a ball is thrown straight down from the top of a building with a speed greater than its terminal speed vt. which of the following graphs best represents the speed v of the ball as a function of time t while it falls to the ground?

44.76

There are two options for formulas to use here, both work.

0=(m1)(V1f)+(m2)(V2f)

Or

(m1)(V1f)=—(m2)(V2f)

Both formulas should give you the answer of 44.763514, which can be rounded to the specifications of whatever you need it for.

Blessings in the Name of Jesus Christ our Lord!

A collision that is fully elastic is one where there is no kinetic energy lost during the contact. In an inelastic collision, a proportion of the energy is converted into another kind of energy during the contact.

In elastic collisions, kinetic energy and momentum are both conserved. Consider two similar trolleys that are moving in the same direction at the same pace. With no loss of speed, they collide and bounce off one another. Since no power has been lost, this collision is fully elastic.

photo of A description of completely elastic collision

When a system's maximal quantity of kinetic energy is equal to zero, a relatively inelastic collision takes place.

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A collision that is fully elastic is one where there is no kinetic energy lost during the contact. In an inelastic collision, a proportion of the energy is converted into another kind of energy during the contact.

In elastic collisions, kinetic energy and momentum are both conserved. Consider two similar trolleys that are moving in the same direction at the same pace. With no loss of speed, they collide and bounce off one another. Since no power has been lost, this collision is fully elastic.

photo of A description of completely elastic collision

When a system's maximal quantity of kinetic energy is equal to zero, a relatively inelastic collision takes place.

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Answer:

Gravity.

Rocket ships.

Ball.

Basketball.

Explanation:

Gravity has to do a lot with air. It puts the planets in there area.

Rocket Ship has to do a lot with air. If i'm right, they calculate the area, weather, about the air.

A ball gets throwed in the air, which gravity comes into place.

Basketball is also a similar example to a ball.

Answer:

The minimum mass of m2 before m1 starts sliding across the table is 57 grams

Explanation:

The given mass on the table, m1 = 250 g

The coefficient of friction between the table and the mass, m1, μ = 0.228

Therefore, the friction force, F\(_F\) between the mass m1 and the table is given as follows;

F\(_F\) = W₁ × μ

Where;

W₁ = The weight of m1  = Mass of m1 × Acceleration due to gravity

W₁ = 250 g × 9.81 m/s² = 0.25 kg × 9.81 m/s² = 2.4525 N

W₁ = 2.4525 N

Which gives;

F\(_F\) = 2.4525 N × 0.228 = 0.55917 N

F\(_F\) = 0.55917 N

By equilibrium of forces, the weight, W₂, of the mass m2 at which the mass m1 starts sliding is equal to the frictional force F\(_F\) of m1 or 0.55917 N

Therefore, for slipping to occur, we have;

W₂ = 0.55917 N

However, W₂ = Mass of m2 × Acceleration due to gravity

∴ W₂ = 0.55917 N = m2 × 9.81 m/s²

0.55917 N = m2 × 9.81 m/s²

m2 = 0.55917 N/(9.81 m/s²) = 0.057 kg = 57 grams

The minimum mass of m2 before m1 starts sliding across the table is 57 grams.

Answer:

(a) 217 Ra          (b)     29 P

      84                          16

Explanation

(a) 221 Rn ---------------> 4 He + 217 Ra

      86                           2             84

    the mass number is reduced by 4 while the atomic number is reduced               by 2 since an alpha particle is emitted

(b) 29 P ------------------> 0 e + 29 P

       15                          -1         16

     the mass number remains the same while the atomic number is reduced by -1 since a beta particle is emitted

We will determine the final speed as follows:

So, superman's final velocity is approximately 201 m/s.

[In this case superman's initial velocity is a datapoint that is not necessary]

Answer:

a)  S = V0 t + 1/2 a t^2     distance ball travels in time t

0 = V0 t - 1\2 * 9.8 * t^2       ball returns to original height

V0 = 4.9 * 4.5 = 22.05 m / s      original speed

b) Since V0 = g t   time to decelerate to zero

t = 22.05 / 9.8 =  2.25 sec       time up equals time down

c) S = V0 t + 1/2 a t^2  

S = 22.05 * 2.25 - 9.8 / 2 * 2.25^2 = 24.8     Max height

Check: Avg speed = 22.05 / 2 = 11.025 m/s

Time to fall from max height = 11.025 * 2.25 = 24.8 ft

After a batter pops a ball straight up we have:

a) The initial speed of the ball before it returns to the height from which it was hit 4.5 seconds later, is 22.07 m/s.

b) The ball reaches its maximum height 2.25 s after it was hit.  

c) The maximum height of the ball, s measured from the point where it was hit, is 24.8 m.          

a) The initial speed can be calculated with the following equation:

\( v_{f} = v_{0} - gt \)

We will use this equation to find the initial speed when the ball is moving upward.

Where:

\(v_{0}\): is the initial speed =?

\(v_{f}\): is the final speed = 0 (at the maximum height)

g: is the acceleration due to gravity = 9.81 m/s² (it is negative because its direction is in the opposite direction to the movement of the ball when it is going up)

t: is the time when the ball is going up

When the ball is going up, the time is:

\( t = \frac{4.5 s}{2} = 2.25 s \)

Hence, the initial speed is:

\( v_{0} = gt = 9.81 m/s^{2}*2.25 s = 22.07 m/s \)

b) The ball reaches its maximum height 2.25 s after it was hit because the ball returns to the height from which it was hit. The rise time is equal to the fall time.  

c) The maximum height of the ball is the following:

\( v_{f}^{2} = v_{0}^{2} - 2gh \)  

Where:

h: is the maximum height

Then, the maximum height is:

\( h = \frac{v_{0}^{2}}{2g} = \frac{(22.07 m/s)^{2}}{2*9.81 m/s^{2}} = 24.8 m \)

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Answer:

KE = 100 J

Explanation: Should be correct

Answer:

A thats answer thankyou

Answer:

A)    Net force in the horizontal direction is 19.641 N

B)    Net force in the vertical direction is 20 N

Explanation:

The normal force (20 N) and the weight force (20 N) cancel out.

Next lets find the horizontal and vertical components on the right side of the diagram.

We are given the angle and the hypotenuse.

First lets find the opposite side (vertical component).

\(sin(x)\frac{O}{H}\)

\(O=Hsin(x)\)

\(O=40sin(30)\)

\(O=20\)

Now lets find the adjacent side (horizontal component).

\(cos(x)=\frac{A}{H}\)

\(A=Hcos(x)\)

\(A=40cos(30)\)

\(A=34.641\)

Now we can ignore the 40 N force.

We are left with 1 force in the vertical direction.

So the net force in the vertical direction is 20 N

We are left with 2 forces in the horizontal direction.

We have 1 force of 15 Newtons moving in the left direction.

We also another force of 34.641 Newtons moving to the right.

So the net force in the horizontal direction is 19.641 N.

Answer:

true

Explanation:

Protons and neutrons are found in the nucleus

Answer:

D. All bulbs will go out

Explanation:

This is a series circuit. If one bulb goes out, all the other bulbs will not light since it is now an incomplete circuit. The circuit cannot flow to the other bulbs since one bulb is out which will prevent current from flowing to the rest of the circuit.

The probability computed shows that we can expect 1 out of 5 clothes to be clean.

From the information given, it was stated that 20% of the clothes are clean. Therefore, the probability of clean clothes will be:

= 20% = 1/5.

Therefore, one out fo five clothes are clean.

The standard deviation will be:

= ✓npq

where,

n = 5

p = 0.20

q = 1 - 0.20 = 0.80

SD = ✓(5 × 0.20 × 0.80)

= ✓0.80

= 0.09

The distribution is close to symmetric.

The binomial distribution table will be:

0 = (0.20)^0 (0.80)^5 = 0.3277

1 = (0.20)¹ (0.80)⁴ = 0.4096

2 = (0.20)² (0.80)³ = 0.2040

3 = (0.20)³ (0.80)² = 0.0512

4 = (0.20)⁴ (0.80)¹ = 0064

5 = (0.20)^5 (0.80)^0 = 0.0003

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To complete the configuration as described, follow the steps below:

1. Assign IP addresses to the serial interfaces:

  - On RouterA's S0/0/0 interface, assign the first address on the subnet: 192.168.2.25 with a 30-bit mask (255.255.255.252).

  - On RouterB's S0/0/1 interface, assign the last address on the subnet: 192.168.2.26 with a 30-bit mask (255.255.255.252).

 Here's an example of how you can configure the IP addresses on both routers:   ```plaintext

  RouterA# configure terminal

  RouterA(config)# interface Serial0/0/0

  RouterA(config-if)# ip address 192.168.2.25 255.255.255.252

  RouterA(config-if)# no shutdown

  RouterA(config-if)# exit

  RouterA(config)# exit

RouterB# configure terminal

  RouterB(config)# interface Serial0/0/1

  RouterB(config-if)# ip address 192.168.2.26 255.255.255.252

  RouterB(config-if)# no shutdown

  RouterB(config-if)# exit

  RouterB(config)# exit

  ```2. Use the `show controllers` command on RouterA to identify the DCE (Data Communications Equipment) device. The DCE device is the one that provides clocking on the serial interface.

```plaintext

  RouterA# show controllers Serial0/0/0

  ```   Look for the line that indicates the DCE status, which should mention something like "Clock rate 9600" or "DCE V.35."

3. Configure the clock rate on the DCE interface:

  - Assuming RouterA is the DCE device based on the previous step, configure the clock rate of 9600 on RouterA's Serial0/0/0 interface.

 ```plaintext

  RouterA# configure terminal

  RouterA(config)# interface Serial0/0/0

  RouterA(config-if)# clock rate 9600

  RouterA(config-if)# exit

  RouterA(config)# exit

  ```4. Bring both interfaces up:

  - On RouterA:

  ```plaintext

  RouterA# configure terminal

  RouterA(config)# interface Serial0/0/0

  RouterA(config-if)# no shutdown

  RouterA(config-if)# exit

  RouterA(config)# exit

  ``` - On RouterB:

```plaintext

  RouterB# configure terminal

  RouterB(config)# interface Serial0/0/1

  RouterB(config-if)# no shutdown

  RouterB(config-if)# exit

  RouterB(config)# exit

  ```5. Save the changes on both routers:

  - On RouterA:

  ```plaintext

  RouterA# write memory

  ``` - On RouterB:

```plaintext

  RouterB# write memory

  ```

By following these steps, you should have completed the configuration of the serial link between the two routers in a back-to-back configuration.

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If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, then it will make 2.2×10⁵ cycles. in 1.0 h. Hence option D is correct.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C

Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.

Frequency is nothing but the number of oscillation in a unit time.

Given,

frequency f = 60.0 Hz.

time t = 1.0 h = 60*60 = 3600s

F = number of cycles/time

number of cycles = F×time

The number of cycles in 1 Hr is

60*3600 = 2.2×10⁵ cycles.

Hence option D is correct.

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Recent trends in global energy use involve a shift towards more renewable energy sources and greater energy efficiency. Fossil fuels such as coal, oil, and gas have been the dominant sources of energy for decades, but their use has been declining as renewable energy sources such as wind, solar, and hydropower have become more affordable and accessible. In addition, there has been a push towards greater energy efficiency, with initiatives aimed at reducing waste and improving the efficiency of buildings, vehicles, and industrial processes.

These trends vary from place to place across the globe, with some regions leading the way in renewable energy and energy efficiency while others lag behind. For example, Europe has been at the forefront of the shift towards renewable energy, with countries such as Denmark and Germany generating a significant portion of their electricity from wind and solar power. In contrast, countries such as the United States and China continue to rely heavily on fossil fuels, although there are signs of progress towards greater renewable energy use in both countries.
In terms of energy efficiency, some countries have implemented aggressive measures to reduce waste and improve efficiency, while others have been slower to adopt such policies. Countries such as Japan and South Korea have made significant progress in this area, while others, such as Russia and India, have been slower to adopt energy efficiency measures.
Overall, the trends in global energy use reflect a growing awareness of the need to transition to more sustainable and efficient sources of energy, but the pace of this transition varies widely across the globe.

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Answer:

D. It focuses on the core muscles

Answer:

A. It is a total body exercise

Explanation:

In cardio kickboxing as described by my school is "

The first benefit is the one which we are focusing on because all the other answers are correct but A. Total body exercise is the best answer because it covers all of them as an compendious answer

Also I took the test and got this correct

Answer:

c

Explanation:

a. The probability that a randomly selected soda can has a volume less than 12 fluid ounces is approximately 0.3085

b. The probability that the sample mean volume is less than 12 fluid ounces, when a sample of size n = 32 is taken, is approximately 0.0023

c. The distribution of the sample mean becomes narrower and more concentrated around the population mean. Consequently, the probability of obtaining a sample mean less than 12 fluid ounces decreases because the sample mean is less likely to deviate significantly from the population mean.

a) Let X be the volume of a randomly selected soda can. We are given that the mean (μ) is 12.01 fluid ounces and the standard deviation (σ) is 0.02 fluid ounces.

We need to calculate P(X < 12). To do this, we standardize the variable using the z-score formula:

z = (X - μ) / σ

Substituting the given values, we have:

z = (12 - 12.01) / 0.02

= -0.5

Now, we can use a standard normal distribution table or calculator to find the probability associated with the z-score of -0.5. From the table, we find that the probability is approximately 0.3085.

b) When a sample of size n = 32 soda cans is drawn randomly from the population, the mean volume of the sample (denoted by X-bar) follows a normal distribution with the same mean (μ = 12.01 fluid ounces) but a smaller standard deviation (σ-bar) given by:

σ-bar = σ / sqrt(n)

Substituting the values, we have:

σ-bar = \(0.02 / \sqrt{(32)\)

= 0.02 / 5.6569

≈ 0.00354

Now, we need to calculate P(X-bar < 12). Again, we standardize the variable using the z-score formula:

z = (X-bar - μ) / σ-bar

Substituting the given values, we have:

z = (12 - 12.01) / 0.00354

≈ -2.8249

Using the standard normal distribution table or calculator, we find that the probability associated with the z-score of -2.8249 is approximately 0.0023.

c) As larger and larger sample sizes are taken, the probability that the sample mean volume is less than 12 fluid ounces tends to decrease. This is because as the sample size increases, the sample mean becomes a better estimate of the population mean. The larger the sample size, the more reliable and representative the sample mean is of the true mean. Hence, the sample mean is more likely to be closer to the population mean.

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The wavelength emitted from an asphalt surface with a temperature of 25 ∘C is approximately 9.7 µm (micrometers), to two significant figures

The formula that is used to calculate the wavelength emitted from an asphalt surface is given by Wien's law, which states that the wavelength of maximum emission for a body at temperature T is given by λmax=2.898 x 10^-3 m K / T.

Therefore, we can substitute the given values of the temperature of the asphalt surface to solve for the wavelength of emitted radiation. The temperature of the asphalt surface is given as 25 °C, which we need to convert to Kelvin by adding 273.15 to obtain 298.15 K.

Substituting this value into the formula yields:

λmax=2.898 x 10^-3 m K / 298.15 K= 9.72 × 10-6 m or 9.7 µm

Therefore, the wavelength emitted from an asphalt surface with a temperature of 25 ∘C is approximately 9.7 µm (micrometers), to two significant figures.

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Answer: I believe it's dispersion, diffraction, reflection of light, refraction of light, polarization of light and interference of light.

Explanation:

Answer:

Reflected

Explanation:

During the process of reflection whatever that is sent forth e.g light comes back (reflects)

Answer:

transmitted

Explanation:

took quiz

1. The method used for electrical isolation of input and output circuits of switching power supply is called as isolation transformer. It uses transformer to separate the input circuit from the output circuit. This is done to avoid the transmission of high voltage spikes from the power input to the output.

2. The control circuit of switching power supply uses negative feedback control. The negative feedback helps to maintain the output voltage in a fixed range by adjusting the duty cycle of the switch based on the output voltage.

3. The SG3525 is a voltage mode switching power supply integrated PWM-controller.

4. The main difference between UC1842, UC2842 and UC3842 are as follows:UC1842 - It is a fixed frequency current mode PWM controllerUC2842 - It is an adjustable frequency current mode PWM controller UC3842 - It is a fixed frequency current mode PWM controller

The UC2842 has the ability to generate a variable frequency which is not present in the UC1842. Similarly, the UC3842 does not have the capability to generate variable frequency.

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a) To balance the gravitational attraction between Earth and the Moon, the electrostatic force between their net negative charges (-Q) needs to be equal to the gravitational force between them. Mathematically, we can equate these two forces:

k(Q^2/r^2) = G(Mm/r^2),

where k is the electrostatic constant, G is the gravitational constant, M is the mass of Earth, m is the mass of the Moon, and r is the distance between their centers.

Canceling out the common terms and solving for Q, we get:

Q = sqrt(GMm/k).

b) The distance between the Earth and the Moon does not affect the value of Q. The gravitational force and electrostatic force both depend on the distance squared (1/r^2), so as long as the distance remains the same, the value of Q required to balance the forces remains constant.

c) To find the number of electrons needed to produce a net charge of -Q, we need to know the charge of a single electron. The elementary charge, e, is approximately -1.602 x 10^-19 Coulombs. Therefore, the number of electrons required can be calculated as:

Number of electrons = Q/e.

In summary, the value of Q required to balance the gravitational attraction between Earth and the Moon can be calculated using the equation Q = sqrt(GMm/k). The distance between the Earth and the Moon does not affect this value. To determine the number of electrons needed to produce this charge, we divide Q by the charge of a single electron, e.

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c it hink this because im geuss

Answer:

c

Explanation:

DPP is a method of capital budgeting. It is the length of time required to recover the initial cash outflow discounted at a specific interest rate.

(i) Discounted Payback Period (DPP): It is a method of capital budgeting. It is the length of time required to recover the initial cash outflow discounted at a specific interest rate. Benefit/Cost Ratio (BCR): It is the ratio of the present value of benefits to the present value of costs. It is used in cost-benefit analysis to identify whether a proposed project or investment is feasible.

(ii) Elements of Bookkeeping: Cash book, purchase book, sales book, journal, ledger. Profit and Loss Account: It is an account that records a company's profits and losses for a specific period of time.

(iii) Common important finance ratios are: Current Ratio, Quick Ratio, Debt-Equity Ratio, Inventory Turnover Ratio, Debt-Service Coverage Ratio.

(iv) BFD, PFD & PID: Block Flow Diagram (BFD), Process Flow Diagram (PFD), and Piping and Instrumentation Diagram (PID) are used to illustrate the process flow.

(v) Gantt Chart: A Gantt chart is a project management tool that uses horizontal bars to represent the duration of tasks or activities in a project.

(vi) Ethics & Professionalism: Ethics and professionalism are the practices that professionals in a particular field must adhere to. It includes the principles of honesty, transparency, fairness, and accountability.

(vii) Heuristics for Storage Vessels and Pressure Vessels: Heuristics for storage vessels and pressure vessels include choosing the correct diameter to height ratio, selecting the right material of construction, designing suitable supports, and selecting appropriate insulation.

(viii) Heuristics for Reactors and Heat Exchangers: Heuristics for reactors and heat exchangers include determining the appropriate size and shape, selecting the right material of construction, and designing suitable internals.

(ix) Heuristics of Distillation and Absorption Towers: Heuristics for distillation and absorption towers include choosing the correct column diameter, selecting appropriate packing materials, and designing suitable feed locations.

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Answer:

1) correct answer is ii  larger size

2) false, 3) false, 4) true, 5) true, 6) true

Explanation:

In this exercise, the answer is asked if the statement is true.

1) in the rapid cooling speed, there is no thermodynamic equilibrium, so the secondary phases do not have time to transform into the main one, therefore many phases appear in the products,

the correct answer is ii

2) False. The transformation of a material to the glass state requires a fixed temperature and rapid changes to reach this temperature,

3) False. The most stable state is the crystalline state, the glass states are metastable, their Gibbs energy is not the lowest possible and they must transition to the crystalline state over time, it can be years or centuries.

4) True. The melting and freezing temperatures change for each material, within the same material it always has the same value, since it corresponds to a change in the state of the system.

5) true. Cast iron is called gray because of the impurities inside that have not had time to move due to rapid cooling.

6) True. The microstructure is reduced in the process of cooling and heating