the net force acting on the truck to its mass and acceleration:

net force = mass × acceleration

Since the net force is zero when the truck is moving at a constant velocity, we can set the net force equal to the force of friction when the truck comes to a stop:

force of friction = mass × acceleration

Plugging in the given values, we get:

force of friction = (2260 kg) × (2.05 m/\(s^2\)) ≈ 4646 N

Finally, we can use the equation for the friction force to solve for the normal force:

normal force = friction force/coefficient of friction

normal force = 4646 N / 0.8 ≈ 5808 N

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Answer:

Fugis

Explanation:

dsd

The rotational speed of the motor 3 in rpm. b. 92

The figure shows a hydraulic circuit that uses three chain conveyors. The torque that drives the motors is T: =1500 N.m. T2 =700 Nm and, T3 = 300Nm.The volumetric flow rate produced by the pump is 6.3 liters per minute. The displacement volume of the motors is V01 =1000 cm3/rev. V02 =1000 cm3/rev and, V09 =500 cm3/rex.

The motors have a volumetric efficiency of 0.9 and an overall efficiency of 0.85. The leakage of hydraulic motors 1 and 3 is internal completely, while the leakage of hydraulic motor 2 is external completely.The orifice of the flow control valve has a diameter of 0.5 mm. The capacity coefficient of the needle valve is 0.7.

The pressure losses through the pipes are ignored. The volumetric flow rate through the needle valve is Q = C × A2 × ΔP / ρ where C is the capacity coefficient, A is the area of the orifice, ΔP is the pressure difference through the needle valve, and ρ is the density of the fluid. The density of the oil used in the hydraulic system is 860 kg/m3. We need to determine the rotational speed of motor 3 in rpm.

So,Let’s first determine the volumetric flow rate required by hydraulic motor 3. Using the expression of volumetric flow rate through the needle valve, we have Q = C × A2 × ΔP / ρ… (i)We are given that the capacity coefficient of the needle valve is 0.7. Its orifice diameter is 0.5 mm.

Hence, the area of the orifice is given byA2 = π d2 / 4where d is the diameter of the orifice. So, A2 = π × (0.5 mm)2 / 4 = 0.196 mm2 = 1.96 × 10-7 m2Using equation (i), we haveQ = C × A2 × ΔP / ρNow, we will calculate ΔP. To do this, we need to determine the flow rates Q1, Q2, and Q3.Let Q’ be the total volumetric flow rate through the system.

Since the overall efficiency of the system is given as 0.85, we haveQ’ = 0.85 × 6.3 l/min = 5.355 l/min = 5.355 × 10-3 m3/minWe know that the volume of fluid passing through the hydraulic motors is equal to their displacement volume multiplied by the number of revolutions per unit time.So, we haveQ1 = V01 × n1 … (ii)Q2 = V02 × n2 … (iii)Q3 = V03 × n3 … (iv)where V01, V02, and V03 are the displacement volumes of hydraulic motors 1, 2, and 3, respectively.

We are given that V01 = V02 = 1000 cm3/rev and V03 = 500 cm3/rev, which gives V01 = V02 = 1 × 10-6 m3/rev and V03 = 0.5 × 10-6 m3/rev.Substituting equations (ii), (iii), and (iv) in equation (i), we haveQ = C × A2 × (Q1 + Q2 - Q3) / ρSolving for Q3, we getQ3 = (Q1 + Q2 - Q) / C × A2 × ρPutting the given values in the above expression, we haveQ1 = V01 × n1 = (1 × 10-6 m3/rev) × n1Q2 = V02 × n2 = (1 × 10-6 m3/rev) × n2Q3 = V03 × n3 = (0.5 × 10-6 m3/rev) × n3Q = 5.355 × 10-3 m3/min = 5.355 × 10-3 / 60 m3/s = 8.925 × 10-5 m3/sA2 = 1.96 × 10-7 m2C = 0.7ρ = 860 kg/m3

Substituting the above values, we get8.925 × 10-5 = (1 × 10-6 × n1 + 1 × 10-6 × n2 - 0.5 × 10-6 × n3) / (0.7 × 1.96 × 10-7 × 860)Solving for n3, we have n3 = 91.6 rpmSo, the correct option is b. 92.

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The ring exerts a force on the rider at the top of the ride, which is equal to the gravitational force on the rider and is approximately 579.39 N.

The force with which the ring pushes on the rider at the top of the ride is equal to the normal force exerted by the ring on the rider, which is also equal to the gravitational force on the rider. The gravitational force on the rider can be calculated using the formula F = mg, where m is the mass of the rider and g is the acceleration due to gravity. Therefore, the force is approximately 579.39 N. At the top of the ride, the net force acting on the rider is zero, so the normal force exerted by the ring must be equal and opposite to the gravitational force. Without knowing the radius of the ring, we cannot calculate the velocity of the rider or the centripetal force. However, if the radius of the ring is very large compared to the size of the rider, then the centripetal force will be negligible, and the normal force will be approximately equal to the gravitational force.

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Ultrasound is a non-invasive imaging technique that uses high-frequency sound waves to produce images of internal organs, including the kidneys. When a doctor wants to look at a patient's kidneys, they will use an ultrasound machine to send sound waves into the body. These sound waves bounce off the kidneys and other internal structures and create echoes that are detected by the machine. The echoes are then used to create an image of the kidneys, which the doctor can use to assess their size, shape, and function. This can help the doctor diagnose kidney diseases, such as kidney stones, tumors, or cysts, as well as monitor the progression of chronic kidney disease. Ultrasound is a safe, painless, and non-invasive method for assessing kidney health, making it a valuable tool for doctors and patients alike.
Hi! A doctor can use ultrasound to look at a patient's kidneys by performing a renal ultrasound. The process involves placing a transducer, which emits high-frequency sound waves, on the patient's abdomen near the kidney area. These sound waves pass through the body, and when they hit the kidneys, they create echoes. The transducer then picks up the returning echoes, and a computer converts them into a real-time visual image of the kidneys. This non-invasive procedure helps doctors assess kidney size, shape, and location, as well as detect any abnormalities, such as cysts or stones, without exposing the patient to radiation.

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Answer:

Explanation:

14.9m

The altitude when the airplane flies a distance of 34 m is equal to 14.9 m.

The distance of an object can be demonstrated as the total length traveled by an object. The distance can be defined as a scalar parameter as it has magnitude, not direction. The distance by an object is always positive (+ve), it can never be zero.

Given, the airplane traveled the distance, BC = 34m as shown in the attached diagram, below:

The angle of the path with horizontal, θ = 26°

From the right angle triangle ΔCBA, we can calculate the BC:

Sin θ = BC/AC

Sin 26° = x/34

x = sin 26° ×34

x = 0.438 × 34

x = 14.9 m

Therefore, the altitude when an airplane has flown this distance is 14.9 m.

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A cyclist going around a circular track at 10.0 m/s^2 has a centripetal acceleration of 5.00 m/s2m/s2 .The radius of the curve is 20.0 meters.

To find the radius of the curve, we can use the formula for centripetal acceleration:

a = (v^2) / r

Where:

a is the centripetal acceleration (given as 5.00 m/s^2)

v is the velocity of the cyclist (given as 10.0 m/s)

r is the radius of the curve (unknown)

Rearranging the formula to solve for r, we have:

r = (v^2) / a

Plugging in the given values:

v = 10.0 m/s

a = 5.00 m/s^2

r = (10.0^2) / 5.00

Calculating the expression:

r = 100 / 5.00

r = 20.0 meters

Therefore, the radius of the curve is 20.0 meters.

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Answer:

As we navigate down a group the atoms get bigger and bigger with more and more electrons. This means the outermost electrons get further and further away from the positively charged nucleus.

Answer:

As we navigate down a group the atoms get bigger and bigger with more and more electrons. This means the outermost electrons get further and further away from the positively charged nucleus

Hope this helps!!!!

The forward azimuth from point A to point B is approximately 151.3421° (clockwise).

The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.

Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.

Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.

Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.

Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.

The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.

Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.

where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.

Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).

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The forward azimuth from point A to point B is approximately 151.3421° (clockwise).

The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.

Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.

Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.

Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.

Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.

The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.

Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.

where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.

Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).

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Answer:

Milimeters

Explanation:

This kind of question must be checked with everyday elements, in this way we will analyze each of the options until we reach the appropriate:

kilograms can not be because this unit serves to measure the mass not the length.

kilometers (km) is a unit of length, but however it does not serve for this measurement since a km is equivalent to 1000 meters, therefore measuring the length of a shoe with a ruler measuring 1000 meters is very impractical.

milliliters is a unit of volume, and can often be found in the measurement of volume content of liquids, for example 700 milliliters of milk or 1000 milliliters of water. Therefore it is impractical to measure a shoe with a unit of volume.

In this way the way to measure a shoe correctly is using a ruler or measuring instrument graduated in millimeters.

Answer:millimeters

Explanation:it the only way to measure something that has width length weight height and more stuff like that not the only way but the most easiest

To calculate the moment of inertia of the steel plate, we need to use the formula, Once you have the limits of integration for your specific triangle, you can calculate the moment of inertia.

I = ∫∫(r² * dm)
Where I is the moment of inertia, r is the perpendicular distance of a small element of mass dm from the axis of rotation, and dm is the mass of that small element.
First, we need to divide the triangle into small squares of area dxdy. Let's assume that the side length of each square is dx. Then the mass of each square is:
dm = density * volume
  = density * dxdy * thickness
  = density * dx² * thickness
Since the density of steel is approximately 7.8 g/cm³ and the thickness of the plate is not given, we cannot calculate the value of density. However, we know that the mass of the plate is m = 550 g, so we can use this value to find the mass of each square:
dm = m / (total number of squares)
Now, let's consider a square located at (x, y) with side length dx. The perpendicular distance of this square from the axis of rotation passing through the origin is:
r = √(x² + y²)
Therefore, the moment of inertia of this small square is:
dI = r² * dm
  = r² * (m / total number of squares)

To find the total moment of inertia of the plate, we need to integrate this expression over the entire triangle. The limits of integration are:
0 ≤ x ≤ base of triangle
0 ≤ y ≤ height of triangle at x
So, the moment of inertia of the steel plate is:
I = ∫∫(r² * dm)
 = ∫∫(r² * (m / total number of squares))
 = ∫₀ˡⁿ∫₀ʰⁿ(√(x² + y²)² * (m / total number of squares))dxdy
Note that the limits of integration depend on the shape of the triangle, which is not given in the question. You need to substitute the appropriate values for the base and height of the triangle in the above expression.

1. Convert mass to kg: m = 550 g = 0.55 kg.
2. Divide the triangle into small squares of area dA = dxdy.
3. Find the moment of inertia of a square at (x, y): dI = dm * r^2, where dm = (mass per unit area) * dA and r is the distance from the axis.
4. To find mass per unit area, first find the area of the triangle. Let's assume the base is b and the height is h. The area of the triangle is A = (1/2) * b * h.
5. Calculate mass per unit area: ρ = m / A.
6. Now, find dm: dm = ρ * dA = ρ * dxdy.
7. Determine r^2 as the sum of x^2 and y^2, since it's the distance from the origin: r^2 = x^2 + y^2.
8. Plug r^2 and dm into the dI equation: dI = dm * r^2 = (ρ * dxdy) * (x^2 + y^2).
9. Integrate dI over the triangle to get the total moment of inertia. Perform a double integral: I = ∫∫ (ρ * (x^2 + y^2) * dxdy), with limits depending on the dimensions of the triangle.

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Answer:

A) lacks the mass of the object

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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Answer:

revolution of the planets around the Sun.

Explanation:

The revolution of the planets around the Sun is a result of the gravitational force exerted by the Sun. The Sun's gravitational pull attracts the planets, causing them to move in an elliptical orbit around it. This motion is known as the revolution of the planets around the Sun. The other options listed (rotation of the planets on their axes, rotation of the Moon on its axis, and revolution of the Moon around Earth) are also related to motion and gravity, but they are different phenomena.

Acoustic power, also known as sound intensity, is defined as the power transmitted by a sound wave per unit area in a direction perpendicular to that area.

A sound wave is a type of energy that propagates in a medium by adiabatic charging and discharging. Important quantities for describing sound waves are sound pressure, particle velocity, particle displacement, and sound intensity.

Sound waves can be classified into three categories:

Longitudinal waves, mechanical waves, pressure waves.

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Answer:

because the density of iron nail is more tha n density of water but the density of ship made iron steel is less than the density of water

Answer:

first density=mass/volume

For volume of mercury,13.56=5*v

or v =5/13.56=0.68 cm cube

for volume of lead 11.36=5*v

or v=5/11.36=0.44

volume of mercury is 0.68 and that of lead is 0.44 so mercury has greater volume

Mercury has a density of 13.56g/cm^3 and lead has a density of 11.36g/cm^3. then between 5g of mercury and 5g of lead, the 5 g of lead would have a greater volume

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

The density of the fluids is used to compare them with others for their relative applications in our day-to-day life such as petrol, diesel kerosene, etc.

formula for density

ρ = mass / volume

As given in the problem mercury has a density of 13.56g/cm^3 and lead has a density of 11.36g/cm^3. for the same amount of mass, the substance that has less density will occupy greater volume, therefore lead has a greater volume than that gold.

Thus, 5g of lead would have a greater volume because it has less density than that of gold.

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ANSWER:

46.08 kg

STEP-BY-STEP EXPLANATION:

Given

m1 = 1152 kg

v1 = 0.06 m/s

v2 = -1.5 m/s

We apply law of conservation of linear momentum:

We plug in and calculate for the mass, just like this:

Which means that the mass of the pianist is 46.08 kg

Hello, yes it is possible to lift heavier load using small magnitude of force.

How? let's see.

Do you know on which principle does hydraulic machine work? Yes, it's Pascal's Principle. So in order to understand how hydraulic machine will lift heavier weight using small magnitude of force we will have to take a look at Pascal's law.

Pascal's law : It sates that in a closed container filled with fluid when pressure is applied to any point that intensity of pressure transfers in all direction equally.

Now look at diagram,

Consider the left piston as X and Right Piston as Y.

the area of piston X is small (A1) and applied force (F1) is also less and the resultant pressure is P.

\(P = \frac{F_1}{A_1}\)

This same amount of pressure will be exerted at Piston Y having area (A2) and resultant output force (F2)

\(P = \frac{F_2}{A_2}\)

So consider I have 5 N force and I have to lift a heavier rock weighing 50 N. take an example the area of Piston X is 1 m² & area of piston Y is 10 m²

So when I will apply 5 N force on piston X it will exert 50 N force on piston Y.

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