a 1.44 gram sample of an unknown gas is found to occupy a volume of 0.828 l at a pressure of 829 mmhg and a temperature of 51 °c. assume ideal behavior. the molar mass of the unknown gas is g/mol.

Answer:The Precambrian era envelopes the major bulk of the history of the Earth, beginning from the creation of the planet approx 4.5 billion years ago and terminating with the origination of composite, multicelled forms of life approximately 4 billion years after.

The Precambrian refers to the earliest of the geologic ages that are signified by the distinct layers of sedimentary rock. The Earth was about more than six hundred million years old when life started. The planet had cooled down from its native molten state, creating a solid crust and oceans formed by water vapor in the atmosphere.

At about three billion years ago, the atmosphere of the Earth was virtually devoid of oxygen. At approximately 2.4 billion years ago, oxygen was discharged from the seas as a waste product of photosynthesis by cyanobacteria. The levels of the gas slowly raised, attaining about 1 percent around two billion years ago.

Approximately 800 million years ago, the levels of oxygen attained about 21 percent and started to breathe life into more composite species. The oxygen-rich ozone layer was also created, protecting the surface of the Earth from the harmful solar radiation.

Explanation:i hope this helps! :)

Answer:

The Precambrian era envelopes the major bulk of the history of the Earth, beginning from the creation of the planet approx 4.5 billion years ago and terminating with the origination of composite, multicelled forms of life approximately 4 billion years after.

The Precambrian refers to the earliest of the geologic ages that are signified by the distinct layers of sedimentary rock. The Earth was about more than six hundred million years old when life started. The planet had cooled down from its native molten state, creating a solid crust and oceans formed by water vapor in the atmosphere.

At about three billion years ago, the atmosphere of the Earth was virtually devoid of oxygen. At approximately 2.4 billion years ago, oxygen was discharged from the seas as a waste product of photosynthesis by cyanobacteria. The levels of the gas slowly raised, attaining about 1 percent around two billion years ago.

Approximately 800 million years ago, the levels of oxygen attained about 21 percent and started to breathe life into more composite species. The oxygen-rich ozone layer was also created, protecting the surface of the Earth from the harmful solar radiation.

Explanation:

Answer:

copper(ll) has 4 oxygen atoms

Answer:

Oxygen forms a double bond in the O2 molecule, and sulfur, selenium, and tellurium form two single bonds in various rings and chains. The halogens form diatomic molecules in which each atom is involved in only one bond. This provides the electron required necessary to complete the octet on the halogen atom.

Explanation:

Answer:

it is #I or (A)

Explanation:

Answer: 6.45 Joules

Explanation: I just did it

Thus mass of dye A = 10.24 mg/L

Plot Beer-Lambert law

Beer-Lambert law states that absorbance of an analye (here, dye A) is directly proportional to its concentration (C) and pathlength (l) of the solution

i.e. A \propto  C*l

or A = \epsilonCl

where \epsilon = proportionality constant and is called absorptivity coefficient. It is characteristic for an analyte at a given wavelength, unit = M-1cm-1

Thus above equation can be compared with a straight line equation as y = mx+c

where y = absorbance, x = concentration and \epsilon = slope, c = intercept = 0 for absorbance vs concentration plot.

b. Calculate the slope (m) of graph:

for absorbance vs concentration plot.

The given data was plotted and fitted to a liner fit that gave the equation as:

y = 27335 x

slope of the line = 27335

thus \epsilon = 27335 M-1cm-1

c. Concnetration using Beer-Lambert plot:

Absorbance of dye A in Sports drink, A = 0.700

point absorbance of 0.007 on y-axis and interpolate to the linear fit. Check the corresponding value at x-axis as follows:

the corresponding line meets x-axis at 0.00002 + 4-squares

In the graph drawn, 7 squares in x-axis = 0.00001

thus 4 squares on x-axis = 0.00001*4/7 = 5.71*10-6

thus for y = 0.700 the corresponding x-axis reads = 0.00002+5.71*10-6

or C = 2.57*10-5 M

d. Concnetration of dye A using slope of fitted line:

Absorbance of dye A in Sports drink, A = 0.700

substituting the absorbance in the linear fit equation we can calulate the concentration as:

0.700 = 27335*C

C = 0.700/27335

C = 2.56*10-5 M

e. Mass of dye A in mg/L

Molar mass of dye = 400 g/mol

Concentration (molarity) of dye A = 2.56*10-5 M

1 M = number of moles of solute present in 1 L of solution volume

number of moles = mass / molar mass

\therefore  Molarity = mass of solute/(molar mass of solute*volume of solution)

for solution volume = 1L

Molarity = mass of solute/molar mass of solute

rearranging this we get:

mass of solute = (Molarity*molar mass of solute) g/L

mass of dye A = 2.56*10-5* 400 g/L

m = 0.01024 g/L

1 g = 1000 mg

Thus mass of dye A = 10.24 mg/L

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Answer:

Supercontinent is a single landmass formed by the combination of many Earth's continental blocks or cratons.

Supercontinents form and split up every 400 or 500 million years and the last supercontinent was formed 300 million years ago, so it is possible that any of the modern continents will combine together to form a new supercontinent in future.

Answer:

Yes, modern continents could recombine to form a new supercontinent. Because the continents move at different rates and in different directions, it’s likely that in the future, continents will collide and join together.

Explanation: Edmentum's EXACT ANSWER SO DO NOT COPY!  Rewrite it in your own words.

Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

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Answer:

Outside or External

Explanation:

Take for example, an Exothermic reaction. This just means that the reaction releases heat to the outside.

Answer:

It means out of, away from, outer, external, outside, or exterior.

Explanation:

Hope this helps!

Brainliest if correct pls

Answer:

There are significant environmental impacts associated with coal mining and use. It could require the removal of massive amounts of top soil, leading to erosion, loss of habitat and pollution. Coal mining causes acid mine drainage, which causes heavy metals to dissolve and seep into ground and surface water.

Explanation:

I hope it will help you...

Answer(s):

Template: reactants ⇒ products

1. \(Ag+KNO_3\) ⇒ \(AgNO_3 + K\)

2. \(Zn+AgNO_3\) ⇒ \(Zn(NO_3)_2 + Ag\)

3. \(Al + H_2SO_4\) ⇒ \(Al_2(SO_4)_3 + H_2\)

4. \(Cl_2+KI\) ⇒ \(HCl + I_2\)

5. \(Li + H_2O\) ⇒ \(LiOH + H_2\)

6. \(Cu + FeSO_4\) ⇒ \(CuSO_4 + Fe\)

7. \(Na + H_2O\) ⇒ \(NaOH + H_2\)

8. \(Fe+Pb(NO_3)_2\) ⇒ \(Fe(NO_3)_2 + Pb\)

9. \(Cu+H_2O\) ⇒ \(CuO + H_2\)

10. \(Cu+Al_2(SO_4)_3\) ⇒ \(CuSO_4 + Al\)

11. \(Al + Pb(NO_3)_2\) ⇒ \(Al(NO_3)_3 + Pb\)

What is a chemical equation?

A chemical equation consists of the chemical formulas of the reactants (on the left) and the products (on the right). The two are separated by an arrow symbol (“→” usually read aloud as “yields”). Each individual substance's chemical formula is separated from others by a plus sign.

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•.. (,('')('') helped :)

Answer:

option first is the right answer

Answer:

2NaBr+Cl2=2NaCl+Br2

Explanation:

each side Na2 Br2 Cl2 atom

The molecular formula of of tobacco that composed of C, H, and N, and A 0.005250 g sample of nicotine was combusted, producing 0.014242 g of CO₂ and 0.004083 grams of H₂O = C₁₀H₁₄N₂.

To determine the empirical formula, we have to divide each member of moles by the smallest one.

Number of C atoms = 3.237 x 10⁻⁴ / 0.646 x 10⁻⁴

= 5

Number of H atoms = 4.536 x 10⁻⁴ / 0.646 x 10⁻⁴

= 7

Number of N atoms = 0.646 x 10⁻⁴ / 0.646 x 10⁻⁴

= 1

Hence, the empirical formula = C₅H₇N

Now, determine the empirical formula mass:

Mass of C₅H₇N = (5 x C) + (7 x H) + (N)

= (5 x 12 + (7 x 1.008) + (14.007)

= 81.118 g/mol

Divide the molar mass of he compound by the empirical formula mass.

(160 ± 5 gr/mol) / 81.118 g/mol

≈ 2

Multiply the empirical formula by 2.

So, the molecular formula = C₁₀H₁₄N₂

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: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.

Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.

Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.

Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.

Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.

Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.

Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.

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The reaction temperature X in a certain chemical process follows a uniform distribution with parameters A = -6°C and B = 6°C.

In a uniform distribution, the probability density function (PDF) is constant within a given interval and zero outside that interval. Since the reaction temperature follows a uniform distribution with parameters A = -6°C and B = 6°C, the interval for the temperature values is [-6, 6].

The PDF of a uniform distribution is given by:

\(\[ f(x) = \frac{1}{B - A} \]\)

Substituting the values, we have:

\(\[ f(x) = \frac{1}{6 - (-6)} = \frac{1}{12} \]\)

This means that the PDF of the reaction temperature X in the chemical process is \(\frac{1}{12}\) within the interval [-6, 6], and it is zero outside this interval.

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Answer:

protons plus neutrons

Explanation:

jsut the definition

Answer:

protons

Explanation:

the sum of the numbers of protons and neutrons present in the nucleus of an atom

Answer:

The correct answer is - reactants.

Explanation:

In any chemical reaction, there is an arrow that distinguishes the two major components of the chemical equation by placed in between them. These two components are reactants and products.

OftenlThe reactants placed on the left side of a chemical equation and the products placed on the right side of a chemical equation. In this given case, the reactants 2H2 + 1O2 are placed on the left side of the equation.

The average kinetic energy of CH4 molecules in a sample of methane gas at 273K and 546K  

6.00 x 10^-21 J and  1.19 x 10^-20 J

To calculate the average kinetic energy of CH4 molecules in a sample of methane gas at 273K and 546K, we need to use the formula:

KEavg = (3/2) kT

where KEavg is the average kinetic energy, k is the Boltzmann constant (1.38 x 10^-23 J/K), and T is the temperature in Kelvin.

At 273K, the average kinetic energy of CH4 molecules is:

KEavg = (3/2) x (1.38 x 10^-23 J/K) x (273K)

At 546K, the average kinetic energy of CH4 molecules is:

KEavg = (3/2) x (1.38 x 10^-23 J/K) x (546K)

Therefore, the average kinetic energy of CH4 molecules in a sample of methane gas increases as the temperature increases. This is because at higher temperatures, the molecules have more kinetic energy and move faster.

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i think a or c but I'm not 100% sure

Answer:

A. Carbohydrate is a coumpound. Oxygen is an element.

Explanation:

Carbohydrates are organic compounds that are organized as ring structures and are always composed of the elements carbon, hydrogen, and oxygen. Carbohydrates are truly hydrates of carbon because the ratio of hydrogen atoms to oxygen atoms is always nearly 2:1, as in H2O. Pure oxygen gas consists of molecules but it is still considered an element, rather than a compound, as the molecules are made up of a single type of element. Compounds are made up of one or more element.

Answer:

The strength of the field varies depending on its location around the magnet. The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole when compared with the south pole.

Explanation:

The steps for solving a problem involving the ideal gas law are:

Step 1: Identify known and unknown variables

Step 2: Rearrange the ideal gas law to isolate the unknown variable and perform any necessary unit conversions.

Step 3: Solve for the unknown variable.

To solve a problem, the first step is to identify the known and unknown variables. In ideal gas law, the variables are P (pressure), V (volume), n (number of moles of gas), R (universal gas constant), and T (temperature). If three variables are known, we can use the ideal gas law to determine the fourth variable.

To isolate the unknown variable in the ideal gas law equation, we need to rearrange the equation. For example, if we want to solve for the number of moles of gas (n), we would rearrange the equation as follows:

n = PV/RT

After rearranging the ideal gas law equation, we can solve for the unknown variable by substituting the known values and performing the necessary calculations. This will result in the value of the unknown variable expressed in the appropriate units.

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The reaction that produces chlorine gas is \(FeCl3(aq) + Br2(l) → FeBr3(aq) + Cl2(g)\). This is the correct option D.

This is a redox reaction where \(FeCl3\) is the oxidizing agent and \(Br2\) is the reducing agent.

\(FeCl3\)oxidizes \(Br2\), causing it to lose electrons and form \(FeBr3\) and\(Cl2\). Chlorine gas is produced as a product of the reaction.

The other options do not produce chlorine gas.

Option a produces hydrogen gas and\(FeCl2\) as a product.

Option b produces copper(II) chloride and\(Fe\) as a product.

Option c produces calcium chloride and \(Fe(NO3)3\) as a product.

Option e produces no reaction as fluorine gas is too reactive to react with \(FeCl3\).

In conclusion, the correct option that produces chlorine gas is d. \(FeCl3(aq) + Br2(l) → FeBr3(aq) + Cl2(g)\).

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The mass of the product is 25.5 g.

A reaction takes place between reactants and products in a reaction system. The reaction in this case could be written as;

4C3H6 + 6NO --> 4C3H3N + 6H2O + N2

Number of moles of C3H6 = 21.6 g/42 g/mol = 0.51 moles

Number of moles of NO = 21.6 g/30 g/mol = 0.72 moles

Given that 4 moles of C3H6 reacts with 6 moles of NO

0.51 moles of  C3H6 reacts with 0.51 moles  *  6 moles / 4 moles

= 0.77 moles

This implies that NO is the limiting reactant.

Hence;

6 moles of NO produces 4 moles of C3H3N

0.72 moles of NO produces 0.72 moles * 4 moles/6 moles

= 0.48 moles of C3H3N

Mass of C3H3N =0.480 mol ×53.06 g/mol= 25.5 g

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Explanation:

To solve the problem, we can use the freezing point depression equation:

ΔT = Kf · molality

where ΔT is the change in freezing point, Kf is the freezing point depression constant, and molality is the concentration of the solution in moles of solute per kilogram of solvent.

In this case, we're looking for the freezing point of a solution of C5H4 in benzene, given that the freezing point of pure benzene is 5.50 °C, and the freezing point depression constant is 5.12 °C/m.

First, let's calculate the molality of the solution:

molality = moles of solute / kilograms of solvent

To find the moles of solute, we need to know the molar mass of C5H4. By looking it up in a periodic table, we find:

Molar mass of C5H4 = 64.09 g/mol

The problem doesn't tell us how much solute was added, but it does give us the concentration of the solution as 0.41 m (which means 0.41 moles of C5H4 per kilogram of benzene). Therefore:

molality = 0.41 moles / 0.998 kg ≈ 0.411 mol/kg

Now we can calculate the freezing point depression:

ΔT = Kf · molality

ΔT = 5.12 °C/m · 0.411 mol/kg ≈ 2.10 °C

The freezing point depression tells us how much the freezing point of the solution is lowered compared to the freezing point of pure benzene. Therefore, the freezing point of the solution is:

Freezing point = 5.50 °C - 2.10 °C = 3.40 °C

Therefore, the freezing point of the 0.41 m solution of C5H4 in benzene is 3.40 °C.

Answer:

C: Most particles in the plasma are heavy, slow, and very low density.

Explanation:

i'm smart like dat

Answer:

C is correct

Explanation:

CH2Cl2 has both dipole-dipole interactions and London dispersion forces as its intermolecular forces.

In CH2Cl2 (dichloromethane), the types of intermolecular forces present are:
1. Dipole-dipole interactions: These occur between polar molecules, like CH2Cl2, which have a positive and a negative end (dipole). In CH2Cl2, the electronegative chlorine atoms pull electron density away from the carbon and hydrogen atoms, creating a dipole moment.
2. London dispersion forces: These are temporary, weak attractive forces that occur between all molecules, including nonpolar ones. They arise due to random fluctuations in the electron distribution, leading to temporary dipoles.
In summary, CH2Cl2 has both dipole-dipole interactions and London dispersion forces as its intermolecular forces. These forces are generally weaker than the covalent bonds within the CH2Cl2 molecules themselves.

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