Answer:
4.089, 4.87 4.881 , 4.89
Step-by-step explanation: this is true because for 4.89 you would just add a 0 to make it 4.890
A train passes two cars moving in the direction at 45km/hr and 50km/hr in 36 sec and 54 sec respectively. What is the length of the train?
Let the speed of the train be v km/hr and its length be l meters. The first car is moving at 45 km/hr while the second car is moving at 50 km/hr. Therefore, the speed of the train relative to the first car = (v - 45) km/hr. Similarly, the speed of the train relative to the second car = (v - 50) km/hr.
Using the formula distance = speed × time, we can calculate the distances covered by the train in passing each car. For the first car, the distance covered is l and the time taken is 36 seconds. Therefore, distance = speed × time gives us l = (v - 45) × (36/3600) km. For the second car, the distance covered is l and the time taken is 54 seconds. Therefore, distance = speed × time gives us l = (v - 50) × (54/3600) km.
Equating both these expressions for l, we get:(v - 45) × (36/3600) = (v - 50) × (54/3600)Simplifying this expression, we get v = 75 km/hr. Now we can substitute this value of v into either of the expressions for l that we derived earlier and get the length of the train. Using the first expression, we get: l = (v - 45) × (36/3600) km= (75 - 45) × (36/3600) km= 0.4 km= 400 meters Therefore, the length of the train is 400 meters. The length of the train is 400 meters. To solve this question, we first need to understand that the train passes two cars that are moving at different speeds. Using the relative speeds of the train and each car, we can set up two equations for the distances covered by the train in passing each car. Equating these expressions for the distances, we can solve for the speed of the train. Finally, substituting this value of the speed into one of the expressions for the distance covered by the train, we can find the length of the train.
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The table below represents the closing prices of stock TUV for the first five
days it was open. Using your calculator, what is the equation of exponential
regression that fits these data?
Day
1
2
3
4
5
Value
3.75
9.375
23.438
58.594
146.484
O A. y= 1.75 2.35*
OB. y= 2.5 3.5*
OC. y= 1.25.2.75*
OD. y= 1.5-2.5*
The equation of exponential regression that fits the data is given as follows:
y = 1.5(2.5)^x.
How to define an exponential function?An exponential function has the definition presented as follows:
y = ab^x.
In which the parameters are given as follows:
a is the value of y when x = 0.b is the rate of change.To obtain the equation of exponential regression, we must insert the points of the data-set into a calculator.
The points are given as follows:
(1, 3.75), (4, 9.375), (3, 23.438), (4, 58.594), (5, 146.484).
Inserting these points into a calculator, the equation is given as follows:
y = 1.5(2.5)^x.
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state five ways by which someone can contact HIV and AIDS
A paper airplane is thrown from the roof of a house and travels 7 feet through the air. The paper airplane's flight path makes a 30∘angle with the ground. How far from the base of the house does the paper airplane land on the ground?
Group of answer choices
3.5 feet from the house
7.12 feet from the house
4.04 feet from the house
6.06 feet from the house
Dan bought a new computer for $900. Each year, the value of the computer decreased by 25% of the previous year’s value.
At this rate, what can Dan expect the approximate value of the computer to be after 12 years?
A $73
B. $90
C. $29
D. $85
Answer:
$29, that is the answer for this question
Answer the questions about the graph shown below.
Part A) What is the price per ticket?
Part B) What equation can be used to represent the line?
Part C) If the theater were to sell 328 tickets, how much money would they make?
Part D) Is this relationship proportional? How do you know?
Therefore , the price per ticket is $12,the equation used is y=12x, the theatre made $3936 by selling 328 ticket and the relationship is proportional.
What is equation?An algebraic equation is a linear equation. Each term in a linear equation is either a constant or the result of a constant plus one variable. In the case of a linear equation with two variables, the graph is a straight line.
Here,
A) From the given we can find the price per ticket
which is => y/x
=> 60/5
=>12
Therefore the price per ticket is $12
B)The equation can be used to represent the graph is
y= 12x
C) The theater were to sell 328 tickets they would make
=> 328*12=3936
Therefore the money would they make is $3936
D)The relationship proportional as we can see from the graph
Therefore , the price per ticket is $12,the equation used is y=12x, the theatre made $3936 by selling 328 ticket and the relationship is proportional.
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what is (6^2)(-3^5) in simpliest form?
The simplified form of the expression (6^2)(-3^5) is -8,748.
To simplify (6^2)(-3^5), we must first evaluate the exponents.6^2 = 36, since 6 × 6 = 36.3^5 = 243,
since 3 × 3 × 3 × 3 × 3 = 243.Now, we substitute the values into the expression:
(6^2)(-3^5) = (36)(-243)
Next, we multiply the values to obtain the simplified form:
(36)(-243) = -8,748
Therefore, (6^2)(-3^5) in its simplest form is -8,748.According to the rules of exponents, when we raise a number to an exponent, the result is the number multiplied by itself the number of times represented by the exponent.
For instance, 6^2 means 6 multiplied by itself 2 times, which is equal to 36.3^5 means 3 multiplied by itself 5 times, which is equal to 243.
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a study indicates that the weights of adults are normally distributed with a mean of 140 lbs and a standard deviation of 25 lbs. what is the probability that a randomly selected adult weights between 120 and 165 lbs?
The probability that a randomly selected adult weighs between 120 and 165 lbs is approximately 0.8186.
Since the weights of adults are normally distributed with a mean of 140 lbs and a standard deviation of 25 lbs, we can use the standard normal distribution to calculate the probability.
We first need to standardize the values using the formula: z = (x - μ) / σ, where x is the weight, μ is the mean, and σ is the standard deviation.
For x = 120 lbs, z = (120 - 140) / 25 = -0.8, and for x = 165 lbs, z = (165 - 140) / 25 = 1.0. We can then use a calculator to find the probability between -0.8 and 1.0, which is approximately 0.8186.
Thus, the chance of picking an adult at random who weighs between 120 and 165 lbs is roughly 0.8186.
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The following are as frequency (count) histogram describes the number of deer at a particular wildlife preserve, by age. How many deer are younger than 15 years old?How many deer are in the preserve, in total
Part a
How many deer are younger than 15 years old?
that means
less than 15
< 15
looking at the graph
8+5=13
The answer part a is 13 deerPart b
How many deer are in the preserve, in total?
8+5+5+2+2+2+2=26 deer
the answer is 26 deerKite ABCD is drawn with diagonals. To find the area of ABCD, Alex imagined the kite divided into two triangles. What is the area of ABCD?
The area of kite ABCD is equal to half the product of the sum of its diagonals and the height between them.
How to find the area of ABCD?Since kite ABCD is divided into two triangles by its diagonals, we can find the area of the kite by finding the sum of the areas of these two triangles.
Let AC and BD be the diagonals of the kite, intersecting at point E. Then triangle ABE and triangle CDE are the two triangles formed by the diagonals.
The area of a triangle can be found using the formula: Area = (base x height) / 2
For triangle ABE, the base is AB and the height is the distance from E to the line containing AB. Similarly, for triangle CDE, the base is CD and the height is the distance from E to the line containing CD.
Since the diagonals of a kite are perpendicular and bisect each other, the distance from E to the line containing AB is the same as the distance from E to the line containing CD.
Therefore, the heights of the two triangles are equal.
So, we can find the area of ABCD as follows:
Area of ABCD = Area of triangle ABE + Area of triangle CDE
= (AB x height)/2 + (CD x height)/2
= (AB + CD) x height / 2
Therefore, the area of kite ABCD is equal to half the product of the sum of its diagonals and the height between them.
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Problem 2: Consider the system defined by; x = Ax+ Bu 8-2 1 20 0 where A = 1 10 10 B = 10 ,C={0} and D = 0 1 4 0 0 b) Find the state variable feedback gain vectorr K, so that the closed loop poles can be moved to -10±j*20 and -40 by hand.
The state variable feedback gain vector K needs to be determined to place the closed-loop poles of the system at specified locations (-10±j*20 and -40). This can be achieved by using the pole placement method to calculate the gain matrix K.
In order to place the closed-loop poles at the desired locations, we can use the pole placement technique. The closed-loop poles represent the eigenvalues of the system matrix A - BK, where B is the input matrix and K is the gain matrix. The desired characteristic equation is given by \(s^3\) + 50\(s^2\) + 600s + 1600 = 0, corresponding to the desired pole locations.
By equating the characteristic equation to the desired polynomial, we can solve for the gain matrix K. Using the Ackermann formula, the gain matrix K can be computed as K = [k1, k2, k3], where k1, k2, and k3 are the coefficients of the polynomial that we want to achieve.
To find the coefficients k1, k2, and k3, we can equate the coefficients of the desired characteristic equation to the coefficients of the characteristic equation of the system. By comparing the coefficients, we obtain a set of equations that can be solved to determine the values of k1, k2, and k3.
After obtaining the values of k1, k2, and k3, the gain matrix K can be constructed, and the closed-loop poles of the system can be moved to the desired locations (-10±j*20 and -40). This ensures that the system response meets the specified performance requirements.
In conclusion, the state variable feedback gain vector K can be determined by solving a set of equations derived from the desired characteristic equation. By choosing appropriate values for K, the closed-loop poles of the system can be placed at the desired locations, achieving the desired performance for the system.
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For each rhombus, solve for x.
67
K
L
110°
N
8x - 5
M
Answer:
x = 5
Step-by-step explanation:
The diagram shows that the rhombus is split into two isosceles triangles, LKM and NMK.
Isosceles triangles have two sides equal in length and the angles opposite these sides are always congruent and equal.Thus, the three angles in triangle LKM are 110, (8x - 5), and (8x - 5).
The Triangle Angle Sum Theorem says that the sum of the measures of the interior angles in a triangle always equals 180°.Thus, we can solve for x by setting the sum of the measures of the three angles in triangle LKM equal to 180:
(8x - 5) + (8x - 5) + 110 = 180
(8x + 8x) + (-5 - 5 + 110) = 180
16x + 100 = 180
16x = 80
x = 5
Thus, x = 5
Optional step:
We can check that we've correctly solved for x by plugging in 5 for x in (8x - 5) twice for both angles, adding the result to 110, and seeing if we get 180 on both sides of the equation:
(8(5) - 5) + (8(5) - 5) + 110 = 180
(40 - 5) + (40 - 5) + 110 = 180
35 + 35 + 110 = 180
70 + 110 = 180
180 = 180
Thus, x = 5 is correct.
Lindsey purchased a random sample of 25 tomatoes at the farmers market. The 95% confidence interval
for the mean weight of the tomatoes is 90.6 to 112.4 grams.
What is the Point Estimate?
What is the Margin of error?
Answer:
3 & 5
Step-by-step explanation:
The value of point estimate is 101.5 and value of margin of error is 10.9 gram if the Lindsey purchased a random sample of 25 tomatoes at the farmers market.
What is the margin of error(MOE)?It is defined as an error that provides an estimate of the percentage of errors in real statistical data.
The formula for finding the MOE:
\(\rm MOE = Z\times \dfrac{s}{\sqrt{n}}\)
Where Z is the z-score at the confidence interval
s is the standard deviation
n is the number of samples.
Let's suppose m is a point estimate and ME is the margin of error.
The structure of the confidence interval is:
(m—ME, m + ME)
The given confidence interval is (90.6, 112.4)
Then, m—ME = 90.6 ..... (1)
m + ME = 112.4 ..... (2)
After solving equation (1) and (2) we get:
m = 101.5
ME = 10.9 grams
Thus, the value of point estimate is 101.5 and value of margin of error is 10.9 gram if the Lindsey purchased a random sample of 25 tomatoes at the farmers market.
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What is the answer to this problem solving for X? (12x-8=10x+6)
Kate writes an algebraic expression using each of the variables, x and y, only once. The first expression she writes uses x and y as factors. Then she writes another expression that uses x and y as terms. If x and y are both negative integers, write a comparison between the two expressions
A more valuable statement is produced when x and y are used as factors rather than as words.
Given,
Kate only uses the variables x and y once in her algebraic expression. She uses x and y as factors in the first expression that she creates. Then she creates another expression using the terms x and y.
We have to write a comparison between two expressions if x and y both are negative integers;
Here,
x and y are factors in her first expression;
xy
The terms x and y are written in her second expression;
x + y
Given that both x and y are negative integers, then;
-x × -y = xy ............... 1
-x + (-y) = - x - y
= - (x + y) .............. 2
Because of this, the value of the x and y factors is higher than when x and y are terms.
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A recipe uses 6 tablespoons of butter for every 8 oz of cheese. the rate is __ tablespoons for every 1 oz. the raze is __ oz for every 1 tablespoon.
1/4 or .75
6 divided by 4 equal 1/4 or .75
for a standard normal distribution, find: p(-1.62 < z < 2.01)
The probability of the interval -1.62 < z < 2.01 in a standard normal distribution is approximately 0.9262 or 92.62%.
In a standard normal distribution, the mean is 0 and the standard deviation is 1. The z-score represents the number of standard deviations a data point is from the mean. To find the probability of a specific interval, we calculate the area under the curve between the corresponding z-values.
Given the interval -1.62 < z < 2.01, we need to find the area under the standard normal curve between these two z-values. This can be done using a standard normal distribution table or by using a statistical software or calculator.
By looking up the z-values in the table or using software, we find the corresponding probabilities: P(z < -1.62) = 0.0526 and P(z < 2.01) = 0.9788.
To find the probability of the interval -1.62 < z < 2.01, we subtract the probability of the lower bound from the probability of the upper bound: P(-1.62 < z < 2.01) = P(z < 2.01) - P(z < -1.62 = 0.9788 - 0.0526 = 0.9262.
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Plz help I don’t understand how to do this problem
Answer:
a) 6b) 3t² - 17t + 28c) 3t² - 5t - 2Step-by-step explanation:
Given function:
g(t) = 3t² - 5t + 4a) g(2)
g(2) = 3*2² - 5*2 + 4 = 3*4 - 10 + 4 = 12 - 6 = 6b) g(t - 2)
g(t - 2) = 3(t - 2)² - 5(t - 2) + 4 = 3(t² - 4t + 4) - 5t + 10 + 4 = 3t² - 12t + 12 - 5t + 16 = 3t² - 17t + 28c) g(t) - g(2)
g(t) - g(2) = 3t² - 5t + 4 - 6 = 3t² - 5t - 2the question is long so I will send a pic lol <3
Explanation
Step 1
let x represents the year
let y represents the hours of electricity generated ( in millons)
then, we have two coordinates of the function
\(undefined\)Find it fast pleasee
Answer:
A
Step-by-step explanation:
Additive inverse is (5/3) and multiplicative inverse is (-3/5). Their product is (-1)
Inverse means the opposite of something.
In this case the opposite of -5/3 is 5/3.
So the answer is: 5/3
order these from least to greatest
9, 3, π
Answer:
3 pi 9
Step-by-step explanation:
Graph the line that passes through the point (1,-1) and is parallel to another line whose slope is 1 .
Answer:
The image is inserted below.
Step-by-step explanation:
The blue line is the line that passes through the point (1,-1) which is marked as A on the graph.
The green line is the new line you need to graph that is parallel to the original line and has a slope of 1.
◄)) Divide:
4) 8,567
R
Submit
The Remainder is 3 and the Quotient is 2141.
What is meant by long term division?Long division is a mathematical technique for breaking down large numbers into smaller groups or parts. It is beneficial to divide a problem into simple and easy steps. Dividends, divisors, quotients, and remainders are all part of the long divisions.The layout of short division and long division is similar, but there are two major differences. Long division is used when dividing multi-digit numbers by two-digit numbers, whereas short division is used when dividing multi-digit numbers by one-digit numbers. Follow the steps below to find the square root of 5 using the long division method. As a result, the value of root 5 is 5 = 2.2360... Long division can be used to calculate the value of the square root of any non-perfect square number.Therefore,
The given Divisor = 4 and Dividend = 8567
4 ÷ 8567
= 2141.75
The Quotient is 2141 and the Remainder is 3
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A quadrilateral with four congruent sides and four congruent angles is:
A
Trapezium
B
Square
C
Rhombus
D
Rectangle
B. Square, A quadrilateral with four congruent sides and four congruent angles is a Square.
A square is a quadrilateral with four congruent sides and four congruent angles (right angles). All sides of a square are equal in length, and all angles are right angles (90 degrees). This makes it a special type of rectangle and a special type of rhombus.
In a rhombus, all four sides are equal in length. A square is also a special type of rhombus in which all four sides are equal and it is also a special type of rectangle with four congruent sides and four congruent angles is a rhombus.
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In the diagram, AC-x, BC-x, and AB -
simplest form.
10√√2. Find the value of x. Write your answer in
What is the answer? Please
Select the correct answer. histogram chart. car prices on x-axis. number of cars sold over 10 years on y-axis. x-axis ranges from 0 to 40000. y-axis ranges from 0 to 700. between 20000 and 30000, bars height over 700. between 5000 and 10000, 40000 and 45000, bar height is 200. a car salesman sells cars with prices ranging from $5,000 to $45,000. the histogram shows the distribution of the numbers of cars he expects to sell over the next 10 years. the salesman has observed that many students are looking for cars that cost less than $5,000. if he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years, how will the distribution be affected?
The bar height for the price range of less than $5,000 will increase by 200.
In the given histogram, the x-axis represents the car prices ranging from $0 to $40,000, while the y-axis represents the number of cars sold over 10 years, ranging from 0 to 700.
Based on the provided information, we can observe that between the price ranges of $20,000 and $30,000, the bar height exceeds the maximum y-axis value of 700. Similarly, between the price ranges of $5,000 and $10,000, and $40,000 and $45,000, the bar height is indicated as 200.
If the car salesman decides to include cars with prices less than $5,000 and projects selling 200 of them over the next 10 years, the distribution will be affected as follows:
The bar representing the price range of less than $5,000 will increase in height by 200, indicating the projected sale of those additional cars. This means that the histogram will show a higher number of cars sold in the lower price range, reflecting the demand from students and the inclusion of more affordable cars in the sales strategy. This modification will result in a redistribution of the bars, with an additional bar added to represent the projected sales of cars below $5,000.
Overall, the distribution in the histogram will be affected by an increase in the bar height for the price range of less than $5,000 by 200 units, indicating the projected sale of those additional affordable cars over the next 10 years.
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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes the heptagon as shown in the diagram. The area of ΔMSQ is left for a children's playground, and the rest of the garden is planted with flowers. Find the area of the garden planted with flowers.
The relationship between the sides MN, MS, and MQ in the given regular heptagon is \(\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}\)
The area to be planted with flowers is approximately 923.558 m²
The reason the above value is correct is as follows;
The known parameters of the garden are;
The radius of the circle that circumscribes the heptagon, r = 25 m
The area left for the children playground = ΔMSQ
Required;
The area of the garden planted with flowers
Solution:
The area of an heptagon, is;
\(A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )\)
The interior angle of an heptagon = 128.571°
The length of a side, S, is given as follows;
\(\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}\)
\(s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69\)
\(The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52\)
The area of the heptagon MNSRQPO is therefore;
\(A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94\)
\(MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08\)
By sine rule, we have
\(\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}\)
\(sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})\)
\(\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}\)
∠MSQ = 128.571 - 2*23.18 = 82.211
The area of triangle, MSQ, is given as follows;
\(Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}\)
The area of the of the garden plated with flowers, \(A_{req}\), is given as follows;
\(A_{req}\) = Area of heptagon MNSRQPO - Area of triangle ΔMSQ
Therefore;
\(A_{req}\)= 1,842.94 - 919.382 ≈ 923.558
The area of the of the garden plated with flowers, \(A_{req}\) ≈ 923.558 m²
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Josh has a spinner that is divided into 4 equal sections. The sections are colored blac
red, white, and orange. If Josh spins the spinner once, what is the probability it will sto
on the orange section?
3
0
-1
1
Done
The probability that the spinner lands on orange is P ( O ) = 1/4 = 25 %
We have,
The probability that an event will occur is measured by the ratio of favorable examples to the total number of situations possible
Probability = number of desirable outcomes / total number of possible outcomes
The value of probability lies between 0 and 1
Given data ,
The total number of sides for the spinner = 4
Since the spinner is divided into 4 equal sections, each section has an equal chance of being landed on
Therefore, the probability of spinning orange is 1 out of 4, or 1/4, which is equivalent to 25%
We can express this probability as:
P(orange) = 1/4
Hence , the probability that Josh spins orange is 1/4 or 25%
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Solve the equation (x − 1)² - 4 = 44 for X. Show your work.
Answer:
x = 1 ± 4\(\sqrt{3}\)
Step-by-step explanation:
(x − 1)² - 4 = 44
(x - 1)² = (x - 1) (x - 1) = x² - x - x + 1 = x² - 2x + 1
x² - 2x + 1 - 4 = 44
x² - 2x - 3 = 44
x² - 2x - 47 = 0
Use the quadratic formula to find the solutions.
\(\frac{-b± \sqrt{b^{2}-4(ac) } }{2a}\)
We get the answer
x = 1 ± 4\(\sqrt{3}\)
So, the answer is x = 1 ± 4\(\sqrt{3}\)