6(33 - w) = 90 solve for w entre your answer in the box w =

If the engineers are planning a car design in which only 25 of adults fit , then this sitting height is 38.68 inches .

To find the sitting height for the tallest 2% of adults, we first find z-score for upper 2% of standard Normal Distribution ;

we know ; that z = (x - μ)/σ ;

where z is = z core, x is = sitting height , μ is = mean sitting height, and

σ is = standard deviation of sitting heights.

From the normal table : Upper 2% of standard normal distribution have a z-score of approximately 2.05 ;

So , 2.05 = (x - 35.4)/1.6 ;

Multiplying both sides by 1.6, we get ;

⇒ 3.28 = x - 35.4

On adding 35.4 to both sides, we get:

⇒ x = 38.68 ;

Therefore, the sitting height for the tallest 2% of adults is 38.68 inches .

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Answer:

A.quadratic

Step-by-step explanation:

3x+x^2+4

Put in order from largest to smallest power of x

x^2 +3x+4

The highest power is 2

A.quadratic   highest power 2

B. quartic   highest power 4

C. linear  highest power 1

D. cubic highest power 3

Answer:

when the imposter is sus

This is because a larger sample size (n) and a greater sum of squares (SS) for the difference scores generally lead to a more significant t statistic.

The repeated-measures t statistic measures the difference between two sets of scores from the same group of individuals, so the larger the difference between the two sets of scores, the more likely it is to produce a significant t statistic. This means that the set of data with the largest SS (sum of squares) for the difference scores is most likely to produce a significant t statistic. Therefore, the answer is d. n = 30 and SS = 100 for the difference scores.
If other factors are held constant, the set of data most likely to produce a significant value for the repeated-measures t statistic is:
d. n = 30 and SS = 100 for the difference scores

This is because a larger sample size (n) and a greater sum of squares (SS) for the difference scores generally lead to a more significant t statistic.

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If Leona and Fred are friendly competitors in high school. the probability that the scores differ by 5 or more points in either direction is: 0.0771.

Let F = Fred

Let L= Leona

In a situation where F and L are respective score , F -  L is has this distribution N(0, √2² + 2²)

Now let find the Probability

P(Fred score 5 point more than Leona) + P(Leona score 5 point more than Fred)

= P(F-L>5) +P(L-F>5) = P(Z> 5-0/√8) +  P(Z> 0-5/√8)

P(Z>1.7678)+ =P(Z< -1.7678)

=2P(Z>1.7678)

=2(0.03854)

=0.0771

Therefore the probability is 0.0771.

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The Solution set for the inequality x - \(6\frac{1}{3}\) ≤ \(1\frac{1}{2}\)  is {x | x ∈ R, x ≤ \(7\frac{5}{6}\)}  , the correct option is (a) .

In the question ,

the inequality is given as

x - \(6\frac{1}{3}\) ≤ \(1\frac{1}{2}\)

we first convert the complex fractions into normal fractions ,

\(6\frac{1}{3}\) = (6 * 3 + 1)/3 = 19/3

and  \(1\frac{1}{2}\) = (1 * 2 + 1)/2 = 3/2

rewriting the given inequality , we get

x - 19/3 ≤ 3/2

adding 19/3 to both sides of the equation ,

we get ,

x ≤ 19/3 + 3/2

Taking LCM of 3 and 2 as 6 and

Simplifying further ,

we get ,

x ≤ 38/6 + 9/6

x ≤ 47/6

x ≤ \(7\frac{5}{6}\)

Therefore , the solution set is {x | x ∈ R, x ≤ \(7\frac{5}{6}\)}  .

The given question is incomplete , the complete question is

Given: x - \(6\frac{1}{3}\) ≤ \(1\frac{1}{2}\) . Choose the solution set.

(a) {x | x ∈ R, x ≤ \(7\frac{5}{6}\)}

(b) {x | x ∈ R, x ≤ \(7\frac{2}{5}\)}

(c) {x | x ∈ R, x ≤ \(5\frac{1}{6}\)}

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Answer:

A=61, B=74

Step-by-step explanation:

Because all the angles in a triangle add up to 180:

(2x+4) + (2x-9) + x = 180

If you solve that for x, you will get that x=35. Now you just plug in x to the angles A and B.

Answer:

The data should be from 1 to 2 with tick marks every 10th

Step-by-step explanation:

(a)Probability of landing on A = 3/4 = 0.75 or 75%.

(b)The probability of the spinner landing on A or B is 100%, which means it is certain that the spinner will land on either A or B.

In part (a), we are asked to find the probability that the spinner will land on the letter A. The spinner has 4 sides and 3 of those sides have the letter A on them, so the probability of landing on A is 3/4. We can also express this probability as a percentage by multiplying 3/4 by 100%, which gives us 75%. Therefore, there is a 75% chance that the spinner will land on the letter A.

In part (b), we are asked to find the probability that the spinner will land on A or B. There are 4 sides on the spinner and 3 of them have the letter A, while only 1 of them has the letter B. To find the probability of landing on A or B, we add the number of sides with A or B, which gives us 3 + 1 = 4. Then, we divide this by the total number of sides on the spinner, which is 4. This gives us a probability of 4/4 or 1. We can also express this probability as a percentage by multiplying 1 by 100%, which gives us 100%. Therefore, there is a 100% chance that the spinner will land on either A or B.

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complete question:

Jenny spins a fair 4-sided spinner with the letters A B A and A on it

a) What is the probability that the spinner will land on A?

b) What is the probability that the spinner will land on A or B?​

Answer:

there's nothing there you have to insert a file

Step-by-step explanation:

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Here we go ~

Let's use Trigonometric ratios to find p :

\(\qquad \sf  \dashrightarrow \: \cos(60) = \cfrac{6}{p} \)

\(\qquad \sf  \dashrightarrow \: \dfrac{1}{2} = \dfrac{6}{p} \)

\(\qquad \sf  \dashrightarrow \: p = 6 \times 2\)

\(\qquad \sf  \dashrightarrow \: p = 12 \: \: units\)

The answer is Option C. If the scatterplot of x = hundreds of papers and y = total cost did not show a perfect linear relationship.

The conditions that must be satisfied in order to perform inference for regression of y on x are:

I. The population of values of the independent variable (x) must be normally distributed.

III. There is a linear relationship between x and the mean value of y for each value of x.

So, the correct answer is C. I and III.

In the given options, violating condition III would result in a violation of the conditions of inference for the above computer output. If the scatterplot of x = hundreds of papers and y = total cost does not show a perfect linear relationship, it means there is a deviation from the assumption of a linear relationship between x and the mean value of y for each value of x.

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Answer:

Step-by-step explanation:

According to the graph, CD is 5 - 1 = 4 units long.

Rotation doesn't change the length of the segment, so C'D' = CD = 4 units.

Correct choice is A.

Length of CD

Distance between (1,-3) and (5,-3)

Rotation means no change in size

So C'D' is also 4units

The surfaces described by the given vector equations are:

1.The surface is a hyperbolic paraboloid.

2.The surface is a part of a cylinder with radius 3 and axis parallel to the y-axis.

3.The surface is a plane parallel to the xy-plane and shifted upwards by 1 unit.

4.The surface is a twisted cylinder along the y-axis.

A vector equation of a surface in three-dimensional space is a function that maps a pair of parameters, say u and v, to a three-dimensional point in space (x, y, z) represented as a vector. The vector equation can be written in the form of r(u, v) = <x(u, v), y(u, v), z(u, v)>.

In general, there are different ways to represent the same surface using vector equations. For example, the surface of a sphere of radius r centered at the origin can be represented by the vector equation r(u, v) = <r sin(u) cos(v), r sin(u) sin(v), r cos(u)>, where u is the polar angle (measured from the positive z-axis) and v is the azimuthal angle (measured from the positive x-axis).

Vector equations can be useful in studying the geometry and properties of surfaces, such as determining their tangent planes, normal vectors, curvature, and surface area. They can also be used to parametrize surfaces for numerical calculations and simulations.

The surfaces described by the given vector equations are:

1.The surface is a hyperbolic paraboloid.

2.The surface is a part of a cylinder with radius 3 and axis parallel to the y-axis.

3.The surface is a plane parallel to the xy-plane and shifted upwards by 1 unit.

4.The surface is a twisted cylinder along the y-axis.

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With regard to all the different sources of caffeine, it really is estimated that 80 percent of Americans frequently consume caffeine in some way, with an average daily intake of 200–250 mg.

A methylxanthine class stimulant, caffeine stimulates the central nervous system. It is employed as a cognitive enhancer to improve alertness and attentional function. In order to increase the release of the neurotransmitters acetylcholine, caffeine works by preventing adenosine from binding to the adenosine A1 receptor.

Because caffeine is a stimulant, it makes your nervous system and brain work harder. Additionally, it causes a greater flow of hormones like cortisol and adrenaline throughout the body. Caffeine can help you feel energized and alert in small doses.

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I understand that the question you are looking for is:

Considering all the various sources of caffeine, it is estimated that 80 percent of Americans regularly use caffeine in some form, and that the average intake is ______ per day.

Use dot products to express y as a linear combination of the vectors in S.

To represent y as a linear combination of the vectors in S using dot products, we calculate the dot product of y with each vector in S and divide it by the squared length of the corresponding vector. The coefficients obtained from the dot products form the linear combination. The steps for each exercise are as follows:

Let S = {7, 20} and y = {-1, 0, 9}.

Dot product with the first vector: (-1)⋅7 = -7

Dot product with the second vector: 0⋅20 = 0

y = (-7/149)⋅7 + (0/400)⋅20 = (-7/149)⋅7

Let S = {3, 1, 2, 0, 9} and y = {5, 5, -1}.

Dot product with the first vector: 5⋅3 = 15

Dot product with the second vector: 5⋅1 = 5

Dot product with the third vector: -1⋅2 = -2

Dot product with the fourth vector: 0⋅0 = 0

Dot product with the fifth vector: 9⋅9 = 81

y = (15/19)⋅3 + (5/26)⋅1 + (-2/14)⋅2 + (0/5)⋅0 + (81/186)⋅9

Let S = {-1, 0} and y = {1, 0}.

Dot product with the first vector: 1⋅(-1) = -1

Dot product with the second vector: 0⋅0 = 0

y = (-1/1)⋅(-1) + (0/1)⋅0 = -1

Let S = {5, 5, -1, -1} and y = {2, 1}.

Dot product with the first vector: 2⋅5 = 10

Dot product with the second vector: 1⋅5 = 5

Dot product with the third vector: 2⋅(-1) = -2

Dot product with the fourth vector: 1⋅(-1) = -1

y = (10/50)⋅5 + (5/50)⋅5 + (-2/2)⋅(-1) + (-1/2)⋅(-1)

Let S = {A, B} and v = {p}.

Dot product with the first vector: p⋅A

Dot product with the second vector: p⋅B

y = (dot product with A)⋅A + (dot product with B)⋅B

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Answer:

35

Step-by-step explanation:

Step 1:

6z ÷ 7 = - 30

Step 2:

6z = - 210

Answer:

z = 35

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Answer:

Distance = \(\sqrt{(1-5)^{2} + (5-2)^{2} }\) units

               = \(\sqrt{(-4)^{2} + (3)^{2} }\) units

               =\(\sqrt{25}\) units

               = 5 units

9514 1404 393

Answer:

  (a) 6² +3² +1² +1² = 47

  (b) 5² +4² +2² +1² +1² = 47

  (c) 3³ +4² +2² = 47

Step-by-step explanation:

It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.

The approach where a cube is required can work the same way.

(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1

__

(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...

__

(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2

Answer:

2, 11, 38

Step-by-step explanation:

Multiply by 3 and then add 5 each time

1st term : 2

2nd term : 2*3 + 5 = 6 + 5 = 11

3rd term : 11*3 + 5 = 33 + 5 = 38

The bearing of A from B would be 247 degrees.

The bearing of B from A would be 067 degrees.

When looking for the bearing of a place from another place, you should draw a straight line North from the original place. Then, draw a straight line to the place that you want to get to.

To find the bearing, you start from the North line and go clockwise till you get to the line connecting to the destination. The degree measure would be the bearing.

The bearing of A from B would therefore be 247 degrees and the bearing of B from A would be 067 degrees as shown by the degree measure of 67 degrees from the N line to the line connecting to B.

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Answer:

5a.

Step-by-step explanation:

The HCF is short for Highest Common Factor.

Write the 2 expressions in factor form:

5a = 5 * a

15a = 5 * 3 + a

Note that 5 and a are common to both sets of factors, so the HCF = 5a.

d)An error because d cannot be negative.

According to the data, effect sizes such as Cohen's d typically range from 0 to positive values, and negative values do not make sense in this context. Therefore, an effect size of d = -63 is likely an error or a typo.

Assuming that the correct effect size is a positive value, the magnitude of the effect size can be described as follows based on Cohen's convention:

However, it's important to note that the interpretation of effect sizes also depends on the context and the specific field of study.

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Answer:

1) Pr(all three) = 0.064

2) Pr(none) = 0.216

3) Independent event

Step-by-step explanation:

Let Probability of homes constructed in the Quail Creek area with a security system = Pr (security)

Where Pr = probability

This is a binomial distribution problem. There ate only two outcomes in this distribution: a success and a failure

Where p = success, q = failure

For n trials,

Pr(X = x) = n!/[(n-x)!x!] × p^x × q^(n-x)

Pr (security) = 40% = 0.4

p = 0.4

q = 1-p = 1-0.4 = 0.6

Numbers selected at random = n = 3

See attachment for more details on the workings.

1) Probability all three of the selected homes have a security system = Pr(all three)

Pr(all three) = 1× (0.4)³ (0.6)^0 = 0.4³

= 0.4×0.4×0.4

Pr(all three) = 0.064

2) Probability none of the three selected homes have a security system

= Pr(none)

Pr(none) = 1 × (0.4)^0 × (0.6)³

= 0.6³ = 0.6×0.6×0.6

Pr(none) = 0.216

3) The events were assumed to be independent as the selection of one house doesn't affect the outcome of the selection of another.

Answer:

Perimeter: 14a+2b

Tickets:7x+6

Step-by-step explanation:

Perimeter: Add all the functions together

Tickets: Subtract 15x+1 by 8x-5.

Answer:

14.8 or round up to 15 burgers

Step-by-step explanation: