a 7.0 μf capacitor is connected in series with a 5.0 kω resistor across a 20-v dc source and an open switch. if the switch is closed at t = 0 s, what is the charge on the capacitor at t = 9 ms

Answers

Answer 1

The charge on the capacitor at t = 9 ms is approximately 31.8 μC. To find the charge on the 7.0 μF capacitor at t = 9 ms when connected in series with a 5.0 kΩ resistor and a 20-V DC source,

We will use the formula for the charge on a charging capacitor in an RC circuit:

Q(t) = Q_max * (1 - e^(-t/RC))

where Q(t) is the charge at time t, Q_max is the maximum charge on the capacitor, R is the resistance (5.0 kΩ), C is the capacitance (7.0 μF), and t is the time (9 ms).

First, calculate Q_max: Q_max = C * V = 7.0 μF * 20 V = 140 μC.
Next, calculate RC: RC = 5.0 kΩ * 7.0 μF = 35 ms.
Finally, calculate Q(9 ms): Q(9 ms) = 140 μC * (1 - e^(-9 ms / 35 ms)) ≈ 31.8 μC.

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Answer 2

To solve this problem, we can use the formula Q = CV, where Q is the charge on the capacitor, C is the capacitance, and V is the voltage across the capacitor.

Initially, when the switch is open, there is no current flowing through the circuit and the voltage across the capacitor is zero. Therefore, the charge on the capacitor is also zero.

When the switch is closed at t = 0 s, the capacitor starts to charge up through the resistor. The voltage across the capacitor increases gradually and the current flowing through the circuit decreases exponentially with time.

The total resistance in the circuit is the sum of the resistance of the resistor and the capacitive reactance of the capacitor, which is given by Xc = 1/(2πfC), where f is the frequency of the source (which is DC in this case). Using the given values, we get:

Xc = 1/(2π*20*10^6*7.0*10^-6) ≈ 1.1 kΩ

Therefore, the total resistance in the circuit is Rtot = R + Xc = 5.0 kΩ + 1.1 kΩ = 6.1 kΩ

Using Ohm's law, we can calculate the current flowing through the circuit at t = 9 ms:

I = V/Rtot = 20/6100 ≈ 3.28 mA

The charge on the capacitor at t = 9 ms is then given by:

Q = CV = 7.0*10^-6 * 3.28*10^-3 ≈ 22.9 μC

Therefore, the charge on the capacitor at t = 9 ms is approximately 22.9 microcoulombs.

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Related Questions

3. Calculate What is the kinetic energy of a 2,000 kg bus that is moving at 25 m/s?
Show your work.

Answers

Answer:

625000 J

Explanation:

KE = mv^2/2

= (2000kg*(25m/s^2))/2

= 625000 J

What do we call the energy that is transferred to
a substance without the substance's temperature
changing?

Answers

Answer:

Latent heat

Latent heat is the heat needed to change a state without a change in temperature.

Explanation:

Hope this helps :D

In a physics lab, students take a long piece of string and cut it into two unequal pieces. One piece is used to suspend a large weight. The second piece is tied to the bottom of the weight as seen in the diagram below. Student 1 predicts that the upper string will always break first since it has to support the weight and the applied force, while Student 2 disagrees and predicts that the shorter piece of string will always break first if you pull slowly but with enough force to exceed the strength of the string.

(a) Which aspect(s) of Student 1’s reasoning, if any, are correct? Explain your answer.


(b) Which aspect(s) of Student 2’s reasoning, if any, are correct? Explain your answer.


(c) Which aspect(s) of both Student 1’s and 2’s reasoning, if any, are incorrect? Explain your answer.

(d) The experiment is performed and both students are surprised to learn that whether
the upper or lower string breaks first depends on whether you pull slowly or with a
sudden pull. Resolve the two lines of reasoning of Student 1 and Student 2 by
explaining the results of the experiment in a clear, concise paragraph.

Answers

Answer:

(a) The aspect of the upper string supporting the weight and the applied force

Student 1 is correct because the upper string is the source of support of the large weight and the force applied to the short string reacts at the support of the long string

(b) The aspect of Student's (2) reasoning that is correct is that the shorter piece of string will always break first, however, the statement is only true for sudden pull due to the increased force experienced by the shorter string from a more rapid change in momentum

(c) The aspect of Student 1's statement that is incorrect is the that the upper string will always break first

The aspect of Student 2's statement that is incorrect is the that the shorter piece of string will always break first

(d) A string will break when subject to a force equivalent to its breaking force. The force experienced by the string increases as the rate of pull (suddenness) increases and the suddenness increases inversely with the length of the string, as such the shorter lower string will break first from a sudden pull before the force of the pull is completely transmitted to the upper string. Whereby the lower string is slowly pulled, the force is evenly transmitted to the upper string which is then taking up the load of the weight and the applied force together and is likely to break first

Explanation:

What does resistance refer to in a circuit?

Answers

Answer:

Resistance is a measure of the opposite to current flow in an electrical circuit. Resistance is measured in ohms.

Hope this helps

Using a mass of 1. 8 g and the volume displaced by the sample, calculate the sample's density. Question 17 options: 0. 17 g/mL 0. 35 g/mL 0. 60 g/mL 0. 78 g/mL.

Answers

The sample's density with respect to the volume it displaces is equal to: C. 0. 60 g/mL

Given the following data:

Mass = 1.8 gramsInitial volume = 20 mLFinal volume = 23 mL

To calculate the sample's density:

First of all, we would determine the volume displaced by the sample;

\(Volume \;displaced = 23-20\)

Volume displaced = 3 mL

Density can be defined as mass all over the volume of an object. Thus, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

\(Density = \frac{Mass}{Volume}\)

Substituting the given parameters into the formula, we have;

\(Density = \frac{1.8}{3}\)

Density = 0.60 g/mL

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Using a mass of 1. 8 g and the volume displaced by the sample, calculate the sample's density. Question

Help me please 80 points!
Differentiate the three mechanisms by which thermal energy is transferred through the Earth's systems: radiation,
conduction and convection.

Answers

Conduction convection and radiation

An eleven quart container of ice cream is to be made in the form of a cube. calculate the length of a side of the cube. 1 gallon = 3.786 liters. answer in units of cm.

Answers

The length of a side of the cube is 21.83 cm.

We need to know about cube volume to solve this problem. Cube volume can be calculated by multiplying the length of the cube. It can be written as

V = L³

where V is cube volume and L is cube length.

From the question above, we know that

V = 11 quart = 2.75 gallon

1 gallon = 3.786 liters

Convert volume to liters

V = 2.75 gallon

V = 2.75 x 3.786 liters

V = 10.41 liters

V = 10.41 dm³

Find the length

V = L³

10.41 = L³

L = ³√10.41

L = 2.18 dm

Convert length to cm

L = 2.183 dm

L = 21.83 cm

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7.) A neutral atom loses two electrons. Which of the following ions might result? HELP ME ASAP!!!

7.) A neutral atom loses two electrons. Which of the following ions might result? HELP ME ASAP!!!

Answers

Answer:

A. Mg+2

Explanation:

im not sure, but since it lost two electrons which have a negative charge it gained two charge.

An electron has a charge of - 1.6x10 ^ - 19 C and a proton has a charge of 1.6x 10 ^ - 19 C . In a hydrogen atom, the distance between them is 5.3x 10 ^ - 11m Determine the electrostatic force between them.

Answers

Answer:, , 8.2 . 10^-6, ATTRACTIVE

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law

A bike accelerates from 0.0 m/s to 4.0 m/s in

4 s. What distance does it travel?

Answers

Answer:

d = 8 m

Explanation:

Given that,

Initial speed, u = 0

Final speed, v = 4 m/s

Time, t = 4 s

We need to find the distance traveled by a bike. Let it is equal to d. Using second equation of kinematics as follows :

\(d=ut+\dfrac{1}{2}at^2\\\\\text{a=acceleration of bike and u = 0}\\\\d=\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\d=\dfrac{(v-u)t}{2}\\\\d=\dfrac{(4-0)4}{2}\\\\d=8\ m\)

So, the car cover a distance of 8 m.

The bike will travel the distance of 8 m during the given time interval.

Given data:

The initial speed of bike is, u = 0.0 m/s.

The final speed of bike is, v = 4.0 m/s.

The time interval is, t = 4 s.

In given problem, we need to obtain the magnitude of acceleration first. Then we can use this value in the third kinematic equation of motion, to find the distance covered by bike.

Then by first kinematic equation of motion,

v = u + at

Solving as,

4.0 = 0 + a(4)

a = 1 m/s²

Now, we can use the third kinematic equation of motion to find the distance travelled as,

\(v^{2}=u^{2}+2as\)

Solving as,

\(4.0^{2}=0^{2}+2(1)s\\\\16 = 2s\\\\s = 8\;\rm m\)

Thus, we can conclude that the bike will travel the distance of 8 m during the given time interval.

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The idea of not wanting or doing too much or too little is called (ex. eat
way too much or starve yourself)

Answers

Answer: below

Explanation:

binge eating then purging. Often known as bulimia. It's an eating disorder. If you starve yourself you have anorexia. If its an idea you are paranoid. Or you are very depressed and you want to get rid of your emotions. It could be called starving yourself too. But you may be looking for the word Orthorexia

The star Arcturus has an apparent magnitude of 0.0 and is found at a distance of 11.0 pc. What is the most likely value for Arcturus' absolute magnitude?

Answers

Arcturus with an apparent magnitude of 0.0  and a distance of 11.0 pc has an absolute magnitude of approximately -0.3.

Arcturus, a star in the constellation Boötes, has an apparent magnitude of 0.0 and is located 11.0 parsecs away from Earth. To determine its absolute magnitude, we can use the distance modulus formula, which relates apparent magnitude (m), absolute magnitude (M), and distance (d) in parsecs: m - M = 5 * log10(d) - 5.

In this case, m = 0.0 and d = 11.0 parsecs. Rearranging the formula to solve for M, we get M = m - 5 * log10(d) + 5. Plugging in the values, we have M = 0.0 - 5 * log10(11.0) + 5.

Calculating the result, we find that Arcturus' absolute magnitude is approximately -0.3. This value represents the intrinsic brightness of the star, or the brightness it would have if it were placed at a standard distance of 10 parsecs away from the observer. In summary, the most likely value for Arcturus' absolute magnitude is -0.3.

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Please help me!! Time = 98 seconds speed=7.5 meters/second what is the distsnce in meters

Answers

Answer:

735 m

Explanation:

The distance covered by an object given it's speed and time taken can be found by using the formula

distance = speed × time

From the question we have

distance = 7.5 × 98 = 735 m

We have the final answer as

735 m

Hope this helps you

Atoms with a low ionization energy give up their outer valence electrons with
ease.
O A. True
O B. False

Answers

Answer:

a. true

Explanation:

i think

that my answer

The law of conservation of energy tells us

A. that energy can be transformed from one form to another

B. energy cannot be created or destroyed

C. the total amount of energy will remain the same

D. All of the above

Answers

Answer:

it is A

Explanation:

because energy can neither be created nor destroyed - only converted from one form of energy to another.

Which direction will thermal energy flow if you pick up a snowball with your bare hand? Thermal energy will flow from the snowball to your hand. Thermal energy will flow from your hand to the snowball. Thermal energy will not flow between your hand and the snowball.

Answers

Answer:

b. Thermal energy will flow from your hand to the snowball.

Explanation:

Answer:

B

Explanation:

How can a person best reduce the risk of sustaining permanent injuries?

- Wear protective clothing while sleeping at home.
- Secure a seat belt only when riding in the front seat.
- Wear a cracked bicycle helmet while riding a bicycle.
- Put away guns in a lockbox that is secure and in a discrete location.

Answers

Answer:

Put away guns in a lockbox that is secure and in a discrete location

Explanation: Took the test. Trust me ;)

Answer:

Put away guns in a lockbox that is secure and in a discrete location

Explanation: Just Trust Me

What is the relationship between transit duration and orbital period?

Answers

Answer:

The length of time between each transit is the planet's "orbital period", or the length of a year on that particular planet. Not all planets have years as long as a year on the Earth! Some planets discovered by Kepler orbit around their stars so quickly that their years only last about four hours!

I hope it helps.

Answer:

lenght of year po

Explanation:

hope it helps

In a compound microscope, the focal lengths of the objective and eyepiece are +0.50 cm and +2.0 cm respectively. The instrument is focused on an object 0.52 cm from the objective lens. Compute the magnify- ing power of the microscope if the virtual image is viewed by the eye at a distance of 25 cm. Ans. 3.4 x 10²


please I need the solution asap​

Answers

Magnification of the compound microscope with given values is 3.4 x 10², which means it can magnify 340 times.

The enhancing power of a compound amplifying focal point is given by the recipe:

Enhancement = (1 + (f0/fe)) x (do/de)

Where f0 is the focal length of the objective point of convergence, fe is the focal length of the eyepiece, do is the distance between the article and the objective point of convergence, and de is the distance between the eyepiece and the virtual picture.

Subbing the given characteristics into the situation, we get:

Enhancement = (1 + (0.50 cm/2.0 cm)) x (0.52 cm/(25 cm - 0.50 cm))

Enhancement = 3.4 x 10²

The given condition for the strengthening force of a compound magnifying lens is utilized with the given qualities to compute the amplification of the magnifying instrument. The subsequent worth of 3.4 x 10² implies that the magnifying lens can amplify an item multiple times its unique size when seen a ways off of 25 cm.

Consequently, the intensifying power of the amplifying instrument is 3.4 x 10², and that suggests that the amplifying focal point can enhance a thing on numerous occasions its one of a kind size when seen a distance away of 25 cm.

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When a component is used to perform the function of stop in a control circuit, it will generally be a normally ____ component and be connected in ____ with the motor starter coil

Closed series
Change position
Parallel

Answers

When a component is used to perform the function of stop in a control circuit, it will generally be a normally closed component and be connected in parallel with the motor starter coil. Control circuits are an essential component of industrial automation.

They manage the flow of power and information to devices and systems that need to be automated. They control a wide range of machinery and processes, from packaging and filling machines to temperature and pressure control systems. Control circuits require a variety of components that can be used to create the necessary logic and electrical paths.

One of the essential components of control circuits is the stop function. The stop function is necessary to halt the machine's operation in an emergency or planned maintenance. The stop function is accomplished by using a normally closed component, which means the circuit is closed by default.

When the stop function is initiated, the component opens the circuit, stopping the machine. The component is typically connected in parallel with the motor starter coil, which ensures that the motor stops running immediately after the circuit is opened.

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mastering physics To understand how to compute the work done by a constant force acting on a particle that moves in a straight line. In this problem, you will calculate the work done by a constant force. A force is considered constant if F⃗ (r⃗ ) is independent of r⃗ . This is the most frequently encountered situation in elementary Newtonian mechanics.

Answers

Complete Question

The complete question is shown of the first uploaded image

Answer:

Explanation:

 The  force vector acting upon the particle is \(\vec F\) (The magnitude is F )

  The displacement vector from point B to A is  \(\vec L\) (The magnitude is  L )

Generally workdone is mathematically represented as

     \(W_{BA} = \vec F * \vec L\)

But from the question we are to that vector L has a magnitude L  and  makes and angle \(\theta \ radian\) with the positive x-axis

also  we are told that Force is pointing to the left and is parallel to the horizontal  axis (i.e at angle  \(\pi \ radian\) (180°))

Generally the angle between the \(\vec F \ and \ \vec L\) is  \(\pi - \theta\)

Hence the workdone is mathematically represented as

       \(W_{BA} =F * L cos (\pi - \theta)\)

=>    \(W_{BA} =-F * L cos \theta\)

Here the negative sign shows that the displacement is acting in opposite direction to the direction of the workdone (the force applied )

mastering physics To understand how to compute the work done by a constant force acting on a particle

Suppose the Sun is 1.29025 X 108 km from
Earth.
The speed of light is 2.99792 x 108 m/s.
How long does it take for its light to reach
us?
Answer in units of min.

Answers

Answer:

It takes the Sun's light 7.17 minutes to reach us.

Explanation:

We can calculate the time that takes the light to reach us by using the following equation:

\( t = \frac{d}{c} \)    

Where:

d: is the distance = 1.29025x10⁸ km = 1.29025x10¹¹ m

c: si the speed of light = 2.99792x10⁸ m/s  

Hence, the time is:

\( t = \frac{d}{c} = \frac{1.29025 \cdot 10^{11} m}{2.99792 \cdot 10^{8} m/s} = 430.38 s = 7.17 min \)

Therefore, it takes the Sun's light 7.17 minutes to reach us.

I hope it helps you!

if a specimen was being viewed using a 20x objective lens and 10x ocular lens, what would be the total magnification? multiple choice 30x 210x 200x 2000x

Answers

The total magnification when using a 20x objective lens and a 10x ocular lens would be 200x.

To calculate the total magnification, we multiply the magnification of the objective lens by the magnification of the ocular lens.

Objective Lens: The objective lens is typically found on the nosepiece of a microscope and provides the primary magnification. In this case, the objective lens has a magnification of 20x.

Ocular Lens: The ocular lens, also known as the eyepiece, is located at the top of the microscope and further magnifies the image produced by the objective lens. The ocular lens in this scenario has a magnification of 10x.

Total Magnification: To find the total magnification, we multiply the magnification of the objective lens by the magnification of the ocular lens.

Total Magnification = Objective Magnification × Ocular Magnification

Total Magnification = 20x × 10x

Total Magnification = 200x

Therefore, the total magnification when using a 20x objective lens and a 10x ocular lens is 200x.

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how does an increased length of time that a force acts on an object affect the strength of the impulse produced?

Answers

An increased length of time that a force acts on an object affects the strength of the impulse produced by increasing it. Impulse is defined as the change in momentum of an object and is directly proportional to the force applied and the time it acts.

According to the impulse-momentum principle, increasing the time over which a force is applied to an object results in a greater change in momentum or impulse. This principle can be mathematically expressed as:

Impulse = Force × Time

When the force is applied for a longer duration, the time in the equation increases. As a result, for the same force magnitude, the impulse produced is larger. Conversely, if the time is decreased, the impulse will be smaller for the same force.

The relationship between impulse, force, and time is essential in understanding the effects of forces on objects, particularly in scenarios involving collisions or changes in momentum. By manipulating the duration of a force, it is possible to achieve different levels of impulse and, consequently, different effects on the object's motion.

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which factor is needed to describe velocity but is not needed to describe speed

Answers

Answer:

Magnitude and direction describe velocity

However if there is only magnitude its mean it is speed.

Fun : probably you have seen speed movie. It could not have director because if speed is directed then it will be velocity lol..

A hunter shoots a 500 g arrow at a 2.0 kg bird perched on a tall tree growing on flat, level ground. The arrow is launched from ground level with a speed of 40 m/s at an angle of 30 degrees above the horizon. It is traveling horizontally when it strikes and embeds in the bird. How far from the base of the tree do the bird and the arrow land

Answers

Answer:

The bird and the arrow are 84.621 meters far from the hunter.

Explanation:

The arrow experiments of a parabolic motion, which is the combination of horizontal motion at constant velocity and vertical uniform accelerated motion. The arrow strikes the bird when it reaches its maximum height. First, we determined the time taken by the arrow before striking the bird:

\(v = v_{o}\cdot \sin \theta + g\cdot t\) (1)

Where:

\(v_{o}\) - Initial speed of the arrow, in meters per second.

\(v\) - Final speed of the arrow, in meters per second.

\(\theta\) - Launch angle, in sexagesimal degrees.

\(g\) - Gravitational acceleration, in meters per square second.

\(t\) - Time, in seconds.

If we know that \(v_{o} = 40\,\frac{m}{s}\), \(\theta = 30^{\circ}\), \(g = -9.807\,\frac{m}{s^{2}}\), \(v = 0\,\frac{m}{s}\), then the time taken by the arrow is:

\(t = \frac{v-v_{o}\cdot \sin \theta}{g}\)

\(t = \frac{0\,\frac{m}{s}-\left(40\,\frac{m}{s}\right)\cdot \sin 30^{\circ} }{-9.807\,\frac{m}{s^{2}} }\)

\(t = 2.039\,s\)

And the initial horizontal distance of the arrow (\(x_{i}\)) is determined by this kinematic formula:

\(x_{i} = (v_{o}\cdot \cos \theta)\cdot t\) (2)

If we know that \(v_{o} = 40\,\frac{m}{s}\), \(\theta = 30^{\circ}\) and \(t = 2.039\,s\), then the initial horizontal distance is:

\(x_{i} = \left[\left(40\,\frac{m}{s} \right)\cdot \cos 30^{\circ}\right]\cdot (2.039\,s)\)

\(x_{i} = 70.633\,m\)

There is an inelastic collision between the arrow and the bird, the initial velocity of the bird-arrow system is:

\(v = \frac{m_{A}\cdot v_{o}\cdot \cos \theta}{m_{A}+m_{B}}\) (3)

Where:

\(v\) - Initial velocity of the bird-arrow system, in meters per second.

\(m_{A}\) - Mass of the arrow, in kilograms.

\(m_{B}\) - Mass of the bird, in kilograms.

If we know that \(m_{A} = 0.5\,kg\), \(m_{B} = 2\,kg\), \(v_{o} = 40\,\frac{m}{s}\) and \(\theta = 30^{\circ}\), then the initial velocity of the bird-arrow system is:

\(v = \frac{(0.5\,kg)\cdot \left(40\,\frac{m}{s} \right)\cdot \cos 30^{\circ}}{0.5\,kg + 2\,kg}\)

\(v = 6.928\,\frac{m}{s}\)

And the maximum height reached by the arrow (\(y\)), in meters, is:

\(y = y_{o} + (v_{o}\cdot \sin \theta)\cdot t +\frac{1}{2}\cdot g\cdot t^{2}\) (4)

Where \(y_{o}\) is the initial height of the arrow, in meters.

If we know that \(y_{o} = 0\,m\), \(v_{o} = 40\,\frac{m}{s}\), \(\theta = 30^{\circ}\),  \(g = -9.807\,\frac{m}{s^{2}}\) and \(t = 2.039\,s\), then the maximum height reached by the arrow is:

\(y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (2.039\,s)\cdot \sin 30^{\circ} +\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}}\right)\cdot (2.039\,s)^{2}\)

\(y = 20.394\,m\)

Time needed by the bird-arrow system to land is determined by this expression based on (4):

\(y = y_{o} + (v_{o,y})\cdot t +\frac{1}{2}\cdot g\cdot t^{2}\)

If we know that \(y_{o} = 20.394\,m\), \(y = 0\,m\), \(v_{o,y} = 0\,\frac{m}{s}\) and \(g = -9.807\,\frac{m}{s^{2}}\), then the time needed to land is:

\(0\,m = 20\,m + \left(0\,\frac{m}{s} \right)\cdot t + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot t^{2}\)

\(t = 2.019\,s\)

And the horizontal distance travelled by the bird-arrow system (\(x_{ii}\)), in meters, is calculated from a formula based on (2):

\(x_{ii} = v_{o, x}\cdot t\)

If we know that \(v_{o,x} = 6.928\,\frac{m}{s}\) and \(t = 2.019\,s\), then the distance travelled by the bird-arrow system is:

\(x_{ii} = \left(6.928\,\frac{m}{s} \right)\cdot (2.019\,s)\)

\(x_{ii} = 13.988\,m\)

The final distance of the bird-arrow system from the hunter is:

\(x = x_{i} + x_{ii}\)

\(x = 70.633\,m + 13.988\,m\)

\(x = 84.621\,m\)

The bird and the arrow are 84.621 meters far from the hunter.

A car moving at a speed of 20 m/s then accelerates uniformly at 1.8 m/s^2 until it reaches a speed of 25 m/s. What distance does it travel during the time it is accelerating?

66 m
54 m
62 m
50 m
58 m

Answers

Answer:

62.5 m

Explanation:

.......................................

A car moving at a speed of 20 m/s then accelerates uniformly at 1.8 m/s^2 until it reaches a speed of

How many electrons must be transferred from one plate to the other to create a spark between the plates?.

Answers

To create a spark between two plates, electrons must be transferred from one plate to the other. The number of electrons required depends on the charge carried by each electron and the total charge needed to create the spark.

The charge carried by each electron is 1.6 x 10^-19 coulombs. Let's assume that the total charge needed to create the spark is Q coulombs. To determine the number of electrons required, we can use the formula:

Number of electrons = Total charge / Charge carried by each electron

So, the number of electrons (N) can be calculated as:

\(N = Q / (1.6 \times 10^-19)\)

For example, if the total charge needed is 1.6 x 10^-5 coulombs, then the number of electrons required would be:

\(N = (1.6 \times 10^-{5}) / (1.6 \times 10^{-19}) = 1 \times 10^{14} electrons.\)

Therefore, in this example, 1 x 10^14 electrons must be transferred from one plate to the other to create a spark between the plates.

In summary, the number of electrons required to create a spark between two plates depends on the total charge needed and the charge carried by each electron.

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Globally, the winter of 2014–15 was the warmest winter on record at that time, but it sure didn’t seem that way for most of the eastern United States. This region experienced record-low temperatures and extreme snowfall, especially in the northern and coastal areas. During this period of extreme cold and snow, it was not uncommon to see comments on social media disputing climate change. For example, some commenters took pictures of huge piles of snow and added comments such as, "This doesn’t look like global warming."


Do these commenters have a point? Should extreme snowfall over the course of a season cast doubt on the theory of global climate change? Make a scientific argument explaining why you agree or disagree with these commenters.

Answers

Answer:

I need help on this to omg

Explanation:

A shopper in a supermarket takes a box of sugar from a shelf that is 1.5 m high because he is going to bake some muffins. He also needs to get some blueberries. The sugar has a weight of 5N. What Potential Energy did the sugar have before it was taken from the shelf?Potential Energy = Weight x HeightWeight = Potential Energy / HeightHeight = Potential Energy / WeightWeight = Mass x 10Mass = Weight / 10

Answers

In order to calculate the potential energy of an object, we can use the formula below:

\(PE=m\cdot g\cdot h\)

Where PE is the potential energy (in Joules), m is the mass (in kg), g is the gravity acceleration (in m/s²) and h is the height (in meters).

Since mass times gravity is equal to the weight force, we can also write the formula as follows:

\(W=m\cdot g\)

Where W is the weight force (in Newtons).

So the formula will be:

\(PE=W\cdot h\)

Potential Energy = Weight x Height

Since the height is equal to 1.5 meters and the weight force is equal to 5 N, we have:

\(\begin{gathered} PE=5\cdot1.5 \\ PE=7.5\text{ J} \end{gathered}\)

The potential energy is 7.5 Joules.

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