a 4kg ball started rolling from rest on top of a 4m high ramp. what is the velocity of the ball at the bottom of the ramp?

Answer:

a) The frequency of the third harmonic is 786 Hz

b) The frequency of the first harmonic is 340 Hz

c) The frequency of the fifth harmonic is 1640 Hz

Explanation:

The rule is as follows:

If the first harmonic frequency (also called the fundamental frequency) is F, then:

The frequency of the second harmonic (also called the second overtone) is:

2*F

The frequency of the third harmonic (also called the third overtone) is:

3*F

And so on.

With this information, we can answer the questions:

a) We want to find the frequency of the third harmonic, such that the frequency of the first harmonic is 262 Hz.

Then we have F = 262Hz

And the frequency of the third harmonic will be:

3*F = 3*262Hz = 786 Hz

b) First harmonic for a string whose fifth harmonic frequency is 1700Hz.

Let's define F as the first frequency (the one we want to find)

Then the fifth harmonic frequency can be written as:

5*F = 1700Hz

With this equation we can find the value of F:

F = 1700Hz/5 = 340Hz

c) We want to find the fifth harmonic for a string whose third overtone (this is the same as the third harmonic) frequency is 984 Hz.

Then if the frequency of the first harmonic is F, we know that:

3*F = 984 Hz

With this we can find the value of F:

F = 984 Hz/3 =328 Hz

Now that we know the frequency of the first harmonic, we can find the frequency of the fifth harmonic:

5*F = 5*328 Hz = 1640 Hz

If the resistance remains constant and the voltage doubles, the power will increase by a factor of 4 (option E)

The following data were obtained from the question:

P = V² / R

Resistance is constant, we have

V₁² / P₁ = V₂² / P₂

V² / P = (2V)² / P₂

V² / P = 4V² / P₂

Cross multiply

V² × P₂ = P × 4V²

Divide both side by V²

P₂ = P × 4V² / V²

P₂ = P × 4

From the above, we can conclude that the power will increase by a factor of 4 (option E)

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Antonio will need a pipette to measure 15 ml of distilled water in a laboratory.

A pipette is a laboratory equipment used in measuring liquids in little amounts. 15 ml is a small amount of liquid so a pipette is a better fit for such amount.

We can conclude that a pipette is a better instrument to measure 15 ml of distilled water.

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Acceleration = (change in speed) / (time for the change)

Change in speed = (speed after the change) - (speed before the change)

Change in speed = (65 m/s) - (35 m/s)  =  30 m/s

Acceleration = (30 m/s) / (5 s)

Acceleration = 6 m/s²

In conclusion, rocket-powered sleds are used to test human responses to acceleration. In this case, one sled can reach a speed of 444 m/s in 1.80 s and can be brought to a stop again in 2.15 s. By calculating the acceleration and deceleration, we can analyze the sled's performance during these phases.

Rocket-powered sleds are used to test the responses of humans to acceleration. In this scenario, one sled starts from rest and reaches a speed of 444 m/s in 1.80 s. It is then brought to a stop again in 2.15 s.
To analyze this situation, we can calculate the sled's acceleration during the initial phase of reaching its top speed and during the deceleration phase when it comes to a stop.
1. First, let's calculate the acceleration during the initial phase using the formula:
  acceleration = change in velocity / time
  The change in velocity is 444 m/s (the sled's final speed) minus 0 m/s (its initial speed), which gives us 444 m/s. The time taken is 1.80 s.
  Therefore, the acceleration during the initial phase is:
  acceleration = 444 m/s / 1.80 s
2. Next, let's calculate the deceleration during the stopping phase using the same formula:
  The change in velocity is 0 m/s (the sled's final speed) minus 444 m/s (its initial speed). The time taken is 2.15 s.
  Therefore, the deceleration during the stopping phase is:
  deceleration = -444 m/s / 2.15 s
  The negative sign indicates that the sled is decelerating or slowing down.
In conclusion, rocket-powered sleds are used to test human responses to acceleration. In this case, one sled can reach a speed of 444 m/s in 1.80 s and can be brought to a stop again in 2.15 s. By calculating the acceleration and deceleration, we can analyze the sled's performance during these phases.

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When one object applies a force to another, the second item responds by applying an equal and opposite force to the first.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

An opposing force to an action force is referred to as a reaction force. The response force that results from surface engagement and adhesion while sliding is known as friction.

When one object applies a force to another, the second item responds by applying an equal and opposite force to the first.

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Answer:

c or a Hope's that helps but I think it's c

Explanation:

byeeeee

Cody needs to stretch the slingshot back more which would increase the amount of potential energy of the rock to make it reach the can and knock it down, therefore the correct answer is option A.

The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.

The expression for total mechanical energy can be given as follows

ME= PE + KE

As given in the problem Cody is using a slingshot and rock to knock down a can that he has placed on a tree stump. His first attempt fails because he realizes the rock didn't go far enough.

Potential energy represents the energy stored in the system, so stretching the slingshot back more would increase the potential energy stored in the rock.

Thus, Cody needs to stretch the slingshot back more, therefore the correct answer is option A.

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The magnifuse of the werage frictional force (in t ) that is exerted on the bullet while it is moving throogh the tree trunk Frictional force = (1/2)mv^2 / (0.01 m)  the moment the bullet enters the eree truck and the moreent it moos maving5.4 m = Average velocity * Time

(a) To find the magnitude of the average frictional force exerted on the bullet while it moves through the tree trunk, we can use work and energy considerations.

The work done by the frictional force is equal to the change in kinetic energy of the bullet. The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy.

The initial kinetic energy of the bullet is given by (1/2)mv^2, where m is the mass of the bullet and v is its initial velocity.

The final kinetic energy of the bullet is zero since it comes to rest inside the tree trunk. Therefore, the work done by the frictional force is equal to the initial kinetic energy of the bullet.

The magnitude of the average frictional force is then given by:

Frictional force = Work done / Distance

Since the distance traveled by the bullet inside the tree trunk is given as 540 cm, we convert it to meters (1 cm = 0.01 m).

Frictional force = (1/2)mv^2 / (0.01 m)

Substituting the given values, we can calculate the magnitude of the average frictional force.

(b) To calculate the time elapsed between the moment the bullet enters the tree trunk and the moment it comes to rest, we can use the equation of motion that relates average velocity, time, and distance traveled. The equation is:

Distance = Average velocity * Time

Since the bullet comes to rest inside the tree trunk, the distance traveled is equal to the depth of penetration, which is given as 540 cm (converted to meters as 5.4 m).

Substituting the given values, we can solve for time:

5.4 m = Average velocity * Time

Rearranging the equation, we can calculate the time elapsed.

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1/Rt = 1/R1 + 1/ R2 ......n.....

1/Rt= 1/5ohm + 1/10ohm + 1/15ohm +1/20ohm

1/Rt= 12ohm + 6ohm + 4ohm +3ohm

60.

1/Rt = 25 ohm

60

Rt= 60

25

Rt= 2.4 ohm.

note: Rt is equivalent resistance.

Answer:

Yes

Explanation:

An atom is made up of itself. Yes this is crazy but true. So far we have found the universe is everlasting, and the universe is part of itself meaning there nothing outside, except heaven and hell

Jonathan should perform 30 minutes of jogging to reach the recommended moderate aerobic activity in a week.

The total activity performed till the mentioned time of week = 120 minutes

The total amount of moderate aerobic activity needed in a week = 150 minutes

So, to calculate the remaining amount of time, we will perform subtraction

Hence, performing subtraction to find the jogging time needed

The amount of time required to reach the recommended moderate aerobic activity in a week = 150 - 120

The amount of time required to reach the recommended moderate aerobic activity in a week = 30 minutes

Therefore, 30 minutes jogging is required.

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Answer:According to the context, its nucleus breaks apart is an event that occurs when an atom undergoes nuclear fission.

Explanation:

The work done lifting a \(2-m\) chain over the side of a building is:

Work = force × distance

Since the force required to lift the chain is equal to its weight (mg), the work done lifting the chain is:

work = \(5 Kg/m 2 m 9.8 m/s2\)

work = \(98 J\)

In physics, the term "work" refers to the measurement of energy transfer that takes place when an item is moved over a distance by an external force, at least a portion of which is applied in the direction of the displacement. By multiplying the length of the path by the component of the force acting along the path, work can be calculated if the force is constant. Work is done on a body in a variety of ways, such as by compressing a gas, rotating a shaft, or even by employing an external magnetic force to move particles within a body without their conscious awareness. Work is also completed by moving the body as a whole from one location to another.

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Astronomers can characterize a planet's atmosphere in absorption via Optioin d. astrometry and the doppler method

For transiting planets, astronomers can obtain valuable information about the atmosphere, surface temperature, and size of the planet. For most Sun-like stars, an orbiting planet that is itself the size of a brown dwarf only reduces the star's brightness to a few percent or less during transit.

Most known exoplanets have been discovered using the transit method. A transit occurs when a planet passes between a star and its observer. As Venus or Mercury moves between us and the Sun, transits within the solar system can be observed from Earth.

A transiting exoplanet's atmosphere can be observed backlit by the star as it passes its host star. Additional atmospheric observations can be made by watching exoplanets disappear and reappear behind their stars.

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Disclaimer:- your question is incomplete, please see below for the comlete question.

Astronomers can characterize a planet's atmosphere in absorption via group of answer choices

a. transits only

b.  transits and the doppler method

c. the doppler method direct imaging

d. astrometry and the doppler method

calorimeter with iron will have the higher temperature at thermal equilibrium.

The particular heat capacity (symbol c) of a material in thermodynamics is the heat capacity of a sample of the substance divided by the mass of the sample, also known as massic heat capacity. Informally, it is the quantity of heat that must be added to one unit of mass of the substance to generate one unit of temperature increase. Specific heat capacity is measured in joules per kelvin per kilogramme, or J⋅kg−1⋅K−1,  The heat required to increase the temperature of 1 kilogramme of water by 1 K, for example, is 4184 joules, hence the specific heat capacity of water is 4184 J⋅kg−1⋅K−1. calorimeter with high specific heat  have the higher temperature at thermal equilibrium.

In this problem, specific heat of lead is 120 J/kg.°C. and that of iron is  450 J/kg°C.

if the both elements are heated from room temperature 25°C to 100°C,

Total heat contained in lead is,

Q = cmΔT = 120×0.05kg×75°C = 450 J

Total heat contained in iron is,

Q = cmΔT = 450×0.05kg×75°C = 1687 J

Specific heat of the water is 4.2 J/g°C.

Temperature of the calorimeter due to lead

T₂ - T₁ = Q/cm = 450/4.2×100

T₂ - 25 = 1.07

T₂ = 1.07 +25 = 26.07°C

Temperature of the calorimeter due to iron

T₂ - T₁ = Q/cm = 1687 /4.2×100

T₂ - 25 = 4.01

T₂ = 4.01 + 25 = 29.01 °C

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Answer:

option C) the iris

Explanation:

2023

The measure of the output produced per unit of an input is called "marginal product."

In economics, the concept of marginal product refers to the additional output that is generated by increasing the quantity of a particular input while keeping all other inputs constant.

It is calculated by dividing the change in total output by the change in the quantity of the input. Marginal product helps us understand the rate of change in production as inputs are increased or decreased.

For example, let's consider a factory that produces widgets. If the factory hires an additional worker and experiences an increase in output, the marginal product of that worker would be the additional number of widgets produced due to their contribution.

The concept of marginal product is essential for firms to determine the optimal level of input usage, as it helps them evaluate the productivity of each additional unit of input and make informed decisions regarding resource allocation.

In summary, the measure of output produced per unit of input is referred to as the marginal product, which helps assess the incremental productivity gained from additional units of input in a production process.

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x for a smaller magnet at the position marked zin

Answer:

The ray box used as the source of light

Answer: its A

Explanation: i just did the test and got it right also known. The ray used as the source of light

a)The aperture size of the radio telescope needs to be approximately 0.27 meters b)The aperture of a radio telescope needs to be much larger than that of an optical telescope because radio waves have much longer wavelengths compared to visible light. c)the resolving power of a telescope depends on the ratio of the wavelength of light.

a. To determine the aperture size of a radio telescope to achieve a resolution at 21 cm, we can use the Rayleigh criterion, which states that the minimum resolvable separation (δθ) is given by:

δθ = 1.22 * (λ / D)

Where λ is the wavelength of the radiation and D is the diameter of the telescope's aperture.

Given that the radio wavelength is 21 cm (or 0.21 m), and we want to achieve the same resolution as the optical telescope (1 second of arc), we can rearrange the formula to solve for D:

D = 1.22 * (λ / δθ)

D = 1.22 * (0.21 m / 1 second of arc)

Calculating the result:

D ≈ 0.27 m

Therefore, the aperture size of the radio telescope needs to be approximately 0.27 meters to achieve a resolution of 1 second of arc at a wavelength of 21 cm.

b. The Rayleigh criterion tells us that the resolution of an instrument is inversely proportional to the wavelength.

Since radio waves have longer wavelengths, the telescope's aperture needs to be larger to achieve the same resolution as an optical telescope. This is because a larger aperture collects more incoming waves and allows for finer spatial detail to be resolved.

c. The ability to resolve two objects using a telescope depends on the size of the aperture relative to the wavelength of the radiation. When it comes to resolving stars, the resolving power of a telescope depends on the ratio of the wavelength of light to the size of the telescope's aperture (λ/D).

Blue light has a shorter wavelength compared to red light. Since the resolving power is directly proportional to the wavelength, a shorter wavelength of blue light allows for better resolution.

Therefore, two predominantly blue stars can be resolved because their shorter wavelength allows for finer detail to be distinguished, while the same separation between two predominantly red stars cannot be resolved due to the longer wavelength.

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In astronomy, a standard candle is an object with a known luminosity or absolute magnitude, used to measure distances to other celestial objects.

By comparing the known luminosity of the standard candle to its observed brightness from a distance, astronomers can calculate the distance to the object based on the inverse square law of light. This technique is often used in cosmology to measure the distances to faraway galaxies and to estimate the size and age of the universe. Some examples of standard candles in astronomy include Cepheid variable stars, Type Ia supernovae, and certain types of galaxies.

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Answer:

Normative social influence

Explanation:

:Normative social influence

True

In place of photographic plates or films, charge coupled devices, or CCDs, are sensitive photon detectors that can be employed in telescopes to create images. CCDs were created in the late 1960s and are now found in various devices, including digital cameras and photocopiers.

CCDs are more light-efficient, catch a greater proportion of incoming photons, can store and transfer digital data, and don't require development like film does. They respond linearly and capture up to 80% of the light that strikes them.

I understand the question you are looking for is this:

One of the primary advantages of CCDs over photographic plates is the former's high efficiency in detecting light. True or false.

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Answer:

The golf ball has a greater mass than the foam ball

Explanation:

Answer: Friction that acts on a sliding object

Explanation:

To calculate resistance, we will use the formula:

R = ρl / A

where ρ(rho) is the resistivity of the material, l is the length of the wire and A is the cross-sectional area

We are given:

Length of wire (l) = 0.65 m

Diameter of wire (d) = 2 mm

Material of wire: Copper

Some important conversions:

- radius of the wire = diameter/2

 radius = 2 mm/2 = 1 mm  OR 1 * 10⁻³m

Calculating the cross-sectional area:

Cross-sectional area is the area of the circle at the end of the wire.

Cross-sectional area = π(r²)

Area = π(1 * 10⁻³)²                                         [replacing the value of r]

Area = π * 10⁻⁶ m²

Calculating the resistance:

using the formula mentioned before:

R = ρl / A

R = \((1.7 * 10^{-8}ohm*m ) * \frac{0.65 m}{3.14 * 10^{-6}m^{2}}\)        [resistivity of copper = 1.7 × 10⁻⁸ Ωm]

R = 3.52 * 10⁻³ (approx)

Answer:

3.5 × 10⁻³ Ω

Explanation:

The resistance of a conductor is calculated by the formula:

Let's start by converting the diameter of the copper wire to meters.

Since we want the radius of the cross-section, we will divide .002 m by 2.

The radius of the copper wire is .001 m. We can calculate the area of the circular cross-section by using the formula:

The area of the cross-section is π · 10⁻⁶ m².

The length of the wire is 0.65 m long. We do not have to convert units for the length of the wire since it is already in the SI units: meters.

Assuming the copper wire is at 20°C, we know that its resistivity is 1.7 · 10⁻⁸ Ω · m.

Using these three variables, we can solve for R in the formula for electric resistance.

Substitute these values into the equation.

Notice how the unit m² cancels out, leaving us with Ω (units of electrical resistance).

The electric resistance of a copper wire 0.65 m long with a radius of .001 m is .0035 ohms (Ω), or 3.5 × 10⁻³ Ω.

With the use of Ohm's law formula and some assumption, the answers are

(a) V2 = 30v

(b) I2 = 5 A

(c) R1 = 1 Ω

(d) R2 = 6 Ω

(e) RT = 4 Ω

Current can simply be defined as the rate at which charges flow in a conducting material. It is measured in Ampere.

From the given circuit,

a) V2 and V3 are in parallel, so they will have the same voltage. The voltage dropped in V1 should be taken away from the total voltage. That is,

V2 = VT - V1

V2 = 40 - 10

V2 = 30v

b) The current produced from the battery is assumed to split equally on R2 and R3. Therefore, I2 = 5 A

c) The total current will flow through I1. That is,

I1 = 10 A

Using Ohm's law V1 = I1 × R1

10 = 10 × R1

R1 = 10/10

R1 = 1 Ω

d) From Ohm's law, V2 = I2 × R2

30 = 5R2

R2 = 30/5

R2 = 6 Ω

e) By using Ohm's law again

VT = IT × RT

40 = 10 × RT

RT = 40/10

RT = 4Ω

Therefore, The resistance in R1, R2 and R3 are 1Ω, 6Ω and 6Ω

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