Answer:
0.1169 s
Explanation:
From the question, it is given that the bat emits the sound when it was at distance of 20.0 m from the insect
This then means that the time taken by the sound to reach the wall is given as
t1 = 20/340
t1 = 0.0588 s
Also, d1 = vt, so that
d1 = 2 * 0.0588
d1 = 0.1176 m, and this is the distance moved by the bat.
Next,
d' = 20 - 0.1176
d' = 19.8824 m is the distance between the bat and the wall.
t2 = d'/[v(c) + v]
t2 = 19.8824 / (340 + 2)
t2 = 19.8824 / 342
t2 = 0.0581 s
Total time, T = t1 + t2
T = 0.0588 + 0.0581
T = 0.1169 s
URGENT PLEASE HELP URGENT
Explanation:
w= mg
weight on earth= 50 * 9.8= 490 Newtons
weight on mars,= 50 * 3.7= 185 Newtons
please email me as brainlist!
If a resistor has the color combination of yellow-violet-red-gold, what is the range of acceptable values of resistance
Answer:
Resistance = 4465 Ω - 4935 Ω
Explanation:
The color bands in a four band resistors are read as follows:
Band 1: 1st digit of Resistance
Band 2: 2nd digit of Resistance
Band 3: Multiplier Value
Band 4: Tolerance
Now interpreting our code:
Band 1 (Yellow) = 4
Band 2 (Violet) = 7
Band 3 (Red) = 10²
Band 4 (Gold) = ±5%
Therefore,
Resistance = 47 x 10² Ω ± 5%
Resistance = 4700 Ω ± 5%
So, the range can be calculated as:
Lower Limit = 4700 Ω - (0.05)(4700 Ω)
Lower Limit = 4700 Ω - 235 Ω
Lower Limit = 4465 Ω
No, for upper limit:
Upper Limit = 4700 Ω + (0.05)(4700 Ω)
Upper Limit = 4700 Ω + 235 Ω
Upper Limit = 4935 Ω
Thus, the acceptable range of resistance will be:
Resistance = 4465 Ω - 4935 Ω
need help with momentum!
Answer:
The total kinetic energy must be greater than the momentum of either ball
Explanation:
In order to solve this problem, we must clarify the following conditions, the balls are in motion that is, there is kinetic energy, the kinetic energy is a scalar magnitude, therefore this energy is greater than zero.
But however momentum is equal to zero, momentum is a vector quantity, that is, these velocities have a direction, momentum is defined as the product of mass by Velocity.
P = m*v (momentum lineal)
where:
P = lineal momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
Since the masses of the balls are equal, we have:
m1 = m2
therefore:
m1*v1 + (m2*v2) = 0 (total momentum)
For the sum to be equal to zero, besides the equivalation of the masses, the velocities must also be equal, but the velocities must be of opposite sign, to meet equality to zero.
m1*v1 - m2*v2 = 0
And the kinetic energy of a body is defined by means of the following equation
Ek = 0.5*m*v²
Since the magnitude of the velocities is greater than zero, so that there is movement, we can say that the kinetic energy is much greater than zero, as well as greater than the total linear momentum
how do you calculate speed
Answer:
distance(d)=.....
time(t)=....
speed =?
we know that
speed =distance /time
5. In a local bar, a customer slides an empty beer mug on the counter for a refill. The bartender does not see the mug, which slides off the counter and strikes the floor 1.4 m from the base of the counter. If the height of the counter is 0.86 m,
(a) with what speed did the mug leave the counter
(b) what was the direction of the mug's velocity just before it hit the floor?
Answer:
sorry about this question
A runner begins a race from rest and reaches a final speed of 22mph. It takes 3.45s. If the runner's mass is 76.4 kg and 1 mile = 1,609.34m. A) What is the runner's acceleration?
B) What is the magnitude of the downward force acting on the runner?
Acceleration:
a = (22 mph - 0 mph) / (3.45s) = 6.37 mph/s
Magnitude of the Downward Force:
F = m*a = 76.4 kg * 6.37 mph/s = 484.53 N
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temperature of 322 K. Over the course of one hour, the engine absorbs 1.37 x 105 J from the hot reservoir and exhausts 7.4 x 104 J into the cold reservoir.
1) What is the power output of this engine?
2) What is the maximum (Carnot) efficiency of a heat engine running between these two reservoirs?
3) What is the actual efficiency of this engine?
Answer:
The power output of this engine is \(P = 17.5 W\)
The the maximum (Carnot) efficiency is \(\eta_c = 0.7424\)
The actual efficiency of this engine is \(\eta _a = 0.46\)
Explanation:
From the question we are told that
The temperature of the hot reservoir is \(T_h = 1250 \ K\)
The temperature of the cold reservoir is \(T_c = 322 \ K\)
The energy absorbed from the hot reservoir is \(E_h = 1.37 *10^{5} \ J\)
The energy exhausts into cold reservoir is \(E_c = 7.4 *10^{4} J\)
The power output is mathematically represented as
\(P = \frac{W}{t}\)
Where t is the time taken which we will assume to be 1 hour = 3600 s
W is the workdone which is mathematically represented as
\(W = E_h -E_c\)
substituting values
\(W = 63000 J\)
So
\(P = \frac{63000}{3600}\)
\(P = 17.5 W\)
The Carnot efficiency is mathematically represented as
\(\eta_c = 1 - \frac{T_c}{T_h}\)
\(\eta_c = 1 - \frac{322}{1250}\)
\(\eta_c = 0.7424\)
The actual efficiency is mathematically represented as
\(\eta _a = \frac{W}{E_h}\)
substituting values
\(\eta _a = \frac{63000}{1.37*10^{5}}\)
\(\eta _a = 0.46\)
From the top of a cliff, 100m above sea level, a stone is thrown vertically upward with a velocity of 30m/s. After how many seconds and with what velocity will it hit the sea?.
According to the given statement After t = (√29+3) seconds and with v = 10√29 m/s velocity will it hit the sea.
What is a velocity ?The displacement how an object and particle experiences with regard to time is expressed vectorially as velocity. The meter per second (m/s) is the accepted unit of flow speed (also known as speed). Instead, the magnitude of velocity can be expressed in centimeters per second (cm/s).
Briefing:Initial height = 100 m
Initial velocity = 30 m/s
g = 10 m/s²
To Find
Time taken and final velocity
Solution
v²-u² = 2as & v = u + at
Assuming downward motion to be positive
According to the Question :
⇒ v²-u² = 2as
⇒ v²-30² = 2(10)(100)
⇒ v² = 900+2000
⇒ v² = 2900
⇒ v = √2900
⇒ v = 10√29 m/s
So then the time taken would be
⇒ v = u + at
⇒ 10√29 = (-30) + 10t
⇒ (10√29+30)/10 = t
⇒ t = (√29+3) sec
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A 770-kg two-stage rocket is traveling at a speed of 6.90×103 m/s away from Earth when a predesigned explosion separates the rocket into two sections of equal mass that then move with a speed of 2.60×103 m/s relative to each other along the original line of motion.What is the speed of each section (relative to Earth) after the explosion?How much energy was supplied by the explosion?
Answer:
Explanation:
Let's just have our reference frame travel along with the original un broken mass. This way the original velocity is not relevant.
Each half will have a mass of 770/2 = 385 kg
Each half will have the same magnitude of velocity (conservation of momentum) which will be 2.6 x 10³/2 = 1.30 x 10³ m/s
Now add back the reference frame velocity to get velocity relative to earth.
Section one will have velocity 6.90 x 10³ + 1.30 x 10³ = 8.2 x 10³ m/s
Section two will have velocity 6.90 x 10³ - 1.30 x 10³ = 5.6 x 10³ m/s
In the moving reference frame, each half will have kinetic energy which could only come from the explosion
KE = ½(385)(1.3 x 10³)² = 325,325,000 J
2(325,325,000) = 650,650,000 J released in the explosion.
Rounding to the three significant figures of the problem numerals
E = 6.50 x 10⁸ J or 650 MJ released
What kind of machines do astronautical engineers work with?
The astronautical engineers work with machine that fly outside the Earth's atmosphere.
What is aerospace engineering?
The design, development, testing, and production of aircraft, spacecraft, and associated systems and equipment fall within the purview of aerospace engineering. The two main and overlapping sections of the field—aeronautical engineering and astronautical engineering—have historically concentrated on issues relating to air and space flight.
The theory, technique, and application of flight within the earth's atmosphere are the main topics of aeronautical engineering.The science and technology of spacecraft and launch vehicles are the main areas of interest in astronautical engineering.Learn more about aerospace and aeronautical engineering here:
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An ant climbs vertically on a fence. Its motion is shown on the following graph of vertical position � yy vs. time � tt. Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec. Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec. What is the instantaneous speed of the ant at time � = 8 s t=8 st, equals, 8, start text, space, s, end text?
The instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s.
To find the instantaneous speed of the ant at time t=8s, we need to calculate the derivative of the displacement function with respect to time. Since the displacement of the ant is given by a piecewise function, we need to differentiate each segment of the function separately and then piece them together. From 0s to 4s, the displacement of the ant decreases linearly from 6m to 2m. The slope of this segment is -1m/s. From 4s to 7s, the displacement of the ant is constant at 2m. The slope of this segment is zero. From 7s to 9s, the displacement of the ant increases linearly from 2m to 5m. The slope of this segment is 1.5m/s. Finally, from 9s to 10s, the displacement of the ant is constant at 5m. The slope of this segment is zero.
Therefore, the instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s. This means that the ant is moving upwards at a constant speed of 1.5m/s at time t=8s. It's important to note that the instantaneous speed of the ant tells us how fast it's moving at a specific moment in time. It's not the same as the average speed over a given time interval, which would be calculated by dividing the total displacement by the total time elapsed.
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Which type of telescope is best used to detect distant planets?
The equation for a travelling wave is y = 4.6 Sin (3t-8x) Find: (a) Its frequency (b) Its wave length (c) Speed of the wave.
Explanation:
Explanation:
Y = 5 Sin27(.2x-3t)
= 5 Sin(5.4x - 81 t)
Amplitude = 5 m
Angular frequency w = 81
frequency = w/ 2π = 81/(2 x 3.14)
-12.89
Wave length λ = 2π/ k,
k = 5.4
λ = 2π/ 5.4
= 1.163 m
Phase velocity=w / k
= 81/5.4
15 m/s.
The wave is travelling in + ve x - direction.
hope help
13. A solid has a mass of 200 g in air and when partly immersed in a certain liquid it has a mass of 160 g. Given that the relative density of the liquid is 0.80, calculate the volume of the solid immersed in the liquid.
The volume of the solid immersed in the liquid is 5 x 10⁻⁵ m³.
What is the volume of the solid?The volume of the solid is calculated as follows;
V = (Ws - Wa) / (ρg)
where;
Ws is the weight of the solid in airWa is the weight of the solid in liquidρ is the density of the solidg is gravityWs = 0.2 kg x 9.8 m/s²
Ws = 1.96 N
Wa = 0.16 kg x 9.8 m/s²
Wa = 1.568 N
ρ = 0.8 x 1000 g/km³ = 800 kg/m³
The volume is calculated as;
V = (1.96 - 1.568 )/(800 x 9.8)
V = 5 x 10⁻⁵ m³
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A candle is sitting in front of a concave mirror at a distance of 18.0 cm. It is found that an image of the ca
25.0 cm. What is the focal length of the mirror?
03.52 cm
07.50 cm
O 10.4 cm
022.1 cm
Answer:
The focal length of the mirror is 10.4 cm.
Explanation:
The object distance ( d₀ ) ( distance of the candle from the mirror) is -18 cm.The Image distance ( dᵢ ) ( distance of the image from the mirror) is -25.0 cm.The mirror equation is 1/f = 1/d₀ + 1/dᵢ.So substitute the values of object distance and image distance in the mirror equation,
1/f = 1/(-18cm) + 1/(-25.0cm)
1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)
1/f = ( -25cm - 18cm)/(18cm x 25cm)
1/f = -43.0/450.0
f = -10.4651 cm.
The focal length of the mirror is approximately -10.4 cm.
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What is energy anything that takes up space and has mass a change in the position of an object a push or pull the ability to cause change in matter
Energy is that which has the ability to cause change in matter.
What is energy?Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.
So in simple definition we can say that energy is that which has the ability to cause change in matter.
Based on the given statements we can classify them as;
anything that takes up space and has mass - matter.cause a change in the position of an object through push or pull - forcethe ability to cause change in matter - energy.Learn more about energy here: https://brainly.com/question/13881533
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A force to be expressed correctly requires
(a) only the magnitude
(b) only the direction
(c) both the magnitude and the direction
(d) none of the above
Explain in short (none equation)
Answer:
Magnitude and Direction
\(\huge\color{pink}\boxed{\colorbox{Black}{♔︎Answer♔︎}}\)
The right option is (c).
\(\huge{\color{magenta}{\fbox{\textsf{\textbf{Explanation}}}}}\)
Force is a vector quantity thats why it's depends upon both magnitude and direction.
Replace the incandescent bulb with the Voltage meter and return loop # to 3. What happens when you move the bar magnet back-n-forth through the loop? Does this appear to be creating a Direct Current or an Alternating Current? How do you know?
If we replace the incandescent bulb with a voltage meter and return the loop to its original configuration, then moving the bar magnet back and forth through the loop will induce an electrical current in the loop, as described by Faraday's law of electromagnetic induction.
What is magnet?A magnet is a material or object that produces a magnetic field, which is a force that can attract or repel certain other materials, such as iron or steel. The magnetic field is created by the motion of electric charges within the magnet, which align in such a way that they produce a net magnetic field. Magnets can be made from a variety of materials, including iron, cobalt, nickel, and certain alloys. They come in many different shapes and sizes, including bars, discs, horseshoes, and rings.
Here,
The type of current that is generated depends on the direction and rate of the magnet's motion. If the magnet is moved back and forth with a constant speed and in a straight line, the current induced in the loop will be an alternating current (AC), because the direction of the current will reverse every time the magnet changes direction. This can be observed by the voltage meter reading a voltage that periodically changes in direction.
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Explain three ways energy moves through the water cycle.
Urgent help!!
Answer:
Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow
Explanation:
its basiclly luquid, water vapor, and the form of clouds.
which correctly relates the kinetic energy of the balls in the table above?
The ball that correctly relates the kinetic energy of a ball is; Ball C
The kinetic energy of an object is the energy generated by an object in motion ( i.e. object whose speed is greater than zero )
and the formula for Kinetic energy = 1/2 mv^2 .
Ball B :
mass = 4kg , speed = 8 m/s . kinetic energy = 130 J
K.E = 1/2 ( 4 * 8^2 )
= 128 J ( 130 J ≠ 128 J ) ( does not correctly relate the kinetic energy
Ball C :
mass = 5 kg, speed = 8 m/s , kinetic energy = 160 J
K.E = \(1/2*\) \(( 5 * 8^2 )\)
= 160 J ( 160 J = 160 J ) ( correctly relates the kinetic energy )
Hence we can conclude that The ball that correctly relates the kinetic energy of a ball is; Ball C.
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Answer:
b=c or b,c
Explanation:
Suppose you are standing in front of a flat mirror which is mounted to a vertical wall. For this problem you may suppose that your height is 1.70 m and your eyes are 12 cm below the top of your head. What is the smallest mirror that will still allow you to see the full length of your body
Answer:
The right approach is "0.85 m".
Explanation:
According to the question, the diagram will is provided below.
So that as per the diagram,
The values will be:
My height,
AO = 1.70 m
My eyes at,
AB = 12 cm
i.e.,
= 0.12 m
As we can see, the point of incidence lies between the feet as well as the eyes, then
BO = 1.58 m
Now,
⇒ \(O'D = \frac{1.58}{2}\)
\(=0.79 \ m\)
The point of incidence of the ray will be:
⇒ \(CO'=1.70-\frac{0.12}{2}\)
\(=1.70-0.06\)
\(=1.64 \ m\)
Hence,
The smallest length of the mirror will be:
= \(CO'-O'D\)
On substituting the values, we get
= \(1.64-0.79\)
= \(0.85 \ m\)
Can heating cooking oil you’ll be classified as producing a chemical change?
yes it is boiling creating bubbles that aren't their originally
Explanation:
When cooking oils are subjected to heat in the presence of air and water (from food), such as in deep-fat frying and sautéing (pan frying), they can undergo at least three chemical changes: 1) oxidation of the fatty acids, 2) polymerization of the fatty acids, and 3) breaking apart of the triglyceride molecules into free fatty acids and glycerol by hydrolysis (reaction with water from the food being cooked) (Choe and Min 2007)
A boy slides a book across the floor, using a force of 5 N over a distance of 2
m. What is the kinetic energy of the book after he slides it? Assume there is
no friction.
A. 5 J
B. 10 J
C. 20 J
D. 2.5 J
SUBMIT
The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.
How to determine the kinetic energy of an object?The work-energy theorem states that "the work done on an object is the change in its kinetic energy".
Hence;
Kinetic energy = work done
Note that: work-done is expressed as:
Work done = f × d
Where f is force applied and d is distance traveled.
Given that:
Force applied f = 5 newton
Distance d = 2 meters
Work done = ?
Plug these values into the above formula and solve for the workdone.
Work done = f × d
Work done = 5N × 2m
Work done = 10Nm
Work done = 10 Joules
Therefore, the kinetic energy is 10 Joules.
Option B) 10 J is the correct answer.
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A boy 11.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the instant the ball is thrown. If the boy throws the ball upward at 50.0 ∘ above the horizontal, at 8.00 m/s .
How fast must the dog run to catch the ball just as it reaches the ground?
How far from the tree will the dog catch the ball?
12414253
Explanation:
T or F A red-hot object is hotter than one that is while-hot?
Answer:
True. The two laws of thermal radiation state; 1) "Each square meter of a hotter object
Explanation:
total potential and kinetic energy of an object.
you have to finish the word
__c____c__ pls help
Answer:
The Total Mechanical Energy
As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.
Explanation:
What is the strength of an electric field that will put a force of
1.28 x 10-15 N on a proton?
Answer: E = 7,490.6 N/C
Explanation:
If we have a field E, and a particle with a charge q, the force that the particle experiences is:
F = E*q
In this case, we know that the force is:
F = 1.2*10^(-15) N
And we know that the particle is a proton, where the charge of a proton is:
q = 1.602*10^(-19) C
Then we can replace these two values in the equation to get:
1.2*10^(-15) N = E*1.602*10^(-19) C
We just need to isolate E.
(1.2*10^(-15) N)/(1.602*10^(-19) C) = E
7,490.6 N/C = E
That is the strength of the electric field.
Why was Conner feeling disenfranchised about his company
He starts off evolved grieving earlier than he has been clearly outsourced.His emotions are associated to the loss that would possibly happen in future. His emotions are due to the response to the predicted loss.
Explain how scientists law is created? Plz Help me
Answer:
the laws of science or statements based on repeated experiments or observations that describe or predict a range of natural phenomena laws are developed from data and can be further developed through mathematics in all cases they are directly or indirectly based on empirical evidence