4 ( - 2 - 4 x) = 26 + 6 x

We can expect to observe 14 complete interference fringes within the central diffraction peak.

The act of bending light around corners such that it spreads out and illuminates regions where a shadow is anticipated is known as diffraction of light. In general, since both occur simultaneously, it is challenging to distinguish between diffraction and interference.

The number of complete interference fringes within the central diffraction peak depends on the specific experimental setup, such as the distance between the slits and the screen, the distance between the slits, and the wavelength of the light being used.

However, we can use the following equation to calculate the number of interference fringes within the central diffraction peak:

N = (2d/a)(L/λ)

where N is the number of interference fringes, d is the distance between the slits, a is the width of the slits, L is the distance between the slits and the screen, and λ is the wavelength of the light being used.

Assuming that we have a double-slit setup and the distance between the slits and the screen is much larger than the slit width, we can simplify the equation to:

N = 2d/a

Given that d/a = 7, we can substitute this value into the equation to get:

N = 2(7) = 14

Therefore, we can expect to observe 14 complete interference fringes within the central diffraction peak.

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Answer:

the trapiezium

Step-by-step explanation:

It has a area of 4 which is the highest

Answer:

B.   3,158

Step-by-step explanation:

h(x) = -49x − 125

Let x = -67

h(-67) = -49(-67) − 125

          =3283-125

          = 3158

Answer:

Answer B

Step-by-step explanation:

To find the value of h(-67) for the function h(x) = -49x - 125,

we substitute -67 for x in the function and evaluate it.

h ( - 67 ) = - 49 ( - 67 ) - 125

Now we can simplify the expression:

h ( -67 ) = 3283 - 125

h ( -67 ) = 3158

Answer:

The equation in standard form is:

x^2-40x-6000 = 0

Step-by-step explanation:

Let the length of the field be x yards.

Now the width of the field is 40 yards less than the length of the field.

Thus, the width of the field would be (x-40) yards

Now, to calculate the area of the field, we simply multiply the length of the field by the width of the field.

Hence;

Since the shape is rectangular, the area is the product of the length and that of the width

x(x-40) =6,000

x^2 -40x = 6,000

x^2-40x-6000 = 0

Answer:

648

Step-by-step explanation:

2=2

We have

for circle C:

radius = CD = 5

therefore, EC = 5

for circle A:

radius = CD + AD = 5 + 5 = 10

therefore, AB = 10

So, BE = AB + AD + CD + EC = 10 + 5 + 5 + 5 = 25

Answer: 25

The answer is A) 10,000,000 seven-digit numbers; B) The number is  20,000 ; C)  5,314,410 identification numbers are possible if no two adjacent digits are the same.

Seven-digit identification number:

A.) The number of possible identifying numbers

Possible digits are 0 up to 9.

Total number of digits: 10

Any of the 10 digits may be used for each;

Hence,

10×10×10×10×10×10×10 equals 10,000,000 potential outcomes.

B.) For it to start begin with either 023 and 003.

- the first digit must be 0 (1 possible value)

- 2nd digit must be 2 or 0 (2 possible values)

- 3rd digit must be 3 (1 possible value)

- 4th and 5th can be filled with any digit (10 × 10 possible values)

Which gives

1×2×1×10×10×10×10 = 20,000

3.) no two adjacent digits are the same that is no two digits that follows each other are the same.

In this case only one digit have 10 possible values.

The other four digits have 9 possible values each.

Which gives:

10×9×9×9×9×9×9 = 10× \(9^{6}\) = 5,314,410

The full question:

A certain identification number is a sequence of seven digits. (a) How many identification numbers are possible? (b) How many of them begin with either 023 or 003? (c) How many identification numbers are possible if no two adjacent digits are the same? (For example, 123-4-567 is permitted, but not 123-3-456.).

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Answer:

A

Step-by-step explanation:

just A

successive y values are 5 TIMES the previous y value

In all the others the y value is an ADDITION of the same amount to the previous y value

The probability that the first card drawn is a queen or the last card drawn is a queen is approximately 0.1538 or 15.38%.

The probability of drawing a queen as the first card is 4/52 or 1/13, since there are 4 queens in the deck and 52 total cards. The probability of drawing a queen as the last card is also 4/52 or 1/13, since the deck is well-shuffled and without replacement, so the probability of drawing a queen does not change.

However, if a queen is drawn as the first card, there are only 51 cards left in the deck and 3 queens remaining, so the probability of drawing a queen as the last card would be 3/51 or 1/17. Similarly, if a queen is not drawn as the first card, there would be 4 queens remaining in the deck of 51 cards, making the probability of drawing a queen as the last card 4/51.

To calculate the overall probability of drawing a queen as the first card or the last card, we can add the probabilities of each scenario: (1/13) + [(12/13) x (4/51)] + [(12/13) x (47/51) x (1/13)] = 0.1538, or approximately 15.38%.

Therefore, the probability that the first card drawn is a queen or the last card drawn is a queen is approximately 0.1538 or 15.38%

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P3(2) = 98e^8

r3(2) = e^8 - 98e^8

To find the value of P3(2), we need to compute the third Taylor polynomial of f(x) about 0 and substitute x = 2. The third Taylor polynomial is given by P3(x) = f(0) + f'(0)x + (f''(0)/2!)x^2 + (f'''(0)/3!)x^3. Taking derivatives of f(x) = e^4x, we find f'(x) = 4e^4x, f''(x) = 16e^4x, and f'''(x) = 64e^4x. Evaluating these derivatives at x = 0, we obtain f(0) = 1, f'(0) = 4, f''(0) = 16, and f'''(0) = 64. Substituting these values into P3(x) and then setting x = 2, we get P3(2) = 1 + 4(2) + (16/2)(2^2) + (64/3!)(2^3) = 98e^8.

To find the value of r3(2), we need to compute the third Taylor remainder of f(x) about 0 and substitute x = 2. The third Taylor remainder is given by r3(x) = f(x) - P3(x). Substituting x = 2 and the expression for P3(2) into the equation, we have r3(2) = f(2) - P3(2) = e^(4*2) - 98e^8 = e^8 - 98e^8.

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CosA is negative for the largest angle in an obtuse triangle. Using the law of cosines, a²>b²+c², a>b, and a>c are derived.

Step 1: As the obtuse triangle has the largest angle A (more than 90 degrees), the cosine function's value is negative.

Step 2: By applying the Law of Cosines in the triangle, a²>b²+c², which is derived from a²=b²+c²-2bccosA, and hence a>b and a>c can be derived.

Step 3: From the previously derived inequality a²>b²+c², we can conclude that a>b and a>c as a²-b²>c². The value of a² is greater than both b² and c² when a>b and a>c.

Therefore, the largest angle of an obtuse triangle is opposite the longest side.

Step 4: In triangle ABC, A=103°, a=25, and c=30.

a² = b² + c² - 2bccos(A),

a² = b² + 900 - 900 cos(103),

a² = b² + 900 + 900 cos(77),

a² > b² + 900, so a > b.

Similarly, a² > c² + 900, so a > c.

Therefore, triangle ABC satisfies a>b and a>c.

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The approximate circumference of spaceship Earth is 160m

The formula for calculating the volume of a sphere is given as;

V = 4/3 πr³

Given that;

Now, substitute the values

65417 = 1. 3 ×3.14r³

Multiply the values

65417 = 4. 082r³

Make r the subject

r³ = 16025. 722

Find the cube root

r = 25. 2m

The circumference is expressed as;

Circumference = 2πr

Substitute the values, we have;

Circumference = 2× 3.14 × 25.2

Circumference = 160 m

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The phase diagrams provide a visual representation of the system's behavior by plotting the vector field and trajectories in the x-y plane.

The given system of differential equations is described by:

\(˙x = a - x^2˙y = x - y\)

To find the equilibria, we set ˙x and ˙y equal to zero:

\(a - x^2 = 0 -- > x^2 = a -- > x = ±√ax - y = 0 -- > y = x\)

So, the equilibria are (±√a, ±√a).

Now let's analyze the behavior of the system for different values of 'a'.

For a > 0:

In this case, there are two real equilibria, (√a, √a) and (-√a, -√a). We can observe that (√a, √a) is a stable node, as the eigenvalues of the linearized system around this point have negative real parts. On the other hand, (-√a, -√a) is a saddle point, as the eigenvalues have opposite signs (one positive and one negative).

For a < 0:

In this case, there are no real equilibria since √a and -√a are imaginary. Therefore, the system has no equilibrium points.

To visualize the phase diagrams for a = 1 and a = -1:

For a = 1:

The system has two real equilibria, (1, 1) and (-1, -1). The point (1, 1) is a stable node, and (-1, -1) is a saddle point. The phase diagram would show trajectories converging towards (1, 1).

For a = -1:

Since a < 0, there are no equilibrium points, and thus the phase diagram would show no fixed points or trajectories.

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Answer:

1 and 3

Step-by-step explanation:

why you delete my other comment

Answer:

73urur

Step-by-step explanation:

ndndndnfnnfnfjgjfjf

Answer:

-0.5

Step-by-step explanation:

x=-23÷46

x=-0.5

that's the answer :)

Given information: Expected sales revenue = $57756Target labour cost percentage = 18%To find: How much money can you spend on labour that day? Solution: Let's assume the amount that can be spent on labour is x. According to the question, Target labour cost percentage is 18%.

Therefore, the amount that will be spent on labour cost = 18% of expected sales revenue. So, we can write it as:

x = 18% of expected sales revenue orx

= (18/100) × 57756Simplify it

,x = 10396.08 (rounded to two decimal places)Thus, the amount that can be spent on labour that day is $10,396.08.

Shawna and Beatrice, by virtue of their status as the offerees, had the option of accepting or rejecting the offer. The acceptance must meet the requirements of a valid contract.

The acceptance must be communicated clearly and immediately. In addition, the acceptance must conform to the offer's terms. In Hyde v Wrench (1840), the court held that an acceptance must be unconditional and absolute and that if the acceptance is not in line with the terms of the offer, it is a counteroffer that terminates the original offer. Since Shawna and Beatrice had not yet responded to the offer, there was no acceptance of the contract. Therefore, there was no legal agreement between the parties as a contract must have both an offer and an acceptance in order to be considered valid.

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Answer:

x=56

Step-by-step explanation:

Since the angles are all the same,

D=78

F=46

All you have to do is subtract these numbers from 180, which gives you 56

Answer:

56

Step-by-step explanation:

1. The surface areas of the cones are;

1)  56.52 in²  2) 565.20ft²  3) 235.50 yd² 4) 898.04ft²   5) 942.00yd²

6) 75.36 in²   7) 1306.24yd²   8) 405.04in²  9. 339.12 ft²

2. The volumes of the cones are;

1) 84.78 in³  2). 564.15ft³  3) 4710yd³  4) 2712.96in³  5) 20.93ft³  6) 870.82yd³  7)  7846.86in³

3.  The volume of the cone-shaped Santa hat is 75.36in³.

For the normal cones, we use the formula  πr² + πrl to calculate the surface area.

(3.14 x 25) + (3.14x10x5) =  235.50 yd²

(3.14 x 121) + (3.14x15x11) = 898.04ft²

However, for cones like the ones in 6 and 8, we use a slightly different formula. √H² + r² = L first and then  π x r x (r + L).

For example  6.  H= 4in r=3in

⇒ √(4^2 + 3^2) =5

⇒  3.14 x 3 x (3 + 5) =75.36

To calculate the volume, we use the formula (V) = (1/3) x π x r² x H

For example,  H= 9in   r=3in ⇒

(1/3) x 3.14 x 3² x 9 = 84.78in³

The answers provided are based on the information in the picture;

1. Find the surface area of each cone. Round your answer to two decimal places ( use π = 3.14)

1. L = 7in  r=2in   2. L=11ft  r=9ft   3. L=10yd r=5yd   4. L=15ft  r=11ft

5. L=20yd  r=10yd   6.  L= 4in r=3in   7. L=19yd  r= 13yd   8. H=14in  r= 8in

9. L=12ft  r=6ft

2. Find the volume of each cone. Round to 2 decimal places. ( use π = 3.14).

1. H= 9in   r=3in     2. H= 11ft   r= 7ft     3. H=20yd   r=15yd  4. H=18in  r= 12in 5. H=5ft  r=2ft    6. H=13yd  r=8yd  7. H= 17in  r= 21

3. For Christmas, Lily make paper cones santa hat. If the height and radius of the cone are 8 inches and 3 inches respectively, what is the volume of the hat? ( use π = 3.14)

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The ratio of sin A can be written as CB/AB.

The correct option is B.

One area of mathematics known as trigonometry examines the relationship between the sides and angles of a right triangle. The relationship between sides and angles is defined for 6 trigonometric functions.

We have to find sine ratio.

We know that sine ratio is the ratio of opposite leg to the Hypotenuse.

From the figure,

Opposite leg = CB and

Hypotenuse = AB

So, sin A = CB/ AB

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Answer:

3rd choice and 5th choice

Step-by-step explanation:

79m + 248 = 880

79m is $79 being charged per month

248 is the initial fees

880 is how much he has spent

we can now solve the equation to find how many months he has been subscribed for

79m = 632

m = 8

Answer:

Amount needed by her \(=\$(5x+5)\)

Step-by-step explanation:

Given: Susie wants to buy 5 slices of pizza and a litre of soda that cost $5 for her and her friends

To find: amount needed by her

Solution:

Let cost of 1 slice of pizza be \(\$x\). Also, a litre of soda costs $5.

Cost of 5 slices of pizza \(=\$5x\)

Cost of a litre of soda \(=\$5\)

Total amount needed by her \(=\$(5x+5)\)

Answer:

A \(1.3 - 5.6 = - 4.3\)

Step-by-step explanation:

\(1.3 - 5.6 = - 4.3\)

Hope this helps! Pwease mark me brainliest! Have a great day!

−xXheyoXx

Answer:

just answering so you can give the other person brainliest :D

Step-by-step explanation:

Hirokawa studied groups to find optimal solutions, while Gouran wanted to find decisions that are acceptable or satisfactory. Optimal solutions are defined as the best or the most effective solutions to a problem or situation. Hirokawa studied groups to find optimal solutions.

According to his research, groups make decisions by going through a communication process that involves four functions: problem analysis, goal setting, identification of alternatives, and evaluation of alternatives. Gouran, on the other hand, was interested in finding acceptable or satisfactory decisions.

He believed that communication within a group leads to the identification of a set of criteria that will lead to an acceptable or satisfactory decision. The group members then search for solutions that meet those criteria. Hence, Gouran wanted to find decisions that are acceptable or satisfactory.

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The false statement regarding the box-and-whisker plot is given by:

There are fewer data points in the lower two quartiles than in the upper two quartiles.​

The box-and-whisker plot is not given for this problem, but from it, we have that:

A box and whisker plot shows five things:

The false statement is:

There are fewer data points in the lower two quartiles than in the upper two quartiles.​

Because 50% values are below the median and 50% are above, meaning that there is an equal number of data points in the lower two quartiles than in the upper two quartiles.​

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The weakest base is C5H5N (pyridine) with Kb = 1.7 × 10^(-9). The correct answer is C.

The strength of a base is determined by its ability to accept or donate a pair of electrons. In general, a stronger base has a higher tendency to accept or donate electrons compared to a weaker base.

In the given options, the bases are characterized by their Kb values. Kb (base dissociation constant) represents the equilibrium constant for the reaction of a base with water to form the corresponding conjugate acid and hydroxide ions.

Comparing the Kb values provided:

A smaller Kb value indicates a weaker base because it corresponds to a lower concentration of hydroxide ions in solution. Therefore, in this case, C5H5N (pyridine) with a Kb value of 1.7 × 10^(-9) is the weakest base among the given options. The correct answer is C.

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Answer:

there are 100 centigrams in a gram

Step-by-step explanation:

Solution:

Note that:

Let's substitute the values into the equation and find the measure of AC.

The time is needed between injections is 3.6 hours, i.e., the drug is to be injected again when the number of milligrams reaches 6 mg.

We have the exponential function of number of milligrams D (ht) of a certain drug that is in a patient's bloodstream h hours after the drug is injected is

\(D(h)=25 {e}^{ - 0.4 h}\)

We have to solve for h (the numbers of hours) that would have passed when the D(h) (the amount of medication in the patient's bloodstream) equals 6 mg in order to know when the patient needs to be injected again.

\(6 = 25 {e}^{ - 0.4h} \)

\( \frac{6}{25} = \frac{25}{25} {e}^{ - 0.4h} \)

\(0.24= {e}^{ - 0.4h} \)

Taking logarithm both sides of above equation , we get,

\( \ln(0.24) = \ln( {e}^{ - 0.4h)} \)

Using the properties of natural logarithm,

\( \ln(0.24) = - 0.4h\)

\( - 1.427116356 = - 0.4h\)

\(h = \frac{1.42711635}{0.4} = 3.56779089\)

=> h = 3. 6

So, after 3.6 hours, the patient needs to be injected again.

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To solve this problem, we need to find the number of ways the 10 different movies can be stored on 40 computers. Since each computer can have at most one movie, we can think of this as arranging the 10 movies in a specific order on the 40 computers.

The number of different ways the 10 movies can be stored on the 40 computers is 10!. The calculation is given as follows:

To find the number of ways to arrange the movies, we can use permutations. The formula for permutations is nPr = n! / (n - r)!, where n is the total number of items and r is the number of items being arranged.
In this case, we have 10 movies and 40 computers, so n = 10 and r = 40.
Plugging these values into the formula, we get:
10P40 = 10! / (10 - 40)! = 10! / (-30)!

Now, we need to simplify this expression. To do that, we can use the fact that 0! = 1.
So, -30! = (-30) * (-31) * (-32) * ... * (-1) * 0! = (-30) * (-31) * (-32) * ... * (-1) * 1 = (-30) * (-31) * (-32) * ... * (-1)

Now we can calculate 10P40:
10P40 = 10! / (-30)! = 10! / [(-30) * (-31) * (-32) * ... * (-1)]

Since we have 10! in the numerator and a long negative product in the denominator, we can simplify the expression further:
10P40 = (10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1) / [(-30) * (-31) * (-32) * ... * (-1)]

Now we can evaluate the numerator and denominator separately:
Numerator: 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 10!
Denominator: (-30) * (-31) * (-32) * ... * (-1)

Since the movies are different and it matters which movie is stored on which computer, we have 10! ways to arrange the movies. So, the number of different ways the 10 movies can be stored on the 40 computers is 10!

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