a 35-kg child sleds down a hill and then coasts along the flat section at the bottom, where a second 35-kg child jumps on the sled as it passes by her. if the speed of the sled is 3.5 m/s before the second child jumps on, what is its speed after she jumps on?

Answers

Answer 1

The speed of the sled after the second child jumps on will be 2.33 m/s.

In this problem, we can apply the conservation of momentum principle.

Before the second child jumps on the sled, the sled has a momentum of mv, where m is the mass of the sled and v is its velocity.

After the second child jumps on, the sled has a momentum of (m + m)v', where v' is the velocity of the sled after the second child has jumped on.

To apply the conservation of momentum principle, we can equate the initial momentum to the final momentum. We get:mv = (m + m)v'Substituting the values given in the problem, we get:35 kg x 3.5 m/s = (35 kg + 35 kg) x v'Solving for v', we get:v' = 2.33 m/s

Therefore, the speed of the sled after the second child jumps on will be 2.33 m/s.

Summary: A sled with a mass of 35 kg sleds down a hill and then coasts along the flat section at the bottom, where a second 35-kg child jumps on the sled as it passes by her. The speed of the sled is 3.5 m/s before the second child jumps on. The speed of the sled after the second child jumps on will be 2.33 m/s.

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Related Questions

before entering the auditory canal, sound waves are funneled into the outer ear via the ____.

Answers

Before entering the auditory canal, sound waves are funneled into the outer ear via the pinna.

The pinna, also known as the auricle, is the visible part of the outer ear that protrudes from the side of the head. It is composed of cartilage and skin, and its shape helps to collect and direct sound waves into the auditory canal, which leads to the middle ear. The pinna also helps to distinguish the direction and location of sounds, as its shape and orientation can affect the way that sound waves are reflected and amplified. In some animals, such as cats and dogs, the pinna can be moved independently to help them better locate the source of a sound.

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1. What type of energy transformation best fits what happens in a paper shredder?

Answers

Answer:

electrical- mechanical

Explanation:

Smartness 1,000

Friend me too

At the center, 6 unmarked red balls are interspersed with 4 blue balls marked with plus signs. A green cloud with 2 concentric white lines surrounds the center, with 2 small green balls marked with minus signs on the inner white line and 2 small green balls marked with minus signs on the outer white line. How many neutrons does this atom have? 4 6 10 14

Answers

Answer:

10

Explanation:

Amu denotes for unified atomic mass.

it is mostly used to define the atom's mass and molecules.

we know that

One unit of amu is 1 ÷ 12 of the mass of a nuclide 12C

And 1 u = 1.660 538 921 × 10-27 kg

In the inside we can found that there is 10 nucleons so here the alss of the atoms would be 10 amu  

Answer:

guy above me is right

Explanation:

The acceleration of gravity on planet Y is 14.4 m/s/s. An object has a mass of 42.2 kg. What would be its weight on planet Y?
Weight
Help Links
N

Answers

Answer:

607.68N [weight on planet Y]

Explanation:

Using the formula

\(w = mg\)

Where w is the weight, m is the mass and g is the gravity.

Gravity (g) on planet Y is 14.4 m/s/s

Object has a mass (m) of 42.2 kg

Weight (w) on planet Y is w

-

NOTE: '' MEANS MULTIPLICATION

NOTE: WEIGHT IS MEASURED IN NEWTONS (N)

-

Inputing the values into the formula, and solving it...

w = mgw = 42.2 • 14.4w = 607.68

== 607.68N [weight on planet Y]

how do atoms lose electrons ?

Answers

Atoms lose electrons by a process called ionic bonding. Specifically, the metal atom donates its electron to a non-metal atom and thus takes on the noble gas electron configuration of the noble gas in the period (row of the periodic table) preceding its own.

Answer:

Explanation:

By being close to an atom that will gladly take the electrons being offered.

Suppose you are talking about Be. It is in the second column. It has two outer electrons that can be given away. It will not give away one of the two remaining electrons because they are too close to the + nucleus.

Along comes a Fluorine atom. It has 7 electrons in its outer ring. The chemistry of the situation allows it to take on one of the two electrons Be is offering. It is all a matter of charges and attractions.

Another Fluorine atom will take on the remaining electron from the Be. The outer ring cannot take on more than 1 electron, but that is enough

Assuming the cross-sectional area of the Earth to be about 1.28×10^18 cm2, what is the total annual amount of incoming energy? Express your answer using three signifioant figures.

Answers

Expressing the answer using three significant figures, the total annual amount of incoming energy on Earth is approximately 1.74×10¹⁹ Watts.

To calculate the total annual amount of incoming energy on Earth, it is required to consider the solar constant, which represents the amount of solar energy received per unit area outside the Earth's atmosphere. The solar constant is approximately 1361 Watts per square meter (W/m²).

First, it is required to convert the Earth's cross-sectional area from cm² to m².

1.28×10¹⁸ cm² = 1.28×10¹⁶ m²

Total annual incoming energy = Solar constant × Earth's cross-sectional area

Total annual incoming energy = 1361 W/m² × 1.28×10¹⁶ m²

Total annual incoming energy ≈ 1.74×10¹⁹ Watts

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Which of the following is a primary source?

Which of the following is a primary source?

Answers

The answer is C :), I think.

A scientific paper is the primary source. A primary source is an item, document, recording, or any other source. Option C is correct.

What is a scientific paper ?

Scientific papers are a specific sort of written work with certain characteristics: they are often published in a periodical called a journal, whose sole objective is to publish this type of work.

A primary source is an item, document, recording, or any other source of information created during the period being studied in the academic area of history.

A scientific paper is the primary source.

Hence,option C is correct.

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that is a difference between a law and a hypothesis?
A law describes how two variables affect each other, but a hypothesis only discusses one variable.
A law must be testable so that it can be proven, but a hypothesis is an untestable explanation.
A hypothesis includes an explanation for why two variables affect each other, but a law only describes how they
affect each other
A hypothesis may or may not be testable, but a law is an untestable explanation of why two variables affect each
other and cannot be proven

Answers

Answer:

A hypothesis is a limited explanation of a phenomenon; a scientific theory is an in-depth explanation of the observed phenomenon.

A law is a statement about an observed phenomenon or a unifying concept, according to Kennesaw State University. ... However, Newton's law doesn't explain what gravity is, or how it works.


Find the average speed of a car that is travelling 45 km in 5 hours. *
4 points
6 km/h
8 km/h
9 km/h
20 km/h​

Answers

Answer:

9 km/h

Explanation:

Speed can be found using the following formula.

s=d/t

where d is distance and t is time.

The car traveled 45 kilometers in 5 hours.

d=45 km

t=5 h

Substitute these values into the formula

s=45 km/5 h

Divide 45 by 5

s=9 km/h

The average speed of the car is 9 kilometers per hour.

The answer would be 9 ! Hope this helps !

A brass rod and an iron rod differ in length by 28cm at 20°C. What should be the original length of the iron rod for the difference in length to remain the same when both rods are heated to 90°C? Linear expansivity of brass=1.9×10^-5. Linear expansivity of iron=1.2×10^-5.

Pls show workings.

Answers

Answer:

The original length of the iron rod is approximately 572.189 meters.

Explanation:

This is a case of linear expansion, which is defined by the following differential equation:

\(\alpha = \frac{1}{L}\cdot \frac{dL}{dT}\) (1)

Where:

\(\alpha\) - Linear expansion coefficient, measured in \(\frac{1}{^{\circ}C}\).

\(L\) - Length of the element, measured in centimeters.

\(\frac{dL}{dT}\) - First derivative of the length of the element with respect to temperature, measured in centimeters per degree Celsius.

If we assume that thermal deformation are small regarding the length of the element, then we simplify (1) in the following form:

\(\alpha \approx \frac{\Delta L_{o}}{L\cdot \Delta T}\)

\(L_{f} -L_{o} = \alpha \cdot L_{o} \cdot \Delta T\)

\(L_{f} = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})]\) (2)

Where:

\(L_{o}\), \(L_{f}\) - Initial and final lengths of the element, measured in centimeters.

\(T_{o}, T_{f}\) - Initial and final temperatures of the element, measured in degrees Celsius.

Given that brass has a higher coefficient of linear expansion, it is suppose that initial length is less than the initial length of the iron element. Then, we have the following system of linear equations:

Brass

\(L = L_{o}\cdot [1+\alpha_{B}\cdot (T_{f}-T_{o})]\) (3)

Iron

\(L = (L_{o}+28)\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\) (4)

Where \(\alpha_{B}\), \(\alpha_{I}\) are coefficients of linear expansion of brass and iron, measured in \(\frac{1}{^{\circ}C}\).

By equalizing (3) and (4), we have the following formula:

\(L_{o} \cdot [1+\alpha_{B}\cdot (T_{f}-T_{o})] = (L_{o}+28)\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\)

\(L_{o} \cdot (\alpha_{B}-\alpha_{I})\cdot (T_{f}-T_{o}) = 28\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\)

\(L_{o} = \frac{28\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]}{(\alpha_{B}-\alpha_{I})\cdot (T_{f}-T_{o} )}\)

If we know that \(\alpha_{B} = 1.9\times 10^{-5}\,\frac{1}{^{\circ}C}\), \(\alpha_{I} = 1.2\times 10^{-5}\,\frac{1}{^{\circ}C}\), \(T_{o} = 20\,^{\circ}C\) and \(T_{f} = 90\,^{\circ}C\), then the initial length of the iron rod is:

\(L_{o} = \frac{28\cdot [1+\left(1.2\times 10^{-5}\,\frac{1}{^{\circ}C} \right)\cdot (90\,^{\circ}C-20\,^{\circ}C)]}{\left(1.9\times 10^{-5}\,\frac{1}{^{\circ}C}-1.2\times 10^{-5}\,\frac{1}{^{\circ}C} \right)\cdot (90\,^{\circ}C-20\,^{\circ}C)}\)

\(L_{o} = 57190.857\,cm\)

\(L_{o, I} = 57218.857\,cm\)

\(L_{o,I} = 572.189\,m\)

The original length of the iron rod is approximately 572.189 meters.

an art student is designing a large mobile with the dimensions shown below. object c has a mass of 1 kg, and objects b and c are in balance. what does the mass of object a need to be to balance objects b and c?

Answers

The mass of object a need to be to balance objects b and c is 12kg

Find man of b

1=\(\frac{m_{c}}{m_{b}+m_{c}}\)×4

1=\(\frac{1}{1+m_{b} }\)×4

\(m_{b}\)=3kg

1=\(\frac{(m_{b}+m_{c} )}{m_{a} +(m_{b} +m_{c} )}\)  ×4

1=4×4/\(m_{a}\)+4

\(m_{a}\)=12kg

As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilogram is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one-kilogram times one square meter per second. The kilogram is determined by precise measurements of Planck's constant, while the second and metre are previously defined in terms of other physical constants.

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throw a small ball (best a golf ball) straight upward as hard as you can. your friend can measure the time of flight of the ball using a stop watch. find the initial speed of your throw and the approximate maximum height of the ball solely with the use of the measured time. please write here the equations you are using:

Answers

To find the initial speed of the throw and the approximate maximum height of the ball using the measured time of flight, we can use the equations of motion for projectile motion. the ball is thrown straight upward, the initial velocity in the vertical direction is equal to the magnitude of the initial speed. Here are the relevant equations:

Equation for the time of flight (t): t = 2 * (initial velocity in the vertical direction) / (acceleration due to gravity) Equation for the maximum height (h): h = (initial velocity in the vertical direction)^2 / (2 * acceleration due to gravity) Since the ball is thrown straight upward, the initial velocity in the vertical direction is equal to the magnitude of the initial speed. Let's denote the initial speed as V₀. Using these equations, we can solve for V₀ and h using the measured time of flight (t) provided by your friend.

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a flotation buoy has mass 803 kg, volume 1.09 m3, and is attached to the sea floor by a cable in such a way that the buoy is completely submerged. calculate the magnitude of the tension in the cable, given the density of sea water is 1025 kg/m3.

Answers

Answer:

Volume of buoy = 1.09 m^3

Volume of seawater displaced = 1.09 m^3

Mass of seawater displaced = 1.09 m^3 * 1025 kg/m*3 = 1117 kg

Mass of buoy = 803 kg

Net mass = 1117 - 803 = 314 kg         Mass supported by cable

Net force on cable F = M a = 314 kg * 9.80 m / s^2 = 3077 N

Einstein's theory of general relativity is currently the best explanation of gravity. what is likely to happen to this theory in the future?
a. it will remain the best explanation, because no one has come up with a better one yet.
b. it will remain the best explanation, because einstein's name is so well-known.
c. it will be replaced by a new theory if popular opinion changes.
d. it will be replaced by a new theory if enough evidence is collected.

Answers

Answer:

d. it will be replaced by a new theory if enough evidence is collected.

Explanation:

i think

D. It will be replaced …
Definetly not answers C or B. Answer a is shaped oddly

A container holds 2.0g of argon at a pressure of 8.0atm.
How much heat is required to increase the temperature by 100?C at constant volume?

Answers

The heat required tο increase the temperature οf 2.0 g οf argοn by 100 °C at cοnstant vοlume is apprοximately 0.104 kJ.

How to calculate the heat?

Tο calculate the heat required tο increase the temperature οf a gas at cοnstant vοlume, we can use the fοrmula:

Q = mCΔT

where Q is the heat, m is the mass οf the gas, C is the specific heat capacity οf the gas, and ΔT is the change in temperature.

Given:

Mass οf argοn (m) = 2.0 g

Pressure (P) = 8.0 atm

Change in temperature (ΔT) = 100 °C

First, we need tο cοnvert the mass οf argοn frοm grams tο kilοgrams:

m = 2.0 g = 0.002 kg

The specific heat capacity οf argοn at cοnstant vοlume (Cv) is apprοximately 0.520 kJ/(kg·K).

Nοw we can calculate the heat required:

Q = mCvΔT

= (0.002 kg)(0.520 kJ/(kg·K))(100 °C)

= 0.104 kJ

Therefοre, the heat required tο increase the temperature οf 2.0 g οf argοn by 100 °C at cοnstant vοlume is apprοximately 0.104 kJ.

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The two conductors are now connected by a wire. How do the potentials at the conductor surfaces compare now? A. VA greater than VB B. VA less than VB C. VA equal to VB

Answers

When two conductors are connected by a wire, the potentials at the conductor surfaces compare as follows: VA equal to VB (Option C).

This is because when connected by a wire, the conductors will reach an equilibrium state where they share the same electric potential, allowing charge to flow between them until their potentials become equal.

Since they are connected by a wire that causes them to function like a single conductor, both spheres' potential must be equal when they come into contact, regardless of the original conditions.

The conductors become one conductor when they are linked together by a string.

The electric potentials at the conductor surfaces are the same because conductors have equipotentials.

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Help please!
Solve for the wavelength (while showing your work completely) in meters of a wave from ‘The Jet’ in Seattle, which transmits at 95.7 MHz. M here means ‘mega’, which means x 1 million or x 106. Remember that the speed of light, and so the speed of radio waves is also 3.00 x 108 m/s.

Answers

The wavelength of the wave with the frequency of 95.7 MHz is 3.1 meters.

What is Wavelength?

Wavelength is the distance between identical points such as crests or troughs in the adjacent cycles of a waveform signal which is propagated in space or along a wire. In the wireless systems, this length is usually specified in the units of meters (m), centimeters (cm) or millimeters (mm).


λ = v/f

where, λ = wavelength of the wave,

v = velocity of the wave,

f = frequency of the wave

f = 95.7 MHz = 95.7 × 10⁶Hz,

v = 3 × 10⁸ m/s

λ = 3 × 10⁸ / 95.7 × 10⁶

λ = 0.031 × 10²

λ = 3.1 meters

Therefore, the wavelength of the wave is 3.1 meters.

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USE THE PICTURE THANKS WILL GIVE B WRONG ANSWER=report lol love ya

USE THE PICTURE THANKS WILL GIVE B WRONG ANSWER=report lol love ya

Answers

Answer:

I would have to say B THe su would rise in the west and set in the east But this is just a guess

If you jumped into your hole, there is a chance that you would not come out the other side. What would happen to you and why?

Answers

Answer:

Explanation:

A tunnel, dug from one side of the Earth to the other would be, on average, 12,742 km. ... If you jumped into the tunnel, you'd fall down towards the center of the Earth, accelerating constantly, thanks to gravity.

Part (c) Which graph represents an object being stationary for periods of time? O O O displacement
displacement V 1(s) O O O displacement displacement displacement 1(3) 1(8)
Part (b) Which graph has only negative velocity? O O O displacement displacement 1(s) O O O
displacement displacement 1(s) 1(s)
Part (a) Which of the following graphs represents an impossible motion? O O O displacement displacement
O O O displacement displacement displacement A 1(s)

Answers

The graph that represents an object being stationary is graph C.

The graph that represents an object only has negative velocity is graph C.

The graph that represents an impossible motion is graph C.

Look at the attachment for the full question. The displacement or changing position from the original position with time can be described by a displacement-time graph. There are

A flat line graph
Indicates that the object is stationary.A straight line with a positive gradient
The line increase and indicates that the object has a constant velocity.A straight line with a negative gradient
The line decrease and indicates that the object has a constant negative velocity.An increasing curve
Indicates that the object has non-uniform motion with acceleration.A decreasing curve
Indicates that the object has non-uniform motion with deceleration.

Look at the first problem.

Stationary objects are shown by a flat line.Only picture C has a flat line.

Look at the second problem.

Negative velocities are shown by a straight line with a negative gradient.Only picture C has a straight line with a negative gradient.

Look at the third problem.

An impossible motion is shown in a displacement-time graph if there are two displacements at one time. Impossible for the same object in two places at one time.Look at picture C. If you draw a vertical line from the point that intersects the x-axis, you will get two points of displacement of the object.Only picture C has impossible motion.

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Part (c) Which graph represents an object being stationary for periods of time? O O O displacementdisplacement

Find the mass of an element with two isotopes, the first of which makes up 75% of the element and has a mass number of 64 and the second , which makes up 25% of the elements and has a mass number 65.

Answers

The mass of an element with two isotopes, the first of which makes up 75% of the element and has a mass number of 64 and the second , which makes up 25% of the elements and has a mass number 65 is 64.25 atomic mass units (u).

To find the mass of the element with two isotopes, we can use the weighted average mass formula.

Convert the percentages to decimal form:

   The first isotope makes up 75% of the element, so its decimal form is 0.75.

   The second isotope makes up 25% of the element, so its decimal form is 0.25.

Multiply the mass number of each isotope by its respective percentage:

   For the first isotope (mass number 64): 64 * 0.75 = 48.

   For the second isotope (mass number 65): 65 * 0.25 = 16.25.

Add the results from Step 2 together:

48 + 16.25 = 64.25.

The mass of the element, considering the given isotopes, is approximately 64.25 atomic mass units (u).

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What is the difference between a theory and an opinion?

Answers

Answer:

A theory is a mental conception while an opinion is obstinacy in holding to one's belief or impression.

What is the purpose of using the string to tie the forelegs and hind legs during dissection?

Answers

Answer:

To holds the legs apart without rupturing any vein

Explanation:

The purpose of using string to tie the forelegs and hind legs during dissection is to hold the legs apart without rupturing ant vein or artillery for easy dissection procedure( the dismembering of the body of a deceased animal or plant to study its anatomical structure)

when tieing the forelegs and the hind legs the same string is used to tie them and the string is then passed/looped under the dissecting table/tray this way the legs will be held apart and the dissection can commence.

How do you determine if you are moving?

Answers

Answer: you can use your chair as a reference point. A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.

Explanation: basically motion.

find fmin , the constant force with the least magnitude that must be applied to the board in order to pull the board out from under the the box (which will then fall off of the opposite end of the board). express your answer in terms of some or all of the variables μs , m1 , m2 , g , and l . do not include f in your answer.

Answers

The constant force with the least magnitude, denoted as fmin, that must be applied to the board in order to pull it out from under the box can be expressed in terms of μs, m1, m2, g, and l. fmin, is given by the expression fmin = μs × (m1 × g + m2 × g).

To determine fmin, we need to consider the maximum static friction force that can be exerted between the board and the box. The maximum static friction force is given by fmax = μs × (m1× g + m2 × g), where μs is the coefficient of static friction, m1 is the mass of the board, m2 is the mass of the box, and g is the acceleration due to gravity.

Since the board is being pulled horizontally, the force required to overcome static friction is equal to fmin. Therefore, fmin = fmax = μs× (m1 × g + m2 × g).

In summary, the constant force with the least magnitude required to pull the board out from under the box, denoted as fmin, is given by the expression fmin = μs × (m1 × g + m2 × g), where μs is the coefficient of static friction, m1 is the mass of the board, m2 is the mass of the box, and g is the acceleration due to gravity.

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The constant force with the least magnitude (fmin) that must be applied to the board is (μs + 1) * m2 * g, expressed in terms of the variables μs, m2, and g.

To find the minimum constant force (fmin) required to pull the board out from under the box, we need to consider the forces acting on the system.

When the force is applied to the board, there are two types of forces that need to be overcome: the friction force between the board and the box and the gravitational force acting on the box.

The friction force between the board and the box is given by:

Friction force = μs * Normal force

where μs is the coefficient of static friction and Normal force is the normal force exerted by the box on the board. The normal force is equal to the weight of the box, which is m2 * g.

The gravitational force acting on the box is m2 * g, where m2 is the mass of the box and g is the acceleration due to gravity.

To pull the board out, the applied force should be greater than or equal to the sum of the friction force and the gravitational force:

fmin ≥ Friction force + Gravitational force

fmin ≥ μs * Normal force + m2 * g

fmin ≥ μs * (m2 * g) + m2 * g

fmin ≥ (μs * m2 + m2) * g

fmin ≥ (μs + 1) * m2 * g

The length of the board (l) and the mass of the other object magnitude on the board (m1) are not required to calculate fmin.

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Help please

Identify three different alloys in your home. Describe how each alloy is used and why the properties of the alloy make it suitable for that application.

Answers

Three different alloys used in home are brass, bronze and copper. Brass and bronze are used for utensils and copper is used in the electrical circuits.  

What are alloys?

Alloys are the homogeneous mixture of metal mixed with metal or non metal. These alloys can't be separated by physical methods.            

The alloy brass and bronze are used for utensils and copper is used in the electrical circuits.                                                                                                                        

The properties of the alloys make it suitable for that application is the electrical conductivity and their melting point.

Brass and Bronze are bad conductors of electricity. On the other side, copper is used in electrical circuits.

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A point charge of +3.0 X 10-7 coulomb is placed 2.0 X 10-2 meter from a second point charge of +4.0 X 10-7 coulomb. What is the magnitude of the electrostatic force on the charges?
A. 6.0 X 10-12 N
B. 3.0 X 10-10 N
C. 5.4 X 10-2 N
D. 2.7 N

Answers

Answer:

D. 2.7 N

Explanation:

Applying

F = kq'q/r²................ Equation 1

Where F = force, k = coulomb's constant, q' = first charge, q = second charge, r = distance between the charge

From the question,

Given: q' = +3.0×10⁻⁷ C, q = +4.0×10⁻⁷C, r = 2.0×10⁻² m

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 1

F = ( +3.0×10⁻⁷)(+4.0×10⁻⁷)(8.98×10⁹)/(2.0×10⁻²)²

F = 26.94×10⁻¹ N

F = 2.694 N

F ≈ 2.7 N

What pathway in the rock cycle might rock take nextv if it is subjected to uplift?

Answers

If rock is subjected to uplift, the next pathway in the rock cycle it may undergo is erosion and transportation. Uplift refers to the upward movement of Earth's crust, often caused by tectonic forces. When rocks are uplifted, they are exposed to weathering and erosion processes.

Here is the potential pathway the rock may follow:

1. Weathering: As the rock is exposed to the surface, it is exposed to weathering agents such as wind, water, and ice. This can break down the rock into smaller pieces.

2. Erosion: The smaller pieces of rock produced by weathering can be transported by agents such as water, wind, and glaciers to new locations.

3. Deposition: As the agents of erosion lose energy, they deposit the sediment they are carrying. Over time, the sediment can accumulate and become buried.

4. Lithification: As sediment accumulates, it can become compacted and cemented together by minerals. This process is called lithification, and it can turn the sediment into sedimentary rock.

5. Metamorphism: If the sedimentary rock is subjected to heat and pressure, it can undergo metamorphism and turn into metamorphic rock.

6. Melting: If the metamorphic rock is subjected to enough heat, it can melt and turn into magma.

7. Solidification: The magma can cool and solidify to form igneous rock.

Therefore, if a rock is subjected to uplift, it may undergo any of these pathways in the rock cycle, depending on the conditions it experiences.

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what is known physical quantity

Answers

Answer:

those quantity which are measured and expressed on mathematical process is called physical quantity

Can anyone help me please ..I need it hurry within 6 hrs.please.
Brainliest for the first best answer.​

Can anyone help me please ..I need it hurry within 6 hrs.please.Brainliest for the first best answer.

Answers

(i) Switch k1 is closed:

The current passing through the circuit is:  0.25 amps

R_total = R1 + R2 = 3 + 5 = 8 ohms

The current passing through the circuit is:

i = V / R_total = 2 / 8 = 0.25 amps

(ii) Switches k1 and k2 are closed:

The current passing through the circuit is: 1.07 amps

1/R_total = 1/R1 + 1/(R2 + R3) = 1/3 + 1/(5 + 0) = 8/15

R_total = 15/8 ohms

The current passing through the circuit is:

i = V / R_total = 2 / (15/8) = 1.07 amps

(iii) Switch k1 is open and k2 is closed:

The current passing through the circuit is: 1.07 amps

1/R_total = 1/R2 + 1/(R1 + R3) = 1/5 + 1/(3 + 0) = 1/5 + 1/3 = 8/15

R_total = 15/8 ohms

The current passing through the circuit is:

i = V / R_total = 2 / (15/8) = 1.07 amps

So the current passing through the circuit depends on which switches are closed, and can range from 0.25 amps to 1.07 amps.

What is current?

Crrent refers to the flow of electric charge through a conductor, such as a wire. It is measured in amperes (A) and is defined as the rate at which electric charge flows past a given point in a circuit. current is caused by the movement of charged particles, such as electrons or ions, through a conductor.

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