A 30 kg block with velocity 50 m/s is encountering a constant 8 N friction force. What is the momentum of the block after 15 seconds?
Answers
The momentum of a 30 kg block with an initial velocity of 50 m/s encountering a constant 8 N friction force and traveling for 15 seconds is 1680 kg m/s.
The initial momentum of the block is given by:
p = mv = (30 kg) x (50 m/s) = 1500 kg m/s
The net force acting on the block is given by the force of friction:
\(F_{net} = F_{friction} = 8 N\)
Using Newton's second law, we can find the acceleration of the block:
\(F_{net} = ma\)
8 N = (30 kg) a
\(a = 8/30 m/s^2\)
Using the equation for displacement with constant acceleration, we can find the distance traveled by the block during the 15 seconds:
\(d = vt + 1/2 at^2\)
\(d = (50 m/s)(15 s) + 1/2 (8/30 m/s^2)(15 s)^2\)
d = 750 m + 450 m = 1200 m
Finally, using the equation for final velocity with constant acceleration, we can find the final velocity of the block:
\(v_{f^2} = v_{i^2} + 2ad\)
\(v_{f^2} = (50 m/s)^2 + 2(8/30 m/s^2)(1200 m)\)
\(v_{f^2} = 2500 \;m^2/s^2 + 640 \;m^2/s^2 = 3140\; m^2/s^2\)
\(v_f\) = 56.0 m/s
Therefore, the momentum of the block after 15 seconds is:
p = mv = (30 kg)(56.0 m/s) = 1680 kg m/s
In summary, the momentum of a 30 kg block with an initial velocity of 50 m/s encountering a constant 8 N friction force and traveling for 15 seconds is 1680 kg m/s.
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Related Questions
Using atomic weight crystal structure and atomic radius data tabulated inside the front cover compute the theoritical densities of alminuim ,nikel......
Answers
Question
Using atomic weight, crystal structure, and atomic radius data tabulated inside the front cover of thebook, compute the theoretical densities of aluminum (Al), nickel (Ni), magnesium (Mg), and tungsten (W), and thencompare these values with the measured densities listed in this same table. The c/a ratio for magnesium is 1.624.
Explanation:
NEED HELP ASAP!!! Please and thank you
Answers
Answer:
Always.
Unbalanced forces mean there will be an acceleration on the object, so speed will change no matter how fast its going already.
Object 1 of mass 0.25 kg moves at 10 m/s towards Object 2 initially at rest of mass 0.25 kg. The resulting collision is perfectly inelastic, what is the speed of the objects after the collision
Answers
After a perfectly inelastic collision, the combined objects move at 5 m/s.
In a perfectly inelastic collision, the two objects stick together after colliding.
To find the final speed, we can use the conservation of momentum principle, which states that the total momentum before the collision equals the total momentum after the collision.
The initial momentum is (0.25 kg × 10 m/s) + (0.25 kg × 0 m/s) = 2.5 kg m/s.
After the collision, the combined mass is 0.5 kg.
To find the final velocity (v), we can use the formula:
total momentum = combined mass × final velocity, so 2.5 kg m/s = 0.5 kg × v, which gives v = 5 m/s.
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Jared is experimenting with a force that is attractive only and the weakest of the fundamental forces. He is experimenting with which force?
electromagnetic
strong
gravitational
weak
Answers
Answer:
C. gravitational
Explanation:
Took the test!
A space probe recovered an 8.5-kg sample of rocks from the surface of Mars. The acceleration due to gravity on Mars is 3.7 meters per second squared. What is the weight of the sample of rocks on the surface of the earth?
Answers
Answer: 31N
Explanation:F = m x a
F = 8.5 x 3.7
F = 31.45
F = 31 (rounded)
F = 31 N
a stunt pilot weighting 658 n performs a vertical circular loop of radius 611 m. at the top of the dive, the pilot has a speed of 219 m/s which at that instant is not changing. what force does the plane exert on the pilot in kn? positive forces are toward the center of curvature and negative forces are away from the center of curvature.
Answers
the force that the plane exerts on the pilot at the top of the dive is 54,475 N, or 54.5 kN (since 1 kN = 1000 N). This force is directed towards the center of curvature, since it is responsible for maintaining the circular motion of the pilot.
When the stunt pilot performs a vertical circular loop, the force exerted on him can be analyzed in terms of the centripetal force (which is directed toward the center of the circular path) and the gravitational force (which is directed toward the center of the Earth).
At the top of the loop, the pilot has a speed of 219 m/s and is moving in a circular path of radius 611 m. The centripetal force required to maintain this circular motion can be calculated using the formula:
F_c = mv^2/r
where F_c is the centripetal force, m is the mass of the pilot, v is the speed of the pilot, and r is the radius of the circular path.
Substituting the given values, we get:
F_c = (658 N) * (219 m/s)^2 / (611 m) = 50,058 N
Therefore, the centripetal force required to maintain the pilot's circular motion is 50,058 N.
Since the centripetal force is directed toward the center of the loop, and we have assumed that positive forces are also directed toward the center of curvature, we can say that the force exerted by the plane on the pilot is 50,058 N directed toward the center of the loop.
Converting this force to kilonewtons, we get:
F_c = 50,058 N / 1000 = 50.058 kN
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TRUE/FALSE. two objects are said to be in thermal equilibrium. this means that the two objects have the same temperature have the same speed have the same thermal energy have the same pressure have the same internal energy
Answers
The two objects are said to be in thermal equilibrium when they have the same temperature, speed, pressure, and thermal and internal energy. This statement is true.
What is thermal equilibrium?When two components come into thermal contact but stop influencing one another’s temperatures, this is known as thermal equilibrium.
For example:
If a bottle of iced strawberry syrup is set on the table in the dining room, then the two objects are said to be in thermal contact. Meanwhile, they can be said to be in thermal equilibrium when the temperatures are the same after several hours.When a cup of hot coffee is on the table, then its temperature can be the same as the surrounding air after a period of time.Learn more about thermal equilibrium:
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In a college homecoming competition, eighteen students lift a sports car. While holding the car off of the ground, each student exerts an upward force of 400 newtons. What is the mass of the car in kilograms?
Answers
734.19567 Kilogram Force
Explanation:
7200 Newton = 734.19567 Kilogram Force
Question 2 1/1 poin To launch a 100 kg human so that he leaves a cannon moving at a speed of 4 m/s, you need a spring with an appropriate spring constant. This spring will be compressed 2.0 m from its natural length to launch the person. Which spring constant do you need? 200 N/m 400 N/m 1600 N/m B00 N/m
Answers
The spring constant required to launch the person is option (B) 400 N/m
To launch the person, the spring will need to exert a force equal to the weight of the person plus the force required to give them the desired velocity.
The force required to give the person a velocity of 4 m/s can be calculated using the kinetic energy formula:
KE = 0.5mv^2
where KE is the kinetic energy, m is the mass of the person, and v is the velocity.
KE = 0.5 x 100 kg x (4 m/s)^2 = 800 J
The force required to produce this energy can be calculated using the work-energy principle:
W = Fd = KE
where W is the work done, F is the force applied, and d is the distance over which the force is applied.
Since the spring is compressed by 2.0 m, the work done by the spring can be expressed as:
W = 0.5kx^2
where k is the spring constant, and x is the compression of the spring.
Setting the work done by the spring equal to the kinetic energy of the person, we get:
0.5kx^2 = KE
0.5k(2.0 m)^2 = 800 J
k = 800 J / (0.5 x 2.0 m)^2 = 400 N/m
Therefore, the correct option is (B) 400 N/m
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The given question is incomplete, the complete question is:
To launch a 100 kg human so that he leaves a cannon moving at a speed of 4 m/s, you need a spring with an appropriate spring constant. This spring will be compressed 2.0 m from its natural length to launch the person. Which spring constant do you need?
A) 200 N/m
B) 400 N/m
C) 1600 N/m
D) 800 N/m
What is the method of heat transfer sunlight melts a wax crayon left outside.
Answers
Answer:
Hey Friend....
Explanation:
This is ur answer....
Transfer of energy by electromagnetic waves. Radiation doesn't require matter. Sunlight melting a wax crayon left outside is radiation.Hope it helps!
Brainliest pls!
Follow me! :)
What net force would be needed to accelerate a 2.95kg bowling ball at 6.25m/s^2?
Answers
The net force would be needed to accelerate a 2.95kg bowling ball at 6.25m/s^2 will be F = 18.4375 N
What is Newton's second law of motion ?Newton's second law of motion states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
For a constant mass , force is equal to Force = mass * acceleration
given
mass(M) = 2.95 kg
acceleration(a) = 6.25 m/s^2
Force(F) = ?
Force(F) = mass(M) * acceleration(a) (from Newton's second law of motion )
F = 2.95 * 6.25
F = 18.4375 N
The net force would be needed to accelerate a 2.95kg bowling ball at 6.25m/s^2 will be F = 18.4375 N
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PLEASE HELP, NO ONE IS HELPING MEEEE :(
While taking the stairs it takes you 10 seconds to reach the top. The next time you take the same stairs, it takes you 5 seconds to reach the top stair. During which of these trips up the stairs did you use more power to climb?
Answers
Answer:
probably the trip where it took u 5 seconds
If a 1-N net force accelerates a l-kg mass at Im/s2, what is the acceleration caused by a net force of 2 N on a 2-kg mass?
Answers
Answer:
The acceleration caused by a net force of 2 N on a 2 kg mass is 1 m/s²
Explanation:
The given parameters on an applied force is as follows;
The acceleration given to a 1 kg mass by a 1-N net force = 1 m/s²
According to Newton's second law of motion, the acceleration, "a", given to an object by a force, "F", is proportional to the magnitude of the net force
Therefore, we have;
F ∝ a
The constant of proportionality is given as the mass, "m", of the object, therefore, we have;
F = m × a
The acceleration given to a 2 kg mass by a 2-N net force is given therefore, given as follows;
2 N = 2 kg × a
a = 2 N/(2 kg) = 1 m/s²
The acceleration, "a", caused by a net force of 2 N on a 2 kg mass is a = 1 m/s².
You wish to date a hip bone fragment you found at a cave site.
You find a ratio of 1 14C atoms for every 31 14N atoms. How many
half- lives have elapsed?
Answers
To determine the number of half-lives that have elapsed, we need to compare the ratio of 14C to 14N atoms found in the hip bone fragment.
The ratio of 1 14C atom for every 31 14N atoms suggests that the hip bone fragment contains a smaller amount of 14C compared to the expected ratio found in a living organism. Since 14C undergoes radioactive decay with a half-life of approximately 5730 years, we can calculate the number of half-lives that have elapsed by observing how many times the ratio needs to double to reach the expected ratio.
In this case, if the expected ratio is 1:1, then the observed ratio of 1:31 would require five doublings to reach 1:1. Therefore, approximately five half-lives have elapsed since the death of the organism from which the hip bone fragment originated.
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Una botella vacía tiene una masa de 24.25g y de 86.55g completamente llena de agua, se vacia el agua y se llena nuevamente con 123.95g de solvente tetracloruro de carbono, ¿cual es la densidad del solvente?
Answers
Answer:
La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.
Explanation:
La masa de agua contenida dentro de la botella es igual a la diferencia entre la masa pesada totalmente llena y la masa pesada totalmente vacía, es decir:
\(m_{w} = 86.55\,g-24.25\,g\)
\(m_{w} = 62.3\,g\)
Ahora, de acuerdo con la definición de densidad, la masa es directamente proporcional a la densidad, entonces, podemos calcular la densidad del solvente mediante la siguiente relación:
\(\frac{m_{x}}{m_{w}} = \frac{\rho_{x}}{\rho_{w}}\) (1)
Donde:
\(m_{x}\) - Masa del tetracloruro de carbono, en gramos.
\(m_{w}\) - Masa del agua, en gramos.
\(\rho_{x}\) - Densidad del tetracloruro de carbono, en gramos por centímetro cúbico.
\(\rho_{w}\) - Densidad del agua, en gramos por centímetro cúbico.
Si sabemos que \(m_{x} = 123.95\,g\), \(m_{w} = 62.3\,g\) y \(\rho_{w} = 1\,\frac{g}{cm^{3}}\), entonces la densidad del tetracloruro de carbono es:
\(\rho_{x} = \left(\frac{m_{x}}{m_{w}} \right)\cdot \rho_{w}\)
\(\rho_{x} = 1.990\,\frac{g}{cm^{3}}\)
La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.
A construction worker holds a heavy tool box. How much work is done by the worker?
Answers
Answer:
zero work is done by the worker
Rainfall from a slow-moving thunderstorm was over 5 inches. This storm led to
the erosion of about 0.2 mm of soil from a field. Express this soil loss in Mg ha-1 (Ton/ha) if the bulk density
of the soil is 1.01 Mg m-3.
Please show your work!
a. 0.202 Mg/ha
b. 2.02 Mg/ha
c. 20.2 Mg/ha
Answers
The soil loss in \(Mg ha^{-1}\) (Ton/ha) if the bulk density of the soil is 1.01 \(Mg m^{-3}\) is option a. 0.202 Mg/ha.
For expressing the soil loss in \(Mg ha^{-1}\), need to convert the units appropriately. First, convert the soil loss from millimetres (mm) to meters (m) by dividing it by 1,000 (1 mm = 0.001 m). Thus, the soil loss is 0.0002 m.
Next, calculate the volume of soil lost per unit area (ha). The volume can be obtained by multiplying the soil loss (0.0002 m) by the area (ha). Since the bulk density of the soil is given as 1.01 \(Mg m^{-3}\), can convert the volume to mass by multiplying it by the bulk density.
Using the formula:
Soil loss (Mg ha-1) = Soil loss (m) × Bulk density (\(Mg m^{-3}\)) × Area (ha)
Substituting the values:
Soil loss (\(Mg ha-1\)) = 0.0002 m × 1.01 \(Mg m^{-3}\) × 1 ha
Calculating the result:
Soil loss (\(Mg ha-1\)) = 0.0002 × 1.01 = 0.000202 \(Mg ha-1\)
Therefore, the correct answer is option a. 0.202 Mg/ha.
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A projectile is launched at some angle to the horizontal with some initial speed vi, and air resistance is negligible.(a) Is the projectile a freely falling body?(b) What is its acceleration in the vertical direction? (Let up be the positive direction.)(c) What is its acceleration in the horizontal direction?
Answers
A) No, the projectile is not a freely falling body.
B) Its acceleration in the vertical direction is 9.8 m/s2.
C) Its acceleration in the horizontal direction is zero.
A) The movement of a projectile is not free fall.
B)The Gravity acts to influence the vertical movement of the projectile
C) The horizontal movement of the projectile is the result of the tendency of any object to remain in motion at constant speed, So your horizontal direction acceleration is zero.
Acceleration is a physical quantity that describes the rate of change of an object's velocity with respect to time. The magnitude of acceleration is measured in units of meters per second squared (m/s²) or feet per second squared (ft/s²), depending on the system of units used. An object can accelerate in several ways, including changing its speed, changing its direction, or both.
The acceleration of an object depends on the net force acting on it and its mass, according to Newton's second law of motion. Positive acceleration occurs when the object is speeding up, negative acceleration (also known as deceleration) occurs when the object is slowing down, and zero acceleration occurs when the object is moving at a constant velocity.
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Complete Question: -
A projectile is launched at some angle to the horizontal with some initial speed vi, and air resistance is negligible.
(a) Is the projectile a freely falling body?Yes or No
(b) What is its acceleration in the vertical direction? (Let up be the positive direction.)____? m/s2
(c) What is its acceleration in the horizontal direction?
South High School still displays with great pride the large sign boasting of their 1996 State Championship Girl’s Basketball Team. The 46.6-kg sign hangs from two cables which make an angle of 35° with the horizontal. Determine the tension in each of the cables, in newtons (N).
Use the approximation g ≈ 10 m/s2.
Answers
The tension in each of the cables is approximately T1 = 267.5 N and T2 = -267.5 N.
The tension in each of the cables can be determined using trigonometry. Let's denote the tension in the first cable as T1 and the tension in the second cable as T2.
To find T1 and T2, we can use the following equations:
\(T1 * sin(35) - T2 * sin(35) = 46.6 kg * 10 m/s^2 (equation 1)\)
\(T1 * cos(35) + T2 * cos(35) = 0 (equation 2)\)
Simplifying equation 2, we get:
\(T1 * cos(35) = -T2 * cos(35)\)
Dividing both sides by cos(35°), we find:
\(T1 = -T2\)
Substituting this into equation 1, we get:
\(-T2 * sin(35) - T2 * sin(35) = 46.6 kg * 10 m/s^2\)
Simplifying further, we have:
\(-2 * T2 * sin(35) = 466 N\)
Dividing both sides by -2 * sin(35°), we find:
\(T2 = 466 N / (-2 * sin(35)) = -267.5N\)
Using this value of T2, we can determine T1 by substituting it back into equation 2:
\(T1 = -T2 = -466 N / (-2 * sin(35)) = 267.5N\)
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You see a plane directly overhead at 1622 m.3.51 seconds later, you hear the sonic boom. The speed of sound is 344
s
m
How fast is the plane traveling? Round your answer to 2 decimal places.
s
m
What is the Mach Number for the plane? Round your answer to 2 decimal places.
Answers
The Mach number for the plane is approximately 3.51.
To find the speed of the plane, we can use the equation:
Speed of sound = Speed of the plane / Time taken
Given: Speed of sound (v) = 344 m/s
Time taken (t) = 3.51 seconds
Let's calculate the speed of the plane:
Speed of plane = Speed of sound × Time taken
Speed of plane =\(344 m/s * 3.51 s\)
Speed of plane ≈ 1206.44 m/s
Rounded to 2 decimal places, the speed of the plane is approximately 1206.44 m/s.
To find the Mach number of the plane, we need to divide the speed of the plane by the speed of sound:
Mach number = Speed of plane / Speed of sound
Mach number ≈ \(1206.44 m/s / 344 m/s\)
Mach number ≈ 3.51
Rounded to 2 decimal places, the Mach number for the plane is approximately 3.51.
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The wave take 0.12 to reach the satellite. Calculate the height of the orbit of the communications satellite
Answers
Answer:
x = 3.6 10⁷ m
Explanation:
The speed of an electromagnetic wave is constant, in a vacuum its value is c = 3 10⁸ m / s, this speed decreases when entering a material medium,
v = c / n
where n is the refractive index, but in this case the refractive index of air is n = 1.00002. The refractive index of a vacuum is n = 1, so we can assume that the change in velocity is negligible.
For the calculation we can use the relations of the uniform motion
v = x / t
x = v t
let's calculate
x = 3 10⁸ 0.12
x = 3.6 10⁷ m
Calculate the maximum wavelength of light capable of dissociating the f–f bond in one molecule of fluorine if the bond energy, or bond dissociation energy, is 157 kj/mol.
Answers
The maximum wavelength of light capable of dissociating the f–f bond in one molecule of fluorine if the bond energy, or bond dissociation energy, is 157 kJ/mol is 7.625 × 10⁻⁵ meters.
Given:
Bond dissociation energy = 157 kJ/mol.
we know,
Avogadro's number = 6.023 × 10²³ mole⁻¹
Speed of light = 3 × 10⁸ms⁻¹
Planck constant = 6.626 × 10⁻³⁴ Js
To calculate the maximum wavelength of light capable of dissociating the f–f bond in one molecule of fluorine,
The energy required to break one f--f bond is calculated as,
⇒ Bond energy / Avogadro's number
= 157 × 10³/ 6.023 × 10²³
= 26.067 × 10⁻²⁰ Joules
Let the wavelength of the light required to break one f -f bond be λ.
We find the maximum wavelength by using Einstein's equation for photon energy.
Einstein's equation for photon energy is represented mathematically by the following formula:
E = hf = hc / λ
In this equation,
E is the energy.h is the Planck constant.f is photon frequency.λ is the wavelength.v is the speed of lightSubstituting the values in the formula,
⇒ 26.067 × 10⁻²⁰ = ( 6.626 × 10⁻³⁴ × 3 × 10⁸) / λ
⇒ λ = ( 6.626 × 10⁻³⁴ × 3 × 10⁸) / 26.067 × 10⁻²⁰
= 7.625 × 10⁻⁵ m
Hence, the maximum wavelength is 7.625 × 10⁻⁵ m.
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speakers c and d emit the same pure tone of wavelength 1.5 m, are exactly in phase, and are 3.6 m apart. how many loud spots (completely constructive interference) exist along the line segment connecting the speakers? enter your answer as an integer.
Answers
There are 2 loud spots (completely constructive interference) along the line segment connecting the speakers.
Constructive interference to occur, the path length difference between the two speakers should be an integer multiple of the wavelength. The formula for the path length difference (Δx) is: Δx=n⋅λ
Where: n is the number of wavelengths difference.
λ is the wavelength.
The speakers are 3.6 m apart and the wavelength is 1.5 m, we can calculate the number of loud spots (constructive interference points) by dividing the distance by the
n =3.6m/ 1.5m
n= 2.4
n≈2.4
Since we're looking for completely constructive interference spots, n should be an integer. The nearest integer to 2.4 is 2.
Therefore, there are 2 loud spots (completely constructive interference) along the line segment connecting the speakers.
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Two astronomers are looking at different supernovae. Supernova Alpha is 8 thousandlight years away. Supernova Charlie is 142 million light years away. Using this infoboth scientist agree thatA. Supernova Charlie is bigger than Supernova AlphaB. Supernova Charlie is more explosive than Supernova Alpha.C. Supernova Charlie formed before Supernova Alpha
Answers
Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to produce to propel Nikolas if he wanted to accelerate at a rate of 1.2 m/s2? Round your answer to the nearest whole newton.
Answers
Answer:
60N
Explanation:
Given parameters:
Combined mass = 50kg
Acceleration = 1.2m/s²
Unknown:
Force to propel = ?
Solution:
From Newton's second law of motion, we know that;
Force = mass x acceleration
So;
Force = 50 x 1.2 = 60N
Answer:
60N
Explanation:
A 700 N (70 kg) skydiver falls towards the Earth. If the force due to air
resistance is 322 N, what is the acceleration of the skydiver?
Label your answer as m/s/s and use +/- to show direction.
Answers
The acceleration of the skydiver is approximately +5.4 m/s².
What is the acceleration?We can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:
Net force = mass x acceleration
In this case, the net force is the force due to gravity minus the force due to air resistance:
Net force = force due to gravity - force due to air resistance
So we have:
(700 N) - (322 N) = (70 kg) x acceleration
Simplifying this equation, we get:
378 N = (70 kg) x acceleration
To find the acceleration, we can divide both sides by the mass:
acceleration = 378 N / (70 kg)
acceleration = 5.4 m/s²
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nilai x
Hitung
3^x2 x 3^5x
= 3^24
Answers
Answer:
x = - 8 atau 3
Explanation:
3ˣ² × 3⁵ˣ = 3²⁴
Penarikan:
Mᵃ × Mᵇ = Mᵃ⁺ᵇ
3ˣ² × 3⁵ˣ = 3ˣ²⁺⁵ˣ
Karena itu
3ˣ² × 3⁵ˣ = 3²⁴
3ˣ²⁺⁵ˣ = 3²⁴
x² + 5x = 24
Mengatur kembali
x² + 5x - 24 = 0
Pemecahan dengan faktorisasi
x² - 3x + 8x - 24 = 0
x (x - 3) + 8 (x - 3) = 0
(x + 8) (x - 3) = 0
x + 8 = 0 atau x - 3 = 0
x = - 8 atau x = 3
Karena itu,
x = - 8 atau 3
What are the types of motion that can be observed in a pendulum ? Some one please answer.√
Answers
Answer:
periodic motion
Explanation:
The massive object is affectionately referred to as the pendulum bob. When the bob is displaced from equilibrium and then released, it begins its back and forth vibration about its fixed equilibrium position. The motion is regular and repeating, an example of periodic motion.
which of the following does not describe a way in which machines function? by enhancing range of motion and speed of movement so that resistance can be moved farther or faster than an applied force by balancing multiple forces by altering the resulting direction of an applied force by enhancing force in an attempt to increase total force needed to overcome a resistance
Answers
The method by which machines increase range of motion and speed of movement so that resistance can be moved farther or more quickly than an applied force is not described in the following.
Which of the following best describes the gravitational attraction of the earth on an object: biomechanics force levers?The earth pulls your body downward, which is known as gravity. The location where your body's mass is concentrated is known as your center of gravity. A hypothetical location where the force of gravity seems to act is the center of gravity (COG) of an organism.
Which of the following claims regarding friction force is false?No relative motion exists between the two contact surfaces in a rolling motion. Therefore, in a rolling motion, the friction does not do any work. Because of this, rolling friction is lower than sliding or kinetic friction.
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what will the volume of the helium be when the balloon rises to the point where the atmospheric pressure is 380 mmhg ? assume that the temperature and amount of the helium remain unchanged.
Answers
The volume of the helium in the balloon when the atmospheric pressure is 380 mmHg is 1520 mL.
To determine the volume of helium in the balloon, the combined gas law must be applied. The formula for the combined gas law is given by:
PV/T = constant
where P is pressure, V is volume, and T is temperature. Since the temperature and the amount of helium remains unchanged, the combined gas law can be written as P1V1 = P2V2 where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Given that the initial pressure P1 = 760 mmHg and the final pressure P2 = 380 mmHg, the final volume V2 can be determined using:
P1V1 = P2V2
V2 = (P1V1)/P2
V2 = (760 mL)(760 mmHg)/(380 mmHg)
V2 = 1520 mL
Hence, the volume of the helium in the balloon when the atmospheric pressure is 380 mmHg is 1520 mL.
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