A 1.018 g sample pure platinum metal was reacted with HCl to form 1.778 g of a compound containing only platinum and chlorine. Determine the empirical formula of this "Pt-Cl" Compound.

Answers

Answer 1

Answer:

\(PtCl_4\)

Explanation:

Hello!

In this case, since HCl and Pt react according to the following chemical equation:

\(HCl+Pt\rightarrow PtCl_x+H_2\)

Whereas PtClx is the compound containing Pt and Cl; thus, since 1.018 g out of 1.778 g correspond to Pt and therefore 0.760 g to chlorine, so we determine the empirical formula of this compound by firstly computing the moles of each element:

\(n_{Pt}=1.018gPt*\frac{1molPt}{195.084gPt}=0.00522molPt\\\\\\n_{Cl}=0.760gCl*\frac{1molCl}{35.45gCl} =0.0214molCl\)

Now, we divide the each moles by those of Pt as the fewest ones in order to compute their subscripts in the empirical formula:

\(Pt=\frac{0.00522}{0.00522}=1 \\\\Cl=\frac{0.0214}{0.00522} =4\)

Thus, the required formula is:

\(PtCl_4\)

Best regards!


Related Questions

PLEASE ANSWER QUICKLY!!!!

2KI (aq) + Cl₂(g) → 2KCl(aq) + 1₂(g)
What volume of 12 gas forms when
21 L Cl2 react at STP?
[?] L 12

PLEASE ANSWER QUICKLY!!!!2KI (aq) + Cl(g) 2KCl(aq) + 1(g)What volume of 12 gas forms when21 L Cl2 react

Answers

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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Given the following data. (i) Ca(s) + 2C(grafite) -> Cacis) X Ca(s) + ⅐0›(g) -> Cao(s) (iit) CaO(s) + H›O(I) -> Ca(OH)(ag) (iv) CHi(g) + 5/20,(8) -> 2C0,(g) + H,0(1) X* (v) C(grafite) + 02(g) -> CO›(g) [4 marks] AH = -62.8 kJ AH = -635.5 kJ AH = -653.1 kJ AH= -1300.0 kJ AH = -393.5 kJ / Calculate AH for the following reaction by using Hess's law and manipulating the given reactions: CaC(s) + H,O(I) - Ca(OH),(ag) + GHa(g) AH = ?

Answers

The enthalpy change (ΔH) for the reaction CaC(s) + H2O(I) → Ca(OH)(ag) + CH4(g) is -3617.6 kJ.

To calculate ΔH for the reaction CaC(s) + H2O(l) → Ca(OH)2(ag) + CH4(g), we can use Hess's law, which states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states.

We can manipulate the given reactions to obtain the desired reaction:

(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X (unknown value)

(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

Now, let's manipulate these equations to cancel out the common reactants and products and obtain the desired reaction:

(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X

(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

Now, let's sum up the equations to obtain the desired reaction:(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X

(ii) 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1271 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

By adding equations (ii), (iii), (iv), and (v), we can cancel out CaO(s), H2O(l), and O2(g):

2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -1271 -653.1 -1300.0 -393.5

2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -3617.6 kJ

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Consider the following reaction:

CO(g)+2H2(g)⇌CH3OH(g)

A reaction mixture in a 5.15-L flask at a certain temperature initially contains 26.6 g CO and 2.36 g H2. At equilibrium, the flask contains 8.63 g CH3OH.

Part A
Calculate the equilibrium constant (Kc) for the reaction at this temperature.

Answers

Answer:

26.6

Explanation:

Step 1: Calculate the molar concentrations

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

[CO]i = 26.6 g / (28.01 g/mol) × 5.15 L = 0.184 M

[H₂]i = 2.36 g / (2.02 g/mol) × 5.15 L = 0.227 M

[CH₃OH]e = 8.63 g / (32.04 g/mol) × 5.15 L = 0.0523 M

Step 2: Make an ICE chart

        CO(g) + 2 H₂(g) ⇄ CH₃OH(g)

I        0.184      0.227           0

C         -x           -2x             +x

E     0.184-x   0.227-2x        x

Since [CH₃OH]e = x, x = 0.0523

Step 3: Calculate all the concentrations at equilibrium

[CO]e = 0.184-x = 0.132 M

[H₂]e = 0.227-2x = 0.122 M

[CH₃OH]e = 0.0523 M

Step 4: Calculate the equilibrium constant (Kc)

Kc = [CH₃OH] / [CO] [H₂]²

Kc = 0.0523 / 0.132 × 0.122² = 26.6

Calculate Theoreticalyield of water g that can be obtained drum combustion of 173g methane

Answers

Answer:

25gc6h1206

Explanation:

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Answers

Answer:

1. The two gases making the highest relative contribution to the greenhouse gases are: "CO2 and CH4."

2. The effect of increasing amount of greenhouse gasses is: "All of the above"

3. Which one of the following is a wrong statement?: "Eutrophication is a natural phenomenon in freshwater bodies"

4. The major contributors to the greenhouse gases are: "All of the above"

Explanation:

CO2 is carbon dioxide, and CH4 is methane. Also, the greenhouse gas effect is natural, except, the amount of greenhouse gases is not.

Mechanical weathering does not change a rock’s
A
shape.

B
size.

C
appearance.

D
composition.

Answers

Answer:

C

Explanation:

Answer:

B: Size

Explanation: It can break it into smaller pieces but not change its composition.

The diagram shows different forms of thermal energy transfer.
Which process is making the pot's handle hot?

Answers

Answer:

Conduction

Explanation:

The handle is touching the pot.

And I got it wrong

how many cats are in the word

Answers

Answer: more than 70,00 and most of that population is living on the streets

Please I need help thank you

Please I need help thank you

Answers

Answer:

its sodium hydroxide

Explanation:

cholorine is more reactive than nitrogen? why

Answers

Answer:

Because of the presence of lone pairs in nitrogen it further adds to its reactivity. Hence nitrogen is more electronegative than chlorine. ... Chlorine is less reactive than nitrogen in other words nitrogen is more reactive than chlorine

Explanation:

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I NEED THIS RIGHT NOW!! Daria had some sand from the beach. The mass of the sand was 72 grams. She used the graduated cylinder below to measure the volume.
What is the volume of the sand found in the graduated cylinder? _____ mL

I NEED THIS RIGHT NOW!! Daria had some sand from the beach. The mass of the sand was 72 grams. She used

Answers

Daria had some beach sand with her. The sand has a 72 gramme mass. She calculated the volume using the graduated cylinder below. The graduated cylinder contains 15 mL of sand.

The volume of the sand is calculated using the graduated cylinder below. The sand's bulk is specified as 72 grammes.

We can use the water displacement method to calculate the volume of the sand. Following is a description of how to estimate the amount of sand using the water displacement method:

The graduated cylinder of water should first be measured for volume.

The graduated cylinder's water volume should then be measured after adding the sand to it. The volume of water increases by the same amount.

Let's use the provided problem to implement this approach.

In the beginning, there is 10 mL of water in the graduated cylinder. The graduated cylinder contains 25 mL of water once the sand has been added.

The amount of sand is therefore equal to the difference between the two volumes, which is: Sand volume equals final water volume minus initial water volume (25 - 10 = 15 mL).

As a result, there are 15 mL of sand in the graduated cylinder.

Answer : 15

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What is the final temperature when 20.0 g of water at 25°C is mixed with 30.0 g of water at 80°C?

Answers

Answer:

80°C

Explanation:

because I'm mixed temperature of watere

The principle of calorimetry is used here to determine the final temperature. The final temperature of water is 58 units.

What is the principle of calorimetry?

When two or more bodies are brought in contact with each other at different temperatures in an isolated system, they attain thermal equilibrium after exchanging heat with one another. The total change in the heat of the system will be always zero.

The amount of heat transferred to or from a substance can be measured using calorimetry. By knowing the heat change, we can predict whether it is endothermic or exothermic.

Here the final temperature of the mixture of the two samples of water is given as:

T = m₁T₁ + m₂T₂ / m₁ + m₂

T = 20.0 × 25  + 30.0 × 80 / 20.0 + 30.0

= 58 units

Thus the final temperature is 58 units.

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The mass number is used to calculate the number of ___ in one atom of an element. In order to calculate the number of neutrons you must subtract the ___ from the ____

Answers

1.) protons + neutrons

2.) protons (or atomic number) from the mass number

Suppose the galvanic cell sketched below is powered by the following reaction: Mg(s)+ SnSO 4(aq) → MgSO4(aq)+ Sn(s) er E1 E2 S1 S2 Write a balanced equation for the half-reaction Write a balanced equation for the half-reaction that happens at the anode of this cell Of what substance is E1 made? Of what substance is E2 made? What are the chemical species in solution S1? What are the chemical species in solution S2?

Answers

The balanced chemical equation is, Mg(s)+ SnSO4 (aq.) → MgSO4(aq.)+ Sn(s) .

The half cell reactions are, Sn2+(aq.)  + 2e-    ----->   Sn(s) and Mg(s)  ---->  Mg2+(aq.)   +  2e-  

A Half cell reaction is expressed either as an oxidation reaction in which electrons are lost or a reduction reaction where electronic are gained. The reactions occur in an electrochemical cell in which the electrons are lost at the anode through oxidation and consumed at the cathode where the reduction occurs. Half-cell reactions are useful in galvanic and voltaic cells in which the electrons flow from the anode to the cathode through an electrolyte to produce an electromotive force (EMF).

Half cell Reaction at cathode : Reduction 

Sn2+(aq.)  + 2e-    ----->   Sn(s)

Half- cell reaction at anode  : Oxidation 

Mg(s)  ---->  Mg2+(aq.)   +  2e-  

E1  is made of   Mg

E2 is made of  Sn 

Chemical species in solution S1 are  Mg2+  and SO42-  .

Chemical species in solution S2 are   Sn2+  and SO42-  

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Common decay process definition in your own words

Answers

Answer:

Your welcome! :)

Explanation:

THE PROCESS IS: Radioactive decay involves the emission of a particle and/or energy as one atom changes into another. In most instances, the atom changes its identity to become a new element.

THE DEFINITION IS: Decay, decompose, rot, putrefy, spoil mean to undergo destructive dissolution. decay implies a slow change from a state of soundness or perfection. a decaying mansion decompose stresses a breaking down by chemical change and when applied to organic matter a corruption.

Conclusion Problems:
1) A metal and a nonmetal form an compound while two non metals form a compound.
2) How many particles are equal to 1 mole? 6.02×10³
3) How many moles are equal to 22.4l of gas? 1 mole
4) How many moles are equal 6.02×10³ molecules? 1 mole
5) Find the molar mass of each of the following and label the STATE of matter:

Conclusion Problems:1) A metal and a nonmetal form an compound while two non metals form a compound.2)

Answers

1. A metal and a nonmetal form an ionic compound while two non-metals form a covalent compound.

2) The number of particles that are equal to 1 mole is 6.02 x 10²³

3) The number of moles that are equal to 22.4 L of gas is 1 mole of gas

4) The number of moles that are equal to 6.02 x 10²³ molecules is 1 mole

5) The molar mass of each of the following and their states of matter are

Fe = 56 g/mol; solid stateCuSO₄.5 H₂O = 249.5 g/mol; liquid (aqueous) stateNaCl = 58.8 g/mol; liquid stateCO₂ = 44 g/mol; gaseous state

What is the molar mass of a compound?

The molar mass of a compound is the mass of 1 mole of a compound.

1 mole of a substance contains 6.02 x 10²³ particles.

For gas, 22.4 L of a gas is equal to 1 mole of the gas and contains  6.02 x 10²³ gas molecules.

The molar mass of the given compounds is calculated from the sum of the atomic masses of the elements in the compound.

The mass of the elements and compounds are as follows;

Moar mass of Fe = 56 g/mol;

Molar mass of CuSO₄.5 H₂O = 63.5 + 32 + (4 * 16) + 5 ( 2 * 1 + 16)

Molar mass of CuSO₄.5 H₂O = 249.5 g/mol

Molar mass of NaCl = 35.5 + 23

Molar mass of NaCl = 58.8 g/mol

Molar mass of CO₂ = 12 + (16 * 2)

Molar mass of CO₂ = 44 g/mol

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A reaction has a rate constant of 0.012s ^ - 1 at 400.0 K and 0.691s ^ - 1 at 450.0 K.

Determine the activation barrier for the reaction.

Answers

Answer:

The rate constant of a reaction is related to the activation energy (Ea) and the temperature (T) by the Arrhenius equation:

k = A * e^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor, R is the gas constant, and T is the absolute temperature.

Taking the natural logarithm of both sides of the equation, we get:

ln(k) = ln(A) - (Ea/RT)

We can use this equation to determine the activation energy for the reaction by comparing the rate constants at two different temperatures. For example, at 400.0 K and 450.0 K, we have:

ln(k1) = ln(A) - (Ea/RT1)

ln(k2) = ln(A) - (Ea/RT2)

where k1 is the rate constant at 400.0 K, k2 is the rate constant at 450.0 K, and RT1 and RT2 are the product of the gas constant and temperature at each temperature.

Taking the difference between the two equations, we get:

ln(k2/k1) = Ea/R * (1/RT1 - 1/RT2)

Solving for the activation energy (Ea), we get:

Ea = -R * ln(k2/k1) / (1/RT1 - 1/RT2)

Substituting the given values, we get:

Ea = -8.314 J/mol*K * ln(0.691/0.012) / (1/400.0 K - 1/450.0 K)

Ea = 93.8 kJ/mol

Therefore, the activation energy for the reaction is 93.8 kJ/mol.

Answer:

Ea ≈ 64.4 kJ/mol

Step by step Explanation:
We can use the Arrhenius equation to relate the rate constant (k) to the activation energy (Ea), the universal gas constant (R), and the temperature (T):

k = Ae^(-Ea/RT)

where A is the pre-exponential factor and R is the gas constant. Taking the natural logarithm of both sides of the equation, we get:

ln(k) = ln(A) - Ea/RT

We can use the given rate constants and temperatures to form two equations:

ln(0.012) = ln(A) - Ea/(R*400.0 K)

ln(0.691) = ln(A) - Ea/(R*450.0 K)

Subtracting the second equation from the first, we can eliminate ln(A) and solve for Ea:

ln(0.012/0.691) = (Ea/R)(1/400.0 K - 1/450.0 K)

Ea = -ln(0.012/0.691) * R/(1/400.0 K - 1/450.0 K)

Using R = 8.314 J/(mol K), we get:

Ea = -ln(0.012/0.691) * 8.314 J/(mol K) / (1/400.0 K - 1/450.0 K)

Ea ≈ 64.4 kJ/mol

Therefore, the activation barrier for the reaction is approximately 64.4 kJ/mol

I need help with this

I need help with this

Answers

As a result, the ideal gas law is applied, and the pressure of the gas in the container is 1.44 atm.

How does Charles Law compute pressure?

The Kelvin temperature and hence the volume are going to be in direct proportion when the pressure on a sample of a dry gas is held constant, according to the definition of the Charles Law Formula. PV = k is the law's equation, and k might be a constant.

This issue can be resolved by applying the ideal gas law:

PV = nR

T = -52 °C + 273.15 = 221.15 K

n = 0.642 mol

V = 8.6 L

T = 221.15 K

\(R = 0.0821 L·atm/mol·K (gas constant for ideal gases)\)

PV = nRT

P = nRT/V

P = (0.642 mol)(0.0821 L·atm/mol·K)(221.15 K)/(8.6 L)

P = 1.44 atm

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Arrange the following in order of increasing bond strength of the carbon oxygen bond: Group of answer choices Carbon monoxide < carbon dioxide < carbonate ion Carbonate ion < carbon monoxide < carbon dioxide Carbon dioxide < carbon monoxide < carbonate ion Carbon dioxide < carbonate ion < carbon monoxide carbonate ion < carbon dioxide < carbon monoxide Carbon monoxide < carbonate ion < carbon dioxide Carbonate ion < carbon monoxide < carbon dioxide

Answers

Answer:

carbonate ion < carbon dioxide < carbon monoxide

Explanation:

Bond strength depends on the bond order of a bond. The higher the bond order, the greater the bond strength since shorter bonds are stronger than longer bonds.

The carbonate ion has a bond order of 1.33, carbon dioxide has a bond order of 2 while carbon monoxide has a bond order of 3.

Since the compound with the highest C-O  bond order has the strongest C-O bond, then carbon monoxide possesses the strongest C-O bond.

Answer: carbonate ion < carbon dioxide < carbon monoxide

Explanation: Carbon dioxide (chemical formula CO2) is a chemical compound made up of molecules that each have one carbon atom covalently double bonded to two oxygen atoms. It is found in the gas state at room temperature, and as the source of available carbon in the carbon cycle, atmospheric CO2 is the primary carbon source for life on Earth. In the air, carbon dioxide is transparent to visible light but absorbs infrared radiation, acting as a greenhouse gas. Carbon dioxide is soluble in water and is found in groundwater, lakes, ice caps, and seawater. When carbon dioxide dissolves in water, it forms carbonate and mainly bicarbonate (HCO−3), which causes ocean acidification as atmospheric CO2 levels increase. Bond strength depends on the bond order of a bond. The higher the bond order, the greater the bond strength since shorter bonds are stronger than longer bonds. The carbonate ion has a bond order of 1.33, carbon dioxide has a bond order of 2 while carbon monoxide has a bond order of 3. Since the compound with the highest C-O  bond order has the strongest C-O bond, then carbon monoxide possesses the strongest C-O bond. It is a trace gas in Earth's atmosphere at 421 parts per million (ppm), or about 0.04% by volume (as of May 2022), having risen from pre-industrial levels of 280 ppm. Burning fossil fuels is the primary cause of these increased CO2 concentrations and also the primary cause of climate change.

A student makes a model of a mineral crystal. The scale is 1:24. The crystal in the model is 5 cm long. How long Is the real-life crystal. A. 120cm B. 0.96cm C. 4.8cm D. 29cm

Answers

The length of the real-life crystal is 120 cm which is 24 times longer than the length of the crystal in the model.

How long Is the real-life mineral crystal?

Given that, a student makes a model of a mineral crystal.

The scale is 1:24. The crystal in the model is 5 cm long.

We are given a scale of 1:24, which means that every unit in the model represents 24 units in real life.

To find the length of the real-life crystal, we need to use the scale factor of 24.

We can set up a proportion to solve for the real-life length of the crystal:

1 unit in the model : 24 units in real life

5 cm in the model : x cm in real life

Using cross-multiplication, we get:

1 × x = 24 × 5

x = 24 × 5

x = 120cm

Therefore, the real-life crystal measures 120cm.

Option A) 120cm is the correct answer.

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Look at the diagram of a fuel cell below.
Which parts of the fuel cell do A and B represent?
A. air
B. anode and cathode
C. electrolyte
D. hydrogen and nitrogen

Look at the diagram of a fuel cell below.Which parts of the fuel cell do A and B represent?A. airB. anode

Answers

B. Anode and cathode
B. anode and cathode

will gave a brain thingy. What are the conditions required for natural selection? Check all that apply.

overproduction of offspring
same traits among all organisms in a population
variation among organisms in a population
favorable adaptations selected by nature
unfavorable adaptations passed on to offspring in larger numbers
favorable adaptations building in population over time

Answers

Answer:

everything.

Explanation:

You need nice weather,good realation ships as well as convection

Answer:

A C D F

Explanation:

Diazomethane has the molecular formula CH2N2. Draw the preferred Lewis structure for diazomethane and assign formal charges to all atoms, if any.

Answers

Answer:

See explanation

Explanation:

We define the formal charge on an atom in a molecule as the charge it carries assuming that electrons in all chemical bonds of the molecule were shared equally between atoms irrespective of the electronegativity of each atom.

The formula for calculating the formal charge on an atom in a molecule is;

Formal Charge = [number of valence electrons on neutral atom] – [(number of lone electron pairs) + (½ number of bonding electrons)] ·

The formal charge on the two nitrogen atoms in diazomethane is obtained as follows;

Middle nitrogen atom = 5 – 8/2 – 0 = +1

Last nitrogen atom = 5 – 4/2 – 4 = –1

The Lewis structure of the molecule is shown in the image attached.

Diazomethane has the molecular formula CH2N2. Draw the preferred Lewis structure for diazomethane and

What is the volume of a sample that has a mass of 20 g and a density of 4 g/mL?

Answers

Answer:

The volume of a sample is 5 ml.

A student planned to make copper sulfate crystals from excess copper oxide and dilute sulfuric acid.
The equation for the reaction is:
CuO(s) + H,SO (aq) -, CuSO (aq) + H20(1)
This is the method used.
1. Add 25 cm° of dilute sulfuric acid to a conical flask.
2. Gently warm the dilute sulfuric acid.
3. Add excess copper oxide to the dilute sulfuric acid.
4. Stir the mixture.
5. Heat to evaporate all the water from the mixture.
Suggest two improvements to the method
Explain why each improvement is needed.

A student plans a method to prepare pure crystals of copper sulfate.
The student's method is:
1. Add one spatula of calcium carbonate to dilute hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a Bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
Explain the improvements the student should make to the method so that pure crystals of copper sulfate are produced.

A student planned to make copper sulfate crystals from excess copper oxide and dilute sulfuric acid.The

Answers

The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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5.
A gas is collected at 22.0 °C and 745.0 mm Hg. When the
temperature is changed to 0 °C, what is the resulting pressure

Answers

Answer:

A gas is collected at 22.0 °C and 745.0 mm Hg. When the temperature is changed to 0 °C, what is the resulting pressure? final pressure would result if the original pressure was 750.0 mm Hg? to 25.0 °C.

Explanation:

What is the name of the longest running musical
and in what year did it premier?

Answers

Answer:

The longest-running show in Broadway history officially opened on January 26, 1988 and is still playing at the Majestic The Andrew Lloyd Webber musical won 7 1988 Tony Awards including Best Musical.

Explanation:

Brainliest plz?

List two ways currents affect life on earth.

Answers

Hi friend! Hope you find this response helpful! :)

Ocean currents regulate the Earth's climate and make up for the difference in solar energy radiation hitting the surface of the planet. As such, water current distributes heat. The ocean absorbs most of the sun's radiation on Earth, in contrast to the atmosphere and to land.

Answer: By moving heat from the equator toward the poles, ocean currents play an important role in controlling the climate.

Explanation:

A student wants to determine the effect of soil type on plant growth. He sets up 3 pots as shown below. Which of the following is NOT a way that the experiment can be improved?

Change the amount of water given to each plant

Make sure the plants receive the same amount of sunlight

Make sure the plants receive water with the same pH

Use the same type of plant in each pot

A student wants to determine the effect of soil type on plant growth. He sets up 3 pots as shown below.
A student wants to determine the effect of soil type on plant growth. He sets up 3 pots as shown below.

Answers

The experiment on determining the effect of soil type on plant growth can be improved by controlling variables such as the amount of sunlight and the pH of water.

Option 1, "Change the amount of water given to each plant," is not a way to improve the experiment because it introduces a new variable that can affect plant growth. If the student wants to test the effect of soil type, then the plants should receive the same amount of water, which is enough to keep the soil moist, but not so much that it causes waterlogging.

Option 2, "Make sure the plants receive the same amount of sunlight," is a way to improve the experiment because sunlight is a factor that can affect plant growth, and therefore, it is important to control the amount of sunlight that each plant receives.

Option 3, "Make sure the plants receive water with the same pH," is also a way to improve the experiment because the pH of water can affect plant growth, and therefore, it is important to keep the pH of water the same for all plants.

Learn more about sunlight here:

https://brainly.com/question/28782526

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The following properties are either physical or chemical. Which one is different from the rest based on those two categories? a) Boiling point,b) flammability,c) Magnetism,d) thermal conductivity

Answers

Answer:

Not D.

Explanation:

I saw the answer somewhere else on brainly and i took the test and it was wrong

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