5. What mass of the following solutes will dissolve in 100 ml of water?

KNO3 at 50o C? ______________________________

NH4Cl at 50o C? _________________________________

NaNO3 at 50o C? _______________________________

Answer:

They look at what people want. They plant the same thing every year. They think about what they like to eat.

Explanation:

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The correct statements are that a rock is considered an ore when it contains at least one metallic mineral in sufficient amounts to be extracted profitably and when it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably.

When it contains at least one metallic mineral in sufficient amounts to be extracted profitably.

When it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably.

Step-by-step explanation:

When it occurs in sufficient amounts to be used to build roads and buildings: This statement is incorrect. Rocks that are used for construction purposes, such as limestone or sandstone, are not considered ores unless they also contain economically valuable minerals.

Only when it contains lead: This statement is incorrect. Ores are not limited to containing only lead. Ores can contain various metallic minerals, not just lead.

When it contains at least one metallic mineral in sufficient amounts to be extracted profitably: This statement is correct. Ores are rocks that contain valuable metallic minerals in concentrations that make extraction economically feasible. These minerals can include gold, silver, copper, aluminum, zinc, and many others.

Only when it contains iron: This statement is incorrect. While iron ores are commonly known and widely used, ores are not limited to containing only iron. There are numerous other metallic minerals that can be extracted profitably from rocks.

When it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably: This statement is correct. Fluorite and sulfur are examples of non-metallic minerals that can be extracted profitably from rocks, and if a rock contains these minerals in sufficient quantities, it can be considered an ore.

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Answer:

Rotting, burning, cooking, are the three example of a chemical change.

Explanation:

burning wood

digesting food

souring milk

The correct answer is Carbon Monoxide (CO). When organic matter is burned with insufficient oxygen, it leads to incomplete combustion and the production of various gases, including carbon monoxide. Carbon monoxide is a colorless, odorless gas that is extremely poisonous and can be fatal in high concentrations.Carbon dioxide (CO2) is a product of complete combustion and is not produced when there is insufficient oxygen.Benzene is a hydrocarbon compound composed of six carbon atoms and six hydrogen atoms, and it is not produced from combustion.Methane (CH4) is a hydrocarbon compound composed of one carbon atom and four hydrogen atoms, and it is not produced from combustion.Mercury is a metallic element and is not related to combustion.

64 g/mol is the molar mass of a gas Z if 0.4g of it occupies a volume of 140 cubic centimeters at s.t.p.

We should use the ideal gas equation to find the molar mass of the gas;

PV = nRT

Where:

P = pressure

V = volume

T = temperature ⇒ 273.15 K(at STP,)

n = number of moles of gas

R = ideal gas constant ⇒ 0.0821 L·atm/(mol·K)

Let's convert the volume

cubic centimeters (cm³) ⇒ cubic decimeters (dm³)

(to make the SI units similar in the equation)

1 cubic centimeter = 1/1000 cubic decimeter

140 cubic centimeters = ?

= 140×1/1000

= 0.14 cubic decimeters

Now we can substitute the given values into the ideal gas equation PV = nRT

1 × 0.14  = n × 0.0821 × 273.15

0.14 = n × (0.0821 × 273.15)

0.14 = n × 22.4

n = 0.14 / 22.4

n ≈ 0.006 mol...eq. (1)

Now we can calculate the molar mass (M) using the formula:

M = m / n

mass (m) = 0.4 g

number of moles (n) = 0.006 mol..from eq. (1)

M = 0.4 g / 0.006 mol

≈ 64 g/mol

Therefore, the molar mass of gas Z is approximately 64.189 g/mol.

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The correct answer is B. H2O; sugar. Photosynthesis involves the transfer of electrons from water (H2O) to sugar (glucose).

Plants and other living things employ a process called photosynthesis to transform light energy into chemical energy that can then be released through cellular respiration to power the organism's activities. The word "photosynthesis," which comes from the Greek words "phs," "light," and "synthesis," "putting together," refers to the process of creating molecules of carbohydrates from carbon dioxide and water that store some of this chemical energy. These molecules include sugars and starches. Photoautotrophs are creatures that perform photosynthesis, including most plants, algae, and cyanobacteria. The majority of the energy required for life on Earth is produced and maintained by photosynthesis.  Photosynthesis is also significantly responsible for producing and maintaining the oxygen concentration of the Earth's atmosphere. Although there are numerous steps involved in photosynthesis in plant leaves, it may be broken down into two phases: the light-dependent reactions and the Calvin cycle.

The thylakoid membrane is the site of the light-dependent processes, which necessitate a constant flow of light energy. This light energy is absorbed by chlorophylls and transformed into chemical energy through the creation of two compounds: ATP, an energy storage molecule, and NADPH, an electron carrier that is reduced. Water molecules are also changed into oxygen gas, which is the oxygen we breathe, throughout this process.

Calvin cycle occurs in the stroma and does not directly require light, commonly known as the light-independent processes. Instead, the Calvin cycle utilises ATP and NADPH from the light-dependent processes to fix carbon dioxide and create molecules of glyceraldehyde-3-phosphate (G3P), a three-carbon sugar that combines with another to generate glucose. The overall result of light-dependent processes is the temporary storage of light energy in the chemical forms of ATP and NADPH. In order to release energy, ATP is broken down, and NADPH contributes its electrons to the process, turning carbon dioxide molecules into sugars. The energy that began as light eventually becomes bound up in the bonds of the sugars.

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The substance used as a reference standard in both the freezing-point and vapor-pressure models is A. Deionized water.

In osmometry, a reference standard is used to calibrate the instrument and establish a baseline for measurements. Both freezing-point and vapor-pressure osmometers require a known substance with well-defined properties for accurate calibration.

Deionized water (option A) is commonly used as the reference standard in osmometers because its freezing-point and vapor-pressure properties are well-established and easily reproducible.

The freezing-point of pure water is 0°C (32°F) at standard atmospheric pressure, and its vapor pressure is also well-defined.

Other substances like NaCl (option B) and KCl (option C) are used as calibration standards in specific contexts, but they are not universally applicable to both freezing-point and vapor-pressure osmometers.

Based on the given information, the substance used as a reference standard in both the freezing-point and vapor-pressure models is deionized water (option A). It serves as a reliable and widely accepted calibration standard for osmometers due to its well-defined freezing-point and vapor-pressure properties.

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Answer:

Explanation:

A. Ethanoic acid-acetic acid being weak acid dissocated weekly and turns solution to weakly acidic, ph will be between 4-7,

B. Hydrochloric acid - the solution would be acidic- with lots of H+ ions, Ph will be between 1-4,

C. Sodium chloride - solution prodcued netural Na+ and Cl- hence wont affect ph of solution will be equalt to 7.

D. Sodium hydrogen carbonate-NaHCO3 is weak base and the PH will be above 7,

Answer:

T=846K

Explanation:

We can use the formula for the Ideal Gas Equation, which is

\(PV=nRT\)

P=pressure

V=volume

n=mols of gas

R=constant (0.08201 L-atm/mol-K)

T=temperature

We will have to rearrange to equation to find temperature, which is

\(T=\frac{PV}{nR}\)

Time to solve:

\(T=\frac{(2.50 atm)(10.30L)}{(0.371 mols)(0.08206 L-atm/mol-K)}\)

\(T=846 K\)

If you want to convert to Celsius, subtract 273 to your answer, which will get you 573ºC.

A balanced equation obeys the law of conservation of mass. The coefficients are the numbers that are added in front of the formulas to balance the equation.

A balanced equation is defined as the chemical equation in which the mass of the products and reactants on either side of the equation will be equal. The number of atoms of each element on both sides of the equation are equal.

1. 4Na + O₂ → 2Na₂O

2. C + 2H₂ → CH₄

3. 2H₂O₂ → 2H₂O + O₂

Thus in the balanced equation, the number of atoms on both sides of the equation are equal.

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Answer:  atoms, molecules, organelles, cells, tissues, organs, organ systems, and the human organism.

Explanation:

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Answer:

0.6802 mol

Explanation:

1 grams K2S  = 0.00907 mol

0.00907 x 75 = 0.6802 mol

Hydroboration of 1-butene leads to the major product 1-butanol through anti-Markovnikov addition. Lindlar catalytic hydrogenation of 2-butyne produces cis-2-butene as the major product, stopping at the alkene stage without full reduction to an alkane.

Hydroboration: Hydroboration is a reaction in which an alkene reacts with borane (BH3) in the presence of a basic solvent such as tetrahydrofuran (THF). The major product of hydroboration is an organoborane compound, which is subsequently converted to an alcohol through oxidation.

For example, let's consider the hydroboration of 1-butene (CH2=CHCH2CH3):

Step 1: Hydroboration

CH2=CHCH2CH3 + BH3 → CH3CH2CH2CH2B

Step 2: Oxidation

CH3CH2CH2CH2B + H2O2, NaOH → CH3CH2CH2CH2OH + B(OH)3

In this reaction, the stereoselectivity depends on the orientation of the alkene. Since 1-butene is an internal alkene, it will undergo anti-Markovnikov addition, resulting in the formation of the alcohol on the less substituted side of the double bond. In this case, the major product is 1-butanol (CH3CH2CH2CH2OH).

Lindlar Catalytic Hydrogenation: Lindlar catalytic hydrogenation is a selective reduction of alkynes to alkenes using a palladium catalyst with poisoned (deactivated) surfaces. This reaction allows for the partial hydrogenation of alkynes, stopping at the alkene stage without full reduction to an alkane.

For example, let's consider the Lindlar catalytic hydrogenation of 2-butyne (CH3C≡CCH3):

CH3C≡CCH3 + H2 (catalyst: Pd/CaCO3, poisoned with quinoline) → CH3CH=CHCH3

The Lindlar catalyst suppresses further hydrogenation and allows the formation of cis-alkenes. Therefore, the major product of this reaction is cis-2-butene (CH3CH=CHCH3), where the two methyl groups are on the same side of the double bond.

Please note that these reactions are general examples, and specific reaction conditions or variations may lead to different products. It's always important to consider the specific reactants and reaction conditions when predicting the major product(s).

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In many cases, the Coase theorem does not work well because c. transaction costs are too high. The Coase theorem suggests that in the absence of transaction costs, parties can negotiate and reach an efficient outcome regardless of the initial allocation of property rights.

However, in reality, transaction costs such as bargaining costs, information costs, and enforcement costs can significantly hinder the ability of parties to negotiate and reach mutually beneficial agreements.

When transaction costs are high, it becomes difficult for parties to gather and exchange information, engage in effective negotiations, and enforce agreements. These costs can include the time and resources required for communication, legal representation, monitoring, and enforcement. High transaction costs can discourage parties from engaging in negotiations or make it economically infeasible to reach an efficient outcome.

Therefore, despite the theoretical possibility of the Coase theorem, transaction costs often present practical barriers to efficient bargaining and prevent the theorem from working effectively in real-world situations.

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\(C_3H_6\)  has a double bond in its carbon skeleton. This is a true statement.

Carbon skeleton refers to the chain of carbon atoms that make up an organic molecule. The presence or absence of double bonds in the carbon skeleton affects the properties of the molecule and how it interacts with other molecules. In \(C_3H_6\), there are three carbon atoms arranged in a linear chain, with each carbon atom forming single covalent bonds with two hydrogen atoms. The remaining valence electrons on each carbon atom form a double bond between the first and second carbon atoms.

This double bond is responsible for the unsaturated nature of the molecule. \(C_3H_6\)is an example of a simple alkene, also known as propene. Its carbon skeleton and double bond make it a versatile molecule that can be used in various applications, including the production of plastics, rubber, and other materials.

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In a metabolic pathway, the product of one chemical reaction becomes the reactant of the next reaction in the pathway.

This occurs in a sequential manner where each step is catalyzed by a specific enzyme. Metabolic pathways are important for the body to carry out functions like digestion, energy production, and the synthesis of biomolecules.

A metabolic pathway is a series of chemical reactions that occur in the body to transform a molecule into another one. These pathways are responsible for the body's essential functions like digestion, energy production, and the synthesis of biomolecules. The reactions in metabolic pathways are organized in a sequential manner, where each step is catalyzed by a specific enzyme.

The product of one reaction is the reactant for the next one. In this way, the product of one reaction serves as a starting point for the next reaction. The pathway's enzymes are typically specific, meaning they only catalyze a particular reaction. Enzymes are essential in metabolic pathways because they speed up the reaction's rate. The rate-limiting enzyme is an enzyme that regulates the rate of a metabolic pathway. These enzymes are significant in maintaining homeostasis in the body

The product of one reaction becomes the reactant for the next reaction in a metabolic pathway. The enzymes are essential in the metabolic pathway because they speed up the reaction's rate. Enzymes are typically specific, meaning they only catalyze a particular reaction. The rate-limiting enzyme is an enzyme that regulates the rate of a metabolic pathway, which is significant in maintaining homeostasis in the body.

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Answer:

HClO3 > HBrO3 > HIO3

Explanation:

let's have a quick look at the terminology used in question,

Acidic strength- It is the ability of any molecule to donate H+ ion

Oxyacids- Acids that contain atleast one hydroxy (-OH) group

in the given oxyacids of Halogens, Chlorine is more electronegative than bromine and iodine.

So it will bind the proton (H+ ion) to it more tightly than other halogens hence the Acidic strength of HClO3 is highest among the following.

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Answer:

Activator effects a mixture if you put to much of the activator your using into a product or thing you are using.

Explanation:

For ex.

If you poor to much activator into slime it will make the slime hard and very wet it will ruin your slime completely so you will have to do it just right but start off pouring it slowly and mix and then more if it needs more.

Answer:

2 .Sulphurous acid

Explanation:

Sulphur dioxide can dissolve in water to form Sulfurous acid(H2SO3). sulphurous acid is weackly dibasic acid. sulphur dioxide is a major component of acid rain since it mixes with vapour in the atmosphere reacting to produce H2So4 .

Answer:

Sulphuric acid

Explanation:

Sulphuric acid is a major component of acid rain since it mixes with water vapour in the atmosphere, reacting to produce Sulphuric acid.

Hope that helped...

Answer:

8.0 g

Explanation:

To convert moles to grams, you need to use the molar mass.  The molar mass of sulfur is 32.06.  The molar mass is the atomic mass of the atom.

(0.25 mol) × (32.06 g/mol) = 8.015 g

Round for significant figures.

8.015 g ≈ 8.0 g

Answer:

chemical energy

Explanation:

A battery stores energy in the form of chemical energy. Chemical energy is stored in the bond of atoms and molecules. These bonds break and convert to other forms of energy. In the given case, the chemical energy is converted to electric energy which powers the flashlight. Thus, flashlight receives energy input in the form of chemical energy.

Answer:

Segments of DNA called RNA.Good luck dude

Answer:

Three formula units, Two Ammonium radical and Sulphate radical

Explanation:

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The concentration of the unknown sulfuric acid sample is 0.0909M.

The first step in solving this problem is to calculate the molarity of the sodium hydroxide solution used in the titrations. This can be done using the balanced chemical equation for the reaction between oxalic acid dihydrate and sodium hydroxide:

\(H_{2} C_{2} O_{4}.2H_{2} O + 2NaOH\) → \(Na_{2} C_{2} O_{4}. 2H_{2}O\)  + \(2H_{2} O\)

From the equation, we can see that 2 moles of NaOH react with 1 mole of   \(H_{2} C_{2} O_{4}.2H_{2}O\) . Therefore, the number of moles of NaOH used in the titration can be calculated as follows:

moles NaOH = (volume of NaOH solution) x (molarity of NaOH solution)

moles NaOH = 25.30 mL x (1 L / 1000 mL) x (1 mol \(H_{2} C_{2} O_{4}.2H_{2}O\) / 126.07 g) x (2 mol NaOH / 1 mol \(H_{2} C_{2} O_{4} .2H_{2}O\)) x (1 L / 20.00 mol NaOH)

moles NaOH  = 0.002012 mol

Using the volume and moles of NaOH used in the first titration, we can calculate the molarity of the NaOH solution:

Molarity of NaOH = moles NaOH / volume of NaOH solution

Molarity of NaOH = 0.002012 mol / (25.30 mL x (1 L / 1000 mL))

Molarity of NaOH = 0.0796 M

Now we can use the volume and molarity of NaOH from the second titration to calculate the number of moles of sulfuric acid in the unknown sample:

moles \(H_{2} SO_{4}\) = (volume of NaOH solution) x (molarity of NaOH solution)

moles \(H_{2} SO_{4}\) = 22.85 mL x (1 L / 1000 mL) x (0.0796 mol NaOH / 1 L)

moles \(H_{2} SO_{4}\) = 0.001818 mol

Finally, we can calculate the concentration of the sulfuric acid:

Molarity of \(H_{2} SO_{4}\) = moles H2SO4 / volume of sulfuric acid

Molarity of \(H_{2} SO_{4}\) = 0.001818 mol / (20.00 mL x (1 L / 1000 mL))

Molarity of \(H_{2} SO_{4}\) = 0.0909 M

Therefore, the concentration of the unknown sulfuric acid sample is 0.0909 M.

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A solution of nitric acid will contain nitric acid molecules (HNO3), hydrogen ions (H+), and nitrate ions (NO3-). Nitric acid is considered a strong acid because it completely dissociates into ions when dissolved in water.

In a solution of nitric acid, the particles present are nitric acid molecules (HNO3), hydrogen ions (H+), and nitrate ions (NO3-). Nitric acid (HNO3) is a strong acid.

Strong acids are substances that ionize completely in water, meaning that they break apart into their constituent ions. In the case of nitric acid, it dissociates fully to produce hydrogen ions (H+) and nitrate ions (NO3-) when dissolved in water.

The dissociation reaction for nitric acid can be represented as follows:
HNO3 → H+ + NO3-

As nitric acid completely ionizes in water, the concentration of hydrogen ions (H+) is high in a solution of nitric acid, making it an acidic solution.

It's important to note that the terms "strong" or "weak" in the context of acids refer to their degree of ionization in water, not their corrosiveness or concentration. Nitric acid is classified as a strong acid because it undergoes complete ionization.

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the mass of oxygen in an acetaminophen sample if there is 8.38 g of carbon present is 2.79g.

The percent composition indicates the proportion by mass of each element contained in a certain substance. Each element's mass percentages in a compound add up to 100. The molecular formula of a sample may be determined using the % content.

The first step is to determine the acetaminophen chemical formula. The chemical equation is \(C _8 H _9 N O_ 2\). Using the subscripts from the chemical formula, we can calculate the relationship between the mass of C and the mass of O. 8 moles of C are present for every 2 moles of O. We also do mass-to-mole conversions using the molar masses of C and O. These are the molar masses:

Molecular Weight C = 12.01 gram each

Molar Mass O = 16.00 grams per mole

\(8.38\times \frac{1}{12.01}\times\frac{2}{8}\times\frac{16}{1}\)=2.79g

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Answer:

A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water. Salts are also formed in this reaction.

Explanation:

A model of the force between two negatively charged particles is attached in the image below.

Force is defined as a cause which is capable of changing the motion of an object. It can cause an object which has mass to change it's velocity. It is also simply a push or a pull . It has both magnitude as well as direction.Hence, it is a vector quantity.

It has SI units of Newton and is represented by'F'.Newton's second law states that force which acts on an object is equal to momentum which changes with time. If mass of object is constant, acceleration is directly proportional to net force acting on an object.

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