510g of sodium carbonate, na2co3, are dissolved in 2.2×103g of ethylene glycol, c2h4(oh)2. what is the molality of sodium carbonate?

The mass of the solid is  2733 g

The mole is a useful unit of measurement in chemistry because it allows scientists to easily compare the amounts of different substances in chemical reactions. By knowing the molar amounts of the reactants and products in a chemical reaction, scientists can calculate important information such as the mass of products formed, the amount of energy released or absorbed, and other key chemical properties.

We know that;

1 mole of the compound would contain 6.02 * 10^23 molecules

x moles of the compound will contain  9.62 x 10^24 molecules

x= 15.98 moles

Then;

Mass = 15.98 moles * 171 g/mol

= 2733 g

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The charges of all the anions are the same. Therefore, we can disregard how the charge affects these anions.

As far as we are aware, the periodic table's Group 6 is where all of the given compounds reside. And the elements are positioned along the group from top to bottom as

O2 Oxygen

Sulfur S

selenite Se

Te Tellurium

As a result, there are more shells along the group as you move from top to bottom. And as the number of shells rises, so do the atomic or ionic radii. Because Oxygen is at the top of the group, it has the fewest shells and hence the shortest radius

.

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Answer:

Option C

Explanation:

In Lewis dot structure the valence electrons are represented as dots around the symbol.

For example,

In hydrogen valence electron is only one it can be represented as,

H·

We know that in covalent bonding atoms share their electron to complete the octet. Thus, their Lewis dot structure would be represented as,

H:H

This is the Lewis dot structure of H₂.

In given atom X their are  2 valence electrons (3s²) thus its Lewis dot structure contain two dots around the symbol.

Option C is correct answer because it has only two dots which actually represent valence electrons.

Other options are incorrect because symbol X has more than two electrons/dots.

Answer:

gnzl8303

gnzl8303vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

Explanation:

Answer:

how they are alike: Both compound and mixture are combined in a definite ratio or in any proportion. Both compound and mixture consist of two or more substances/elements. Both compounds and mixtures have physical and chemical properties.

how they are different: The chemical composition of compounds is always fixed. A mixture can have a variable composition of the substances forming it. Mixtures can either be homogeneous or heterogeneous in nature. The constituents of a compound can only be separated by either chemical or electrochemical methods (like extraction).

Explanation:

When a material is cooled from a temperature of 225 ° c temperature to 25 oC, 160 j worth heat energy are released. H=0.17 J/g*C is the metal's specific heat capacity if its mass is 5.0 g.

Heat is the interchange of "thermal" energy caused by a temperature difference. Consider a system that is isolated and has two components that are initially running at different temperatures. Energy is transmitted from the large heat subsystem 2 to the cooler temperature subsystem 2.

Atoms and molecules move more quickly and clash when the temperature rises, producing excess heat (also known as heat energy). The energy that comes from a heated substance's temperature is known as thermal energy.

=160 J released

=5.0 g metal

=A temperature change of (225-35) or 190C.

=160J/(5.0g*190C) = 0.1684 J/g*C

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Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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Answer:

Explanation:

SO; If we assume that:

P should be the diffusion of oxygen towards the surface ; &

Q should be the  diffusion of carbondioxide away from the surface.

Then  the total molar flux of oxygen is illustrated by :

\(Na,x = - cD_{PQ}\frac{dy_P}{dr} +y_P(NP,x + N_Q,x)\)

where;

r is the radial distance from the center of the carbon particle.

Since ;

\(N_P,x = - N_Q, x\) ; we have:

\(Na,x = - cD_{PQ}\frac{dy_P}{dr}\)

The system is not steady state and the molar flux is not independent of r because the area of mass transfer \(4\pi r^{2}\) is not a constant term.

Therefore,  using quasi steady state assumption, the mass transfer rate   \(4\pi r^{2}N_{P,x}\) is assumed to be independent of r at any instant of time.

\(W_{P}=4\pi r^{2}N_{P,x}\)

\(W_{P}=-4\pi r^{2}cD_{PQ}\frac{dy_{P}}{dr}\)        

       = constant

The oxygen concentration at the surface of the coal particle \(yP,R\) will be calculated from the reaction at the surface.

The mole fraction of oxygen at a location far from pellet is 1.

Thus, separating the variables and integrating result into  the following:

\(W_{P}\int_{R}^{\infty} \frac{dr}{r^{2}}=-4\pi\)

\(r^{2}cD_{PQ}\int_{y_{P,R}}^{y_{P,\infty }}dy_{P}\)

\(-W_{P}\frac{1}{r}\mid ^{\infty }_{R}= -4\pi cD_{PQ}(y_{P,\infty }-y_{P,R})\)

\(=> W_{P}= - 4\pi cD_{PQ}(1-y_{P,R})R\)

The mole of oxygen arrived at the carbon surface is equal to the mole of oxygen consumed by the chemical reaction.

\(W_{P} = 4 \pi R^2R"\)

\(W_{P}= 4\pi R^{2}k_{1}"C_{O_{2}}\mid _{R}\)

\(W_{P}= 4\pi R^{2}k_{1}"c y _{P,R}\)

\(-4\pi cD_{PQ}(1-y_{P,R})R= - 4\pi R^{2}k_{1}"c y _{P,R}\)

\(y_{P,R}=\frac{D_{PQ}}{D_{PQ}+Rk_{1}}\)

\(y_{P,R}=\frac{1.7 \times 10^{-4}}{1.7\times 10^{-4}+10^{-3}\times 0.1}\)

\(\mathbf{= 0.631}\)

Obtaining the total gas concentration from the ideal gas law; we have the following:

where;

R= \(0.082m^3atm/kmolK\)

\(c=\frac{P}{RT} \\ \\ c=\frac{1}{0.082\times 1450} \\ \\ = 0.008405kmol/m^3\)

The steady state \(O_2\) molar consumption rate is:

\(W_{P}= -4\pi cD_{PQ}(1-y_{P,R})R\)

\(W_{P}= -4\pi (0.008405)(1.7\times 10^{-4})(1-0.631)(10^{-3})\)

\(W_{P}= - 6.66\times 10^{-9}kmol/s\)

Answer:

Temperature and salinity

Explanation:

Answer:

precipitation occur

Explanation:

the solute do not dissolve in water

The dispersion and mixing of particles would be made easier through the application of ultrasonic waves.

Ultrasonic waves can facilitate the dispersion and mixing of particles in an experimental procedure. When ultrasonic waves are applied, they generate high-frequency sound waves that create alternating compression and rarefaction waves in a liquid medium.

These waves produce tiny bubbles due to the phenomenon of cavitation. During cavitation, the bubbles rapidly expand and collapse, creating localized areas of high pressure and temperature.

This process exerts mechanical forces on the surrounding particles, leading to their effective dispersion and mixing. The energy from ultrasonic waves helps to break down agglomerates, disperse fine particles, and enhance the overall homogeneity of the mixture.

The application of ultrasonic waves can be particularly beneficial in procedures such as sample preparation, emulsification, dispersion of nanoparticles, and dissolution of substances. It improves the efficiency and effectiveness of processes that require uniform distribution and thorough mixing of components.

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The dominant transport mechanism in the lake is diffusion. The water treatment plant has a limited time before it needs to start treating for manganese, and the minimum height above the lake bottom for the water intake to provide one year for designing and installing a manganese treatment system needs to be determined.

Dominant transport mechanism: Diffusion is the main transport mechanism in the lake. This means that manganese is gradually diffusing from the solid deposits at the lake bottom into the water column.

 t = (L^2) / (4D)

where t is the time in seconds, L is the distance from the bottom (1 ft or 30.48 cm), and D is the diffusion coefficient of manganese (6.88×10^(-6) cm^2/s).

Calculation Plugging in the values into the equation, we can calculate the time it takes for manganese to reach the water intake level.

  t = (30.48^2) / (4 × 6.88×10^(-6)) = 126,707 seconds

  Converting seconds to days: 126,707 seconds ÷ (24 hours/day × 3600 seconds/hour) ≈ 1.47 days

  Therefore, the water treatment plant has approximately 1.47 days before it needs to start treating for manganese.

Minimum intake height: To provide one year for designing and installing a manganese treatment system, the intake should be raised to a height where the time it takes for manganese to reach that level is one year.

  t = (L^2) / (4D)

  Rearranging the equation to solve for L:

  L = √(4Dt)

  Plugging in the values: L = √(4 × 6.88×10^(-6) cm^2/s × (1 year × 365 days/year × 24 hours/day × 3600 seconds/hour))

  L ≈ 49.65 cm or 0.163 ft

The minimum height above the lake bottom that the intake should be raised to is approximately 0.163 ft.

The dominant transport mechanism in the lake is diffusion, where manganese is slowly diffusing from the solid deposits into the water column. The water treatment plant has approximately 1.47 days before it needs to start treating for manganese to maintain concentrations below the detection limit. To provide one year for designing and installing a treatment system, the intake should be raised to a minimum height of approximately 0.163 ft above the lake bottom.

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Answer: Radio Waves

Explanation:

electromagnet transmit Radio waves

Explanation:

atomic no. is 42

chemical symbol is Mo

no. of protons is 42

atomic mass is 95.95

no. of electrons is 42

no. of electron in outer most shell is 1

no of electrons in the n 3 shell is 18

no. of neutron is 96

The element molybdenum is 42nd element in periodic table with the symbol Mo and  a mass of 96. It have 42 electrons and 42 protons.

Molybdenum (Mo) is a transition metal in periodic table included in the d-block. The atomic number of molybdenum is 42 which is the number of protons and electrons in it.

The atomic number of a neutral atom is equal to the number of electrons in it. For a neutral atom the number of electrons and protons are equal and thus the number of both electrons and protons in Mo is 42.

Mass number is the sum of number protons and neutrons in an atom. The mass number of Mo is 96 and number of protons is 42. Thus, the number of neutrons is 96 -42 = 54.

The outer shells of Mo are 4d and 5s containing 4 and 2 electrons respectively. Thus the number of outer electrons is 6.The level n= 3 is M shell which contains 18 electrons for Mo.

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The empirical formula for an ionic compound comprising at least four ions, including \(Fe^{3+}\), \(NO^{3-}\), \(NH^{4+}\), and \(CN^{-}\), are:

\(Fe(CN)_6^{3-}\) , \(Fe(NO3)_3\) , \(NH_4NO_3\) , \((NH_4)_2Fe(CN)_6\)

\(Fe^{3+}\):  \(Fe(CN)_6^{3-}\) is the empirical formula for this ionic compound. It is made up of cyanide ions \(CN^{-}\)and iron(III) ions \(Fe^{3+}\).

\(NO^{3-}\): The empirical formula for this ionic molecule \(Fe(NO3)_3\) is  \(NO^{3-}\) and \(Fe^{3+}\). It is created when nitrate ions and iron(III) ions \(Fe^{3+}\) combine.

\(NH^{4+}\) : The empirical formula for this ionic molecule is \(NH_4NO_3\). It is made up of nitrate and ammonium ions.

\(CN^{-}\) : This ionic compound, which has the empirical formula \((NH_4)_2Fe(CN)_6\), contains the ions ammonium, iron(III) , and cyanide.

The relative ratios of the ions involved in the creation of each compound are shown by these empirical formulas, which give a clear picture of the compounds.

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The complete question is-

Write the empirical formula for at least four ionic compounds that could be formed from the following ions:

\(Fe^{3+}\) , \(CN^{-}\) , \(NO^{3-}\) , \(NH^{4+}\).

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The atoms of different chemical elements can be differentiated based on the number of protons.

Each chemical element is differentiated by his number of protons. This number of protons is also knowing as atomic number and it is represented by the letter (Z).

The atomic number represented the number of protons in the nucleus of an element. For example:

The atom is the smallest part of the composition of matter, it is indivisible and is composed of a nucleus that has protons and neutrons, and around the nucleus there are the electrons.

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To determine the value of ΔHºrxn (the standard enthalpy change for the reaction), we can use the equation:

ΔGº = -RT ln(K)

where ΔGº is the standard Gibbs free energy change, R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin, and K is the equilibrium constant for the reaction.

First, let's calculate ΔGº at each temperature using the given equilibrium constants:

At 350 K:

ΔGº(350 K) = -RT ln(K) = -(8.314 J/(mol·K) * 350 K) * ln(91.4) = -2.08 x 10^3 J/mol

At 298 K:

ΔGº(298 K) = -RT ln(K) = -(8.314 J/(mol·K) * 298 K) * ln(2.05 x 10^-4) = 446 J/mol

To calculate ΔHºrxn, we can use the relationship between ΔGº and ΔHº at constant temperature:

ΔGº = ΔHº - TΔSº

where ΔSº is the standard entropy change for the reaction.

By rearranging the equation, we can solve for ΔHº:

ΔHº = ΔGº + TΔSº

At 350 K:

ΔHº(350 K) = -2.08 x 10^3 J/mol + (350 K * ΔSº)

At 298 K:

ΔHº(298 K) = 446 J/mol + (298 K * ΔSº)

Since ΔHº is independent of temperature, we can equate the two equations:

-2.08 x 10^3 J/mol + (350 K * ΔSº) = 446 J/mol + (298 K * ΔSº)

Simplifying the equation:

52 K * ΔSº = 2.526 x 10^3 J/mol

ΔSº = (2.526 x 10^3 J/mol) / 52 K

ΔSº = 48.58 J/(mol·K)

Finally, we can calculate ΔHºrxn using either of the original equations:

ΔHºrxn = ΔHº(350 K) = -2.08 x 10^3 J/mol + (350 K * 48.58 J/(mol·K))

ΔHºrxn ≈ 2.08 x 10^3 J/mol

Therefore, the value of ΔHºrxn is approximately 2.08 x 10^3 J/mol, which is equivalent to 2.08 x 10^3 kJ/mol (option a).

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Answer: s - stable

i - unstable

th - unstable

Explanation: only the first has the same number of neutrons as protons (i hope this is right i’m just a sophomore chem student lol)

The best choice for screening a person's genetics for 1,000 or more genes would be: C. Sequencing.

Sequencing techniques, such as next-generation sequencing (NGS), are well-suited for screening a large number of genes efficiently and comprehensively. NGS allows for high-throughput sequencing of DNA, enabling the simultaneous analysis of multiple genes or even the entire genome. It provides detailed information about the sequence of nucleotides in the DNA, allowing for the identification of genetic variations, mutations, or other genomic features.

Microarray analysis (A) is a technique that can analyze gene expression patterns or detect specific genetic variations, but it is limited in the number of genes it can assess simultaneously compared to sequencing.

RELP analysis (B) is a technique used for detecting genetic variations based on restriction enzyme digestion patterns, but it is more suitable for specific target regions rather than screening a large number of genes.

Karyotyping (D) involves the visualization and analysis of chromosomes to detect large-scale chromosomal abnormalities but is not suitable for screening a large number of individual genes.

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An alcohol barometer would have a higher column height when compared to a mercury barometer. If the Magdeburg hemispheres were 2 km above the sea, it would be simpler to separate them. Two pistons make up a hydraulic device, one with a tiny cross-section area and the other with a larger cross-section area.

Barometric pressure, commonly known as air pressure or atmospheric pressure, is measured by a device called a mercury barometer using the various physical properties of mercury contained in a tube. Barometers are helpful instruments for weather forecasting since they can be used to predict impending changes in the weather. For instance, when the barometric pressure falls, it may indicate the impending arrival of storms, rain, or wind. On the other side, a rise in atmospheric pressure could suggest that dry, fair weather may start to develop soon. There is no assurance that the weather will behave as predicted, despite the fact that barometer reading interpretation is a fairly precise science.

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A graph of 1/[A]t vs. time will give you a straight line if the reaction will be second order.

The plot of 1/[A] against time required towards a second order reaction is displayed in the following picture as a straight line where k = slope of the line. For a second order reaction, additional graphs were curved.

The graph of the second order reaction can be shown as:

The reaction exhibits zero-order kinetics even when an increase in the reactant lengthens the half life. It has first-order kinetics if there is no effect. The process exhibits second-order kinetics whereas if half life shortens as the reactant concentration rises.

Therefore, the correct answer will be option (C).

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Ca(OH)2 (aq) because of elements oxygen and hydrogen

Ca(OH)2(aq)+H2SO4(aq)—→ CaSO4(s)+ 2H2O(l)

Answer:

your answer is D

Explanation:

Answer:

What letter on the graph corresponds to both liquid water and steam? D

Explanation:

Liquid water exists between 0 and IOO degrees Celcius.

Answer:

3.5 milligram

Explanation:

From;

N/No = (1/2)^t/t1/2

Where;

N = amount of Po-210 that remains unchanged after 414 days

No = 28.0 milligram of Po-210 originally present

t = 414 days

t1/2 = half life of Po-210 = 138 days

Substituting values;

N/28 = (1/2)^414/138

N/28 = (1/2)^3

N/28 = 1/8

8N = 28

N = 28/8

N = 3.5 milligram

         Certain metal-based nanoparticles have the potential to interact with the hydrogen peroxide found in every cell and change it into a hydroxyl radical that can enter the nucleus and cause DNA damage.

     Scratch-resistant eyewear, crack-resistant paint, anti-graffiti coatings for walls, transparent sunscreen, stain-repellent fabrics, self-cleaning windows, and ceramic coatings for solar cells are all products made with nanoparticles today.

    In addition to living matter, naturally produced nanoparticles can also be found in volcanic ash, ocean spray, fine sand, and dust (e.g. viruses). The diversity of synthetic nanoparticles is on par with that of its counterparts in nature, if not greater.

    The usage of nanoscale materials in medications, medical devices, biologics, cosmetics, and food is anticipated to rise significantly in the coming years, according to the FDA, which has already assessed and authorized a few nanotechnology-based items.

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The most likely effect of the nationwide chain of gas stations adding recharging stations for electric vehicles to all of its locations is that charging stations will become less scarce. Option C is correct.

As more charging stations become available, it becomes easier for electric vehicle owners to find a place to charge their cars. This, in turn, makes it more likely that people will purchase electric vehicles, since they will have access to convenient and accessible charging stations. It also means that electric vehicle owners will no longer need to worry about running out of power during longer trips or in areas where charging stations were previously scarce.

The decision by the gas station chain does not necessarily mean that they will have less gas available, and it is unlikely that consumers will stop using the charging stations since they will become more widely available. Charging stations will become more important as more people switch to electric vehicles, and gas stations will need to adapt to this trend in order to remain competitive.

Hence, C. is the correct option.

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--The given question is incomplete, the complete question is

"A nationwide chain of gas stations has decided to add recharging stations for electric vehicles to all of its locations. What is the most likely effect of this decision? A) The locations will have less gas available. B) Consumers will stop using the charging stations. C) Charging stations will become less scarce. D) Charging stations will become less important."--

Answer:

89.3 %

Explanation:

M(CH4) = 12+ 4*1 = 16 g/mol

M(O2) = 2*16 = 32 g/mol

M(CO2) = 12 + 2*16 = 44 g/mol

8.50 g * 1 mol/16 g = 0.5313 mol CH4

15.9 g * 1 mol/32 g = 0.4969 mol O2

9.77 g * 1 mol/44 g = 0.2220 mol CO2

1)                                  CH4        + 2O2 -----> CO2 + 2H2O

from reaction             1 mol          2 mol

given                       0.5313 mol   (0.4969 mol)

1 mol CH4              --- 2 mol O2

0.5313 mol  CH4  --- x mol O2

x= 2*0.5313 = 1.0626 mol O2

We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.

2)                               CH4        + 2O2 -----> CO2 + 2H2O

from reaction                             2 mol        1 mol

given                                      0.4969 mol   x mol

x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield

3)

Practical yield CO2 = 0.2220 mol

Theoretical yield CO2 = 0.2485 mol

% yield = (0.2220/0.2485)*100% = 89.3 %