A 0.360-m-long metal bar is pulled to the left by an applied force F. The bar rides on parallel metal rails connected through a 45.0 ohm resistor, as shown in the diagram, so the apparatus makes a complete circuit. The circuit is in a uniform 0.650-T magnetic field that is directed out of the plane of the figure. At the instant when the bar is moving to the left at 5.90 m s, (a) is the induced current in the circuit clockwise or counterclockwise and (b) what is the rate at which the applied force is doing work on the bar? ​

The runner is running the fastest in Graph B because of the graph's steepest slope. Graph B is the solution as a result.

The slope, or steepness, of each line shows the velocity of the item. In general, the steeper the slope, the faster an object moves. A straight line denotes constant speed, whereas changes in slope over time denote varying speeds.

A position-time graph's slope serves as a proxy for velocity. The rate of change of motion increases with slope steepness. A negative slope indicates that the object is moving backward or in the opposite direction, or that the velocity is negative.

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Answer:

1.48 g

Explanation:

A = A₀ (½)^(t / T)

where A is the final amount,

A₀ is the initial amount,

t is time,

and T is the half life.

A = (5.00 g) (½)^(5.00 a / 2.85 a)

A = 1.48 g

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.

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dyed I don't it sorryvplss

The Kinetic energy of the cell phone of mass 0.08 kg is 9 J.

Kinetic energy is the energy of a body in motion.

To calculate the kinetic energy of the cell phone, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the Kinetic energy of the cell phone is 9 J.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

calculate 1.6*7.8*3.1

Explanation:

Answer:

Coulomb's law is:

\(F = \frac{1}{4*pi*e0} *(q1*q2)/r^2\)

First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:

N = (1/{e0})*C^2/m^2

then we have:

{e0} = C^2/(m^2*N)

And we know that N = kg*m/s^2

then the dimensions of e0 are:

{e0} = C^2*s^2/(m^3)

(current square per time square over cubed distance)

And knowing that a Faraday is:

F = C^2*S^2/m^2

The units of e0 are:

{e0} = F/m.

Answer:

un café y a seguir pensando porque no se la respuesta xd

Answer:

Velocity of the stone after 1.5 seconds has passed = 37 m/s

Explanation:

Initial velocity (u) = 22 m/s

Time (t) = 1.5 sec

Acceleration due to gravity (g) = 10 m/s²

By using kinematics equation:

v = u + gt

v = 22 + 10 × 1.5

v = 22 + 15

v = 37 m/s

Final velocity (v) = 37 m/s

The thermosphere has the highest temperature of any layer in Earth’s atmosphere.

The term troposphere is the region that is found  12 to 50 kilometers from Earth’s surface. This region is found to be the region where you can find a lot of gases.

Both the Troposphere and the stratosphere  get colder as altitude increases. However, the ozone in the stratosphere  protects people from ultraviolet (UV) radiation.

The thermosphere has the highest temperature of any layer in Earth’s atmosphere.

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Answer:

Volume =  24 cm^3

Explanation:

We recall that the volume of the box is calculated via the formula:

Volume = length * height * width

and that in a product, the number of significant figures for the result should coincide with the number of significant figures of the factor that has the least of them.

In this case, all measures have the same number of significant figures: two. so we calculate the product, and then limit the answer value to exactly two significant figures:

Volume = 4.1 cm * 2.8 cm * 2.1 cm = 24.108 cm^3, which must be rounded to two significant figures as: 24 cm^3

Answer:

Volume = 24.108cm³

Explanation:

Volume = length × breadth × height

Volume = 4.1 × 2.8 × 2.1

Volume = 24.108

Answer:

24.775N

Explanation:

According to Newton's second law

\sum Fx = ma

F- Ff = ma

F and Ff are the forces acting on the object

m is the mass

a is the acceleration

Given

Ff = 10N

m = 7.5kg

a = 1.97m/s²

Required

F

Substitute the given parameters into the formula

F - 10 = 7.5(1.97)

F-10= 14.775

F= 10+14.775

F = 24.775N

Hence the greatest possible magnitude of the other force is 24.775N

1)a) Pressure is the force exerted per unit area, measured in units such as pascals (Pa) or pounds per square inch (psi).

b) The value of standard atmospheric pressure is approximately 101.3 kilopascals (kPa) or 1 atmosphere (atm).

c) One application of liquid pressure in our daily life is in hydraulic systems, like car brakes, where liquid pressure is used to transmit force and amplify it.

d) The instruments used to measure the pressure of compressed air include pressure gauges or manometers.

e) An instrument called a barometer is used to measure atmospheric pressure.

f) The unit of compressed air is typically measured in pounds per square inch (psi) or pascals (Pa).

g) Standard atmospheric pressure is the pressure exerted by the Earth's atmosphere at sea level. It is approximately equal to 1 atm or 101.3 kPa.

h) The property of liquid that is applicable in water supply systems in cities is its ability to flow and exert pressure, allowing water to be distributed through pipes and reach different levels in buildings.

i) The property of liquid that supports its use in hydraulic machines is its incompressibility, allowing it to transmit force and energy effectively.

2) a)Atmospheric pressure is the force exerted by the weight of the Earth's atmosphere on a surface.

b) The equation P = dgh. This equation can be derived by considering the weight of the fluid column and the force it exerts on a unit area at the base.

c) A mercury barometer consists of a glass tube filled with mercury, inverted into a dish of mercury. The mercury in the tube adjusts its height based on the atmospheric pressure.

d) The importance of atmospheric pressure can be seen in its role in weather patterns, maintaining the balance of gases in the atmosphere, and facilitating breathing for humans and animals.

e) Applications of liquid pressure include hydraulic systems in machinery, such as lifts and cranes, hydraulic brakes in vehicles, and water towers for maintaining water pressure in buildings.

f) Events in daily life directly related to pressure include inflating a balloon, using a bicycle pump to inflate tires, and squeezing toothpaste out of a tube.

1)a) Pressure is defined as the force per unit area. Its unit in the S.I system is newtons per square meter (N/m²) or Pascal (Pa).

b) The value of standard atmospheric pressure at sea level is 101.3 kPa (kilopascals) or 1 atm (atmosphere). c) Liquid pressure has numerous applications in our daily life, but one of the most common ones is the hydraulic braking system used in cars.

d) An instrument used to measure the pressure of compressed air is called a pressure gauge. e) An instrument used to measure atmospheric pressure is called a barometer.

f) The unit of compressed air is generally psi (pounds per square inch).

g) Standard atmospheric pressure is the pressure exerted by the atmosphere at sea level and is equal to 101.3 kPa or 1 atm.

h) The property of liquids that is applicable in water supply systems in cities is their incompressibility. i) The property of liquids that supports their use in hydraulic machines is their incompressibility.

2)a) Atmospheric pressure is defined as the force per unit area exerted by the weight of the atmosphere on the surface. It is proven with the help of the following activity: Take a glass full of water and place a cardboard over it. Hold the cardboard tight and invert the glass. The water will not spill out of the glass, which is because the atmospheric pressure is greater on the cardboard than the pressure inside the glass.

b) The pressure exerted by a fluid can be derived using P = dgh, where P is the pressure, d is the density, g is the acceleration due to gravity, and h is the height of the fluid column.

c) A mercury barometer is made up of a glass tube that is closed at one end and filled with mercury. The tube is inverted and placed in a container of mercury. The pressure of the atmosphere on the open surface of the container forces the mercury in the tube to rise to a height that is proportional to the atmospheric pressure.

d) The importance of atmospheric pressure can be explained by the following points: it enables breathing, regulates the weather, and causes the ocean tides.

e) Some applications of liquid pressure include hydraulic brakes in cars, hydraulic lifts, and hydraulic jacks.

f) Some events that are directly related to pressure include gas escaping from a pressurized container, balloons being inflated, and soda cans being opened.

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Answer:

The mass of the object and the height of the object are the two factors affecting gravitational potential energy.

Explanation:

the dig would -5 from where he first started.

The magnitude of the boat’s resultant velocity with respect to the starting point is 6.0 m/s. Hence, option (3) is correct.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

The velocity of the boat in  still water = 5 meters per second along east.

The velocity of stream =  3.3 meters per second along south.

Hence, the magnitude of the boat’s resultant velocity with respect to the starting point is = √(5² + 3.3²) m/s

=6.0 m/s.

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For this circuit, the voltage is 4.2 V. then power given is 0.9 W and receiving across 55Ω resistance is 0.07 W and that of 30Ω resistance is 0.14 W. Resistor are connected in parallel, its equvalent resistance is R₁R₂/R₁+R₂.

Both resistor are connected in parallel hence their equivalent resistance in parallel combination is given as,

R = 55*30/(55+30)

R = 19.4 Ω

Power given to the circuit is,

P = V²/R = 4.2/19.4 = 0.9 W

Receiving power taken from 55Ω resistor

P = V²/R = 4.2/55 = 0.07 W

Receiving power taken from 30Ω resistor

P = V²/R = 4.2/30 = 0.14 W

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Answer:

Explanation:

I got the same thing. So, i don't know but good luck

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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The initial vertical velocity of the javelin is given by the expression:

During the flight time, the vertical velocity changes due to the gravitational acceleration. When the javelin touches the ground, the magnitude of its velocity is the same but the direction has changed.

Since the vertical movement of the javelin can be modeled as a uniformly accelerated motion, we can find the time that the javelin is in the air using the equation:

Isolate t from the equation and replace v_f=-v_0:

Replace the expression for v_0 and a=-g:

Finally, replace v_0=28.5m/s, g=9.81m/s^2 and θ=43.2º:

Therefore, the answer is: 3.98 seconds.

Yes, that is correct. The angular speed of Earth is 1.99 x 10-7 radians per second. This is equal to 2π radians per year, or 1 revolution per 365.25 days.

The angular speed of the Earth is the rate at which it rotates around its own axis. It is measured in radians per second, and is typically expressed as 2π radians per day, or 7.27 x 10-5 rad/s. The angular speed of the Earth is constant, meaning that it does not change over time. This is important, as it allows us to measure the length of a day and use this to calculate the rate of other processes such as the seasons and the passage of time.

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Answer:

40 N

Explanation:

Both forces to the right are friction forces.  The 40 N force has to be the kinetic friction force because kinetic friction is always less than static friction.  So, the 80 N force has to be the static friction force, which is always greater than the kinetic friction.

Answer: the total energy of the puck, ice surface, and surrounding air decreases to zero

Explanation:

A hockey puck slides across the ice and eventually comes to a stop because of friction between surface of the puck and ice surface.

Friction is a resistance to motion of the object. for example, when a body slides on horizontal surface in positive x direction, it has friction in negative x direction and that measure of friction is a frictional force. frictional force is directly proportional to the Normal(N). i.e. \(F_{fri}\) ∝ N

\(F_{fri}\) = μN where μ is called as coefficient of the friction. It is a dimensionless quantity.

When a body is kept on horizontal surface, its normal will be straight upward which is reaction of mg. i.e. N=mg.

Frictional force is equal to

\(F_{fri}\) = μmg

When hockey puck slides across the ice, friction between surface of puck and surface of ice produces resistance to the motion of the puck, due to resistance puck slow down slowly and eventually come to a stop. Motion and frictional force are opposite to each other. we can calculated the exact value of frictional force when we know the coefficient of friction between puck and ice surface.

hence due to friction, puck come to a stop

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Answer:

Theory

Explanation:

Conservation of energy is explained as a scientific law and not a theory because it does not explain why energy is conserved.

A law is a the statement of a scientific fact. It is a product of repeated experiment and observation through time. Most laws do not explain the reason for the logic behind their premise.

A theory on the other hand provides an explanation for an observed phenomenon. Most theories are no immutable. They are often changed when new finds are reported or made.

Laws are immutable and they stand still.

Answer:

Explanation:

The attachments show the labeling of the network nodes. We found it convenient to do this so we could identify the specific nodes any given branch was attached to. Then the connections for each resistor were identified, and the list sorted to make it easier to see parallel connections.

Resistors 1 and 2 are in parallel

Resistors 5, 6, 8, 9 are in parallel

Resistors 4, 7, 11 are in parallel

No resistor has a parallel connection to resistor 3.

Answer:

8mph

Explanation:

speed=mph.

half an hourx2.

4 milesx2.

8 miles per hour.

That is the speed.

Hope this helps :D

Answer:

Dalton’s atomic theory was a scientific theory on the nature of matter put forward by the English physicist and chemist John Dalton in the year 1808. It stated that all matter was made up of small, indivisible particles known as ‘atoms’.

Explanation:

Atoms can be divided into their subatomic particles.

The statement that is part of Dalton's atomic theory is as follows: Matter is composed of small particles called atoms.

John Dalton is a scientist that first stated the theory of chemical combination in 1803.

The components of these theory are as follows:

Therefore, according to this question, the statement that is part of Dalton's atomic theory is as follows: Matter is composed of small particles called atoms.

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