Answers
Hi there!
We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.
\(\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}\)
There is NO initial vertical velocity, so:
\(\large\boxed{\Delta d= \frac{1}{2}at^2}}\)
Rearrange to solve for time:
\(2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}\)
Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)
\(t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s\)
Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:
\(\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}\)
Related Questions
Which property of matter is conserved in chemical reactions and shown by balanced equations?
O mass
O volume
O density
O shape
Answers
Answer:
Mass.
Explanation:
I took the quiz and got the answer right
if p=2i+4j+3k and q=I+5j-2k,find P×q.
Answers
Answer:
\(p\times q=-23i+7j+6k\)
Explanation:
We are given that
p=2i+4j+3k
q=i+5j-2k
We have to find pxq
We know that
\(p\times q=\begin{vmatrix} i&j &k\\ 2&4 & 3\\ 1& 5 & -2\end{vmatrix}\)
\(p\times q=i(-8-15)-j(-4-3)+k(10-4)\)
\(p\times q=-23i+7j+6k\)
Hence,\(p\times q=-23i+7j+6k\)
Which function has a graph that intersects the y-axis at the point (0-4)?
Plz help por favor
Answers
Answer:
I believe B. The picture is not completely clear
Explanation:
What is the main purpose for learning about significant figures in science and/or technology courses? Give a detailed answer without plagiarism.
Answers
The significant figure of a value or measurement is the number of important digits that it contains
The main purpose for learning about significant figures in science and/or technology courses is precision of measurements.
In science and technology experiments and reseaches, we always want to ensure that measured values are as close to the true values as possible. This is because any deviation from the true value can invalidate the result of the experiment. Also, errors due to repeated approximations can have cummulative effects on the experimental results.
Therefore, the knowledge of significant figures is useful in science and technology to be able to record values of experimental measurements as close as possible to the actual value.
"Part B? Question
The total resistance in a circuit with two parallel resistors is 2 ohms and $R_1$ is 6 ohms. Using the equation for R₂, in terms of Rt and R₁, what is R₂ ?
R₂ is ohms."
Answers
The value of R₂, given that the total resistance in a circuit with two parallel resistor is 2 ohms, is 3 ohms
How do I determine the value of R₂?The formula to obtain the total resistance in a parallel connection for two resistors is given as folllow:
Rₜ = (R₁ × R₂) / (R₁ + R₂)
With the above formula, we can obtain the value of R₂. Details below:
Total resistance (Rₜ) = 2 ohmsResistor 1 (R₁) = 6 ohms Resistor 2 (R₂) = ?Rₜ = (R₁ × R₂) / (R₁ + R₂)
2 = (6 × R₂) / (6 + R₂)
2 = 6R₂ / (6 + R₂)
Cross multiply
2 × (6 + R₂) = 6R₂
Clear bracket
12 + 2R₂ = 6R₂
Collect like terms
12 = 6R₂ - 2R₂
12 = 4R₂
Divide both sides by 4
R₂ = 12 / 4
R₂ = 3 ohms
Thus, we can conclude that the value of R₂ is 3 ohms
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A car weighs 15,000 n and its tires are I flared to a pressure of 190 kPa. How large is the area of the cars tires that are in contact with the road
Answers
From pressure definition, the area of the car tires that are in contact with the road is 0.079 m
What is Pressure ?Pressure can be defined as the ratio of force to area. It is measured in Pascal.
Given that a car weighs 15,000 N and its tires are I flared to a pressure of 190 kPa. How large is the area of the cars tires that are in contact with the road ?
From the definition of Pressure, P = F/A
Where
P = 190 KPaF = 15,000 NA = ?190000 = 15000/A
A = 15000/190000
A = 0.079 m
A car will have 4 tires. The area of one in contact with the road will be
A = 0.079/4
A = 0.02 m
Therefore, the area of the car tire that is in contact with the road is 0.02 m
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In order to catch a ball, a baseball player moves their hand backwards in the direction of the balls motion. Doing this reduces the force of impact on the players hand because A momentum of impact is increasedB time of impact is reducedC velocity of the hand is reducedD time of impact has decreased
Answers
Using the impulse formula:
\(\begin{gathered} F\Delta t=m\Delta v \\ so: \\ \Delta t=\frac{m\Delta v}{F} \end{gathered}\)As we can see, the time is inversely proportional to the force, so increasing the time over which the ball's momentum is brought to 0 will decrease the force required to stop it.
Answer:
B. Time of impact is reduced
What is the frequency of a wave if its wavelength is 5 m and its speed is 20 m/s?.
Answers
Answer:
v=fy
Explanation:
v=fy
v= speed of light
f=frequency
y=wave lenght
make f subject of formula in this case
v=fy
f=v/y
f=20/5
f=4Hz
What I need help with is attached below
Answers
Answer:
Explanation:
3. answer is d.
Displacement increases b/c slopes of both lines are positive. Spring 1 displaces more than Spring 2 per unit force applied. Graphs are straight lines, so the increase is proportional.
4. Fnet = 5 - 30 - 5 = -30 N Positive direction is to the right, negative direction is to the left.
answer is d. 30 N to the LEFT
Could someone explain to me how to got the answer B, thank you very much
Answers
Answer:
since -6 lasted for 5 seconds, multiplying both would result in -30
3 lasted for 10 seconds, so multiplying both would give +30
average = ( 30 + (-30) ) / 2
30 -30 is already equal to zero, so the answer should be 0
At the start of an experiment, the potential energy of an object was 326 joules and its kinetic energy was 117 joules. At the end of the experiment, the potential energy of the object was 89 joules, and its kinetic energy was 331 joules. What conclusion can be drawn from this experiment?
The total energy of the system increased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.
The mechanical energy of the system increased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.
The mechanical energy of the system decreased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.
The total energy of the system decreased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.
Answers
he mechanical energy of the system decreased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.
Answer:
C. The mechanical energy of the system decreased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.
Explanation:
This answer is right because I just got done with the quick check and I got a 100%.
6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
Answers
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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Since the bullets also have zero velocity, a more exact description of the bullet's state would be _____.
Answers
Answer:
Static equilibrium.
Explanation:
Please help...
!!!!!!!
Answers
Answer:
1) C. The precise location of weather-related phenomena
2) C. It shows that the galaxies are moving farther away.
Explanation:
1) The global positioning system can be used in many ways, like in navigation, mapping and surveying the land. It is also used to observe the small changes taking place in the movement of objects on earth. They are usually used to study earthquakes.
2) When light from the galaxies is shifted towards the longer wavelengths, it is called red shift. When light shifts towards the shorter wavelengths, it is called blue shift. Big bang theory states how the primordial universe started expanding from a hot and dense singularity, in the process of evolution of the universe.
The universe is expanding always. Galaxies that are a part of the universe keep expanding and move farther away from each other. The galaxies that are very far off appear to move much faster than the nearby galaxies.
A long, thin rod is cut into two pieces, one being twice as long as the other. To the midpoint of piece A (the longer piece), piece B isattached perpendicularly, in order to form the inverted "T" shown in the drawing. The application of a net external torque causes thisobject to rotate about axis 1 with an angular acceleration of 1.8 rad/s2. When the same net external torque is used to cause the objectto rotate about axis 2, what is the angular acceleration?
Answers
Let x represent the original length of the rod.
From the information given,
angular acceleration, α1 = 1.8 rad/s^2
Since the rod is divided into A and B, then
A + B = x
A is twice the length of B. It means that
A = 2B
Thus,
2B + B = x
2B = x
B = x/3
A = x - x/3
A = 2x/3
Let M be the initial mass of the rod
Mass of A = 2M/3
Mass of B = M/3
The formula for calculating the moment of inertia of a thin rod with length x whose axis passes through the center and it is perpendicular to its length is
I = Mx^2/12
If the axis passes through one end,
I = Mx^2/3
Calculating moment about axis 1,
I1 = 0 + 1/3 * M/3 * (x/3)^2
I1 = Mx^2/81
Calculating moment about axis 2,
I2 = 1/12 * 2M/3 * (2x/3)^2 + 0
I2 = 8Mx^2/324
In both cases, the external applied torques are equal. This,
I1α1 = I2α2
α2 = I1α1/I2
By substituting the given values,
α2 = (Mx^2/81 * 1.8)/(8Mx^2/324)
α2 = Mx^2/81 * 1.8 * 324/8Mx^2
α2 = 0.9 rad/s^2
the angular acceleration = 0.9 rad/s^2
3. Most horoscopes are off by two astrological signs due to the past 2000 years of the Earth's wobble.
Answers
What is the force between two balloons with a negative charge of 1.6 ✕ 10 to power of -10 C if the balloons are 7.6 cm apart?
Answers
Answer: 4.0·10^-8 N
Explanation: both forces are negative so force is repulsive
F = k q1·q2 /r². K = Coulomb's constant 9·10^ 9 Nm²/C².
Both Charges are -1.6·10^-10 C and r= 0.076 m
URGENT 50 POINTS
Show all Steps of your work.
7. Mohammed whose mass is 50kg swings back and forth on a long vine makes an angle 45 from the vertical resting position. His friend Abdella notices in amazement that he makes 30 complete swings in 2.0 minuies.
(a) What is the frequency (in hertz) of Tarzan's swing?
(b) What is the period of oscillation?
(c) How long is the vine he is using?
(d) Calculate the Restoring force on Mohammed?
Answers
The frequency of oscillation of the swing is 0.25 Hz.
The time period of oscillation of the swing is 4 s.
The length of the vine of the swing is 3.97 m.
The restoring force acting on Mohammed is 692.9 N.
Mass of Mohammed, m = 50 kg
Angle made by the vine with the vertical, θ = 45°
Number of complete swings made by Mohammed, n = 30
Time taken for this swing, t = 2 minutes = 120 seconds
a) The frequency of the swing is defined as the number of complete oscillations in one second.
So, the frequency of oscillation of the swing is,
f = n/t
f = 30/120
f = 0.25 Hz
b) The time period of oscillation of the swing is,
T = 1/f
T = 1/0.25
T = 4 s
c) The expression for the time period is given by,
T = 2π√(l/g)
T² = 4π² x (l/g)
l/g = T²/4π²
Therefore, the length of the vine of the swing is,
l = T²g/4π²
l = 4² x 9.8/4 x (3.14)²
l = 3.97 m
d) The restoring force acting on Mohammed,
F = mg sinθ
F = 50 x 9.8 x sin 45°
F = 490 x 1/√2 = 490/1.414
F = 692.9 N
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The softest sound a human ear can hear is at 0 dB (Io = 10-12 W/m2). Sounds above 130 dB cause pain. A particular student's eardrum has an area of A = 51 mm2. What is the most power, in watts, the ear can receive before the listener feels pain?
Im so confused on how to even start with this problem, my main question is how sound and power are related.
Answers
Answer:
Sound and power are related through intensity, which is the amount of power per unit area. The intensity of a sound wave is proportional to the square of its amplitude, which is a measure of how far the wave oscillates from its equilibrium position.
To solve this problem, you can use the formula for sound intensity:
I = P/A
where I is the intensity of the sound wave in watts per square meter (W/m^2), P is the power of the sound wave in watts (W), and A is the area of the eardrum in square meters (m^2).
You are given that the softest sound a human ear can hear is 0 dB, which corresponds to an intensity of 10^-12 W/m^2. You are also given that sounds above 130 dB cause pain. To find the maximum power the ear can receive before the listener feels pain, you can rearrange the formula for intensity to solve for power:
P = AI
where A is the area of the eardrum in square meters.
Substituting the given values, you get:
P = (51 x 10^-6 m^2)(10^-12 W/m^2 x 10^(130/10))
Simplifying this expression, you get:
P = 1.8 x 10^-3 W
Therefore, the most power the ear can receive before the listener feels pain is 1.8 x 10^-3 watts.
1. What is the total distance traveled?
A 3.0m
B 4.0m
C 5.0m
D 6.0m
Answers
Answer:
c
Explanation:
The force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your school would be exactly twice as much if your school: a Had twice as much mass b Was twice as tall c Had twice as much volume d Covered twice as much area
Answers
Answer: a Had twice as much mass
Explanation:
The data that we have is:
"The force of gravity pulls down on your school with a total force of 400,000 newtons. "
First, remember that, by the second Newton's law that:
F = a*m
F = force
a = acceleration
m = mass
In the case of the gravitational force, the gravitational acceleration is a constant: a = 9.8m/s^2
Then, if we want to have twice as much force the only thing that we can change in the equation is the mass:
Then if the initial force is written as:
F = a*m
twice as much that force is written as:
2*F = a*x
x is a variable that represents the new mass.
We know that F = a*m
2*F = 2*a*m
2*a*m = a*x
2*m = x
Then, if we want to have twice as much force, we should have twice as much mass.
Which of the following statements is not true of vibrations
Answers
Answer:
Forced vibrations, such as those between a tuning fork and a large cabinet surface, resulting in a much lower sound than was produced by the original vibrating body.
Explanation:
Just took the test, this is correct. :)
If the mass m of the wrecking ball is 3920 kg , what is the tension TB in the cable that makes an angle of 40 ∘ with the vertical? What is the tension TA in the horizontal cable?
Answers
The tension TB in the cable makes an angle of 40 ∘ and the tension TA in the horizontal cable
TB=49380.9NTA=31741.4NThis is further explained below.
What is tension?Generally, To represent tension in a vertical direction, the term is:
\(T_B=\frac{m g}{\cos \theta}\)
Substitute $3860kg for m, 9.8m/s^2 for g, and 40^0 for \(\theta\).
\(T_B &=\frac{(3860 \mathrm{~kg})\left(9.8 \mathrm{~m} / \mathrm{s}^2\right)}{\cos 40^{\circ}} \\\)
=49380.9N
Because the cosine of the tension in the cable, which is pushing up on the item, is equal to the weight force, which is pressing down on the ground, the ball is not moving and is thus in equilibrium.
The expression for the horizontal cable tension is,
\(T_A=T_B \sin \theta\)
Substitute $49380.9N for T_B and $40^o for \(\theta\)
\(T_A &=(49380.9 \mathrm{~N}) \sin 40^{\circ}\)
=31741.4N
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Digestion and breathing are _____.
controlled by ganglia and plexus
reflexive actions controlled by the spinal cord
voluntary actions
controlled by the central nervous system
Answers
Answer:
hehehe
Explanation:
The speed of light in a vacuum is 300,000,000 m/s. How long does it take light to travel 1.5 x 108 km (which happens to be the distance from the sun to Earth)?
Answers
The speed of light is 3 × 10⁸ m/s. Light will take a time of 500 seconds to travel a distance of 1.5 × 10¹¹ m.
What is speed of light ?Speed is a physical quantity used to measure the distance travelled by an object per unit time. It is usually expressed in the unit m/s. Light is the fastest thing in the universe to be known.
The speed of light is the product of its frequency and wavelength. In general the ratio of the distance covered per time taken.
Speed of light = 3 × 10⁸ m/s
distance from earth to sun = 1.5 × 10⁸km = 1.5 × 10¹¹ m
Now, the time taken by light to travel this distance is :
time = distance/speed.
t = 1.5 × 10¹¹ m / 3 × 10⁸ m/s = 500 seconds.
Therefore, the time taken by light from sun to reach earth surface is approximately 500 s.
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Data:
Depth Velocity Wavelength
(meters) (km/h) (km)
7000 943 282
4000 713 213
2000 504 151
200 159 48
50 79 23
10 36 10.6
Predict the tsunami speed for the following ocean depths:
a. 8000 meters __________________________
b. 3500 meters ___________________________
c. 70 meters _____________________________
d. 5 meters _______________________________
Answers
a. The speed of the tsunami at ocean depth of 8000 m is 1,019.66 km/h.
b. The speed of the tsunami at ocean depth of 3500 m is 660.75 km/h.
c. The speed of the tsunami at ocean depth of 70 m is 89.66 km/h.
d. The speed of the tsunami at ocean depth of 5 m is 30.625 km/h.
Speed of the tsunami at the given depths
The speed of the tsunami is calculated from method of extrapolation or interpolation as shown below;
Speed at 8000 meters8000 m -------- ?
7000 m -------- 943 km/h
4000 m -------- 713 km/h
(8000 - 7000)/(7000 - 4000) = (? - 943)/(943 - 713)
0.3333 = (? - 943)/230
230(0.3333) = ? - 943
76.66 = ? - 943
? = 1,019.66 km/h
Speed at 3500 m4000 m ---------- 713 km/h
3500 m ---------- ?
2000 m ----------- 504 km/h
(4000 - 3500)/(4000 - 2000) = (713 - ?) / (713 - 504)
0.25 = (713 - ?) /209
0.25(209) = 713 - ?
52.25 = 713 - ?
? = 660.75 km/h
Speed at 70 m200 m ------ 159 km/h
70 m --------- ?
50 m ------- 79 km/h
(200 - 70)/(200 - 50) = (159 - ?)/(159 - 79)
0.8667 = 159 - ? / 80
80(0.8667) = 159 - ?
69.336 = 159 - ?
? = 89.66 km/h
Speed at 5 meters50 m ------- 79 km/h
10 m --------- 36 km/h
5 m ---------- ?
(50 - 5)/(50 - 10) = (79 - ?)/(79 - 36)
1.125 = 79 - ?/43
43(1.125) = 79 - ?
48.375 = 79 - ?
? = 30.625 km/h
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A toy car is given an initial velocity of 5.0 m/s and experiences a constant
acceleration of 2.0 m/s/s. What is the final velocity after 6.0 s?
Answers
The final velocity after 6.0 s is
1304.2 .
What is velocity?
velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.
Solution -
As per the given-
Mass of runner m = 74kg
initial velocity of runner u=4.8 m/s
final velocity of runner v =0
Coefficient of friction ¥=0.7
Let's d be the distance moved by runner till the stop.
a- mechanical energy lost due to friction
As friction does negetive work causing the runner to stop.
As we know,
Mechanical energy lost= Kinetic energy of runner
Mechanical energy lost =
1/2 mv^2 = 1/2 ×74×4.8^2=852.2
Distance move by runner-
Work done by friction = mechanical energy lost
-¥×mg×d =852.2 j
-0.7×74×9.8×d = -491.2
Solving the equation we get
1304.2.
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A pendulum of mass 12 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 19 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that: g = 9.8 m/s²)
20 m
A35
B186
C78
D112
Answers
The energy lost to friction and air resistance is 186 J.
option B.
What is the energy lost to friction and air resistance?The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.
The initial potential energy of the pendulum at the initial position is calculated as;
PEi = mghi
where;
m is the massg is gravityh is the initial heightP.Ei = 12 kg x 9.8 m/s² x 20 m
P.Ei = 2,352 J
The final kinetic energy of the pendulum is calculated as follows;
K.Ef = 0.5 x 12 kg x (19 m/s)²
K.Ef = 2,166 J
ΔE = 2,166 J - 2,352 J
ΔE = -186 J
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In a car crash, how are force, mass, acceleration, and velocity related?
Answers
Answer:
the answer is simple but click on the brainiest and thank me.
Explanation:
F=force, m=mass, a=acceleration, v=velocity
v=displcement/time
a= v/t
F= m×a
F= m× (v/t)
Change of state due to cooling is due to
Answers
Change of state due to cooling is due to the removal of thermal energy from a substance. A substance changes states, such as from a gas to a liquid or from a liquid to a solid, when its particles lose kinetic energy as it loses heat and moves more slowly. Eventually, the particles reorganize into a more ordered form with less energy. The term "solidification" or "freezing" refers to this process.