-7+ 3x-2(3x+4)= 5(2x-3) + 4 (3x - 1) - 4.

The correct answer is d) f^(-1)(x) = x/3, as it represents the Inverse relationship of y = 3x.

To find the inverse of a function, we need to switch the roles of x and y and solve for the new y.

The given function is y = 3x.

To find its inverse, let's swap x and y:

x = 3y

Now, solve this equation for y:

Dividing both sides of the equation by 3, we get:

x/3 = y

Therefore, the inverse function of y = 3x is f^(-1)(x) = x/3.

Among the given options:

a) f^(-1)(x) = 1/3x

b) f^(-1)(x) = 3x

c) f^(-1)(x) = 3/x

d) f^(-1)(x) = x/3

The correct answer is d) f^(-1)(x) = x/3, as it represents the inverse relationship of y = 3x.

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The height of the building is 81 feet.

∫cos(2x)dx, we can use the substitution u = 2x, du/dx = 2, dx = du/2, to get:
∫cos(2x)dx = (1/2)∫cos(u)du = (1/2)sin(u) + C = (1/2)sin(2x) + C,
Where C is the constant of integration.
The formula for cos(kx), where k is a nonzero constant, we can use the trigonometric identity cos(2θ) = 2cos²θ - 1, to get:
cos(kx) = cos((k/2)(2x)) = 2cos²((k/2)x) - 1.
Using the identity cos²θ = (1 + cos(2θ))/2, we get:
cos(kx) = 2[(1 + cos(kx))/2]² - 1
= (1/2)[1 + 2cos(kx) + cos²(kx)] - 1
= (1/2)(cos(kx) + 1).
The formula from part (b), we can write:
10cos³(5x) - 4cos²(5x) + cos(5x)
= 10cos(5x)cos²(5x) - 4cos²(5x) + cos(5x)
= (5cos(5x) + 1)(2cos²(5x) - 1)
We can use the equations of motion to solve this problem.

Let h be the height of the building. The initial velocity is 0, and the acceleration due to gravity is -32ft/sec². Integrating the acceleration gives us the velocity as a function of time:
v(t) = -32t + C,
where C is the constant of integration. Since the velocity at time t = 0 is -72ft/sec, we have:

v(0) = -32(0) + C = -72
C = -72
Therefore, the velocity as a function of time is:
v(t) = -32t - 72.
Integrating the velocity gives us the height as a function of time:
h(t) = -16t² - 72t + D,
where D is the constant of integration. Since the initial height is h, we have:
h(0) = D
D = h
Therefore, the height as a function of time is:
h(t) = -16t² - 72t + h.
To find the height of the building, we need to find the time when the rock hits the ground.

This occurs when h(t) = 0, so we need to solve the quadratic equation:
-16t² - 72t + h = 0.
Using the quadratic formula, we get:
t = (-(-72) ± √((-72)² - 4(-16)(h)))/(2(-16))
t = (9 ± √(81 + 4h))/4
Since we are interested in the positive root, we have:
t = (9 + √(81 + 4h))/4.
Plugging this value of t back into the equation for h(t), we get:
h = -16[(9 + √(81 + 4h))/4]² - 72[(9 + √(81 + 4h))/4] + h
Simplifying this equation, we get:
81 + 4h = 2304/16

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An equation that mode the relationship between thee two variable is y=2x+3 .

Let x represent the number of 6-month period worked

Let y represent the total number of paid vacation day

According to the question,

When he started work, he was given three paid day of vacation. For each six-month period he pay at the job, his vacation is increased by two day.

Each year has 2 six-month periods. After 4.4 years Roberto will have worked 8.8 six-month periods. He will have been given vacation days for each of the 8 whole working periods he has completed. x=8 y=2*8+3 y=19

An equation that mode the relationship between thee two variable is y=2x+3 (Total vacation time equals 2 days times x plus the 3 days he was given at the start).

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Therefore, the vertical component of the force exerted on the block by the floor is equal to the normal force (N).

To determine the vertical component of the force exerted on the block by the floor, we need to consider the forces acting on the block. In this case, since the block is being pulled horizontally, the main forces to consider are the gravitational force (mg) acting vertically downward and the normal force (N) exerted by the floor perpendicular to the surface.

Since the block is on a rough horizontal floor and being pulled horizontally, there is a frictional force (f) opposing the motion. The frictional force acts parallel to the surface and in the opposite direction to the applied force. The vertical component of the force exerted by the floor is equal to the normal force (N). The normal force balances the downward force due to gravity (mg) to keep the block in equilibrium vertically.

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If you perform multiple t-tests, the Type I error increases.

When conducting multiple t-tests, each individual test has a certain probability of committing a Type I error, which is the probability of incorrectly rejecting the null hypothesis when it is actually true. The standard threshold for Type I error is typically set at 5% (or 0.05).

However, when multiple tests are performed, the probability of committing at least one Type I error across all the tests increases. This is known as the problem of multiple comparisons or multiple testing.

The more tests you perform, the higher the likelihood of observing a significant result by chance alone, leading to an increased Type I error rate.

To address this issue, it is common to adjust the significance level (e.g., using Bonferroni correction) or conduct post hoc comparisons using methods such as Tukey's test or Bonferroni adjustment.

These methods help control the overall Type I error rate when multiple comparisons are made.

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Answer:

78 degrees

Step-by-step explanation:

hope this is right i added and somehow got this tell me if i got it right or wrong no hate

Answer:

151 notes

Step-by-step explanation:

$85/1=85 notes

125/5=25 notes

150/10=15 notes

420/20=21 notes

500/100=5 notes

85+25+15+21+5=151 notes total

Answer:

$(8m + 13n)

Step-by-step explanation:

Given that :

Total Cost of 6 bouquet = 6m

Total cost of 8 chocolate = 8n

Total amount spent = $(6m + 8n)

Total amount left = $(2m + 5n)

Hence, amount had at first :

Total amount. Spent + total amount. Left

(6m + 8n) + (2m + 5n)

(6m + 2m + 8n + 5n)

$(8m + 13n)

Answer:

5 eggs

Step-by-step explanation:

Answer:

2 beads

Step-by-step explanation:

This is because 5 * 6 = 30

Meaning 5 necklaces with 6 beads each

Answer:

The speed is 2/9 miles per minute

Step-by-step explanation:

Speed is defined as the distance covered per unit time.

The formula for speed is given by:

\(Speed = \frac{distance}{time}\)

Let s be the speed, d be the distance and t be the time then

\(s = \frac{d}{t}\)

Given

\(d = 3\frac{2}{3} = \frac{11}{3}\ miles\\t = 16\frac{1}{2} = \frac{33}{2}\ minutes\)

The speed will be calculated by dividing the number of miles by minutes

So putting the values in the formula

\(s = \frac{\frac{11}{3}}{\frac{33}{2}}\\= \frac{11}{3} * \frac{2}{33}\\=\frac{1}{3} * \frac{2}{3}\\=\frac{2}{9}\)

Hence,

The speed is 2/9 miles per minute

In order to have an equation with no solution, the variable x should not appear in the equation and the final sentence must be false.

So, using the variable 'y' to represent the missing number and simplifying the equation, we have:

Since we want the variable x to disappear (this way we will have 0 = 20, which is false), we need the coefficient (10 - y) to be zero:

So the missing number is 10.

Answer:

Step-by-step explanation:

wwwwwwwwwwwwwwwwwwwwwwwww

Answer:

360° 32 I belive?

( Brainlyst will help me rank up! Thanks! )

Answer:

y=-2.5-5/4x and no it doesn't pass through (4,12)

Step-by-step explanation:

5x-4y=10

-5x     +5x

-4y=10+5x

/-4     /-4

y=-2.5-5/4x

Answer:

44

Step-by-step explanation:

because i just did the test

The length of the segment in the given figure is 44 units.

Consider triangle STR and ΔQTR.

We have to find the length of QV.

∠TRQ = ∠TRS = 90°

TR = TR (Common)

SR = RQ (Given)

So, ΔTSR ≅ ΔTQR ( By SAS Congruence Criterion)

So, By CPCT (Correspondence part of congruent triangle)

TS = TQ

2x+8=40

2x=32

Divide both sides by 2

x=16

Now segment QV=3x-4

3(16)-4

48-4=44 units

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Answer:

vertex at (-1,1)

axis of symmetry:  x=-1

y-intercept at 5

Step-by-step explanation:

False. very few tools are available to assist system analysts and end users in analyzing data.

There are many tools available to assist system analysts and end users in analyzing data. Some commonly used tools include spreadsheets (such as Microsoft Excel), data visualization software (such as Tableau or Power BI), statistical analysis software (such as R or SPSS), and business intelligence software (such as SAP or Oracle).

These tools allow analysts and end users to process, manipulate, and visualize large volumes of data, as well as to perform complex statistical analyses and modeling. Additionally, with the advent of big data technologies, such as Hadoop and Spark, analysts and end users can now analyze vast amounts of data in real-time, using distributed computing systems.

In summary, there are many tools available to assist system analysts and end users in analyzing data, and these tools continue to evolve and improve over time.

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Answer: If this isn't a trick question it is $68.60

Step-by-step explanation: You just multiply the 98 cents by the 70 songs.

Answer:

68. 60

Step-by-step explanation:

You have to put the 0 from 70 first then times 8x7 then 9x7 giving you your answer

Answer:

0.9/3=0.3 First one

Step-by-step explanation:

0.9/3=0.3

The boxes are being divided into 3 equal parts and each section has 0.30 squares

Answer:

The answer is A: 0.9÷3=0.3

Step-by-step explanation:

The boxes are equally divided into thirds

Austin drove the truck for a total of 262 miles.

This can be calculated using the following formula:
base fee + (additional charge * total miles) = total cost


$14.99 + (0.72 * x) = $189.95


Rearranging the equation gives us: 0.72x = $174.96


Then, dividing both sides by 0.72 gives us: x = 262 miles

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you add two with six which is 8

Step-by-step explanation:

you add 2 with6

Answer:

\( \frac{BD}{AD} = \frac{5}{7} \)

Step-by-step explanation:

Coordinate of B = 1

Coordinate of D = 6

Coordinate of A = -1

BD = |1 - 6| = 5 units

AD = |-1 - 6| = |-7| = 7 units

\( \frac{BD}{AD} \)

Plug in the values

\( \frac{BD}{AD} = \frac{5}{7} \)

a.  The probability that this runner will complete this road race: In less than 160 minutes is 0.0764. The correct answer is C.

b.  The probability that this runner will complete this road race: In 215 to 245 minutes is 0.1125 The correct answer is C.

a. To find the probability for each scenario, we'll use the given normal distribution parameters:

Mean (μ) = 190 minutes

Standard Deviation (σ) = 21 minutes

Probability of completing the road race in less than 160 minutes:

To calculate this probability, we need to find the area under the normal distribution curve to the left of 160 minutes.

Using the z-score formula: z = (x - μ) / σ

z = (160 - 190) / 21

z ≈ -1.4286

We can then use a standard normal distribution table or statistical software to find the corresponding cumulative probability.

From the standard normal distribution table, the cumulative probability for z ≈ -1.4286 is approximately 0.0764.

Therefore, the probability of completing the road race in less than 160 minutes is approximately 0.0764. The correct answer is C.

b. Probability of completing the road race in 215 to 245 minutes:

To calculate this probability, we need to find the area under the normal distribution curve between 215 and 245 minutes.

First, we calculate the z-scores for each endpoint:

For 215 minutes:

z1 = (215 - 190) / 21

z1 ≈ 1.1905

For 245 minutes:

z2 = (245 - 190) / 21

z2 ≈ 2.6190

Next, we find the cumulative probabilities for each z-score.

From the standard normal distribution table:

The cumulative probability for z ≈ 1.1905 is approximately 0.8820.

The cumulative probability for z ≈ 2.6190 is approximately 0.9955.

To find the probability between these two z-scores, we subtract the cumulative probability at the lower z-score from the cumulative probability at the higher z-score:

Probability = 0.9955 - 0.8820

Probability ≈ 0.1125

Therefore, the probability of completing the road race in 215 to 245 minutes is approximately 0.1125. The correct answer is C.

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Answer:

Compounded weekly

Step-by-step explanation:

Answer: Cumulative frequency distribution

Step-by-step explanation: Not entirely sure but I believe you are looking for this definition based on the question. Hope this helps :)

(a) The statement is "For functions f, if f"(x) < 0 on the interval (a, b), then f'(x) > 0 on the interval (a, b)." : some

(b) The statement is "For functions f, if f(x) is a polynomial, then it is differentiable for all x." : all

(c)The statement is "For functions f, the tangent line to f(x) at x = a will intersect the graph of f(x) at exactly one point." : no

(a) The statement is "For functions f, if f"(x) < 0 on the interval (a, b), then f'(x) > 0 on the interval (a, b)."

Answer: Some.

The statement is not true for all functions. Here are two specific examples:

Example where the statement is true: Let f(x) = -x^2. The second derivative is f"(x) = -2. On the interval (-∞, ∞), f"(x) < 0, which satisfies the "if" part of the statement. However, the first derivative is f'(x) = -2x, which is negative for x > 0 and positive for x < 0, contradicting the "then" part of the statement.

Example where the statement is false: Let f(x) = x^3. The second derivative is f"(x) = 6x. On the interval (-∞, ∞), f"(x) < 0 is never satisfied. Therefore, we don't have any interval where the "if" part of the statement is true, making the "then" part irrelevant.

(b) The statement is "For functions f, if f(x) is a polynomial, then it is differentiable for all x."

Answer: All.

The statement is true for all polynomials. A polynomial function is differentiable for all x because it is formed by a finite number of terms involving powers of x, constant coefficients, and addition or multiplication operations. The derivative of a polynomial can be obtained using the power rule, which is applicable to all terms of the polynomial. Therefore, the statement holds true for all polynomial functions.

(c) The statement is "For functions f, the tangent line to f(x) at x = a will intersect the graph of f(x) at exactly one point."

Answer: No.

The statement is not true for all functions. Here are two specific examples:

Example where the statement is true: Let f(x) = x^2. The tangent line to f(x) at x = 0 is the line y = 0. It intersects the graph of f(x) at exactly one point (0, 0).

Example where the statement is false: Let f(x) = |x|. The tangent line to f(x) at x = 0 is the line y = 0. However, the graph of f(x) does not intersect the tangent line at exactly one point. The graph of f(x) has a "V" shape at x = 0 and intersects the tangent line at infinitely many points.

In conclusion:

(a) The statement is "For functions f, if f"(x) < 0 on the interval (a, b), then f'(x) > 0 on the interval (a, b)." : some

(b) The statement is "For functions f, if f(x) is a polynomial, then it is differentiable for all x." : all

(c)The statement is "For functions f, the tangent line to f(x) at x = a will intersect the graph of f(x) at exactly one point." : no

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Answer:

3(6x + 1)

Step-by-step explanation:

3(6x + 1) =

18x + 3

Answer:

[4,infinity] for DECREASING

[negative infinity, 4] for INCREASING

Step-by-step explanation: