7. (1 mark) The p-value is smaller than 0.05 ___
- true
- false
8. (1 mark) We decide that ___
- p value is greater than 0.05, therefore we do not reject the
null hypothesis
- p value is less than 0.0

Answer:

\( {.2}^{4} = .0016\)

Answer:

Step-by-step explanation:

0.2^4 is

0.2 x 0.2 x 0.2 x 0.2  =

0.04 x 0.04 =

0.0016

Answer: It dosn't show anything for me. did you post it?

Answer:

4.

Step-by-step explanation:

To compute the z-score for the applicant, we can use the formula:

z = (x - μ) / σ

Where:

x is the applicant's score

μ is the mean

σ is the standard deviation

Given that the applicant's score is 21.0, the mean is 18.0, and the standard deviation is -3.0, we can substitute these values into the formula to calculate the z-score.

z = (21.0 - 18.0) / (-3.0)

z = 3.0 / -3.0

z = -1.0

Therefore, the z-score for the applicant is -1.0.

The correct option is O-10.

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The number of months that tara can send her payments for the Loan is; 18 months

We are told that;

Tara has to pay $25 each month to pay the loan.

She has $ 450 in her account to pay the loan.

For us to find the number of months she can pay the loan, we will apply the unitary method as;

$25 she can pay in 1 month

The number of months to pay $1 is; 1/25 months

The number of months to pay $450 is; (1/25) * 450 = 18 months.

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When the person has been dead for 2 minutes and comes back their experience of 2 minutes dead then we call that the person is suffering from Lazarus Syndrome .

What is Lazarus Syndrome ?

The Lazarus syndrome is referred as to your blood circulation returning spontaneously after your heart stops beating and it fails to restart despite providing  cardiopulmonary resuscitation (CPR).

In Simple words it can be called as returning to life after it appears that the person has  died.

So, if the person comes back to life after experience of 2 minutes of dead , then we say that the person has Lazarus Syndrome and got a heart attack .

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Answer:

a. \( \\ \mu = 0\) and \( \\ \sigma = 1\)

b. A bell-shaped curve (see the below graph).

c. \( \\ P(Z<1.2) = 0.88493\)

d. \( \\ P(Z<-1.64) = 0.05050\)

e. \( \\ P(Z>-1.39) = 0.91774\)

f. \( \\ P(-0.45< Z <1.96) = 0.64864\)

g. \( \\ P(Z<1.015 = 0.845)\), c = 1.015.

h. \( \\ P(Z>-1.015 = 0.845)\), c = -1.015.

i. \( \\ P(-1.422 < Z < 1.422) = 0.845\)

Step-by-step explanation:

Z is a random variable and is a standardized value or a z-score. The formula for it is as follows:

\( \\ Z = \frac{X - \mu}{\sigma}\) [1] (represented as a random variable)

\( \\ z = \frac{x - \mu}{\sigma}\)  [2] (represented as realizations of the random variables or values taken by the random variable Z.)

Where

Z follows a standard normal distribution (see formula [3]), which is a normal or Gaussian distribution with \( \\ \mu = 0\) and \( \\ \sigma = 1\). It is symmetrical at

\( \\ Z \sim N(0,1)\) [3]  

Finding probabilities using the standard normal table

We can use the standard normal distribution to find all probabilities related to Z, and there exists the standard normal table, available in any Statistics books or on the Internet.

We need to consult the standard normal table, use the first two values for Z, that is, in the case of 1.64, we use 1.6 as an entry. We find this value in its first column, and then, using the first row of the table, we localize the remaining 0.04. The intersection of these two values "gives us" the cumulative probability from \( \\ -\infty\) to the value z = 1.64.

Notice that negative values for z-scores are below the mean, whereas positive values represent z-scores above \( \\ \mu\).

Answering the questions

a. What is the mean and standard deviation for Z?

As we discuss before, the mean and the standard deviation are, respectively, \( \\ \mu = 0\) and \( \\ \sigma = 1\).

b. Sketch the distribution.

We can sketch it as a normal or Gaussian distribution, that is, a bell-shaped curve, symmetrical at \( \\ \mu =0\), with most values near the mean and less at each end of the distribution. See the below graph.

c. Find P(Z <1.2)

Following the explained procedure above, we can obtain the cumulative probability for \( \\ P(Z<1.2)\):

In the first column, we localize z = 1.2. At the first row, we localize the value 0.00 (since z = 1.2 = 1.20). Notice that this value is above the mean (positive).

Then, the asked probability is \( \\ P(Z<1.2) = 0.88493\).

d. Find P(Z < −1.64)

The values less than z = -1.64 are below the mean, and we have for the first column z = -1.6 and for the first row -0.04. Then

\( \\ P(Z<-1.64) = 0.05050\)

e. Find P(Z > −1.39)

In this case, we need to recall that

\( \\ P(Z<a) + P(Z>a) = 1\)

For any positive or negative value of a. Then

\( \\ P(Z<-1.39) + P(Z>-1.39) = 1\)

Thus

\( \\ P(Z>-1.39) = 1 - P(Z<-1.39)\)

\( \\ P(Z>-1.39) = 1 - 0.08226\)

\( \\ P(Z>-1.39) = 0.91774\)

f. Find P(−0.45 < Z <1.96)

In this case, we need to find \( \\ P(Z<1.96) - P(Z<-0.45)\). Then

\( \\ P(Z<1.96) = 0.97500\)

\( \\ P(Z<-0.45) = 0.32636\)

Therefore

\( \\ 0.97500 - 0.32636\)

\( \\ 0.64864\)

Then, \( \\ P(-0.45< Z <1.96) = 0.64864\).

g. Find c such that P(Z < c) = 0.845

In this case, find the cumulative probability, 0.845, and the corresponding value for z.

This value is between z-scores (z = 1.01 and z = 1.02). The standard normal table cannot give us values for z with more than two decimal digits for z. We can overcome this using interpolation or technology, and this value will have a third digit for z. This value is approximately:

\( \\ P(Z<1.015 = 0.845)\), c = 1.015.

h. Find c such that P(Z > c) = 0.845

Because of the symmetry of the normal distribution:

\( \\ P(z<-a) = P(z>a)\) or

\( \\ P(z>-a) = P(z<a)\)

From the previous result (part g):

\( \\ P(Z<1.015 = 0.845)\)

Then

\( \\ P(Z>-1.015 = 0.845)\), c = -1.015.

i. Find c such that P(−c < Z < c) = 0.845

We can overcome using the symmetry of the normal distribution again, and we know that 0.845 is a value between -c and c. At both extremes of the distribution we have symmetrically the following probabilities:

\( \\ \frac{1 - 0.845}{2}\)

\( \\ \frac{0.155}{2}\)

\( \\ 0.07750\)

Then, we use

\( \\ P(z<-a) = P(z>a)\)

\( \\ P(z<-1.42) = P(z>1.42)\)

Then, approximately, c = 1.42 and -c = -1.42 or \( \\ P(-1.42 < Z < 1.42) = 0.845\). Using linear interpolation or technology, we can have a value of c = 1.422 and -c = -1.422.  

Answer:

2

Step-by-step explanation:

Animal Stickers = 15

Flower stickers = 28

15/3= 5 in each row

28/4 = 7 in each row

7-5= 2

Answer:

Here Is Your Answer 150% Is Greater Than 100 But Less Than 150

Answer:

Simplify the expression.

x

+

4

Step-by-step explanation:

Answer:

.25 kilometers

Step-by-step explanation:

Divide the length value by 1000 when going from meters to kilometers

(a) We fail to reject the null hypothesis at a significance level of 0.10 since the p-value (0.0675) is greater than the significance level. (b) The calculated p-value for this test is approximately 0.0675.

To answer the questions, we need to perform a hypothesis test for a proportion.

a. To determine the conclusion, we compare the p-value to the significance level (α). If the p-value is less than α, we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.

b. To calculate the p-value, we can use the normal approximation to the binomial distribution.

Given:

H0: p ≤ 0.11 (null hypothesis)

H1: p > 0.11 (alternative hypothesis)

p = 0.2 (sample proportion)

n = 110 (sample size)

α = 0.10 (significance level)

To calculate the test statistic, we can use the formula:

\(z = \frac{p - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}\)

where p0 is the value specified in the null hypothesis (0.11 in this case).

Calculating the test statistic:

\(z = \frac{0.2 - 0.11}{\sqrt{\frac{0.11 \cdot (1 - 0.11)}{110}}}\)

\(z = \frac{0.09}{\sqrt{\frac{0.09789}{110}}}\)

z ≈ 1.493

Next, we need to find the p-value associated with this test statistic. Since the alternative hypothesis is one-sided (p > 0.11), the p-value corresponds to the area under the standard normal curve to the right of the test statistic.

Using a standard normal distribution table or calculator, we find that the p-value is approximately 0.0675.

a. Conclusion: Since the p-value (0.0675) is greater than the significance level (α = 0.10), we fail to reject the null hypothesis.

b. The p-value for this test is approximately 0.0675.

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a. We reject the null hypothesis H₀ and favor the alternative hypothesis H₁

b. The p-value from the data is 0.00001.

To answer the questions, we need to perform a hypothesis test and calculate the p-value.

a. To draw a conclusion, we compare the p-value to the significance level (α).

If the p-value is less than α, we reject the null hypothesis (H0) in favor of the alternative hypothesis (H1). If the p-value is greater than or equal to α, we fail to reject the null hypothesis.

b. To determine the p-value, we can use a one-sample proportion test.

The sample proportion (p) is calculated by dividing the number of successes (110) by the total sample size (n):

p = 110/110 = 1

To calculate the test statistic (Z-score), we use the formula:

Z = (p - p0) / √(p0 * (1 - p0) / n)

where p0 is the hypothesized proportion under the null hypothesis (0.11 in this case).

Z = (1 - 0.11) / √(0.11 * (1 - 0.11) / 110)

  = 0.89 / 0.0323

  ≈ 27.59

Using a Z-table or statistical software, we can find the p-value associated with a Z-score of 27.59. Since the p-value is extremely small (close to 0), we can conclude that the p-value is less than the significance level α = 0.10.

a. Conclusion: We reject the null hypothesis (H0) in favor of the alternative hypothesis (H1). There is evidence to suggest that the true proportion (p) is greater than 0.11.

b. The p-value for this test is very close to 0.

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For a uniform distribution random variable X, the probability that the random variable has a value between 0.6 and 2.1 is equals to 0.1875. So, option(a) is right one.

The uniform distribution is defined as a continuous probability distribution and the events are equally likely to occur. In other words in this distribution every possible outcome has an equal probability. There is a uniform distribution of variable. Let the random variable be denoted by X be uniformly distributed. The above figure shows uniform density curve for X. That is \( X \: \tilde \: \: U( 0, 8) \).

Probability density function is f(x) = \(\frac{ 1}{8} = 0.125\)

We have to determine probability that the random variable has a value between 0.6 and 2.1, P(0.6 ≤ X ≤ 2.1). So, required probability is P(0.6 ≤ X ≤ 2.1) = \(\int_{0.6}^{2.1} f(x) dx \).

\(= [ 0.125x ]_{0.6}^{2.1}\)

= 0.125 ( 2.1 - 0.6)

= 0.125 ( 1.5)

= 0.1875

Hence, required value is 0.1875.

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Complete question:

the above figure complete the question.

Using the uniform distribution density curve answer the question :

what is the probability that the random variable has a value between 0.6 and 2.1?

a) 0.1875

b) 0.4625

c) 0.3375

d) 0.2125

Answer:

D:17

Step-by-step explanation:

Answer:

D :17

Step-by-step explanation:

:)

Answer:

n < 8

{n|n are all rational numbers less than positive 8}

Step-by-step explanation:

If you convert it, it'll be:

2 × ( n - 4 ) < 8

Distribute 2:

2n - 8 < 8

2n - 8 + 8 < 8 + 8

2n < 16

2n/2 < 16/2

n < 8

Answer:

I think it's 35, because if there's 25 dark and you divide 25 by 5 you get 5, so 1/12 is equal to 5

Answer:

(0,8)

Step-by-step explanation:

Answer:

Answer: not a function

Step-by-step explanation:

the input x=5 has two outputs, y=3 and y=1

(x,y)

The area of the shaded region is 60 square units.

Area is the entire amount of space occupied by a flat (2-D) surface or an object's form. On a sheet of paper, draw a square using a pencil. It has two dimensions. The area of a form on paper is the area that it occupies.

To find the area of the shaded region, we need to subtract the area of the rectangular region that was removed from the larger rectangular region.

The area of the larger rectangle is:

11 x 8 = 88

The area of the rectangle that was removed is:

7 x 4 = 28

So, the area of the shaded region is:

88 - 28 = 60

Therefore, the area of the shaded region is 60 square units.

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John needs to make an annual beginning-of-the-year payment of approximately $369,238.68 to fund the estimated college costs of $196,000 in 10 years, given the after-tax rate of return of 8.65% compounded annually.

To compute the annual beginning-of-the-year payment necessary to fund the estimated college costs, we can use the present value of an annuity formula.

The present value of an annuity formula is given by:

P = A * [(1 - (1 + r)^(-n)) / r],

where P is the present value, A is the annual payment, r is the interest rate per period, and n is the number of periods.

In this case, John wants to accumulate $196,000 in 10 years, and the interest rate he can earn is 8.65% compounded annually. Therefore, we can substitute the given values into the formula and solve for A:

196,000 = A * [(1 - (1 + 0.0865)^(-10)) / 0.0865].

Simplifying the expression inside the brackets:

196,000 = A * (1 - 0.469091).

196,000 = A * 0.530909.

Dividing both sides by 0.530909:

A = 196,000 / 0.530909.

A ≈ 369,238.68.

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Answer:

$8.08

Step-by-step explanation:

First subtract 9.50 from 35.75 to get

24.25

Then divide 24.25 by 3 to get

Approx $8.08

Answer:

Step-by-step explanation:

1 + 2 + 4 = 7

7x = 1400

x = 1400/2 = 200

1(200) + 2(200) + 4(200) = 1400

Sand:  200 kg

Gravel:  400 kg

Cement:  800 kg

You would need 200 kg of sand, 400 kg of gravel, and 800 kg of cement to make 1400 kg of dry concrete using the ratio 1:2:4,

Let's assign variables to represent the quantities:

Let x be the quantity of sand.

Let y be the quantity of gravel.

Let z be the quantity of cement.

According to the given ratio, the quantities will be as follows:

Sand: x

Gravel: 2x (twice the amount of sand)

Cement: 4x (four times the amount of sand)

The total weight of the dry concrete is the sum of the weights of the individual components:

x + 2x + 4x = 1400 kg

Combining like terms:

7x = 1400 kg

Dividing both sides of the equation by 7:

x = 200 kg

Now that we know the quantity of sand, we can find the quantities of gravel and cement:

Gravel: 2x = 2 × 200 kg = 400 kg

Cement: 4x = 4 × 200 kg = 800 kg

Therefore, you would need 200 kg of sand, 400 kg of gravel, and 800 kg of cement.

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The inner product of two vectors A = (2, -3,0) and B = (-1,0,5) is -2 / √(13×26).

Solving the given system of equations using Gaussian elimination:

2x + 3y + z = 2 y + 5z = 20 -x+2y+3z = 13

Matrix form of the system is

[A] = [B] 2 3 1 | 2 0 5 | 20 -1 2 3 | 13

Divide row 1 by 2 and replace row 1 by the new row 1: 1 3/2 1/2 | 1

Divide row 2 by 5 and replace row 2 by the new row 2: 0 1 1 | 4

Divide row 3 by -1 and replace row 3 by the new row 3: 0 0 1 | 5

Back substitution, replace z = 5 into second equation to solve for y, y + 5(5) = 20 y = -5

Back substitution, replace z = 5 and y = -5 into the first equation to solve for x, 2x + 3(-5) + 5 = 2 2x - 15 + 5 = 2 2x = 12 x = 6

The solution is (x,y,z) = (6,-5,5)

Therefore, the solution to the given system of equations using Gaussian elimination is (x,y,z) = (6,-5,5).

The given two vectors are A = (2, -3,0) and B = = (-1,0,5). The inner product of two vectors A and B is given by

A·B = |A||B|cosθ

Given,A = (2, -3,0) and B = (-1,0,5)

Magnitude of A is |A| = √(2²+(-3)²+0²) = √13

Magnitude of B is |B| = √((-1)²+0²+5²) = √26

Dot product of A and B is A·B = 2(-1) + (-3)(0) + 0(5) = -2

Cosine of the angle between A and B is

cosθ = A·B / (|A||B|)

cosθ = -2 / (√13×√26)

cosθ = -2 / √(13×26)

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Answer:

Religion: There were temples and the worship of many gods. Animal sacrifices and complex rituals made some people feel disconnected from Hinduism. Religious beliefs were spread through trade.

Intellectual:

Technology: Gupta metal workers built a huge wrought-iron pillar. Indian doctors practiced Ayurvedic medicine. They could set bones and perform simple surgeries. They also began vaccinating people against smallpox.

Economy:

Buddhism & the Mauryans

Social:

Political: In 321 BCE, Chandragupta Maurya took over the former Magadha kingdom. It became the center of the Mauryan Empire. His government was a highly organized bureaucracy. He worked his way westward to the Indus Valley. The third emperor, Asoka, brought all of India, except the far south, into the empire. He used military strategy to rule.

Religion:

Intellectual: Buddha's teachings and the Four Noble Truths were passed down through oral tradition. Buddhists meditate to find their own truths. Asoka placed stone pillars providing moral guidance all over India (Edicts of Asoka.)

Technology:

Economy: Roads and harbors were built to help trade grow. Royal officials collected taxes.

Step-by-step explanation:

Answer:

can someone please help me with this

??

Step-by-step explanation:

Answer:

y=4

Step-by-step explanation:

I use the slope formula

y2-y1/x2-x1

4-4=0

/

-18-(-7)=11

=0

Finding the y-intercpt

I use (-7,4). Since you know the slope-intercpet form which is y=mx+b

y=mx+b

4=0(-7)+b

4=0+b ( subtract zero on both sides)

4=b

Thus, the equation of the line is y=4.

Answer:

If the missing side is long then it's 29 or if its short, then it's 6.4

Step-by-step explanation:

just do a^2 + b^2 = c^2 method

Answer:

C. 8296

Step-by-step explanation:

Answer:

c.8295

Step-by-step explanation:

8544-12 = 8532

8532-237 =8295

Answer:

1

Step-by-step explanation:

Answer:

Hi!

Step-by-step explanation:

-5 (x-3) + 3(4 - x) + 2x

Let's distribute the -5 within its parentheses.

A negative multiplied by a negative number has a positive result.

Let's distribute the 3 within its parentheses.

-5x+15+12-3x+2x

Combine like terms...

-5x-3x+2x=-6x

15+12=27

-6x+27

Both numbers are divisible by 3...

3(-2x+9)

or -3...

-3(2x-9)