A ball that is dropped from rest from a height h reaches a speed v just before impact with the ground. If the ball is dropped from rest from a height of 2h, instead, it will reach a speed of v multiplied by _______ just before impact with the ground.

Answer:

1.2 m/s^2

Explanation:

average acceleration = vf-vi/t = (15 m/s-0 m/s)/10 s = 1.2 m/s^2

Answer:

It often happens in a circuit which was conducting,and a switch is opened. Any inductance in the circuit will help the voltage increase due to back emf,and this can cause breakdown of the air insulation and an arc can form.

Explanation:

Answer:

A blood transfusion is the process of transferring blood or one of its components from one person to another.

Here we need to study the motion equations of an object.

We will see that:

The time that passes between the moment Gary throws the ball and the moment Alex catches it is t = 1.37 seconds.

Let's write the motion equations of the ball:

Any object that is on the air (when we ignore the air resistance and such) is only being accelerated by Earth's gravitational force.

Thus, the acceleration of the ball will be:

a(t) = -9.8m/s^2

Where the negative sign is because this acceleration is downwards.

Now to get the velocity of the ball we need to integrate over time, we will get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the initial velocity of the ball, which we know is 10m/s, then we have:

v(t) =  (-9.8m/s^2)*t + 10m/s

To get the position equation of the ball we integrate again:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10m/s)*t + p0

where p0 is the initial position of the ball, we do not know it, and really we do not need it, so we can define p0 = 0m, then the position equation is:

p(t) =  (1/2)*(-9.8m/s^2)*t^2 + (10m/s)*t

Such that p(0s) = 0m

We know that the ball is caught when it is 4.5m above the position where it was thrown, so we need to solve:

p(t) = 4.5m

for t.

4.5m = (1/2)*(-9.8m/s^2)*t^2 + (10m/s)*t

(4.9 m/s^2)*t^2 - (10 m/s)*t + 4.5m = 0

This is a quadratic equation, so we can just use the Bhaskara's formula to get the solutions:

\(t = \frac{-(-10m/s) \pm \sqrt{(-10m/s)^2 - 4*(4,9m/s^2)*(4.5m)} }{2*(4.5 m/s^2)} \\\\t = \frac{(10m/s) \pm 3.44 m/s }{9.8 m/s^2}\)

Then we have two solutions:

\(t = \frac{(10m/s) - 3.44 m/s }{9.8 m/s^2} = 0.67 s\\\\t = \frac{(10m/s) + 3.44 m/s }{9.8 m/s^2} = 1.37 s\)

The first one is for the first time that the ball reaches the height of 4.5m (when it is going up) while the second one is for the part when the ball is falling down.

So the time that passes between the moment Gary throws the ball and the moment Alex catches it is t = 1.37 seconds.

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Answer:

k.E= 49 ms^-2

Explanation:

k.E= 1/2 mv^2

From that formula of k.E

K.E is directly proportional to the ( velocity)^2

K.E directly proportional to (7)^2

so that k.E increase by 49

The correct option is (a) i.e. a galaxy in the local group, galaxies is likely to be oldest.

A galaxy is a collection of stars, stellar remains, interstellar gas, dust, and dark matter that are gravitationally bonded together. The name comes from the Greek word galaxias, which means "milky" and refers to the Milky Way galaxy, which houses the Solar System. Galaxies, which contain an average of 100 million stars, range in size from dwarfs, which contain fewer than 100 million stars, to supergiants, which contain 100 trillion stars, all of which orbit the galaxy's center of mass. Only a small percentage of the mass in a normal galaxy is visible in the form of stars and nebulae; the majority of the galaxy's mass is dark matter. Supermassive black holes are a typical component of galaxy centers. According on their optical shape, galaxies are classified as elliptical, spiral, or irregular. It is believed that the nuclei of many of them contain supermassive black holes. Sagittarius A*, the name of the Milky Way's primary black hole, is four million times more massive than the Sun. GN-z11 is the oldest and furthest away galaxy as of March 2016. It can be seen as having existed only 400 million years after the Big Bang and is located 32 billion light-years away from Earth.

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Answer: B or "diamonds are rare,valuable gems".

Explanation:

since the link does not show very much, I don't know if A is correct or not. D is incorrect because that  is an opinion. C is incorrect.

Answer:

allah is pog

Explanation:

Answer: gas

Explanation:

The force from student is positive, the force due to gravity is zero and the frictional force due to air is negative.

Given the distance of the bag from the room = 3m

From the diagram we can see that there are three different forces acting on the bag such as:

Fs : force from the student

FG: Force due to gravity

f: force of friction from air

Here we can say that according to the free-body diagram:

The force from from student(Fs) is acting upwards and is positive since the student is pushing the bag across the room, the force from the student (Fs) is doing positive work on the bag.

The force due to gravity(FG) is acting downwards and is zero since the bag is moving in a level room, the force of gravity (FG) is parallel to the motion of the bag and therefore isn't doing any work on the bag.

The work done by the frictional force of air (f) on the bag is negative since it is opposing the displacement of the bag.

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The tension in the cord is 4.6 N

According to Newton's second law, an object's acceleration is determined by two factors: the net force acting on the object and the mass of the object.

So, if we chose the positive +x uphill for the FedEx box of mass m2= 1.0 kg and +ve axis for m1 = 3.0 kg such that their accelerations have the same magnitude.

As we apply Newton's second law to each box, we discover that:

\(\mathbf{F - T -m_2gsin\theta = m_2a}\)

where;

Thus, the first equation can be rewritten as:

\(\mathbf{F-m_2gsin\theta = (m_1+m_2)a}\)

Now, the acceleration moving in the same direction can be computed as:

\(\mathbf{a=\dfrac{12N (1.0 kg)(9.8 \ m/s^2)sin 37^0}{(1.0+3.0)kg}}\)

a = 1.53 m/s²

Finally, the tension \(\mathbf{T=m_1a}\) = (3.0 kg) (1.53 m/s²)

= 4.6 N

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To maximize the objective function p with the given constraints, we use linear programming by identifying the feasible region.

Finding corner points, evaluating p at each point, and selecting the point with the maximum value of p.In this case, the given constraints are x = 0, y = 0, 2x + 2y = 4, and x + y = 8. To maximize the objective function p, we follow these steps:Identify the feasible region by graphing the constraints on a coordinate plane.

The corner points, which represent the vertices of the feasible region.Evaluate the objective function p at each corner point.Select the point with the maximum value of p as the optimal solution that maximizes p while satisfying the given constraints.

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No, my measurement does not agree with the prediction of 343 m/s, because it must be within two standard deviations of the prediction to agree.

A standard deviation is a measure of how much data is scattered around the average or mean value. In this case, the average or mean value is 343 m/s. In order for the measurement to agree with the prediction, it must be within two standard deviations of the mean.

This means that the measurement must be between (343 m/s - 2 x standard deviation) and (343 m/s + 2 x standard deviation), which is a much wider range than just 343 m/s. Therefore, unless the measurement is within two standard deviations of the prediction of 343 m/s, it does not agree with the prediction.

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Answer:

C. Pulmonary endurance

Explanation:

I'm pretty sure it's "C" because cardiovascular and pulmonary endurance are the same thing and usually you'd hear cardiovascular more than pulmonary.

Sorry if I'm wrong!

Answer:

c

Explanation:

i just took the test

Answer:

a) \(W_{Mercury}=92.5 N\)

b) \(W_{Mars}=92.8 N\)

c) \(W_{Saturn}=261.0 N\)

d) \(W_{Pluto}=15.5 N\)

Explanation:

First of all, we need to remember the value of gravity acceleration on each planet.

\(g_{Mer}=3.70 m/s^{2}\)

\(g_{Mar}=3.71 m/s^{2}\)

\(g_{Sat}=10.44 m/s^{2}\)

\(g_{Plt}=0.62 m/s^{2}\)

The definition of weigh is the product between the mass and the gravity acceleration, therefore we will have:

a) \(W_{Mercury}=25*3.70=92.5 N\)

b) \(W_{Mars}=25*3.71=92.8 N\)

c) \(W_{Saturn}=25*10.44=261.0 N\)

d) \(W_{Pluto}=25*0.62=15.5 N\)

I hope it helps you!

The charge that passes a cross-sectional area of the circuit in 0.44 s when the compressor on an air conditioner draws 22.0 A when it starts up is 9.68 C.

To find the charge that passes a cross-sectional area of the circuit in this time,

we can use the formula Q = I x t, where Q is the charge, I is the current, and t is the time.

We are given that the current when the compressor starts up is 22.0 A and the time it takes to start up is 0.44 s. Therefore, we can plug these values into the formula and get:

Q = 22.0 A x 0.44 s
Q = 9.68 C

Therefore, the charge that passes a cross-sectional area of the circuit in 0.44 s is 9.68 C.



When an air conditioner starts up, its compressor draws a large amount of current for a short period of time. This current surge is known as inrush current or startup current. In this question, we are given the value of the current when the compressor starts up and the time it takes to start up, and we need to find the charge that passes a cross-sectional area of the circuit in this time.

To understand this question, we need to know the formula for calculating charge, which is Q = I x t, where Q is the charge, I is the current, and t is the time. We can use this formula to calculate the charge that passes a cross-sectional area of the circuit in 0.44 s when the compressor on an air conditioner draws 22.0 A when it starts up.

Plugging in the given values into the formula, we get:

Q = 22.0 A x 0.44 s
Q = 9.68 C

Therefore, the charge that passes a cross-sectional area of the circuit in 0.44 s is 9.68 C.

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The total length of the brass used to make the girls neck rings= 840cm

The radius of the brass = 20 cm

The volume of the cylinder = 15,086cm³

The mass of brass = 131700.78g

The number of turns that makes up the neck rings = 21

The circumference of each turn = 40cm

Therefore the total length = 40 × 21 = 840cm

The height of the brass= 12cm

The circumference of the turns= 40cm

Therefore the radius = 40/2 = 20cm

The formula for the volume of cylinder,

V = πr²h

r = 20cm

h = 12cm

V= 22/7 × 20² × 12

V = 22× 400×12/7

V= 105600/7

V= 15,086cm³

Density =8.73 g/cm³

Volume = 15,086cm³

mass= density × volume

mass= 8.73 × 15,086

Mass = 131,700.78g

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The tendency of a wave to bend as it passes from one transparent medium to another is called refraction.

This phenomenon occurs because light travels at different speeds through different materials, causing the wave to change direction and bend. The amount of refraction that occurs depends on the angle of incidence and the difference in the refractive indices of the two materials. When light passes from a medium with a higher refractive index to one with a lower refractive index, the wave bends away from the normal (a line perpendicular to the surface of the interface between the two media). Conversely, when light passes from a medium with a lower refractive index to one with a higher refractive index, the wave bends towards the normal.

Refraction is responsible for many optical phenomena, such as the apparent bending of a pencil in a glass of water and the formation of rainbows. Understanding the principles of refraction is important in many fields, including optics, engineering, and medicine.

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Answer:

its b

Explanation:

cause im in  7th grade ive been asked the same question

The helium-stuffed ball is surely transferring against the direction of what looks like gravity.

The equal thing that it does while you're not in an accelerating body. It does that for the equal motive: buoyancy because of being lighter than air. The air inside the vehicle has a higher density inside the back of the car than it does inside the front. this means that the net pressure on the balloon due to collisions with the air will be in the ahead path.

The balloon does the other to something your body could do. for that reason, if the car comes to rest the balloon moves toward the return. The secret is that the balloon is filled with helium (He) and you are made of stuff a great deal heavier than air.

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Answer:

speed

Explanation:

The distance traveled and time, the average speed of an object can be calculated. The correct answer would be option (A).

Average speed is defined as the total distance traveled by an object divided by the total time it took to travel that distance. This is a measure of the overall pace of an object's motion over a period of time.

Instantaneous speed is the limit of the average speed as the time interval approaches zero. In other words, it's the rate of change of an object's position with respect to time at a specific moment.

Average acceleration is defined as the change in velocity (speed in a certain direction) divided by the time interval over which that change occurred. This is a measure of the rate of change of an object's speed over a period of time.

Instantaneous acceleration is the limit of the average acceleration as the time interval approaches zero. In other words, it's the rate of change of an object's velocity at a specific moment.

In summary, with the given information of distance traveled and time, the average speed of an object can be calculated, but the instantaneous speed, average acceleration, and instantaneous acceleration cannot be calculated.

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The complete question would be as:

If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculated?

A. Average speed

B. Instantaneous speed

C. Average acceleration

D. Instantaneous acceleration

To find:

Which of the planets has the highest density.

Explanation:

Neptune is known as the ice planet. It has a higher density than gas giants but a lower density than rocky planets. The density of the Neptune is 1638 kg/m³.

Jupiter is known as a gas giant. Gas giants has the lowest densities. The density of Jupiter is 1326 kg/m³.

The Earth and the Mercury are rocky planets. The densities of rocky planets are more than that of the gas giants and ice giants. The density of the Earth is 5514 kg/m³ and the density of the Mercury is 5429 kg/m³.

Final answer:

On comparing the densities of the planets, the Earth has the highest density.

Thus the correct answer is option C.

The specific heat of pure water is 4.184 J/g °C. A 10.00-gram sample of pure water goes from 22.00°C to 32.00°C. The specific heat of pure water is 4.184 J/g °C. A 10.00-gram sample of pure water goes from 22.00°C to 32.00°C. sample gain  418.4 J. Therefore correct option is B.

To calculate the amount of heat gained by the sample of water, we can use the formula:

q = m × c × ΔT

where q is the amount of heat gained, m is the mass of the sample (in grams), c is the specific heat of water (in J/g °C), and ΔT is the change in temperature (in °C).

Plugging in the values given in the question, we get:

q = 10.00 g × 4.184 J/g °C × (32.00°C - 22.00°C)
q = 10.00 g × 4.184 J/g °C × 10.00°C
q = 418.4 J

Therefore, the answer is B. 418.4 J.

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The pilot should immediately reduce the speed to the maximum specified for the category to ensure the safety of the flight. The pilot should also adjust the airplane's altitude and heading to maintain a stable approach path and touchdown point.

The pilot should follow the appropriate procedure as outlined in the airplane's operating manual. If pilot is circling to land in a Category B airplane but is maintaining a speed 5 knots faster than the maximum specified for that category.

The pilot should also adjust the airplane's altitude and heading to maintain a stable approach path and touchdown point. The pilot should communicate with air traffic control and follow their instructions to ensure proper sequencing with other traffic. Additionally, the pilot should remain vigilant and monitor the airplane's systems and

instruments to ensure that the airplane is operating within its limits and that the flight remains safe and under control. Following these procedures will help ensure a safe and successful landing.

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To complete your masters degree in physics, your advisor has you design a small linear accelerator capable of emitting protons each with a kinetic energy of 10.00 kev.

A small linear accelerator, also known as a linear particle accelerator, is an instrument used to accelerate charged particles, including protons. It utilizes a high-frequency electromagnetic field to propel particles forward in a straight line. To complete your master's degree in physics, your advisor has asked you to design one of these devices, which must be capable of emitting protons with a kinetic energy of 10.00 keV.

To design a small linear accelerator, you will need to understand the basic principles of electromagnetism, as well as the properties of charged particles and how they interact with electromagnetic fields. You will also need to be familiar with the various components of an accelerator, such as the radiofrequency cavities and the beam tube.

To create a linear accelerator capable of emitting protons with a kinetic energy of 10.00 keV, you will need to carefully select the appropriate components and adjust their parameters to optimize the acceleration process. This will require a combination of theoretical knowledge, experimental skills, and analytical thinking.

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The work done during the process is  506.2 J.

The work done during the process is calculated by applying the following equation.

W = PΔV

W = P ( Vf - Vi )

where;

The final volume of the system is calculated as follows;

Vf = A x h

Vf = 7.4 x 10⁻³ m² x 7.2 x 10⁻² m

Vf = 5.33 x 10⁻⁴ m³

W = 9.5 x 10⁵ Pa x ( 5.33 x 10⁻⁴ m³ - 0 )

W = 506.2 J

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Newton's second law allows to find the acceleration of the two-body system, where a mass is hanging is:

Newton's second law states that the net force on a body is equal to the product of the mass and the acceleration.

         ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

A free body diagram is that diagram of the system where the forces are shown without the details of the bodies. In the attachment we have a free-body diagram of the system.

Let's write Newton's second law for each axis.

x- axis

        T = m₁ a

y-axis

body in the horizontal part

        N-W₁ = 0

       N = W₁

Body hanging.  

         W₂ - T = m₂ a

Wwhere the positive direction is down, let's write our system of equations.

                T = m₁ a  

         W₂-T = m₂ a

Let's Resolve.

          m₂ g = (m₁ + m₂) a

          a = \(\frac{m_2}{m_1+m_2} \ g\)  

Let's calculate.

         a =\(\frac{63}{10+63} \ 9.8\)  

         a = 8.46 m / s²

In conclusion using Newton's second law we can find the acceleration of the two-body system, where a mass is hanging is:

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The interaction of an attracting or repulsive force between two charged bodies is referred to as an electric force.

This force is comparable to other forces in that it strikes and affects a specific item, and it is simple to illustrate using Newton's law of motion. One of the forces acting on other bodies is the electric force.

Electric force is the interaction of any two charged bodies that is either repellant or attracting. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so. The list of additional forces that apply to objects includes the electric force.

The electrostatic force between the two electrons is one of repulsion since electrons are negatively charged and items with like charges repel one another.

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