6. Find the value of x:

Answer:

u > 7

Step-by-step explanation:

-2u -6 < -20  Add 6 to both sides

-2u - 6 + 6 < -20 + 6

-2u < -14  Divide both sides by -2.  When you multiply or divide both sides by a negative number, you must flig the sign.

\(\frac{-2u}{-2}\) > \(\frac{-14}{-2}\)

u > 7

Helping in the name of Jesus.

The answer is:

u > 7

In-depth explanation:

You haven't told me what the values of u are, but I'll solve the equation for u.

Add 6 on each side:

\(\bf{-2u-6 < -20}\)

\(\bf{-2u < -14}\)

Divide each side by -1 and reverse the sign:

\(\bf{2u > 14}\)

Now divide each side by 2

\(\bf{u > 7}\)

Answer:

One proportion is 15 songs / 2.5 hours = 18 songs / h hours.

ok I'll try to answer

first the given 15/2.5=18/h

so the second hour is missing so we have to multiply cross then the result will be

15h=45

divide 15 for 15 and we got h

again divide 45 for 15

[h=3]

The two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let \($&\overline{A B} \cong \overline{D E} \\\) and \($&\overline{A C} \cong \overline{D F}\)

Angle between \($\overline{A B}$\) and \($\overline{A C}$\) exists \($\angle A$\).

Angle between \($\overline{D E}$\) and \($\overline{D F}$\) exists \($\angle D$\).

Therefore, \($\triangle A B C \cong \triangle D E F$\) by SAS, if \($\angle A \cong \angle D$$\).

Given:

\($&\overline{A B} \cong \overline{D E} \\\) and

\($&\overline{A C} \cong \overline{D F}\)

According to the SAS congruence property, two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let \($&\overline{A B} \cong \overline{D E} \\\) and \($&\overline{A C} \cong \overline{D F}\)

Angle between \($\overline{A B}$\) and \($\overline{A C}$\) exists \($\angle A$\).

Angle between \($\overline{D E}$\) and \($\overline{D F}$\) exists \($\angle D$\).

Therefore, \($\triangle A B C \cong \triangle D E F$\) by SAS, if \($\angle A \cong \angle D$$\).

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X = 1 4 5 6

Y = 20 8 4 0

From the function: Y = 24 - 4X

If X = 1, then Y = 24 - 4(1) = 20

If X = 4, then Y = 24 - 4(4) = 8

If X = 5, then Y = 24 - 4(5) = 4

If X = 6, then Y = 24 - 4(6) = 0

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Answer:

what are c and d?

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

john earns more than don

Answer:

x = 1.125

Step-by-step explanation:

Answer:

x + 1 3/4 = 2 7/8

x + (1 + 3/4) = (2 + 7/8)

8x = 9

x = 9 /8  = 1.125

Step-by-step explanation:

Step-by-step explanation:

Question A-

To find: Greatest number of toys that Paul can buy with $2760

We can simply divide the total money by the toy's price-

total money/toy's price

= 2760 / 9

= 306.6

= 306 (since we cannot buy .6 of a toy we round it off to the previous number)

Question B-

To find: Amount of money left after buying the toys

The remanider of 2760/9 will give us the money left with Paul

= $6

Answer:

Angle B = 29.74

Step-by-step explanation:

Tan(x)=opp/adj

Tan(x)=4/7

x=\(Tan^{-1} (\frac{4}{7} )\)

x=29.74

Answer:

-32

Step-by-step explanation:

Let the number be x.

\(2(x+8)=-48 \\ \\ x+8=-24 \\ \\ x=-32\)

The calculated possible value in the unit for M is 2 units

From the question, we have the following parameters that can be used in our computation:

The composite figure

The volume of the figure is the sum of the volumes of the individual figures

Using the above as a guide, we have the following:

Volume = 3 * 1 * 5 + m * 1 * 4

This gives

Volume = 15 + 4m

Karen calculated the total volume as 23 cubic units.

So, we have

15 + 4m = 23

Evaluate

4m = 8

Divide by 4

m = 2

Hence, a possible value of m is 2

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Step 1: Isolate the Sin Operator

\(8 sin(\frac{\pi }{6} x)=2\\sin(\frac{\pi }{6} x)=0.25\\\\\)

Step 2: Use Inverse Sin(arcsin) to isolate the term with the x variable

Note that since trig functions have 2 general solutions, this will give us one of our general solutions.

\(x=\frac{6 arcsin(0.25)}{\pi } =0.48\)

x₁= 0.48

Solving for x₂

Use the period identity for Sin Functions

\(sin(x)=sin(\pi -x)\)

X in this case is arcsin(0.25)

\(\frac{\pi }{6} x=\pi -arcsin(0.25) = 5.52\)

So our two general solutions are 0.48 and 5.52

Step 3: Period

Trig Functions have periodic behavior and this function period is

\(\frac{2\pi }{1} (\frac{6}{\pi } )= 12\)

So our general solutions are

0.48±12k, where k is an integer

5.52±12k, where k is an integer

Let k=1, and we get our next set of solutions:

12.48 and 17.52

So our answer is 0.48,5.52,12.48,17.52

Answer:

3 times x plus seven

Step-by-step explanation:

k

Answer:

3(x + 5y) - 2(x + y)

3x + 15y - 2x - 2y

x + 13y

(3x + 15y) + (-2x + -2y)

x + 13y

Set A has a peak at 5. It is also skewed to the right. The center is 5.

Set B also has a peak at 5. Is relatively symmetrical. The center is also 5.

(Sorry about those circle in the back of my picture)

Answer: The function would have a minimum value because the least you will ever have is 0$. It cannot go below 0, so that is the minimum. However, depending on how much time has passed, the maximum amount of money you have can change. It can always go up more, so there is no set maximum.

Step-by-step explanation:

Answer: 1.6

Step-by-step explanation:

each golf is 1.6 ounces and you 20 golf balls in order to reach 32 ounces

Answer:

shown below

Step-by-step explanation:

golf balls per ounce = 5/8 or 0.625

ounces per gold ball = 8/5 or 1.6

Using the concept of word problems and quadratic equation it will take 1 year until the sum of square of their ages be 45.

Word problems are mathematical problems that are delivered in ordinary words, instead of mathematical symbols.

Part of the problem with dealing with word problems that they first need to be translated into mathematical equations, and then the equations need to be solved.In this problem;

let x represent the number of years from now when the sum of square of their respective age will be

45.(x + 2)² + (x + 5)² = 45

Expanding the brackets;

x² + 4x + 4 + x² + 10x + 25 = 45

2x² + 14x + 29 = 45

2x² + 14x + 29 - 45 = 0

2x² + 14x - 16 = 0

Solving the quadratic equation for x;

x = 1, x = -8

Taking the positive value, the value of x is 1

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The decibel measurement for the quiet room is 54 dB.

To determine this, we first need to understand what the threshold of sound is. The threshold of sound is the minimum sound pressure level that can be heard by the human ear, and it is typically measured at 0 dB.

Next, we can use the formula for decibel measurement:

dB = 10 log (I/I0)

where I is the intensity of the sound in the quiet room, and I0 is the threshold of sound.

Since the noise in the quiet room is 500 times as intense as the threshold of sound, we can plug in the values into the formula:

dB = 10 log (500/1)

dB = 10 log (500)

dB = 10 * 2.7

dB = 27

Therefore, the decibel measurement for the quiet room is 27 dB. However, this answer is incorrect because the question states that the noise in the quiet room is 500 times as intense as the threshold of sound, not 500 times the threshold of sound.

To correct this mistake, we need to use the formula for decibel measurement with the correct values:

dB = 10 log (500 * I0/I0)

dB = 10 log (500)

dB = 10 * 2.7

dB = 27

Therefore, the decibel measurement for the quiet room is 27 dB + 27 dB = 54 dB.

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Answer:

r = −0.08, weak negative correlation

 r = −0.83, strong negative correlation

 r = 0.96, strong positive correlation

r = 0.06, weak positive correlation  

Answer: Half of them are even and half of them are odd.

Step-by-step explanation:

The even numbers are 6, 12, 18, 24, and 30. An even number is defined as a number that is divisible by 2, meaning it has no remainder when divided by 2. For example, 6 divided by 2 equals 3 with no remainder, so 6 is even.

The odd numbers are 3, 9, 15, 21, and 27. An odd number is defined as a number that is not divisible by 2, meaning it has a remainder of 1 when divided by 2. For example, 9 divided by 2 equals 4 with a remainder of 1, so 9 is odd.

Therefore, out of the given numbers, half of them are even and half of them are odd.

________________________________________________________

The pοlynοmial functiοn with a fifth degree, 2 as a zerο οf multiplicity 4, −3 as the οnly οther zerο, and a leading cοefficient οf 2 is:

\(f(x) = 2(x-2)^4(x+3) = 2x^5 - 32x^4 + 192x^3 - 384x^2 + 216x + 1080\)

What is Polynomial Function?

A pοlynοmial functiοn is a mathematical functiοn οf the fοrm \(f(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_1 x + a_0\), where the coefficients\(a_n, a_{n-1}, ..., a_1, a_0\) are constants, x is the variable, and n is a non-negative integer. It is a functiοn that can be graphed as a smοοth curve with nο breaks οr jumps.

If 2 is a zerο οf multiplicity 4, then the pοlynοmial functiοn must have the factοr\((x-2)^4\).

If −3 is the οnly οther zerο, then the pοlynοmial functiοn must alsο have the factοr (x+3).

The pοlynοmial functiοn with these properties and a leading cοefficient οf 2 can be written as:

\(f(x) = 2(x-2)^4(x+3)\)

Expanding this polynomial gives:

\(f(x) = 2x^5 - 32x^4 + 192x^3 - 384x^2 + 216x + 1080\)

Therefore, the polynomial function with a fifth-degree, 2 as a zero of multiplicity 4, −3 as the only other zero, and a leading coefficient of 2 is:

\(f(x) = 2(x-2)^4(x+3) = 2x^5 - 32x^4 + 192x^3 - 384x^2 + 216x + 1080\)

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Answer:

0x+-3y=...     and 1x+5y=...     or 0x-3y=...  and 1x-5y=...

Step-by-step explanation:

there you go both equations in plus form and minus form hope this helps

Answer:

y = -2x - 3

Step-by-step explanation:

By using the slope formula, you can find the 'a' value, -2. The y-intercept of the line is -3 so that is the 'b' value. Plug those values into the equation y = mx + b and you'll get y = -2x - 3.

Answer:

The answer is (B) 1/2=12

Answer:

Ughhhhhhhhh harder daddy

Step-by-step explanation:

First you let him put the penis in the hole

Answer:

2q+6

Step-by-step explanation:

So basically, you would do this.

-2q-6+6q+12-2q

Next

-4q+6q = 2q

12-6=6

2q+6

Answer:

2q + 6

Step-by-step explanation:

To simplify, we will use the distributive property.

-(2q + 6) simplifies to -2q - 6 (In this case we are distributing the - sign or -1)

3(2q + 4) simplifies to 6q + 12

So if we recombine: -2q - 6 + 6q + 12 - 2q

Let's combine like terms (q's with q's, numbers with numbers)

-2q + -2q + 6q = 2q

-6 + 12 = 6

So if we recombine: 2q + 6

The class of the equation and the cross section equation are;

The equation is a hyperboloid of two sheets

The cross sections are;

Equation at z = 0 is; y²/8 - x²/8 = 1

Equation at y = -4 is; x²/8 + z² = 1

Equation at y = 0 is; x²/8 + z² = -1

Equation at y = 4 is; x²/8 + z² = 1

Equation at x = 0 is; y²/8 - z² = 1

An equation is a mathematical statement which indicates the equivalence two expressions by joining them with the '=' sign.

The equation can be presented as follows;

y² = x² + 8·z² + 8

y² - x² - 8·z² = 8

y²/8 - x²/8 - z² = 1

The above equation is the equation of an hyperboloid of two sheets, where;

a² = 8, b² = 1, and c² = 8

Please find attached the diagram of the surface, created with an online 3D graphing tool.

The equation for the cross section at z = 0, can be obtained by plugging in z = 0, into the equation as follows;

y²/8 - x²/8 - 0 = 1

y²/8 - x²/8 = 1

The above equation is the equation of an hyperbola in the xy plane

The equation for the cross section at y = -4, can be obtained by plugging in y = -4, into the equation as follows;

4²/8 - x²/8 - z² = 1

- x²/8 - z² = 1 - 4²/8 = -1

- x²/8 - z² = -1

x²/8 + z² = 1

The above is an equation of an ellipse in the xz plane

The equation for the cross section at y = 0, can be obtained by plugging in y = 0, into the equation as follows;

0²/8 - x²/8 - z² = 1

- x²/8 - z² = 1

Therefore; x²/8 + z² = -1

The equation for the cross section at y = 4, can be obtained by plugging in y = 4, into the equation as follows;

4²/8 - x²/8 - z² = 1

- x²/8 - z² = 1 - 2 = -1

x²/8 + z² = 1

The above equation is the equation of an ellipse in the xz plane

The equation for the cross section at x = 0, can be obtained by plugging in x = 0, into the equation as follows;

y²/8 - 0²/8 - z² = 1

y²/8 - z² = 1

The equation is the equation of an hyperbola in the yz plane

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The total cash due at signing is $3,700 at the local dealership..

The addition operation in mathematics adds values on each side of the operator.

For example 4 + 2 = 6

The total cash due is calculated as:

Down payment: $1,800

Security deposit: $400

Acquisition fee: $300

Total: $1,800 + $400 + $300

Apply the addition operation, and we get

= $3,700

Thus, the total cash due at signing is $3,700.

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Answer:

improper fraction- 15/4

Mixed number-  3  3/4

Decimal- 3.75

Step-by-step explanation:

use K.C.F (Keep Change Flip)

Answer:

55 boxes

Step-by-step explanation:

The linear equation provided is: \(y=78x+8840\) and since we want to check if we can carry 60 boxes, we just need to weight by substituting in "60" as x and then comparing that to the limit of 13200 pounds.

\(y = 78(60)+8840\\\\y=4680+8840\\\\y=13,520\)

This of course is over the limit of 13200 pounds but we can set up an inequality and solve for "x"

\(78x+8840 < 13200\)

From here we subtract 8840 from both sides

\(78x < 4,360\)

Now divide both sides by 78

\(x < 55.89\)

now of course we can't have 55.89 boxes, so we want to round down as we can't have 56 boxes as that would go over the limit, but we can have 55 boxes.