-90 = -100 + x help need answer

Answer: 3.2%

Step-by-step explanation: i searched it up

There is no stationary point at x = 2. The nature of the curve at x = 2 cannot be determined since there is no stationary point.

To verify that the curve has a stationary point at x = 2, we need to find the derivative of the equation and set it equal to zero.

Given the equation:

y = 2x + 1/(x-1)²

Let's find the derivative dy/dx:

dy/dx = d/dx [2x + 1/(x-1)²]

To find the derivative, we can use the power rule and the chain rule. Let's differentiate each term separately:

For the first term, 2x, the derivative is 2.

For the second term, 1/(x-1)², we can rewrite it as (x-1)^(-2) to apply the power rule. The derivative is then:

d/dx [(x-1)^(-2)] = -2(x-1)^(-3) * d/dx (x-1)

Using the chain rule, d/dx (x-1) = 1, so the derivative becomes:

-2(x-1)^(-3) * 1 = -2/(x-1)^3

Now, let's set dy/dx equal to zero and solve for x:

-2/(x-1)^3 = 0

This equation is satisfied when the numerator is equal to zero:

-2 = 0

However, -2 is not equal to zero, which means there is no x value that makes dy/dx equal to zero.

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Figure C shows only a line segment highlighted in red.

Figure C has four line segments connected to form a square, with the bottom line segment colored red.

The other three line segments in the figure are not colored, and only the bottom line segment is highlighted in red.

This means that only a line segment is shown in red, which is what the question is asking for.

Hence, figure C shows only a line segment highlighted in red.

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From the computation done, the cost of the pound of fruits based on the information will be $5.45.

From the information given, it's stated that the cost of a bag of fruits is proportional to the number of pounds and that cost for 1 ⅕ pound of fruit is $6.54.

Therefore, to calculate the cost of a pound of fruit, this will be:

= 6.54 / 1 ⅕

= 6.54 / 1.2

= $5.45

Therefore, the pound of fruits cost $5.45.

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The probability of getting red balls is 0.68.

Given : Urn 1 contains 5 red balls and 3 black balls. Urn 2 contains 3 red balls and 1 black ball. Urn 3 contains 4 red balls and 2 black balls. If an urn is selected at random and a ball is drawn.

To find : The probability it will be red ?

Total urn = 3

1. If an urn is selected at random then the probability is

P(U) = 1/3

2. In urn 1 - 5 red balls + 3 black balls

Probability of getting red ball from urn :

1 - P(R₁) = 5/8

3. In urn 2 - 3 red balls + 1 black balls

Probability of getting red ball from urn :

2 - P(R₂) = 3/4

4. In urn 3 - 4 red balls + 2 black balls

Probability of getting red ball from urn :

3 - P(R₃) = 4/6

Choosing red ball from urn is

   P(R) = P(R₁) + P(R₂) +P(R₃)

⇒ P(R) = 5/8 + 3/4 + 4/6

⇒ P(R) = \(\frac{15 + 18 + 16}{24}\)

⇒ P(R) = 49/24

The probability of getting red balls is

   P = P(U) + P(R)

⇒ P = 1/3 × 49/24

⇒ P = 49/72

⇒ P = 0.68

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Answer:

Adults=155, children = 196

Step-by-step explanation:

Answer:

Step-by-step explanation:

NA = √[(- 4 - 1 )² + (- 3 - 2)²] = 5√2

AT = √[(8 - 1 )² + (1 - 2)²] = 5√2

TS = √[(3 - 8 )² + (- 4 - 1)²] = 5√2

NS = √[(- 4 - 3 )² + (- 3 + 4)²] = 5√2

NA = AT = TS = NS = 5√2

\(m_{NA}\) = (- 3 - 2) / (- 4 - 1) = 1 ........ (1)

\(m_{TS}\) = (- 4 - 1) / (3 - 8 ) = 1 ......... (2)

From (1) and (2) ⇒ NA║TS

\(m_{AT}\) = ( 1 - 2) / ( 8 - 1) = - 1 / 7 .......... (3)

\(m_{NS}\) = ( - 4 + 3) / ( 3 + 4) = - 1 / 7 .... (4)

From (3) and (4) ⇒ AT║NS

Thus, NATS is rhombus.

Answer: yo if you look up math equation calculator and type that equation in it would solve the problem step by stem.

Step-by-step explanation: i hope this helps :D

Answer:

Number 6 is 3, Iḿ pretty sure if not sorry I tried my best

Step-by-step explanation:

Answer:

B)  4 sq units

Step-by-step explanation:

A = bh/2

A = (4)(2) ÷ 2

A = 4

For the given arena's tickets sales , the round of figure of all the sales to the nearest thousand is given by :

   Events                                         Nearest thousand

As given in the question,

Rules to round of nearest thousand are:

Check the near by hundred digit :

Given is the actual ticket rates of the different events tickets sales ,round off to the nearest thousand is given by:

 Events                                         Nearest thousand

Therefore, For the given arena's tickets sales , the round of figure of all the sales to the nearest thousand is given by :

   Events                                         Nearest thousand

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the regular price is "x", which oddly enough is the 100%.

now, the table is 74% off, so that means the sale price is really 100% - 74% = 26%, so is really 26% of the regular price, and we know that's $202.80.

\(\begin{array}{ccll} amount&\%\\ \cline{1-2} x & 100\\ 202.80& 26 \end{array} \implies \cfrac{x}{202.80}~~=~~\cfrac{100}{26} \implies \cfrac{x}{202.80}=\cfrac{50}{13} \\\\\\ 13x=(202.80)(50)\implies x=\cfrac{(202.80)(50)}{13}\implies x=780\)

Answer:

see explanation

Step-by-step explanation:

using the tangent ratio in the right triangle

tan A = \(\frac{opposite}{adjacent}\) = \(\frac{BC}{AB}\) = \(\frac{5}{11}\) , then

∠ A = \(tan^{-1}\) ( \(\frac{5}{11}\) ) ≈ 24.4° ( to 1 decimal place )

tan C = \(\frac{opposite}{adjacent}\) = \(\frac{AB}{BC}\) = \(\frac{11}{5}\) , then

∠ C = \(tan^{-1}\) ( \(\frac{11}{5}\) ) ≈ 65.6° ( to 1 decimal place )

using Pythagoras' identity in the right triangle

the square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

AC² = AB² + BC² = 11² + 5² = 121 + 25 = 146 ( take square root of both sides )

AC = \(\sqrt{146}\) ≈ 12.08 ( to 2 decimal places )

The answer to this question: B

Answer:

45

Step-by-step explanation:it gives you the answer chiices if you plug each number into x and then do the equation you will get 180

Answer:  45

Step-by-step explanation:

Did the test.

The smallest integer that Pearl wrote down is -12.Let's assume the smallest integer that Pearl wrote down is represented by the variable "x."

According to the given information, the sum of the seven consecutive integers is equal to $\frac{21}{4}$ times the largest integer.

The sum of consecutive integers can be expressed as the sum of an arithmetic series. The sum of an arithmetic series can be calculated using the formula:

Sum = (n/2)(first term + last term)

In this case, the first term is x and the last term is x + 6 (since there are seven consecutive integers). Therefore, the sum of the integers can be written as:

Sum = (7/2)(x + (x + 6))

Simplifying the equation:

(7/2)(2x + 6) = (21/4)(x + 6)

Multiplying both sides by 4 to eliminate the fractions:

14x + 42 = 21x + 126

Subtracting 14x from both sides:

42 = 7x + 126

Subtracting 126 from both sides:

-84 = 7x

Dividing both sides by 7:

-12 = x.

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Answer:

40 square units

Step-by-step explanation:

This is a rhombus, so you multiply the two diagonals and divide by 2.

8x10÷2=40

The answer choice which is not a step in finding the area of the unknown figure is; Plug all dimensions into the formula: SA=Ixwxh. option B

It follows from the task content that all other steps except Plugging all dimensions into the formula; SA = l×w×h are correct steps.

This is due to the fact that, the formula does not work for all shapes and hence, it can't be generalized for all situations.

The step which is not involved in finding the area of an unknown figure is; Plug all dimensions into the formula: SA=Ixwxh.

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Answer:

B) Plug all dimensions into the formula: SA=Ixwxh.

Step-by-step explanation:

The inequality represented by the graph is given as follows:

y > 3x - 4.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which:

The graph crosses the y-axis at y = -4, hence the intercept b is given as follows:

b = -4.

When x increases by 1, y increases by 3, hence the slope m is given as follows:

m = 3.

Hence the equation of the line is:

y = 3x - 4.

The inequality is composed by the values to the right (greater) of the line, and has an open interval due to the dashed line, hence:

y > 3x - 4.

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Answer:

The answer is -3 - 2/3

Step-by-step explanation:

Just subtract

let's bear in mind that on the III Quadrant, sine and cosine are both negative, whilst on the IV Quadrant, sine is negative and cosine is positive, that said

\(\cos(\alpha )=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\hspace{5em}\textit{let's find the \underline{opposite side}} \\\\\\ \begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{5}\\ a=\stackrel{adjacent}{3}\\ o=opposite \end{cases} \\\\\\ o=\pm \sqrt{ 5^2 - 3^2} \implies o=\pm \sqrt{ 16 }\implies o=\pm 4\implies \stackrel{IV~Quadrant }{o=-4} \\\\[-0.35em] ~\dotfill\)

\(\tan(\beta )=\cfrac{\stackrel{opposite}{4}}{\underset{adjacent}{3}}\implies \tan(\beta )=\cfrac{\stackrel{opposite}{-4}}{\underset{adjacent}{-3}} \\\\[-0.35em] ~\dotfill\\\\ \tan(\alpha + \beta) = \cfrac{\tan(\alpha)+ \tan(\beta)}{1- \tan(\alpha)\tan(\beta)} \\\\\\ \tan(\alpha + \beta)\implies \cfrac{ ~~\frac{-4}{3}~~ + ~~\frac{-4}{-3} ~~ }{1-\left( \frac{-4}{3} \right)\left( \frac{-4}{-3} \right)}\implies \cfrac{0}{1-\left( \frac{-4}{3} \right)\left( \frac{-4}{-3} \right)}\implies \text{\LARGE 0}\)

The rectangle \(R\) is the set

\(R = \{(x,y) \mid 0 \le x \le 2 \text{ and } -1 \le y \le 1\}\)

The average value of \(f(x,y)\) over \(R\) is the ratio of the integral of \(f\) over \(R\) to the area of \(R\).

\(f_{\rm ave} = \dfrac{\displaystyle \iint_R f(x,y) \, dA}{\displaystyle \iint_R dA}\)

The rectangle is 2-by-2, so its area is

\(\displaystyle \iint_R dA = 2\times2 = 4\)

Integrate \(f\).

\(\displaystyle \iint_R xy^2 \, dA = \int_{-1}^1 \int_0^2 xy^2 \, dx \, dy \\\\ ~~~~~~~~ = 2 \int_{-1}^1 y^2 \, dy \\\\ ~~~~~~~~ = 4 \int_0^1 y^2 \, dy = \frac43\)

Then the average value of \(f\) is

\(f_{\rm ave} = \dfrac{\frac43}4 = \boxed{\dfrac13}\)

To find the area of the combined rectangles, we need the dimensions (length and width) of each rectangle. However, the provided text and numbers do not seem to correspond to a clear description of the rectangles or their dimensions. Could you please provide more specific information or clarify the question?

Answer:

You can use the division sign.

Step-by-step explanation:

48÷{2×[(6×5)-(9×3)]} =

48÷{2×[(30)-(27)]} =

48÷{2×[3]} =

48÷{6} =

8

Answer:

Step-by-step explanation:10,000 cats

Answer:

Option 4

Step-by-step explanation:

The domain of this function is the possible values of n that are suitable for this function. Since n represents a number of vehicles, the domain of n should be a whole number (since you cannot have a negative number of vehicles or half of a vehicle).

hope this helps :)

The algebraic rule for the transformation is B' = (Bx + 15, By - 12)

Given data ,

To determine the algebraic rule for the transformation from point B to point B', we need to find the equations that relate the coordinates of the preimage point B to the image point B'.

Let's denote the translation amounts in the x-direction and y-direction as (dx, dy). The coordinates of B' can be obtained by adding these translation amounts to the coordinates of B:

B' = (Bx + dx, By + dy)

Given that B is located at (5, -4) and B' is located at (20, -16), we can calculate the translation amounts:

dx = 20 - 5 = 15

dy = -16 - (-4) = -12

Hence , the algebraic rule for the transformation is B' = (Bx + 15, By - 12)

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f(x) = 4.1/(42.4x-10(x-2)), x-intercept = -4.878, y-intercept = (0,-2.05), asymptotes: vertical at x=2, horizontal at y=0, and slant at y=4.1/8x.

Given: f(x) = 4.1/(42.4x-10(x-2))

To find the x-intercept, we set f(x) to zero and solve for x:

0 = 4.1/(42.4x-10(x-2))

0 = 4.1/(32.4x+20)

0 = 4.1/4.08(x+4.878)

So, the x-intercept is x = -4.878.

To find the y-intercept, we set x to zero and solve for f(x):

f(0) = 4.1/(42.4(0)-10(0-2))

f(0) = -2.05

So, the y-intercept is (0,-2.05).

To write f(x) in the form f(x) = -1/(ax + b) + q, we can simplify the expression as follows:

f(x) = 4.1/(42.4x-10(x-2))

f(x) = 4.1/(32.4x+20)

f(x) = 4.1/4.08(8x+5)

So, a = 8, b = 5, and q = 4.1/4.08.

To draw the graph of f, we plot the x- and y-intercepts and the vertical asymptote x = 2.

We can find the horizontal asymptote by noting that as x becomes very large or very small, the term 10(x-2) dominates the expression, so f(x) approaches 4.1/-10x. Thus, the horizontal asymptote is y = 0.

To find the equations of the slant asymptotes, we divide the numerator by the denominator using long division:

4.1

8x + 5 | 4.1

- 4.1

0

So, the slant asymptote is y = 4.1/8x.

Therefore, the intercepts of f are x = -4.878 and (0,-2.05), and the equation of f(x) in the form f(x) = -1/(ax + b) + q is f(x) = -1/(8x + 5) + 1.0039.

The graph of f has intercepts with the x-axis at x = -4.878 and the y-axis at (0,-2.05), a vertical asymptote at x = 2, a horizontal asymptote at y = 0, and a slant asymptote at y = 4.1/8x.

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