Answer:
No because you can split a tree
Step-by-step explanation:
let k(x) be piecewise function such that k(x) = sinx/x if x ≠ 0, 0 if x=0. let h(x) = 1+x from domain (-infinity, 2), and also let h(x) = -1+x from domain [1, infinity)
what would be limit as x approaches 0 of k(x)-h(x)/k(x) ?
a 0
b 1
c 2
Answer:
a. 0
Step-by-step explanation:
You want the limit of (k(x) -h(x))/k(x) as x approaches 0 when k(x) = sin(x)/x {x≠0} and h(x)=x+1 {x<1}.
LimitSince we're concerned about the limit as x → 0, we don't have to be concerned with the fact that the expression is undefined at x = 0.
The function h(x) is defined as h(0) = 1, so we can just be concerned with the value of ...
lim[x→0] (k(x) -1)/k(x)
The limit of k(x) as x → 0 is 1, so this becomes ...
lim[x→0] (k(x) -1)/k(x) = (1 -1)/1 = 0
Sin(x)/xAt x=0, sin(x)/x is the indeterminate form 0/0, so its limit there can be found using L'Hôpital's rule. Differentiating numerator and denominator, we have ...
lim[x→0] sin(x)/x = lim[x→0] cos(x)/1 = cos(0) = 1
The fact that k(0) = 0 is irrelevant with respect to this limit.
__
Additional comment
We like to use a graphing calculator to validate limit values. The attachment shows the various functions involved. It also shows that as x gets arbitrarily close to 0 from either direction, the value of g(x) does likewise. This is all that is required for (0, 0) to be declared the limit. The lack of definition of g(x) at x=0 simply means the relation has a (removable) discontinuity there.
<95141404393>
Evaluate -2x + 8y when x=1/3
and y = 1/6.Write your answer as a fraction in simplest form.
Answer:
2/3 or 0.6
Step-by-step explanation:
Mhanifa please help I will mark brainliest!
Parallel lines problem:
Parallel lines have the same slope, so the answer should give a pair of lines whose slope is equal to that of line m, i.e., 2/3.
The only line that fits the bill is line p, whose slops is (8-6)/(12-9) = 2/3; none of the other lines has a slope of 2/3. Thus, b would be the correct answer here for the first image.
Congruent triangles problem:
Segment ZX and angle Y would be congruent to segment SQ and R, respectively, so the correct answer for the second image would be a.
Drag the tiles to the correct boxes to complete the pairs.
Match each quadratic function to its graph.
A: f(x) = -2(x + 3)2 − 1
B: f(x) = -2(x + 3)2 + 1
C: f(x) = 2(x + 3)2 + 1
D: f(x) = 2(x − 3)2 + 1
Answer:
f(x) = 2(x + 3)² + 1 corresponds to graph C.
f(x) = -2(x + 3)² + 1 corresponds to graph D.
f(x) = 2(x - 3)² + 1 corresponds to graph A.
f(x) = -2(x + 3)² - 1 corresponds to graph B.
Step-by-step explanation: hope its right
A lawn sprinkler can spray up to 20 feet. If it sprays in a circular pattern, what is the approximate area in square feet watered by the sprinkler?
Answer:
1256.64 square feet
Step-by-step explanation:
In this situation, 20 feet is the radius of the circle that is sprayed.
Use the area formula, A = \(\pi\)r²
Plug in 20 as the radius and solve:
A = \(\pi\)r²
A = \(\pi\)(20)²
A = 400\(\pi\)
This is approximately equivalent to 1256.64
So, the approximate area watered by the sprinkler is 1256.64 square feet
Compute the following arithmetic problems in Z/8. Represent your answer with the least positive representative of the appropriate equivalence class (a) [3] + [4] 7 ] (b) [2] . ([2] + [7]) 2 ]] (c) ([6] + [5]). ([3] + [7])
The answers to the given arithmetic problems are- (a) [3] + [4] 7 ] = 7, (b) [2] . ([2] + [7]) 2 ]] = 4, and (c) ([6] + [5]). ([3] + [7]) = 110.
Here, we are given three equations as follows, let us solve them one by one-
a. [ [3] + [4] 7 ]
Here [z] = remainder when z is divided by 8
Thus, [4] = 4
⇒ [ [3] + 4*7 ]
= [ 3 + 28 ]
= [ 31 ]
= 7
b. [ [2] . ([2] + [7]) 2 ]
= [ 2 . (2 + 7) 2 ]
= [ 2*9*2 ]
= [ 36 ]
= 4
c. ([6] + [5]). ([3] + [7])
= (6 + 5). (3 + 7)
= 11*10
= 110
The answers to the given arithmetic problems are- (a) [3] + [4] 7 ] = 7, (b) [2] . ([2] + [7]) 2 ]] = 4, and (c) ([6] + [5]). ([3] + [7]) = 110.
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The acceleration of a Maserati (sports car) is proportional to the difference between 250 km/h and its velocity. If the car can accelerate from rest to 100 km/h in 10 s, how long will it take for the car to accelerate from rest to 200 km/h?
Answer:
a) The differential equation for the velocity is given by
(dv/dt) = k(250 - v)
b) v(t) = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾
With units of km/h
Step-by-step explanation:
Acceleration, a ∝ (250 - v)
But acceleration is widely given as dv/dt
(dv/dt) ∝ (250 - v)
(dv/dt) = k(250 - v)
where k = constant of proportionality
(dv/dt) = k(250 - v)
b) (dv/dt) = k(250 - v)
dv/(250 - v) = k dt
∫ dv/(250 - v) = ∫ k dt
- In (250 - v) = kt + c (where c is the constant of integration)
v(0) = 0; meaning, at t = 0, v = 0
- In 250 = 0 + C
c = - In 250 = - 5.52
- In (250 - v) = kt - 5.52
In (250 - v) = 5.52 - kt
250 - v = e⁽⁵•⁵² ⁻ ᵏᵗ⁾
v = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾
With units of km/h
i hope this work for you
and sory if im wrang
Two ladders are leaning against the wall as shown below. What is the length of the longer ladder?
The length of the longer ladder is 50 ft. Therefore, the answer is D.
How to find the length of the longer ladder?Two ladders are leaning against the wall as shown below. The length of the longer ladder can be found as follows:
The triangles formed are right angle triangle. The triangles are similar to each other.
Similar triangles are the triangles that have corresponding sides in ratio to each other and corresponding angles congruent to each other.
Therefore, using proportion,
15 / x = 3 / 10
cross multiply
150 = 3x
divide both sides by 3
x = 150 / 3
x = 50
Therefore,
length of the ladder = 50 ft
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The Simpsons rented a trailer that was 8 feet long and 5 feet wide. If they load the trailer with 1-by-1-by-1-foot boxes to a height of 3 feet, how many boxes can be loaded onto the trailer?
The total number of boxes that can be loaded onto the trailer is 27.
Here we have to determine the maximum number of boxes.
That can be stored in a locker by the volume of one box.
From the given information volume of the box is Vb and the volume f the locker is Vl.
What is the volume of the box?
\(Volume=Length\times width\times height\)
Therefore we get,
\(V_b=4\times3\times2\\V_b=24ft^3\)
The volume of the locker is
\(V_L=12\times6\times 9\\V_L=684ft^3\)
Therefore the number of the maximum boxes are
\(\frac{VL}{V_b} =\frac{648}{24} \\=27\)
Therefore, The total number of boxes can be loaded onto the trailer are 27.
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state the trigonometric substitution you would use to find the indefinite integral. do not integrate.
∫ (81+x^2)^−5 dx
X(θ) = ______
To find the trigonometric substitution for ∫ (81+x^2)^−5 dx, we can use x = 9tanθ.
This substitution is useful because it allows us to rewrite the expression in terms of trigonometric functions, which we can then integrate using trigonometric identities.
Therefore, X(θ) = 9tanθ.
To find the indefinite integral of the given function using trigonometric substitution, you'll need to choose an appropriate substitution. For the integral ∫ (81+x^2)^−5 dx, we can use the substitution:
x(θ) = 9 * tan(θ)
This is because we can relate x^2 to a trigonometric identity. After substituting, you would proceed with integration, but since you asked to not integrate, I'll stop here. So the trigonometric substitution for this problem is:
x(θ) = 9 * tan(θ)
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Once you have identified a problem, the next step is to determine the possible solutions, which are called
Answer:
decision alternatives
Step-by-step explanation:
uhhh yea thats pretty much it -
What is the relationship between a 90% confidence interval around a mean and a 95% confidence interval around a mean?
a. The 90% C.I. is wider and includes more values than the 95% C.I.
b. The 95% C.I. is more precise in estimating a mean than the 90% C.I.
c. The 90% C.I. is more precise in estimating a mean than the 95% C.I.
d. The 95% C.I. is narrower and includes less values than the 90% C.I.
The relationship between a 90% confidence interval around a mean and a 95% confidence interval around a mean is (b) The 95% C.I. is more precise in estimating a mean than the 90% C.I.
You have a 5% probability of being incorrect with a 95% confidence interval. You have a 10% probability of being incorrect with a 90% confidence interval.
The upper and lower numbers of a range with a 95% confidence interval (CI) of the mean are determined from a sample. This range describes potential possibilities for the mean because the actual population mean is unknown. Hence, the 95% C.I. is more precise in estimating a mean than the 90% C.I.
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In the following descriptions of a study, confounding is present. Describe the explanatory and confounding variable in the study and how the confounding may invalidate the conclusions of the study. Furthermore, suggest how you would change the study to eliminate the effect of the confounding variable.
a. A prospective study is conducted to study the relationship between incidence of lung cancer and level of alcohol drinking. The drinking status of 5,000 subjects is determined, and the health of the subjects is then followed for 10 years. The results are given below.
Lung Cancer
Drinking status Yes No Total
Heavy drinker 50 2150 2200
Light drinker 30 2770 2800
Total 80 4920 5000
b. A study was conducted to examine the possible relationship between coronary disease and obesity. The study found that the proportion of obese persons having developed coronary disease was much higher than the proportion of nonobese persons. A medical researcher states that the population of obese persons generally have higher incidences of hypertension and diabetes than the population of nonobese persons.
Confounding may invalidate the conclusions of the study as it can cause a bias that can make the effect of the explanatory variable look larger or smaller than it actually is.
This means that the relationship between alcohol drinking status and incidence of lung cancer is influenced by After the classification of smokers and non-smokers, a separate analysis can be done to find the effect of alcohol drinking on lung cancer in both groups.
Explanatory and Confounding Variable in the study :In the given study, the explanatory variable is obesity and the response variable is coronary disease. Whereas, the confounding variable is hypertension and diabetes because these diseases are associated with obesity. The confounding variable can invalidate the conclusions of the study as it can affect the relationship between obesity and coronary disease .To eliminate the effect of the confounding variable, the study can be changed in the following ways.
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(23 pts) Let X and Y have joint density f XY (x,y)=24xy f XY (x,y)=\ matrix 24xy&x>=0,y>=0,x+y<=1\\ 0&otherwise matrix
Find the marginal density of X / Y
(1)
To find the marginal density of X/Y, we need to integrate the joint density function fXY(x, y) over the range of Y. By performing the integration, we obtain the marginal density of X/Y as a function of X. The resulting marginal density provides information about the distribution of the ratio X/Y.
The marginal density of X/Y can be obtained by integrating the joint density function fXY(x, y) over the range of Y. In this case, the joint density function is given by:
fXY(x, y) =
24xy if x >= 0, y >= 0, and x + y <= 1
0 otherwise
To find the marginal density of X/Y, we integrate fXY(x, y) with respect to y, while keeping x as a constant. The integration limits for y can be determined based on the given conditions x >= 0, y >= 0, and x + y <= 1. Since y must be non-negative, the lower limit of integration is 0. The upper limit of integration can be determined by the constraint x + y <= 1, which implies y <= 1 - x.
Integrating fXY(x, y) over the range of y, we obtain the marginal density of X/Y as follows:
fX/Y(x) = ∫[0 to (1 - x)] 24xy dy
Evaluating the integral, we have:
fX/Y(x) = 24x * ∫[0 to (1 - x)] y dy
= 24x * [(y^2)/2] evaluated from 0 to (1 - x)
= 12x * (1 - x)^2
The resulting marginal density fX/Y(x) represents the distribution of the ratio X/Y. It provides information about the likelihood of different values of X/Y occurring. The shape of the distribution can be further analyzed to understand the characteristics of the random variable X/Y.
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Which number line and expression show how to find the distance from -4 to
1?
O A.
B.
C.
O D.
5
4
3
-2
|-4-1|
4
4-(-1)
4-1
-1 0
|-4-(-1)
1
2 3 4
23
The distance from -4 to 1 is 5 units.
The correct number line and expression to find the distance from -4 to 1 are:
Number line: -4 -3 -2 -1 0 1
Expression: |-4 - 1|
To find the distance, we subtract the smaller number (-4) from the larger number (1) and take the absolute value:
|-4 - 1| = |-5| = 5
Therefore, the distance from -4 to 1 is 5 units.
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Solve this fraction based question for 20 points.
The simplified form of the expression is -11/9
Rational expressionsThese are expressions written as fractions. Given the following fraction
\(\dfrac{\frac{5}{8} +\frac{3}{4} }{\frac{-2}{3}-\frac{5}{6} }\)
Find the LCM of the numerator and denominator
\(\dfrac{\frac{5}{8} +\frac{3}{4} }{\frac{-2}{3}-\frac{5}{6} }\\\dfrac{\frac{5+6}{8} }{\frac{-4-5}{6} } \\\dfrac{\frac{11}{8} }{\frac{-9}{8} }\)
Divide the result to have:
11/8÷-9/8
11/8 * 8/-9
-11/9
Hence the simplified form of the expression is -11/9
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1. If f(x) = (3x-2)/(2x+3), then f'(x) =
Answer:
\(f'(x)= \frac{13}{(2x+3)^2}\\\)
Step-by-step explanation:
\(f(x)= \frac{3x-2}{2x+3} \\\)
\(f'(x)=\frac{dy}{dx} = \frac{d}{dx}(\frac{3x-2}{2x+3})\\ f'(x)= \frac{(2x+3)\frac{d}{dx}(3x-2)-(3x-2)\frac{d}{dx}(2x+3) }{(2x+3)^{2} } \\f'(x)= \frac{(2x+3)(3)-(3x-2)(2)}{(2x+3)^{2} } \\\)
\(f'(x)= \frac{6x+9-6x+4}{(2x+3)^{2} }\\ f'(x)= \frac{13}{(2x+3)^2}\\\)
Which statement correctly compares the ratios?
The ratio 9 to 12 is greater than 4 to 6.
The ratio 9 to 12 is less than 4 to 6.
The ratio 9 to 12 is equal to 4 to 6.
The ratios cannot be compared.
Answer:
The ratio 9 to 12 is greater than 4 to 6
Step-by-step explanation:
9÷12=0.75
4÷6=0.67
0.75> 0.67
what is the solution pls help
Answer:
n=15.1
Step-by-step explanation:
14.8=n-0.3
14.8+0.3=n
15.1=n
Which of the following is a degenerate circle?
O A. x² + y² = -4
B. x² + y² = 121
c. (x - 5)² + (y-1)² = 0
D. x+y=12
The require degenerative circle is (x - 5)² + (y - 1)² = 0. Option C is correct.
Given that,
The equation for the degenerative circle is to be determined.
The circle is the locus of a point whose distance from a fixed point is constant i.e center (h, k). The equation of the circle is given by
(x - h)² + (y - k)² = r²
where h, k is the coordinate of the circle's center on the coordinate plane and r is the circle's radius.
The degenerative circle is a circle whose radius is zero, from the option,
Option C has the equation of the circle with radius zero.
Thus, the required degenerative circle is (x - 5)² + (y - 1)² = 0.
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Please help! I am supposed to write a recursive and an explicit function for the geometric sequence but this one is really frustrating me. Thank you!
Step-by-step explanation:
Initially, there's only 1 letter.
Tania sends the letter to 4 friends.
Each friend sends a letter to 4 more friends (4 × 4 = 16).
Each of those friends sends to 4 more friends (16 × 4 = 64).
The pattern is 1, 4, 16, 64, etc.
This is a geometric sequence. The first term is 1 and each term is 4 times the previous term.
a₁ = 1
aₙ = 4 aₙ₋₁
The explicit formula is:
aₙ = 1 (4)ⁿ⁻¹
Tri-County G\$T selis 150,000 MWh per yeat of electrical power to Boulder at $80 per MWh, has fixed costs of $80.1 milion per yoar, and has varistele costs of $20 por MWh. If Tri-County has 1,000,000MW h of demand from its customers (other than Boulder), what will Tri-County have to charge to break even? Tri-County wit have to charge? to break oven. (Enter your response rounded to the nearest penny.)
Tri-County will have to charge approximately $83.1 per MWh to break even.
To calculate the break-even price that Tri-County will have to charge to cover its costs, we need to consider both the fixed costs and the variable costs. The fixed costs are given as $80.1 million per year.
The variable costs are calculated by multiplying the quantity of electrical power sold (150,000 MWh per year to Boulder) by the variable cost per MWh ($20). Therefore, the variable costs amount to 150,000 MWh/year * $20/MWh = $3 million per year.
To cover both fixed and variable costs, Tri-County needs to charge a total amount that equals the sum of these costs. The total cost is $80.1 million + $3 million = $83.1 million per year.
Now, let's calculate the break-even price per MWh. Since Tri-County has a demand of 1,000,000 MWh from its customers (other than Boulder), we can divide the total cost by this quantity to find the break-even price.
Break-even price = Total cost / Quantity of electrical power demanded
Break-even price = $83.1 million / 1,000,000 MWh = $83.1/MWh
Therefore, Tri-County will have to charge approximately $83.1 per MWh to break even.
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A ball is released from rest and falls 125 meters in 5 seconds. What was the magnitude of its acceleration?
From the calculations using the data provided, the acceleration of the ball is 10 m/s^2
What is the acceleration?We know that the acceleration is the rate at which there is an increase or a decrease in the velocity of a body. In this case, we are told that A ball is released from rest and falls 125 meters in 5 seconds.
We have the following;
Distance of the object = 125 meters
Time taken = 5 seconds
Given that;
s = ut + 1/2at^2
u = 0 m/s because it was released from rest
s = 1/2at^2
a = 2s/t^2
a = 2(125)/(5)^2
a = 250/25
a = 10 m/s^2
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a trough is 12 feet long and 3 feet across the top (see figure). its ends are isosceles triangles with altitudes of 3 feet. if water is being pumped into the trough at 2 cubic feet per minute, how fast is the water level rising (in feet per minute) when \displaystyle hh is 1 foot deep?
If water is being pumped into the trough at 2 cubic feet per minute, then the water level rising (in feet per minute) when h is 1.6 foot deep is 0.1 feet cubic per minute.
Suppose that we have a function y = f(x), and wish to find the rate of change of y with respect to a third variable t, where we do not have y expressed explicitly in terms of t. We use the chain rule in differentiation to find this rate of change in a process called implicit differentiation.
dy/dt = dy/dx × dx/dt
If base is equal to the height, by similar triangles:
Volume v = base x height x length/2
= bhl/2
= h²12/2
= 6h².
Therefore,
dv/dt = 12hdh/dt
= 2 ft³/min
Now,
dh/dt = 2/(12h)
when h = 1.6,
dh/dt = 2/(12 × 1.6) ≈ 0.1 ft³/min
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The table shows the results of a survey of 150 students. Use the table to find the probability of a student participating in each sport.
1. Tennis
2. Football
3. Gymnastics
4. Volleyball
Can someone please help!
Answer:
See below
Step-by-step explanation:
Using the table of 150 students, we can configure probabilities.
18 students participate in tennis, so the probability of a student participating in tennis is 18/150, or 3/25 simplified.
45 students participate in football, so the probability of a student participating in football is 45/150, or 3/10 simplified.
12 students participate in gymnastics, so the probability of a student participating in gymnastics is 12/150, or 2/25 simplified.
9 students participate in volleyball, so the probability of a student participating in volleyball is 9/150, or 3/50 simplified.
What is the interquartile range (IQR) of this data set?
2, 6, 7, 11, 15, 16, 17
A.9
B.7
C.10
D.15
Answer:
11 is the median of the entire data set
6 is the median of the lower half and 16 is the median of the upper half data scores...
Subtract 16 from 6 gives 10 so the answer is C) 10
=============================================================
Explanation:
The first step is to sort the data from smallest to largest. Luckily, that's already been done for us.
Next, we find the median. This is the middle most number of the set. In this case, the median is 11 since we have 3 values below it (2,6,7) and 3 values above it (15,16,17).
Let
L = {2,6,7}
U = {15,16,17}
where L and U are the lower and upper sets respectively.
In other words, anything in set L is lower than the median while anything in set U is above the median. The median itself (11) is not part of either set.
Notice how 6 is the midpoint of set L, while 16 is the midpoint of set U.
This means Q1 = 6 and Q3 = 16
Therefore,
IQR = Q3 - Q1
IQR = 16 - 6
IQR = 10
which is why choice C is the final answer.
Use the information given in the diagram to prove that triangle PUX is congruent to triangle QSY. I have multiple photos I would like to upload on here.
SOLUTION
We want to use the information in the diagram to prove that
\(\Delta PUX\cong\Delta\text{QSY}\)Now, we have been given for number 1
2.
\(\begin{gathered} RS=VU \\ \text{Definition of congruent segments } \end{gathered}\)3.
\(\begin{gathered} RU=RS+SU,VS=VU+SU \\ \text{Segment addition postulate } \end{gathered}\)4.
\(\begin{gathered} VS=RS+SU \\ Substitution\text{ property of equality} \end{gathered}\)5.
\(\begin{gathered} RU\cong VS \\ Transitive\text{ property of equality } \end{gathered}\)6.
\(\begin{gathered} RU=VS \\ \text{Definition of congruent segments} \end{gathered}\)7.
\(\begin{gathered} \Delta PUR\cong\Delta QSV \\ \text{ASA congruence theorem } \end{gathered}\)8.
\(\begin{gathered} m\angle RUX\cong m\angle VSY \\ m\angle PUR\cong m\angle QSV \\ \text{Corresponding parts of congruent triangles are congruent } \end{gathered}\)9. and 10. is good (correct)
11.
\(\begin{gathered} m\angle PUX=m\angle QSY \\ \text{Substitution property of equality} \end{gathered}\)12.
\(\begin{gathered} m\angle QSY=m\angle PUR+m\angle RUX \\ \text{Transitive property of equality} \end{gathered}\)13.
\(\begin{gathered} m\angle PUX=m\angle QSY \\ \text{Definition of congruent angles } \end{gathered}\)14.
\(\begin{gathered} \Delta PUX\cong\Delta\text{QSY} \\ \text{ASA congruence theorem} \end{gathered}\)PLS SOMEONE HELP ME URGENTLY PLS
The vector z in the component form is z = < 21 , 24 , -27 >
Given data ,
A vector in component form is typically written as an ordered pair or triplet, where each component represents the magnitude of the vector along a specific coordinate axis.
Now , the vector u = < -1 , 3 , 1 >
v = < 4 , -3 , -1 >
w = < 10 , 5 , -10 >
Now , the value of vector z = < 3w - 2v + u >
z = 3w - 2v + u
z = 3w - 2 * < 4 , -3 , -1 > + < -1 , 3 , 1 >
Using scalar multiplication, we get:
z = < 30 , 15 , -30 > - < 8 , -6 , -2 > + < -1 , 3 , 1 >
Adding vectors, we get:
z = < 30 - 8 - 1 , 15 - (-6) + 3 , -30 + 2 + 1 >
z = < 21 , 24 , -27 >
Hence , the vector z in component form is z = < 21 , 24 , -27 >
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PLEASE HELP IM STUCK ON THIS
which table of values can be defined by the function y=6x-2
x y
-2 10
-1 8
0 6
1 4
2 2
x y
-14 -2
-8 -1
-2 0
4 1
10 2
x y
0 -2
6 -4
12 -6
18 -8
24 -10
x y
-10 -62
-5 -32
0 -2
5 28
10 58
Answer:
23
Step-by-step explanation:
find the circumference using the formula calculate your answer to the nearest hundredth
The circumference of the circle to the nearest hundredth is 21.98 inches.
How to find the circumference of a circle?The circumference of a circle is the measure of the boundary or the length of the complete arc of a circle.
The circumference of a circle is the perimeter of the circle. It's the wholes boundary of the circle.
The circumference of the circle can be found as follows:
circumference of a circle = 2πr
where
r = radiusTherefore,
diameter of the circle = 7 inches
radius of the circle = 7 / 2 = 3.5 inches
Hence,
circumference of a circle = 2 × 3.14 × 3.5
circumference of a circle = 21.98 inches
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