a base current of 50 micro amps is applied to the transistor in figgure 4-54 and a voltage of 5v is dropped across rc. determine the beta dc of the transistor
Answers
The beta DC of the transistor can be determined using the given information.
Beta DC is the direct current gain of a transistor, which is defined as the ratio of collector current to base current. In order to calculate beta DC, we need to know the value of collector current (Ic) and base current (Ib) of the transistor.
We are given the base current (Ib) as 50 microamps (50 x 10^-6 A). A voltage of 5V is dropped across Rc. We need to determine the collector current (Ic) using Ohm's Law: Ic = V / Rc. However, the value of Rc is not provided in the question. Once you have the value of Rc, you can calculate the collector current (Ic).
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Related Questions
QUESTION 4:
4.1
Name FOUR principles of kinetic friction
Answers
Answer:
The force of friction always acts in a direction, opposite to that in which the body is moving.
The magnitude of kinetic friction bears a constant ratio to the normal reaction between the two surfaces. ...
For moderate speeds, the force of friction remains constant.
Answer:
Explanation:Kinetic friction is a force that acts between moving surfaces. An object that is being moved over a surface will experience a force in the opposite direction as its movement. The magnitude of the force depends on the coefficient of kinetic friction between the two kinds of material.
using data in Appendix A ,calculate the number of atoms in 1 tonne of iron
Answers
\(1.0783*10^{28}(atoms).\)
Explanation:Since I don't have access to "Appendix A", I'll solve the problem using data from the periodic table.
1. Determine the molar mass of iron.
According to the periodic table, the molar mass of iron is:
55.845g/mole.
2. Convert 1 tonne to grams.\(1(tonne)*1000=1000kg\\1000kg*1000=1000000g=10^6g\)
3. Apply rule of 3.\(55.845g\) ----------- \(1 mole\)
\(10^6g\) ----------- \(x\)
\(x=\frac{10^6*1}{55.845}=17906.7061(moles)\)
4. Determine the amount of atoms.Considering that there are, approximately, \(6.022*10^{23}\) atoms in a mole of any element, apply another rule of 3.
1 mole --------------------- \(6.022*10^{23}(atoms)\)
\(17906.7061(moles)\) --------------------- x
\(x=\frac{17906.7061*6.022*10^{23}}{1}=1.0783*10^{28}\).
A commercial jet is flying at a standard altitude of 35,000 ft with a velocity of 550 mph: (a) what is the Mach number? (b) should the flow be treated as incompressible, why or why not?
Answers
Answer:
Mach number = 0.68168
The flow should be treated as compressible.
Explanation:
Given that:
The altitude of a commercial jet = 35000
The properties of air at that given altitude are as follows:
Pressure = 24.577 kPa
Temperature T = 50.78176° C
Temperature T = ( 50.78176 + 273 )K = 328.78176 K
\(\varphi = 0.38428 \ kg/m^3\)
The velocity is also given as: 550 mph = 245.872 m/s
Therefore, the sonic velocity is firstly determined by using the formula:
\(a = \sqrt{ \vartheta \times R \times T\\)
\(a = \sqrt{1.4 \times 287 \times 323.78176\)
\(a = \sqrt{130095.5112\)
a = 360.68755 m/s
Then, we can calculate the Mach number by using the expression:
\({Mach \ number = \dfrac{V}{a}}\)
\(Mach \ number = \dfrac{245.872}{360.68755}\)
Mach number = 0.68168
b) Ideally, all flows are compressible because the Mach number is greater than 0.3, suppose the Mach number is lesser than 0.3, then it is incompressible.
2. Because she has a Victim mindset and having low grade in her Math class, Julianna believes
O a. her low grades are the fault of her unfair teacher.
O b. she needs to take an easier class.
O c. that working with a tutor is the only way for her to pass the class.
O d. she can improve her grades if she studies more.
Answers
Because she has a Victim mindset and having low grade in her Math class, Julianna believes: A. her low grades are the fault of her unfair teacher.
What is a Victim mindset?A Victim mindset is also referred to as victim mentality and it can be defined as an acquired personality trait in which an individual tends to recognize and believe that the negative and unfair actions of others towards him or her, is responsible for the bad and unpleasant things that happens.
This ultimately implies that, an individual with a Victim mindset is prejudiced and strongly believes that every other person is against him or her, and as such these people are responsible for their failures.
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architects must consider the availability and cost of when they plan their projects. question 1 options: bribes breathing apparatus building materials fresh water none of the other answers
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Architects must consider the availability and cost of building materials when they plan their projects.
Who are architects?Building planning and design are the expertise of an architect, who typically has a significant impact on how a building is built. The art and science of building design are fields in which architects have extensive training. Architects need to be licenced professionally because they are in charge of ensuring the security of the people who use their buildings.
The Greek term for "chief builder" is the origin of the word "architect." Between the craftsman who designed a building and the one who actually built it, there was no distinction for a large portion of history.
Buildings could then be planned much more thoroughly before being built thanks to the development of linear perspective drawing in the 1500s, which made it possible to accurately depict three-dimensional structures in two dimensions.
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A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answers
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
The steepest, stable, slope angle possible in unconsolidated, granular materials like sand and gravel is called the angle of retention repose slope stability
Answers
The steepest, stable, slope angle possible in unconsolidated, granular materials like sand and gravel is called the angle of repose. This angle of repose is the angle at which a material can maintain a stable slope without sliding.
The angle of repose can differ depending on the type of granular material in question and other environmental factors. For example, dry sand usually has an angle of repose between 34 and 35 degrees, while wet sand has an angle of repose between 30 and 34 degrees.In addition to providing information on slope stability, the angle of repose is also used in industries such as mining and agriculture to determine the maximum angle at which materials can be safely piled or stored without collapsing or spilling.
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A cylindrical steam boiler stack has a diameter of 1.0 m and is 30.0 m high. It is exposed to a wind at 250C having a velocity of 50 miles/h. Calculate the force exerted on the boiler stack
Answers
To calculate the force exerted on the cylindrical steam boiler stack by the wind, we need to use the following formula:the force exerted on the cylindrical steam boiler stack by the wind is approximately 9058.4 Newtons.
\(F = 0.625 * Cd * A * ρ * V^2\) where F is the force exerted, Cd is the drag coefficient, A is the cross-sectional area of the stack, ρ is the density of air, and V is the wind velocity.First, we need to convert the units of the wind velocity to meters per second:50 miles/h = 22.352 m/s Next, we can calculate the cross-sectional area of the stack: \(A = π * r^2 = π * (0.5 m)^2 = 0.7854 m^2\) Assuming a drag coefficient of 1.2 and a density of air of \(1.2 kg/m^3\), we can substitute these values into the formula: \(F = 0.625 * 1.2 * 0.7854 * 1.2 * (22.352 m/s)^2\)F = 0.625 * 1.2 * 0.7854 * 1.2 * (22.352 m/s)^2 F = 9058.4 N Therefore, the force exerted on the cylindrical steam boiler stack by the wind is approximately 9058.4 Newtons.
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Marks for each question are indicated. Subparts are worth equal weight unless specified. Total: 32 marks. 1. (2 marks) For this question you may only use NAND gates, i.e., gates with inputs A,B and output C where C=AB (a) Construct a NOT gate using one NAND gate. (b) Construct a two-input OR gate using three NAND gates.
Answers
(a) The configuration effectively implements the NOT gate using a NAND gate.
(b) a NAND gate can be used to create any other gate, so understanding its behavior allows us to construct different logic gates.
A NAND gate can be used to create any other gate, so understanding its behavior allows us to construct different logic gates.
In this configuration, if either input is 1, at least one of the NAND gates will output 0, resulting in an overall output of 1. Only when both inputs are 0 will the output be 0.
To construct a NOT gate using only NAND gates, we need to understand that a NAND gate can act as a universal gate, meaning it can be used to create any other gate.
(a) To create a NOT gate, we can connect one input of the NAND gate to the other input, and the output of the NAND gate will act as the NOT gate output. In other words, if we connect both inputs of the NAND gate together (A = B), the output of the NAND gate will be the logical complement of the input.
For example, if A = 1, then B = 1, and the output C will be 0. This configuration effectively implements the NOT gate using a NAND gate.
(b) To construct a two-input OR gate using three NAND gates, we can use the following steps:
1. Connect one input of the first NAND gate to the inputs of the other two NAND gates.
2. Connect the second input of the first NAND gate to one input of the second NAND gate.
3. Connect the output of the second NAND gate to one input of the third NAND gate.
4. Connect the output of the first NAND gate to the second input of the third NAND gate.
5. The output of the third NAND gate will be the OR gate output.
In this configuration, if either input is 1, at least one of the NAND gates will output 0, resulting in an overall output of 1. Only when both inputs are 0 will the output be 0.
Remember, a NAND gate can be used to create any other gate, so understanding its behavior allows us to construct different logic gates.
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tìm phản lực gối tựa
Answers
Answer:
jwjehevrvbdbejd HB dbnwjsishrb t bxjwbkozkwnwn shxvbebhgvevhehjhr. jebn
The roof of a house consists of a 22-cm-thick concrete slab (k = 2 W/m•K) that is 15 m wide and 20 m long. The emissivity of the outer surface of the iroof is 0.9, and the convection heat transfer coefficient on that surface is estimated to be 15 W/m2•K The inner surface of the roof is maintained at 15°C. On a clear winter night, the ambient air is reported to be at 10°C while the night sky temperature for radiation heat transfer is 255 K. Considering both radiation and convection heat transfer, determine the outer surface temperature and the rate of heat transfer through the roof. if the house is heated by a furnace burning natural gas with an efficiency of 85 percent, and the unit cost of natural gas is 51.20/therm (1 therm = 105.500 U of energy content), determine the money lost through the roof that night during a 14-hour period.
Answers
Answer:
Explanation:
Consider the outer surface of the roof to be \(T_{out}\)
Since, the heat conducted is equal to the sum of the heat transferred through convection and the rest by radiation
\(Q_{cond}=Q_{rad}+Q_{conv}\)
Rewrite the equation as follows
\(kA_s\frac{\Delta T}{L} =\epsilon \sigma A_s(T_s^4-T_{\infty}^4)+hA_s \Delta T\\\\k\frac{\Delta T}{L} =\epsilon \sigma (T_s^4-T_{\infty}^4)+h \Delta T\)
\(k\frac{T_{in}-T_{out}}{L} =\epsilon \sigma (T_{out}^4-T_{rad}^4)+h(T_{out}-T_{\infty})\)
subsititute
k = 2 W/m
\(15^o C=T_{in}\)
0.22 for L
\(0.9 = \epsilon\)
\(5.67\times 10^{-8}W/m^2.K^4=\sigma\)
\(255=T_{rad}\)
\(15W/m^2.K = h\)
\(10^oC=T_{\infty}\)
\(2\times \frac{15 -T_{out}}{0.22} =[0.9\times(5.67\times10^-^8)\times((T_{out}+273)^4-255^4)]+[15\times(T_{out}-10)]\\\\T_{out}=7.7^oC\)
Hence, the temperature of outer surface of the roof is \(T_{out}=7.7^oC\)
Calculate the surface area of the roof
\(A_s=b\times l\)
Here, b is the width , l is the length
substitute 15 for b , 20 for l
\(A_s=15 \times 20\\\\=300m^2\)
Write the equation for conduction
\(Q_{cond}=kA_s\frac{\Delta T}{L}\)
substitute 2W/m.K for k
\(300m^2 \ \ for \ A_s\\\\(15-7.7)^oC \ \ for \ \Delta T\\\\0.22m \ for \ L\)
\(Q_{cond}=2\times 300 \times \frac{15-7.7}{0.22}\\\\=19,000\)
Therefore, the total heat transferred through conduction is \(Q_{cond}=19,9009W\)
Consider the amount of natural gas required be R and the cost incurred in running the furnace through the night be M
\(R=\frac{Q_{cond}}{0.85} \times T\)
Duration of time T = 14 x 3600s
\(R=\frac{19909\times(14\times3600)}{0.85}kJ\\\\= \frac{19909\times(14\times3600)}{0.85\times105500}therm\\\\=11.2 \ therm\)
And the required money for the gas M = 11.2 x $1.2
= $13.44
Therefore, the money lost through the roof due to the heat transfer M=$13.44
QUESTION 2 (15 Marks) (1) State three differences between the Field Effect Transistor (FET) and the Bipolar Junction Transistor (BJT). [3 marks] (ii) Draw the physical structure and device symbol for an n-channel JFET. [2 marks] (iii) What is meant by drain characteristics [2 marks] (b) Determine the drain current of an n-channel JFET having pinch-off voltage VP = -4 and drain-source saturation current IDSS-12mA at the following gate-source voltages (1) VGS-OV (ii) VGS=-2V 14 marks] (c) Calculate the transconductance, gm of a JFET having specified values of IDSS-12mA and VP-4V at bias points (1) VGS-OV and (ii) VGS -1.5V. (4 marks] QUESTION 3 (15 Marks) (a) (i) Mention four JFET parameters and explain any two [5 marks] (ii) Distinguish between depletion and enhancement MOSFET [2 marks] (b) For an n-channel enhancement MOSFET with threshold voltage of 2.5V, determine the current at values of gate-source voltage (1) VGS 4V and (ii) VGS-6V [k-0.3mA/V2] [4 marks] (e) Determine the values of transconductance for an n-channel enhancement MOSFET having threshold voltage VT-3V at the following operating points (i) 6V and (ii) 8V 14 marks] Examiner: Dr. Samuel Afoakwa/Ing. Sammy Obeng Addae/Mr. Nana Boamah
Answers
The paragraph related to transistor technologies covers questions about the differences between FET and BJT, the physical structure of an n-channel JFET, drain characteristics, JFET parameters, and the comparison between depletion and enhancement MOSFETs.
What are the main topics covered in the paragraph related to transistor technologies?This paragraph contains two separate questions related to transistor technologies, specifically Field Effect Transistors (FET) and Bipolar Junction Transistors (BJT).
In Question 2, the first part asks for three differences between FET and BJT, which could include variations in construction, operation principles, or characteristics. The second part requests a drawing of the physical structure and device symbol for an n-channel Junction Field Effect Transistor (JFET). Lastly, it inquires about the meaning of drain characteristics in relation to JFET.
Question 3 begins with the mention of four JFET parameters and requires an explanation of any two of them. The second part asks for a comparison between depletion and enhancement Metal-Oxide-Semiconductor Field Effect Transistors (MOSFET).
The third part requests the determination of current at different gate-source voltage values for an n-channel enhancement MOSFET with a given threshold voltage.The paragraph concludes by mentioning the examiners responsible for the questions.
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Which of the following can cause a flopping sound at the front of the engine
A) drive belt too loose
B) timing chain too loose
C) drive belt too tight
D) timing chain too tight
Answers
Which of the following is NOT a factor in the quality of digital video? a.- frame rate and resolution c. compression technique b. memory technology in your camera de color and bit depth
Answers
The choices that best describe the process of digitization are: Option A: binary-stored video. Option C converts analog video to digital video.
Information transformation into a digital format is referred to as digitization. Be aware that in this format, data is organized into discrete units of data called bits. As a result, the following options best represent the digitization process: Option A: binary-stored video. Option C converts analog video to digital video. This is due to the fact that digital video is a key technology for both video conferencing and video messaging in addition to being a key technology for digital television. This was demonstrated by its use in messaging apps for confidential conversations and for hosting virtual conferences for business meetings amongst personnel.
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in a steady flow process, energy can be transferred by . multiple choice question. work only work, mass, and heat mass and heat only mass only work and heat only
Answers
In a steady flow process, energy can be transferred by work and heat only.
In a steady flow process, energy transfer occurs through work and heat. Work refers to the mechanical energy transfer due to forces acting on the system, such as work done by a pump or work done by a turbine. Heat, on the other hand, is the transfer of thermal energy between the system and its surroundings due to a temperature difference. The flow of energy in a steady flow process can be characterized by the exchange of work and heat, while mass does not directly contribute to energy transfer in this context. Therefore, the correct answer is work and heat only.
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A 1.5-kg specimen of a 90 wt% Pb-10 wt% Sn alloy (Animated Figure 9.8) is heated to 250°C; at this temperature it is entirely an α-phase solid solution. The alloy is to be melted to the extent that 50% of the specimen is liquid, the remainder being the α phase. This may be accomplished either by heating the alloy or changing its composition while holding the temperature constant.
Answers
Answer:
A. By hit and trial method 280 C
Explanation:
ion know B sorry
which statement about life on earth is true ?
Answers
Answer:
Humans have been on Earth for a very short amount of time.
Explanation:
edgeunity 2021
Answer:
Humans have been on Earth for a very short amount of time<3
D.
Explanation:
The company PureNSafe is designing a portable, solar-powered disinfection system for Army use only. The system is simply an inlet pipe, a pump, a mixing chamber and an outlet pipe. The water is continuously pumped into the chamber where it is irradiated with UV light before it exits through the the appropriate tube into a collection vessel. The disinfection rate constant rate of disinfection with UV light is 7.80 s.1 and the amount of bacteria has to be reduced by 99.9%. be reduced by 99.9%. Since the Army requires an object that can be carried in a backpack, it requires that the chamber of the apparatus must not hold a capacity greater than 2 L. How much water will the system be able to produce during 10 hours of sunshine?
Answers
Solution :
The treatment system will operate as the well mixed chamber.
Disinfection rate constant for the UV light, k is 7.80 /s. Number of bacteria in water need to be reduced by 99.9%
Percent reduction of bacteria should be \($(1-10^{0.99}) \times 100 =89.7\%$\)
Volume of the unit chamber is fixed at 2L
Assume the inlet concentration, \($C_0$\) as 1000
The outlet concentration of bacteria, C should be \($1000-\left(1000 \times \frac{89.7}{100}\right)$\)
= 103
The well mixed chamber will then follow a completely mixed flow reactor model.
Compute the time required :
\($t=\frac{1}{k}\left(\frac{C_0}{C}-1\right)$\)
\($t=\frac{1}{7.8}\left(\frac{1000}{103}-1\right)$\)
= 1.115 s
Flow through the system is \($\frac{2 \ L}{1.115 \ s}$\) = 1.79 L/s
The amount of water treated during the 10 hours of sunlight is 1.79 x 10 x 60 x 60 = 64440 L
what causes your car to eventually slow down and stop when you take your foot off the gas pedal
Answers
What type of caliper is shown here?
Answers
Answer:
its a floating caliper definetly
CAN I GET ANSWERS PLEASE, I TRY THE FORMULA AND MY TEACHER HAS A FAMILY EMERGENCY SO HE CANT RESPOND BACK SO PLEASE HELP ME
Answers
Explanation:
I won't answer each of these, but will give you an explaination of how to solve for each.
You'll need to use Ohm's Law and Kirchhoff's Voltage Law.
Remember Ohm's Law as \(V = IR\).
Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.
\(E_T = E_1 + E_2 + E_3\)
A couple of other helpful notes:
These three resistors are in series which means that the current flowing through them is equal.
So it is easy to see that... \(V = IR \rightarrow E_1 = 4*2 = 8 V\)
Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).
In three-phase motors, each phase is ________ degrees out of phase (symmetrical) with the other phases
Answers
In three-phase motors, each phase is 120 degrees out of phase symmetrical with the other phases. Three-phase motors are a type of electric motor that employs three-phase electrical power.
The voltage of each phase is shifted by 120 degrees or one-third of a cycle from that of the other phases. The current in each phase is also shifted by one-third of a cycle from that of the other phases. This arrangement allows for a smooth, steady flow of power to the motor, resulting in less vibration and noise than single-phase motors. Three-phase power is used in a variety of industrial and commercial applications, including pumps, compressors, fans, and conveyor belts. In addition, three-phase motors are used in appliances such as washing machines, refrigerators, and air conditioners. Three-phase motors are typically more efficient and reliable than single-phase motors. They are also more expensive and require more complex wiring. However, the benefits of three-phase power make it a popular choice for high-power applications.
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A major coffee retailer seeks Accenture's help to improve its supply chain
management. Accenture should suggest an enterprise platform utilizing which type
of process?
Answers
A major coffee retailer seeks Accenture's help to improve its supply chain
management. Accenture should suggest an enterprise platform utilizing which type
of process?
Which of the following statements are true about staying safe while
working around all caught-in caught-between hazards?
Select two answers that apply.
What you should do changes based on hazards you’re exposed to.
You should be aware of any hazards that are present
You should be aware of the only hazards indicated as critical by management
What you should do is the exact same no matter the hazard
Answers
Answer:
What you should do changes based on the hazards you're exposed to.
You should be aware of any hazards that are present.
how many pairs of wires get switched when making a gigabit ethernet crossover cable
Answers
Answer:ALL FOUR PAIRS
Explanation: first major difference is the gigabit standards require the use of all four pairs (all eight wires), unlike Fast Ethernet which only utilizes two pairs of wires. As a result, in Gigabit Ethernet, all four pairs must be crossed when building a Crossover cable
When making a Gigabit Ethernet crossover cable, two pairs of wires get switched. Ethernet cables are used to connect computer networks that enable communication between different devices. The two most popular types of Ethernet cables are crossover and straight cables.
Ethernet cables use four pairs of wires to transmit data, out of which two pairs are utilized for transmitting and two pairs are used for receiving. In a straight-through Ethernet cable, the wire arrangement is identical at both ends. For this reason, a straight-through cable is employed to connect devices that belong to the same category. In contrast, a crossover Ethernet cable is employed to connect devices belonging to different categories. A crossover cable reverses the transmitting and receiving pairs, allowing the devices to communicate with one another. In a Gigabit Ethernet crossover cable, two pairs of wires are swapped or switched. These pairs are Pins 1-2 (White and Orange) and Pins 3-6 (White and Green). Therefore, we can conclude that two pairs of wires get switched when making a Gigabit Ethernet crossover cable.
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A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and a 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream consists of 6% trucks, 4% buses, and 3% recreational vehicles. The driver population adjustment factor is estimated at 0.90. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume
Answers
Answer:
peak-hour volume = 1890 veh/h
Explanation:
Determine the peak-hour Volume
Applying the equation below
Vp = v / ( PHF * N * Fg * Fdp ) -------------- ( 1 )
where :
Vp = 1250
v ( peak - hour volume ) = ?
PHF ( peak hour factor ) = 0.84
N = 2 lanes per direction
Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1
Fdp = 0.90
Back to equation 1
v = Vp ( PHF * N * Fg * Fdp )
= 1250 ( 0.84 * 2 * 1 * 0.90 )
= 1890 veh/h
Are you?
Yes
No
omg secret message
Answers
Answer:
are you wht
didn't understand the question
Answer:
Yes/No
Explanation:
NANI?!
1. In a base bias configuration with a supply voltage is 15v, what does Ver equal when reverse biased?
a. 7.5V
b. OM
c. 15V
d. the Q point
Answers
Help me for this question
Answers
Link BD consists of a single bar 36 mm wide and 18 mm thick. Knowing that each pin has a 12-mm diameter, determine the maximum value of the average normal stress in link BD if (a) θ 5 0, (b) θ 5 90°.
Answers
Answer:
hello the diagram attached to your question is missing attached below is the missing diagram
answer :
a) 48.11 MPa
b) - 55.55 MPa
Explanation:
First we consider the equilibrium moments about point A
∑ Ma = 0
( Fbd * 300cos30° ) + ( 24sin∅ * 450cos30° ) - ( 24cos∅ * 450sin30° ) = 0
therefore ; Fbd = 36 ( cos ∅tan30° - sin∅ ) kN ----- ( 1 )
A ) when ∅ = 0
Fbd = 20.7846 kN
link BD will be under tension when ∅ = 0, hence we will calculate the loading area using this equation
A = ( b - d ) t
b = 12 mm
d = 36 mm
t = 18
therefore loading area ( A ) = 432 mm^2
determine the maximum value of average normal stress in link BD using the relation below
бbd = \(\frac{Fbd}{A}\) = 20.7846 kN / 432 mm^2 = 48.11 MPa
b) when ∅ = 90°
Fbd = -36 kN
the negativity indicate that the loading direction is in contrast to the assumed direction of loading
There is compression in link BD
next we have to calculate the loading area using this equation ;
A = b * t
b = 36mm
t = 18mm
hence loading area = 36 * 18 = 648 mm^2
determine the maximum value of average normal stress in link BD using the relation below
бbd = \(\frac{Fbd}{A}\) = -36 kN / 648mm^2 = -55.55 MPa
The maximum value of the average normal stress in link BD at the given angles are;
At θ = 0°; 64.15 MPa
At θ = 90°; 66.66 MPa
Average Normal Stress
The image of the link and the single bar is missing and so i have attached it.
From the image of the link and single bar attached, i have drawn a free body diagram of link ABC that will help us to solve this question.
Taking Moments about point A and summing to zero, we can solve for F_bd at the given angles as;
A) At θ = 0°;
From the diagram, AC = 450 mm = 0.45 m and force acting at point C is 24 kN or 24000 N. Thus;
(0.45 * sin 30)(24000) - F_bd(0.3 * cos 30) = 0
Thus;
(0.45 * sin 30)(24000) = F_bd(0.3 * cos 30)
⇒ 5400 = 0.2598F_bd
F_bd = 5400/0.2598
F_bd = 20785.22 N
Area at tension Loading is;
A = (0.03 - 0.012)0.018
A = 324 × 10⁻⁶ m²
Thus;
Average Normal stress is;
σ = 20785.22/(324 × 10⁻⁶)
σ = 64.15 × 10⁶ Pa = 64.15 MPa
B) At θ = 90°;
(0.45 * cos 30)(24000) + F_bd(0.3 * cos 30) = 0
Thus;
-(0.45 * cos 30)(24000) = F_bd(0.3 * cos 30)
F_bd = -36000 N
Area at compression Loading is;
A = 0.03 * 0.018
A = 540 × 10⁻⁶ m²
Thus;
Average Normal stress is;
σ = -36000/(540 × 10⁻⁶)
σ = 66.66 × 10⁶ Pa = 66.66 MPa
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