A 57 kg paratrooper falls through the air. How much force is pulling him down?

Answers

Answer 1

Answer:

Explanation:

Force = Mass * acceleration due to gravity.

Given

Mass of the paratrooper = 57kg

Acceleration due to gravity = 9.81m/s²

Required

Force pulling him down

Substitute unto formula;

F = 57 * 9.81

Force = 559.17 N

Hence the force pulling him down is 559.17N

Answer 2

The force pulling the paratrooper as he falls down is 558.6 N.

The given parameters;

mass of the paratrooper, m = 57 kgacceleration due to gravity, g = 9.8 m/s²

The force pulling the paratrooper is force of gravity and the magnitude can be determined by applying Newton's second law of motion as shown below;

F = mg

F = 57 x 9.8

F = 558.6 N

Thus, the force pulling the paratrooper as he falls down is 558.6 N.

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Related Questions

A runner of mass 80 kg is moving at 8.0 m/s. Calculate her kinetic energy. ​

Answers

Answer:

2560J

Explanation:

By definition the kinetic energy can be calculated in the following way:

K = (mv²)/2 = 80kg·(8.0m/s)²/2 = 2560 J

The image shows a diagram explaining a concept.

Which concept does the diagram show?
A. tempature
B. Altitude
C. air density
D. air pressure

The image shows a diagram explaining a concept. Which concept does the diagram show? A. tempatureB. AltitudeC.

Answers

Answer:

D.

Explanation

Air pressure.

Answer:air pressure

Explanation:

What is the net force on a truck if the force of friction is 31 N and the force of the engine is 79 N?

48 N backword

79 N forward

48 N forward

110 N forward​

Answers

Answer:

Fr = 48 [N] forward.

Explanation:

Suppose the movement is on the X axis, in this way we have the force of the engine that produces the movement to the right, while the force produced by the brake causes the vehicle to decrease its speed in this way the sign must be negative.

∑F = Fr

\(F_{engine}-F_{brake} =F_{r}\\F_{r}=79-31\\F_{r}=48[N]\)

The movement remains forward, since the force produced by the movement is greater than the braking force.

SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?

Answers

The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

How to explain tje information

Isaac's force:

Magnitude: 255 N

Angle: 13 degrees North of East

x-component: 255*cos(13) = 245.1 N (Eastward)

y-component: 255*sin(13) = 58.1 N (Northward)

Newton's force:

Magnitude: 156 N

Angle: 34 degrees South of East

x-component: 156*cos(34) = 129.4 N (Westward)

y-component: 156*sin(34) = 86.5 N (Southward)

Now we can add the x- and y-components of the forces to find the net force:

Net force:

x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)

y-component: 58.1 N - 86.5 N = -28.4 N (Southward)

The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

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What is the speed of the object at the end of 10 s?

Answers

Answer:

-100m/s not shure tho thx tho

A water bed that is 1.5 m wide and 2.5 m long weighs 1055 N. Assuming the entire lower surface of the bed is in contact with the floor, what is the pressure the bed exerts on the floor?
a.
250 Pa
c.
270 Pa
b.
260 Pa
d.
280 Pa

Answers

D
P=F/A
A=1.5*2.5= 3.75m^2
P= 1055/3.75 = 281Pa

A model rocket flies horizontally off the edge of a cliff at a velocity of 80.0m/s. If the canyon below is 128.0 m deep, how far from the edge of the cliff does the model rocket land?

a. 112m
b. 225m
c. 337m
d. 409m

Answers

Answer:

c. 337

Explanation:

can someone answer my question

A spacecraft has a momentum of 20,000 kg-m/s, and a mass of 250 kg. What is the magnitude of its velocity?
A. 80 m/s
B. 800 m/s
C. 400 m/s
D. 40 m/s SUBMIT​

Answers

Answer:

A. 80 m/s

Explanation:

The velocity of the spacecraft can be found by using the formula

\(v = \frac{p}{m} \\ \)

p is the momentum

m is the mass

From the question we have

\(v = \frac{20000}{250} = \frac{2000}{25} \\ \)

We have the final answer as

80 m/s

Hope this helps you

A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What is the longest wavelength that forms an intensity maximum in the fifth order

Answers

Answer:

377 nm

Explanation:

Number of lines per meter is, \(N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}\)

Grating element is, \(d=\frac{1}{N}\)

\(=1.8868 \times 10^{-6} \mathrm{~m}\(

Order is, n=5

Condition for maximum intensity is, \(d \sin \theta=n \lambda\)

 \(\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\ &=0.377 \times 10^{-6} \mathrm{~m} \\ &=377 \mathrm{~nm}\)

We know that the frequency and wavelength of an oscillation are related by the velocity of the wave . In standing waves, the wave velocities of the different harmonics are the same.Think about why this may be and explain that in your notebook. (Hint: The wave velocity is dependent on the static properties of the oscillating object like mass per unit length and tension)

Answers

Answer

the medium does not change the speed of the on they should change.

Explanation:

The speed of the waves is constant for a given medium, depending on the physical properties of the medium,

When a wave is strapped on a wall of a medium it does not change the properties of the medium, the wave changes direction, but since the medium does not change the speed of the on they should change.

Please help !!
Urgent !
The options are the same for the questions

Please help !! Urgent ! The options are the same for the questions

Answers

Answer:

it have magnitude and direction is vector

it have magnitude but not direction is scalar

by multiplying ..... is magnitude

ny adding you get another vector

Explanation:

yeah I hope this helpa

What order does energy flow: sun prodecer consumer?

Answers

Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.

Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.

At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.

The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.

Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.

At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.

It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.

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15- Now, if Javier leaves Mayagüez (24.0 km) at a speed of 100.0 km/h to meet María in Rincón, how long does it take to get to Rincón?

Answers

Speed = Distance/Time

Time = Distance/Speed = 24 km/ 100 km/h = 0.24 h = 14.4 minutes

A. Organized process to test a hypothesis
B. An educated guess about the solution to a problem
C. Observations & measurements recorded
D. A summary based on the results of an experiment
E. The response that is measured in an experiment
F. The factor that is manipulated during an experiment

Answers

The scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable.

What is an observation in science?

Observation is the first step of the scientific method, which then requires to raise a question that will be answered by a testable hypothesis.

The scientific method is a series of well-established steps used to collect scientific empirical data/evidence, which allow to test a given hypothesis.

In conclusion, the scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable..

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A rectangular field is of length 42 cm and breadth 25 m. Find the area of the field in SI unit.​

Answers

Answer:

(42/100) (25)=area

10.5 m^2 = area

A small dog walks 12 meters east
and then 5 meters north. How many
meters is the dog from her starting
position?
[?] m

5 m
12 m

Answers

7m- it’s 12-5=7!! Brainlist please

Answer:

13m

Explanation:

North and East are perpendicular so if you illustrate this it will be a right-angle triangle;

One side will be 12 and the another will be 5;

The hypotenuse will be the desired distance;

We can use pythagoras to calculate it:

5² + 12² = x²

25 + 144 = x²

169 = x²

x = 13

II. Understanding Concepts

Skill: Hypothesizing

1. The dots in the balloon represent particles of air. Use what you know about
pressure, temperature, volume, and the kinetic theory of matter to write a
hypothesis explaining what will happen to the volume of the balloon if
pressure is kept constant and the temperature is lowered.

Answer in complete sentences

II. Understanding ConceptsSkill: Hypothesizing1. The dots in the balloon represent particles of air.

Answers

As the temperature of the balloon is lowered, its volume will decrease as well.

What is kinetic theory of matter?

The kinetic theory of matter  says that all matter consists of many, very small particles which are constantly moving or in a continual state of motion.

According to Charles law, the volume of a fixed mass of a gas is directly proportional to its absolute temperature.

Based on Charles law, as the temperature of the balloon is lowered, its volume will decrease as well because the average kinetic energy of the gas molecules has reduced, the rate of gas collision decreased, which will cause a drop in the volume of the balloon.

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Kent Belate is driving down I-294 at 26.7 m/s. He accelerates at a uniform rate of 5.78 m/s/s over a distance of 52.1 m. How much time is required to cover this distance?

Answers

The time taken for Kent Belate to travel the distance is 3.21 seconds.

What is the time taken for Kent Belate to travel the distance?

The time taken for Kent Belate to travel the distance is calculated by applying the following kinematic equation as shown below.

s = (u + v)/2 x t

where;

u is the initial velocity of Kent Belate v is the final velocity of Kent Belate t is the time of motion of Kent Belate s is the distance travelled by Kent Belate

2s = (u + v)t

t = (2s) / (u + v)

t = (2 x 52.1) / (26.7 + 5.78)

t = 3.21 second

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5 points
15. *
15. Which one of the following
quantities is NOT a vector?
A velocity
B acceleration
C distance
D displacement
A
B
С

Answers

Answer:

distance is not a vector. it is scalar

The largest stars we know of have masses of a little over 1035 kilograms, while the lowest mass stars have masses of about 1032 kilograms. How many times more massive are the most massive stars than the lowest mass stars?
Group of answer choices

a thousand times more massive.

a hundred times more massive.

ten times more massive.

ten thousand times more massive

Answers

Answer:

the bigger stars tend to be hotter and burn through their fuel more quickly than smaller stars they also tend to ether be turned into a black hole or a huge nebula with a neutron star the smaller stars have a tendency to go through their fuel slower and don't get as hot as big stars until the red giant stage.

Explanation:

Problem 19: Oil with a density of 892 kg/m is flowing smoothly through a pipe, as
shown. In the lower portion, the oil is flowing at vi = 1.84 m/s, and the pressure gauge
indicates P, = 237 kPa. In the upper portion of the pipe, oil is flowing at V2 = 3.61 m/s at a
height that is 8.63 m above the lower portion.

Answers

The pressure of the oil with the given properties flowing in the horizontal pipe at the upper portion of the pipe is 157 kPa.

Pressure in the upper portion of the pipe

The pressure in the upper portion of the pipe is calculated by applying Bernoulli's equation,

P₁ + ¹/₂ρv₁² + ρgh₁ = P₂ + ¹/₂ρv₂² + ρgh₂

Given;

P₁  = 237 kPav₁ = 1.84 m/sh₁ = 0v₂ = 3.61 m/sh₂ = 8.63 mρ = 892 kg/m³P₂  = ?

Susbtsitute the given parameters and solve the for the pressure in the upper portion of the pipe.

237,000 + ¹/₂(892)(1.84)² + (892)(9.8)(0) = P₂ + ¹/₂(892)(3.61)² + (892)(9.8)(8.63)

238,509.9776 = P₂ + 81,252.325

P₂ = 238,509.9776 - 81,252.325

P₂ = 157,257.65 Pa

P₂ ≅ 157 kPa

Thus, the pressure of the oil with the given properties flowing in the horizontal pipe at the upper portion of the pipe is 157 kPa.

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An object of height 5cm is placed 20cm in front of pin hole camera from a cubic box of side 6cm . Determine the height of the image formed​

Answers

5 20!!!!!!!!!!!!!!!!

at divergent plate boundaries, iron-rich minerals will align themselves with the existing magnetic field when they cool from a magma. t/f

Answers

Answer:

True

Explanation:

What is the impulse of a car hitting another car if it's initial velocity was 50m/s
and it's velocity after hitting it is 4.4m/s? The car weighs 2168kg.
J=A P
AP=mvf-mvi

Answers

The impulse of the car after hitting is 98860.8 kg.m/s

In physics, the term "impulse" is used to characterize or measure the impact of force operating gradually to alter an object's motion. It is often stated in Newton-seconds or kilograms per second and is denoted by the symbol J.

            J = m ( v-u)

where, m = 2168 kg

           u = 50 m/s

           v = 4.4 m/s

J = 2168 ( 4.4 - 50)

J = 2168(45.6)

J = 98860.8 kg.m/s

since the final velocity is decreasing the impulse is a vector term thus a negative sign will also be included in this.

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Explain why it’s much colder at the bottom of the pool than at the top. also describe what heat transfer processes is taking place

Answers

Heat transfer by radiation and convection causes the surface water of the pool to be warm which decreases with depth.

Why is it colder at the bottom of the pool than the top of the pool?

There are two heat transfer process responsible for variation in temperature of water at different depth of a pool, they include;

Heat transfer by radiationHeat transfer by convection

Heat transfer by radiation

The surface of the water absorbs heat from the air and the sun. The heat from the sun is transferred to the pool through radiation.

Heat transfer by convection

The heat from the air is transferred to the pool through convection.

Thus, these two heat transfer processes  causes the surface water of the pool to be warm which decreases with depth.

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A 0.21 kg apple falls from a tree to the ground 4.0m below. Ignoring air resistance, determine the apple's kinetic energy, the gravitational potential energy, and the total mechanical energy of the system when the apple’s height above the ground is 3.0m.

Answers

Given :

Mass of the apple (m): 0.21 kgHeight of the apple above the ground at the start (initial height) (h1): 4.0 mHeight of the apple above the ground at the end (final height) (h2): 3.0 mAcceleration due to gravity (g): 9.81 m/s^2

To Find :

The falling apple's kinetic energy, gravitational potential energy, and total mechanical energy.

Solution :

We can use the conservation of energy principle to find the apple's kinetic energy, gravitational potential energy, and total mechanical energy at the height of 3.0m above the ground.

First, we need to find the gravitational potential energy (GPE) of the apple when it is at the height of 4.0m above the ground:

GPE = mgh

where m is the mass of the apple, g is the acceleration due to gravity (9.81 m/s^2), and h is the height above the ground.

So, GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) = 8.2266 J

Next, we find the apple's kinetic energy (KE) just before it hits the ground. We can use the conservation of energy principle, "which states that a system's total mechanical energy is conserved (i.e., it remains constant) if no external forces are acting on it." In this case, gravity is the only force acting on the apple, an internal force within the system (i.e., the apple and the Earth).

So, at the height of 3.0m above the ground, the total mechanical energy (TME) of the system is:

TME = GPE + KE

Since the apple is falling freely, we can assume that all of its potential energy at the height of 4.0m has been converted into kinetic energy just before it hits the ground. Therefore, at the height of 3.0m above the ground, the GPE is:

GPE = (0.21 kg) x (9.81 m/s^2) x (3.0 m) = 6.1359 J

Using the conservation of energy principle, we can find the kinetic energy just before the apple hits the ground:

TME = GPE + KE

KE = TME - GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) - 6.1359 J = 2.0907 J

Therefore, the kinetic energy of the apple just before it hits the ground is 2.0907 J.

To summarize:

Gravitational potential energy (GPE) of the apple at a height of 4.0m above the ground: 8.2266 J

Gravitational potential energy (GPE) of the apple at a height of 3.0m above the ground: 6.1359 J

Kinetic energy (KE) of the apple just before it hits the ground: 2.0907 J

The system's total mechanical energy (TME) is conserved throughout the fall.

5. A person on a trampoline jumps straight up. When the person is 3 m above the surface and
with upward velocity of 2.5 m/s, drops a ball. a) What is the speed of the ball at the time of
impact? b) How long before the ball impacts the surface of trampoline?

Answers

a)The speed of the ball at the time of impact will be 8.1 m/sec.

b)The time taken by the ball impacts the surface of trampoline will be 1.1 second.

What is speed?

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. Its SI unit is m/sec.

Given data;

g( gravitational acceleration) = 9.81 m/s2

u (initial velocity of ball) = 2.5 m/s

h₁(initial height of the ball) = 3.0 m

v (speed of the ball at the time of impact ) ?

The time taken by ball for upward journey = u / g

t₁ = u / g

t₁  = (2.5 m/s) / (9.81 m/s2) =

t₁  =0.2548 s

From second equation of motion,upward vertical distance covered by ball is;

\(\rm h_2= \frac{1}{2} gt^2\\\\ h_2=\frac{1}{2} \times 9.81 \times (0.2548)^2\\\\ h_2=0.3184\)

The total distance in the downward direction travelled;

\(\rm h_3=h_1+h_2 \\\\ h_3=3.0+0.3184 \\\\ h_3=3.3184 \ m\)

The time taken for the downward motion is;

\(\rm t_2 = (\frac{2 \times h_3 }{g} )^\frac{1}{2}\\\\ t_2 = 0.825 \ m/sec\)

The speed of the ball at the time of impact is found as;

\(\rm V=gt_2 \\\\ V= 9.81 \times 0.8225 \\\\ V= 8.07 \ m/sec\)

The total time of the flight of ball is;

\(\rm t_3 = t_1+t_2 \\\\ t_3=0.2548+0.8225 \\\\ t_3=1.0774 \ sec\)

Hence,the speed of the ball at the time of impact will be 8.1 m/sec and time taken by the ball impacts the surface of trampoline will be 1.1 second.

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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.

Answers

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Near the surface of Earth, an electric field points radially downward and has a magnitude of approximately 100 N/C. What charge (magnitude and sign) would have to be placed on a penny that has a mass of 3 g to cause it to rise into the air with an upward acceleration of 0.19 m/s2?

Answers

Answer:

q = 2.997*10^-4C

Explanation:

In order to find the required charge that the penny have to have, to acquire an upward acceleration, you take into account that the electric force on the penny must be higher than the weight of the penny.

You use the second Newton law to sum both electrical and gravitational forces:

\(F_e-W=ma\\\\qE-mg=ma\)             (1)

Fe: electric force

W: weight of the penny

q: required charge = ?

m: mass of the penny = 3g = 0.003kg

E: magnitude of the electric field = 100N/C

g: gravitational acceleration = 9.8m/s^2

a: acceleration of the penny = 0.19m/s^2

You solve the equation (1) for q, and replace the values of the other parameters:

\(q=\frac{ma+mg}{E}=\frac{m(a+g)}{E}\\\\q=\frac{(0.003kg)(0.19m/s^2+9.8m/s^2)}{100N/C}\\\\q=2.997*10^{-4}C\)

It is necessary that the penny has a charge of 2.997*10^-4 C, in order to acquire an upward acceleration of 0.19m/s^2

Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?

Answers

The height that will illustrate the distance will be d = 6.36m

How to calculate the height?

Based on the information given, the length of the vine will be:

L = ✓(16² + 27.7)²

L = 32m

The velocity of Jane when she reaches position B will be:

V = ✓2gh

V = ✓(2 × 9.8 × 4.3)

V = 9.18m/s

We will apply the conversation of momentum. This will be:

50 × 9.18 = (50 + 80)V1

V1 = 3.53m/s

Therefore, the height that will illustrate the distance will be:

31.36² + d² = 32²

d² = 32² - 31.36²

d = 6.36m

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A practical number is a positive integer n such that all positive integers smaller than n can be expressed as sums of distinct divisors of n. For example, 8 is a practical number because the numbers 1 through 7 can be expressed as sums of 1, 2, and 4 as follows: 1 = 1, 2 = 2, 3 = 2 + 1, 4 = 4, 5 = 4 + 1, 6 = 4 + 2, and 7 = 4 + 2 + 1. Show that 18 is a practical number. a light is suspended at a height h above the floor. the illumination, i, at a point p is inversely proportional to the square of the distance, r, from the point p to the light and directly proportional to the cosine of the angle theta. assume k is the constant of proportionality. which of the following can be used to represent the illumination at point p? i An isosceles trapezoid has a perimeter of 45 millimeters. Its shorter base measures 6. 3 millimeters and its longer base measures 16. 1 millimeters. The two remaining sides have the same length; what is that length? The start of an El-Nio event begins with Weakening SOI Strengthening SOI Unchanged SOI Polar vortex What is biodiversity? Please explain. Ill give literally anyone branliest...I NEED HELP ASAP! A substance that keeps its shape because its particles can't flow freely is a(n) _____________. In terms.of the origins of government, what impact did the geeks have on our worldHelpp I am confused on how to do this. Exercise 3-8 Applying Overhead; Journal Entries; Disposing of Underapplied or Overapplied Overhead [LO3-1, LO3-2, LO3-4] The following information is taken from the accounts of Latta Company. The entries in the T-accounts are summaries of the transactions that affected those accounts during the year. Manufacturing Overhead (a) 499,968 (b) 416,640 Bal. 83,328 Work in Process Bal. 5,360 (c) 778,000 319,500 93,500 (b) 416,640 Bal. 57,000 Finished Goods Bal. 33,000 (d) 674,000 (c) 778,000 Bal. 137,000 Cost of Goods Sold (d) 674,000 The overhead that had been applied to production during the year is distributed among Work in Process, Finished Goods, and Cost of Goods Sold as of the end of the year as follows: Work in Process, ending $ 27,360 Finished Goods, ending 65,760 Cost of Goods Sold 323,520 Overhead applied $ 416,640 For example, of the $57,000 ending balance in work in process, $27,360 was overhead that had been applied during the year. Required: 1. Identify reasons for entries (a) through (d). 2. Assume that the underapplied or overapplied overhead is closed to Cost of Goods Sold. Prepare the necessary journal entry. 3. Assume that the underapplied or overapplied overhead is closed proportionally to Work in Process, Finished Goods, and Cost of Goods Sold. Prepare the necessary journal entry. Question \( 4 . \) (15 marks) Some challenging aspects of designing a HExBOT agent are the hexagonal grid, the asymmetric cost of actions (pushing is more expensive than pulling a widget), rotation of Calculate the hydroxide ion concentrations of the following solutions at 25'C, given tbe pOH. pOH 8.85 [OH-]=_________ Find the 95% confidence interval of the average amount of electromagnetic waves ... of electromagnetic waves was measured to obtain X = 0.11 and S = 0.06. Tech Gurus Thats the business name the picture is the one that need to answer to the business I made Tech Gurus ? -3 + r > 4 OR r + 1 < -1PLEASE HELP What is the name of the organization created by Osama bin Laden and Ayman al Zawahiri that represents a variety of Jihadist groups limits on advertising and other public service requirements imposed on britain's commercial broadcasters in exchange for the right to broadcast constitute broadcasters' limits on advertising and other public service requirements imposed on britain's commercial broadcasters in exchange for the right to broadcast constitute broadcasters' remand warning. public service remit. d-notice. prior notification. Math question! please help What equation is ALWAYS TRUE? There are 3 sets of balls numbered 1 through 12 placed in a bowl. if balls are randomly chosen without replacement, find the probability that the balls have the same number. Express your answer as fraction. Which structures do ALL cells have in common