5. 54 J of heat is required to raise the temperature of a 2.47g unknown substance from 17.10C to 46.70C. a) Calculate the specific heat of the substance b) What is the substance

Answers

Answer 1

Answer:

C = 0.7385J/g°C

Explanation:

Heat energy (Q) = 54J

Mass (m) = 2.47g

Initial temperature (T1) = 17.10°C

Final temperature (T2) = 46.70°C

Specific heat capacity of substance (c) = ?

Heat energy of a substance (Q) = Mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity of the substance

∇T = change in temperature of substance = T2 - T1

Q = mc∇T

Q = mc (T2 - T1)

54 = 2.47 * c * (46.70 - 17.10)

54 = 2.47 * 29.6 * c

54 = 73.112c

C = 54 / 73.112

C = 0.7385

Specific heat capacity of the substance is 0.7385J/g°C

B.

The specific heat capacity of the above substance does not match any metal in the periodic table, however the closest to it was potassium with a value of 0.7536J/g°C and silicone with value of 0.711756J/g°C

Answer 2

Answer:

The specific heat of the substance is 0.739 J/g°C

The substance can be glass or SiO2

Explanation:

Step 1: Data given

Heat required = 54 J

Mass of the substance = 2.47 grams

Initial temperature = 17.10 °C

Final temperature = 46.70 °C

Step 2: Calculate the specific heat of the substance

Q = m*c¨*ΔT

⇒with Q = the heat required =54 J

⇒with m = the mass of the substance = 2.47 grams

⇒with c = the specific heat of the substance = TO BE DETERMINED

⇒with ΔT = the change of temperature = T2 - T1 = 46.70 - 17.10 = 29.60 °C

c = Q / (m*ΔT)

c = 54 / (2.47 * 29.60)

c = 0.739 J/g°C

The specific heat of the substance is 0.739 J/g°C

The substance can be glass or SiO2


Related Questions

Nickel has a cubic unit cell. The edge of the unit cell is 3.524
x 10^(-8)cm. Determine the atomic radius of Nickel.

Answers

The approximate atomic radius of nickel is 1.532 × 10^(-8) cm.

In a cubic unit cell, the body diagonal length (diagonal that passes through the center of the unit cell) is equal to four times the atomic radius (4r). We can use this relationship to find the atomic radius of nickel.

Given: Edge length of the unit cell (a) = 3.524 × 10^(-8) cm

The body diagonal length is given by:

Diagonal length (d) = a√3

Substituting the given values:

d = (3.524 × 10^(-8) cm) × √3

Now, we can calculate the atomic radius (r) by dividing the diagonal length by 4:

r = d / 4

Performing the calculations:

r = [(3.524 × 10^(-8) cm) × √3] / 4

r ≈ (3.524 × 10^(-8) cm) × (1.732 / 4)

r ≈ 1.532 × 10^(-8) cm

Therefore, the approximate atomic radius of nickel is 1.532 × 10^(-8) cm.

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All flowers have colorful petals and smell wonderful.
True
False

Answers

Answer:

false i am pretty sure because dead flowers.

False because not all flowers have colorful petals and some don’t have a smell

Mole Calculation Worksheet. Answer the following questions: 1) How many moles are in 25.0 grams of water, H₂O? What is the percent composition for each element? 2) How many grams are in 4.500 moles of Li₂O? What is the percent composition for each element? 3) How many molecules are in 23.0 moles of oxygen, O₂? What is the percent composition for each element? 4) How many moles are in 3.4 x 10¹ molecules of H₂SO,? What is the percent composition for each element? 5) How many molecules are in 25,0 grams of NH,? What is the percent composition for each element?

Answers

There are approximately 1.387 moles in 25 grams of water (1) and 134.46 grams in 4.5 moles of Li₂O (2).

1. To calculate the number of moles, we need to divide the given mass of water by the molar mass of water, which is approximately 18.015 g/mol.

Number of moles = 25 grams / 18.015 g/mol

≈ 1.387 moles

Therefore, there are approximately 1.387 moles in 25 grams of water.

2. To calculate the mass in grams, we need to multiply the number of moles by the molar mass of Li₂O, which is approximately 29.88 g/mol.

Mass in grams = 4.5 moles x 29.88 g/mol

≈ 134.46 grams

Therefore, there are approximately 134.46 grams in 4.5 moles of Li₂O.

3. To determine the number of molecules in 23 moles of oxygen, we can use Avogadro's number, which states that there are 6.022 x 10²³ molecules in one mole of any substance. Therefore, for 23 moles of oxygen, we can calculate:

Number of molecules = 23 moles x 6.022 x 10²³ molecules/mole

= 1.38646 x 10²⁵ molecules

So, there are approximately 1.38646 x 10²⁵ molecules in 23 moles of oxygen.

4. To determine the number of moles in 3.4 x 10²³ molecules of H₂SO₄, we can use Avogadro's number. Since one mole contains 6.022 x 10²³ molecules, we can calculate:

Number of moles = (3.4 x 10²³ molecules) / (6.022 x 10²³ molecules/mole)

= 0.564 moles

So, there are approximately 0.564 moles in 3.4 x 10²³ molecules of H₂SO₄.

5. To determine the number of molecules in 25 grams of NH₃, we need to convert grams to moles using the molar mass of NH₃. The molar mass of NH₃ is 17.03 g/mol.

Number of moles = 25 grams / 17.03 g/mol

≈ 1.468 moles

Using Avogadro's number, we can calculate the number of molecules:

Number of molecules = (1.468 moles) x (6.022 x 10²³ molecules/mole)

= 8.831 x 10²³ molecules

So, there are approximately 8.831 x 10²³ molecules in 25 grams of NH₃.

The complete question is:

Answer the following questions:

1) How many moles are in 25 grams of water?

2) How many grams are in 4.5 moles of Li₂O?

3) How many molecules are in 23 moles of oxygen?

4) How many moles are in 3.4 x 10²³ molecules of H₂SO₄?

5) How many molecules are in 25 grams of NH₃ ?

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Deshawn carefully mixes the substances together in an Erlenmeyer flask. When mixed together, the substances undergo a change. Afterward, Mimi measures the mass and finds it to be 10 grams. Mimi and Deshawn repeat this experiment twice more with the same results. What is the most likely explanation for this data?

Answers

I need help with it too

When stomach acid helps to break down food into smaller particles this is
an example of a change.*
O Physical
Chemical
O
Elemental
о
Atomic

Answers

Answer:

chemical, is the answer your looking for

1. Tyrone is riding his newly bought motorcycle at 30 m/s when he sees a cat on the road ahead. He applied immediately the brakes and comes to a stop in 3.0 s. What was the acceleration of his motorcycle?

Given:

Asked:

Solution:

Final Answer:

2. A jeepney speeds up from 50 km/h to 60 km/h to overtake a truck. If this requieres 20 s, what is the (a) acceleration and (b) distance traveled by the car?

Given:

Asked:

Solution:

Final Answer:

Pls help​

Answers

Answer:

1. a = -10 m/s²

2. a = 1.8 × 10³ km/h²; s = 0.31 km

Explanation:

1.

Given:

Initial speed (u): 30 m/s

Final speed (v): 0 m/s (rest)

Time elapsed (t): 3.0 s

Asked:

Acceleration (a)

Solution:

We will use the following expression.

a = (v-u)/t = (0 m/s - 30 m/s)/3.0 s = -10 m/s²

Final Answer:

a = -10 m/s²

2.

Given:

Initial speed (u): 50 km/h

Final speed (v): 60 km/h

Time elapsed (t): 20 s

Asked:

(a) Acceleration (a)

(b) Distance traveled (s)

Solution:

(a) First, we will convert the time to hours.

20 s × 1 h/3600 s = 0.0056 h

Then, we will use the following expression.

a = (v-u)/t = (60 km/h - 50 km/h)/0.0056 h = 1.8 × 10³ km/h²

(b) We will use the following expression.

s = u × t + 1/2 × a × t²

s = 50 km/h × 0.0056 h + 1/2 × 1.8 × 10³ km/h² × (0.0056 h)² = 0.31 km

Final Answer:

a = 1.8 × 10³ km/h²

s = 0.31 km

When the volume of a gas is
changed from 250 mL to 425 mL, the temperature will change from 137°C to_____°C.

Answers

Answer:

\(\boxed {\boxed {\sf 232.9 \textdegree C}}\)

Explanation:

This question asks us to find the temperature change given a volume change. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:

\(\frac {V_1}{T_1}= \frac{V_2}{T_2}\)

The volume of the gas starts at 250 milliliters and the temperature is 137 °C.

\(\frac{250 \ mL}{137 \textdegree C}= \frac{V_2}{T_2}\)

The volume of the gas is increased to 425 milliliters, but the temperature is unknown.

\(\frac{250 \ mL}{137 \textdegree C}= \frac{425 \ mL}{T_2}\)

We are solving for the new temperature, so we must isolate the variable T₂. First, cross multiply. Multiply the first numerator and second denominator, then multiply the first denominator and second numerator.

\(250 \ mL * T_2 = 137 \textdegree C * 425 \ mL\)

Now the variable is being multiplied by 250 milliliters. The inverse of multiplication is division. Divide both sides of the equation by 250 mL.

\(\frac{250 \ mL * T_2}{250 \ mL}=\frac{ 137 \textdegree C * 425 \ mL}{250 \ mL}\)

\(T_2=\frac{ 137 \textdegree C * 425 \ mL}{250 \ mL}\)

The units of milliliters (mL) cancel.

\(T_2=\frac{ 137 \textdegree C * 425 }{250 }\)

\(T_2= \frac{58225}{250} \textdegree C\)

\(T_2=232.9 \textdegree C\)

The temperature changes to 232.9 degrees Celsius.

In an experiment, 8.50 g of methane, CH4, was reacted with 15.9 g of oxygen gas to produce carbon dioxide and water. Determine the percentage yield if 9.77 g of carbon dioxide was obtained in the lab.

Answers

Answer:

89.3 %

Explanation:

M(CH4) = 12+ 4*1 = 16 g/mol

M(O2) = 2*16 = 32 g/mol

M(CO2) = 12 + 2*16 = 44 g/mol

8.50 g * 1 mol/16 g = 0.5313 mol CH4

15.9 g * 1 mol/32 g = 0.4969 mol O2

9.77 g * 1 mol/44 g = 0.2220 mol CO2

1)                                  CH4        + 2O2 -----> CO2 + 2H2O

from reaction             1 mol          2 mol

given                       0.5313 mol   (0.4969 mol)

1 mol CH4              --- 2 mol O2

0.5313 mol  CH4  --- x mol O2

x= 2*0.5313 = 1.0626 mol O2

We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.

2)                               CH4        + 2O2 -----> CO2 + 2H2O

from reaction                             2 mol        1 mol

given                                      0.4969 mol   x mol

x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield

3)

Practical yield CO2 = 0.2220 mol

Theoretical yield CO2 = 0.2485 mol

% yield = (0.2220/0.2485)*100% = 89.3 %

what is the colour of [Mn(H2O)6]2+

Answers

The color of [Mn(H2O)6]2+ is pale pink or light purple.

[Mn(H2O)6]2+ is a complex ion containing a central Mn2+ ion surrounded by six water molecules in an octahedral arrangement. The color of the complex is due to the d-electron transitions of the Mn2+ ion, which can absorb certain wavelengths of light and reflect others.

In the case of [Mn(H2O)6]2+, the complex absorbs light in the green to yellow range and appears pale pink or light purple to the human eye. The exact color can depend on the concentration of the complex and the specific conditions of the experiment.

The color of metal complexes is an important property that can be used to identify and characterize them in various fields such as biochemistry, environmental science, and materials science.

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How could you explain why soap is able to clean the oil and dirt off our bodies?

Answers

Answer:

When you wash your hands with soap, it dislodges the dirt, grease, oils, and disease-ridden fecal matter particles on your hands by creating these micelles. Surrounded by the soap, the oil molecules become suspended and distributed in the water rather than stubbornly clinging to your skin.

Answer:

Soap has two different types of molecules, a non-polar and a polar. The non-polar molecules attract the fats while the polar molecules make the soap, fats, and dirt dissolve in water.

Explanation:

WILL GIVE BRANLIEST

1)how many liters of HCl are produced when 47.2 L of chlorine are reacted with excess hydrogen at STP

2)if you need to make 24.0 g LiOH , how many grams of Li3N must you react with excess water?

3)How many moles of hydrogen gas can be produced from 13.2 moles of hydrochloric acid (HCl)

4)if 34.9g of copper (ll) chloride reacts with 42.1g of sodium nitrate what is the limiting reactant?

Answers

Answer to question 2)
WILL GIVE BRANLIEST1)how many liters of HCl are produced when 47.2 L of chlorine are reacted with excess

This is an unbalanced equation representing a chemical reaction HgO->Hg+O2 (two is supposed to be small and on the bottom right part of the O) Which equation is the correctly balanced chemical equation for this reaction? A. HgO->Hg+20 (and a tiny 2 next to the 20) B. 2Hgo->Hg+0 (and a tiny 2 next to the 0) C. 2HgO->2Hg+0 (and a tiny 2 next to the 0) D. 2Hgo->Hg+20 (and a tiny 2 next to the 20)

Answers

Answer: C. \(2HgO\rightarrow 2Hg+O_2\)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The skeletal chemical equation will be:

\(HgO\rightarrow Hg+O_2\)

The balanced chemical equation will be:

\(2HgO\rightarrow 2Hg+O_2\)

The correctly balanced chemical equation for the reaction \(HgO - > Hg + O_{2}\) is: C. \(2HgO - > 2Hg + O_{2}\)

The law of conservation of mass states that mass can neither be created nor destroyed; it can only be transferred from one location to another. As a result, the mass of the products is required to be the same as the mass of the reactants.

On both the  reactant and product sides of the reaction, the identical amount of atoms of each element is required. Therefore, the equations used in chemistry are balanced.

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What is a key difference between chemical and nuclear reactions?

A. In chemical reactions, new compounds are formed. In nuclear reactions, compounds are destroyed.
B. Chemical reactions involve electron rearrangements. Nuclear reactions involve changes to the nucleus.
C. Chemical reactions involve large changes in energy. Nuclear reactions absorb or release small amounts of energy.
D. In chemical reactions, only alpha radiation is emitted. In nuclear reactions, alpha, beta, and gamma decay may occur.

Answers

Answer:

B

Explanation:

Chemical reactions involve electron rearrangements. Nuclear reactions involve changes to the nucleus.

Answer:

B

Explanation:

Which of the following represents a double-displacement reaction?
a. ABC ➡️AB +C
b. A+B ➡️AB
c. AB + CD➡️AD + CB
d. A + BC ➡️AC + B

Answers

It’s C! Here’s an equation you can refer to that’ll help in the future!
AX + BY —> AY + BX
The first letter of the first letter of the 1st reactant and the last letter of the 2nd reactant go together to make a new product. The second letter of the 2nd reactant and the second letter 1st reactant go together.


12. Determine the number of moles of boric acid that react in the equation to produce 10 moles of water.

Answers

In the preceding equation, 6.67 moles of boric acid (\(H_3BO_3\)) will react to generate 10 moles of water (\(H_2O\)).

To determine the number of moles of boric acid that react in the equation to produce 10 moles of water, we need to examine the balanced chemical equation and use stoichiometry.

1. Begin by examining the balanced chemical equation for the reaction involving boric acid and water. Let's assume the equation is:

  \(3H_2O\) + \(3H_2O\) -> \(B_2O_3\) + \(6H_2O\)

2. From the balanced equation, we can see that 2 moles of boric acid (H3BO3) react with 3 moles of water (\(H_2O\)) to produce 6 moles of water (\(H_2O\)).

3. Use the given information that 10 moles of water (\(H_2O\)) are produced. Since the stoichiometric ratio between boric acid and water is 2:3, we can set up a proportion to find the number of moles of boric acid:

  2 moles \(H_3BO_3\) / 3 moles \(H_2O\) = x moles \(H_3BO_3\) / 10 moles \(H_2O\)

4. Cross-multiply and solve for x:

  (2 moles \(H_3BO_3\))(10 moles \(H_2O\)) = (3 moles \(H_2O\))(x moles \(H_3BO_3\))

  20 moles \(H_2O\) = 3x moles \(H_3BO_3\)

5. Divide both sides of the equation by 3 to isolate x:

  x moles \(H_3BO_3\) = (20 moles \(H_2O\)) / 3

6. Calculate the value of x:

  x moles \(H_3BO_3\) ≈ 6.67 moles \(H_3BO_3\)

Therefore, approximately 6.67 moles of boric acid (\(H_3BO_3\)) will react to produce 10 moles of water (\(H_2O\)) in the given equation.

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Why are gamma rays not able to reflect off a mirrors surface

Answers

Answer:

the Ray's go right through it

Explanation:

the Ray's are so small they punch right through them

Answer:

Explanation:

The reason why is based in something called the plasma frequency of the metal of a mirror. A metal, as you may know, is composed of a series of atom (ion, effectively) cores - nuclei, together with some, but not all, of their bound electrons - which contribute the remaining outermost electrons of their unbound forms to a communally shared "electron sea" - kind of like a giant, distributed omnidirectional covalent bond that extends all throughout the whole metal crystal (here we're just considering a single crystal for simplicity). The electrons are quantumed out all over the full extent of the crystal and effectively form a sort of "gas" throughout and permeating the metal.

When an electromagnetic wave approaches that gas, the free charges within it - the electrons - start oscillating, and as they do so, they set up another wave going outward at the same time as the first is going in. This begins as soon as the first wave begins to impinge.

However, if the wave oscillation is fast enough, the electrons can't keep up due to their mass, and thus they are unable to form the reflected wave. The frequency at which this occurs is called the metal's plasma frequency (and is inversely proportional to the square root of the mass, so that a high mass particle would have a lower plasma frequency). The name comes from the fact that the metal can be thought of in a sense as a kind of "solid plasma" - ions with free electrons, the difference with what most people think of as a "plasma" being here the ions are not free to move about of their own accord.

Classify the following phase changes as endothermic or exothermic.1) liquid to solid2) solid to liquid3) gas to liquid4) solid to gas5) liquid to gas6) gas to solid

Answers

Exothermic and endothermic process are involved in changing of the state which is given below.

Conversion of a liquid into a solid is an exothermic process because all the particles come closer to each other, and also the thermal energy of the substance decreases.Conversion of a solid into a liquid is an endothermic process because all the particles go far apart from each other, and also the thermal energy of the substance increases, which requires the absorption of heat.Conversion of a gas into a liquid is an exothermic process because all the particles come closer to each other, and also the thermal energy of the substance decreases.Conversion of a solid into a gas is an endothermic process because all the particles go far apart from each other, and also the thermal energy of the substance increases.The conversion of a liquid into a gas is an endothermic process because all the particles go far apart from each other, and also the thermal energy of the substance increases.Conversion of a gas into a solid is an exothermic process because all the particles come closer to each other, and also the thermal energy of the substance decreases.

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A new material was produced in a laboratory by bonding atoms of

different elements together in a unique arrangement. Other laboratories

were able to reproduce these results, producing the same material with

the same elements in the same arrangement. What type of matter was

produced?

*

Answers

Answer:

A compound

Explanation:

A compound is a substance formed from the chemical combination of atoms of two or more elements together.

A chemical compound always contains the same kinds of atoms of elements combined together in as specific ratio by mass and can be represented by a chemical formula. For example, water is a compound formed from the chemical combination of hydrogen and oxygen atoms in the ratio of 2 : 1. It has a chemical formula H2O.

A pure compound also always have the same chemical properties irrespective of the source of the compound. For example, chemically pure has similar properties irrespective of whether it is obtained from rain, streams or underground wells.

Therefore, if a new material was produced in a laboratory by bonding atoms of different elements together in a unique arrangement and other laboratories were able to reproduce these results, producing the same material with the same elements in the same arrangement, then the substance must be a compound.

Which hypothesis of Thomson was later found to be not true by Rutherford and why?​

Answers

Answer:

Explanation:

The electrons revolved around the nucleus, like the rings revolving around Saturn. In 1911, Rutherford showed that Thomson's model was "wrong": the distribution of positive and negative particles was not uniform. Rutherford showed that the atom contains a small, massive, positively charged nucleus.

The Thomson's atomic model is also called the plum pudding model. His atomic model was discarded after the discovery of Rutherford's model of atom.

What is Thomson's atomic model?

According to Thomson's atomic model, an atom is considered as a uniform sphere of positive electricity with electrons embedded throughout which gives the most stable arrangement like raisins scattered in a plum pudding.

Rutherford showed that Thomson's model is wrong, because the distribution of positive and negative particles was not uniform. According to Rutherford's model most of the mass and positive charge of an atom is concentrated in a very small region called the nucleus.

The nucleus at the center of atom is surrounded by negatively charged particles which balance the positive charge on the nucleus. Thus the atom as a whole is electrically neutral.

Thus the negative charge is distributed through out the positive charge is the wrong hypothesis of Thomson's model.

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7. What happens at the atomic level when a metal is subjected to pressure, such as a blow from a hammer? The metal cations are pushed together, and the crystal shatters. Valence electrons travel from one end of the metal to the other. Valence electrons transfer permanently from one metal atom to another. The metal cations easily slide past one another.

Answers

When a metal is subjected to pressure, such as a blow from a hammer, the metal cations easily slide past one another. This is due to the unique properties of metallic bonding and the arrangement of atoms in a metal lattice.

In a metal, the atoms are held together by metallic bonds, which are formed by the sharing of valence electrons among all the atoms in the lattice. These delocalized valence electrons move freely throughout the metal, creating a sea of electrons that surround and hold the metal cations together. The metal cations, which are positively charged ions, are arranged in a regular and repeating pattern within the lattice.

When pressure is applied to a metal, the metal cations are pushed closer together. However, due to the presence of the delocalized electrons, the metal cations can easily slide past one another without the crystal structure shattering. This ability of metal cations to slide past each other is known as plastic deformation, and it is a characteristic feature of metals.

The delocalized electrons act as a lubricant, reducing the resistance between the metal cations as they slide. This phenomenon allows metals to be malleable and ductile, meaning they can be bent, shaped, and drawn into wires without breaking.

It is important to note that during this process, there is no transfer of valence electrons from one metal atom to another. The delocalized electrons remain within the metal lattice, maintaining the metallic bonding. The movement of the valence electrons facilitates the flow of electrical current in metals, contributing to their high electrical conductivity.

In summary, when a metal is subjected to pressure, the metal cations easily slide past one another due to the presence of delocalized electrons. This property allows metals to be malleable and ductile, distinguishing them from other types of materials.

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State and explain the three basic properties of element​

Answers

Answer: Some are solid, some are gaseous, a few are liquid. Some are metallic: they have a peculiar lustre; some are coloured (like sulfur) or colourless. Some have a low density; some have a high density. Some are malleable and ductile; some are brittle. Some conduct electricity and heat well; some don’t.

Many metals tend to have structural uses. Nonmetallic elements less so.

Metals tend to have crystal forms featuring close-packed centro-symmetrical structures. Nonmetallic elements tend to have crystal structures featuring more open and directionally packed structures.

Some are especially toxic; some are essential to life; some are both depending on exposure level.

Most are stable; some are less so.

Some elements are highly reactive; some are almost inert (helium, neon, and argon may be completely inert in ambient conditions).

Many metals have basic oxides; quite a few oxides of nonmetallic elements form acids when they are dissolved in water. Some elements can go both ways.

There are many generalisations you can make about metallic and nonmetallic elements, and quite a few exceptions at the margins.

Explanation:

Given :-

State and explain the three basic properties of element.

Answer :-

Some properties of an element can be observed only in a collection of atoms or molecules of the element. These properties include color, density, melting point, boiling point, and thermal and electrical conductivity.

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Answered by - ItzMaster

an aqueous solution of hydrobromic acid is standardized by titration with a 0.186 m solution of calcium hydroxide. if 14.3 ml of base are required to neutralize 23.8 ml of the acid, what is the molarity of the hydrobromic acid solution?

Answers

The molarity of the hydrobromic acid solution 0.223 M.

Volume of Ca(OH)₂, (V₁) = 11.9mL = 14.3 × 10⁻³ L

Strength of Ca(OH)₂, (S₁) = 0.186 M

Volume of HBr, (V₂) = 23.8 mL= 23.8 × 10⁻³ L

To find out Strength of HBr, (S₂) = (?) M

The Balanced chemical equation of the acid base reaction is given as,

Ca(OH)₂ + 2HBr → CaBr₂ + 2H₂O

1mol         2mol

For neutralization the mole ratio HBr  :Ca(OH)₂ = 2 : 1

So we can write,

S₂ × V₂ / S₁ × V₁ = 2/1

⇒ S₂ = (2 × S₁ × V₁) / V₂

⇒ S₂ = (2 × 14.3 × 10⁻³ L× 0.186 M) / 23.8 × 10⁻³ L

⇒ S₂ ≈ 0.223 M

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What is the molality of a solution that contains 31.0 g HCI in 5.00 kg water?

Answers

The molar mass of HCl is:
Molar mass (H) + Molar mass (Cl) = 1.007 g/mol + 35.453 g/mol = 36.460 g/mol

Now, calculate the number of moles of HCl:
moles = mass / molar mass
moles = 31.0 g / 36.460 g/mol ≈ 0.850 mol

Next, calculate the mass of water (solvent) in kilograms:
mass of water = 5.00 kg

molality = moles of solute / mass of solvent (in kg)
molality = 0.850 mol / 5.00 kg ≈ 0.170 m

Helium atoms emit light at several wavelengths. Light from a helium lamp illuminates a diffraction grating and is observed on a screen 50. 00 cm behind the grating. The emission at wavelength 501. 5 nm creates a first-order bright fringe 21. 90 cm from the central maximum.

Answers

the spacing between the lines of the diffraction grating is 1.200 × 10^-5 cm.

We can use the equation for the diffraction of light by a grating to determine the spacing between the lines of the grating:

d * sin(theta) = m * lambda

where d is the spacing between the lines of the grating, theta is the angle between the incident light and the diffracted light, m is the order of the bright fringe, and lambda is the wavelength of the light.

We know that the first-order bright fringe for the emission at wavelength 501.5 nm is located 21.90 cm from the central maximum. Since the central maximum occurs when theta = 0, we can use this information to find the angle of diffraction:

d * sin(theta) = m * lambda

d * sin(theta) = 1 * 501.5 nm

sin(theta) = (501.5 nm) / d

For the first-order bright fringe, m = 1, so we can substitute the given values and solve for d:

d * sin(theta) = m * lambda

d * sin(theta) = 501.5 nm

d = (501.5 nm) / sin(theta)

d = (501.5 nm) / sin(arctan(21.90 cm / 50.00 cm))

d = 1.200 × 10^-5 cm

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How many significant figures are in 340500

Answers

Answer:

Five significant figures

Explanation:

You have to change the number to standard form

340500 = 3.405×10**5

** means raise to power

10**5

Where five represents the number of significant figures.

Answer:

4!

Explanation:

How many moles of C are needed to produce 4.5 moles of CO?

How many grams of antimony (Sb) are produced when 56.7 grams of antimony oxide (Sb2O3) are used up completely?

A chemist is able to collect 18.3 grams of Sb from the reaction of 42 grams of C with excess Sb2O3. What is the chemist’s percent yield of Sb?

A chemist has 62 grams of Sb2O3 and 33 grams of C available to produce Sb. What is the limiting reagent?

Answers

Answer:  2.25 moles of C, 40.6 grams of Sb, 77%, and

How many moles of C are needed to produce 4.5 moles of CO?

Answer: 2.25 moles of C

Explanation: To answer this question, we need to use a mole ratio, which is a stoichiometric relationship between the amounts in moles of any two substances in a chemical reaction. The balanced equation for the reaction is:

\ce {C} (s) + \ce {O2} (g) \rightarrow \ce {CO} (g) + \ce {CO2} (g) C(s) + OX 2(g) → CO(g) + COX 2(g)

The mole ratio between C and CO is 1:1, which means that for every mole of C that reacts, one mole of CO is produced. Therefore, to produce 4.5 moles of CO, we need 4.5 moles of C.

How many grams of antimony (Sb) are produced when 56.7 grams of antimony oxide (Sb2O3) are used up completely?

Answer: 40.6 grams of Sb

Explanation: To answer this question, we need to use composition stoichiometry, which is the calculation of quantities by weight in a reaction described by a balanced equation. The balanced equation for the reaction is:

\ce {Sb2O3} (s) + \ce {C} (s) \rightarrow \ce {Sb} (s) + \ce {CO} (g) SbX 2OX 3(s) + C(s) → Sb(s) + CO(g)

To find the mass of Sb produced from a given mass of SbX 2OX 3, we need to convert the mass of SbX 2OX 3 to moles using its molar mass, then use the mole ratio between SbX 2OX 3 and Sb to find the moles of Sb produced, and then convert the moles of Sb to mass using its molar mass. The molar masses of SbX 2OX 3 and Sb are 291.5 g/mol and 121.8 g/mol, respectively. The mole ratio between SbX 2OX 3 and Sb is 1:2, which means that for every mole of SbX 2OX 3 that reacts, two moles of Sb are produced.

A chemist is able to collect 18.3 grams of Sb from the reaction of 42 grams of C with excess Sb2O3. What is the chemist’s percent yield of Sb?

Answer: 77%

Explanation: To answer this question, we need to use the concept of percent yield, which is the ratio of the actual yield (the amount of product obtained from a reaction) to the theoretical yield (the maximum amount of product that can be obtained from a reaction) expressed as a percentage. The balanced equation for the reaction is:

\ce {Sb2O3} (s) + \ce {C} (s) \rightarrow \ce {Sb} (s) + \ce {CO} (g) SbX 2OX 3(s) + C(s) → Sb(s) + CO(g)

A chemist has 62 grams of Sb2O3 and 33 grams of C available to produce Sb. What is the limiting reagent?

Answer: C is the limiting reagent

Explanation: To answer this question, we need to use the concept of limiting reagent, which is the reactant that is completely used up in a reaction and thus determines when the reaction stops. The balanced equation for the reaction is:

\ce {Sb2O3} (s) + \ce {C} (s) \rightarrow \ce {Sb} (s) + \ce {CO} (g) SbX 2OX 3(s) + C(s) → Sb(s) + CO(g)

To find the limiting reagent, we need to compare the amounts of SbX 2OX 3 and C in moles and use the mole ratio between them from the balanced equation. The mole ratio between SbX 2OX 3 and C is 1:1, which means that for every mole of SbX 2OX 3 that reacts, one mole of C is needed. Therefore, if we have more moles of one reactant than the other, that reactant is in excess and the other one is limiting. To find the moles of SbX 2OX 3 and C, we need to use their molar masses. The molar masses of SbX 2OX 3 and C are 291.5 g/mol and 12.0 g/mol, respectively.

Since we have more moles of C than SbX 2OX 3, C is in excess and SbX 2OX 3 is limiting. However, another way to find the limiting reagent is to use a formula based on the mole ratio:

Limiting Reagent Formula

Determine the amount of each reactant in moles.In the balanced chemical equation, divide the actual number of moles of each reactant by its stoichiometric coefficient.The limiting reactant is the one with the lowest mole ratio.Using this formula, we can find the limiting reagent.

Since 0.213 < 2.75, SbX 2OX 3 is the limiting reagent.

Hope this helps, and have a great day! =)

How many moles of ammonium sulfate, (NH4)2SO4, can be made from the reaction of 30.0 mol of NH3?

Answers

The reaction is:
2NH3 + H2SO4 -----> (NH4)2SO4
it tells us that 2 moles of ammonia yields 1 mol of Ammonium sulfate.
So we just need to state that:
2 moles NH3 - 1 mol (NH4)2SO4
30 moles NH3 - x
x = (30) (1) / 2 = 15 moles of (NH4)2SO4

Hope this helps! And remember if it does give me a like, please and thank you!

Balancing Quesrion AP chem. How much do I add in each to balance?

Balancing Quesrion AP chem. How much do I add in each to balance?

Answers

a) We have a Fe ion with a positive charge +2, therefore we will also have a Fe ion with a +3 charge.

The charge difference is +1, this means that the Fe3+ ion gained an electron, therefore 1 must be put in front.

\(Fe^{+2}\rightarrow1Fe^{+3}+1e^-\)

b) Now, in the second reaction we have 4 oxygens in the reactants and one in the products, so we put the coefficient 4 in front of H2O and thus we will have 4 oxygens in the products.

Now it would be necessary to balance the hydrogens, we have 8 hydrogens in the products and 1 in the reactants, so we put the coefficient of 8 in front of the hydrogen

Now the Mn, there is an atom of Mn in the reactants, the coefficient 1 is placed in front of the Mn+2.

So far the balanced reaction will go like this:

\(Mn_{}O^-_{4^{}}+8H^++ne^-\rightarrow1Mn^{+2}+4H_2O\)

We need to balance the electrons. For that, we see what is the oxidation state of Mn in the molecule MnO4-. Oxygen has an oxidation state of -2.:

\(Mn^{+7}\lbrack O^{-2}_4\rbrack^{-8}\)

The oxidation state in the MnO4 molecule is +7, therefore it must gain 5 electrons to be left with a +2 charge.

\(Mn_{}O^-_{4^{}}+8H^++5e^-\rightarrow1Mn^{+2}+4H_2O\)

And so we have the balanced equation.

what is the percent yield if the combustion of gasoline results in 680 grams of steam produced when a theoretical yield is 985 grams of steam?

Answers

Answer:

69%

Explanation:

Percent yield = ?

Theoretical yield = 985 grams

Experimental Yield = 680 grams

Percent Yield = Experimental Yield / Theoretical Yield * 100

Percent Yield = 680 / 985  * 1 00

Percent Yield = 0.690 * 100 = 69%

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Cyanobacteria are photosynthetic single-celled organism that thrive on the sunlight and nutrients. Cyanobacteria blooms (blue-green algae) are a frequent occurrence in the Great Lakes, particularly in Lake Erie, Green Bay, and Saginaw bay in august and early September. Which statement describe the main causes of the Cyanobacteria blooms in the Great Lakes?

Someone plsss help me I will make you as brain plsssCyanobacteria are photosynthetic single-celled organism

Answers

Answer:

2 only

Explanation:

Hope this helps

Answer:

The answer is two and three.

Explanation:

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