-7,5 + 4,2 =?


-0,9 * 2,7 =?

Answer:

(-12, -8)

Look at the photo for explaination.

The four functions can be described as follows: a) rect(x/8) - rectangular pulse centered at the origin with a width of 8 units, b) Δ(ω/10) - Dirac delta function with a spike at ω = 0 and zero everywhere else, c) rect(t-3/4) - rectangular pulse centered at t = 3/4 with a width of 1 unit, d) sinc(t) * rect(t/4) - modulated sinc function by a rectangular pulse of width 4 units centered at the origin.

a) rect(x/8):

The function rect(x/8) represents a rectangle function with a width of 8 units centered at the origin. It has a value of 1 within the interval [-4, 4] and a value of 0 outside this interval. The graph of rect(x/8) will consist of a rectangular pulse centered at the origin with a width of 8 units.

b) Δ(ω/10):

The function Δ(ω/10) represents a Dirac delta function with an argument ω/10. The Dirac delta function is a mathematical construct that is zero everywhere except at the origin, where it is infinitely tall and its integral is equal to 1. The graph of Δ(ω/10) will be a spike at ω = 0. The value of Δ(ω/10) at ω ≠ 0 is zero.

c) rect(t-3/4):

The function rect(t-3/4) represents a rectangle function with a width of 1 centered at t = 3/4. It has a value of 1 within the interval [3/4 - 1/2, 3/4 + 1/2] = [1/4, 5/4] and a value of 0 outside this interval. The graph of rect(t-3/4) will consist of a rectangular pulse centered at t = 3/4 with a width of 1 unit.

d) sinc(t) * rect(t/4):

The function sinc(t) * rect(t/4) represents the product of the sinc function and a rectangle function. The sinc function is defined as sinc(t) = sin(t)/t. The rectangle function rect(t/4) has a width of 4 units centered at the origin. The graph of sinc(t) * rect(t/4) will be the multiplication of the two functions, resulting in a modulated sinc function where the rectangular pulse shapes the sinc function.

Therefore, the four functions can be described as follows:

a) rect(x/8) - rectangular pulse centered at the origin with a width of 8 units.

b) Δ(ω/10) - Dirac delta function with a spike at ω = 0 and zero everywhere else.

c) rect(t-3/4) - rectangular pulse centered at t = 3/4 with a width of 1 unit.

d) sinc(t) * rect(t/4) - modulated sinc function by a rectangular pulse of width 4 units centered at the origin.

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We need to know about the concept of dilation to understand the question.

The coordinate of C' will be 1/2 times it's original coordinate.

Dilation is a form of transforming an object by changing it's size or shape by either increasing or decreasing it's dimensions with the use of scaling factors.For example if a shape is said to have been dilated by a factor of 2 it simply means that the object has been doubled it's size.The coordinates of the new object will be twice of the original coordinates. So if one of the coordinate was (1,1) then the coordinates of that point will be (2,2) after dilation.

Here in the question it is said that ABCD has been dilated by a factor of 1/2, so to find the new coordinates of the point C' we will have to multiply the original coordinates at C by 1/2.

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Answ34.5

Step-by-step explanation:

Factoring integers with sublinear resources on a superconducting quantum processor can be achieved using quantum approximate optimization algorithm" (QAOA) or quantum phase estimation algorithm (QPE) approach.

Factoring large integers is a problem of significant importance in the field of cryptography.

Classical computers have limited efficiency in solving this problem, and their performance is expected to decline further as the size of the integers to be factored increases.

In contrast, quantum computers are expected to have exponential speedup in factoring large integers, thanks to Shor's algorithm.

Recently, researchers have been exploring the possibility of using superconducting quantum processors to factor integers with sublinear resources.

One approach is to use a so-called "quantum approximate optimization algorithm" (QAOA), which maps the problem of factoring integers to a problem of finding the ground state of a certain Hamiltonian.

The QAOA can be implemented using a superconducting quantum processor, with the problem Hamiltonian implemented by a set of two-qubit gates.

Another approach is to use the quantum phase estimation algorithm (QPE) to estimate the eigenvalues of the problem Hamiltonian.

This can be used to factor integers by finding the period of a certain function using the quantum Fourier transform, as in Shor's algorithm. QPE can be implemented on a superconducting quantum processor using phase estimation circuits, which require only polynomial resources.

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Answer:

92 m

Step-by-step explanation:

Use the Pythagorean theorem to find the length of the shorter side.

Let w = length of the shorter side.

\(w^{2} + 30^{2} = 34^{2} \\ w^{2} + 900 = 1156\\w^{2} = 256\\w = \sqrt{256} = 16\)

The perimeter is 2l + 2w = 2(30) + 2(16) = 60 + 32 = 92 m

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Answer:

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By elimination, the solution of the system of equations, 5x - 2y = -19 and 2x + 3y = 0, is (-3 , 2).

A system of equations is a set of two or more equations which includes common variables. To solve system of equations, we must find the value of the unknown variables used in the equations that must satisfy all the equations.

There are three methods that can be used to solve system of equations.

1. Elimination

2. Substitution

3. Graphing

Using the elimination method, given two equations in x and y, a variable should be eliminated by adding/subtracting the two equations.

First, multiply the first equation by 3 and the second equation by 2.

5x - 2y = -19 ⇒ 15x - 6y = -57     (equation 1)

2x + 3y = 0 ⇒ 4x + 6y = 0     (equation 2)

Adding the two equations will eliminate the variable y.

15x - 6y = -57     (equation 1)

4x + 6y = 0     (equation 2)

19x        = -57

x = -3

Substitute the value of x to any of the two equation and solve for y.

2x + 3y = 0     (equation 2)

2(-3) + 3y = 0

3y = 6

y = 2

Hence, the solution of the system of equations is (-3 , 2).

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Answer:

$3.90

Step-by-step explanation:

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Y is constant.

The equation of line will be

Answer:

y=1

Step-by-step explanation:

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Answer:

230 children

Step-by-step explanation:

Answer:

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Step-by-step explanation:

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a) The probability of selecting a blue marble is P ( B ) = 1/4

b) The probability of selecting a green marble is P ( G ) = 1/6

c) The probability of selecting not a green marble is P' ( G ) = 5/6

The probability that an event will occur is measured by the ratio of favorable examples to the total number of situations possible

Probability = number of desirable outcomes / total number of possible outcomes

The value of probability lies between 0 and 1

Given data ,

Let the number of blue marbles = 3

Let the number of red marbles = 6

Let the number of green marbles = 2

Let the number of black marbles = 1

So , the total number of marbles = 12

So , the probability is given as

The probability of selecting a blue marble is P ( B ) = 1/4

The probability of selecting a green marble is P ( G ) = 1/6

The probability of selecting not a green marble is P' ( G ) = 5/6

Hence , the probability is solved

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The complete question is attached below :

There are 3 blue marbles, 6 red marbles, 2 green marbles and 1 black marble in a bag. Suppose you select one marble at random. Find the probability for each of the following.

The largest possible last digit in the string of 2002 digits and number divisible by 19 or 31 is 9.

Given the first digit of a string of 2002 digits is 1 and the two digit number formed by consecutive digits within the string is divisible by 19 or 31.

We have to tell the last largest digit of such number.

Two digit numbers divisible by 19=19,38,57,76,95.

Two digit numbers divisible by 31=31,62,93,124

Number started with 1 =19

Last digit is 9

We have said that the number should be divisible by 19 or 31 not from both and started with 1.

Hence the largest possible last digit and number divisible by 19 or 31 in this string is 9.

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78

Step-by-step explanation:

23+28+16+11=78

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Answer:

false is the answer ........

Solution:

So the statement is false and the correct statement is:

For any two integers a and b, (a+b)^2 = a^2+2ab+b^2.

Answer:

107  4/5. This is because 2/5 is 0.4 and 15 times 7 is 105.

Aggregate Demand (AD) is a macroeconomic concept that represents the total demand for goods and services in an economy. The X factor in the AD equation represents exports, which are an important part of the economy.

AD is calculated by adding up the individual components of demand, which include consumer spending (C), investment spending (I), government spending (G), and net exports (X-M). The X-M component represents the difference between exports (X) and imports (M).

The X component in the equation represents exports, which are the goods and services produced domestically and sold to foreign countries. Exports are an important part of the economy as they generate income and create jobs. The M component in the equation represents imports, which are the goods and services purchased from foreign countries and consumed domestically. Imports can have a negative impact on the economy as they represent a drain on resources and can lead to a trade deficit. The X factor in the equation is used to represent exports because it is a variable that can change over time. Factors that can affect exports include exchange rates, tariffs, and global demand for certain products. If the exchange rate between two currencies changes, it can make exports more or less expensive for foreign buyers, which can affect the level of exports. Tariffs are taxes on imports, which can make domestic products more competitive in foreign markets.

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The simplified expression is -x + 16.

To solve a distributive property problem with more than one set of parentheses, you can follow these steps:

Identify the terms that need to be distributed. These are the terms outside the parentheses.

Distribute each term to every term inside the parentheses.

Simplify the expressions inside the parentheses by performing any necessary operations (addition, subtraction, multiplication, etc.).

Combine like terms if possible.

Continue simplifying until you have a final expression.

Here's an example to illustrate the process:

Problem: Simplify the expression 3(x + 2) - 2(2x - 5)

Solution:

Identify the terms to distribute: 3 and -2.

Distribute each term to the terms inside the parentheses:

3(x + 2) becomes 3x + 6

-2(2x - 5) becomes -4x + 10

Simplify the expressions inside the parentheses:

3x + 6 - 4x + 10

Combine like terms:

(3x - 4x) + (6 + 10) = -x + 16

The simplified expression is -x + 16.

By following these steps, you can solve distributive property problems with multiple sets of parentheses. Remember to carefully distribute each term and simplify the expressions inside the parentheses before combining like terms.

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The order of the U5 and U6 is not equal hence isomorphic.

U5 fifth root of unit

U6  sixth root of unit

U5 = { z E c : Z^5 =1 }

= {e ^2ikx : k=0,1,2,,,,n}

U6 = { z E c : Z^6 =1 }

= {e ^2ikx : k=0,1,2,,,,n-1}

U5 = Z5

U6 = Z6

In mathematics, an isomorphism is a structure-preserving mapping between two similar structures that can be reversed by inverse mapping. Two mathematical structures are isomorphic if there is an isomorphism between them.

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Answer:

there are 40% black ball a

white ball we don't know

so, we let = x

40\100 × x

now we cutting

ans is 10x

Answer:

Step-by-step explanation:

P/6

Answer:

1

Step-by-step explanation:

All are divisible by 1.

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Good luck on your assignment...

The correct answer is b. Cost(k) = a k + b.

Affine gap penalties in sequence alignment involve a linear function that considers the number of gaps in a row. The function typically includes two components: a linear term to represent the initial gap and an additional linear term to account for each consecutive gap.

In option a, the cost function includes a quadratic term (k^2), which does not represent a linear affine penalty.

In option c, the cost function includes a logarithmic term (log(k)), which also does not represent a linear affine penalty.

Option b, with the cost function of a k + b, correctly represents an affine gap penalty, as it includes a linear term (a k) to account for the number of gaps in a row.

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