The 5.6 kg box on a frictionless 41∘ slope is connected to a hanging 2.3 kg weight using a massless string over a massless, frictionless pulley.
What is the acceleration of the box and the tension in the string?
The acceleration of the box is 2.27 m/s2.The tension in the string is 29.8 N. How to solve for the acceleration of the box and the tension in the string: Let's begin by drawing a diagram of the given problem, as shown below: Here, we can see that the box and the hanging weight are connected via a massless string over a massless, frictionless pulley. As a result, the tension in the string on both sides of the pulley is the same, and the acceleration of the box is the same as the acceleration of the hanging weight. To solve for the acceleration of the box and the tension in the string, we can use the following equations: Sum of forces in the direction of motion (x-axis): ma = T1 - mgsinθ ...(1)Sum of forces perpendicular to the direction of motion (y-axis):T2 = mgcosθ ...(2)Here, m is the mass of the hanging weight (2.3 kg), and M is the mass of the box (5.6 kg).a is the acceleration of the box, g is the acceleration due to gravity (9.81 m/s2), θ is the angle of the slope (41∘), T1 is the tension in the string on the side of the box, and T2 is the tension in the string on the side of the hanging weight. Substituting the value of T2 from equation (2) into equation (1), we get: ma = T1 - mgcosθsinθ = (5.6 kg)(9.81 m/s2)(sin 41∘)T1 = (5.6 kg)(9.81 m/s2)(sin 41∘) + (2.3 kg)(9.81 m/s2)(cos 41∘)T1 = 29.8 NTherefore, the tension in the string is 29.8 N. The acceleration of the box is given by:a = (T1 - mgsinθ)/M ...(3)Substituting the values of T1, m, M, g, and θ into equation (3), we get:a = (29.8 N - 2.3 kg x 9.81 m/s2 x sin 41∘)/5.6 kg = 2.27 m/s2Therefore, the acceleration of the box is 2.27 m/s2.
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find the voltage across the 15 Ω resistor.
Answer:
5.41 volts
Explanation:
You want the voltage across the 15Ω resistor that is in series with the parallel combination of 20Ω and 35Ω in a circuit powered by a 10V source.
Parallel resistanceThe parallel combination of the 20Ω and 35Ω resistors has a value of ...
(20)(35)/(20 +35) = 140/11 ohms
Voltage dropThe voltage across the 15Ω resistor is then ...
10(15/(15+140/11)) = 330/61 = 5 25/61 ≈ 5.41 . . . . volts
The voltage across the 15Ω resistor is about 5.41 volts.
How would an object’s kinetic energy change if it’s mass decreased by a factor of 3 and it moved 6 times faster?
Answer: Decreases in mass cause decreases in kinetic energy due to the aforementioned positive relationship between the two. Therefore when mass is decreased, an increase in kinetic energy is possible if velocity increases.
Answer:: Decreases in mass cause decreases in kinetic energy due to the aforementioned positive relationship between the two.
Consider an uncharged, conducting hollow spherical shell. The electric field on the inside surface of the spherical shell is measured to be directed toward the inner shell wall and varies in magnitude over the spherical shell's inside surface. It is known that the only charge in the hollow cavity inside the spherical shell is a point charge with magnitude q. What is the sign of the charge q?
Answer:
The sign of charge q is negative.
Explanation:
This is because electric field lines usually emanate from positive charges and terminate at negative charges. The negative charge in the hollow cavity induces a positive charge on the inner shell wall of the hollow shell which in turn induces the negative charge q on the hollow spherical shell.
Since the induced electric charge on the inner wall is positive, the electric field lines from that charge terminates at the inner charge q. Since electric field lines terminate only at negative charges, q is negative.
how do you change 6.1 ampres to milliamperes?
Answer:
How many ampere in 1 milliampere? The answer is 0.001.
We assume you are converting between ampere and milliampere.
You can view more details on each measurement unit:
ampere or milliampere
The SI base unit for electric current is the ampere.
1 ampere is equal to 1 ampere, or 1000 milliampere.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between amperes and milliamperes.
Type in your own numbers in the form to convert the units
Explanation:
Hope this helped :)
Three blocks of identical mass are placed on a frictionless table as shown. The center block is at rest, whereas the other two blocks are moving directly towards it at identical speeds v. The center block is initially closer to the left block than the right one. All motion takes place along a single horizontal line.
When three blocks of identical mass are placed on a frictionless table, with the center block at rest and the other two blocks moving directly towards it at identical speeds v, the center block will experience a collision. The center block will exert a force on both the left and right blocks, causing them to decelerate.
The left block will eventually come to a stop and reverse its direction, while the right block will continue to move towards the center block until it too comes to a stop. The distance traveled by each block before coming to a stop will depend on factors such as the initial distance between the blocks and the initial speed v.
In this scenario, the specific values of these factors are not provided, so a more precise answer would require additional information.
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Part one objects with masses of 207 kg and 516 kg are separated by 0.482 m. a 31.8 kg mass is placed midway between them. find the magnitude of the net gravitational force exerted by the two larger masses on the 31.8 kg mass. the value of the universal gravitational constant is 6.672 × 10−11 n · m^2/kg^2. answer in units of n. part two leaving the distance between the 207 kg and the 516 kg masses fixed, at what distance from the 516 kg mass (other than infinitely remote ones) does the 31.8 kg mass experience a net force of zero? answer in units of m.
It has been determined that the 31.8 kg mass experiences a net gravitational force of 1.129105 N from the two larger masses.
What is Magnitude?The absolute or relative direction or size of an object's motion in the sense of motion can be used to define magnitude. It is extensively utilized to convey something's size or scope. In physics, the term "magnitude" typically means "distance" or "quantity."
Elaborating:Take the right to be positive. Sum of forces on the 31.8 kg mass:
∑F = GM₁m / r₁² − GM₂m / r₂²
∑F = G (M₁ − M₂) m / r²
∑F = (6.672×10⁻¹¹ N kg²/m²) (516 kg − 207 kg) (31.8 kg) / (0.482 m / 2)²
∑F = 1.129×10⁻⁵ N.
Repeating the same steps, the second part this time ∑F = 0 and we're solving for r.
∑F = GM₁m / r₁² − GM₂m / r₂²
0 = GM₁m / r₁² − GM₂m / r₂²
GM₁m / r₁² = GM₂m / r₂²
M₁ / r₁² = M₂ / r₂²
516 / r² = 207 / (0.482 − r)²
516 (0.482 − r)² = 207 r²
516 (0.232 − 0.964 r + r²) = 207 r²
119.9 − 497.4 r + 516 r² = 207 r²
119.9 − 497.4 r + 309 r² = 0
r = 0.295 or 1.315.
It is found that r can't be greater than 0.482, so r must be equal to 0.295 m.
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Using the star finder according to the instructions given in lab and those listed on the previous page, complete each of the following: 4) Which zodiacal constellations are visible in the western sky at 6 am on January 25 ? The star finder is a device that aids in locating celestial objects when viewing the sky. Its design enables an observer to determine valuable information such as rising time, setting time, position, etc. The instructor will provide details during the lab time, but some information requires additional emphasis: - When using the star finder for actually locating celestial objects for viewing, it must be held overhead, with the compass points on the star finder matching the compass points in reality. (You may have noticed that east and west are reversed when looking down on the star finder.) - The entire star field contained within the open ellipse on the star finder represents the sky for the time and date shown. The edges of the ellipse correspond to the observer's horizon. - East and west are not located at the midpoint along the elliptical horizon between south and north. Because of the distortion involved in trying to map a threedimensional hemisphere onto a flat page, the east and west cardinal points are located north along the ellipse from their respective midpoints. - The zenth is located directly overhead for all observers and the zenith never moves. To locate and fix the position of the zenith, tape both ends of a piece of string between N and S (or noon and midnight) on the star finder, across the entire visible sky. Use an ink pen to place a dot on the string midway between the northern and southern horizons. Do not remove the string. The dot is the zenith. (Notice, as the sky moves, the zenith remains stationary and directly overhead.) - The brass rivet, about which the entire star field rotates, is the celestial north pole. Polaris happens to be located at this position. (In the real sky, all stars seem to wheel or revolve around this point.) The star finder is a device that aids in locating celestial objects when viewing the sky. Its design enables an observer to determine valuable information such as rising time, setting time, position, etc. The instructor will provide details during the lab time, but some information requires additional emphasis: - When using the star finder for actually locating celestial objects for viewing, it must be held overhead, with the compass points on the star finder matching the compass points in reality. (You may have noticed that east and west are reversed when looking down on the star finder.) - The entire star field contained within the open ellipse on the star finder represents the sky for the time and date shown. The edges of the ellipse correspond to the observer's horizon. - East and west are not located at the midpoint along the elliptical horizon between south and north. Because of the distortion involved in trying to map a threedimensional hemisphere onto a flat page, the east and west cardinal points are located north along the ellipse from their respective midpoints. - The zenith is located directly overhead for all observers and the zenith never moves. To locate and fix the position of the zenith, tape both ends of a piece of string between N and S (or noon and midnight) on the star finder, across the entire visible sky. Use an ink pen to place a dot on the string midway between the northern and southern horizons. Do not remove the string. The dot is the zenith. (Notice, as the sky moves, the zenith remains stationary and directly overhead.) - The brass rivet, about which the entire star field rotates, is the celestial north pole. Polaris happens to be located at this position. (In the real sky, all stars seem to wheel or revolve around this point.)
To determine which zodiacal constellations are visible in the western sky at 6 am on January 25, refer to the star finder and locate the corresponding positions on the celestial map.
The star finder is a helpful tool for locating celestial objects and obtaining information about the night sky. To use the star finder effectively, it should be held overhead with the compass points aligned to match the actual compass points. Keep in mind that east and west may appear reversed when looking down at the star finder.
The star finder consists of an open ellipse representing the sky for a specific time and date. The edges of the ellipse correspond to the observer's horizon. East and west are not located at the midpoint along the elliptical horizon due to the distortion caused by representing a three-dimensional hemisphere on a flat page. The east and west cardinal points are positioned north along the ellipse from their respective midpoints.
Locating the zenith is essential, as it is directly overhead for all observers and remains stationary. To find the zenith, tape both ends of a string between the north and south points on the star finder, spanning the entire visible sky. Mark a dot on the string midway between the northern and southern horizons using an ink pen. This dot represents the zenith.
By using the star finder and aligning it with the correct date and time, you can identify the zodiacal constellations visible in the western sky at 6 am on January 25. Simply locate the corresponding constellations on the star finder and observe their positions in the western region of the celestial map.
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You have a 100 ohm resistor. How
much resistance must you add in
parallel to the 100 ohm resistor to
create an equivalent resistance of
75.0 ohms?
Answer:
R2 = 300 Ohms
Explanation:
Let the two resistors be R1 and R2 respectively.
RT is the total equivalent resistance.
Given the following data;
R1 = 100 Ohms
RT = 75 Ohms
To find R2;
Mathematically, the total equivalent resistance of resistors connected in parallel is given by the formula;
\( RT = \frac {R1*R2}{R1 + R2} \)
Substituting into the formula, we have;
\( 75 = \frac {100*R2}{100 + R2} \)
Cross-multiplying, we have;
75 * (100 + R2) = 100R2
7500 + 75R2 = 100R2
7500 = 100R2 - 75R2
7500 = 25R2
R2 = 7500/25
R2 = 300 Ohms
Why do we see Moon phases?
Answer:
The moon its self does not generate life.
Explanation:
Moon phases are determined by the relative positions of the Moon, Earth, and Sun. Instead, the Moon's phase depends only on its position relative to Earth and the Sun. The Moon doesn't make its own light, it just reflects the Sun's light as all the planets do. The Sun always illuminates one half of the Moon.
{ hope this helps T-T }
Which statements best describe X-rays?
Answer:x rays are electromagnetic waves.
x rays are transverse waves
x rays travel at the speed of light
Explanation:
You climb up a ladder, which was 3.4 m in height, and fell. If your mass is 65.8 kg, how fast would your velocity be right before you hit the ground upon falling?
Answer:
Below
Explanation:
Your mass is irrelevant....here is why:
All of your POTENTIAL energy (mgh)
will be converted to KINETIC energy ( 1/2 m v^2)
so
mgh = 1/2 m v^2 divide both sides by 'm' <====then 'm' is gone !
gh = 1/2 v^2 now multiply by 2
2 gh = v^2 sqrt both sides
v = sqrt (2gh) = sqrt [ 2 ( 9.81)(3.4)] = 8.2 m/s
What are the primary features for the galaxy s23 series?
The primary features for the galaxy s23 series are as follows:
1. 5G Connectivity: As the first Samsung device with 5G connectivity, the Galaxy S23 series gives you access to lightning-fast download rates, reduced latency, and an enhanced mobile gaming experience.
2. Infinity-O Display: For a totally immersive experience, the Infinity-O Display offers a huge 6.7-inch curved Super AMOLED display with an almost bezel-less design.
3. Professional-Grade Camera: The triple pro-grade camera array on the Galaxy S23 series has a 64MP main sensor, a 12MP ultra-wide angle lens, and a 12MP telephoto lens.
4. Intelligent Battery: The Galaxy S23 series can intelligently optimise power consumption by learning from your usage habits and reducing power consumption to prolong battery life.
5. Wireless PowerShare: By inserting compatible devices on the rear of the Galaxy S23 series, you may wirelessly charge them with Wireless PowerShare.
6. IP68 Water and Dust Resistance: The Galaxy S23 series is dust and water resistant, earning the IP68 certification. As a result, it can survive 1.5 metres of water for up to 30 minutes.
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Complete the following sentence: How much you pay in taxes depends on _________________________.
Answer:
How much you pay in taxes depends on the amount of your taxable income
Explanation:
The total amount expected to be payed as taxes is a factor of the amount of taxable income earned within the given tax period.
The taxable income is found by subtracting the amount of deductions and exemption allowed in the tax year from the gross income. It is also specified as the adjusted gross income
The set marginal tax rate indicates the percentage of the taxable income that is to be paid as taxes, such that there are three different ranges or tax brackets and taxes are paid according to the bracket to which a taxable income belongs.
Una pelota recorre 20 m hacia la derecha y luego 10 m hacia la izquierda, todo en un lapso de tiempo de 10 s , cual es si velocidad y rapidez?
Answer:
v = 1 i ^ m / s, v = 1 m / s
Explanation:
In this problem we show the difference between vectors and scalars.
The average speed is
v = Δx / Δt
The bold are vectors
Δx = 20-10 = 10 i^ m
v = 10/10
v = 1 i ^ m / s
the unit vector indicates that the velocity is on the x-axis
The average speed is
v =Δx / Δt
v = 10/10
v = 1 m / s
in this case we have a scalar
1.32 light-years to miles (a light-year is an astronomical measure of the distance traveled by light in a year, or 365 days; the speed of light is 3.00 × 108 m/s)
The distance of 1.32 light-years is equal to approximately 7.816 × 10¹² miles.
This can be calculated using the speed of light, which is 3.00 × 10⁸ m/s. To convert light-years to miles, we can use the formula:
1 light-year = distance traveled by light in one year = speed of light × time (1 year)
Given that the speed of light is 3.00 × 10⁸ m/s, we can first convert the distance to meters by multiplying 1.32 light-years by the number of meters in a light-year:
1.32 light-years = 1.32 × (9.461 × 10¹² m/light-year) = 1.32 × 9.461 × 10¹² m= 1.2462 × 10¹³ m
Next, we can convert meters to miles by dividing by the number of meters in a mile:
1 mile = 1,609.34 m
Therefore, we have:
1.2462 × 10¹³ m ÷ 1,609.34 m/mi= 7.816 × 10¹² miles
Thus, 1.32 light-years is equal to approximately 7.816 × 10¹² miles.
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What is the density of a block of aluminum that has a volume of 15.0 cm³ and a mass of 40.5 g?
A: 2.7 g/cm³
B: 27 g/cm³
C: 27 grams
D: 2.7 grams
Answer:
A: 2.7 g/cm³
is correct answer
you live on an island in the pacific. an earthquake of magnitude 8.5 off the coast of japan, 8000 km away, generates a tsunami with a wavelength of 200 km. the average water depth between your island and japan is 4900 m. if a tsunami warning is issued for your island, how many hours will you have before the waves arrive?
If a tsunami warning is issued for the island, they will have approximately 11.7 hours before the waves arrive.
What is Magnitude?
Magnitude is a measure of the strength or intensity of a physical quantity or phenomenon, such as an earthquake or a sound wave. It is often expressed using a numerical scale, with higher values indicating greater strength or intensity. In the case of earthquakes, magnitude is typically measured using the Richter scale or the moment magnitude scale, which take into account the amplitude of seismic waves and the energy released by the earthquake.
To calculate the time it takes for a tsunami to travel from Japan to the island, we can use the following formula:
t = (2 * pi * d) / g * ln(1 + sqrt(h/d))
where t is the time it takes for the tsunami to travel, d is the average water depth, h is the wave height, and g is the acceleration due to gravity (9.8 m/s^2).
Magnitude of the earthquake: 8.5
Wavelength of the tsunami: 200 km = 200,000 m
Average water depth: 4,900 m
To calculate the wave height, we can use the following formula:
h = (M / 5) * (D / 10)^1/2
where M is the magnitude of the earthquake and D is the distance between the earthquake epicenter and the observation point (in this case, the island). Note that this formula is an approximation and may not be accurate for all cases.
Using the given values, we get:
D = 8,000 km = 8,000,000 m
h = (8.5 / 5) * ((8,000,000 / 10)^1/2) = 2,738.6 m
Substituting these values into the formula for t, we get:
t = (2 * pi * 4,900) / 9.8 * ln(1 + sqrt(2,738.6/4,900)) = 11.7 hours
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What are the advantages of a reflecting telescope over a refracting telescope?A. Mirrors can be made bigger than lenses in size.
B. No chromatic aberration.
C. In case parabolic mirror is used, then no spherical aberration.
D. Some light gets blocked inside the refracting telescope, but not reflecting telescope.
A. Mirrors can be made bigger than lenses in size.
B. No chromatic aberration.
C. In case parabolic mirror is used, then no spherical aberration.
D. Some light gets blocked inside the refracting telescope, but not reflecting telescope.
Therefore, all options are correct.
There are several advantages of a reflecting telescope over a refracting telescope:
A. Mirrors can be made bigger than lenses in size: One advantage of a reflecting telescope is that mirrors can be made much larger than lenses, which means that they can gather more light and provide a higher resolution image. This is because it is easier and less expensive to manufacture large mirrors than large lenses, which require much more precise and expensive machining.
B. No chromatic aberration: Another advantage of reflecting telescopes is that they do not suffer from chromatic aberration, which is a distortion of the image caused by different colors of light refracting at different angles through a lens. This is because reflecting telescopes use mirrors instead of lenses to focus light.
C. In case parabolic mirror is used, then no spherical aberration: Reflecting telescopes can also be designed to eliminate spherical aberration, which is a distortion of the image caused by the curvature of the lens or mirror. This is achieved by using a parabolic mirror, which can focus all incoming light to a single point without any distortion.
D. Some light gets blocked inside the refracting telescope, but not reflecting telescope: Finally, reflecting telescopes also have the advantage of not blocking any incoming light, as is the case with refracting telescopes. In a refracting telescope, the lens itself blocks some of the incoming light, which reduces the overall amount of light that can be gathered and can affect image quality.
Overall, these advantages make reflecting telescopes a popular choice for many astronomers and observatories, especially those that require large telescopes for studying deep space objects.
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Why do we weigh less in the equator rather than in poles ?
Give all the reasons for this situation
Answer:
There are a few reasons why we weigh slightly less at the equator compared to the poles. Here are the main factors contributing to this phenomenon:
1. Centrifugal force: The Earth rotates on its axis, causing a centrifugal force at the equator due to the circular motion. This force acts opposite to gravity and reduces the effective gravitational pull at the equator. As a result, we experience slightly less weight at the equator compared to the poles.
2. Earth's shape: The Earth is not a perfect sphere but rather an oblate spheroid, meaning it is slightly flattened at the poles and bulges at the equator. This shape is due to the rotation of the Earth. As a result of this oblate shape, the distance between the center of the Earth and any object is greater at the equator compared to the poles. Since gravitational force decreases with distance, the gravitational pull is slightly weaker at the equator.
3. Altitude variation: The Earth's surface is not perfectly uniform, and there are variations in elevation and altitude across different locations. The force of gravity decreases as we move farther away from the Earth's center. At the poles, we are closer to the center of the Earth compared to the equator, resulting in a slightly stronger gravitational pull at the poles. Hence, our weight is slightly higher at the poles due to the smaller distance from the center of the Earth.
It's important to note that these differences in weight are extremely small and difficult to perceive with regular scales. The variation is typically on the order of a few tenths of a percent, so it has a negligible impact on our daily lives.
what is an accretion disk, and what are its characteristics? select the true statements regarding accretion disks.
An Accretion disk is a rotating disk of matter, such as gas and dust, that forms around a central object, usually a star or a black hole. The matter in the disk is attracted by the central object's gravitational pull and gradually spirals inward, transferring angular momentum outward.
Some key characteristics of accretion disks are:
1. Temperature gradient: The inner regions of the disk are hotter due to higher density and gravitational compression, while the outer regions are cooler.
2. Density gradient: The density of the matter decreases as you move away from the central object.
3. Emission of radiation: Due to the friction between particles in the disk, it emits electromagnetic radiation, ranging from radio waves to X-rays depending on the temperature.
4. Conservation of angular momentum: As matter spirals inward, it transfers angular momentum outward, allowing the disk to maintain a stable rotation.
Select the true statements regarding accretion disks:
- Accretion disks form around a central object due to its gravitational pull.
- The inner regions of an accretion disk are hotter than the outer regions.
- Accretion disks emit electromagnetic radiation due to friction between particles.
- The conservation of angular momentum allows the disk to maintain a stable rotation.
These are accurate descriptions of an accretion disk and its characteristics.
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10.Un móvil recorre 26 m en el tercer segundo de su movimiento. Determinar la velocidad inicial del móvil, si su aceleración es de 8 m/s. AYUDA POR FAVOR
Answer: La velocidad inicial es 6m/s
Explanation:
Primero escribamos las ecuaciones de movimiento:
Sabemos que la aceleración es 8m/s^2.
a(t) = 8m/s^2.
Para obtener la velocidad, tenemos que integrar sobre el tiempo:
v(t) = (8m/s^2)*t + v0
donde v0 es la velocidad inicial.
Para la posición volvemos a integrar sobre el tiempo, y tenemos:
p(t) = (1/2)*(8m/s^2)*t^2 + v0*t + p0 = (4m/s^2)*t^2 + v0*t + p0
Donde p0 es la posición inicial.
Nosotros sabemos que en el tercer segundo, el móvil recorre 26m
Esto significa que:
p(3s) - p(2s) = 26m = (4m/s^2)(3s^2 - 2s^2) + v0(3s - 2s) + p0 - p0
26m = (4m/s^2)*5s^2 + v0*1s
De aquí podemos despejar el valor de v0:
26m = 20m + v0*1s
6m = v0*1s
v0 = 6m/s
If Europium (Eu) undergoes proton decay and loses 3 protons, which element will it become?
Answer:
Neodymium (Nd)
Explanation:
An element is made up of atom, which contains three subatomic particles namely; proton, electron, and neutron. In a neutral atom, the number of protons determines the atomic number of that element and the atomic number of an element is the identity of that element in the periodic table.
Hence, a change in the proton number of an element means a change in the atomic number and ultimately a change of that element. In this question, Europium (Eu) element with atomic number, 63, loses three protons. This means that that atom now has 60 protons, which denotes the atomic number of another element called Neodymium (Nd).
Therefore, Europium (Eu) element has become Neodymium (Nd) due to loss of protons.
In fig. p6.110 the pipe entrance is sharp-edged. if the flow rate is 0.004 m3/s, what power, in w, is extracted by the turbine?
The power extracted by the turbine can be calculated by multiplying the flow rate of 0.004 m3/s with the appropriate fluid power equation.
To determine the power extracted by the turbine, we need to use the fluid power equation. The fluid power equation relates the flow rate of a fluid, the pressure difference across the turbine, and the power extracted. In this case, we are given the flow rate of 0.004 m3/s.
To calculate the power, we need additional information such as the pressure difference or head across the turbine. Without this information or any additional context provided, it is not possible to directly determine the power extracted by the turbine.
The power extracted by a turbine is influenced by various factors, including the design of the turbine, the efficiency of the turbine, and the specific properties of the fluid being used. These factors would need to be considered and additional information provided to accurately calculate the power extracted.
It is important to note that the power extracted by the turbine represents the energy being converted from the fluid flow into mechanical work. The efficiency of the turbine will also play a role in determining the actual power output.
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what are the effects on the brain if you use this opioid
Answer:
Anxiety. Depression. Hypoxia, or lack of oxygen supply. Hyperalgesia, or sensitivity to pain.
Sophia was studying with Maalik about the layers of the Earth. They were given several different statements about the layers. Which statement about the layers would they identify as correct?
A-The outer core is less than 70 km in thickness.
B-The crust assists in forming Earth’s magnetic field.
C-The mantle is denser than the crust.
D- Pressure increases when moving from the core to the crust.
The statement about the layers of the Earth that both Sophia and Malik would identify as correct is: C. The mantle is denser than the crust.
Earth is one of the planets that rotates on its axis and revolves around the Sun. Also, planet Earth is the only planet known to harbor and support life.
Based on astronomical records, planet Earth comprises four (4) distinct layers starting at the center and these include:
The inner coreThe outer coreThe mantleThe crustThe mantle has a density of 4.5 \(g/cm^3\) while the crust has a density of 2.6 \(g/cm^3\) because temperature and pressure within planet Earth increases with depth.
In conclusion, the mantle is denser than the crust since it is made up of metals rather than solid rocks and minerals which are found within the crust.
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Answer:
c
Explanation:
A container gas expands to fill a 3l container has a mass of 129g what is its density
A container gas expands to fill a 3l container and has a mass of 129g its density is equal to 0.043 \(kgm^{-3}\)
Let's understand the answer in detail
Density is equal to the mass of a substance divided by its volume. The SI unit of density is Kg/m3. Other units of density are g/cm3, g/mL, kg/L
The formula we are using is going to be
D=m/v, where
D= density
m=mass
V=volume
The data that is given to us states that
mass = 129g
volume= 3 L
density = ?
Now we will put the values in the formula,
d= m/v
d = 0.129 Kg / 3L
d = 0.043 Kg / L
Therefore the density of the gas is 0.043 Kg / L.
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which of these is not a reason that astronomers believe jupiter and saturn failed to fall in further toward the early sun? Answer choicesThe later formation of Saturn created a mutual tug-of-war transferring energy between the planets.The two planets together were able to clear much remaining debris from their orbits, greatly lessening the drag force on the planets.A nearby passing star was able to gravitationally pull the two gas giants toward the outer parts of the solar system by countering the gravity of the early protosun.The two planets were able to fling a great deal of debris into the inner solar system, driving themselves toward the outer solar system due to conserved angular momentum.
A nearby passing star was able to gravitationally pull the two gas giants toward the outer parts of the solar system by countering the gravity of the early protosun.
What do you mean by gravity?Gravity is a force that acts between two masses and attracts them towards each other. It is the force that keeps the planets in orbit around the sun and the moon in orbit around the Earth. The strength of the gravitational force between two objects depends on their masses and the distance between them. The basic idea behind gravity was first described by Sir Isaac Newton in his law of universal gravitation, which states that every object in the universe attracts every other object with a force proportional to the product of their masses and inversely proportional to the square of the distance between them.
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Draw a dot diagram of an object moving at constant speed to the right
The dot diagram of an object moving at constant speed to the right is in the diagram uploaded.
What is constant speed?
Constant speed refers to a situation in which an object moves in such a way that its rate of change of position is the same at all times. This means that the object is covering an equal distance in equal intervals of time.
In other words, it moves with a uniform velocity, meaning that its speed does not change.
For example, if a car is traveling at a constant speed of 60 miles per hour, it covers 60 miles in each hour of its journey, regardless of whether it has been traveling for 1 hour or 5 hours.
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a heat engine is operating between 287 c and 32 c. if the engine extracted 400 mj of energy from fuel, how many mj of energy could be used as mechanical energy?
A heat engine is operating between 287 c and 32 c. if the engine extracted 400 mj of energy from fuel, 4109.6 Jews mj of energy could be used as mechanical energy
Using the temperatures, a heat engine's efficiency is determined (lowest and highest).
The ratio of the system's provided heat to the desired work is considered the system efficiency. An engine's efficiency ranges from 0 to 1.
The efficiency of the engine is 27%, or 0.27. Since the heat was turned down due to the 3000 gems, we must find productive employment. Heat input and network efficiency are connected. That is the line. Qc was rejected by two W plus heat, leading to Qh. The cost of networking is composed of Nita W and Nita Qc. The network completed is identical to Nita. Q C is split into two halves. As a result, we must divide our efficiency, which is 0.27, by 3000. The engine's work is represented by this. Let's calculate the result of 0.27 multiplied by 3000 divided by 1. 1109 and 0.6 gems are the answer. He rejected our quote, which is +110 9.6 plus three thousand. 4109.6 Jews is quite close to the heat input.
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can someone please help me
A blank graph grid is 20 boxes by 20 boxes. You want to plota data set on this graph. The range ofx-axis values is 0–60.The range ofy-axis values is 0–15. Sketch the best scale touse that would maximize the graph size.
The rule for a good graph can be found that the scales in for the two axes are
x-axis 3 values / box y-axis 0.75 values / box
Graphical representation is the best method to visualize a set of data and understand the relationship between them.
A good graph must ensure that the data occupies the largest possible part of the sheet and the resolution is such that errors can be visualized.
The way to make a good graph must comply with:
The best range where the values occupy the maximum of paper. Let's use the relationRange = \(\frac{Value_{final} - Value_{initial} }{boxes}\)
Where Value area the experimetla value, boxes are the division grid.
If the value is fractional it must be close to the following value, for example the range is 0.95 it must be close to 1 If the data is very large or small use scientific notation If the model contemplates the zero crossing, it should be included in the graph
In this case the paper divisions are 20 boxes on each axis, let's find the range
x-axis
Rₓ = \(\frac{60-0}{20}\)60-0 / 20
Rₓ = 3
y-axis
\(R_y\) = \(\frac{15 -0 }{20}\)15-0 / 20
\(R_y\) = 0.75
In the attachment we have a diagram of the axes of the graph, to avoid that the values are very saturated, some have been placed in a spaced way.
In conclusion using the rules for a good graph we can find that the scales in for the two axes are
x-axis 3 values / box y axis 0.75 values / box
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