The percent yield that is required to produce 0.67 grams of HF from 4.0 grams of H2O is 15.1%.
The percent yield is defined as the degree of how much of an item you really get compared to how much you were assumed to induce agreeing to the chemical condition.
In this case, we know that 4.0 grams of H2O created 0.67 grams of HF.
To discover the percent yield, we begin with knowing how much HF we were gathered to induce based on the chemical condition.
The condition for the response between H2O and HF is
H2O + HF --> H3O+ + F-
This condition tells us that for each atom of H2O, we can get one particle of HF. So, ready to utilize the molar mass of water (18 g/mol) to calculate how numerous moles of water we had:
4.0 g / 18 g/mol = 0.2222 mol H2O
Since we ought to get one atom of HF for each particle of H2O, we know that we ought to have created 0.2222 moles of HF. Able to utilize the molar mass of HF (20 g/mol) to change over this to grams:
0.2222 mol HF x 20 g/mol = 4.44 g HF
So, according to the chemical condition, we ought to have created 4.44 grams of HF. In any case, we really as it were produced 0.67 grams of HF.
To discover the percent yield, we utilize the equation:
percent yield = (actual yield / theoretical yield) x 100D
In this case, the theoretical yield is 0.67 grams and our theoretical yield is 4.44 grams. So, we plug those values into the equation:
So the , percent yield = (0.67 g / 4.44 g) x 100% = 15.1D
for 44, the percent yield is 15.1%.
This implies that as it were 15.1% of the HF . we were gathered to urge was really created. The rest was misplaced due to other variables, such as inadequate responses or misfortune amid the exchange handle.
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A gas that has a volume of 28 L , a temperature 45 Celsius and an unknown pressure has its volume increase a 34 L in the temperature decrease to 35 Celsius if I measure the pressure after the change to be 2.0 ATM what was the original pressure of the gas
Answer:
2.5 atm
Explanation:
To find the original pressure of the gas, you need to use the Combined Gas Law. The corresponding equation is:
\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)
In this equation, "P₁", "V₁", and "T₁" represent the original pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the new pressure, volume, and temperature.
Before you can plug the given values into the equation and solve for "P₁", you need to convert the temperatures from Celsius to Kelvin (°C + 273 = K).
The final answer should have 2 sig figs like the least accurate given value.
P₁ = ? atm P₂ = 2.0 atm
V₁ = 28 L V₂ = 34 L
T₁ = 45°C + 273 = 318 K T₂ = 35°C + 273 = 308 K
\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\) <----- Combined Gas Law
\(\frac{P_1(28L)}{318K}=\frac{(2.0 atm)(34L)}{308K}\) <----- Insert values
\(\frac{P_1(28L)}{318K}=0.2208\frac{atm*L}{K}\) <----- Simplify right side
\({P_1(28L)}=70.21atm*L\) <----- Multiply both sides by 318 K
\(P_1=2.5atm\) <----- Divide both sides by 28 L
percent yield of 0.20 g of Al
Answer:
the dividend yield is 4%
Explanation:
The computation of the dividend yield is as follows:
Dividend yield = Dividend per share ÷ current share price per share
= ($0.20 × 4 quarters) ÷ $20
= $0.80 ÷ $0.20
= 4%
hence, the dividend yield is 4%
The same is determined by applying the above formula
b) These are the parts of DNA that carry the robustness of DNA genetic code. -pyrimidines -purines -the carbohydrate -phosphate group
The parts of DNA that carry the robustness of DNA genetic code are the nitrogenous bases, which are divided into two categories: pyrimidines and purines.
Pyrimidines include thymine (T) and cytosine (C), while purines include adenine (A) and guanine (G). These nitrogenous bases pair up with complementary bases to form the rungs of the DNA ladder, and the sequence of these base pairs determines the genetic code. The nitrogenous bases are attached to a sugar molecule, which is known as the carbohydrate, and a phosphate group. Together, these three components make up a nucleotide, which is the building block of DNA.
Hence, The robustness of the DNA genetic code is primarily carried by purines and pyrimidines. Purines include adenine and guanine, while pyrimidines consist of cytosine, thymine, and uracil. These nitrogenous bases form the genetic code by pairing through hydrogen bonds, providing the foundation for DNA's stability and genetic information transmission.
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i need help ASAP!!!!!!
Answer: A
Explanation:
Edge
Explain the importance of Brownian motion to the development of particle theory
Explanation:
Particles in both liquids and gases (collectively called fluids) move randomly. This is called Brownian motion. They do this because they are bombarded by the other moving particles in the fluid. Larger particles can be moved by light, fast-moving molecules.
Brownian motion is named after the botanist Robert Brown, who first observed this in 1827. He used a microscope to look at pollen grains moving randomly in water. At this point, he could not explain why this occurred.
In a cube full of small fast-moving particles, two much larger particles appear to move at random as a result of collisions with the smaller particles.
Brownian motion
But in 1905, physicist Albert Einstein explained that the pollen grains were being moved by individual water molecules. This confirmed that atoms and molecules did exist, and provided evidence for particle theory.
What do you call a substance that can only be separated into two or more simpler substances using chemical changes?
Answer:
Compounds are substances composed of two or more elements chemically combined that can be separated into simpler substances only by chemical means. Water, for example, is a compound because pure water is composed of only H2O molecules.
Pls choose me as brainliest!
What volume of 0.205MK 3
PO 4
solution is necessary to completely react with 118 mL of 0.0110M NiCl 2
? Express your answer to three significant figures.
The volume of the solution that we are going to require is 0.00422 L
What is the stoichiometry?Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in chemical reactions. It involves calculating the amounts of substances involved in a chemical reaction and understanding the ratios of reactants and products based on the principles of conservation of mass.
The first thing that we need is the equation of the reaction as we have it below;
3NiCl₂ + 2K₃PO₄ ---> Ni₃(PO₄)₂ + 6KCl
Number of moles of NiCl₂ = 0.0110M * 118/1000
= 0.001298 moles
We have that;
3 moles of the NiCl₂ reacts with 2 moles of K₃PO₄
0.001298 moles of NiCl₂ reacts with 0.001298 * 2/3
= 0.000865 moles
Then;
Volume = 0.000865 moles/ 0.205
= 0.00422 L
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Missing parts;
What volume of 0.205 M K3PO4 solution is necessary to completely react with 134 mL of 0.0102 M NiCl2?
What practical applications my the chemistry experiment have?
Answer:
Observation
Hypothesis
how often a wave passes a single point per second is called the ____.
A trough
B. frequency
C. crest
D. amplitude
What type of particle reinforced composite has extremely small particles?
Answer:
large particle composite
A pressure of 125,400 Pa is equal to
kPa.
Answer:
it is equal to 125 kPa
Explanation:
move the decimal 3 to the left
What shape would you expect O2 to have?
Every diatomic molecule is having a linear geometry. The shape of dioxygen is linear with double bond between the oxygen atoms.
What is molecule?Molecules are formed by the combination of atoms. There are diatomic , triatomic or tetratomic molecules or simply polyatomic molecules. Molecule are the basic units of compounds.
Oxygen is an electronegative element and is normally exists as diatomic molecules in atmosphere. Oxygen have 6 valence electrons and need two more electrons to achieve stability.
Thus, one oxygen combines with other by sharing two electrons each and forms a double bond between. Thus the oxygen molecules exhibit a linear geometry.
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the output of glycolysis is pyruvate, but the citric acid cycle uses acetyl coa. briefly explain how glycolysis and the citric acid cycle are linked.
The output of glycolysis is pyruvate, but the citric acid cycle uses acetyl CoA. Briefly glycolysis and the citric acid cycle are linked to the results of glycolysis, namely pyruvic acid is converted to acetyl Co-A for the raw material of the citric acid cycle.
Cellular respiration is a complex organic breakdown process at the cellular level that aims to produce ATP that occurs in the mitochondrial matrix. ATP is the energy used by cells to meet their needs in order to carry out various activities. The first stage of cellular respiration is glycolysis. Glycolysis is an energy-releasing reaction that breaks one molecule of glucose into two molecules of pyruvic acid, a NADH and 2 ATP.
The citric acid cycle is a cycle that occurs after glycolysis. In glycolysis, pyruvic acid is produced which is then converted to acetyl Co-A during oxidative decarboxylation. then acetyl co-A is used as raw material for the citric acid cycle to produce 2 ATP, 6 NADH, 2 FADH2, and 4 CO2.
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Can someone answer these please i'll give 25 points it would mean alot to me <3
Answers:
Continental Tropical - 2
Maritime Tropical - 3
Continental Polar - 6
Arctic Air - 5
Maritime Polar - 4
Maritime - 1
Hope this helped! :^)
Answer:
Continental Polar = Cold and dry
Maritime polar = Cold and humid
Maritime tropical = Warm and humid
Continental tropical = Warm and dry
Arctic air = Extremely cold and dry
Maritime = of or related to sea
Explanation:
]
Consider the following intermediate chemical equations.
C(s) +
CO(g) +
O₂(g) → CO(g)
How will oxygen appear in the final chemical equation?
O O2(g) as a product
O O2(g) as a reactant
OO(g) as a product
O 20(g) as a reactant
O₂(g) → CO₂(g)
In the above intermediate chemical equation, oxygen will appear as follows: O₂(g) as a reactant (option B).
What is a chemical equation?A chemical equation in chemistry is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.
According to this question, an intermediate chemical equation is presented as follows:
CO(g) + O₂(g) → CO(g)C(s) + O₂(g) → CO₂(g)As observed in the above chemical equation, oxygen will react in its gaseous form i.e. as a reactant.
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A solution is made by mixing 48.5 g acetone (CH 3
COCH 3
) and 48.5 g methanol (CH 3
OH). What is the vapor pressure of this solution at 25 ∘
C ? What is the composition of the vapor expressed as a mole fraction? Assume ideal solution and gas behavior. (At 25 ∘
C the vapor pressures of pure acetone and pure methanol are 271 and 143 torr, respectively.) The actual vapor pressure of this solution is 161 torr. Explain any discrepancies. P ldeal =
χ acetoon V
=
χ methanol V
=
The solute and solvent do not behave exactly as if they were in the pure state.
We are given that 48.5 g of acetone (CH₃COCH₃) and 48.5 g of methanol (CH₃OH) are mixed to make a solution. We need to determine the vapor pressure of this solution at 25°C and the composition of the vapor expressed as a mole fraction. We are given that the vapor pressures of pure acetone and pure methanol at 25°C are 271 torr and 143 torr, respectively, and we assume ideal solution and gas behavior.
Let the mole fraction of acetone be x₁ and the mole fraction of methanol be x₂. The total number of moles n of solute in the solution is
n = mass of acetone / molar mass of acetone + mass of methanol / molar mass of methanol
= 48.5 / 58.08 + 48.5 / 32.04= 0.8348 mol
The mole fraction x₁ of acetone isx₁ = moles of acetone / total moles= 48.5 / 58.08 / (48.5 / 58.08 + 48.5 / 32.04)= 0.355
The mole fraction x₂ of methanol is
x₂ = 1 - x₁= 1 - 0.355= 0.645
The vapor pressure of the solution is the sum of the vapor pressures of the individual components, multiplied by their respective mole fractions:
P = x₁P°₁ + x₂P°₂
where P°₁ and P°₂ are the vapor pressures of acetone and methanol, respectively. Substituting the values, we get:
P = 0.355 × 271 + 0.645 × 143= 193.39 torr
The actual vapor pressure of the solution is given as 161 torr. There is a discrepancy between the actual vapor pressure and the vapor pressure calculated using the ideal solution model.
This can be due to the fact that the solute-solvent interaction is not perfectly ideal, and the activity coefficients of the solute and solvent are not equal to 1.
In other words, the solute and solvent do not behave exactly as if they were in the pure state.
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At the wavelengths included in Study 1, as the
wavelength of light increases, the reflectance of
Cyanide:
A.
increases only.
B.
decreases only.
C.
increases, then decreases.
D.
decreases, then increases.
Based on the research in Study 1, as the wavelength of light increases, the reflectance of Cyanide: C. increases, then decreases.
What is wavelength?Wavelength is simply defined as the distance (in meters) between two (2) successive crests or troughs of a wave. Thus, wavelength refers to the horizontal distance between two adjacent crests or troughs of a wave.
Generally, there is a linear relationship between the wavelength of light and reflectance. Thus, as the wavelength of light increases, the reflectance of Cyanide in Study 1 increases, before it then decreases.
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Plssssss helpppppp
Consider a beaker half-filled with water there’s a balloon stretched over the opening and nothing can leak out. What would happen if you placed the beaker/balloon apparatus on a hot plate and let the water come to a boil?
Answer:
The balloon will expand
Explanation:
Steam needs more space than the equivalent wt amount of liquid
Explain why an orange is the color orange.
Answer:
Because
Explanation:
A orange is called a orange because it is the color orange
as well as orange is orange because of the orange
CONNECT IT
Relate how a household sponge and water can be used to model
the concept of an unsaturated solution, a saturated solution, and a supersaturated
solution.
The sponge is unsaturated when it is taking in more water. It becomes saturated when it stops taking in water. It is supersaturated when water starts oozing out from the sponge.
A saturated solution contains just as much solute as it normally hold at a particular temperature. An unsaturated solution contains less solute than it can normally hold at a particular temperature. A supersaturated solution contains more solute than it can normally hold at a particular temperature.
We can use a sponge to model these three scenario as follows;
Water continues to enter into the sponge when it is unsaturated, this continues until the sponge becomes saturated with water and takes in no more water. When the sponge becomes supersaturated, water begins to ooze out from the sponge because it can no longer hold more water.
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task c has two immediate predecessors, tasks a and b. task a has an early finish time of 3 days, and task b has an early finish time of 5 days. task c is 2 days long. What is the early finish time of task c
The early finish time of task C is 7 days.
To determine the early finish time of task C, we consider the early finish times of its immediate predecessors, tasks A and B. Task A has an early finish time of 3 days, while task B has an early finish time of 5 days.
Since task C has two immediate predecessors, we select the maximum early finish time among them, which is 5 days. This means that task C cannot start before day 5.
Next, we add the duration of task C (2 days) to its predecessors' maximum early finish time.
Early finish time of task C
= Maximum early finish time of predecessors + Duration of task C
= 5 days + 2 days
= 7 days
Therefore, the early finish time of task C is 7 days.
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The early finish time of task c is if task c has two immediate predecessors, task a has an early finish time of 3 days, task b has an early finish time of 5 days, and task c is 2 days long is 8 days.
Task c can start once the two immediate predecessors are completed. The early finish time (EF) of task c will be the sum of the duration of task c and the maximum early finish time of the two immediate predecessors. The formula for calculating early finish time is:
EF = Maximum of (EF of immediate predecessors) + Task duration.
Early finish time of task c is calculated as follows:
EF of task c = Maximum of (EF of task a, EF of task b) + duration of task c
EF of task a = early finish time of task a = 3 days
EF of task b = early finish time of task b = 5 days
EF of task c = Maximum of (3 days, 5 days) + 2 days = 8 days
Thus, the early finish time of task c is 8 days.
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phương trình nào sau đây không đúng
Mg(OH)2 (t°)→ MgO+H2O
Fe(OH)2 (t°,chân không)→FeO+H2O
2Fe(OH)3 (t°)→Fe2O3+3H2O
2NaOH (t°)→Na2O+H2O
Phương trình NaOH sai nha
The image above shows a wave
Answer:
I need an image to help you as best as I can. Hopefully, this gets your attention so I can try to help!
Explanation:
CaCO3 Calcium oxide and carbon dioxide
Answer:
Explanation:Calcium oxide (CaO), commonly known as quicklime or burnt lime, is a widely used chemical compound. It is a white, caustic, alkaline, crystalline solid at room ...
what is the molality of a solution formed when 80.0 moles of potassium hydroxide (koh) are mixed with 5.4 kg of water?
Answer:
15 mol/kg or 14.81 mol/kg
Explanation:
Formula: molality = moles of solute ÷ kilogram of solvent
Solution :
m = 80.0 mols / 5.4 kg = 14.81 mol/kg
In 2 significant figures: 15 mol/kg
Could someone help me answer these questions with the answer and typed steps for how each answer was found? I asked this question previously but, I could not read the handwritten answer.
7. A 25 g soil sample was extracted with 75 mL of NH4OAc (pH 7.0), and the filtrate was analyzed
on an atomic absorption unit. The following results were obtained:
100 mg/L Ca2+, 45 mg/L Mg2+, 85.5 mg/L K+, 94.2 mg/L Al3+ and 8.0 mg/L H+.
a. What is the CEC in cmol(+)/kg for this sample?
b. What is the % B.S. for this soil?
c. What is the % acid saturation for this soil sample?
The CEC for this soil sample is 675.2 cmol(+)/kg.
The % Base Saturation for this soil sample is approximately 136.62%.
The % Acid Saturation for this soil sample is approximately 60.55%.
To calculate the CEC, % Base Saturation (B.S.), and % Acid Saturation for the given soil sample:
a. Calculation of CEC (Cation Exchange Capacity):
CEC is the sum of exchangeable cations in the soil. From the given results, we have:
CEC = Ca2+ + Mg2+ + K+ + Al3+
CEC = (100 mg/L + 45 mg/L + 85.5 mg/L + 94.2 mg/L) / (25 g / 1000)
CEC = 168.7 mg / (25 g / 1000)
CEC = 675.2 cmol(+)/kg
b. Calculation of % Base Saturation (B.S.):
% B.S. represents the percentage of CEC occupied by base cations. In this case, we consider Ca2+, Mg2+, and K+ as base cations. The formula to calculate % B.S. is:
% B.S. = (Ca2+ + Mg2+ + K+) / CEC * 100
% B.S. = (100 mg/L + 45 mg/L + 85.5 mg/L) / (168.7 cmol(+)/kg) * 100
% B.S. = 230.5 mg / (168.7 cmol(+)/kg) * 100
% B.S. = 136.62%
c. Calculation of % Acid Saturation:
% Acid Saturation represents the percentage of CEC occupied by acid cations, in this case, H+ and Al3+. The formula to calculate % Acid Saturation is:
% Acid Saturation = (H+ + Al3+) / CEC * 100
% Acid Saturation = (8.0 mg/L + 94.2 mg/L) / (168.7 cmol(+)/kg) * 100
% Acid Saturation = 102.2 mg / (168.7 cmol(+)/kg) * 100
% Acid Saturation = 60.55%
Please note that the given values were in milligrams per liter (mg/L), and the CEC and % Saturation values were calculated assuming a conversion from mg/L to cmol(+)/kg using the mass of the soil sample (25 g).
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a nonelectrolyte chemical treatment for aluminum alloys to increase corrosion resistance and paint bonding qualities is called
A nonelectrolyte chemical treatment for aluminum alloys to increase corrosion resistance and paint bonding qualities is called alodizing.
What is a non-electrolyte chemical?
A non-electrolyte chemical can be defined as the substance that does not allow the flow of electric current in any solution.
In other words we can say that when a non-electrolyte substance is dissolved in water it does not produce ions and that is why does not conduct electric current.
Examples of non-electrolyte chemical substances are ethanol, sugar as well as nonelectrolytes.
Simply put, non-electrolyte chemical is a poor conductor because it contains un-charged molecules which do carry charge and thus no electrical flow occurs.
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How many grams are in 9.05 x 1023 atoms of silicon
Answer:
42.2075 grams
Explanation:
Which particle has high rate of deposition
Answer:
a particle with jagged rough ends has a high rate of deposition
Answe
Explanation:
1st Remove ( )
2nd select like terms
3rd Move the constant to the left
4th calculate
5th divided both sides
6th use quadratic formula
What is the density of the block?
Answer:
1.666
≈ 1.67 g/cm³
Explanation:
Mass = 200g
Length = 6cm
Width = 4cm
Height = 5cm
Density = Mass/ Volume
Volume = length×width×height
\(V = 6 \times4 \times 5 \\ = 120\)
Density =
\( \frac{200}{120} = 1.6\)