Explanation:
The pascal (symbol: Pa) is the SI derived unit of pressure used to quantify internal pressure, stress, Young's modulus and ultimate tensile strength. It is defined as one newton per square metre. It is named after the French polymath Blaise Pascal
Use the diagram below for questions 2-4
2
1
С
-1
Question 2
Which wave has the greatest amplitude?
A Wave A
B. Wave B
C. Wave C
lustify your answer:
Answer:
A. It extends farthest from the horizontal axis
Explanation:
The amplitude of a wave is the measure of its peak excursion from the reference value. Here, the reference value is the horizontal axis of the graph. The wave that extends the farthest in the positive and/or negative directions is wave A. Wave A has the greatest amplitude.
__
Additional comment
There are various ways to define the amplitude of the wave if it is not symmetrical about the reference line. In this case, we don't need to concern ourselves with that. The value of the amplitude here is the maximum distance from the reference line, expressed as a positive number. Wave A has an amplitude of about 2.
what do we mean by accretion in the context of planet formation?
Rolls of foil are 304 mm wide and 0.017 mm thick. (the density of foil is 2.7 g/cm3 .) what maximum length of foil can be made from 1.34 kg of foil?
The maximum length of foil that can be made from 1.34 kg of foil is approximately 9575.045 cm. Steps are discussed below:
To calculate the maximum length of foil that can be made from a given mass, we need to consider the volume of the foil and its density.
First, let's calculate the volume of the foil using its width and thickness:
Volume = Width x Thickness x Length
Since we want to find the maximum length, we can rearrange the equation as:
Length = Mass / (Width x Thickness x Density)
Given:
Width = 304 mm
Thickness = 0.017 mm
Density = 2.7 g/cm³
Mass = 1.34 kg = 1340 g
Converting the width and thickness to centimeters:
Width = 30.4 cm
Thickness = 0.0017 cm
Now, we can calculate the maximum length of foil:
Length = 1340 g / (30.4 cm x 0.0017 cm x 2.7 g/cm³)
Simplifying the equation:
Length = 1340 / (30.4 x 0.0017 x 2.7) cm
Length ≈ 1340 / 0.14005608 cm
Length ≈ 9575.045 cm
Therefore, the maximum length of foil that can be made from 1.34 kg of foil is approximately 9575.045 cm.
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The wavelengths in the hydrogen spectrum with m = 1 form a series of spectral lines called the Lyman series. Calculate the wavelengths of the first four members of the series.
the wavelengths in the hydrogen spectrum of the first four members of the series where m=1, the first four members have the wavelength of \(1.464 * 10^7 m,\) \(1.231 * 10^7 m,\) \(1.164 * 10^7 m,\) and \(1.097 * 10^7 m.\)
The wavelengths of the spectral lines in the Lyman series of the hydrogen spectrum can be calculated using the Rydberg formula:
1/λ = \(R * (1/n1^2 - 1/n2^2)\)
Where λ is the wavelength of the spectral line, R is the Rydberg constant (approximately \(1.097 * 10^7 m^-^1)\), and n1 and n2 are positive integers representing the energy levels of the electron in the hydrogen atom.
For the Lyman series, we have m = 1, which means the electron transitions from higher energy levels (n2) to the first energy level (n1 = 1).
Let's calculate the wavelengths for the first four members of the Lyman series:
For n2 = 2:
1/λ = \(R * (1/1^2 - 1/2^2)\)
1/λ = \(R * (1 - 1/4)\)
1/λ = \(R * (3/4)\)
λ = \(4/3R\)
Substituting the value of the Rydberg constant:
λ = \((4/3) * (1.097 × 10^7 m^-^1)\)
λ ≈ \(1.464 * 10^7 m\)
For n2 = 3:
1/λ = \(R * (1/1^2 - 1/3^2)\)
1/λ = \(R * (1 - 1/9)\)
1/λ = \(R * (8/9)\)
λ = \(9/8R\)
Substituting the value of the Rydberg constant:
λ = \((9/8) * (1.097 * 10^7 m^-1)\)
λ ≈ \(1.231 * 10^7 m\)
For n2 = 4:
1/λ = \(R * (1/1^2 - 1/4^2)\)
1/λ = \(R * (1 - 1/16)\)
1/λ = \(R * (15/16)\)
λ = \(16/15R\)
Substituting the value of the Rydberg constant:
λ = \((16/15) * (1.097 * 10^7 m^-^1)\)
λ ≈ \(1.164 * 10^7 m\)
For n2 = 5:
1/λ = \(R * (1/1^2 - 1/5^2)\)
1/λ = \(R * (1 - 1/25)\)
1/λ = \(R * (24/25)\)
λ = \(25/24R\)
Substituting the value of the Rydberg constant:
λ = \((25/24) * (1.097 * 10^7 m^-^1)\)
λ ≈ \(1.097 * 10^7 m\)
Therefore, the wavelengths of the first four members of the Lyman series are approximately:
\(1.464 * 10^7 m,\)
\(1.231 * 10^7 m,\)
\(1.164 * 10^7 m,\)
and \(1.097 * 10^7 m.\)
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A 10-kg rock and a 20-kg rock are dropped at the same time and experience no significant air resistance. If the 10-kg rock falls with acceleration a, what is the acceleration of the 20-kg rock?.
When a 10-kg rock and a 20-kg rock are dropped at the same time and experience no significant air resistance the acceleration of both rocks is: the same and equal to the gravity
When an object is dropped (in the absence of air resistance) it has a positive acceleration equal to the gravity.
Therefore, no matter in which instant of the movement both rocks are, their acceleration will always be equal to the acceleration of gravity 32.17 ft/s², and after finishing their movements the acceleration will be equal to zero (0) because they will reach the ground and will be at rest.
What is gravity?In physics, gravity is the force of attraction that the earth exerts on all bodies possessing mass by pulling them toward its center.
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An echo returned in 3s. What is the distance of the reflecting surface from the source, given that the speed of sound is 342ms^-1
Answer:
d = 513 m
Explanation:
Given that,
An echo returned in 3s.
We need to find the distance of the reflecting surface from the source, given that the speed of sound is 342 m/s.
The sound will cover 2d distance. The formula for the speed is given by :
v = d/t
So,
\(v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{342\times 3}{2}\\\\d=513\ m\)
So, the required distance is 513 m.
Explain how light and
heavy elements are
created within stars?
Great question! Your answer is below.
They were created prior to the formation of our solar system, thus...
Huge, gigantic stars had to have existed, perished, and burst, releasing the materials they produced into the universe. These materials subsequently gathered via gravity to form our solar system and perhaps dozens or hundreds of others.
Our Sun is currently fusing hydrogen into helium; when hydrogen runs out, the Sun will compress a little, and the added pressure on the core will cause the helium to start fusing into carbon for a short while; then, the sun will die, and that will be that. Stars fuse lighter materials into heavier ones.
But with large stars, the outer layer may be made of hydrogen, which will be fusing into helium underneath it along a boundary. The helium layer will fuse into the carbon layer, the carbon layer will fuse into the calcium layer, and so on, up to the iron layer.
When iron production in a star's core starts, the star is doomed. The creation of elements *heavier* than Iron *takes* energy* Iron is the heaviest element ever formed that will release energy. Therefore, the star will eventually stop fusing, and its powerful gravitational pull will lead it to collapse. The abrupt in-falling mass generates the energy required for fusing the heavier metals, such as lead, gold, and uranium, after which the star's mass rebounds, resulting in the explosion known as a supernova. Before the formation of our solar system, all of this took place.'
Thanks!
- Eddie
pasteurization is a process that can be used to reduce food spoilage using high heat to kill all bacteria present
Pasteurization is a process wave that uses high heat to kill all bacteria present, which can reduce food spoilage. Pasteurization does not kill all bacteria, however, it can significantly reduce the number of harmful bacteria present.
Pasteurization is a heat treatment method used to destroy harmful bacteria present in food, particularly milk and dairy products. The process was developed by Louis Pasteur in the 19th century and has since been widely adopted in the food industry. During pasteurization, the food is heated to a specific temperature for a certain amount of time, which varies depending on the food type. The heat kills bacteria that can cause foodborne illness and spoilage, making the food safer to consume and last longer.
Pasteurization involves heating food, typically liquids such as milk or fruit juice, to a specific temperature for a certain period of time. This process destroys most harmful microorganisms and pathogens, which can cause foodborne illnesses and spoilage. It is important to note that pasteurization does not kill all bacteria but reduces their numbers to a safer level. By doing this, the shelf life of the food product is extended, and the risk of foodborne illness is minimized.
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a) Calculate the oscillating frequency of an LC circuit with a capacitor of 2 Farads and an inductor of 2 Henry.
b) Calculate the frequency in units of Hz in part (a).
c) What will you do to double the oscillating frequency in part (a)?
The oscillating frequency of the LC circuit with a capacitor of 2 Farads and an inductor of 2 Henrys is approximately 0.03979 Hertz or 39.79 millihertz.
the oscillating frequency of an LC circuit can be calculated using the formula:
f = 1 / (2π√(LC))
where f is the frequency in hertz (Hz), L is the inductance in henries (H), and C is the capacitance in farads (F).
Given that the capacitor has a capacitance of 2 Farads (F) and the inductor has an inductance of 2 Henrys (H), we can substitute these values into the formula:
f = 1 / (2π√(2 H * 2 F))
Simplifying further:
f = 1 / (2π√(4 H*F))
f = 1 / (2π * 2 H*F)
f = 1 / (4π H*F)
Using the approximation of π as 3.14159:
f ≈ 1 / (4 * 3.14159 * 2 H * 2 F)
f ≈ 1 / (25.13272 H*F)
f ≈ 0.03979 H*F
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What is the name of the convection
current in the atmosphere that cycles
between the equator and 30° N and
30° S?
Answer:
Hadley cells
Explanation:
Formation of Convection Currents
Atmospheric convection currents are global patterns of air movement that are initiated by the unequal heating of Earth. Hadley cells- the convection currents that cycle between the equator and 30˚ north and south.
PLEASE HELP ME ON QUESTION 27 ILL GIVE YOU BRAINLIEST!!
Answer:
question 22, the third answer is correct
Explanation:
you sent question 22 not 27
Why does the time for 20 complete oscillations need to be taken in the pendulum oscillation experiment?
Answer:
In order to minimize the uncertainty in the period, we measured the time for the pendulum to make 20 oscillations, and divided that time by 20
Explanation:
class 2 cables shall have a minimum voltage rating of ? .
Class 2 cables shall have a minimum voltage rating of 300 volts.
What is the voltage ?
The voltage is a measure of the difference in electric potential between two points in a circuit. It is measured in volts and is one of the basic parameters of electrical engineering. Voltage can be generated in a variety of ways, including through #SPJ1generators, batteries, and power supplies. When two points with different potentials are connected, current can flow from the higher potential point to the lower potential point. Voltage is also used to measure the potential difference between two points in a circuit, as well as to calculate the power in the circuit. In addition, voltage is used to control the flow of current in a circuit, by either increasing or decreasing the potential difference between the two points.
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Two particles, each of mass m, are moving with velocity -v and 2v. The kinetic energy at the center of mass is? A. (1/2) mv^2 B. mv^2 C. (1/4)mv^2 D. 4mv^2
The kinetic energy at the center of mass is C. (1/4)mv².
The center of mass is the point at which the two particles are balanced, and it is moving at a velocity equal to the average velocity of the two particles.
The kinetic energy at the center of mass (K.E._COM) can be found using the formula K.E._COM = 1/2 * total mass * velocity² of COM. First, let's determine the center of mass velocity (V_COM).
Since both particles have the same mass m, the center of mass velocity can be calculated as:
V_COM = (m*(-v) + m*(2v)) / (m + m) = (v) / 2
Now we can calculate the kinetic energy at the center of mass using the formula:
K.E._COM = 1/2 * (m + m) * (V_COM)² = 1/2 * (2m) * (v/2)² = 1/2 * 2m * (1/4)v² = (1/4)mv²
Therefore, the kinetic energy at the center of mass is (1/4)mv², which corresponds to option C.
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!!!!URGENT!!!! Which of these does not change with the increase in pressure?
A- Changing the number of particles
B- Changing the volume
C- Change the temperature
D- Changing the states of matter.
Answer:
a the number of particles
Explanation:
the volume will decrease because the particles are closer
if the particles are closer they generate more heat and thus can change their state of matter
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Answer:
jahahsnsbhahajab
The hazard management process consists of a number of activities designed to reduce loss of life and destruction of property. Natural hazard management has often been conducted independently of development planning. A distinctive feature of OAS technical assistance is the integration of the two processes.
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a stone is dropped from the top of a tower 400 m high and at the same time another stone is projected upward vertically from the ground with a velocity of 100 m/s. find where and when the two stones will meet.
Answer:The stones will be at the same height of 62.59 feets 4.4 seconds later.
Explanation:
A wire with a circular cross section and a resistance R is lengthened to 4.65 times its original length by pulling it through a small hole. The total volume of the wire is unchanged. Find the resistance of the wire after it is stretched. Answer in units of R.
The resistance of the wire after stretching is 21.6 times the original resistance (21.6R).
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. When the wire is lengthened by a factor of 4.65, its resistance will increase by the same factor.
This is because the resistance is determined by the ratio of the length to the cross-sectional area. As the length increases, the resistance increases proportionally. However, the volume of the wire remains constant during the stretching process.
Since the wire has a circular cross-section, its volume is given by V = πr^2L, where r is the radius and L is the length. Since the volume is unchanged, when the length is increased by a factor of 4.65, the cross-sectional area must decrease by the same factor to compensate.
The cross-sectional area of a circular wire is given by A = πr^2. If the length is increased by 4.65 times, the radius will decrease by the square root of 4.65 (approximately 2.155).
Consequently, the cross-sectional area will decrease by the same factor (2.155^2), resulting in a decrease in resistance by a factor of 4.65^2 (approximately 21.6). Therefore, the resistance of the wire after stretching is 21.6 times the original resistance (21.6R).
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if a horse runs around a 1900 meter circular track once in 95 seconds, what is the velocity, in m/s, of the horse?
The velocity of the horse is 20 meters/second.
To find the velocity of the horse, we can use the formula:
velocity = distance / time
In this case, the distance is 1900 meters and the time is 95 seconds. Plugging in these values into the formula, we get:
velocity = 1900 meters / 95 seconds
Simplifying, we find that the velocity of the horse is:
velocity = 20 meters/second
Speed is the speed and the bearing of movement of an item. Speed is a basic idea in kinematics, the part of traditional mechanics that depicts the movement of bodies. Velocity. As a shift in course happens while the dashing vehicles turn on the bended track, their speed isn't steady.
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what power does the defibrillator deliver to the body?
A defibrillator is a medical device used to deliver an electric shock to the heart in order to restore normal heart rhythm during a life-threatening condition called cardiac arrest. The power delivered by a defibrillator is typically expressed in terms of energy rather than power.
The defibrillator delivers a high-energy electric shock, measured in joules (J), to the body. The energy delivered during defibrillation is used to depolarize the heart muscles and allow the natural pacemaker of the heart to resume control over the heart rhythm.
The energy delivered by a defibrillator can vary depending on the specific device and the protocol being followed. Typically, the initial shock delivered by a defibrillator ranges from 120 to 200 joules. However, subsequent shocks may require higher energy levels.
It's important to note that the power of the defibrillator is determined by the rate at which energy is delivered. Power is the rate of energy transfer, measured in watts (W). The power delivered by a defibrillator is typically very high for a very short duration, allowing for the rapid delivery of the required energy to the heart.
Overall, while the defibrillator delivers a high-energy electric shock measured in joules, the power of the device depends on the rate at which the energy is delivered, and it is typically very high for a very short duration.
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what if? what is the minimum distance (absolute value, in mm) from the central maximum where you would find the intensity to be half the value found in part (a)?
The minimum distance (absolute value, in mm) from the central maximum where we would find the intensity to be half the value found in part (a) is approximately 0.443 mm.
What is intensity?The intensity of a wave is the amount of energy it transfers per unit time across a unit area of surface, and it is also equal to the energy density multiplied by the wave speed.
Assuming this is a follow-up question related to interference and diffraction of light:
If we want to find the minimum distance (in mm) from the central maximum where the intensity is half the value found in part (a), we need to use the equation for the intensity of the double-slit interference pattern:
I = \(I_{max\) * cos² (πd sinθ/λ)
where \(I_{max\) is the maximum intensity at the central maximum, d is the distance between the two slits, θ is the angle between the line from the center of the double-slit to the point where we want to find the intensity and the line perpendicular to the double-slit plane, λ is the wavelength of the light.
When the intensity is half the value found in part (a), we have:
I = \(I_{max\)/2
Substituting this into the equation above, we can solve for the angle θ:
cos² (πd sinθ/λ) = 1/2
Taking the square root of both sides, we get:
cos(πd sinθ/λ) = 1/√2
Solving for θ, we have:
θ = sin⁻¹(λ/(√2d))
Now, we need to find the corresponding distance x from the central maximum:
x = ytanθ
where y is the distance from the double-slit to the screen.
Substituting the values given in part (a), we have:
y = 2.00 m
λ = 633 nm
d = 0.200 mm
Thus, we get:
θ = sin⁻¹(633 nm/(√2 * 0.200 mm)) = 0.122 rad
And:
x = ytanθ = 2.00 m * tan(0.122 rad) = 0.443 mm
Therefore, the minimum distance (absolute value, in mm) from the central maximum where we would find the intensity to be half the value found in part (a) is approximately 0.443 mm.
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1. Calculate the total binding energy of 12
6 C.
Answer in units of MeV.
2. Calculate the average binding energy per nucleon of 24
12Mg.
Answer in units of MeV/nucleon.
3. Calculate the average binding energy per nucleon of 85
37Rb.
Answer in units of MeV/nucleon.
4. Find the binding energy per nucleon of 238
92U.
Answer in units of MeV/nucleon.
5. Calculate the total binding energy of 20
10Ne.
Answer in units of MeV.
6. Calculate the total binding energy of 40
20Ca.
Answer in units of MeV.
Answer:
1. B = 79.12 MeV
2. B = -4.39 MeV/nucleon
3. B = 2.40 MeV/nucleon
4. B = 7.48 MeV/nucleon
5. B = -18.72 MeV
6. B = 225.23 MeV
Explanation:
The binding energy can be calculated using the followng equation:
\( B = (Zm_{p} + Nm_{n} - M)*931 MeV/C^{2} \)
Where:
Z: is the number of protons
\(m_{p}\): is the proton's mass = 1.00730 u
N: is the number of neutrons
\(m_{n}\): is the neutron's mass = 1.00869 u
M: is the mass of the nucleus
1. The total binding energy of \(^{12}_{6}C\) is:
\( B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u \)
\( B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV \)
2. The average binding energy per nucleon of \(^{24}_{12}Mg\) is:
\( B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u \)
Where: A = Z + N
\( B = \frac{(12*1.00730 + 12*1.00869 - 24.305)}{(12 + 12)}*931.49 MeV/u = -4.39 MeV/nucleon \)
3. The average binding energy per nucleon of \(^{85}_{37}Rb\) is:
\( B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u \)
\( B = \frac{(37*1.00730 + 48*1.00869 - 85.468)}{85}*931.49 MeV/u = 2.40 MeV/nucleon \)
4. The binding energy per nucleon of \(^{238}_{92}U\) is:
\( B = \frac{(92*1.00730 + 146*1.00869 - 238.03)}{238}*931.49 MeV/u = 7.48 MeV/nucleon \)
5. The total binding energy of \(^{20}_{10}Ne\) is:
\( B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u \)
\( B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV \)
6. The total binding energy of \(^{40}_{20}Ca\) is:
\( B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u \)
\( B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV \)
I hope it helps you!
an elementary student of mass m=34 kg is swinging on a swing. the length from the top of the swing set to the seat is L=4.7 m. the child is attempting to swing all the way around in a full circle.
-what is the minimum speed in meters per second the child must be moving with at the top of the path in order to make a full circle?
-assuming the child is traveling at the speed found in part a what is their apparent weight in newtons at the top of their path? (at the top, the child is upside-down)
-if the velocity at the very top is the same velocity from part a what is the childs apparent weight in newtons at the very bottoms of the path?
An elementary student of mass m=34 kg is swinging on a swing. the length from the top of the swing set to the seat is L=4.7 m.
a) The minimum speed the child must be moving at the top of the path in order to make a full circle is 9.14 m/s.
b) The apparent weight of the child at the top of the path is 1005.52 N.
c) The apparent weight of the child at the bottom of the path is 333.54 N.
We can solve this problem using the conservation of energy and the centripetal force equation.
(a) At the top of the swing, the child is momentarily at rest, so all of the kinetic energy has been converted to potential energy. All of the potential energy has been transformed into kinetic energy at the swing's bottom.
The minimum speed required at the top of the path to make a full circle is the speed at which the centripetal force required to keep the child moving in a circle is equal to the gravitational force pulling the child downward.
Setting the centripetal force and gravitational force equal, we have:
\(mv^2 / L\)= mg
where m is the mass of the child, v is the speed of the child at the top of the path, L is the length of the swing, and g is the acceleration due to gravity.
Solving for v, we get:
v = \(\sqrt{(gL) }\)= \(\sqrt{(9.81 m/s^2 * 4.7 m) }\)≈ 9.14 m/s
Therefore, the minimum speed the child must be moving at the top of the path in order to make a full circle is approximately 9.14 m/s.
(b) At the top of the path, the child is momentarily upside-down, so the apparent weight is the sum of the gravitational force and the centripetal force required to keep the child moving in a circle.
The gravitational force on the child is:
\(mg = 34 kg * 9.81 m/s^2 = 333.54 N\)
To keep the kid moving in a circle, you need to apply the following centripetal force:
\(mv^2 / L = 34 kg * (9.14 m/s)^2 / 4.7 m\) ≈ \(671.98 N\)
Therefore, the apparent weight of the child at the top of the path is approximately 1005.52 N (333.54 N + 671.98 N).
(c) At the bottom of the path, the child is moving at the same speed as at the top, so the centripetal force required to keep the child moving in a circle is the same. However, at the bottom of the path, the gravitational force is the only force acting on the child.
The gravitational force on the child is the same as in part (b):
mg = \(34 kg * 9.81 m/s^2 = 333.54 N\)
The centripetal force required to keep the child moving in a circle is:
\(mv^2 / L = 34 kg * (9.14 m/s)^2 / 4.7 m\) ≈ \(671.98 N\)
Therefore, the apparent weight of the child at the bottom of the path is approximately 333.54 N (equal to the gravitational force).
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A car advertisement states that a certain car can accelerate from rest to 70 km/h in 7 seconds. Calculate the acceleration of the car.
Answer:
10 km/h
Explanation:
which of the following instrument would you prefer to measure the length of table
1 vernier calliper
2screw gage
3 microscope
4meter rod
Answer:
4. meter rod
Explanation:
The length of an object is dimension that expresses how long the object is. It is measured in meters as the SI unit.
From the given question, to determine the length of a given table, the appropriate instrument that should be used is a meter rod. This would make it possible to measure in meters and know the exact dimension of the object with respect to how long it is.
A meter rod has a length of 1 m (100 cm), and can be easily used for the purpose.
A model shows a machine that works using electrical fields. What would this machine
need for the electrical field to function properly? (1 point)
A. at least two charged, interacting parts
B. all neutral components
C. Moving parts, for kinetic energy
D. springs, to store potential energy
Answer:
c
Explanation:
Two 3 g bullets are fired with speeds of 40 m/s and 80 m/s. what is the kinetic energy of the first bullet
The answer is 60. Second is 120.
HELP ASAP. WILL GIVE BRAINLIEST. BEING TIMED HURRY!!!!
Choose all the answers that apply.
Which of the following statements is true?
Decreasing force increases an object's acceleration, where mass is constant.
Friction works in the direction opposite of motion.
Increasing mass increases an object's inertia.
| Increasing mass decreases an object's acceleration, where force is constant.
Answer:
B
Explanation:
B BBB
Answer: I think the answer is B if im not wrong
Explanation:
jordan has a mass of 65kg and carlos has a mass of 78.0kg. jordan is running at 5.75m/s when he is tackled by carlos who is running in the opposite direction. after the collision of both players are at rest. calculate their velocity before the collision.
Given
mj = 65 kg
mc = 78 kg
voj = 5.75 m/s
after collision
vfj = vfc = 0 m/s
Procedure
The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
\(\begin{gathered} p_o=p_f \\ m_jv_{0j}-m_cv_{0c}=0 \\ m_jv_{0j}=m_cv_{0c} \\ v_{0c}=\frac{m_jv_{0j}}{m_c} \\ v_{0c}=\frac{65kg*5.75m/s}{78kg} \\ v_{Oc}=4.8m/s \end{gathered}\)
The velocity before the collision would be 4.8m/s
12 1 point question at position 12 find the parallel line segments in the diagram and write a mathematical statement showing the parallel line segments.
The parallel line segments are ΔABC ~ ΔAED
Solution:
Parallel line segments: BC/ED
Similar triangles: ΔАВС ~ΔAED
Reason for Similar triangles
In ΔABC and ΔAED, we have
<A= <A (common)
m <ABC = M <AED (Corresponding Angles)
M<ACB = M<ADE (corresponding Angles)
= ΔABC ~ ΔAED
Parallel lines or parallel line segments are always them. They never meet at an equal distance from each other. edge. A table or book is a parallel segment. If a line crosses two sides of a triangle and bisects them equally, the line must be parallel to the third side of the triangle.
Parallel lines are lines that do not intersect or intersect at any point in the plane. They are always parallel and at the same distance from each other. Parallel lines are lines that do not intersect. It can be said that parallel lines meet at infinity. If the slopes are the same and the y-intercepts are different.
Learn more about Parallel lines here:-https://brainly.com/question/24607467
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