87 mL of 0.040 M NaF is mixed with 29 mL of 0.10M Sr(NO3)2. Calculate the concentration of Sr2+ in the final solution. Assume volumes can be added. (Ksp for SrF2 = 2.0 ×10-10)
Answer Options:
0.050 M
0.030 M
0.00014 M
0.010 M
0.025 M

Reactions tend to run to completion if a product precipitated as a solid. Option B is correct.

When one of the products is taken out of the reaction mixture, reactions frequently proceed to completion. If a product is precipitated as a solid, it is no longer in the reaction mixture and is effectively removed from the system. This drives the reaction to completion in order to produce more of the solid product.

On the other hand, the physical state of a product (high melting point, liquid, or ionic) does not necessarily affect the extent to which a reaction runs to completion. While a high melting point may make it difficult to remove the product from the reaction mixture, it does not necessarily prevent the reaction from reaching completion.

Hence, B.is the correct option.

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The right response is d. Both enzymes will have the same ΔG for catalysis.

The reaction rate and equilibrium constant have an impact on the Gibbs free energy (ΔG). No matter the source of the enzyme, such as E. coli or a thermophilic microbe, the ΔG for a reaction is the same. As a result, both enzymes will have the same ΔG for sucrose hydrolysis.

The ΔG may be written mathematically as:

ΔG = -RT ln (K)

T is the temperature, K is the equilibrium constant, and R is the gas constant..

As both enzymes have the same reaction rate (K) and temperature (T), the reaction's ΔG  value will likewise be the same.

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fluorine, chlorine, bromine, and iodine,

Answer:

(the numbers are suppose small on the bottom right of the letter)

1. H2SO4 + K

2. H2SO4 + Mg

3. HCL + Na

Answer:

I believe you can evaporate the water.

Explanation:

If you evaporate the water, it leaves the baking soda particles.

Answer:

cyfctr rytfuhv

Explanation:

The hydrolysis of phosphatidylinositol 4,5‑bisphosphate (pip2) by phospholipase C generates inositol 1,4,5-trisphosphate ( \(IP_{3}\) ) and diacylglycerol (DAG) secondary messengers.

The small molecules and ions relay signals received by cell-surface receptors to effector protein is referred as second messenger.Examples of secondary messengers are cyclic AMP,cyclic GMP inositol 1,4,5-trisphosphate ( \(IP_{3}\) ) ,diacylglycerol (DAG) ,and calcium. \(IP_{3}\) induces a transient increase in intracellular free \(Ca^{+2}\) ,whereas DAG directly activates protein kinase C.

There are two distinct kinds of signaling pathways that use phosphatidylinositol. Phospholipase C breaks down phosphatidylinositol-4,5-bisphosphate to create IP3, which serves as a crucial part of the Ca-signaling mechanism described earlier.

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Answer:

New growth of trees is an exception

Explanation:

when volcanoes erupt, they release hot magma that is destructive to the environment causing personal damage, lack of breathable air and death.

heat produce cannot in any way help in growth of trees

Answer:

Kr- dispersion forces

CBr4- dispersion forces

CH3OH - dispersion forces, dipole interaction, hydrogen bonding

NaF- ionic

Kr-<CBr4<CH3OH<NaF

Explanation:

The magnitude of intermolecular forces influences the boiling points of substances. The stronger the intermolecular forces the higher the boiling point.

The strongest intermolecular forces here is the Ionic bond hence it accounts for the highest boiling point followed by CH3OH having hydrogen bonding.

Though Krypton and CBr4 both have dipole interaction, the higher relative molecular mass of CBr4 makes it to have a higher boiling point than Kr

Answer:

The planets follow these orbit  paths as they travel around the Sun. The Sun’s gravity  

makes the planets move in this way. It pulls on the planets, keeping them in motion in their orbit.

Modeling is a way to see ideas or have a  particular idea or

concept.

 Models do have some lines .

 Often a model is made with certain things.

 A model of the solar system may contain all of the planets and the Sun, but it may not include the planets’

individual moons or every planit  and rock in the solar system.

Explanation: if you think about it and and look at pics it is easy

hope this helps

Pd is a transition metal ion hence it is a type 2 metal cation.

A transition metal ion is an ion that is derived from a transition metal element. Transition metals are a group of elements located in the center of the periodic table and characterized by their ability to form multiple stable oxidation states. This property is due to the presence of unpaired electrons in their d-orbitals, which are involved in chemical reactions.

Transition metal ions play important roles in many chemical and biological processes, including catalytic reactions, the formation of coordination complexes, and the regulation of enzymes. They are also commonly used in applications such as pigments, catalysts, and magnetic materials.

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Answer:

lets say your doing a frog

it jumps it speeds up and then slows down

Explanation:

Answer:

Atom

Explanation:

atom: The basic unit of matter; the smallest unit of an element, having all the characteristics of that element; consists of negatively-charged electrons and a positively-charged center called a nucleus.

To produce 235 mL of a 1.77 M H₂SO₄ solution from an 18.0 M H₂SO₄ solution, you would need 27.54 mL of the concentrated solution.

To find this, we can use the dilution formula: M₁V₁ = M₂V₂. Here, M₁ is the initial concentration (18.0 M), V₁ is the volume required, M₂ is the final concentration (1.77 M), and V₂ is the final volume (235 mL).

1. Rearrange the formula to solve for V₁: V₁ = (M₂V₂) / M₁
2. Plug in the given values: V₁ = (1.77 M × 235 mL) / 18.0 M
3. Calculate the result: V₁ = 27.54 mL

Therefore, you would need 27.54 mL of the 18.0 M H₂SO₄ solution to produce 235 mL of a 1.77 M H₂SO₄ solution.

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Answer:

second (S) is the SI unit of time.

Answer:

second

Explanation:

the gap between any two intervals is called time

time can be measured in hour,minute,second

but second is the SI unit of time

Based on the given isotopic composition, the relative contribution of C3 plants is higher compared to C4 plants in the soil organic matter of Kenya.

To determine the relative contribution of C3 and C4 plants to the soil organic matter in Kenya based on their stable carbon isotopic composition, we can use the concept of isotopic discrimination.

C3 and C4 plants have different photosynthetic pathways, and they exhibit distinct carbon isotope signatures. C3 plants typically have a more negative δ13C value (around -30 permil to -22 permil), while C4 plants have a less negative δ13C value (around -16 permil to -9 permil).

In this case, the soil organic matter in Kenya has a δ13C value of -18 permil, while the air δ13C value is -7 permil. The difference between these values (-18 permil - (-7 permil)) gives us the isotopic discrimination between the atmosphere and the soil organic matter.

δ13C discrimination = δ13C organic matter - δ13C atmosphere

δ13C discrimination = -18 permil - (-7 permil)

δ13C discrimination = -11 permil

Since the δ13C discrimination is negative, it suggests that C3 plants have a dominant contribution to the soil organic matter. C4 plants, with their less negative δ13C values, are less likely to contribute significantly to the organic matter in this case.

Therefore, based on the given isotopic composition, the relative contribution of C3 plants is higher compared to C4 plants in the soil organic matter of Kenya.

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The characteristics which are necessary for a location to be suitable for chemical storage are:

Chemical storage as the name implies refers to the storage of controlled substances or hazardous materials as the case may be in chemical stores, chemical storage cabinets, or similar devices.

On this note, the characteristics which are necessary for a location to be suitable for chemical storage are as listed above.

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The characteristics required for suitable chemical storage include dark, dry, and cool.

In conclusion, the characteristics required for suitable chemical storage include dark, dry, and cool.

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The required gas volumes obtained at different pressures is a. \(279.825cm^3\), b. \(0.804m^3\), c. \(37.43cm^3\), d. \(551.5cm^3\) and e. \(200cm^3\).

The ideal gas equation is a mathematical equation used to relate the four main properties of an ideal gas: pressure (P), volume (V), temperature (T), and moles of gas (n). It is expressed as PV = nRT, where R is the ideal gas constant. This equation is used to calculate the pressure, volume, and temperature of an ideal gas given any two of these properties.

a. Given \(338cm^3\) at 86.1kPa to 104.0kPa

We can calculate this using the ideal gas law:

P1V1 = P2V2

86.1 * 338 = 104.0 * V2

V2 =\(279.825cm^3\)

b. Given \(0.873m^3\) at 94.3kPa to 102.3kPa

P1V1 = P2V2

(94.3) * (0.873) = (102.3) * V2

V2 = \(0.804m^3\)

c. Given \(31.5cm^3\) at 97.8kPa to 82.3kPa

P1V1 = P2V2

(97.8) * 31.5 = 82.3 * V2

V2 = \(37.43cm^3\)

d. \(524cm^3\) at 110.0kPa to 104.5kPa

P1V1 = P2V2

110.0 * 524 = 104.5 * V2

V2 = \(551.5cm^3\)

e. \(171cm^3\) at 122.5kPa to 104.3kPa

P1V1 = P2V2

122.5 * 171 = 104.3 * V2

V2 = \(200cm^3\)

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The orbital notation for nitrogen showed that in the valence shell there are 3 paired electrons and 1 unpaired.

The electronic configuration of nitrogen is:

1s²2s²2p⁶.

Nitrogen has five valence electrons with 2 electrons in the 2s orbital and 3 electrons in the 2p orbital.

The 2p orbital has three orbitals, which can accommodate six electrons.

The electronic configuration of nitrogen can be represented as:

1s²2s²2p³Nitrogen has a valence shell of 5 electrons, with 3 of those electrons in the 2p orbitals.

There are three unpaired electrons in the 2p orbitals.

The valence shell electronic configuration of nitrogen can be shown using orbital notation as shown below:

Orbital notation is a symbolic representation of the configuration of electrons in the orbitals of an atom or molecule.

It represents the electron configuration of an atom by showing the energy level and sublevel for each electron in an atom.

It uses arrows to represent electrons and boxes to represent orbitals.

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Answer:

Explanation:

The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit (amu, also known as daltons, D).  The atomic mass is a weighted average of all of the isotopes of that element, in which the mass of each isotope is multiplied by the abundance of that particular isotope.  (Atomic mass is also referred to as atomic weight, but the term "mass" is more accurate.)

Answer:

The characteristic molar mass of an element is simply the atomic mass in g/mol. However, molar mass can also be calculated by multiplying the atomic mass in amu by the molar mass constant (1 g/mol). To calculate the molar mass of a compound with multiple atoms, sum all the atomic mass of the constituent atoms.

Explanation:

Answer:

Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. The Earth's surface lithosphere rides atop the asthenosphere and the two form the components of the upper mantle.

I think it is helpful for you!!!!

Please make me brainliest..

Answer:

The answer is

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume of bromine = 50 mL

density = 3.10 g/cm³

It's mass is

mass = 50 × 3.10

We have the final answer as

Hope this helps you

Answer:

\(\boxed {\tt 155 \ grams}\)

Explanation:

The formula for density is:

\(d=\frac{m}{v}\)

Rearrange the formula for mass, m. Multiply both sides by v.

\(d*v=d=\frac{m}{v}*v\)

\(d*v=m\)

Mass is found by multiplying the mass by the volume.

The density of the bromine is 3.10 grams per cubic centimeter. The volume is 50 milliliters. Since a milliliter is equal to a cubic centimeter, the volume is also 50 cubic centimeters.

\(d= 3.10 \ g/cm^3\)

\(v= 50 \ cm^3\)

Substitute the values into the formula.

\(m=d*v\)

\(m=3.10 \ g/cm^3 *50 \ cm^3\)

Multiply. Note the centimeters cubed will cancel out.

\(m=3.10 \ g * 50\)

\(m= 155 \ g\)

The mass of the bromine is 155 grams.

Answer:

a chemical bond in which two pairs of electrons are shared by two atoms and a molecule. Examples of compounds with double bonds include oxygen gas, carbon dioxide, acetone, and ozone

a chemical bond in which two pairs of electrons are shared between two atoms.

Answer:

A= Covalent compound

B= Covalent compound

Answer:

2

Explanation:

to separate objects or ideas into group based on ways they are alike

Species which has the largest dipole moment is CH3Cl.

Dipole moment can be defined as the product of the distance between the centers of positive and negative charge and the magnitude of the charge. It is denoted by μ.

The trend of dipole moment in case of yhe halogens areas below:

The dipole moment of species CH3Cl is greater than CH3F due to the electron affinity.

Thus, we concluded that species which has the largest dipole moment is CH3Cl.

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Answer:

Cobalt chloride papers are often used as humidity indicators because they change color in response to the relative humidity of the air. When the air is dry, the cobalt chloride paper is blue or purple. As the air becomes more humid, the paper turns pink or red. The color change is reversible, meaning that the paper will return to its original color as the humidity decreases.

Explanation:

Transition Metals are characterized by the filling of d orbitals?

Answer:

See explanation.

Explanation:

Kilo = 1000

Hecto = 100

Deca = 10

Base Unit = 1

Deci = 10

Centi = 100

Milli = 1000

Energy in chemical reactions involves the process in which it is absorbed to break bonds, and energy is evolved as bonds are made.

This is referred to as a process in which one or more substances, the reactants, are converted to one or more different substances, the products.

According to the modern view of chemical reactions, bonds between atoms in the reactants must be broken, and the atoms or pieces of molecules are reassembled into products by forming new bonds. All chemical reactions involve energy changes ad in some reactions, we are able to observe these energy changes as either an increase or a decrease.

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