6ab + 2ac + 3db+ dc needs to be factorized

Answer:

5.5 pounds

Explanation:

weight in kg = 2.5 kilograms

conversion:

1 kg ↔ 2.205 pounds

solve:

Answer:

5.5 pounds (nearest tenth)

Step-by-step explanation:

1 kilogram = 2.20462262 pounds

To determine how many pounds are in 2.5 kg, multiply by 2.5:

⇒ 2.5 kilograms = 2.20462262 × 2.5

                           = 5.5 pounds (nearest tenth)

Answer:parallel

Step-by-step explanation:

Answer

18

Step-by-step explanation:

I hope this helps

Answer:

18

Step-by-step explanation:

Use the order of operations here to solve your expression.

First do Parentheses, then Exponents, Multiplication and Division, and Addition and Subtraction. An easy way to remember this is PEMDAS.

Let's dive right in,

\(-3^{2}-7*-3+6\\-9-7*-3+6\\-9+21+6\\12+6\\18\)

In conclusion, the value of this expression is 18. Hope this helped :D

Edit: fixed an error (did 3^2 instead of -3^2)

To convert grams per tablespoon to grams per pint, we need to know the conversion factor between tablespoons and pints.

Since there are 2 tablespoons in 1 fluid ounce (oz), and there are 16 fluid ounces in 1 pint, we can calculate the conversion factor as follows:

Conversion factor = (2 tablespoons/1 fluid ounce)  (1 fluid ounce/16 fluid ounces) = 1/8

Given that the solution is 1 gram per tablespoon, we can multiply this value by the conversion factor to find the grams per pint:

Grams per pint = (1 gram/tablespoon)  (1/8)  2 pints = 0.25 grams

Therefore, there are 0.25 grams in 2 pints of the solution.

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Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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Answer:Hope fully this helps please mark me brainliest :)

Step-by-step explanation:

Answer: -2.25 = x

Step-by-step explanation:

The model represents the equation:

-1(6) = 4x + 1(3)

-6 = 4x + 3

SUBTRACT 3 FROM BOTH SIDES

-9 = 4x

DIVIDE BOTH SIDES BY 4

-2.25 = x

For a sale of $8400 made his gross pay is $373.21

In this question, we have been given Mike Lasueze is guaranteed a minimum salary of $220 per week or 5.5 percent of his total sales, whichever is greater.

We need to find his gross pay for a week in which his total sales were $8,400

weekly pay = $220

commission = 5.5% of sales

                    = 0.055 of sales

Let m be the total sale and his gross pay be represented by y.

So, we get an equation for the total/gross pay:

y = 0.055x + 220

Required is the gross pay y for x = 8400

y = 0.055(8400) + 220

y = 682

Therefore, for a sale of $8400 made his gross pay is $373.21

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The correct answer is option 2: 0.089.  the margin of error for the survey results described. In a survey of 125 adults, 30% said that they had tried acupuncture at some point in their lives.

To find the margin of error for the survey results, we can use the formula:

Margin of Error = Critical Value * Standard Error

The critical value is determined based on the desired confidence level, and the standard error is a measure of the variability in the sample data.

Assuming a 95% confidence level (which corresponds to a critical value of approximately 1.96 for a large sample), we can calculate the margin of error:

Standard Error = sqrt((p * (1 - p)) / n)

where p is the proportion of adults who said they had tried acupuncture (30% or 0.30 in decimal form), and n is the sample size (125).

Standard Error = sqrt((0.30 * (1 - 0.30)) / 125)

Standard Error = sqrt(0.21 / 125)

Standard Error ≈ 0.045

Margin of Error = 1.96 * 0.045 ≈ 0.0882

Rounding the margin of error to three decimal places, we get 0.088.

Therefore, the correct answer is option 2. 0.089.

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The measure of DE, given that Triangle ABC is similar to Triangle DEF, is 53. 09 units .

To find the measure of DE, you need to use the corresponding sides of BC and EF to find the scale factor that shows the difference in the sizes of corresponding sides.

The scale factor is:

= 31 / 8

= 3. 875

Now, since the value of the corresponding side of AB is 13.7 units, the measure of DE would be :

= 13. 7 x 3. 875

= 53. 09 units

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Answer:

13.2

Step-by-step explanation:

hope this helped

Answer:

13 3/4

Step-by-step explanation:

11 x 5/4 = 55/4 = 13 3/4

check:

13 3/4 x 4/5 = 55/4 x 4/5 = 210/20 = 11

Answer:

Step-by-step explanation:

Find either c or d first. Those are easy and everything will fall into place after those 2 are found.

c: angle c is supplementary with 115. That means that they add up to equal 180; therefore, 115° + c° = 180° so c = 65°.

d: angle d is supplementary with 70. Therefore, 70° + d° = 180° so d = 110°.

a and c are same side interior, so they are also supplementary. That means that a = 115°.

b and d are also same side interior, so they are also supplementary. That means that b = 70°.

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer:

Im pretty sure the answer is B) 349.45 in^2

Step-by-step explanation:

Hope This helps

Have A great Day

~Zero~

Answer:

H

Step-by-step explanation:

According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7

Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.

Given,

n = 66

We know that,

According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

\(k=1+log_{2} n\)

Here, n is equal to 66 and by substituting the value to the equation we get:

\(k=1+log_{2} (66)\)

k = 7.0444

k ≈ 7

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Answer:

Step-by-step explanation:

9-3/5- -3=  slope= 6/8 or 3/4

Answer: Let me help ya!

Step-by-step explanation: It's simple, Math is the science of numbers and their operations.

Have a noice day!

The cash ratio is 0.80, or 0.80:1, which means that the company has $0.80 in cash and cash equivalents for every $1 of current liabilities that it owes.

The cash ratio is a financial ratio that measures the ability of a company to pay off its current liabilities using only its cash and cash equivalents.

The formula for the cash ratio is:

Cash Ratio = (Cash and Cash Equivalents) / (Total Current Liabilities)

Using the information given in the question:

Cash and cash equivalents = $60,000

Total current liabilities = $75,000

Plugging these values into the formula:

Cash Ratio = $60,000 / $75,000 = 0.80

Therefore, the cash ratio is 0.80, or 0.80:1, which means that the company has $0.80 in cash and cash equivalents for every $1 of current liabilities that it owes.

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Answer:

numbers

Step-by-step explanation:

numbers

Answer:

The zeros are -2.5 and 2.

Step-by-step explanation:

2x^2 +x-10 = 0

2x^2 - 4x + 5x - 10 = 0

2x(x - 2) + 5(x - 2) = 0

(2x + 5)(x - 2) = 0

2x + 5 = 0 gives x = -2.5.

x - 2 = 0 gives x = 2.

Answer:

Hope It Help

Brainliest please

Answer:

3

Step-by-step explanation:

The unit rate is a rate with 1 in the denominator. The unit rate for this equation would be how much money he makes in one hour. So, to find the unit rate plugin 1 for r and solve for g. One times three (1*3) is equal to 3; therefore, that is the unit rate.

The true mean number of times college students text per day falls within this interval.

To find the 98% confidence interval for the mean number of times per day that college students text, we can use the following formula:

Where:

Z = Z-score corresponding to the desired confidence level

n = sample size

n = 144 students

Confidence Level = 98% (which corresponds to a Z-score of 2.326)

Substituting the given values into the formula, we can calculate the confidence interval:

Confidence Interval = 25.4 ± 2.326 * (16.6 / √144)

Calculating the values inside the parentheses:

16.6 / √144 = 16.6 / 12 = 1.383

Calculating the product of Z * (σ / √n):

2.326 * 1.383 = 3.219

Finally, calculating the confidence interval:

Confidence Interval = 25.4 ± 3.219

Lower Limit = 25.4 - 3.219 = 22.181

Upper Limit = 25.4 + 3.219 = 28.619

Rounded to 3 decimal places, the 98% confidence interval for the mean number of times per day that college students text is approximately (22.181, 28.619).

This means that we are 98% confident that the true mean number of times college students text per day falls within this interval.

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Answer:

О  A) 7/20

Step-by-step explanation:

3/4 = 15/20

2/5 = 8/20

Then:

15/20 - 8/20 = (15-8) / 20

= 7 / 20

...

Answer:

h= 9.473684 in.

Step-by-step explanation:

1/2(8)(15)*2+2(15h)+8h=480

120+38h=480

38h=480-120

38h=360

h= 9.473684 in.

The expression P(N) represents the probability of adults responding "never" when asked how often they typically travel on commercial flights. The value of P(N) is 0.33.

In the context of the Harris survey, the expression P(N) represents the probability of an adult responding "never" when asked about their frequency of travel on commercial flights. The letter N is used to represent the response category "never."

The value of P(N) is given as 0.33. This means that out of the total number of adults surveyed, approximately 33% of them responded with "never" when asked about their travel frequency on commercial flights.

The probability P(N) can be understood as a measure of the likelihood of selecting an individual from the survey sample who falls into the "never" category. In this case, P(N) has been determined to be 0.33, indicating that a significant proportion of the respondents in the survey do not travel on commercial flights.

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The probability which represents the likelihood of randomly selecting a card that is a heart or a 7 from a well-shuffled standard deck is 4/13.

To calculate the probability of selecting a card that is either a heart or a 7 from a standard deck of 52 cards, we need to determine the number of favorable outcomes (cards that are hearts or 7s) and the total number of possible outcomes (all the cards in the deck).

Let's break it down:

Number of favorable outcomes:

- There are 13 hearts in a deck (one for each rank).

- There are four 7s in a deck (one for each suit, including the 7 of hearts).

- However, we need to subtract one card (the 7 of hearts) from the count since it has already been counted as a heart.

So, the number of favorable outcomes is 13 + 4 - 1 = 16.

Total number of possible outcomes:

- There are 52 cards in a deck.

Therefore, the probability of selecting a card that is either a heart or a 7 is:

Probability = Number of favorable outcomes / Total number of possible outcomes

          = 16 / 52

          = 4 / 13

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The result of inverse trigonometric function are: cos, tan^-1, sin, tan^-1(5), sin^-1, tan^-1(-1), sin^-1(1), cos, sin, cos^-1(0), tan(13), sin^-1(1), cos, cos^-1.

Inverse trigonometric functions are used to determine the angle measures of a right triangle given the length of two sides. In this problem, we are matching the inverse tangent solutions to the corresponding trigonometric problems. The inverse tangent function, tan^-1(x), gives the angle whose tangent is x.

Therefore, matching tan^-1(1/6) with problem number 2 means finding the angle whose tangent is 1/6. Similarly, matching cos^-1(0.5) with problem number 10 means finding the angle whose cosine is 0.5. The other inverse trigonometric functions, such as sin^-1(x) and cos^-1(x), give the angles whose sine and cosine are x, respectively.

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the value of "k" with the condition (2, 509) is approximately 1.2611.

To find the value of "k" in the general solution y = Ke³ˣ with the condition (2, 509), we need to substitute the x and y values from the condition into the equation and solve for "k."

Let's substitute x = 2 and y = 509 into the equation:

509 = Ke³⁽²⁾

509 = Ke⁶

To solve for "k," divide both sides of the equation by e⁶:

509 / e⁶ = K

Now, we can calculate the value of k using a calculator or numerical approximation:

k ≈ 509 / 403.42879 ≈ 1.2611

Therefore, the value of "k" with the condition (2, 509) is approximately 1.2611.

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The coordinate of triangle D'O'G' after rotating the triangle DOG is (2,-1), (3,-3), (-1,-1).

Here we have to find the coordinate of D'O'G' after rotating the triangle DOG.

When the coordinate of any point gets rotated the coordinate get changes as:

(x, y) → ( -x, -y)

So by this, we get the coordinate of the triangle after rotating it.

The coordinate of triangle DOG:

D(-2,1)

O(-3,3)

G(1,1)

After rotation the coordinate of triangle D'O'G':

D'= (2, -1)

O' = ( 3, -3)

G' = ( -1, -1)

Therefore the coordinate of triangle D'O'G' is (2,-1), (3,-3), (-1,-1).

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