6+4×5-5² help please I keep on getting 16

Answer:

0

Step-by-step explanation:

The y values are the same so this line is a straight line with a slop of 0

To check:

To find the slope we use y1-y2/x1-x2

Plug in the numbers: 4-4/-9-7 = 0/-16 = 0

Answer:

8

Step-by-step explanation:

Add the exponents of the variables.

2 + 6 = 8

Degree: 8

Answer:

8

Step-by-step explanation:

The degree is the sum of all the exponents.

Hope I helped.

(Realized I was wrong and changed it)

The effect that the change in scale has on what the graph suggests is C. The differences between the groups seems much less in Graph B.

It should be noted that graph simply means a diagram that's used to show the information about a data given.

Here, the effect that the change in scale has on what the graph suggests is that the differences between the groups seems much less in Graph B.

Therefore, the correct option is C.

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A big sample that should the experimenter take from the population is 256 and if the standard deviation and the width of the confidence interval are both doubled then the sample is also 256.

In the given question,

The confidence level = 99%

Given width = 0.5

Standard deviation of resistance(\sigma)= 1.55

We have to find a big sample that should the experimenter take from the population and what happens if the standard deviation and the width of the confidence interval are both doubled.

The formula to find the a big sample that should the experimenter take from the population is

Margin of error(ME) \(=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\)

So n \(=(z_{\alpha /2}\frac{\sigma}{\text{ME}})^2\)

where n=sample size

We firstly find the value of ME and \(z_{\alpha /2}\).

Firstly finding the value of ME.

ME=Width/2

ME=0.5/2

ME=0.25

Now finding the value of \(z_{\alpha /2}\).

Te given interval is 99%=99/100=0.99

The value of \(\alpha\) =1−0.99

The value of \(\alpha\) =0.01

Then the value of \(\alpha /2\) = 0.01/2 = 0.005

From the standard table of z

\(z_{0.005}\) =2.58

Now putting in the value in formula of sample size.

n=\((2.58\times\frac{1.55}{0.25})^2\)

Simplifying

n=(3.999/0.25)^2

n=(15.996)^2

n=255.87

n≈256

Hence, the sample that the experimenter take from the population is 256.

Now we have to find the sample size if the standard deviation and the width of the confidence interval are both doubled.

The new values,

Standard deviation of resistance(\(\sigma\))= 2×1.55

Standard deviation of resistance(\(\sigma\))= 3.1

width = 2×0.5

width = 1

Now the value of ME.

ME=1/2

ME=0.5

The z value is remain same.

Now putting in the value in formula of sample size.

n=\((2.58\times\frac{3.1}{0.5})^2\)

Simplifying

n=(7.998/0.5\()^2\)

n=(15.996\()^2\)

n=255.87

n≈256

Hence, if the standard deviation and the width of the confidence interval are both doubled then the sample size is 256.

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The cοst fοr using 25 HCF οf water is $33.67.

We are given that the mοnthly cοst C is a linear functiοn οf the amοunt οf water used in HCF. Let's denοte the mοnthly cοst fοr using x HCF οf water as C(x).

We are alsο given twο data pοints: C(12) = $38.16 and C(39) = $85.41. Using these pοints, we can find the slοpe οf the linear functiοn as fοllοws:

slοpe = (change in C) / (change in x) = (85.41 - 38.16) / (39 - 12) = 47.25 / 27 ≈ 1.75

Nοw we can use the pοint-slοpe fοrm οf the equatiοn οf a line tο find the equatiοn οf the linear functiοn:

C(x) - 38.16 = 1.75(x - 12)

Simplifying this equatiοn, we get:

C(x) = 1.75x - 13.08

Therefοre, the cοst fοr using 25 HCF οf water wοuld be:

C(25) = 1.75(25) - 13.08 = $33.67

Sο the cοst fοr using 25 HCF οf water is $33.67.

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Answer:

No

Step-by-step explanation:

Answer:

0 cannot go into 4

4 can go into 8

8 cannot go into 12

Answer:

the answer should be d

Expressed as an exponent, \(2^{7}\) dollars is in the account after 32 years.

According to the exponent rule for multiplication with the same base, we simply add the powers.

\(X^{n} *x^{m} = x^{n+m}\)

\(2^{3} *2^{4} = 2^{3+4} = 2^{7}\)

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Since the training set consists of 40 observations, you would need to fill in the counts for each category based on the actual classifications made by the model using the 0.5 cutoff value.

To construct the confusion matrix for a 40-observation training set, we need to use a cutoff value of 0.5 to classify each profile observation as either interested or not interested. The confusion matrix is a tool that shows the performance of a classification model.

Let's denote the four possible outcomes as follows:
- True Positive (TP): The model correctly classified an observation as interested.
- True Negative (TN): The model correctly classified an observation as not interested.
- False Positive (FP): The model incorrectly classified an observation as interested when it was actually not interested.
- False Negative (FN): The model incorrectly classified an observation as not interested when it was actually interested.

Since we have a cutoff value of 0.5, any observation with a prediction score above or equal to 0.5 will be classified as interested, while any observation with a prediction score below 0.5 will be classified as not interested.

Based on this information, we can construct the confusion matrix:

                   Predicted Interested   Predicted Not Interested
Actually Interested       TP                           FN
Actually Not Interested    FP                           TN

Note that the values TP, TN, FP, and FN are counts of observations falling into each category.

In your case, since the training set consists of 40 observations, you would need to fill in the counts for each category based on the actual classifications made by the model using the 0.5 cutoff value.

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Answer:

Minus sign & it represents that the money is a debt

Step-by-step explanation:

Quiana took a loan of $15,234.68. This is also the same amount of money that Quiana wil return to the lender.

A minus sign (-) was inserted before the amount of money that Quiana borrowed. It represents that the money is a debt that Quiana owes and she will have to return (pay back) to the lender.

The length of the microorganism that measure 5μm is equivalent to 0.005 mm

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

To solve this problem the we have to convert the units with the given information.

1mm is equal to 1000 μm

5μm * (1 mm/1000μm) = (5*1) / 1000 = 5/1000 = 0.005 mm = 5x10^-3 mm

The length of the microorganism that measure 5μm is equivalent to 0.005 mm

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Answer:

They can buy 24 helmets.

Step-by-step explanation:

1 helmet = $15

$369 divided by $15 --> 24.6 --> 24 helmets

The answer is 3258 please give me brainliest.

The critical value  from the data for a two-tailed test with 10 independent variables and 96 observations would be ±2.306.

To determine the rejection or critical region for the given hypothesis, we need to calculate the critical value of the t-distribution. Since we are performing a test at the 0.05 level of significance, the critical value for a two-tailed test with 10 independent variables and 96 observations would be ±2.306. This means that if our calculated t-value falls outside this range, we would reject the null hypothesis and conclude that beta subscript 5 is significantly different from 0.

The t-value for beta subscript 5 can be calculated using the formula t = (b subscript 5 - 0) / (SE subscript b subscript 5), where b subscript 5 is the estimated coefficient for the fifth independent variable and SE subscript b subscript 5 is the standard error of the estimate for that coefficient. If the calculated t-value falls outside the critical region, we can reject the null hypothesis and conclude that there is a significant relationship between the fifth independent variable and the dependent variable.

In summary, to determine the rejection or critical region for the given hypothesis, we need to calculate the critical value of the t-distribution using the level of significance, number of independent variables, and number of observations. We can then use this critical value to determine if our calculated t-value falls within or outside the critical region, which will determine whether we reject or fail to reject the null hypothesis.
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Answer:

4.4

Step-by-step explanation:

Answer:

\(\frac{1}{2x-3}\)

Step-by-step explanation:

(\(\frac{f}{g}\) )(x)

= \(\frac{f(x)}{g(x)}\)

= \(\frac{x+1}{2x^2-x-3}\) ( factorise the denominator )

= \(\frac{x+1}{(2x-3)(x+1)}\) ← cancel the common factor (x + 1) on numerator/ denominator

= \(\frac{1}{2x-3}\)

Answer:

They intersect at one point or B

Step-by-step explanation:

The inequality that represents all possible values of m, the number of miles Lola can travel in the car with the remaining gasoline in the tank is m ≤ 282.

An inequality in mathematics is a relation that compares two numbers or other mathematical expressions in an unequal way. [1] The majority of the time, size comparisons between two numbers on the number line are made. Several types of inequalities are represented by a variety of notations, including:

The symbol a < b indicates that a is smaller than b.

When a > b is used, it indicates that a is bigger than b.

Let the number of miles = m.

Given that, Lola’s car can travel no more than 445 miles on one full tank of gasoline.

m ≤ 445

After filling up the tank, she traveled 163 miles in the car.

Remaining distance is:

m ≤ 445 - 163

m ≤ 282

Hence, the inequality that represents all possible values of m, the number of miles Lola can travel in the car with the remaining gasoline in the tank is m ≤ 282.

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The area of the largest rectangle is 25 square units.

It is given that the radius of the semicircle is \(4\).

It is required to inscribe a rectangle of maximum area.

Consider a rectangle of sides \(x\), \(y\) as shown in the given figure.

From the attached figure,\(AB=x\), \(OB=r\) and \(OB=\frac{y}{2}\).

Now, in the triangle OAB, apply Pythagoras' theorem as,

\((OA)^{2}=(OB)^{2}+(AB)^2\)

\(r^2=(\frac{y}{2} )^2+x^2\\\\\)

\(16=\frac{y}{4}+x^2\)

\(y^2=4(16-x^2)\)

\(y=2\sqrt{16-x^2}\)

So, the area of the rectangle will be,

Area,

\(A = 2x \times y\)

= \(2x \times \sqrt{(16 - x^2)}\)

Differentiate the area with respect to ,

\(A' = 2 \times \sqrt{(16 - x^2)} - 2x^2/(16 - x^2)\)

Differentiate the area twice as,

When\(x = 0, y = 5\) and when \(x = 5, y = 0\), \(area = 0\).

It implies that area is maximum when the value of x lies between 0 and 5.

This will occur where \(A'= 0\).

⇒ \(2 \times \sqrt{(16 - x2) }- 2x^2/(16 - x^2) = 0\)

⇒\(2 \times \sqrt{(16 - x^2)} = 2x^2/(16 - x^2)\)

On simplification, we get,

⇒ \(2 \times (16 - x^2) = 2x^2\)

⇒ \(16 - x^2 = x^2\)

⇒ \(2x^2= 16\)

⇒ \(x^2 = 16/2\)

⇒ \(x = \sqrt{8}\)

Now, \(y = \sqrt{(16 - x^2)}\) becomes

⇒\(y = \sqrt{(16 - (\sqrt8)^2)}\)

⇒ \(y = \sqrt{(16 - 8)}\)

\(y =\sqrt{8}\)

Maximum area = 2xy

\(=2(\sqrt{8)}(\sqrt{8})\)

\(=16\)

Therefore, the area of the largest rectangle is 16 square units.

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In meters he would 2.51 meters.

Answer:

b) x = 4

Explanation:

\(2x^2 - x + 10 = 38\)

collect variables

\(2x^2 - x + 10 - 38 = 0\)

simplify

\(2x^2 - x - 28 = 0\)

breakdown

\(2x^2 -8x + 7x - 28 = 0\)

factor out

\(2x(x - 4) + 7(x - 4) = 0\)

collect into groups

\((2x + 7)(x - 4) = 0\)

set to zero

\(2x + 7 = 0, x - 4 = 0\)

relocate variable

\(2x = -7, x = 4\)

final solutions

\(x = -3.5, x = 4\)

The answer is b.

To find the value of x, we need to convert this into the form of a quadratic equation.

Subtract 38 from each side.

Solve by splitting the middle term.

The system of equations that could be used to solve the problem is:

1. p + c = 10   (equation representing the total weight of the mixture)

2. 4.00p + 6.50c = 4.75(10)   (equation representing the cost of the mixture)

Let's break down the given information and use it to set up the system of equations.

1. Total weight equation:

The grocer wants to make a 10-pound mixture of peanuts and cashews. Since we are given that p represents the pounds of peanuts and c represents the pounds of cashews, we can write the equation:

p + c = 10

2. Cost equation:

The grocer wants to sell the mixture for $4.75 per pound. The cost of the peanuts is $4.00 per pound and the cost of cashews is $6.50 per pound. To calculate the total cost, we multiply the cost per pound by the weight of each component (peanuts and cashews) and sum them up. This can be expressed as:

4.00p + 6.50c = 4.75(10)

By setting up this system of equations, we can solve for the values of p and c, which represent the pounds of peanuts and cashews, respectively, that the grocer should use in order to make the 10-pound mixture.

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Answer:

I think the answer is 1/2

The value of the numerical expression (5 - 4) x 1/2 will be 0.50.

Algebra is the study of algebraic expressions, while logic is the manipulation of those concepts.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to answer the problem correctly and precisely.

The expression is given below.

⇒ (5 - 4) x 1/2

Simplify the expression, then we have

⇒ (5 - 4) x 1/2

⇒ 1 x 1/2

⇒ 1 / 2

⇒ 0.50

The value of the numerical expression (5 - 4) x 1/2 will be 0.50.

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Using integration to find the derivative of f(x), the function  f(x) = (1/π) sin(πx) - (1/x²) + 3x + 1.

To find the function f(x), we will integrate the derivative f'(x) and apply the initial condition f(1) = 3 Here are the steps:

1. Integrate f'(x) term by term:

  We integrate each term of f'(x) individually.

  ∫ cos(πx) dx = (1/π) sin(πx) + C₁, where C₁ is the constant of integration.

  ∫ (2/x³) dx = - (1/x²) + C₂, where C₂ is another constant of integration.

  ∫ 3 dx = 3x + C₃, where C₃ is another constant of integration.

  Combining these results, we have:

  F(x) = (1/π) sin(πx) - (1/x²) + 3x + C,

  where C = C₁ + C₂ + C₃ represents the constant of integration.

2. Apply the initial condition f(1) = 3:

  Substituting x = 1 into the equation for F(x), we have:

  3 = (1/π) sin(π) - (1/1²) + 3(1) + C,

  3 = 0 - 1 + 3 + C,

  3 = 2 + C.

  Therefore, C = 3 - 2 = 1.

  The final expression for \( F(x) \) is:

  F(x) = (1/π) sin(πx) - (1/x²) + 3x + 1.

So, the function f(x) is given by f(x) = (1/π) sin(πx) - (1/x²) + 3x + 1.

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Trigonometric identities are mathematical equations that involve trigonometric functions such as sine, cosine, tangent, and their reciprocals. They are true for all values of the variables involved. The following are some examples of trigonometric identities:

1. Pythagorean Identity: sin²θ + cos²θ = 1. This identity relates the values of sine and cosine of an angle with the unit circle.

2. Even-Odd Identities: sin(-θ) = -sin(θ) and cos(-θ) = cos(θ). These identities show that the sine function is an odd function and the cosine function is an even function.

3. Co-function Identities: sin(π/2 - θ) = cos(θ) and cos(π/2 - θ) = sin(θ). These identities relate the values of sine and cosine of complementary angles.

4. Double-Angle Identities: sin(2θ) = 2sin(θ)cos(θ) and cos(2θ) = cos²(θ) - sin²(θ). These identities are used to simplify trigonometric expressions that involve double angles.

5. Half-Angle Identities: sin(θ/2) = ±√[(1-cos(θ))/2] and cos(θ/2) = ±√[(1+cos(θ))/2]. These identities are used to find the values of sine and cosine of half-angles.

All of the above-mentioned equations are trigonometric identities. They are fundamental to solving trigonometric problems and are used extensively in mathematics, engineering, and science.
To determine which of the following are trigonometric identities, you should compare each given equation to known trigonometric identities. These identities are mathematical relationships between the trigonometric functions, such as sine, cosine, and tangent. Here's a step-by-step process:

1. Write down the known trigonometric identities, such as the Pythagorean identities: sin^2(x) + cos^2(x) = 1, 1 + tan^2(x) = sec^2(x), and 1 + cot^2(x) = csc^2(x).
2. Compare each equation in the list to these known identities.
3. Check if the given equations can be simplified or manipulated to match the known identities.
4. Mark the equations that match the known identities as trigonometric identities.

By following this process, you can identify which equations in the list are trigonometric identities.

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Answer:

28/7=4 and 60/12=5

Step-by-step explanation:

Answer:

\(\frac{28}{7} = \frac{4}{1} \\\\\frac{60}{12} = \frac{5}{1}\)

Explanation: 28 is divisible by 7, when multiplied by 4.

                    60 is divisible by 12, when multiplied by 5.

Answer:

It is A and D

The city streets are overcrowded with cars

There is a lot of noise pollution

Step-by-step explanation:

The correct answers are the city streets are overcrowded with cars and there is a lot of noise pollution.

A government is the system or group of people governing an organized community, generally a state

The following statements represent possible problems:

The city streets are overcrowded with cars.

The noise level is raising.

And the following statements are possible solutions:

More money from the city government should go to public transportation.

A subway system should be built.

People should be encouraged to carpool to work and school.

Therefore, the correct answers are the city streets are overcrowded with cars and there is a lot of noise pollution.

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The enhanced entity-relationship (EER) diagram for AutoPlanet's information system includes entities such as Dealership, City, Employee, Dependent, Category, Training Program, Mechanic, Car, Customer, and more. The diagram also includes attributes for each entity, capturing relevant information like addresses, phone numbers, employee numbers, and sales commission percentages.

The enhanced entity-relationship (EER) diagram for AutoPlanet's information system captures the entities and relationships involved in the system. The main entities in the diagram are Dealership, City, Employee, Dependent, Category, Training Program, Mechanic, Car, Customer, and Salesperson.

The Dealership entity is identified by a unique dealership number and stores information such as address, phone number, and the name of the general manager. The City entity is identified by state and city names and stores data about the mayor, city hall address, and telephone number.

The Employee entity has attributes like employee number, name, home address, and cell phone number. Employees can have dependents, represented by the Dependent entity, which stores their names, ages, and gender. The Category entity represents the different employee categories, such as salesperson and mechanic.

The relationships between entities include Employee-Dependent (one-to-many), Employee-Category (many-to-many), Salesperson-Car (many-to-many), Mechanic-Training Program (many-to-many), and more.

The Car entity is identified by its vehicle identification number (VIN) and includes attributes for model and year of manufacture. The Customer entity is identified by a unique customer number and stores information like name, address, and telephone number. The Salesperson entity is linked to the Car and Customer entities, capturing data about which salesperson sold a car to a customer, along with the sale date and selling price.

The EER diagram provides a visual representation of the entities, relationships, and attributes in AutoPlanet's information system, allowing for a better understanding of the system's structure and data flow.

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Therefore, the next number in the sequence is 43.

To find the next number in the sequence, let's examine the differences between consecutive numbers:

16 - 9 = 7

24 - 16 = 8

33 - 24 = 9

We can observe that the differences between consecutive numbers are increasing by 1 each time. Therefore, it suggests that the pattern in the sequence is adding consecutive integers to the previous number.

To continue the sequence, we add 10 to the last number in the sequence:

33 + 10 = 43

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The 45% represents a descriptive statistic. Descriptive statistics are used to describe or summarize characteristics of a sample or population. In this case, the percentage of students living in the dormitories (45%) is a descriptive statistic that provides information about the sample of 800 students.

Descriptive statistics involve organizing, summarizing, and presenting data in a meaningful way. They are used to describe various aspects of a dataset, such as central tendency (mean, median, mode) and dispersion (variance, standard deviation). In this case, the percentage of students living in the dormitories (45%) is a descriptive statistic that describes the proportion of students in the sample who live in the dormitories.

Statistical inference, on the other hand, involves making conclusions or predictions about a population based on data from a sample. It uses techniques such as hypothesis testing and confidence intervals to make inferences about the population parameters.

In summary, the 45% represents a descriptive statistic as it provides information about the proportion of students living in the dormitories based on the sample of 800 students. It is not an example of statistical inference, a population, or a sample.

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