3.) Technician A says that a scan tool can be used to verify engine operating temperature,
Technician B says that a refractometer can be used to verify engine operating temperature.
Who is right?
OA. A only
OB. B only
OC. Both A and B
OD. Neither A nor B

the following are desirable characteristics of refractory ceramics

a. Ability to remain unreactive and inert in severe environments.

b. Ability to withstand high temperatures.

d. High strengths.

e. Thermally insulative.

The ability to withstand high temperatures is essential for refractory ceramics, as they are often used in high-temperature applications such as furnaces and kilns. The ability to remain unreactive and inert in severe environments is also important to ensure that the material does not react with the surrounding environment or other materials in the system, which could lead to degradation or failure of the component. High strength is desirable to prevent fracture or deformation under mechanical loads. Lastly, being thermally insulative is useful for applications where heat needs to be contained or controlled within a given space.

Know more about refractory ceramics here:

https://brainly.com/question/31874920

#SPJ11

Answer:

Explanation:

Increased by the constant. Take a very simple case.

4  +  5 +  6 = 15

The mean is 5  (obtained by dividing the total (15) by the number of terms (3).

Now add a constant say 6

4 + 6 = 10

5 + 6 = 11

6 + 6 = 12

Total = 33/3 = 11

So the mean 5 is increased by the constant 6.

Now do the same thing more symbolically.

4 + c

5 + c

6 + c

Total = 15 + 3c

Divide by 3 you get 5 + c

If you want a more formal proof involving n terms, leave a note.

It is very important to know where online information comes from in order to validate, authenticate and be sure it's the right information

Online informations are information which are available on the internet such as search engines, social handles and other websites

In conclusion, it is very important to know where online information comes from in order to validate, authenticate and be sure it's the right information

Learn more about online information:

https://brainly.com/question/921157

#SPJ1

Answer: Calendars are important so that; Students know what’s coming up. Adequate time is planned for important events and studying different levels of detail are accounted for students may be organized and prepared for anything.

Explanation:

The reason why it is important for Raul to use the different types of calendars is; So that he can know what is coming up

Calendars are documents that contain dates of all days in a year as classified by that specific calendar.

The most common calendar system types in the world today are Gregorian, Islamic and Chinese. Now, regardless of the type of calendar being used, the one common factor with all of them is that they assist everyone including students to know the events that are coming up.

In conclusion the reason why it is important for Raul to use the different types of calendars is So that he can know what is coming up

Read more on calendars at; https://brainly.com/question/7353753

Common agricultural commodities include dairy products, wheat, and coffee. You can invest in and “trade” these products virtually, without running a farm and purchasing and storing the items yourself.

The value of the site is $10,472,000.

The total construction costs are:

$6,000/m2 * 10,000m2 + $400,000 = $64,000,000

The professional fees are:

$64,000,000 * 0.13 = $8,320,000

The total development costs are:

$64,000,000 + $8,320,000 = $72,320,000

The developer's return for risk and profit is:

$72,320,000 * 0.20 = $14,464,000

The total cost of the development is:

$72,320,000 + $14,464,000 = $86,784,000

The expected rent is:

$3,000/m2 * 8,000m2 * 12 months = $28,800,000

The initial yield is:

$28,800,000 * 0.07 = $2,016,000

The value of the site is:

$86,784,000 - $2,016,000 = $10,472,000

Read more about initial yield here:

https://brainly.com/question/14714924

#SPJ1

There are several physical properties that can be used to visually identify rock types, but three key properties are color, texture, and mineral composition.

Color is an easily observable property and can provide clues about the mineral content of a rock. For example, light-colored rocks typically contain minerals like quartz and feldspar, while dark-colored rocks may have minerals like biotite or hornblende.

Texture refers to the size and arrangement of mineral grains within a rock. Coarse-grained rocks are typically formed from slowly cooling magma or lava, while fine-grained rocks often result from rapid cooling or sedimentation.

Mineral composition can also be used to identify rocks. Certain minerals are characteristic of specific rock types, such as calcite in limestone or feldspar in granite. By examining the minerals present in a rock, geotechnical laboratory teams can identify its likely rock type.

Learn more about rocks on:

https://brainly.com/question/19930528

#SPJ1

patience

problem-solving skills

ability to handle complex calculations

Explanation:

Engineering's fundamental building block is arithmetic, and biomedical engineers unquestionably require solid maths abilities. Geometry and calculus are frequently used by biomedical engineers while assessing and developing medical solutions. Thus, option A,C,D is correct.

To better the lives of patients, biomedical engineers analyse challenges in biology and medicine and create solutions. A good aptitude for engineering, an imaginative spirit, and a love for working in healthcare are all required for this position. The human anatomy fascinates biomedical engineers, and they enjoy addressing problems.

No more difficult than any other type of engineer, at least. For those with a talent for engineering, this field is rigorous but rewarding, even though it is generally difficult to break into. No engineering discipline is more demanding than biomedical engineering.

Therefore, patience, problem-solving skills, ability to handle complex calculations talents do Biomedical Engineers need.

Learn more about Biomedical Engineers here:

https://brainly.com/question/11617187

#SPJ2

Answer:

an ability to identify, formulate, and solve engineering problems. an understanding of professional and ethical responsibility. an ability to communicate effectively. the broad education necessary to understand the impact of engineering solutions in a global, economic, environmental, and societal context

Answer:

B because as a textile engineer, your job is to help design and create fabric, including the equipment and materials needed for fabrication.

The average normal stress at the midsection of rod AB will be 25.8 MPa.

Stress is the force exerted on a material divided by the cross-sectional area of the substance. Strain is the material's displacement or distortion as a result of applied stress. Note: The length change of a material (L - L0) is sometimes shown as.

Given, d1 = 30 mm

          d2 = 50mm

          P = 50kN

now, stress = force/ area

stress = 50/ 1.9635×10⁻³

stress = 25.8×10⁶ Pa

stress = 25.8 MPa

The average normal stress at the midsection of rod AB is 25.8 MPa.

To know more about stress visit

brainly.com/question/1178663

#SPJ4

The flue gas resulting from burning producer gas with 20% excess air will contain carbon dioxide, nitrogen, oxygen, hydrogen, and water vapor.

If the combustion is only 90% complete, then the flue gas will contain more carbon dioxide and oxygen than if the reaction was 100% complete.

The general equation for burning producer gas is:

CxHy + (x + y/4)O2 → xCO2 + (y/2)H2O

]

Where C represents carbon, H represents hydrogen and O represents oxygen.

To calculate the composition of the flue gas, we need to know the amount of oxygen and fuel burned and the percentage of combustion completion.

In this case, we know that 100 kg of producer gas and 20% excess air were burned and the combustion was only 90% complete. We can then calculate the total amount of oxygen and fuel burned.

Amount of fuel = 100 kg

Amount of O2 = 100 kg x 20% excess air = 20 kg

Total mass of fuel and O2 = 120 kg

Now we need to calculate the amount of oxygen and fuel that is not combusted. This can be done by multiplying the total mass of fuel and O2 by the percentage of combustion completion.

Amount of oxygen and fuel not combusted = 120 kg x 10% = 12 kg

Now we can calculate the amount of oxygen and fuel combusted.

Amount of oxygen and fuel combusted = 120 kg - 12 kg = 108 kg

We can then calculate the amount of each gas produced by the combustion of the producer gas.

Amount of CO2 = 108 kg x (x/100) = 108 x 0.28 = 30.24 kg

Amount of H2O = 108 kg x (y/200) = 108 x 0.035 = 3.78 kg

Amount of O2 = 108 kg x (1/4) = 27 kg

Amount of N2 = 108 kg x (68/100) = 73.44 kg

Therefore, the composition of the flue gas is 30.24 kg of CO2, 3.78 kg of H2O, 27 kg of O2, and 73.44 kg of N2.

If the excess air is increased to 40%, then the total mass of fuel and O2 will be 140 kg and the amount of oxygen and fuel not combusted will be 14 kg. This means that the combustion reaction will not be complete and there will still be some unburned fuel and oxygen in the flue gas.

For more questions like Combustion reaction click the link below:

https://brainly.com/question/14521417

#SPJ4

Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

An airplane flying across the sky experience drag force determined by the factors including the speed of flight, coefficient of skin friction and the reference surface area

The boundary layer thickness is approximately 0.233 cm

The total skin friction drag, is approximately 265 N

Reason:

First part:

Given parameters are;

Chord length, L = 3 m

Velocity of the plane, V = 200 m/s

Density of the air, ρ = 1.225 kg/m³

Viscosity of the air, μ = 1.81 × 10⁻⁵ kg/(m·s)

The Reynolds number is given as follows;

\(R_{eL} = \dfrac{\rho \times V \times L}{\mu}\)

Therefore;

\(R_{eL} = \dfrac{1.255 \times 200 \times 3}{1.81 \times 10^{-5}} = 4.16022099448 \times 10^7 \approx 4.16 \times 10^7\)

Boundary layer thickness, \(\delta_L\), for laminar flow, is given as follows;

\(\dfrac{ \delta_L }{L}=\dfrac{5.0}{\sqrt{R_{eL} } }\)

\({ \delta_L }=\dfrac{5.0 \times L}{\sqrt{R_{eL} } }\)

Which gives;

\({ \delta_L }=\dfrac{5.0 \times 3}{\sqrt{4.16 \times 10^{7}} } \approx 2.33 \times 10^{-3 }\)

The boundary layer thickness, \(\delta_L\) ≈ 2.33 × 10⁻³ m = 0.233 cm

Second Part

The total skin friction is given as follows;

\(Dynamic \ pressure, q = \dfrac{1}{2} \cdot \rho \cdot V^2\)

Therefore;

\(q = \dfrac{1}{2} \times 1.225 \times 200^2 = 24,500\)

The dynamic pressure, q = 24,500 N/m²

Skin friction drag coefficient, \(C_D\), is given as follows;

\(C_D = \dfrac{1.328}{\sqrt{R_{eL} } }\)

Therefore;

\(C_D = \dfrac{1.328}{\sqrt{4.16 \times 10^7 } } \approx 2.06 \times 10^{-4}\)

Skin friction drag, \(D_f\), is given as follows;

\(D_f\) = q × \(C_D\) × A

Where;

A = The reference area

∴ \(D_f\) = 24,500 N/m² × 2.06 × 10⁻⁴ × 3 m × 17.5 m = 264.9675 N ≈ 265 N

The total skin friction drag, \(D_f\) ≈ 265 N

Learn more here:

https://brainly.com/question/12977939

(a) Factor of safety: Fs = 350 / 28.87 = 12.11. (b) Factor of safety: Fs = 350 / 23.84 = 14.68. (c) Factor of safety: Fs = 350 / 49.56 = 7.06. (d) Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(53.76 / 0.577, 88

The factor of safety against yielding is given by the ratio of the yield strength to the maximum allowable stress. For plane stress, the maximum allowable stress is determined by the distortion energy and maximum shear stress theories. Using these theories, we can calculate the maximum allowable stress for each plane stress state and then calculate the factor of safety.

(a) For σₓ = σy = 100 MPa,

Maximum shear stress theory: τmax = σ/2 = 100/2 = 50 MPa

Distortion energy theory: σmax = (σₓ + σy)/2 + √[(σₓ - σy)/2]^2 + τxy^2 = 100 + √0 + 0 = 100 MPa

Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(50 / 0.577, 100 / 1.732) = 28.87 MPa

Factor of safety: Fs = 350 / 28.87 = 12.11

(b) For σₓ = 100 MPa and σy = 50 MPa,

Maximum shear stress theory: τmax = (σₓ - σy)/2 = 25 MPa

Distortion energy theory: σmax = (σₓ + σy)/2 + √[(σₓ - σy)/2]^2 + τxy^2 = 75 + √562.5 = 88.96 MPa

Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(25 / 0.577, 88.96 / 1.732) = 23.84 MPa

Factor of safety: Fs = 350 / 23.84 = 14.68

(c) For σₓ = 100 MPa and Tₓy = -75 MPa,

Maximum shear stress theory: τmax = (σₓ + |Tₓy|)/2 = 87.5 MPa

Distortion energy theory: σmax = (σₓ + σy)/2 + √[(σₓ - σy)/2]^2 + τxy^2 = 100 + √(1875 + 5625) = 182.32 MPa

Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(87.5 / 0.577, 182.32 / 1.732) = 49.56 MPa

Factor of safety: Fs = 350 / 49.56 = 7.06

(d) For σₓ = -50 MPa, σy = -75 MPa, and Txy = -50 MPa,

Maximum shear stress theory: τmax = √[(σₓ - σy)/2]^2 + Txy^2 = √[(25/2)^2 + 50^2] = 53.76 MPa

Distortion energy theory: σmax = √[(σₓ - σy)/2]^2 + Txy^2 + √[(σₓ + σy)/2]^2 = √[(25/2)^2 + 50^2] + √(625 + 5625)/2 = 88.96 MPa

Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(53.76 / 0.577, 88

Learn more about Strength of Materials here: brainly.com/question/15741538

#SPJ4

The missing option is attached below

Answer:

  A ≈ 37.0°

  B ≈ 109.9°

  C ≈ 33.1°

Explanation:

Triangle solvers are available for phone or tablet, and on the internet. Obviously, you have no issue with using technology to find your answer. Here it is using appropriate technology.

  A ≈ 37.0°

  B ≈ 109.9°

  C ≈ 33.1°

__

If you're solving this by hand, it usually works best to use the Law of Cosines to find the largest angle:

  B = arccos((a² +c² -b²)/(2ac)) = arccos(-13.638/40.044) ≈ 109.912°

Then the another angle can be found using the Law of Sines.

  C = arcsin(c/b·sin(B)) = arcsin(4.26/7.34·sin(109.912°)) ≈ 33.071°

The remaining angle will bring the total to 180°.

  A = 180° -109.912° -33.071° = 37.017°

Answer:

A = 37.0°

A = 37.0°B = 109.9⁰

A = 37.0°B = 109.9⁰C = 33.1°

Explanation:

Triangle solvers are available for phone or tablet, and on the internet. Obviously, you have no issue with using technology to find your answer. Here it is using appropriate technology.

A = 37.0⁰B = 109.9⁰C = 33.1°If you're solving this by hand, it usually works best to use the Law of Cosines to find the largest angle:

B = arccos((a² +c²-b²)/(2ac)) = arccos(-13.638/40.044) = 109.912

°

Then the another angle can be found using the Law of Sines.

C = arcsin(c/b-sin(B)) = arcsin(4.26/7.34-sin(109.912°)) = 33.071°

The remaining angle will bring the total to 180°

.A = 180° -109.912° -33.071° = 37.017°

The sum and product of each hexadecimal number are for a D6A, 1A3F88 for b 216BB, 1438D5A for c ACD8F, B051FA2E for d E0BAA8, 92A26ABAE4

Here is how you find the sum and product of each of these pairs of hexadecimal numbers.

a) (1AE)16, (BBC)16
Sum: 1AE + BBC = D6A (in hexadecimal)
Product: 1AE * BBC = 1A3F88 (in hexadecimal)

b) (20CBA)16, (A01)16
Sum: 20CBA + A01 = 216BB (in hexadecimal)
Product: 20CBA * A01 = 1438D5A (in hexadecimal)

c) (ABCDE)16, (1111)16
Sum: ABCDE + 1111 = ACD8F (in hexadecimal)
Product: ABCDE * 1111 = B051FA2E (in hexadecimal)
d) (E0000E)16, (BAAA)16
Sum: E0000E + BAAA = E0BAA8 (in hexadecimal)
Product: E0000E * BAAA = 92A26ABAE4 (in hexadecimal)

Learn more about hexadecimal numbers:https://brainly.com/question/11109762

#SPJ11

The safety technique that is recommended for this situation of moving a heavy industrial printer is to Bend at the knees when lifting.

This refers to the process of executing a task in a safe and acceptable way that does not put the user or others at risk

Hence, we can see that The safety technique that is recommended for this situation of moving a heavy industrial printer is to Bend at the knees when lifting.

This is to ensure that the person doing the lifting does not injure himself and has the proper form when lifting.

Read more about safety procedures here:

https://brainly.com/question/14367881

#SPJ1

Answer:

"Physical" would be the right approach.

Explanation:

So the answer here is just the perfect one.

It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

Learn more about internet browser applications.:
https://brainly.com/question/16829947
#SPJ1

The jet pipe rear nozzle is controlled to open when reheat is selected to ensure that there is enough space for the additional exhaust gases produced during reheat.

The reheat system, also known as the afterburner, injects fuel into the hot exhaust gases exiting the engine turbine, allowing for an increase in thrust and speed of the aircraft. The increase in the amount of fuel also means that the amount of exhaust gases will increase, which would lead to a possible collision of the exhaust with the aircraft structure if the rear nozzle is not opened.

This could cause damage to the aircraft and is also a safety risk for pilots and passengers. Therefore, the jet pipe rear nozzle is controlled to open when reheat is selected to allow the exhaust gases to exit without causing any damage. It is important to ensure that the nozzle is controlled precisely to prevent any performance issues or damage to the engine or aircraft.

to know more about nozzle visit:

https://brainly.com/question/32333301

#SPJ11

In traffic engineering, space mean speed is higher than time mean speed. Space mean speed refers to the average speed of a vehicle in space, whereas time mean speed refers to the average speed of a vehicle in time.

Space mean speed is defined as the distance covered by a vehicle during a given time interval divided by the time interval. Space mean speed is measured in meters per second or kilometers per hour. Space mean speed is dependent on the distance traveled, which means that it is based on spatial measurements. It is unaffected by traffic lights or signal changes, which is why it is the preferred speed measure for traffic engineers. Time mean speed is defined as the total distance traveled by a vehicle divided by the total time taken to travel that distance. It is the average speed over the length of the trip, and it is expressed in kilometers per hour. Time mean speed is a function of time, which means that it is based on temporal measurements. It is heavily influenced by traffic signals, stop signs, and other traffic control devices.

In traffic engineering, space mean speed is higher than time mean speed because it is based on spatial measurements rather than temporal measurements. Time mean speed is greatly influenced by traffic control devices, whereas space mean speed is not. Traffic engineers favor space mean speed because it better reflects the actual speed of vehicles on the road.

Learn more about traffic engineering visit:

brainly.com/question/29417480

#SPJ11

The worst way to show self-management is to ask your boss to set all your goals. Self-management is the act of managing one's own behavior, time, and resources effectively to reach a goal.

It is the ability to organize oneself and control impulses, emotions, and actions. It is a skill that requires discipline, self-awareness, and commitment. There are different ways to show self-management, but some ways are better than others.Asking your boss to set all your goals is the worst way to show self-management because it shows a lack of initiative and responsibility. It suggests that you are not willing to take ownership of your career or invest in your development. It also implies that you are not confident in your ability to set and achieve your own goals. By asking your boss to set all your goals, you are giving away your power and agency, and relying on someone else to define your success and progress. This approach can be limiting, disempowering, and demotivating.There are better ways to show self-management, such as planting a time to evaluate your progress, setting your own career goals, and asking for feedback on your progress. Planting a time to evaluate your progress is a proactive way to assess your performance and identify areas for improvement. Setting your own career goals demonstrates ambition, vision, and ownership of your future. Asking for feedback on your progress shows a willingness to learn, grow, and adapt to new challenges. These approaches are more empowering, engaging, and effective than relying on your boss to set all your goals.

To know more about self-management visit :

https://brainly.com/question/4574856

#SPJ11

Answer:

The temperature of the strip as it exits the furnace is 819.15 °C

Explanation:

The characteristic length of the strip is given by;

\(L_c = \frac{V}{A} = \frac{LA}{2A} = \frac{5*10^{-3}}{2} = 0.0025 \ m\)

The Biot number is given as;

\(B_i = \frac{h L_c}{k}\\\\B_i = \frac{80*0.0025}{21} \\\\B_i = 0.00952\)

\(B_i\) < 0.1,  thus apply lumped system approximation to determine the constant time for the process;

\(\tau = \frac{\rho C_p V}{hA_s} = \frac{\rho C_p L_c}{h}\\\\\tau = \frac{8000* 570* 0.0025}{80}\\\\\tau = 142.5 s\)

The time for the heating process is given as;

\(t = \frac{d}{V} \\\\t = \frac{3 \ m}{0.01 \ m/s} = 300 s\)

Apply the lumped system approximation relation to determine the temperature of the strip as it exits the furnace;

\(T(t) = T_{ \infty} + (T_i -T_{\infty})e^{-t/ \tau}\\\\T(t) = 930 + (20 -930)e^{-300/ 142.5}\\\\T(t) = 930 + (-110.85)\\\\T_{(t)} = 819.15 \ ^0 C\)

Therefore, the temperature of the strip as it exits the furnace is 819.15 °C

Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

Learn more about shaft on:

https://brainly.com/question/30541080

#SPJ2

Answer:

(166.0 mm Hg) (273.15 mL) = (760.0 mm Hg) (x)

Answer:

for 13

Explanation:

''.''

TRUE. It is preferable to utilize double-line multiview drawings that are appropriately scaled for complex plumbing systems.

An multiview painting is one that depicts two or more perspectives of a three-dimensional subject in two dimensions.Drawings with many perspectives show an object's shape.Multiview drawings are the primary means of communication among designers and manufacturers when used in conjunction with dimensions.

Multiview or graphical drawings can be made using parallel projection techniques.This front multiview design was made using orthographic projection, which involves projecting specifics onto a plane parallel to the viewpoint of the object that was chosen as the front.

To know more about  complex piping  visit:

https://brainly.com/question/14218637

#SPJ4

Answer:

The answer is "F".

Hope this helped!