A 1.00 liter solution contains 0.42 moles nitrous acid and 0.32 moles sodium nitrite .
If 0.16 moles of nitric acid are added to this system, indicate whether the following statements are true or false.
(Assume that the volume does not change upon the addition of nitric acid.)
A. The number of moles of HNO2 will decrease.
B. The number of moles of NO2- will remain the same.
C. The equilibrium concentration of H3O+ will increase.
D. The pH will decrease.
E. The ratio of [HNO2] / [NO2-] will increase

The molar mass of a gas with a density of 1.02 g/L at 2.13 atm and a temperature of 20°C is 47.9 g/mol.The molar mass of an element or compound is the mass of one mole of that substance. A mole is the SI unit for the amount of a substance.

It's defined as the amount of a substance that contains the same number of entities as there are atoms in 12 grams of carbon-12.Molar mass (M) = mass (m) ÷ amount of substance (n)So, M = m/n

Where m is the mass in grams and n is the number of moles. The unit of molar mass is grams per mole (g/mol).

The ideal gas law is used to calculate the molar mass of a gas. The ideal gas law is:P V = n R T,Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Convert the density to grams per liter: 1.02 g/L.

The density is mass/volume, thus 1.02 g/L means that 1 liter of the gas weighs 1.02 g.

This means that 1 mole of gas will occupy 22.4 L (at standard temperature and pressure, STP).Calculate the number of moles of gas using PV = nRT.P = 2.13 atmV = 22.4 L (at STP)R = 0.0821 L·atm/K·molT = 273.15 K + 20 K = 293.15 K

Thus, n = PV/RT = (2.13 atm × 22.4 L)/(0.0821 L·atm/K·mol × 293.15 K) = 0.973 mol

Calculate the molar mass (M) using M = m/n.m = density × volume = 1.02 g/L × 22.4 L = 22.848 gM = m/n = 22.848 g/0.973 mol = 23.5 g/mol Convert to units of grams per mole: 23.5 g/mol

The molar mass of a gas with a density of 1.02 g/L at 2.13 atm and a temperature of 20°C is 47.9 g/mol.

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Answer:

The answer you picked was right.

Explanation:

The maximum mass of water that could be produced by the chemical reaction is 162 g.

The given chemical equation is: 2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)In the chemical reaction of liquid octane with gaseous oxygen, the products are gaseous carbon dioxide and gaseous water.According to the balanced chemical equation, 2 moles of C8H18 react with 25 moles of O2 to form 18 moles of H2O.So, 1 mole of C8H18 react with 25/2 = 12.5 moles of O2 to form 9 moles of H2O.The molar mass of C8H18 is 114 g/mol. So, the number of moles in 17 g of C8H18 is:17 g / 114 g/mol = 0.149 molThe molar mass of O2 is 32 g/mol. So, the number of moles in 112 g of O2 is:112 g / 32 g/mol = 3.5 molFrom the balanced chemical equation, 1 mole of C8H18 react with 12.5 moles of O2 to form 9 moles of H2O.So, the number of moles of O2 required to react with 0.149 mol of C8H18 to form H2O is:(12.5 mol / 1 mol) × (0.149 mol / 2 mol) = 0.935 molThe maximum number of moles of H2O that can be produced from 0.149 mol of C8H18 and 0.935 mol of O2 is 9 mol.So, the mass of water produced from 17 g of C8H18 and 112 g of O2 is:9 mol × 18 g/mol = 162 g

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Answer:

I believe its B

Explanation:

Answer:

B. Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.

The given statement "A parasitic way of life can be best demonstrated by the feeding adaptations of the spider." is False. Because, While some spiders are parasites, not all spiders are parasitic.

Additionally, many spiders are not even true parasites, as they typically do not harm their host organism. Spiders are typically classified as predators, as they feed on other insects and arthropods. While some spiders may occasionally feed on the blood of larger animals, such as birds or mammals, this behavior is not typically considered parasitic, as it does not involve a long-term relationship between the spider and the host organism.

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Answer:

I think it's B, when hair begins to grow.

Explanation:

Good luck! <3

a) To calculate the minimum frequency of electromagnetic radiation required to release electrons from the metal, you can use the following formula:

f = W / h

where f is the minimum frequency of electromagnetic radiation required, W is the work function of the metal in joules, and h is the Planck constant in joules per second.

Plugging in the values for W and h, you get:

f = (5.86 x 10^-19 J) / (6.626 x 10^-34 J/s) = 8.9 x 10^14 Hz

This is the minimum frequency of electromagnetic radiation required to release electrons from the magnesium metal.

b) To calculate the kinetic energy of the ejected electronic light of frequency 2.00 x 10^14 Hz, you can use the following formula:

KE = hf - W

where KE is the kinetic energy of the ejected electron, h is the Planck constant in joules per second, f is the frequency of the electromagnetic radiation in hertz, and W is the work function of the metal in joules.

Plugging in the values for h, f, and W, you get:

KE = (6.626 x 10^-34 J/s) * (2.00 x 10^14 Hz) - (5.86 x 10^-19 J) = 1.32 x 10^-19 J - 5.86 x 10^-19 J = -4.54 x 10^-20 J

This is the kinetic energy of the ejected electron when light of frequency 2.00 x 10^14 Hz is used to irradiate the magnesium metal. Since the kinetic energy is negative, this means that the electron is not released from the metal when irradiated with this frequency. The frequency of the electromagnetic radiation needs to be higher than the minimum frequency required to release the electron in order for the electron to be ejected from the metal.

The valency of Carbon Dioxide is 4.

The best way to measure the pH of a natural solution while out in a forest is to use a portable pH meter or pH test strips specifically designed for field use. These instruments provide accurate and reliable pH measurements and are convenient for outdoor applications.

1. Prepare the necessary equipment: Before heading out to the forest, gather the required tools. You will need a portable pH meter or pH test strips, as well as the necessary reagents or calibration solutions if using a pH meter.

2. Collect the sample: Locate the natural solution you want to measure the pH of, such as a stream, pond, or soil. Use a clean container to collect a representative sample of the solution.

3. Calibrate the pH meter (if applicable): If you are using a portable pH meter, it is essential to calibrate it before taking measurements. Follow the manufacturer's instructions to calibrate the meter using the provided calibration solutions.

4. Conduct the measurement: For pH meters, immerse the electrode into the collected sample. Allow some time for the reading to stabilize, and then record the pH value indicated on the meter's display.

5. Using pH test strips: If you are using pH test strips, dip the strip into the collected sample for the recommended amount of time. Remove the strip and compare the color change with the provided color chart. Determine the corresponding pH value from the chart.

6. Repeat for accuracy: To ensure reliability, repeat the measurement process at least once and compare the results. This step helps confirm the accuracy of your measurements.

7. Record and analyze the data: Note down the pH values obtained and any relevant observations. Analyze the data as needed for your research or monitoring purposes.

By following these steps and using the appropriate equipment, you can effectively measure the pH of a natural solution while in a forest setting.

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Answer:

5.physical change

6.chemical change

7.physical change

8.conservation of mass

9.thermal energy

10.physical change

I honeslty dont know if this is right

explanation:

The final pressure in the container if the temperature remains constant is 68.3 kPa.

Given the following data;

To find the final pressure in the container if the temperature remains constant, we would use Boyle's Law:

Mathematically, Boyle's law is given by the formula;

\(P_1V_1 = P_2V_2\)

Where;

Substituting the values into the formula, we have;

\(205\) × \(4 =\) \(12P_2\)

\(820 = 12P_2\\\\P_2 = \frac{820}{12}\)

Final pressure, P2 = 68.3 kPa

Therefore, the final pressure in the container if the temperature remains constant is 68.3 kPa.

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6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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The chemical formulas for the ions and compounds you listed:

Copper (II) ion: Cu²⁺

Bromide ion: Br⁻

Magnesium ion: Mg²⁺

Phosphide ion: P³⁻

Copper (I) Bromide: CuBr

Sulfur Dichloride: SCl₂

Barium Fluoride: BaF₂

Magnesium Phosphate: Mg₃(PO₄)₂

Lithium Permanganate: LiMnO₄

Strontium Sulfite: SrSO₃

Nitrogen Monoxide: NO

Diselenium Tetraoxide: Se₂O₄

Aluminum Sulfide: Al₂S₃

Tin (IV) Iodide: SnI₄

Beryllium Oxide: BeO

Potassium Hydroxide: KOH

Copper (II) ion: Cu²⁺

Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.

Bromide ion: Br⁻

The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.

Magnesium ion: Mg²⁺

The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.

Phosphide ion: P³⁻

The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.

Copper (I) Bromide: CuBr

Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.

Sulfur Dichloride: SCl₂

Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.

Barium Fluoride: BaF₂

Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.

Magnesium Phosphate: Mg₃(PO₄)₂

Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.

Lithium Permanganate: LiMnO₄

Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.

Strontium Sulfite: SrSO₃

Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Nitrogen Monoxide: NO

Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.

Diselenium Tetraoxide: Se₂O₄

Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.

Aluminum Sulfide: Al₂S₃

Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "

2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.

Tin (IV) Iodide: SnI₄

Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.

Beryllium Oxide: BeO

Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Potassium Hydroxide: KOH

Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.

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Decomposition of 1 gm of NH₃ into its constituents elements gives the greatest amount of N₂ gas.

The balanced chemical reaction for decomposition of NH₃ is given as,

2NH₃(g) ⇌ N₂(g) + 3H₂(g)

Decomposition reactions are defined as the processes in which chemical species break up into simpler parts. Usually, decomposition reactions require energy input. For example, a common method of producing oxygen gas in the laboratory by the decomposition of potassium chlorate (KClO₃) by heat. There are three different types of decomposition reactions which are thermal, electrolytic, and photolytic decomposition reaction.

Hence, the decomposition of 1 gm of NH₃ into its constituents elements gives the greatest amount of N₂ gas.

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Answer:

Formula unit = 32.9746×10²³

Explanation:

Given:

Mass of NaCl = 320 g

Molar mass of  NaCl = 58.44 g/mol

Find:

Formula unit

Computation:

Formula unit = [Mass of NaCl / Molar mass of  NaCl]Avogadro's number

Formula unit = [320 /58.44]6.022×10²³

Formula unit = 32.9746×10²³

Answer:

5.00 moles O₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

3.01 × 10²⁴ molecules O₂

Step 2: Convert

\(3.01 \cdot 10^{24} \ mc \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ mc \ O_2} )\) = 4.99834 moles O₂

Step 3: Check

We are given 3 sig figs. Follow sig fig rules and round.

4.99834 moles O₂ ≈ 5.00 moles O₂

Substance that gives out ions when dissolved in water, which are able to conduct electricity describes an electrolyte.

The fact that an airplane flying due east from an airport will eventually return to its starting point indicates that the Earth is a sphere due to the curvature of the Earth's surface.

How can an airplane flying due east provide evidence for the shape of the Earth?

By continuing to fly east, and with enough fuel, the airplane will eventually reach the same airport it started from. The longest eastward journey would occur from an airport located at one of the Earth's poles. Very short journeys would occur near the equator.

The fact that the airplane returns to its starting point indicates that the Earth is a sphere, as it would not be possible on a flat plane. This phenomenon is due to the curvature of the Earth's surface, which causes the plane's trajectory to follow a circular path along the Earth's surface.

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Answer:

1) 3,400 milliliters

2) 4,500 centimeters

3)0.876 meters

4)0.0117 kilograms

5)78.999 grams

6)0.9 liters

7)0.009 grams

8)0.44 meters

9)112,000 millimeters

10)277,000 grams

Explanation:

Answer:

640 g

Explanation:

Step 1: Given and required data

Step 2: Calculate the moles of oxygen gas

We will use the ideal gas equation

P × V = n × R × T

n = P × V / R × T

n = 25 atm × 20 L / (0.082 atm.L/mol.K) × 300 K = 20 mol

Step 3: Calculate the mass corresponding to 20 moles of oxygen

The molar mass of oxygen is 32.00 g/mol.

20 mol × 32.00 g/mol = 640 g

Taking into account the reaction stoichiometry, 128.4 grams of C are required to produce 10.7 moles of methane.

In first place, the balanced reaction is:

C + 2 H₂ → CH₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 1 mole of CH₄ is produced by 12 grams of C, 10.7 moles of CH₄ are produced by how much mass of C?

mass of C= (10.7 moles of CH₄×12 grams of C)÷1 mole of CH₄

mass of C= 128.4 grams

Finally, 128.4 grams of C are required.

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Answer:

GAUUUUUUUUUUUUUUUUUUUUUUUuR

Explanation:

Answer:

C. Do grits work better at killing fire ants than commercial products?

Explanation:

The statement "when a bottle of soda was opened, bubbles rapidly appeared in the liquid and were given off at the surface" can be categorized as an observation.

Observation refers to the act of noticing or perceiving something through the senses. In this case, the statement describes a specific event that was directly observed: the opening of a bottle of soda and the rapid appearance of bubbles in the liquid, which were then given off at the surface. This observation describes a phenomenon that can be witnessed and measured.

The appearance of bubbles when a bottle of soda is opened is a well-known and predictable occurrence. It can be explained by the principles of gas solubility and pressure.

The soda contains dissolved carbon dioxide (CO2) under high pressure, which is responsible for the carbonation. When the bottle is opened, the sudden release of pressure causes the dissolved CO2 to come out of solution, forming bubbles. These bubbles then rise to the surface and are released into the air.

While this statement captures an observed phenomenon, it does not propose a general principle or provide a comprehensive explanation of the underlying mechanisms. Therefore, it does not qualify as a law or theory, but rather as an observation based on direct sensory perception.

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To calculate the heat gained by the cold liquid, we need to use the formula: q = m * c * ΔT

where q is the heat gained or lost by the substance, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature of the substance.

Let's assume that we have a cold liquid with a mass of 100 grams and an initial temperature of 10°C. We then add 50 grams of a hot solid that has been heated to 80°C. After the solid and liquid are allowed to equilibrate, the final temperature of the mixture is 20°C.

We can first calculate the heat lost by the hot solid using the same formula:

q = m * c * ΔT

q = 50 g * 0.385 J/g°C * (80°C - 20°C)

q = 15400 J

The negative sign indicates that the solid lost heat to the colder liquid.

To calculate the heat gained by the cold liquid, we can use the same formula and the final temperature of the mixture:

q = m * c * ΔT

q = 100 g * 4.184 J/g°C * (20°C - 10°C)

q = 4184 J

Therefore, the heat gained by the cold liquid is 4184 J.

The complete question is :

Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected.

Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.

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We are given the moles and molarity of the solution. To find the liters we must take into account the definition of molarity. Molarity is defined as:

We clear the liters of the solution and replace the known data:

Answer: There are present 3 liters

Answer:

D. Nitrogen, because the ratio of moles is greater than 3:1 for H2:N2

Explanation:

Hello,

In this case, given the reaction:

\(3H_2 + N_2 \rightarrow 2NH_3\)

In order to identify the limiting reactant we must compute the moles of ammonia yielded by both reactants at first:

\(n_{NH_3}^{by\ H_2}=24.0gH_2*\frac{1molH_2}{2molH_2}*\frac{2molNH_3}{3molH_2}=8molNH_3\\ \\n_{NH_3}^{by\ N_2}=8.0gN_2*\frac{1molN_2}{28molN_2}*\frac{2molNH_3}{1molN_2}=0.57molNH_3\)

Thus, since nitrogen yields the smallest amount of ammonia as it is more heavy than hydrogen and it is in a 3:1 mole ratio for H2:N2, it is the limiting reactant, therefore the answer is D. Nitrogen, because the ratio of moles is greater than 3:1 for H2:N2.

Regards.

To determine the concentration of H2SO4, we can use the concept of molarity (M) and the equation:

M1V1 = M2V2

where:

M1 = concentration of NaOH (in this case, 1.90 M)

V1 = volume of NaOH used (in this case, 38.70 cm^3)

M2 = concentration of H2SO4 (what we're trying to find)

V2 = volume of H2SO4 used (in this case, 10.30 cm^3)

Rearranging the equation, we have:

M2 = (M1 * V1) / V2

Substituting the given values:

M2 = (1.90 M * 38.70 cm^3) / 10.30 cm^3

M2 ≈ 7.12 M

Therefore, the concentration of H2SO4 is approximately 7.12 M.

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6.72L is the volume occupied by 0.3 mole of hydrogen chloride. A measurement of three-dimensional space is volume.

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic foot and litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship. A container's capacity is typically thought of as being represented by its volume.

Volume = 0.3×22.4

            =6.72L

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Answer:D

Explanation:

Decomposers decompose food and return it to the environment through the soil