A 280-mL flask contains pure helium at a pressure of 762 torr . A second flask with a volume of 465 mL contains pure argon at a pressure of 732 torr .
A) If the two flasks are connected through a stopcock and the stopcock is opened, what is the partial pressure of helium?
B) If the two flasks are connected through a stopcock and the stopcock is opened, what is the partial pressure of argon?
C) If the two flasks are connected through a stopcock and the stopcock is opened, what is the total pressure?
all answers with units of torr

Answers

Answer 1

A) The partial pressure of helium will remain at 762 torr.

B) The partial pressure of argon will remain at 732 torr.

C) The total pressure will be the sum of the partial pressures, which is 1494 torr.

When the two flasks are connected, they will reach a state of equilibrium where the partial pressures of each gas add up to the total pressure.

A) To find the partial pressure of helium, we can use the following equation:

PHe = XHe × Ptotal

where PHe is the partial pressure of helium, XHe is the mole fraction of helium, and Ptotal is the total pressure.

First, we need to find the mole fraction of helium. We can do this by dividing the number of moles of helium by the total number of moles:

XHe = nHe / (nHe + nAr)

Since each flask contains only one gas, we can find the number of moles using the ideal gas law:

n = PV / RT

where n is the number of moles, P is the pressure, V is the volume, R is the gas constant, and T is the temperature (which we assume to be constant). We can use this equation to find the number of moles of helium and argon in each flask.

For the first flask:

nHe = (762 torr)(0.280 L) / (0.0821 L·atm/mol·K)(298 K) = 0.0107 mol He

For the second flask:

nAr = (732 torr)(0.465 L) / (0.0821 L·atm/mol·K)(298 K) = 0.0194 mol Ar

Now we can find the mole fraction of helium:

XHe = 0.0107 mol / (0.0107 mol + 0.0194 mol) = 0.356

Finally, we can use the equation above to find the partial pressure of helium:

PHe = (0.356)(1494 torr) = 532 torr

Therefore, the partial pressure of helium is 532 torr.

B) To find the partial pressure of argon, we can use the same equation as above, but with the mole fraction of argon:

PAr = XAr × Ptotal

First, we need to find the mole fraction of argon:

XAr = nAr / (nHe + nAr) = 0.0194 mol / (0.0107 mol + 0.0194 mol) = 0.644

Now we can use the equation above to find the partial pressure of argon:

PAr = (0.644)(1494 torr) = 962 torr

Therefore, the partial pressure of argon is 962 torr.

C) The total pressure is simply the sum of the partial pressures:

Ptotal = PHe + PAr = 532 torr + 962 torr = 1494 torr

Therefore, the total pressure is 1494 torr.

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Answer 2

A) The partial pressure of helium will remain at 762 torr.

B) The partial pressure of argon will remain at 732 torr.

C) The total pressure will be the sum of the partial pressures, which is 1494 torr.

When the two flasks are connected, they will reach a state of equilibrium where the partial pressures of each gas add up to the total pressure.

A) To find the partial pressure of helium, we can use the following equation:

PHe = XHe × Ptotal

where PHe is the partial pressure of helium, XHe is the mole fraction of helium, and Ptotal is the total pressure.

First, we need to find the mole fraction of helium. We can do this by dividing the number of moles of helium by the total number of moles:

XHe = nHe / (nHe + nAr)

Since each flask contains only one gas, we can find the number of moles using the ideal gas law:

n = PV / RT

where n is the number of moles, P is the pressure, V is the volume, R is the gas constant, and T is the temperature (which we assume to be constant). We can use this equation to find the number of moles of helium and argon in each flask.

For the first flask:

nHe = (762 torr)(0.280 L) / (0.0821 L·atm/mol·K)(298 K) = 0.0107 mol He

For the second flask:

nAr = (732 torr)(0.465 L) / (0.0821 L·atm/mol·K)(298 K) = 0.0194 mol Ar

Now we can find the mole fraction of helium:

XHe = 0.0107 mol / (0.0107 mol + 0.0194 mol) = 0.356

Finally, we can use the equation above to find the partial pressure of helium:

PHe = (0.356)(1494 torr) = 532 torr

Therefore, the partial pressure of helium is 532 torr.

B) To find the partial pressure of argon, we can use the same equation as above, but with the mole fraction of argon:

PAr = XAr × Ptotal

First, we need to find the mole fraction of argon:

XAr = nAr / (nHe + nAr) = 0.0194 mol / (0.0107 mol + 0.0194 mol) = 0.644

Now we can use the equation above to find the partial pressure of argon:

PAr = (0.644)(1494 torr) = 962 torr

Therefore, the partial pressure of argon is 962 torr.

C) The total pressure is simply the sum of the partial pressures:

Ptotal = PHe + PAr = 532 torr + 962 torr = 1494 torr

Therefore, the total pressure is 1494 torr.

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Related Questions

La serie de Lyman se situa en la region ultravioleta del espectro. ¿Que linea quedara mas cerca de la zona visible del espectro? Explica por qué.

Answers

Answer:

Lyman series of hydrogen atom lies in the ultraviolet region, Balmer series lies in visible region, Paschen series lies in near infrared region whereas Bracket, Pfund as well as Humphrey series lie in far infrared region of electromagnetic spectrum.

Hammerhead sharks have weakly-muscled gills and must be in constant motion in the ocean in order to maintain a steady flow of water over their gills. The steady flow of water across their gills is necessary for –
attracting mates.

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attacking prey.

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i’m pretty sure it is obtaining oxygen

The following reaction shows the synthesis of zinc citrate, a ingredient in toothpaste, from zinc carbonate and citric acid.
3ZnCO3+2C6H8O7=Zn3(C6H5O7)2+3H2O+3CO2
a. How many moles of ZnCO3 and C6H8O7 are required to produce 30.0 moles of ZN3(C6H5O7)2
b.What quantities, in kilograms, of H2O and CO2 are produced by the reaction of 500. mol of citric acid.

Answers

To determine how many moles of ZnCO3 and C6H8O7 are required to produce 30.0 moles of ZN3(C6H5O7)2, we need to use the stoichiometry of the reaction.

The balanced equation shows that 3 moles of ZnCO3 and 2 moles of C6H8O7 are required to produce 1 mole of ZN3(C6H5O7)2. Therefore, to produce 30.0 moles of ZN3(C6H5O7)2, we need:(30.0 moles ZN3(C6H5O7)2) * (3 moles ZnCO3 / 1 mole ZN3(C6H5O7)2) = 90.0 moles ZnCO3(30.0 moles ZN3(C6H5O7)2) * (2 moles C6H8O7 / 1 mole ZN3(C6H5O7)2) = 60.0 moles C6H8O7To determine the quantities of H2O and CO2 produced by the reaction of 500. mol of citric acid, we again use the stoichiometry of the reaction. The balanced equation shows that 3 moles of H2O and 3 moles of CO2 are produced for every 2 moles of C6H8O7 that react. Therefore, for 500. mol of C6H8O7, we have:(500. mol C6H8O7) * (3 moles H2O / 2 moles C6H8O7) = 750. mol H2O(500. mol C6H8O7) * (3 moles CO2 / 2 moles C6H8O7) = 750. mol CO2To convert from moles to kilograms, we need to use the molar masses of H2O and CO2. The molar mass of H2O is 18.015 g/mol and the molar mass of CO2 is 44.01 g/mol.Therefore, we have:(750. mol H2O) * (18.015 g/mol) * (1 kg / 1000 g) = 13.511 kg H2O.(750. mol CO2) * (44.01 g/mol) * (1 kg / 1000 g) = 33.008 kg CO2.So the quantities of H2O and CO2 produced are 13.511 kg and 33.008 kg, respectively.

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The united states mint uses electrolysis to copper plate zinc pennies by placing them in a cu2+ solution and connecting the pennies and a copper electrode to a battery. Enter the half-reaction that takes place when the pennies are plated with solid copper. Include phases.

Answers

Cathode reaction: \(Cu^{2+} + (aq) + 2e-- > Cu (s).\\\)

Anode reaction: \(Cu(s) -- > Cu^{2}+ (aq) + 2e\) is

What is half-reaction?

A redox reaction's oxidation or reduction reaction component is known as a half reaction (or half-cell reaction). By taking into account the change in oxidation states of specific chemicals participating in the redox reaction, a half reaction is produced.

Here Zn pennies act as cathode , reduction of \(Cu^{2+}\) to Cu take place here.

Cu rod acts as anode,here dissolution of Cu (s) to \(Cu^{2+}\) take place .

Half cell reactions

Cathode reaction: \(Cu^{2+} + (aq) + 2e-- > Cu (s).\\\)

Anode reaction: \(Cu(s) -- > Cu^{2}+ (aq) + 2e\)

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._____ are tiny, tiny pieces of matter that cannot be broken apart any further.

Answers

Atoms are tiny, tiny pieces of matter that cannot be broken apart any further.

Atoms are the basic units of matter and the smallest particles that retain the properties of an element. Atoms are composed of a nucleus that contains protons and neutrons, surrounded by electrons that orbit around the nucleus.

Atoms cannot be broken down any further by chemical or physical means without losing their identity as the element they belong to.

The properties of atoms determine the characteristics of the matter they make up, and the arrangement of atoms in molecules determines the properties of compounds. The study of atoms and their behavior is the foundation of modern chemistry.

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With which temperature scale is temperature directly proportional to average kinetic energy? Celsius
Kelvin
centigrade
Fahrenheit

Answers

Answer:

The Kelvin temperature scale is the scale that is based on molecular motion and so absolute zero is also called 0K.

Explanation: The Kelvin temperature of a substance is directly proportional to the average kinetic energy of the particles of the substance.

62g 72cm what is the density

Answers

Answer:

0.861111... g/cm³

Explanation:

density= mass/volume

a 50.0- ml volume of 0.15 m hbr is titrated with 0.25 m koh . calculate the ph after the addition of 15.0 ml of koh .

Answers

The pH of the solution after the addition of 15.0 ml of KOH is 1.28.

In the given problem, we have been provided with the volume of HBr (hydrogen bromide) solution and its concentration.

We have been also provided with the concentration and volume of KOH (potassium hydroxide) solution.

We need to calculate the pH of the solution after the addition of 15.0 ml of KOH.

Let’s begin the calculation process-

1. Write down the balanced chemical equation of HBr and KOH-

HBr + KOH → KBr + H2O

2. To Calculate the number of moles of HBr-

We know that, Number of moles = Concentration x VolumeNumber of moles of HBr = 0.15 x 50/1000= 0.0075 moles of HBr

3. To Calculate the number of moles of KOH-

Number of moles of KOH = Concentration x VolumeNumber of moles of KOH = 0.25 x 15/1000= 0.00375 moles of KOH

4. To Calculate the number of moles of HBr left after the reaction-

Number of moles of HBr left = Number of moles of HBr – Number of moles of KOHNumber of moles of HBr left = 0.0075 - 0.00375= 0.00375 moles of HBr

5. To Calculate the concentration of HBr-

Concentration of HBr = Number of moles / VolumeConcentration of HBr = 0.00375 / 50/1000= 0.075 M

6. To Calculate the concentration of OH-

Number of moles of KOH = Concentration x Volume

Number of moles of KOH = 0.25 x 15/1000= 0.00375 moles of KOH

Concentration of KOH = Number of moles / Volume

Concentration of KOH = 0.00375 / 65/1000= 0.0577 M

Concentration of OH- = Concentration of KOH= 0.0577 M

7. To Calculate the concentration of H+

Using the formula of pH = -log[H+], we can get

[H+] = 10-pHLet pH = x[H+] = 10-x

From the balanced chemical equation, we know that 1 mole of HBr will give 1 mole of H+ and 1 mole of KOH will give 1 mole of OH-.

As the moles of KOH is less than the moles of HBr, KOH is the limiting reagent.

Now, using the formula of neutralization reaction, we can write-Volume of HBr x Concentration of HBr = Volume of KOH x Concentration of KOH50/1000 x 0.075 = 15/1000 x 0.0577Volume of HBr = 0.06 L

Now, H+ ion concentration can be calculated as-H+ ion concentration = KOH concentration – HBr concentration= 0.0577 – (0.075 x 0.015 / 0.06)= 0.0519 M

8. To Calculate pH of the solution-

We know that, pH = -log[H+]= -log(0.0519)= 1.28

Hence, the pH of the solution after the addition of 15.0 ml of KOH is 1.28.

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what phase change happens when you drop the dry ice into the water

ASAP

Answers

Answer:

Sublimation, the dry ice changes to a gas, solid to gas is sublimation

Show how you would synthesize each compound from benzene, toluene, or phenol using the following reactions Reactions 1. Halogenation 2. Nitration 3. Sulfonation 4. Friedel-Crafts acylation 5. Friedel-Crafts alkylation 6. Oxidation of methyl group 7. Reduction of nitro group

Answers

Halogenation, Nitration, Sulfonation, Friedel-Crafts acylation, Friedel-Crafts alkylation, Oxidation of methyl group, Reduction of nitro group are  distinct chemical reactions involving organic compounds.

Using Halogenation, Nitration, Sulfonation, Friedel-Crafts acylation and alkylation, Oxidation of methyl group and Reduction of nitro group, benzene, toluene, or phenol can be synthesized in the following ways:

1. Halogenation: Benzene, toluene, or phenol can be halogenated by reacting them with a halogen (e.g., chlorine or bromine) in the presence of a Lewis acid catalyst.

For example, benzene can be chlorinated to form chlorobenzene using FeCl3 as a catalyst.

2. Nitration: Nitration of benzene, toluene, or phenol involves the substitution of a nitro group (-NO2) onto the aromatic ring.

This reaction is typically carried out by treating the compound with a mixture of concentrated nitric acid and sulfuric acid. For instance, benzene can be nitrated to produce nitrobenzene.

3. Sulfonation: Sulfonation introduces a sulfonic acid group (-SO3H) onto the aromatic ring. It can be achieved by reacting benzene, toluene, or phenol with concentrated sulfuric acid.

For example, benzene can be sulfonated to form benzenesulfonic acid.

4. Friedel-Crafts acylation: Friedel-Crafts acylation involves the reaction of benzene or toluene with an acyl chloride in the presence of a Lewis acid catalyst, such as aluminum chloride (AlCl3).

This reaction results in the formation of an aromatic ketone. For instance, benzene can be acylated to produce acetophenone.

5. Friedel-Crafts alkylation: Friedel-Crafts alkylation allows the introduction of an alkyl group onto the aromatic ring.

It can be achieved by reacting benzene or toluene with an alkyl halide in the presence of a Lewis acid catalyst. For example, benzene can be alkylated to form ethylbenzene.

6. Oxidation of methyl group: Toluene contains a methyl group attached to the aromatic ring, which can be oxidized to a carboxylic acid.

This can be accomplished by treating toluene with a strong oxidizing agent, such as potassium permanganate (KMnO4) or chromic acid (H2CrO4).

The oxidation of the methyl group in toluene results in the formation of benzoic acid.

7. Reduction of nitro group: Nitro groups (-NO2) can be reduced to amino groups (-NH2) by various reducing agents, such as hydrogen gas in the presence of a metal catalyst (e.g., palladium, Pt).

For example, nitrobenzene can be reduced to aniline (phenylamine) by catalytic hydrogenation.

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Which property is conserved in both nuclear reactions and chemical
reactions?
A. Total number of protons and neutrons
O B. Number of atoms
C. Total mass of atoms
O D. Type of atoms

Answers

Answer:

A. Total number of protons and neutrons

Explanation:

In both nuclear reactions and chemical reactions, the total number of protons and neutrons are conserved.

It implies that the starting number of protons and neutrons in both reactions must be the same.

Chemical reactions involves, loss, gain or sharing electrons between two atoms.

Nuclear reactions deals with the nucleus of an atom.

It must be ensured that the mass and atomic number in nuclear reactions is conserved.

Answer:

Total number of protons and neutrons

Explanation:

Ap3x

How many moles of water could you make with 0.5 mol of H2?

Answers

Answer:

0.5 mols of water

Explanation:

3. In which 1. 0-gram sample are the particles arranged in a crystal structure? A) CaCl2(s) B) C2H6(g) C) CH3OH(l) D) CaI2(aq)

Answers

According to the given information CaCl₂(s) are the particles arranged in a crystal structure.

The correct option is A.

What is crystal structure and its types?

A crystal system is composed of a number of axes. Or, to put it another way, the structure is an arranged grouping of atoms, ions, or molecules. The crystal structure is made up of bonded atoms, atom clusters, or molecules. Due to the constituent particles' innate propensity to arrange themselves in symmetrical patterns, this structure forms.

Briefing:

This inorganic salt is crystallized calcium cations and chlorine anions. Ions are grouped in a systematic way.

Ethane (C₂H₆) is a gas; the symbol for a gas in chemistry or its physical state is g. Gases lack a solid structure.

Methanol (CH₃OH) is a liquid; the symbol for liquids in chemistry is l, and it lacks a structural structure.

Since water dissolves calcium iodide, the resulting aqueous solution (aq) lacks a crystal structure.

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Force, mass, and acceleration have to do with which law of motion?
Newton's 1st Law
Newton's 2nd Law
Newton's 3rd Law
Newton's 4th Law

Answers

Newton's law of motion states the relationship between the force acting on the body in motion. The relation between force, mass, and acceleration is given by Newton's second law.

What is Newton's second law?

Newton's second law states the relationship between mass, force, and acceleration. It relates the force with the change of the motion of an object with a mass.

Newton's second law is given as,

\(\rm F = ma\)

Where F is force, m is the mass of the object and a is the acceleration.

Newton's first law is about inertia, the third law is about the law of action and reaction, and the fourth law is about the law of gravitation.

Therefore, option B. Newton's second law states the relationship between force, mass, and acceleration.

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In order for something to be scientific, it needs to be ________________, ___________________, _________________, and __________________.

Answers

Answer:

In order for something to be scientific it needs to be:

a) observable

b) replicable;

c) falsifiable,

d) testable

Explanation:

A) Science does not deal with non-obserbale or faith based phenomena. If it's not observable, it probably imaginary, therefore unscientific.

B) a scientists must be able to replicate phenomena under controlled environments in order to study it more closely.

C) a scientific phenomena must allow for the formation of a hypothesis. That is, if it is scientific, then the phenomena should allow for an explanation (no necessarily the right one) to be postulated at an experiment

D) the hypothesis surrounding the scientific pheonomena must be testable.

Cheers!  

Identify the key differences between the Articles of Confederation and the U.S. Constitution. Then explain which document created the better system of government for the new nation, and support your response with the differences you have identified.
22 POINTS + WILL RATE BRAINLEST!!!!!

Answers

The key differences between the Articles of Confederation and the U.S Constitution is the article of confederation is sovereignty in states and the constitution  is expand the governments authority.

The document created the better system of government for the new nation is the US constitution.

The Article of confederation , the state have stronger power than the central power and in the US constitution , the power of central government is stronger than the states. The important development was the establishment of three departments. There are three departments of government that is legislative , executive and judicial.

Thus, The key differences between the Articles of Confederation and the U.S. Constitution is the article of confederation is sovereignty in states and the constitution  is expand the governments authority.

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The compounds that form from the bonding of the hydroxyl group (-OH) to a hydrocarbon are called the aldehydes.
True
False

Answers

i think its true, not 100% sure tho

Answer:

False.

I just got it right, lol.

during the cell cycle, compounds called cyclins increase and decrease in a regular pattern. what is the role of cyclins?

Answers

During the cell cycle, compounds called cyclins increase and decrease in a regular pattern. They regulate the stages of cell division and growth.

Cell cycle development is regulated in element by way of the sequential pastime of various cyclins. The cyclins are regulatory subunits that bind, prompt and provide substrate specificity for their catalytic companion serine-threonine kinases, collectively called cyclin-established kinases.

Cyclins are a family of proteins that don't have any enzymatic interest of their personal however spark off CDKs through binding to them.

S cyclins are involved inside the induction of DNA replication and early stages of mitosis. Their stages upward push at the beginning of S phase and fall in early mitosis.

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This Example Illustrates Gasoline Blending Problems Faced In A Petroleum Refinery. We Need To Blend Gasoline From Three

Answers

Gasoline blending in petroleum refineries involves analyzing the properties of different components and determining the optimal mixing ratios to produce gasoline that meets specific octane rating and quality requirements.

Gasoline blending is a critical process in petroleum refineries where different components are combined to produce the desired gasoline product. In this example, the challenge is to blend gasoline from three different components.

To solve the gasoline blending problem, various factors need to be considered such as the desired octane rating, volatility, and environmental regulations. The first step is to determine the optimal proportion of each component based on their individual characteristics. This involves analyzing the properties of each component, such as its research octane number (RON), motor octane number (MON), and vapor pressure.

The second step is to develop a blending strategy that achieves the desired gasoline specifications. This involves determining the appropriate mixing ratios of the three components to meet the target octane rating and other quality requirements. The blending process requires precise calculations and adjustments to ensure the final gasoline product meets the desired specifications.

Additionally, economic considerations play a role in gasoline blending. The cost of each component and the market demand for specific gasoline grades can influence the blending decisions. Refineries aim to optimize the blend to minimize costs while meeting quality standards.

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Is silicon(IV) oxide the same as silicon dioxide

Answers

Answer:

Yes, it is

Explanation:

Silicon (IV) oxide, commonly known as silica is a substance that majorly constitutes SAND. It has the chemical formula, SiO2, which contains a combination of silicon and oxygen.

The IUPAC name of SiO2 is Silicon IV oxide, which can also be referred to as Silicon dioxide because the structure the compound contains two (-di) oxygen atoms. Hence, based on the question, silicon(IV) oxide is the same as silicon dioxide.

How many bromide ions are there in 2.00g of MgBr2?

Answers

There are 1.31 x 1022 bromide ions in 2.00 g of \(MgBr_2\).

The chemical formula of magnesium bromide (\(MgBr_2\)) contains one magnesium ion (\(Mg2^+\)) and two bromide ions (Br-). To find the number of bromide ions in 2.00 g of \(MgBr_2\), we need to use the molar mass of \(MgBr_2\) to determine the number of moles of \(MgBr_2\) present in 2.00 g of the compound, then use the stoichiometry of the chemical formula to determine the number of bromide ions present. First, we need to calculate the molar mass of \(MgBr_2\). The molar mass of \(MgBr_2\) is equal to the sum of the atomic masses of magnesium (Mg) and two bromine (Br) atoms. The atomic mass of Mg is 24.31 g/mol, and the atomic mass of Br is 79.90 g/mol. Molar mass of \(MgBr_2\) = 24.31 g/mol + (2 x 79.90 g/mol)  = 184.11 g/mol Next, we can use the molar mass to determine the number of moles of \(MgBr_2\) present in 2.00 g of the compound: Number of moles of \(MgBr_2\) = mass of \(MgBr_2\) / molar mass of \(MgBr_2\)
= 2.00 g / 184.11 g/mol
= 0.0109 mol Finally, we can use the stoichiometry of the chemical formula to determine the number of bromide ions present:  Number of bromide ions = 2 x number of moles of \(MgBr_2\)
= 2 x 0.0109 mol
= 0.0218 mol Therefore, there are 0.0218 moles of bromide ions in 2.00 g of \(MgBr_2\). To convert this to the number of bromide ions, we can multiply by Avogadro's number (6.02 x 1023): Number of bromide ions = 0.0218 mol x 6.02 x 1023 ions/mol  = 1.31 x 1022 ions

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serup is which solution​

Answers

Answer:

dilute solution . . . . . . .

Explanation:

. .

Answer:

dilute soloution

Explanation:

dilute soloution as it dissolves

a . liquid and solid
b. liquid only
c. liquid and gas
d. gas only

a . liquid and solidb. liquid only c. liquid and gas d. gas only

Answers

Answer:

i think it represents gas only becoz that is vaporization curve

How Many Moles Of HCl Need To Be Added To 150.0 ML Of 0.50 M NaZ To Have A Solution With A PH Of 6.50

Answers

The number of mole of HCl needed for the solution is 1.035×10¯³ mole

How to determine the pKa

We'll begin by calculating the pKa of the solution. This can be obtained as follow:

Equilibrium constant (Ka) = 2.3×10¯⁵pKa =?

pKa = –Log Ka

pKa = –Log 2.3×10¯⁵

pKa = 4.64

How to determine the molarity of HCl pKa = 4.64pH = 6.5Molarity of salt [NaZ] = 0.5 MMolarity of HCl [HCl] =?

pH = pKa + Log[salt]/[acid]

6.5 = 4.64 + Log[0.5]/[HCl]

Collect like terms

6.5 – 4.64 = Log[0.5]/[HCl]

1.86 = Log[0.5]/[HCl]

Take the anti-log

0.5 / [HCl] = anti-log 1.86

0.5 / [HCl] = 72.44

Cross multiply

0.5 = [HCl] × 72.44

Divide both side by 72.44

[HCl] = 0.5 / 72.4

[HCl] = 0.0069 M

How to determine the mole of HCl Molarity of HCl = 0.0069 MVolume = 150 mL = 150 / 1000 = 0.15 L Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 0.0069 × 0.15

Mole of HCl = 1.035×10¯³ mole

Complete question

How many moles of HCl need to be added to 150.0 mL of 0.50 M NaZ to have a solution with a pH of 6.50? (Ka of HZ is 2.3 x 10 -5 .) Assume negligible volume of the HCl

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In the combustion of ethane, how many moles of co2 can be produced from 1. 00 mole of c2h6?.

Answers

If 1.00 mole of \(C_{2}H_{6}\) is combusted, then the amount of \(CO_{2}\) produced would be 2 times that amount, or 2.00 moles of \(CO_{2}\).

The balanced chemical equation for the combustion of ethane is \(C_{2}H_{6}\) + 3.5\(O_{2}\) -> 2\(CO_{2}\) + 3\(H_{2}O\). This means that for every 1 mole of \(C_{2}H_{6}\) that is combusted, 2 moles of \(CO_{2}\) are produced.

Therefore, if 1.00 mole of \(C_{2}H_{6}\) is combusted, then the amount of \(CO_{2}\) produced would be 2 times that amount, or 2.00 moles of \(CO_{2}\).

It is important to note that this calculation assumes that the reaction proceeds to completion, meaning that all of the reactants are consumed and all of the products are formed.

In reality, reactions may not always go to completion due to factors such as incomplete mixing or side reactions.

Additionally, there may be other factors that affect the stoichiometry of the reaction, such as the temperature, pressure, and presence of catalysts.

Therefore, the actual amount of \(CO_{2}\) produced in a real-world scenario may differ from the theoretical calculation based on the balanced equation.

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A chemist measures the amount of mercury in sediment samples from three areas of a river (the source, the midway point, and the
mouth).

Which is the most reasonable hypothesis for the chemist's experiment?

If a chemical plant near the source of the river is dumping mercury, then the mercury levels should be highest at the mouth
and lowest at the source.

If a chemical plant near the source of the river is dumping mercury, then the mercury levels should be highest at the mouth
and lowest at the midway point.

If a chemical plant near the source of the river is dumping mercury, then the mercury levels should be the same all along
the river.

If a chemical plant near the source of the river is dumping mercury, then the mercury levels should be highest at the
source and lowest at the mouth.

Answers

If a chemical plant near the source of the river is dumping mercury, then the mercury levels should be highest at the source and lowest at the mouth.

Further testing should show that this is a commonly followed rule. Observations should be explained in a published scientific paper. Scientists look for answers to questions and solutions to problems using a process called the scientific method. This process consists of observation, hypothesis development, and experimental design. Bringing additional observations hypotheses, and experiments in repeated cycles

Chemists use the scientific method to conduct experiments formulate hypotheses formulate laws, and develop theories to better understand how the natural world behaves. In scientific thinking, hypotheses are formed before applicable research is conducted. The theory, on the other hand, is supported by evidence. This is a principle formulated as an attempt to explain what the data already support.

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At what degree of sloping dose soil erosion begin to taper off

Answers

There is no specific threshold or degree of slope steepness at which soil erosion abruptly begins to taper off

Soil erosion is influenced by various factors, including slope steepness, rainfall intensity, soil characteristics, vegetation cover, and land management practices. As slope steepness increases, the potential for soil erosion generally increases due to the gravitational force acting on the eroded materials. However, there is no specific threshold or degree of slope steepness at which soil erosion abruptly begins to taper off. The relationship between slope steepness and soil erosion is generally non-linear. At low slope angles, soil erosion tends to be minimal as the gravitational force is relatively weak. As the slope angle increases, soil erosion typically increases exponentially due to the increased force of gravity. Eventually, as the slope steepness continues to increase, soil erosion may reach a point of maximum potential where the erodibility of the soil and other factors become limiting factors. Beyond this point, the rate of soil erosion may start to taper off, but it does not completely stop. Instead, it may stabilize or decrease slightly compared to the maximum erosion potential observed at steeper slopes.

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True or false, Henry Moseley discovered through X-Ray crystallography the number of neutrons that were present
in the nucleus of atoms of every element.

Answers

Answer:

Im pretty sure its true

Explanation:

Answer:

answer is true .

Explanation:

this may help you

decide which element probably forms a compound with hydrogen that has a chemical formula most and least similar to the chemical formula of the compound formed by hydrogen and selenium.potassium,sulfur,chlorine,fluorine

Answers

The element that probably forms a compound with hydrogen that has a chemical formula most and least similar to the chemical formula of the compound formed by hydrogen and selenium is sulfur.

Sulfur is in the same group as selenium, which means they have similar chemical properties. Therefore, sulfur would most likely form a compound with hydrogen that has a chemical formula similar to hydrogen selenide (H₂Se), the compound formed by hydrogen and selenium. On the other hand, chlorine and fluorine are both highly reactive nonmetals that would not likely form compounds with hydrogen in a similar way to selenium.

Potassium is a highly reactive metal and would not likely form a compound with hydrogen in a similar way to selenium either.

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You generate a chimeric gfp to which you added the first 18 amino acids encoded by the bip gene to the beginning of the gfp coding region. You also changed the last 4 amino acids of gfp to leu-ala-gly-lys. What will you most likely observe if you express this chimeric gfp in an otherwise normal cell?.

Answers

Using DNA recombinant technology, scientists combine the Gfp gene with another gene that generates a protein they wish to study, and then they introduce the resultant complex into a cell. If a cell produces the green fluorescence, scientists infer that it is expressing the target gene.

In intact cells, GFP is a known marker for protein targeting and gene expression. It is widely utilized as genetically encoded fluorescent markers in biological investigations. This fluorescent marker is used to research how proteins interact and allows for multicolor labeling.

Because it retains its fluorescent properties when recombinantly expressed in both prokaryotic (Escherichia coli) and eukaryotic (Caenorhabditis elegans and Drosophila melanogaster) living cells, the green fluorescent protein (GFP) of the jellyfish Aequorea victoria can be used as a potent marker of gene expression in vivo.

The non-essential amino acids include alanine, asparagine, aspartic acid, glutamic acid, and serine.

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You generate a chimeric gfp to which you added the first 18 amino acids encoded by the bip gene to the
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