A 73-kg base runner begins his slide into second base when he is moving at a speed of 4.7 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.
(a) How much mechanical energy is lost due to friction acting on the runner? J
(b) How far does he slide? m

Answer:

I think the answer is B. amount of energy present but I'm not 100% sure

Explanation:

Answer:

The tractor applies 1,748.418 N to the plow.

Explanation:

Net Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn=m.a

If the acceleration is zero, then the net force is also zero. That means all forces acting on the mass are balanced.

The tractor drags the m=313 Kg plow at a constant speed, thus the acceleration is zero and so is the net force.

The horizontal forces acting on the plow are:

Since both forces are balanced, then:

Ft=Fr

The friction force is calculated as:

\(Fr=\mu \cdot N\)

Where \(\mu\) is the coefficient of friction between the plow and the ground and N is the normal force. In the situation described, the normal force is equal to the weight of the plow:

\(N=W=m.g=313*9.8=3,067.4\)

The normal force is N=3,067.4 N

The friction force is now calculated:

\(Fr=0.579 \cdot 3,067.4\ N\)

\(Fr=1,748.418\ N\)

Thus, the tractor applies 1,748.418 N to the plow.

The wave's frequency, f=0.5Hz or 1/s, should be regarded as the waves with a wavelength = 200 cm.

Wavelength is the separation between corresponding points (adjacent crests) in successive cycles of a waveform signal traveling through space or over a wire. In wireless systems, the length is typically expressed in meters (m), centimeters (cm), or millimeters (mm).

Since the wavelength is 200 cm or 2m

Also we know that

frequency is reciprocal of wavelength

So,

f=1/2

f=0.5Hz

The wavelength is a crucial characteristic since it governs the nature of the light. Green light spectrum that is distinct from both of them, while red light has a wavelength that is distinct from both blue and green light.

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The most prevalent kind of star in the cosmos and one with a lengthy lifespan are low-mass red giant stars, also referred to as "M-dwarfs."

These stars can blaze more steadily and slowly over billions of years because they are cooler and less powerful than our sun.

This lengthy lifespan is significant because it offers planetary systems a secure setting in which to grow and possibly support life. M-dwarfs are home to a large number of exoplanets, some of which are situated in the star's habitable zone, where liquid water might occur.

Because of this, low-mass red giant stars are essential to our comprehension of the genesis and possibility of life in the cosmos.

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Answer:

0.613 milliseconds

Explanation:

When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, the magnetic induction (B) is increased.

Therefore, the correct answer is:

(a) There is a large increase in the magnetic induction (B)

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The carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.

The term nuclear fusion refers to a kind of reaction in which two nuclei fuse together to give rise to a single nuclei with the evolution of energy.

We can see that the carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.

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Answer:

A. Nuclear fusion

Explanation:

got it right, trust

Answer:19.51%

Explanation:

Gauge pressure is the pressure measured relative to atmospheric pressure. A commonly used instrument for measuring gauge pressure is the pressure gauge.

A pressure gauge typically consists of a circular dial with a pointer, a pressure sensing element, and a scale. The sensing element, which is usually a diaphragm or a Bourdon tube, is connected to the system or container whose pressure is being measured.

The pressure gauge is usually connected to the system or container through an inlet port. When the pressure in the system or container changes, it exerts a force on the sensing element of the pressure gauge. This force causes the sensing element to deform, which in turn moves the pointer on the dial. The position of the pointer on the pressure scale indicates the gauge pressure.

The pressure scale on the dial is calibrated in units such as psi (pounds per square inch), bar, or kPa (kilopascals), depending on the application and region. The scale allows the user to directly read the gauge pressure value.

It's important to note that the pressure gauge measures the difference between the pressure being measured and the atmospheric pressure. If the system or container is under vacuum (pressure lower than atmospheric pressure), the gauge will indicate negative values.

Pressure gauges are widely used in various industries and applications where monitoring and control of pressure is essential, such as in industrial processes, HVAC systems, pneumatic systems, and hydraulic systems.

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During the phase transition from liquid to gas, the temperature of the object remains constant despite continuous heating. The energy supplied to the object is used to break the intermolecular forces holding the liquid molecules together rather than increasing the temperature.

During the phase transition from liquid to gas, the temperature of the object remains constant at the boiling point of the substance. This phenomenon is known as the latent heat of vaporization. As heat is supplied to the liquid, the energy is used to break the intermolecular forces between the molecules, allowing them to overcome the attractive forces and transition into the gas phase.

While the energy is being absorbed by the liquid to undergo the phase transition, the temperature does not increase. Instead, it remains constant until the entire substance has transitioned to the gas phase. This is because the energy supplied is utilized in the process of changing the state of the substance rather than increasing the kinetic energy of the individual molecules, which would result in a temperature increase.

Once the phase transition is complete, any additional energy supplied will result in an increase in temperature as the gas molecules gain kinetic energy. Thus, the phase transition from liquid to gas involves a constant temperature and a transfer of energy to break intermolecular forces rather than a change in the object's temperature.

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Answer:

15,000

Explanation:

Answer:

Autocracy

Explanation:

Answer:

Approximately \(2.69\; {\rm A}\).

Explanation:

Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:

\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).

Electric current \(I\) is the rate of flow of electric charge.

In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:

\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).

The container has a rectangular shape with dimensions 1 meter by 1 meter, the area of the bottom is 1 square meter. Dividing the weight of the water by the area of the container gives us a pressure of approximately 1,372 Pascal (Pa) or 0.0137 bar.

Explanation:

The pressure at the bottom of the water layer is determined by the weight of the water above it. The weight of the water is equal to the density of water (1000 kg/m³) multiplied by the volume of water (140 cm or 1.4 m) and the acceleration due to gravity (9.8 m/s²). This gives us a weight of approximately 1,372 kg.

Since the oil layer is floating on top of the water, it does not contribute to the pressure at the bottom of the water layer. Therefore, the pressure at the bottom of the water layer is simply the weight of the water divided by the area of the bottom of the container holding the water.

Assuming the container has a rectangular shape with dimensions 1 meter by 1 meter, the area of the bottom is 1 square meter. Dividing the weight of the water by the area of the container gives us a pressure of approximately 1,372 Pascal (Pa) or 0.0137 bar.

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Answer:

1 and 2>3 and 4=4 and 5 that is the answer

A girl rides her cycle round a circular track of diameter 60 m. The track is banked at 15° to the horizontal. The coefficient of friction between the track and the tyres of the cycle is 0.25. Modelling the girl and her cycle as a particle of mass 60 kg moving in a horizontal circle, the minimum speed at which she can travel without slipping is 13.64 m/s.

To find the minimum speed at which the girl can travel without slipping, we need to consider the forces acting on her and her cycle as they move in a circular track.

The forces acting on the girl and her cycle are the gravitational force (mg), the normal force (N), and the frictional force (f). The frictional force provides the centripetal force necessary to keep the girl moving in a circular path.

The normal force can be resolved into two components: the vertical component (N⊥) and the horizontal component (N∥). The vertical component balances the gravitational force, while the horizontal component provides the centripetal force.

Mass of the girl and cycle (m) = 60 kg

Diameter of the circular track (d) = 60 m

Bank angle (θ) = 15 degrees

Coefficient of friction (μ) = 0.25

Find the normal force components:

N⊥ = mg cos(θ)

N∥ = mg sin(θ)

The frictional force:

f = μN⊥

The frictional force (f) provides the centripetal force required for circular motion:

f = m(v² / r)

Here, v is the velocity and r is the radius of the circular track. The radius is:

r = d / 2

Combining the equations, we have:

μN⊥ = m(v² / r)

Substituting the values we have:

μmg cos(θ) = m(v² / (d / 2))

v² = (μmg cos(θ) / m) * (d / 2)

v² = (μg cos(θ)) * (d / 2)

v = √((μg cos(θ)) * (d / 2))

v = √((0.25 * 9.8 * cos(15)) * (60 / 2))

v ≈ 13.64 m/s

Therefore, the minimum speed at which the girl can travel without slipping is approximately 13.64 m/s.

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A change in temperature frequently causes substances to change phases. Most substances are solid at low temperatures; as the temperature rises, they become liquid; and at still greater temperatures, they become gaseous.

Melting is the conversion of a solid into a liquid (an older term that you may see sometimes is fusion). Solidification is the process where a liquid turns into a solid. The melting point, or the temperature at which a pure substance begins to melt, is a property of that substance. A solid must expend energy to become a liquid. A specific quantity of energy is required by every pure substance in order to transform from a solid to a liquid. This amount is known as the substance's enthalpy of fusion (or heat of fusion).

The complete question is- The diagram shows how states of matter can change when energy is either added or removed.

System before change

System after change

00000

00000

00000

00000

00000

00000

00000

All of these statements below are true EXCEPT

Energy was added to the matter causing the particle movement to increase.

The matter changed states which is a physical change.

The particles in the matter before the change had more energy than after the change.

The particles in the matter before the change had less energy than after the change.

the diagram is attached below.

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The distance between slits on a diffraction grating is 0.60 mm: The path difference for the second-order bright band is 0.12 mm.

In a diffraction grating, when light passes through the slits, it diffracts and creates interference patterns. The path difference is the difference in the distance traveled by light from two adjacent slits to a specific point on the screen.

To calculate the path difference, we can use the formula:

Path Difference = d * sin(θ)

where d is the distance between slits (also known as the slit spacing) and θ is the angle of diffraction.

In this case, the distance between slits is given as 0.60 mm, and the angle of diffraction is 0.30°. Since it is mentioned that the light forms a second-order bright band, we need to consider the path difference corresponding to the second-order interference.

Using the formula, we can calculate the path difference as follows:

Path Difference = (0.60 mm) * sin(0.30°)

Calculating the value, we find:

Path Difference = 0.60 mm * 0.0052359 ≈ 0.0031416 mm ≈ 0.12 mm

Therefore, the path difference for the second-order bright band is approximately 0.12 mm.

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Answer:

The frequency at which the string will create a standing wave be  with three loops is 8.6 Hz

Explanation:

The speed of the of the wave, v = 12.9 m/s

The number of loops of the standing wave = 3 loops

The length of the string = 2.00 m

Given that one loo = half of the wavelength, we have;

Three loops = 3 × half = One and half wavelength  = 1.5·λ

The frequency of a wave = f = v/λ

Therefore, we have;

The frequency, f = 12.9/1.5 = 8.6 Hz

The frequency at which the string will create a standing wave be  with three loops = 8.6 Hz.

Answer:

9.675

Explanation:

got it right on acellus

The mathematical relationship exists between the wave speed and the density of the medium is that the density of the medium is inversely proportional to the wave speed.

The amount of space a wave covers in a certain amount of time, such as the number of meters it covers in a second, is known as its wave speed. The following equation relates wave speed to both wave frequency and wavelength: Wavelength x Frequency = Speed.

Since sound is a mechanical wave, it moves through a medium by being compressed and rarefied. In an elastic medium, its velocity is proportional to the square root of the tension present. More elasticity in the medium results from higher density, which also increases the ease with which compression and rarefaction can occur. In this manner, the density increases while the sound velocity increases.

As a result, the square root of the medium's density and the velocity of sound in that medium are inversely related.

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The equation of motion for the given system, considering the damping force and the external force, can be determined using Newton's second law.

The equation of motion for the system can be expressed as:

\(m * a + c * v + k * x = f(t)\)

Where:

Using Newton's second law (F = ma), we can rewrite the equation as:

\(10 * (d^2x/dt^2) + 90 * (dx/dt) + 140 * x = 5 * sin(t)\)

This is the equation of motion that describes the behavior of the system, taking into account the mass, damping force, spring constant, and the applied external force.

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Oculomotor depth cues are ineffective beyond 2 meters in judging the relative distances of objects in the visual field.

Oculomotor profundity signs allude to the actual changes made by the muscles that control eye developments while zeroing in on objects at various distances. These changes give the mind data about the general distances of articles in the visual field. Nonetheless, oculomotor profundity prompts are simply compelling up to a specific distance.

Studies have shown that oculomotor profundity signs become ineffectual for distances past 2 meters. Past this point, other profundity signals like binocular uniqueness, movement parallax, and viewpoint become more significant in deciding the overall distances of articles in the visual field.

Hence, assuming an item is found multiple meters away, depending exclusively on oculomotor profundity signs to pass judgment on its distance would be questionable.

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The work done on a 50 Kg student by the elevator in 2 seconds if the elevator is accelerating upwards from rest at a rate of 2 ms⁻² would be

The total amount of energy transferred when a force is applied to move an object through some distance.

The work done is the multiplication of applied force with displacement.

Work Done = Force × Displacement

As given in the problem we have to find the work done  on a 50 Kg student by the elevator in 2 seconds if the elevator is  accelerating upwards from rest at a rate of 2 ms⁻²,

Lets us first calculate the displacement of the elevator in 2 seconds if it is accelerating upwards from rest at a rate of 2 ms⁻².

s = ut + 0.5at²

  = 0 + 0.5×2×2²

  = 4 meters

The work done on the elevator = mgh

                                                    =50×9.81×4

                                                    =1962 joules

Thus, the work done on the elevator would be 1962 joules.

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The measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

Option C.

The median is the middle point in a dataset—half of the data points are smaller than the median and half of the data points are larger.

To find the median: Arrange the data points from smallest to largest. If the number of data points is odd, the median is the middle data point in the list.

So from the given data of the 100 meter dash, the measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

The median will help to separate half of the data points that are smaller than the cutoff time and half of the data points are larger than the cutoff time.

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We can see other people because they reflect visible light.

When light hits an object, some wavelengths are absorbed and some are reflected. The wavelengths that are reflected are what we see as color. In the case of people, the visible light that hits their skin is reflected back to our eyes, allowing us to see them.

People do also emit some infrared radiation, but this is not what allows us to see them. Instead, infrared radiation is used in thermal imaging, which can detect differences in temperature between objects.

We can see other people because they reflect visible light. Visible light is a part of the electromagnetic spectrum that our eyes can detect. When a light source, such as the sun or an artificial light, illuminates an object like a person, the object reflects some of this visible light. Our eyes then perceive this reflected light, and our brain processes the information to form an image of the person. In contrast, thermal radiation and infrared light are not visible to the human eye, so they don't contribute to our ability to see other people.

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a) The speed of the pendulum at the lowest point is approximately 6.26 m/s.

b)The maximum angle of the swing assuming negligible air resistance is determined by the height attained by the pendulum, which is 2 meters.

a) To determine the speed of the pendulum at the lowest point, we can use the conservation of mechanical energy. At the lowest point, the pendulum has maximum kinetic energy and minimum potential energy. The total mechanical energy, E, is given by the sum of kinetic and potential energy:

E = KE + PE

At the lowest point, all potential energy is converted into kinetic energy, so:

E = KE

The potential energy at the highest point is given by:

PE = mgh

Where m is the mass (1.5 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height (2.0 m).

PE = (1.5 kg)(9.8 m/s^2)(2.0 m) = 29.4 J

Since E = KE, the kinetic energy at the lowest point is also 29.4 J.

The kinetic energy is given by:

\(KE = (1/2)mv^2\)

Where v is the velocity (speed) of the pendulum at the lowest point.

\(29.4 J = (1/2)(1.5 kg)v^2\)

\(v^2 = (2)(29.4 J) / (1.5 kg)\)

\(v^2 = 39.2 m^2/s^2\)

v = √(39.2) ≈ 6.26 m/s

b) The maximum angle of the swing can be determined using the conservation of mechanical energy. When neglecting air resistance, the total mechanical energy remains constant throughout the swing. At the highest point, the pendulum momentarily comes to a stop, so its kinetic energy is zero. Therefore, the total mechanical energy is equal to the potential energy at the highest point.

E = PE

PE = mgh

Where m is the mass (1.5 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the maximum height attained by the pendulum.

PE = (1.5 kg)(9.8 m/s^2)(h) = 14.7h J

Since E = PE, the total mechanical energy is also 14.7h J.

At the lowest point, all the potential energy is converted into kinetic energy, so:

\(KE = (1/2)mv^2\)

\(KE = (1/2)(1.5 kg)(6.26 m/s)^2 = 29.4 J\)

Since the total mechanical energy remains constant:

29.4 J = 14.7h J

h = 2 meters

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The potential difference across the 2 Ω resistor is 2 V.

The potential difference across the 2 Ω resistor is equal to the current flowing through it multiplied by the resistance of the resistor. The current flowing through the circuit is 1 A, and the resistance of the 2 Ω resistor is 2 Ω.

Therefore, the potential difference across the 2 Ω resistor is:

= 1 A * 2 Ω = 2 V.

V = I * R

V = 1 A * 2 Ω

V = 2 V

Therefore, the potential difference across the 2 Ω resistor is 2 V.

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In the absence of any horizontal forces, the puck will move horizontally with a constant velocity.

When neglecting air resistance, what horizontal forces should Jadon tell Sylvia act on the puck once the string breaks-Jadon should tell Sylvia that there are no horizontal forces that will act on the puck once the string breaks. This is because there are no forces acting horizontally on the puck initially.There are two types of forces, i.e., Contact and Non-contact forces. The contact force is the force that is caused by the contact of two objects, and non-contact force is the force that exists between two objects, even without contact between them.There are four types of non-contact forces, namely gravitational force, electromagnetic force, weak nuclear force, and strong nuclear force. In the case of a puck, the only force that acts upon it is gravitational force.However, the gravitational force acts vertically and not horizontally. The horizontal force comes into play only when there is any force acting upon the puck.The force with which a puck hits the ground will depend on the speed at which it is dropped, the distance over which it falls, and the acceleration due to gravity. If a puck is dropped from a height, it will fall down, and the only force acting upon it will be gravity. Once it hits the ground, the force will be applied vertically upward, causing the puck to rebound.

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The acceleration of the object is 2.0 m/s². This means that for every second the object is in motion, its velocity will increase by 2.0 meters per second.

The given information is the net force (N) = 5.0 and the mass (kg) = 2.5. We need to determine the acceleration.


Acceleration is the rate at which an object's velocity changes over time.

It is directly proportional to the net force applied to the object and inversely proportional to its mass.

The formula to calculate acceleration is:

Acceleration = Net Force / Mass

Now, let's substitute the given values into the formula:

Acceleration = 5.0 N / 2.5 kg

Simplifying the equation:

Acceleration = 2.0 m/s²

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