-5X-3=42
help meee plss i don’t understand on how to solve this

Answer:

can you expand on your question?

Step-by-step explanation:

seen 2 pretty best friends

ⓘ

Step-by-step explanation:

8 bc

Answer:

y = 8

x = 18

Step-by-step explanation:

(x + y = 26) x2 -1

2x+3y = 60 -2

2x+2y = 52 -1

2x+3y = 60 -2

Subtracting equation 2 from equation 1

= -y = -8

= y = 8

_____________________________________________________

2x+3y = 60

= 2x+3x8 = 60

= 2x+24 = 60

= 2x = 60-24

= 2x = 36

= x = 36/2

= x = 18  

Please attached a diagram drawn with MS Word based on the question parameters, and from a diagram from a similar question.

The length of the rectangle that contains 10 identical squares and has a width of 15 centimeters is 21 centimeters

A square is a quadrilateral that has four sides of the same length and the the four interior angles are each equal to 90°.

Some parts of the question appear missing, please find attached the design of a rectangle based on a similar GCSE question online. The width of the rectangle = 15 cm

The number of squares = 10

The number of squares that make up the width from the drawing = 5

The side length of the square is therefore; 15 cm ÷ 5 = 3 cm

The number of squares that make up the length of the rectangle = 7

The length of the rectangle is therefore, L = 7 × 3 cm = 21 cm

The length of the rectangle = 21 centimeters

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Given :

Collection in third week, C = $25,992,412.50 .

Average ticket price, T = $8.35 .

To Find :

Number of people who saw movie in  week.

Solution :

Let, number of people are x.

\(\text{Number of people }=\dfrac{\text{Total amount }}{\text{Average price}}\\\\= \dfrac{25,992,412.50 }{8.35}\\\\\)

≈ 3112864

Therefore, around 3112864 people saw the movie this week.

Hence, this is the required solution.

The sample mean is X[bar]=$1500

The sample standard deviation is S=$100

The sample size is n=70

The data set has a bell shaped distribution

The empirical rule states that

The values $1400 and $1600 are within one standard deviation away from the mean:

X[bar]+S=$1500+$100=$1600

X[bar]-S=$1500-$100=$1400

Following the rule you can expect 68% of the sample to be between them.

Whats left to do is to calculate the 68% of the sample

Around 47.6 of the farms have values per acre are between $1400 and $1600

(a) For the claim that the mean age of all students at college is 30 years:

H0: μ = 30 (Null hypothesis)

H1: μ ≠ 30 (Alternative hypothesis)

The claim is about the mean age of all students at college. This is a two-tailed test as the alternative hypothesis allows for deviations in both directions from the claimed mean of 30. The type of testing is a two-tailed hypothesis test.

(b) A situation of Type I Error assuming H0 is valid would be if, based on a sample of students, the researcher rejects the null hypothesis (H0: μ = 30) and concludes that the mean age is significantly different from 30, when in reality, the mean age of all students at college is actually 30. This would be an incorrect rejection of the null hypothesis, leading to a false positive conclusion.

2. For the claim that the proportion of all students at college that voted in the last presidential election was below 30%:

H0: p ≥ 0.30 (Null hypothesis)

H1: p < 0.30 (Alternative hypothesis)

The claim is about the proportion of students at college who voted in the last presidential election. This is a left-tailed test as the alternative hypothesis suggests that the proportion is below 30%. The type of testing is a one-tailed hypothesis test.

(b) A situation of Type II Error assuming H0 is invalid would be if, based on a sample of students, the researcher fails to reject the null hypothesis (H0: p ≥ 0.30) and concludes that the proportion of students who voted is not significantly below 30%, when in reality, the proportion of all students at college who voted is actually below 30%. This would be an incorrect acceptance of the null hypothesis, leading to a false negative conclusion.

3. For the claim that the standard deviation of salaries of all nurses in southern California is more than $450:

H0: σ ≤ $450 (Null hypothesis)

H1: σ > $450 (Alternative hypothesis)

The claim is about the standard deviation of salaries of all nurses in southern California. This is a right-tailed test as the alternative hypothesis suggests that the standard deviation is greater than $450. The type of testing is a one-tailed hypothesis test.

(b) A situation of Type I Error assuming H0 is valid would be if, based on a sample of salaries, the researcher rejects the null hypothesis (H0: σ ≤ $450) and concludes that the standard deviation of salaries is significantly greater than $450, when in reality, the standard deviation of salaries of all nurses in southern California is actually not significantly greater than $450. This would be an incorrect rejection of the null hypothesis, leading to a false positive conclusion.

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Answer:

x = 41°

Step-by-step explanation:

Complementary angles are angles that add up to 90°

y = x + 8

x + y = 90°

Plug in x+8° for y:

-Chetan K

under the restrictions that c is negative to ensure strict concavity, the utility function u(w) = -(b - w)c displays increasing absolute risk aversion.

To ensure that u(w) is strictly increasing, we need the derivative of u(w) with respect to w to be positive for all values of w. Taking the derivative, we have du(w)/dw = -c. For u(w) to be strictly increasing, -c must be positive, which implies c must be negative.

To ensure that u(w) is strictly concave, we need the second derivative of u(w) with respect to w to be negative for all values of w. Taking the second derivative, we have d²u(w)/dw² = 0. Since the second derivative is constant and negative, u(w) is strictly concave.

Now, let's examine the concept of increasing absolute risk aversion. If a utility function u(w) exhibits increasing absolute risk aversion, it means that as wealth (w) increases, the individual becomes more risk-averse.

In the given utility function u(w) = -(b - w)c, when c is negative (as required for strict concavity), the absolute risk aversion increases as wealth (w) increases. This is because the negative sign implies that the utility function is concave, indicating that the individual becomes more risk-averse as wealth increases.

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Answer:

-1.13

Step-by-step explanation:

you can count the lines and get the answer, one line down from -1.1 is -1.11 since -1.1 is technically -1.10 and you keep counting until the dot

Answer:

108

Step-by-step explanation:

Answer:

answer is 108

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

C. C is the correct answer

The exact values of the sine, cosine, and tangent of the angle 255° are -1/√2, 1/√2, and -1, respectively.

To find the exact values of the sine, cosine, and tangent of the angle 255°, we can use the identity that relates the trigonometric functions of an angle to the trigonometric functions of its complement.

By expressing 255° as the sum of 300° and -45°, we can determine the exact values of the trigonometric functions for the given angle.

We know that the sine, cosine, and tangent of an angle are periodic functions, repeating every 360 degrees. To find the exact values of the trigonometric functions for 255°, we can express it as the sum of 300° and -45°, where 300° is a multiple of 360°.

Since the sine, cosine, and tangent functions are odd or even functions, we can use the values of the trigonometric functions for 45° to determine the values for -45°.

For 45°:

sin(45°) = cos(45°) = 1/√2

tan(45°) = 1

Since cosine is an even function, cos(-45°) = cos(45°) = 1/√2.

Since sine is an odd function, sin(-45°) = -sin(45°) = -1/√2.

Using the definition of tangent as the ratio of sine to cosine, tan(-45°) = sin(-45°) / cos(-45°) = (-1/√2) / (1/√2) = -1.

Therefore, for the angle 255°:

sin(255°) = -1/√2

cos(255°) = 1/√2

tan(255°) = -1

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Answer:

We can split this into ∛8 * ∛n⁹. ∛8 = 2 and ∛n⁹ = n³ so the answer is 2n³.

Answer:

2n^3

Step-by-step explanation:

Answer:

Step-by-step explanation:

\( \frac{(5m - 4)}{6} - 1 = 4m - \frac{(3m + 10)}{2} \)

\( = > \frac{5m - 4 - 6}{6} = \frac{8m - 3m - 10}{2} \)

\( = > \frac{5m - 10}{6} = \frac{5m - 10}{2} \)

[Cross Multiplication]

=> 2(5m - 10) = 6(5m - 10)

=> 10m - 20 = 30m - 60

=> 60 - 20 = 30m - 10m

=> 40 = 20m

\( = > m = \frac{40}{20} \)

=> m = 2 (Ans)

Answer:

58

Step-by-step explanation:

first we want to write an equation and that equation would be

2500=40x+160 now we solve for x

step 1 subtract 160 from each side

2340=40x

then we divide each side by 40

x=58.5

because he cant bring half a box he can only bring 58

Answer:

The median is 11.

Step-by-step explanation:

To find the median, you need to put all of the numbers in order.

In this case it would go:

2, 5, 8, 10, 10, 12, 14, 17, 20, 22

Now you find the middle number. Since there is an even amount of numbers, the median will fall between two different numbers. These numbers are 10 and 12. The median will be the number in between these two, which is 11. Therefore, the median is 11.

IM SO SORRY IF THIS DID NOT MAKE SENSE!

Answer:

Step-by-step explanation:

Area of rectangle = Length ×Breadth

\(Length =8x+1\\Breadth = 3x-2\\\\A =\left(8x+1\right)\left(3x-2\right)\\\\=8x\times\:3x+8x\left(-2\right)+1\times\:3x+1\times\left(-2\right)\\\\=8\times\:3xx-8\times \:2x+1\times \:3x-1\times\:2\\\\=24x^2-13x-2\)

SOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

I´m sure this was already answered because for me it says it was from a while ago so ima just take tha points

THAMKSSSSSSSSSSSSSSSSSSSSSS

The critical point(s) is/are (0,0) for the given function of two variables is f(x,y) = 2x² − 6y².

For a function of two variables, f(x,y), critical points are points (x,y) in the domain of the function where either the partial derivative with respect to x or the partial derivative with respect to y is zero.

The given function is f(x,y) = 2x² − 6y². To find the critical points of the function, we need to find the partial derivative of the function with respect to x and y.

Respect to x, the partial derivative isfₓ(x,y) = 4x

Respect to y, the partial derivative isf_y(x,y) = -12y

Now, we need to find the critical points of the function by equating both the partial derivative equations to zero. We get

4x = 0   =>   x = 0 and, -12y = 0   =>   y = 0

Hence, the critical points are (0,0).

Therefore, the correct choice is A.

The critical point(s) is/are (0,0).

Thus, the correct option is A. The critical point(s) is/are (0,0).

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To find the minimum score required for an A grade, we need to determine the cutoff point that corresponds to the top 13% of scores.

Given that the scores on the test are normally distributed with a mean of 69.5 and a standard deviation of 9.5, we can use the standard normal distribution to calculate the cutoff point. Using a standard normal distribution table or a statistical calculator, we find that the z-score corresponding to the top 13% is approximately 1.04. To find the corresponding raw score, we can use the formula:

x = μ + (z * σ)

where x is the raw score, μ is the mean, z is the z-score, and σ is the standard deviation. Plugging in the values, we have:

x = 69.5 + (1.04 * 9.5) ≈ 79.58

Rounding this to the nearest whole number, the minimum score required for an A grade would be 80. Therefore, a student would need to score at least 80 on the test to achieve an A grade according to the professor's grading scheme.

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Answer:

5,1

Step-by-step explanation:

midpoint formula

x1+x2÷2, y1+y2/2

6+4/2,-1+3/2

5,1

Answer:

h(x) = 5x²-6

Step-by-step explanation:

f(x) = 5x²-1, translated vertically downward by 5 units, it becomes

h(x) = 5x² -1-5 = 5x²-6

Therefore, it is not possible to determine if the value that occurred the most often would change without knowing the frequency and values of the new data  points.

Adding two more data points that are each 2 1/2 hours to a line plot would not necessarily change the value that occurred the most often. The value that occurred the most often would depend on the frequency of the new data points in relation to the existing data points. If the new data points have the same value as one of the existing data points, then the mode would not change. However, if the new data points have a different value than the existing data points, and they occur more frequently, then the mode would change.

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The polar coordinates are solved and the functions are:

a) r(θ) = f(|θ|)

b) r(θ) = f(θ + π)

c) r(θ) = -f(θ)

Given data:

In polar coordinates, a point is represented by the pair (r, θ), where r is the distance from the origin to the point and θ is the angle formed with the positive x-axis in the counterclockwise direction. To describe functions with specific symmetries in polar coordinates, we use the following:

a)

Symmetry with respect to only the x-axis:

For a function with symmetry with respect to the x-axis, the value of r is the same for angles θ and -θ. In other words, the function is even with respect to the polar angle.

Formula: r(θ) = f(|θ|)

Example: r(θ) = 2 + cos(|θ|)

b)

Symmetry with respect to only the y-axis:

For a function with symmetry with respect to the y-axis, the value of r is the same for angles θ and θ + π. In other words, the function is even with respect to the polar angle plus π.

Formula: r(θ) = f(θ + π)

Example: r(θ) = 3 + sin(θ + π)

c)

Symmetry with respect to the origin:

For a function with symmetry with respect to the origin, the value of r is the same for angles θ and θ + π. In other words, the function is odd with respect to the polar angle.

Formula: r(θ) = -f(θ)

Example: r(θ) = 4 - 2sin(θ)

To draw the graph of each function, you would plot points for different values of θ and connect them to create the polar graph. Note that the graphs for (a) and (b) will look the same since they both have symmetry with respect to the x-axis, and the graphs for (c) will look different as it has symmetry with respect to the origin.

Hence, the polar coordinates are solved.

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If Charmaine made 8 stacks with her coins and every stack had 6 coins, then the number of coins that she has all together is 48 coins

The number of coins that she has made  = 8 stacks

The number of coins in each stack = 6 coins

To find the number of coins that she has, we have to multiply the number of stack and number of coins in each stack

Then the number of coins that she has all together = The number of coins that she has made × The number of coins in each stack

Substitute the values in the equation

= 8 × 6

= 48 coins

Hence, if Charmaine made 8 stacks with her coins and every stack had 6 coins, then the number of coins that she has all together is 48 coins

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By combining the like terms, the simplified form of the expression 5+10s-8s is 2s+5

Given,

The algebraic expression = 5+10s-8s

Combine the like terms

5+10s-8s = 5+2s

Simplified form is 2s+5

Hence, by combining the like terms, the simplified form of the expression 5+10s-8s is 2s+5

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a) The proportion of the students scored at least 26 points on this test is 0.02275.

b) The 71 percentile of the distribution of test scores is 24.073

A low standard deviation suggests that values are often close to the mean of the collection, whereas a large standard deviation suggests that values are dispersed over a wider range.

Standard deviation, often known as SD, is most frequently represented in mathematical texts and equations by the lower case Greek letter (sigma), for the population standard deviation, or the Latin letter s, for the sample standard deviation.

Let the scores be X and X is normally distributed with a mean of 22 and standard deviation of 2.

μ=22

σ=2

X≈N(22,2)

a) P(X≥26)=P(((X-μ)/σ)≥(26-μ)/σ)

=1-P(Z≥2)

=1-P(Z<2)

=1-0.97725

=0.02275

b) Let a is the 71th percentile of X,

P(X≤a)=0.71

P((X-μ)/σ)≤(a-μ)/σ)=0.71

P(Z≤z)=0.71

From the standard normal table by calculating with z value, we get

a=24.073

Therefore,

a) The proportion of the students scored at least 26 points on this test is 0.02275.

b) The 71 percentile of the distribution of test scores is 24.073.

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The effect of the student presenting such a monologue would be B. The mean will decrease.

Order the data points:

1. 5, 1. 5, 2, 2. 5, 2. 5, 2. 5, 3, 3. 5, 3. 5, 4

Find the mean ;

= (1. 5 + 1. 5 + 2 + 2. 5 + 2. 5 + 2. 5 + 3 + 3. 5 + 3. 5 + 4) / 10

= 27 / 10

= 2. 7

Then find the new mean after the student presents the monologue:

= ( 0. 5 + 1. 5 + 1. 5 + 2 + 2. 5 + 2. 5 + 2. 5 + 3 + 3. 5 + 3. 5 + 4) / 11

= 2. 5

The mean therefore reduced.

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Answer:

b

Step-by-step explanation: