(9-4n)(-4)
Need help simplify this plz

The corresponding probabilities are: A. P(R) = 0.72 B. P(R') = 0.28 C. P(A ∩ R) = P(R) * P(A | R) = 0.72 * 0.51 = 0.367 D. P(A | R) = 0.51 E. P(A ∩ R') = P(R') * P(A | R') = 0.28 * 0.10 = 0.028 F. P(A' ∩ R) = P(R) * P(A' | R) = 0.72 * 0.49 = 0.352 G. P(A' ∩ R') = P(R') * P(A' | R') = 0.28 * 0.90 = 0.252

(a) The tree diagram with the corresponding probabilities is:

A (0.51) A' (0.49) A (0.10) A' (0.90)

(b) The proportion of students who earn an A and don't attend class regularly is:

P(A ∩ R') = 0.028

(c) The chance that a randomly chosen student will earn an A in the class is:

P(A) = P(A ∩ R) + P(A ∩ R')

= 0.367 + 0.028

= 0.395

(d) Given that a student earned an A, the chance they attend class regularly is:

P(R | A) = P(A ∩ R) / P(A)

= 0.367 / 0.395

≈ 0.9291 (rounded to four decimal places)

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Complete question:

A professor has noticed that students hat attend class regularly, mss no more than two classes per term, generally get better grades. For he class, the overall percent o students who attend regularly s 72% or those who come to class on a regular basis, 51% receive A's. Of those who don't attend regularly, only 10% get A's. (b)Among all students what proportion earn an A and don't attend class regularly?

Answer:no solution??

Answer: d

Step-by-step explanation:

(i) The 90% confidence interval for the population parameter is (27.37, 45.79).

(ii) The interval (boundary values) of the 90% confidence interval is shown on the distribution graph.

After calculating the lower and upper limits using the formula above, the interval is found to be (27.37, 45.79) and  we can be 90% confident that the population parameter lies within this range.

Given the following information:

Random sample of 18 students

Sample standard deviation = 10.49

90% confidence interval

To find:

(i) Form a 90% confidence interval for the population parameter.

(ii) Show the interval (boundary values) on the distribution graph.

The population variance can be estimated using the sample variance. Since the sample size is small (n < 30) and the population variance is unknown, we will use the t-distribution instead of the standard normal distribution (z-distribution). The t-distribution has fatter tails and is flatter than the normal distribution.

The lower limit of the 90% confidence interval is calculated as follows:

Lower Limit = sample mean - (t-value * standard deviation / sqrt(sample size))

The upper limit of the 90% confidence interval is calculated as follows:

Upper Limit = sample mean + (t-value * standard deviation / sqrt(sample size))

The t-value is determined based on the desired confidence level and the degrees of freedom (n - 1). For a 90% confidence level with 17 degrees of freedom (18 - 1), the t-value can be obtained from a t-table or using statistical software.

After calculating the lower and upper limits using the formula above, the interval is found to be (27.37, 45.79).

(ii) Showing the interval (boundary values) on the distribution graph:

The distribution graph of the 90% confidence interval of the variance of the students' final grade is plotted. The range between 27.37 and 45.79 represents the interval. The area under the curve between these boundary values corresponds to the 90% confidence level. Therefore, we can be 90% confident that the population parameter lies within this range.

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Answer:

Step-by-step explanation:

So you've got 38 to which you add 50% of 38 since we're talking about increasing.

You can either use percentage directly in your calculation, or you can see it as 50/100, meaning 1/2.

\(38+38*50/100 = 38 + 38*1/2 = 38 + 19 = 57\\\)

And here you go !

Answer:

Step-by-step explanation:

First we need to know how many customers in total received a coupon the day that there were 150 customers.

If for each 25 customers, 3 received a coupon. 0.12 of customers received a coupon (\(\frac{3}{25}\) = 0.12)

You can multiply this value by 150 to get 0.12 x 150 = 18 people

Another way you can think about this is 150/25 = 6 and 6 x 3 = 18 people

Now that we know how many people received coupons, we need to find the monetary value of these coupons. To do this, we multiply 18 by $10. Therefore, the total value of the coupons that were given out was $180.

Answer: $180

Answer:

18 people

Step-by-step explanation:

3/25 = x/150

3 times 150 / 25

= 450/25

= 18 people

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The question is an illustration of equivalent equations

The approximated value of a is 0.94

The given parameters are:

\(\mathbf{N(t) = 100(2.72)^{-0.060t}}\)

\(\mathbf{N(t) = 100a^t}\)

Equate both expressions to solve for a

\(\mathbf{ 100a^t = 100(2.72)^{-0.060t}}\)

Divide both sides by 100

\(\mathbf{a^t = (2.72)^{-0.060t}}\)

By comparison

\(\mathbf{a = (2.72)^{-0.060}}\)

Using a calculator, we have:

\(\mathbf{a = 0.94172882931}\)

Approximate

\(\mathbf{a = 0.94}\)

Hence, the approximated value of a is 0.94

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Answer:

x < -3

Step-by-step explanation:

9(2x + 1) < 9x – 18

18x +9 < 9x – 18

-9x            -9x

9x +9 < – 18

-9          -9

9x < – 27

÷9   ÷9

x < -3

HOPE THIS HELPS:)

Answer:

B

Step-by-step explanation:

16 times means multiply the expression by 16

Answer:

SI=PRT/100

=10000*5*42/12*100

=1750

SI=1750

TOTAL AMOUNT=PRINCIPLE+SI

=10000+1750

=101750

Answer:

Common Ratio = 2.5

Step-by-step explanation:

Given

Points: (1, 1), (2, 2.5), (3, 6.25)

Required

Determine the common ratio

The points can be rewritten as:

x --- f(x)

1 ---- 1

2 --- 2.5

3 ---- 6.25

The data under the x column are the domain of the function and in this case,  they are not needed;

To calculate common ration, Lena should use data in function f(x) column

Common ratio is calculated by dividing a term by the previous term;

Hence;

Common Ratio = 2.5/1 or 6.25/2.5

Common Ratio = 2.5 or 2.5

Notice that, the results are the same;

Hence, the usable common ratio is 2.5

Answer:

c

Step-by-step explanation:

edge2020

Answer:

1 third

Step-by-step explanation:

Have a blessed day!

Answer:

32 and 40

Step-by-step explanation:

Let's call the smaller number x. If the smaller number is x, the equation for this problem is 2x + 8 = 72

Equation:

2x + 8 = 72

2x = 64

x = 32

So now we know the smaller number is 32, so now add 8 and we get 40.

Therefore the 2 numbers are 32 and 40

Step-by-step explanation:

x = number of multiple choice questions

y = number of short response questions

x + y = 15

5x + 10y = 100

=>

x + 2y = 20

let's subtract the first from the second equation :

x + 2y = 20

- x + y = 15

--------------------

0 y = 5

x + y = 15

x + 5 = 15

x = 10

to graph you need to consider both equations as linear functions. and you need to transform them into e.g. a slope intercept form : y = ax + b

a is the slope, b is the y- intercept.

x + y = 15

transforms to

y = -x + 15

this line goes e.g. through the points (0, 15) and (1, 14).

and

x + 2y = 20

transforms to

2y = -x + 20

y = -x/2 + 10

this line goes e.g through (0, 10) and (2, 9).

the crossing point of both lines is the solution and should therefore be the point (10, 5) as calculated above.

The value of x is either 2 or -7/3.

Given expression:-

(x/x+1)+((x-1)/4)=(11/12)

We have to find the value of x.

The LCM of (x + 1) and 4 is 4(x - 1).

We can write,

[4x + (x + 1)(x - 1)]/4(x + 1) = 11/12

\(\frac{4x+x^2-1}{4(x+1)}=\frac{11}{12}\)

We can multiply 4 to the given equation, and get,

\(\frac{4x+x^2-1}{(x+1)}=\frac{11}{3}\)

By cross multiplying, we can write,

\(12(4x+x^2-1)=11(4(x+1))\)

12x + \(3x^2\) -3 = 11x + 11

\(3x^2\) + 12x - 11x -3-11 = 0

\(3x^2\) + x-14 = 0

Using the middle-term split theorem, we can write,

\(3x^2\) + 7x - 6x -14 = 0

x(3x + 7) - 2(3x + 7) = 0

(3x + 7)(x - 2) = 0

x = -7/3, 2.

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Since the length and width of the rectangle is doubled, then the perimeter of the rectangle is doubled and the area of the rectangle is fourfold.

Perimeter and area of rectangle:

The general form to calculate  Perimeter of a Rectangle

P = 2(a + b);

And Area of Rectangle

A= a × b

where

a refers the length

b refers the width

Given,

Suppose the length and width of the rectangle are doubled.

Here we need to find the effect on the perimeter and the area of the rectangle.

While we looking into the given rectangle,

We have identified that the value of

length = 17 feet,

width = 4 feet

So, the perimeter of rectangle is,

=> P = 2 (17 + 4) = 42

Similarly, the area of the rectangle is

=> A = 17 x 4 = 68

Here we have given that the length and width is doubled, then the value of length is 34 and the width is 8.

Now, the perimeter of the rectangle is,

=> P = 2 (34 + 8) = 84

And the area of the rectangle is,

=> A = 34 x 8 = 272

While we comparing the resulting values we have identified that the perimeter is doubled and the area is fourfold.

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Answer: Start off and multiply 12x30=360

Step-by-step explanation: He will recieve 360$

such pair of equation that have only one pair of solutions which satisfy both equation is linear equation

the volume of the rectangular prism is 1,080 cubic inches.

Why is it?

The volume V of a rectangular prism is given by the formula:

V = length x width x height

Substituting the given values, we get:

V = 10 inches x 18 inches x 6 inches

Simplifying, we get:

V = 1,080 cubic inches

Therefore, the volume of the rectangular prism is 1,080 cubic inches.

A rectangular prism is a three-dimensional solid shape that has six rectangular faces, where each pair of opposite faces are congruent and parallel to each other. It is also known as a rectangular parallelepiped.

A rectangular prism is characterized by its length, width, and height or depth. The length is the measurement of the longest side of the prism, the width is the measurement of the shorter side, and the height or depth is the measurement of the perpendicular distance between the two faces that are parallel to each other.

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Answer:

(-6,24)

Step-by-step explanation:

the truth value of the proposition [A ⊃ ~(B · Y)] ≡ ~[B ⊃ (X · ~A)] when A and B are true and X and Y are false is also true.

we can break down the proposition into two parts:

1. A ⊃ ~(B · Y)
2. ~[B ⊃ (X · ~A)]

Since A and B are both true, we can simplify the first part to A ⊃ ~Y. Since Y is false, we know that ~Y is true. Therefore, the first part of the proposition is true.

For the second part, we can simplify it to ~(~B ∨ (X · ~A)). Since A and B are true, we can simplify this further to ~(~B ∨ X). Since X is false and B is true, we know that ~B ∨ X is true. Therefore, ~(~B ∨ X) is false.

Taking the equivalence of the two parts, we get true ≡ false, which is false. However, we are given that A and B are true and X and Y are false, so the main answer is that the truth value of the proposition is true.

the proposition [A ⊃ ~(B · Y)] ≡ ~[B ⊃ (X · ~A)] is true when A and B are true and X and Y are false.

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Option D. The median cost of course materials for nursing majors is over $300 more than the median cost of course materials for non-nursing majors.

The given boxplots show the circulation of the expense obviously materials for nursing majors and non-nursing majors. From the plots, we can reason that the scope of the circulation of the expense obviously materials for nursing majors is like that of non-nursing majors, as the most extreme and least qualities are around at a similar level. We can likewise infer that the most extreme expense for non-nursing majors is more prominent than the middle expense for nursing majors.

Also, the inconstancy of the expense obviously materials for the center half of nursing majors is more noteworthy than the fluctuation of the center half for non-nursing majors, as the cases for nursing majors are more extensive. In any case, we can't reason that the middle expense obviously materials for nursing majors is more than $300 more than the middle expense obviously materials for non-nursing majors, as the medians are not straightforwardly named and their division isn't plainly shown. At last, we can see that the study included 17 nursing majors and 17 non-nursing majors.

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The complete question is:

A college professor conducted a survey in order to assess how much money nursing majors spend on course material compared to all other majors. To do so, she selected a random sample of 34 students. Each student was classified as a nursing major or as a non-nursing major. They were then asked how much they spent on books and other materials required for their courses this semester. Shown above are parallel boxplots summarizing the responses. Based upon the boxplots, which of the following statements cannot be concluded?

A. The range of the distribution of the cost of course materials for nursing majors is about the same as that of non-nursing majors.

B. The maximum cost for non-nursing majors is greater than the median cost for nursing majors.

C. The variability of the cost of course materials for the middle 50% of nursing majors is greater than the variability of the middle 50% for non-nursing majors.

D. The median cost of course materials for nursing majors is over $300 more than the median cost of course materials for non-nursing majors.

E. The boxplots reveal that 17 students are nursing majors and 17 students are non-nursing majors

Yes, the connection between the semimajor axis and an orbit's period varies as the eccentricity of the orbit changes.

In geometry, the eccentric definition is the distance from any point on a conic section to the focus divided by the perpendicular distance from that point to the nearest directrix. In general, eccentricity aids in determining the curvature of a form. The eccentricity grows as the curvature lowers.

Here,

In general, an orbit's period is proportional to the square root of the semimajor axis multiplied by three. This connection, however, is only valid for circular orbits with zero eccentricity. When the eccentricity is larger than zero, the period of the orbit is still determined by the magnitude of the semimajor axis, but it is also determined by the form of the orbit as given by the eccentricity. The relationship between the semimajor axis and the period in this situation is not as straightforward as a proportionate relationship.

As a result, modifying an orbit's eccentricity modifies the connection between the semimajor axis and the period.

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Answer:

j=7

Step-by-step explanation:

Answer:

A trapezoid has two pairs of parallel sides

Answer:

A. 6(n + 8) = 19

Step-by-step explanation:

Look for key words.

6 times the sum of a number and 8 is nineteen.

From these key words it is clear that the solution is 19, you are adding an unknown number (a variable, which we will represent with x) to 8, and multiplying our (x+8) by 6.

Write out the equation.

6(n + 8) = 19

Don't know how clear this is, but I hope it helped you figure this out!

Trevor and Kim will be situated 21 kilometers apart from each other at 1:30 PM. They will be separated by a distance of 21 km when the clock strikes 1:30 in the afternoon.

To determine at what time Trevor and Kim will be 21 km apart, we can set up a distance-time equation based on their relative speeds and distances.

Let's assume that t represents the time elapsed in hours since noon. At time t, Trevor would have traveled a distance of 8t km, while Kim would have traveled a distance of 6t km in the opposite direction.

Since they are running in opposite directions, the total distance between them is the sum of the distances they have traveled:

Total distance = 8t + 6t

We want to find the time when this total distance equals 21 km:

8t + 6t = 21

Combining like terms, we have:

14t = 21

To solve for t, we divide both sides of the equation by 14:

t = 21 / 14

Simplifying, we find:

t = 3 / 2

So, they will be 21 km apart after 3/2 hours, which is equivalent to 1 hour and 30 minutes.

Therefore, Trevor and Kim will be 21 km apart at 1:30 PM.

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